Using boosting with 1,000 trees on the Hitters data set, after removing observations with unknown salary information and log-transforming salaries, results in a test set MSE (Mean Squared Error) value.
1. Remove observations with unknown salary information from the Hitters data set.
2. Log-transform the remaining salaries.
3. Create a training set with the first 200 observations and a test set with the remaining observations.
4. Apply the boosting algorithm on the training set, using 1,000 trees as the parameter.
5. Evaluate the performance of the boosting model on the test set by calculating the Mean Squared Error (MSE). The test set MSE will give you an indication of the model's accuracy in predicting salary based on the provided data.
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a) ¿Cuál es el coeficiente del término 23x5?
Answer:
El coeficiente del término 23x^5 es 23.
Step-by-step explanation:
Question 10(Multiple Choice Worth 2 points)
(Comparing Data MC)
The box plots display measures from data collected when 20 people were asked about their wait time at a drive-thru restaurant window.
A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 8.5 to 15.5 on the number line. A line in the box is at 12. The lines outside the box end at 3 and 27. The graph is titled Super Fast Food.
A horizontal line starting at 0, with tick marks every one-half unit up to 32. The line is labeled Wait Time In Minutes. The box extends from 9.5 to 24 on the number line. A line in the box is at 15.5. The lines outside the box end at 2 and 30. The graph is titled Burger Quick.
Which drive-thru typically has more wait time, and why?
Burger Quick, because it has a larger median
Burger Quick, because it has a larger mean
Super Fast Food, because it has a larger median
Super Fast Food, because it has a larger mean
Question 11(Multiple Choice Worth 2 points)
(Creating Graphical Representations MC)
The number of carbohydrates from 10 different tortilla sandwich wraps sold in a grocery store was collected.
Which graphical representation would be most appropriate for the data, and why?
Circle chart, because the data is categorical
Line plot, because there is a large set of data
Histogram, because you can see each individual data point
Stem-and-leaf plot, because you can see each individual data point
Question 12(Multiple Choice Worth 2 points)
(Comparing Data MC)
The line plots represent data collected on the travel times to school from two groups of 15 students.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 10, 16, 20, and 28. There are two dots above 8 and 14. There are three dots above 18. There are four dots above 12. The graph is titled Bus 14 Travel Times.
A horizontal line starting at 0, with tick marks every two units up to 28. The line is labeled Minutes Traveled. There is one dot above 8, 9, 18, 20, and 22. There are two dots above 6, 10, 12, 14, and 16. The graph is titled Bus 18 Travel Times.
Compare the data and use the correct measure of center to determine which bus typically has the faster travel time. Round your answer to the nearest whole number, if necessary, and explain your answer.
Bus 14, with a median of 14
Bus 18, with a mean of 12
Bus 14, with a mean of 14
Bus 18, with a median of 12
Question 13(Multiple Choice Worth 2 points)
(Appropriate Measures MC)
The line plot displays the number of roses purchased per day at a grocery store.
A horizontal line starting at 1 with tick marks every one unit up to 10. The line is labeled Number of Rose Bouquets, and the graph is titled Roses Purchased Per Day. There is one dot above 1 and 2. There are two dots above 8. There are three dots above 6, 7, and 9.
Which of the following is the best measure of variability for the data, and what is its value?
The range is the best measure of variability, and it equals 8.
The range is the best measure of variability, and it equals 2.5.
The IQR is the best measure of variability, and it equals 8.
The IQR is the best measure of variability, and it equals 2.5
The drive-thru is able to estimate their wait time more consistently will be A. Burger Quick, because it has a smaller IQR.
What is the IQR?The interquartile range (IQR) is a measure of variability that represents the range of values in the middle 50% of scores in a distribution. It is used when the data is skewed and the median is a better measure of central tendency than the mean.
In this scenario, Burger Quick has an IQR of 14.5, while Fast Chicken has an IQR of 4.5.
The IQR is calculated by subtracting the first quartile (Q1) from the third quartile (Q3).
For Burger Quick, Q1 is 9.5 and Q3 is 24, so the IQR is 24 - 9.5 = 14.5. For
Fast Chicken, Q1 is 10 and Q3 is 14.5, so the IQR is 14.5 - 10 = 4.5.
Therefore, Burger Quick has a larger IQR than Fast Chicken, indicating that its data is more consistent and less spread out. This means that Burger Quick is better able to estimate its wait time consistently.
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Consider the function f(x) = 5 – 2x^2, -5 ≤ x ≤ 2. The absolute maximum value is
and this occurs at x = The absolute minimum value is and this occurs at x =
As a result, the function's absolute maximum and minimum values are 5 and -45, respectively, at x = -5 and x = 2, respectively.
what is function ?Every element in a set (referred to as the domain) in mathematics is connected by a rule known as a function to exactly one component in some other set (called the range or codomain). In other terms, a role is a connection among 2 sets where every element in the domain matches exactly one member in the range. Using a formula or equation with a variable input, function notation is a common way to represent functions. As an illustration, the formula f(x) = 2x + 1 gives each true figure x the value 2x + 1.
given
We can apply the second derivative test to determine whether this critical point is a maximum or minimum. By taking f'(xderivative, )'s we arrive at:
f''(x) = -4
The critical point at x = 0 is a local maximum since f"(0) = -4 is a negative value.
Secondly, we must determine whether the interval's endpoints of -5 x 2 provide values that are higher or lower than the crucial point. By entering x = -5 and x = 2, we obtain:
[tex]f(-5) = 5-2(-5) (-5)^2 = 5 – 50 = -45[/tex]
[tex]f(2) = 5 - 2(2) (2)^2 = -3[/tex]
As a result, the function's absolute maximum and minimum values are 5 and -45, respectively, at x = -5 and x = 2, respectively.
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Regina writes the expression y + 9 x 3/4. Which expression is equivalent to the one Regina writes?
The expression that is equivalent to the one Regina wrote is y + 27/4
Which expression is equivalent to the one Regina wrote?From the question, we have the following parameters that can be used in our computation:
y + 9 x 3/4
This means that
Expression = y + 9 x 3/4
When expanded, we have
Expression = y + 27/4
Using the above as a guide, we have the following:
The expression that is equivalent to the one Regina wrote is y + 27/4
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4x + 8y = 3x + 7y + 14; y=2
Answer:
Step-by-step explanation:
as we alderdy have value of y,we can substuite it in the place of y
4x+8(2)=3x+7(2)+14
4x+16=3x+14+14
4x-3x=28-16
x=12
Determine the distance between the points (−3, −6) and (5, 0).
[tex]~~~~~~~~~~~~\textit{distance between 2 points} \\\\ (\stackrel{x_1}{-3}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{5}~,~\stackrel{y_2}{0})\qquad \qquad d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2} \\\\\\ d=\sqrt{(~~5 - (-3)~~)^2 + (~~0 - (-6)~~)^2} \implies d=\sqrt{(5 +3)^2 + (0 +6)^2} \\\\\\ d=\sqrt{( 8 )^2 + ( 6 )^2} \implies d=\sqrt{ 64 + 36 } \implies d=\sqrt{ 100 }\implies d=10[/tex]
Ben practises playing the Oboe daily.
The time (in minutes) he spends on
daily practice over 28 days is as follows:
10, 15, 30, 35, 40, 40, 45, 55, 60, 62,
64, 64, 66, 68, 70, 70, 72, 75, 75, 80,
82, 84, 90, 90, 105, 110, 120, 180
a Find the median time.
b
Find the lower quartile.
c Find the upper quartile.
d
Find the range.
Determine whether there
outliers in the data.
e
(2 marks)
(2 marks)
(2 marks)
(2 marks)
are any
(4 marks)
f Draw a box-and-whisker diagram for
the above data.
(3 marks)
Therefore, (70+72)/2 = **71 minutes** is the median time. B)42.5 minutes as a result. C,D)The range is determined by deducting the dataset's smallest value from highest value.
A)When the data are organized in order of magnitude, the median time is the middle value. The median in this situation is the average of the 14th and 15th values, which are 70 and 72, respectively. There are 28 data points in this situation. Therefore, (70+72)/2 = **71 minutes** is the median time.
b) The median of the lowest half of the data constitutes the lower quartile (Q1). We must arrange the data in descending order of magnitude before determining the median of the first half of the data in order to determine Q1. is the average of the seventh and eighth values, which are 40 and 45, respectively, in the first half of the data, which consists of 14 values. Q1 = (40+45)/2 = **42.5 minutes as a result.
b) The median of the upper half of the data constitutes the upper quartile (C). We must first organise the data in descending order of magnitude before determining the median of the remaining data in order to determine Q3. Q3 is the average of the seventh and eighth values from the last, which are 90 and 105, respectively, in the second half of the data, which consists of 14 values. Q3 = (90+105)/2 = **97.5 minutes**3 as a result.
d) The range is determined by deducting the dataset's smallest value from highest value.
In this instance, Ben's practise time can be anywhere from **10 minutes** to **180 minutes**. Range then equals maximum value - minimum value, which in this case is 180 - 10 = **170 minutes**
e) Extreme values that are beyond the typical range of a dataset's values are known as outliers. We can use a criterion that states that any value that sits more than 1.5 times the interquartile range (IQR) below Q1 or above Q3 is regarded as an outlier to ascertain whether there are outliers in this dataset. When Q1 is subtracted from Q3, the result is the IQR: Q3 - Q1 = 97.5 - 42.5 = **55 minutes**3. By using this rule, we can see that the dataset contains the outliers **180** and **120** minutes.
IQR stands for what?The term "interquartile range" is IQR. It is a measure of variability that is based on quartilizing a dataset. The first quartile (Q1) is subtracted from the third quartile to determine the IQR. (Q3). It is a representation of the middle 50% of the data's range.
f) A box-and-whisker plot illustrates a dataset's quartiles, outliers, and range1. For Ben's practice, here's how to create a box-and-whisker plot:
- Create a number line with all the values Ben practised with.
- Draw a box spanning Q1 through Q3.
- Inside the box, at the location of Q2, draw a vertical line. (the median).
Draw whiskers from the box's two ends to all values that are not outliers.
- Place every outlier on the graph as a separate point, outside of any whiskers.
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Answer this Question
The missing numbers on the grids are given as follows:
2 and -6.
How to obtain the amounts?The amounts are obtained by a system of equations, for which the variables are given as follows:
x and y.
The top grid represents the sum of the measures, hence:
x + y = -4.
The bottom grid represents the subtraction of the measures, hence:
x - y = 8.
Adding the two equations, the value of x, representing the left grid, is given as follows:
2x = 4
x = 2.
Then the value of y, representing the right grid, is given as follows:
2 + y = -4
y = -6.
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i need help !!!!!!!!!!!!!!!!!!
Answer:
[tex]\displaystyle\textsf{a) }\binom{8}{4}\\\\\textsf{b) }\binom{-8}{4}[/tex]
Step-by-step explanation:
Given a translation vector ...
[tex]\displaystyle \binom{g}{h}[/tex]
moves g to the right and h up, you want the vectors for 8 right, 4 up, and for 8 left, 4 up.
SubstitutionWhen we have g = units to the right, and we want 8 units to the right, we know that g = 8. Similarly, h = units up, and we want 4 units up, so h = 4.
Putting these values in the vector form, we have ...
a) 8 right, 4 up matches vector ...
[tex]\displaystyle \boxed{\binom{8}{4}}[/tex]
b) Left is the opposite of right, so 8 units left will be represented by ...
g = -8
As before, 4 units up means h = 4.
[tex]\displaystyle \boxed{\binom{-8}{4}}[/tex]
<95141404393>
A cat falls from a tree (with zero initial velocity) at time t = 0. How far does the cat fall between t = 0.5 s and t=1.4 s? Use Galileo's formula u(t) = -32t ft/s.
Answer = _______
The distance is negative because it's a fall, so the cat falls 27.36 ft between t = 0.5 s and t = 1.4 s.
To find the distance the cat falls between t = 0.5 s and t = 1.4 s, we need to use the formula for velocity and distance.
we first need to find the position at each of these times using the given formula u(t) = -32t ft/s.
The formula for distance fallen is:
distance(t) = initial position + initial velocity × t + (1/2) × acceleration × t²
Since the cat falls with zero initial velocity and starts from the tree, we can simplify the formula:
distance(t) = (1/2) × acceleration × t²
First, let's find the velocity of the cat at t = 0.5 s and t = 1.4 s using Galileo's formula:
u(0.5) = -32(0.5) = -16 ft/s
and, u(1.4) = -32(1.4) = -44.8 ft/s
Now, we can use the formula for distance:
distance = (velocity at t = 0.5 s + velocity at t = 1.4 s) / 2 x (t = 1.4 s - t = 0.5 s)
⇒ distance = (-16 ft/s + (-44.8 ft/s)) / 2 x (1.4 s - 0.5 s)
⇒ distance = (-60.8 ft/s) / 2 x (0.9 s)
⇒ distance = -27.36 ft/s x s
Therefore, the cat falls 27.36 feet between t = 0.5 s and t = 1.4 s.
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Suppose a friend or family asked you how it could be possible that an annual interest rate is higher than 100%. write out an explanation of what you might say to them
If someone asked me how it could be possible for an annual interest rate to be higher than 100%, I would explain that it is actually quite common in certain situations, particularly in the case of loans with very short terms or loans with high fees.
For example, let's say you borrowed $100 from a lender and agreed to pay back $110 in one week. The lender is essentially charging you 10% interest for the one-week loan period, but if you annualize that rate, it comes out to over 520%. This is because the lender is charging you a very high interest rate for a very short period of time.
Another example would be if you took out a payday loan, which typically have very high fees attached to them. For instance, you might borrow $500 and have to pay back $575 in two weeks. The interest rate on this loan might be calculated as the $75 fee divided by the $500 borrowed, which comes out to 15%. However, if you annualize that rate, it comes out to over 390%.
In both of these examples, the interest rate is very high because the loan term is very short and/or the fees are very high. It's important to note that borrowing at such high interest rates can be extremely costly and can lead to a cycle of debt, so it's generally recommended to avoid loans with high interest rates whenever possible.
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Joe bought g gallons of gasoline for $2.85 per gallon and c cans of oil for $3.15 per can. What expression can be used to determine the total amount Joe spent on gasoline and oil?
Answer:
The total amount Joe spent on gasoline and oil can be determined by the expression: 2.85g + 3.15c. This expression represents the cost of g gallons of gasoline at $2.85 per gallon plus the cost of c cans of oil at $3.15 per can.
Step-by-step explanation:
(1 point) Consider the function f(x, y) = xy + 33 – 48y. f har ? at (-43,0) f has at (0,4). a maximum a minimum a saddle some other critical point no critical point f ha: at (463,0). f has at (0,0). f has ? at (0, –4).
At point (-43,0), f has a maximum. At point (0,4), f has a minimum. At point (463,0), f has a maximum. At point (0,0), f may have a critical point. none of the given points are critical points of the function f (x, y) = xy + 33 - 48y.
Hi! To analyze the critical points of the function f(x, y) = xy + 33 - 48y, we first need to find the partial derivatives with respect to x and y:
fx = ∂f/∂x = y
fy = ∂f/∂y = x - 48
Now, we can analyze the given points:
1. (-43, 0)
At this point, fx = 0 and fy = -48. Since both partial derivatives are not equal to 0, this point is not a critical point.
2. (0, 4)
At this point, fx = 4 and fy = 0. Again, both partial derivatives are not equal to 0, so this is not a critical point.
3. (463, 0)
At this point, fx = 0 and fy = 463 - 48 = 415. Since both partial derivatives are not equal to 0, this is not a critical point.
4. (0, 0)
At this point, fx = 0 and fy = -48. Since both partial derivatives are not equal to 0, this is not a critical point.
5. (0, -4)
At this point, fx = -4 and fy = -48. Again, both partial derivatives are not equal to 0, so this is not a critical point.
In summary, none of the given points are critical points of the function f(x, y) = xy + 33 - 48y.
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Please help I need it ASAP, also needs to be rounded to the nearest 10th
Answer: 161.2
Step-by-step explanation:
Plug into formula
6.9² = 13²+17.8²-2(17.8)(13) cos C >simplify numbers
-438.23 = -2(17.8)(13) cos C >Divide both sides by -2(17.8)(13)
cos C=.947 > use [tex]cos^{-1}[/tex] C to solve for angle
<C=180-18.75 = 161.2 > neded to subtract from 180 for this
one
When do you hit the water and what is your maximum height above the pool?
The time till you hit the water, given your height above the water, would be 0.76 seconds.
The maximum height above the pool you would get is 15.39 feet.
How to find the maximum height and time ?We are given h ( t ) = - 16 t ² + 5t + 15
You hit the water at 0 so the formula is:
0 = - 16 t ² + 5t + 15
Using the quadratic equation, we can solve:
t = ( - b ± √ ( b ² - 4 ac ) ) / 2a
t = ( - 5 ± √ ( 5 ² - 4 ( - 16 ) ( 15 ) )) / 2 (- 16)
t = (- 5 ± √ 985 ) / -32
t = 0. 76 seconds
The vertex of the parabolic function would be:
= - b / 2a
= - 5 / ( 2 x - 16 )
= 0. 15625 seconds
Maximum height is therefore:
= -16 ( 0. 15625 ) ² + 5 ( 0. 15625 ) + 15
= 15.39 feet
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Consider a point with rectangular coordinates (x,y).
if x<0 then the polar coordinates of the point are (r,θ) where r≥0 and −π/2≤θ<3π/2and:
r=
θ=
if x≥0 then the polar coordinates of the point are (r,θ) where r≥0 and −π/2≤θ<3π/2 and:
r=
θ=
Polar coordinates for rectangular coordinates if x<0: r=√(x²+y²) and θ=tan⁻¹(y/x)+π if y≥0 or θ=tan⁻¹(y/x)−π if y<0, For x≥0: r=√(x²+y²) and θ=tan⁻¹(y/x) if y≥0 or θ=tan⁻¹(y/x)+2π if y<0.
The polar coordinates of a point with rectangular coordinates (x,y) depend on the sign of x.
If x<0, the polar coordinates are (r,θ) where r≥0 and −π/2≤θ<3π/2. If x≥0, the polar coordinates are (r,θ) where r≥0 and −π/2≤θ<3π/2.
If x<0, t
hen r=√(x²+y²) and
θ=tan⁻¹(y/x)+π if y≥0
or θ=tan⁻¹(y/x)−π if y<0.
The value of r is the distance from the origin to the point and θ is the angle between the positive x-axis and the line segment from the origin to the point.
If x≥0, then r=√(x²+y²) and θ=tan⁻¹(y/x) if y≥0 or θ=tan⁻¹(y/x)+2π if y<0.
In this case, θ is the angle between the positive x-axis and the line segment from the origin to the point, measured counterclockwise.
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The monthly income of a man is Rs 53000. He deposits 20% of his yearly income in civil investment fund and 10% in charity. If 1 % social security tax should be paid on First Rs 300000and 15% tax is imposed yearly ,how much tax should he pay?
The man needs to pay a total tax of Rs 69780 (3000 for social security and 66780 for yearly tax).
How to find the tax should he pay?To find the tax, let's find the man's yearly income:
Yearly income = Monthly income x 12
Yearly income = 53000 x 12 = 636000
Next, let's find how much he deposits in civil investment fund and charity:
Amount deposited in civil investment fund = Yearly income x 20%
Amount deposited in civil investment fund = 636000 x 0.2 = 127200
Amount deposited in charity = Yearly income x 10%
Amount deposited in charity = 636000 x 0.1 = 63600
Now, let's calculate the total taxable income:
Total taxable income = Yearly income - Amount deposited in civil investment fund - Amount deposited in charity
Total taxable income = 636000 - 127200 - 63600 = 445200
Since the man's taxable income is above Rs 300000, he needs to pay 1% social security tax on Rs 300000:
Social security tax = 1% of 300000 = 3000
Now, let's calculate the yearly tax imposed at a rate of 15%:
Yearly tax = Total taxable income x 15%
Yearly tax = 445200 x 0.15 = 66780
Therefore, the man needs to pay a total tax of Rs 69780 (3000 for social security and 66780 for yearly tax).
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Quality-control research determined that of all new
cars sold by Sherman Motors, 8% will require a
minor repair during the first year of ownership.
Suppose you survey the owners of three cars from
Sherman Motors. Find the probability to the nearest
percent that exactly one car will require a minor
repair in the first year
The probability that out of three exactly one car will require a minor repair in the first year = 33%
P(E ) = no. of favorable outcome/total no. of outcome
E here represents exactly one car that requires a minor repair.
out of three cars, exactly one car will need a minor repair
No. of favorable outcome = 1
Total no. of outcome = 3
Now, putting value in P(E) we get
P(E) = 1/3
P(E) = 0.333
To get percentage we multiply by 100
P(E) = 0.333 × 100
P(E) = 33.3
The probability to the nearest percent = 33%
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Now that you have chosen your mode of transportation, use your choice to answer the questions that follow.
What would the cost of your transportation be if you drove:
a. 10 miles? b. 25 miles? c. 42 miles? d. 68 miles?
Make sure to list your chosen mode of transportation and then answer all parts and show your work
(a) The cost of City Bus for driving 10 miles = $3.
(b) The cost of City Bus for driving 25 miles = $7.5.
(c) The cost of City Bus for driving 42 miles = $12.6.
(d) The cost of City Bus for driving 68 miles = $20.4.
We previously choose City Bus as our mode transport since the per mile cost for City Bus is less.
Let the model for City Bus be f(x) = cx + d, where f(x) is total cost and x is number of miles.
From the table of Taxi we get, f(2) = 0.60; f(4) = 1.20; f(6) = 1.80 and f(8) = 2.40.
So, 2a + b = 0.60 and 4a + b = 1.20
(4a + b) - (2a + b) = 1.20 - 0.60
2a = 0.60
a = 0.60/2 = 0.30
Now, f(8) = 2.40
8*0.30 + b = 2.40
2.40 + b = 2.40
b = 2.40 - 2.40 = 0
So the function rule for City Bus is, f(x) = 0.3x.
(a) Total cost to drive 10 miles is,
f(10) = 0.3*10 = 3
(b) Total cost to drive 25 miles is,
f(25) = 0.3*25 = 7.5
(c) Total cost to drive 42 miles is,
f(42) = 0.3*42 = 12.6
(d) Total cost to drive 68 miles is,
f(68) = 0.3*68 = 20.4
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A company knows that unit cost and unit revenue from the production and sale of x units are related by C. + 10621. Find the rate of change of revenue per unit when the 102.000 cost per unit is changing by $8 and the revenue is $4,000 O A $102.00 OD $160.00 OC. $577.05 OD. $1,052.10
The rate of change of revenue per unit is $8 when the unit cost is changing by $8 and the revenue is $4,000.
We are given that the unit cost (C) and unit revenue (R) are related by the equation C = R + 10621.
We want to find the rate of change of revenue per unit, dR/dx, when the unit cost (C) is changing by $8 per unit and the revenue (R) is $4,000.
1. Differentiate the given equation with respect to x: dC/dx = dR/dx
2. Plug in the given values: dC/dx = $8 (cost per unit is changing by $8) R = $4,000 (revenue per unit)
3. Solve for the cost per unit (C) using the equation
C = R + 10621
C = $4,000 + 10621
C = $14,621
4. Since dC/dx = dR/dx, and we know dC/dx = $8,
we can find the rate of change of revenue per unit (dR/dx) when the cost per unit is changing by $8: dR/dx = $8
Thus, the rate of change of revenue per unit is $8 when the unit cost is changing by $8 and the revenue is $4,000.
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You doing the practice 1
Using the intersection of sets we find that A ∩ B = {1, 3}
What is a set?A set is a collection of well ordered items.
Givent hat set A = {x| x is an od number greater than 0 and less than 10} and set B = {1, 2, 3, 4}, we desire to find A ∩ B. We proceed as follows.
First since set A = {x| x is an odd number greater than 0 and less than 10}, its elements are A = {1, 3, 5, 7, 9}
Also, set B = {1, 2, 3, 4}
Since we require A ∩ B which is the intersection of both sets and is the elements that both sets have in common. Since both sets have element 1 and 3 in common, we have that
A ∩ B = {1, 3}
So, A ∩ B = {1, 3}
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What is the slope of the line that passes through the points (9, 1) and (10, -1)?
Write your answer in simplest form.
Answer:
m=2
Step-by-step explanation:
The surface area of a triangular pyramid is 450 square meters. The surface area of a similar triangular pyramid is 50 square meters.
What is the ratio of corresponding dimensions of the smaller pyramid to the larger pyramid?
The ratio of the corresponding dimensions of the smaller pyramid to the larger pyramid is 1/3.
What is a dimension?Dimension is the measure of the distance or length of an obeject.
To calculate the ratio of the corresponding dimensions of the smaller pyramid to the larger pyramid, we use the formula below
Formula:
l/L = √(a/A) ........................ Equation 1
Where:
l/L = Ratio of the dimension of the smaller pyramid to the larger onea = Area of the smaller pyramidA = Area of the larger pyramidFrom the question,
Given:
a = 50 m²A = 450 m²Substitute these values into equation 1
l/L = √(50/450)l/L = √(1/9)l/L = 1/3Learn more about dimension here: https://brainly.com/question/27404871
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Find the volume of this cylinder using 3.14 as pi
13 ft
20 ft
The value of the volume of the cylinder is 706. 5 cm³
How to determine the valueThe formula for the volume of a cylinder is expressed as;
V = πr²h
Such that the parameters are;
V is the volume of the cylinderπ takes the value 3.14r is the radius of the cylinderh is the height of the cylinderNow, substitute the values into the formula, we get;
Volume, V = 3.14 × 5² × 9
Find the square value and substitute
Volume, V = 3.14 × 25 × 9
Multiply the values
volume, V = 706. 5 cm³
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If the an average American makes around $ 40,000 per year for his or her lifetime and works from age 22 to 65, what amount will he or she pay in taxes for their entire lifetime?
We can see here that the amount he or she will pay in taxes for their entire lifetime is: $344,000
What is tax?Tax is a financial obligation that all people, businesses, and other types of entities must fulfill for a government organization.
Let us say that an average American makes $40,000 for his or her lifetime and works from age 22 to 65, and pays a combined federal and state income tax rate of 20%, the amount of taxes paid per year would be:
$40,000 x 0.20 = $8,000
Over a 43-year period (from age 22 to 65), the total amount of taxes paid would be: $8,000 x 43 = $344,000
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An investor purchases 500 shares of Exxon-mobil stock at $98. 93 per share. His broker charges 2% of the cost of the stock. What is the cost of the stock?
The cost of the stock for the investor would be calculated as follows:
Cost of 1 share = $98.93
Number of shares purchased = 500
Total cost of the stock = Cost per share x Number of shares
Total cost of the stock = $98.93 x 500
Total cost of the stock = $49,465
The broker charges 2% of the cost of the stock, so the broker's fee would be calculated as:
Broker's fee = 2% x Total cost of the stock
Broker's fee = 2% x $49,465
Broker's fee = $989.30
Therefore, the total cost of the stock for the investor including the broker's fee would be:
Total cost of the stock + Broker's fee = $49,465 + $989.30
Total cost of the stock + Broker's fee = $50,454.30
So the cost of the stock for the investor including the broker's fee is $50,454.30.
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A van can ferry a maximum of 12 people. By setting up an inequality, find the maximum number of vans that are needed to ferry 80 people
By setting up an inequality, the maximum number of vans that are needed to ferry 80 people are 7 vans.
To find the maximum number of vans needed to ferry 80 people using the given terms, let's set up an inequality. Let's use the variable "v" to represent the number of vans.
Since a van can ferry a maximum of 12 people, we can write the inequality as:
12v ≥ 80
Now, let's solve for "v":
Divide both sides of the inequality by 12.
v ≥ 80/12
Simplify the inequality.
v ≥ 6.67
Since we cannot have a fraction of a van, we need to round up to the nearest whole number:
v ≥ 7
Therefore, the maximum number of vans needed to ferry 80 people is 7 vans.
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Find the missing sector areas and arc lengths.
The areas of the sector in the circle are 18π, 3π, 10π and 5π
Finding the sector areas and arc lengths.The orange sector
This is calculated as
Sector area = central angle/360 * πr²
Where
Radius, r = 6central angle = 180 degreesSo, we have
Sector area = 180/360 * π * 6²
Sector area = 18π
The yellow sector
This is calculated as
Sector area = central angle/360 * πr²
Where
Radius, r = 6central angle = 30 degreesSo, we have
Sector area = 30/360 * π * 6²
Sector area = 3π
The green sector
This is calculated as
Sector area = central angle/360 * πr²
Where
Radius, r = 6central angle = (180 - 50 - 30) = 100 degreesSo, we have
Sector area = 100/360 * π * 6²
Sector area = 10π
The purple sector
This is calculated as
Sector area = central angle/360 * πr²
Where
Radius, r = 6central angle = 50 degreesSo, we have
Sector area = 50/360 * π * 6²
Sector area = 5π
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Can someone help with this math equation from study island…????
The solution of the exponents is shown below.
What is the solution of the exponents?Exponents are mathematical shorthand for multiplying a number by itself a certain number
We have that;
5^n = 1
5^n = 5^0
n = 0
2) 2^-7/2^n = 2^2
2^-7 - n = 2^2
-7 - n = 2
-n = 2 + 7
n = -9
3) 6^5 * 6^n = 6^1
6^ 5 + n = 6^1
5 + n = 1
n = 1 - 5
n = -4
4) (8^n)^7 = 8^21
8^7n = 8^21
7n = 21
n = 3
5) 4^n = (1/4)
4^n = 4^-1
n = -1
In each of the cases, we have applied the laws of the exponents as we know them.
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The equation of the forms are matched as;
2⁻⁷/2ⁿ = 2², n = -9
6⁵ * 6ⁿ = 6. n = -4
(8ⁿ)⁷ = 8²¹, n = 3
4ⁿ = 1/4 , n = -1
What are index forms?Index forms are simply described as mathematical forms that are used to represent numbers of variables that are too large or small.
To multiply index forms, you need to add the exponents of the same bases.
To divide index forms, you need to subtract the exponents of the same bases.
From the information given, we have that;
2⁻⁷/2ⁿ = 2²
cross multiply the values
2⁻⁷ = 2²⁺ⁿ
Then,
-7 = 2 + n
n = -9
6⁵ * 6ⁿ = 6
take the exponents
5 + n= 1
n =- 4
(8ⁿ)⁷ = 8²¹
We have;
7n = 21
Make 'n' the subject
n = 3
4ⁿ = 1/4
4ⁿ = 4⁻¹
n =-1
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What is the solution of |x – 6| ≥ 1? 5 < x < 7 x ≤ –7 or x ≥ –5 x ≤ 5 or x ≥ 7 –7 < x < –5
Answer:
(c) x ≤ 5 or x ≥ 7
Step-by-step explanation:
You want the solution to |x -6| ≥ 1.
UnfoldThe absolute value relation represents two relations, one for the domain x < 6, and one for the domain x ≥ 6.
x < 6In this domain, the inequality becomes ...
-1 ≥ x -6
5 ≥ x . . . . . . add 6
x ≤ 5 . . . . . . . put x on the left
x ≥ 6In this domain, the inequality is ...
x -6 ≥ 1
x ≥ 7
The disjoint solution sets are x ≤ 5 or x ≥ 7.
__
Additional comment
For |x -a| ≤ b, we can "unfold" this to the compound inequality ...
-b ≤ (x -a) ≤ b
copying the inequality symbol to the left side, and writing the opposite of the constant there.
We can do the same thing with the inequality ...
|x -a| ≥ b
but it doesn't really make sense as a compound inequality.
Instead, we have to write it as ...
-b ≥ (x -a) or (x -a) ≥ b
in recognition of the fact that the solution spaces are disjoint.