vSphere Client is used to install and operate the guest OS. true or false

Answer:

/etc/yum.conf

Explanation:

The absolute pathname for YUM is /etc/yum.conf. The configuration file For yum and related utilities can be found there. The file has one compulsory section, and this section can be used to place Yum options with global effect, it could also have one or more sections, that can enable you to set repository-specific options.

Answer:

cell_count = int(input("Enter the value: "))

cell_count *= 10

print(cell_count)

Explanation:

Ask the user to enter a value and set it to the cell_count variable

Multiply the cell_count by 10 and assign it to the cell_count (It can also be written as cell_count = cell_count * 10)

Print the cell_count

Answer:

The programming language is not stated (I'll answer using C++)

#include <iostream>

using namespace std;

int convert(float miles)

{

   return miles * 5280;

}

int main() {

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

   return 0;

}

Explanation:

Here, I'll explain some difficult lines (one after the other)

The italicized represents the function that returns the number of feet

int convert(float miles)

{

   return miles * 5280;

}

The main method starts here

int main() {

The next two lines gives an info about the program

   cout<<"Console:"<<endl;

   cout<<"Hike Calculator"<<endl;

   float miles;

   char response;

This line prompts user for number of miles

   cout<<"How many miles did you walk?. ";

   cin>>miles;

This line calls the function that converts miles to feet and prints the feet equivalent of miles

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

This line prompts user for another conversion

   cout<<"Continue? (y/n): ";

   cin>>response;

This is an iteration that repeats its execution as long as user continue input y as response

   while(response == 'y')

   {

   cout<<"How many miles did you walk?. ";

   cin>>miles;

   cout<<"You walked "<<convert(miles)<<" feet"<<endl;

   cout<<"Continue? (y/n): ";

   cin>>response;

   }

   cout<<"Bye!";

Answer:

The correct answer will be "Virtual networks".

Explanation:

Answer:

The scores array: 70,20,35,15,40

Explanation:

I will explain the code line by line:

var scores = [70, 20, 35, 15];  

The above statement declares and assigns values to an array named scores

scores[scores.length] = 40;  

The above statement uses length to set the length of the scores array. It sets the last element of the scores array to 40. So this means 40 is set as the last element of scores.

scores.length returns the length of the scores array i.e. 4 as there are 4 elements in scores array 70,20,35,15

So the statement becomes:

scores[4] = 40;

This assigns value 40 to the 4th index of the scores array. Do not confuse 4th index with 4th element of the array because array element location starts from 0. So scores[4] does not mean 4th element but scores[4] means 4th index position of scores array. This makes 5th element of scores. So set the element 40 as 5th element at 4th index of scores.

alert("The scores array: " + scores);

This displays an alert box with the following message:

The scores array: 70,20,35,15,40

Complete Question:

Let's say that you handle the IT systems administration for your company. There's a server inside of your organization that checks how often client machines access it. If a client machine hasn't accessed the server in three months, the server won't allow the client machine to access its resources anymore. What can you set to make sure that your client machines and the server times are in sync?

Answer:

Network Time Protocol (NTP).

Explanation:

As the IT systems administrator, you can set the network time protocol (NTP) to make sure that your client machines and the server times are in synchronization.

A network time protocol (NTP) can be defined as an internet standard protocol which is used by an IT system administrator to synchronize a computer's clock to a particular time reference over packet switched or local area network (LAN) and variable-latency data networks. NTP was developed at the University of Delaware by Professor David L. Mills.

Basically, the network time protocol uses the coordinated universal time (UTC) and a client-server model to measure the total round-trip delay for a computer process.

Answer:

public static boolean isPalindrome(String word) {

   //TODO: Complete this method

   String reverse = "";  

       for (int i = (word.length()-1); i>=0; i--) {

           if(word.charAt(i)!=' '){

               reverse+=word.charAt(i);

           }

       }

   String without_space = word.replaceAll(" ", "");

   return reverse.equals(without_space);

   }

Methods are collections of named code blocks, that are executed when called or evoked.

The isPalindrome method written in Java, where comments are used to explain each line is as follows

//This defines the method

public static boolean isPalindrome(String word) {

   //This removes all the spaces in the word

   String newStr = word.replaceAll(" ", "");

   //This initializes an empty string

   String rev = "";  

   //This iterates through the word, in reverse order

   for (int i = (word.length()-1); i>=0; i--) {

       //This gets all the characters in the string (without the space)

       if(word.charAt(i)!=' '){

           rev+=word.charAt(i);

       }

   }

   //This returns true or false

   return reverse.equals(newStr);

}

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Answer:

B

Explanation:

When organizing your career portfolio, you should highlight the skills and experiences most relevant to those thinking of hiring you. Thus, option B is correct.

A combination resume  can be described as the resume format  which was designed for highly-trained job seekers with previous work experience.

In a case whereby a chronological resume lists your work history in reverse order, starting with your current or most recent job and working backwards and many employers like this format because it presents your work history in a clear, easy-to-follow arrangement the type of resume will you choose to use is Combination resume.

It should be noted that it is been reffered to as combination”  as a result of how it combines the most notable features of both the functional resume format and the chronological resume.

Therefore, When organizing your career portfolio, you should highlight the skills and experiences most relevant to those thinking of hiring you. Thus, option B is correct.

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Answer:The new directory method creates a new directory within the current working directory.

Explanation:The new directory function and returns the list of the files within that directory.The new directory function allow to with the built in function MK dir().

To the new directory function create a current working directory.

import OS

OS.MKdir()

The code creates the directory projects in the current working directory to specify the full path.

Answer:

I am writing  a JAVA program. Let me know if you want this program in some other programming language.

import java.util.Scanner;  // class to take input from user

class EvenOddNum{  //class name

   static void EvenOdd(int array[]) {  //function that takes an array as input and displays number of even numbers and odd numbers

       int even = 0;  // counts even numbers      

       int odd = 0;   //counts odd numbers

       for(int i = 0 ; i < array.length-1 ; i++){  //loop through the array elements till the second last array element

           if ((array[i] % 2) == 1) {  // if the element of array is not completely divisible by 2 then this means its an odd  number

               System.out.println(array[i]+" = odd");  //display that element to be odd

               odd++ ; }  //adds 1 to the count of odd every time the program reads an odd number

           else{  // if above IF condition evaluates to false then the number is an even number

                System.out.println(array[i]+" = even"); //display that element to be odd

                even++ ; } }  //adds 1 to the count of odd every time the program reads an odd number

       System.out.println( "Number of even numbers = " + even);  //counts the total number of even integers in the array

       System.out.println( "Number of odd numbers = " + odd);    }   //counts the total number of odd integers in the array      

   public static void main (String[] args){  //start of main function body

       Scanner scan= new Scanner(System.in); //creates Scanner class object

       int [] integers = new int[10];  //declares an array named integers that stores 10 integers

       System.out.print("Enter numbers: ");  //prompts user to enter the integers

       for(int i = 0;i<integers.length;i++){  //loops to read the input integers

           integers[i] = scan.nextInt(); }  //scans and reads each integer value

       EvenOdd(integers);    } }  //calls function EvenOdd to display number of even and odd numbers

Explanation:

The program has a method EvenOdd that takes an array of integers as its parameter. It has two counter variables even and odd. even counts the number of even input integers and odd counts the number of odd input integers. The for loop iterates through each element (integer) of the array except for the last one. The reason is that it is assumed that the input ends with 0 so the last element i.e. 0 is not counted. So the loop iterates to length-1 of the array. The number is odd or even is determined by this if condition: if ((array[i] % 2) == 1) A number is even if it is divisible by 2 otherwise its odd. If the element of array is not completely divisible by 2 i.e. the remainder of the division is not 0 then the number is odd. The modulo operator is used which returns the remainder of the division of number by 2. Each time when an odd or even number is determined, the array[i]+" = even" or  array[i]+" = odd" is displayed on the output screen for each integer in the array. Here array[i] is the element of the array and even or odd depicts if that element is even or odd. The last two print statement display the total number of even and odd numbers in the array.

Answer:

the HTML tag for the paragraph is <p>.

Explanation:

To insert the paragraph in the website, use the <p> tag to start the paragraph and to end the paragraph, use the closing paragraph tag that is </p>.

The paragraph tag is used inside the body tag. for example,

<html>

 <head></head>

 <body>

   <p>this is a paragraph

   </p>

 </body>

</html>

Answer:

Last name: Duck

Explanation:

explanation is provided in the attached document.

Answer:

b. myString[:-5]

d. myString[-15:-5]

Explanation:

I believe you have a typo in d. It must be d. myString[-15:-5]

Slicing can be done:

myString[starting_index, stopping_index, step] (step is optional). If you do not specify the starting index, it will start from the 0 as in b. If you write a range that is not in the range, as in d, Python will replace it with either 0 or length of the string (In this case, it is replaced with 0 because the starting index must be smaller than stopping index)

a. myString[5] → This will give you the sixth character

b. myString[:-5] → This will give you the first five characters

c. myString[0:6] → This will give you the first six characters

d. myString-15:-5] → This will give you the first five characters

e. myString[0:10:2] → This will give you the first, third, fifth, seventh, and ninth characters

Answer:

C. DAT-1

Explanation:

Chain of custody is applied when examining digital evidence and checking for proof that no alterations have been made to the document. It ensures that the original piece of digital evidence which could be in text, image, video, or other electronic formats, is preserved and protected from alterations. Hashing algorithms which are mathematical computations that help to condense files are applied during this procedure.

Common hashing algorithms applied, include;  the message digest 4, secure hashing algorithms 1, 2, 256, 224, 512, etc. The message digest 4 is used to evaluate why a particular piece of evidence was handled by an individual. This is further authenticated by examining the fingerprint.

Answer and Explanation:

A BST is the short form for Binary Search Tree. It is a special type of binary tree data structure in which nodes are arranged in a particular order such that;

i. the left subtree of a particular node should always contain nodes whose key values are less than that of the key value of the node itself.

ii. the right subtree of a particular node should always contain nodes whose key values are greater than that of the key value of the node itself.

iii. the right and left subtrees should also be a binary search tree.

For the given set of data:

36,22,10,44,42,16,25,3,23,24;

The equivalent binary search tree is attached to this response.

As shown in the attachment:

i. the first data value (36) is the root node value.

ii. the second value (22) is less than the root node value (36), therefore, 22 goes to the left of the root node.

iii. the third value is 10. This is less than 36 and then also less than 22, so 10 goes to the left of 22.

iv. the fourth value is 44. This is greater than the root node value (36), therefore, 44 goes to the right of the root node.

v. the fifth value is 42. This is greater than the root value (36) so it is going to be positioned somewhere at the right of the root node. But it is less than the value (44) of the direct right node of the root node. Therefore, 42 goes to the left of the direct right (44) of the root node.

vi. the sixth value is 16. This is less than the root node value (36). So it is going to be positioned somewhere at the left of the root node. It is also less than the value (22) of the direct left node of the root node. So it is going to be positioned somewhere at the left of the node with 22. But it is greater than the node with 10. Therefore, 16 is going to be to the right of the node with 10.

This trend continues until all data values have been rightly positioned.

PS: A binary tree is a data structure in which each node cannot have more than two nodes directly attached to it.

Answer:

The drivers wont be loaded and the deamons will not be running in the background unnecessarily, that makes the processes to run more faster

Explanation:

The chief advantage of deferred configuration or the advantage when some network applications defer configuration until a service is needed is that the drivers won't be loaded and the deamons will not be running in the background unnecessarily or when idle, that makes the processes to run more faster.

Network configuration is the activity which involves setting up a network's controls, flow and operation to assist the network communication of an organization or network owner.

Explanation:

Microsoft Access is an information management tool that helps you store information for reference, reporting, and analysis. Microsoft Access helps you analyze large amounts of information, and manage related data more efficiently than Microsoft Excel or other spreadsheet applications.

A real-life example of a Microsoft Access Query is a table that stores the names of new customers at a supermarket.

Microsoft Access is a database management software application designed and developed by Microsoft Inc., in order to avail its end users an ability to create, store and add data to a relational database.

In Microsoft Access, the options that are available on the File tab include the following:

Opening a database.

Selecting a template.

Creating a new database.

In conclusion, a database is an element in Microsoft Access which is an ideal data source and a query would always obtain, generate, or pick information from it.

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Answer:

Here is the C++ program:

#include <iostream>  //for using input output functions

using namespace std;  //to identify objects like cin cout

class Plane{  //class Plane

private:  // declare private data members i.e. first_class and eco_class

int first_class;  //variable for first class

int eco_class;  //variable declared for economy class

public:  // public access modifier

Plane(){  //constructor to initialize values of first_class and eco_class

first_class=0;  //initialized to 0

eco_class=0;}   //initialized to 0

int getFirst(){  // class method to get data member first_class

return first_class;}   //returns the no of reserved first class seats

int getEco(){  // class method to get data member eco_class

return eco_class;}  //returns the no of reserved eco class seats

void CheckIn(){  //method to handle the check in process

int choice;  //choice between first and economy class

cout<<"\nEnter 1 to select First Class Seat: "<<endl;  //prompts user to enter 1 to reserve first class seat

cout<<"\nEnter 2 to select Economy Class Seat: "<<endl;   //prompts user to enter 2 to reserve economy class seat

cin>>choice;   //reads the choice from user

switch(choice){  // switch statement is used to handle the check in process

case 1:  //to handle the first class seat reservation

if(getFirst()<5){  //if the seat is available and the seat limit has not exceed 5

first_class++;  //add 1 to the first_class seat to count that a seat is reserved

cout<<"You reserved First class seat! ";} //display the message about successful seat reservation in first class

cout<<"\nNumber of first class seats reserved: "<<getFirst()<<endl;}  //displays the number of seats already reserved

else{  //if all first class seats are reserved then display the following message

cout<<"No more seats available for you selection!"<<endl;  

if(getEco()>=5 && getFirst()>=5){  //if all seats from first class and economy class are reserved display the following message

cout<<"All seats are reserved!"<<endl;  

exit(1);}}  //program exits

break;  

case 2:  //to handle the economy seat reservation

if(getEco()<5){   //if the seat is available and the seat limit has not exceed 5

eco_class++;  //add 1 to the eco_class seat to count that a seat is reserved

cout<<"You reserved Economy class seat! "; //display the message about successful seat reservation in economy class

cout<<"\nNumber of Economy class seats reserved: "<<getEco()<<endl;}  //displays the number of seats already reserved

else{  //if all economy class seats are reserved then display the following message

cout<<"No more seats available for you selection!"<<endl;

if(getEco()>=5 && getFirst()>=5){  //if all seats from first class and economy class are reserved display the following message

cout<<"All seats are reserved!"<<endl;

exit(1);}}  //program exits

break;

default: cout<<"Enter a valid choice"<<endl; } } };   //if user enters anything other that 1 or 2 for choice then this message is displayed

int main(){  //start of main() function body

int select;  // choice from first or economy class

Plane plane;  //create an object of Plane class

cout<<"**************************"<<endl;

cout<<"Airline Reservation System"<<endl;  //display this welcome message

cout<<"**************************"<<endl;

while(true){  // while loop executes the check in procedure

plane.CheckIn();} }  //class CheckIn method of Plane classs using plane object to start with the check in process

Explanation:

The program is elaborated in the comments with each statement of the above code. The program has a class Plane that has a method CheckIn to handle the check in process. The user is prompted to enter a choice i.e. enter 1 to select First Class Seat and enter 2 to select Economy Seat. A switch statement is used to handle this process. If user enters 1 then the case 1 of switch statement executes which reserves a seat for the user in first class. If user enters 2 then the case 2 of switch statement executes which reserves a seat for the user in economy class.There are only 5 seats for each First Class and Economy. So when the limit of the seats reservation exceeds 5 then the no more seats available for you selection is displayed. If all the seats are taken in both the first and economy class then it displays the message All seats are reserved. If the user enters anything other than 1 or 2 then display the message Enter a valid choice. Whenever the user reserves one of first or economy class seats the relevant seat is incremented to 1 in order to count the number of seats being reserved. The program and its output are attached.

Answer:

A function is defined before it is first invoked.

Explanation:

A function prototype is a term in computer programming that is used as the declaration of a function that specifies function's name, parameters and return type. However, unlike function itself, which specifies what it does, a function prototype specifies function's interface only and not what it does.

Hence, A function prototype can always be omitted when: a function is defined before it is first invoked.

Answer:

Spear Phishing and War Dialing

Explanation:

So let's tackle these one at a time.

Vishing is simply any type of message (i.e., email, text, phone call, etc.) that appears to be from a trusted source but is not.

Whaling is simply a spear phishing attack of a high-value target such as a CEO or someone with high-level access at a company.

Spear phishing is simply a targeted phishing attack, usually towards a specific person or group of people.  (Phishing attack is simply a social attack to try and gain unauthorized access to a resource).

Pharming is an attack that attempts to redirect website traffic to a fake site.

War dialing is a technique to automatically scan a list of numbers in an area in attempt to search for exposed modems, computers, board systems, or fax machines, in order to breach the network.

Hoaxing is simply a social attack that describes a serious threat in attempts to retrieve unauthorized access or money from a victim.  (Think microsoft tech support scams)

Now that we have defined these things, let's identify the possible threats that need to be reported.

(a) Vishing?  The sec admin report doesn't mention the source of the message so we cannot associate this one

(b) Whaling? The sec admin report says a user, implying someone not high up in the company, but doesn't say it's not someone high up.  This is possible.

(c) Spear phishing?  The sec admin report says a user, implying that only this user is being targeted so this is definitely valid.

(d) Pharming?  The sec admin report says nothing about site redirection.

(e) War dialing? The sec admin report doesn't say anything about unauthorized scanning; however, it mentions the user has an old functioning modem, so this is possible.

(f) Hoaxing?  The sec admin report doesn't mention a pop up in the email or the content of the email so we are uncertain.

Thus with these considerations, the two threats that are identified and need mitigation are Spear phishing and War Dialing/Whaling.  Note that we aren't positive of the war dialing or whaling, but a case could be made for either; however, given the modem information, the question seems to indicate war dialing.

Answer:

//import the Random class

import java.util.Random;

//Begin class definition

public class CoinFlipper {

   //The main method

    public static void main(String []args){

       //Create an object of the Random class

       Random ran = new Random();

       System.out.println("Result");    

       //Use the object and the number of times for simulation

       //to call the flipCoin method

       flipCoin(ran, 25);

    } //End of main method

    //Method to flip coin

    public static void flipCoin(Random ran, int nooftimes){

        //Create a loop to run as many times as specified in variable nooftimes

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}   //End of class definition

====================================================

Sample Output:

Result

1

1

1

2

1

2

2

1

2

1

1

2

1

2

1

1

1

2

1

1

1

2

2

1

2

========================================================

Explanation:

The above code has been written in Java. It contains comments explaining every part of the code. Please go through the comments.

The sample output from the execution of the code is also given above.

The code is re-written as follows without comments.

import java.util.Random;

public class CoinFlipper {

    public static void main(String []args){

       Random ran = new Random();

       System.out.println("Result");    

       flipCoin(ran, 25);

    }

    public static void flipCoin(Random ran, int nooftimes){

       for(int i=1; i<=nooftimes; i++)

           System.out.println(ran.nextInt(2) + 1);

    }

}

Answer:

(B) It allows an attacker to redirect targets to malicious webserver.

(D) It affects any clients querying the poisoned DNS server.

Explanation:

DNS cache poisoning is a serious type of attack that is designed to exploit the vulnerabilities inherent in a Domain Name Server (DNS) where a user is redirected from a real server to a fake one. It is also called DNS spoofing.

Normally, when your browser tries to visits a website through a given domain name, it goes through the DNS server. A DNS server maintains a list of domain names and their equivalent Internet Protocol addresses. This server (DNS) then responds to the request with one or more IP addresses for the browser to reach the website through the domain name.

The computer browser then get to the intended website through the IP address.

Now, if the DNS cache is poisoned, then it has a wrong entry for IP addresses. This might be via hacking or a physical access to the DNS server to modify the stored information on it. Therefore, rather than responding with the real IP address, the DNS replies with a wrong IP address which then redirects the user to an unreal website.

Although they might not be able to control your computer remotely as long as you are not trying to visit a web page via the poisoned information, there are other dangers attached to this type of attack.

Once the DNS server has been poisoned, any client trying to query the server will also be affected since there is no direct way of knowing if the information received from the server is actually correct.

Answer:

when there is no junk

Explanation:

If you choose the checkbox next to “Delete the driver software from this device,” your computer will no longer contain the driver or any associated registry keys. Either method will prevent you from using the device until you reinstall the device driver.

To connect and communicate with particular devices, a computer needs device drivers.

It may be taken out without any trouble. However, it also comes with the installers for your PC's drivers. You will need to go to the manufacturer's website to download them again if you accidentally delete them.

Therefore, No, unless your new driver is broken and corrupts data. Install the driver if it comes from a reliable source. It is not intended to. Having a backup system that keeps your data safe in case of issues is a good idea.

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Answer:just do it

Explanation:

How different quantities are determined

Answer:

2500 kb

Explanation:

Here, we are to calculate the bandwidth delay product

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

Answer:

I am writing a Python program. Here is the function twoWordsV2:

def twoWordsV2 (length,firstLetter):#definition of function which takes length of the first word and first letter of the second word as parameter and returns these two words in a list

   word1 = "" # stores the first word

   word2= "" #holds the second word  

   while(len(word1)!=length): # checks if the input word1 length is not equal to the specified length

       word1 = input('A ' + str(length) + '-letter word please: ') #asks user to enter the input word1 of specified length

   while(word2!=firstLetter): #checks if the first character of input word2 is not equal to the specified firstLetter character

       word2 = input('A word beginning with ' + firstLetter+ ' please: ')#asks user to enter the input word2 begining with specified first letter

       if word2[0] == firstLetter.upper() or word2[0] == firstLetter.lower():#second word may begin with either an upper or lower case instance of firstLetter      

           return [word1,word2] #return the two words in a list                

#to check the working of the function use the following statement        

print(twoWordsV2(4,'B')) #calls twoWordsV2  method by passing 4 (length) and B (first letter)

Explanation:  

twoWordsV2 method has two parameters i.e length which is the length of the first word and firstLetter which is the first character of the the second word. This means the first word should be of specified length, and the second word should begin with a specified first letter. The function returns the two resultant words with the above specifications. These two words are displayed in a list. I will explain the working of the function with the help of an example:

Suppose length = 4 and firstLetter = 'B' and user enters "ok" as word1. input() method takes first word input from user.

The first while loop checks if the length of word1 i.e. ok is not equal to specified length i.e. 4. Length of word1 is checked using len function which returns 2 so length of word1 is 2. The loop condition is true because length of word1 i.e. 2 is not equal to specified length i.e. 4. So the body of the loop executes which displays this message:

A 4-letter word please:

Here notice that str(length) is changed to 4. This is because length=4 and str() converts this value into string.

So the above message keeps displaying until user enters a four letter word. Lets suppose user now enters "four". Now the while loop condition evaluates to false and the loop breaks. The program control  moves to the next line which is a while loop.

The second while loop checks if the first character of input word2 is not equal to the specified firstLetter character. Suppose word2 = "apple" and firstLetter= 'B'

Now the loop condition evaluates to true because word2 is not equal to first letter B. Now the main part of this while loop is the if condition: if word2[0] == firstLetter.upper() or word2[0] == firstLetter.lower() This statement checks if the first index of the word2 is equal to firstLetter. The word2 can contain a capital B or a small B so if condition checks both the cases by using upper and lower methods that converts the firstLetter to upper or lower and then match with the first letter of word2 i.e. the letter at index 0 of the word2. If this condition evaluates to true then next return statement returns the word1 and word2 in a list otherwise the second while loop keep asking user to enter the word2 with starting letter to be firstLetter i.e. 'B'.

The screenshot of the program and its output is attached.

The function for the given problem is:

These 10 lines of code were written using the Python programming language and this was used to define, store and hold the function and then request input from the user, check if the given input was according to the required parameters, and then print the output.

Read more about python programming language here:
https://brainly.com/question/7015522

Answer:

A structure can contain an instance of itself

Explanation:

The statement which is known to be false out of the option given is that a structure may comprise or contain an instance of itself. Because to my knowledge, variables of diverse type are always most likely to attributed and contain by a structure.

It is worthy of note that object that aren't similar are utilize in constructing a structure. Another true statement about structure is that a semicolon usually end it's explanation.

Answer:

c. suffer from indefinite postponement.

Explanation:

Algorithm is a set of rules that are followed in calculations or other problem solving operation by a computer. An algorithm may execute for unknown amount of time and it may suffer indefinite postponement. Algorithm depends on random numbers and it can execute continuously.

Answer:

Bandwidth delay product = 2500 Kbits

Utilization = 0.02%

Explanation:

We proceed as follows;

From the question, we are given that

band width = 500 Mbps

The bandwidth-delay product is = 500 x 10^6 x 25 x 10^-3

= 2500 Kbits

The system can send 12500 Kbits during the time it takes for the data to go from the sender to the receiver and then back again.

However, the system sends only 2500 bits.

The the link utilization =

2500/(12500 x 10^3) = 0.02%

Answer:

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is (c)251? correct since i'm not really sure