Use variation of parameters to find the particular solution to y''+y' - 12y = - 340 sin(t) Y(t) =

The distance from P to the airplane is y = x + 100 ≈ 628.38 m.

A triangle is a three-sided polygon with three angles. It is a fundamental geometric shape and is often used in geometry and trigonometry.

From a certain point Q on a straight road, which forms an angle of 22° with the horizontal, the angle of elevation of an airplane at point A is 57°. At the same instant from another point Q, 100 meters ahead of the first point, the angle of elevation of the airplane is 63°. The points P, Q, and A are in the same vertical plane. Find the distance from P to the airplane.

To solve the problem, we can use the concept of similar triangles. Let's call H the height of the airplane and x the distance from Q to the airplane. Then, the distance from P to the airplane is given by y = x + 100.

From triangle QA1H, we have:

tan(57°) = H / x

From triangle QA2H, we have:

tan(63°) = H / (x + 100)

Dividing these two equations, we get:

tan(57°) / tan(63°) = x / (x + 100)

Solving for x, we get:

x = 100 * tan(63°) / (tan(63°) - tan(57°)) ≈ 528.38 m

Therefore, the distance from P to the airplane is:

y = x + 100 ≈ 628.38 m.

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The correct answer is: c. null: mu1 - mu2 = 0; alternative: mu1 - mu2 is not equal to 0

The null hypothesis states that there is no significant difference in the mean lifespan of people in the two towns, while the alternative hypothesis states that there is a significant difference in the mean lifespan of people in the two towns.

Since we are comparing the means of two populations, we use the difference between the means as the test statistic. Therefore, the null hypothesis is mu1 - mu2 = 0 (there is no difference between the means) and the alternative hypothesis is mu1 - mu2 is not equal to 0 (there is a difference between the means).

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The Sample size that is necessary for the selection is =7203

Given that,

[tex]\hat p= 0.25[/tex]

[tex]1 - \hat p = 1 - 0.25 = 0.75[/tex]

margin of error = E = 0.01

At 95% confidence level the z is ,

\alpha = 1 - 95% = 1 - 0.95 = 0.05

[tex]\alpha / 2 = 0.05 / 2 = 0.025[/tex]

Z\alpha/2 = Z0.025 = 1.96 ( Using z table )

Sample size = n = [tex](Z\alpha/2 / E)2 * \hat p * (1 - \hat p)[/tex]

= (1.96 / 0.01)2 * 0.25 * 0.75

= 7203

Sample size =7203

In statistics, the sample size is the measure of the number of individual samples used in an experiment.

The size of the sample holds significant importance in any empirical study that aims to draw conclusions about a larger population based on a smaller sample.

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The solution to the equation √8x + 4 = 6 is x = 0.5.

An equation is simply a mathematical formula that expresses the equality of two expressions, using the equals sign as a connection between them.

Given the equation in the question:

√8x + 4 = 6

To solve for x in the equation, isolate the term containing the variable x.

Subtract 4 from both sides of the equation:

√8x + 4 - 4 = 6 - 4

√8x = 6 - 4

√8x = 2

Square both sides of the equation:

( √8x )² = 2²

8x = 4

Divide both sides of the equation by 8:

x = 4/8

x = 1/2

x = 0.5

Therefore, the value of x is 0.5.

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To determine if two lines intersect, compare their slopes and y-intercepts, and solve their equations simultaneously.

To determine if two lines intersect, you need to compare their key features, such as their slope and y-intercept.

If the slopes of the two lines are different, then they will intersect at some point.

If the slopes are the same, then the lines may or may not intersect, depending on whether or not their y-intercepts are also the same.

To find the point of intersection, you can set the two linear functions equal to each other and solve for the variable. The resulting value will give you the x-coordinate of the intersection point, which can then be substituted back into either equation to find the corresponding y-coordinate.

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Answer:

2.2

Step-by-step explanation:

To find your GPA, use the attached image:

After you've written down your numerical scores, divide it by the total classes you're taking, which is 7.

So, your GPA is 2.2

The linear equation from the given scatterplot will be y = -0.1x + 9.

On the given scatterplot we have the song released details on the x-axis and the average rating of the songs by the family members on the y-axis.

To get the linear equation from the given scatterplot we have to find the y-intercept of the equation.

The general form of the equation is y = mx + c

here, m is the slope and c is the y-intercept.

By, the given graph we can say that y is intercepting at the value '9'. So, the y-intercept is 9.

To find the slope we have to take two points,

Let's take two points as (1970, 7) and (1990, 5).

From the points slope = (5-7)/(1990-1970)

                                     = -2/20 = -1/10 = -0.1

So, the equation from the given scatterplot is y = mx+c

So, y = -0.1x + 9.

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Adding another 12 to the data set would increase the sum of the values by 12, resulting in a new sum of 239. To find the new mean, we divide the new sum by the total number of values in the set, which is now 8. So the new mean would be 29.875, which is slightly lower than the original mean of 31.6.

To find the new median, we first need to rearrange the values in ascending order: 12, 18, 26, 32, 41, 46, 46, 12. Since there are now an even number of values, we take the average of the middle two, which in this case is (26 + 32) / 2 = 29. So the new median would be 29, which is lower than the original median of 32.

In summary, adding another 12 to the data set would slightly decrease the mean and lower the median.

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first off, let's look at the equation of the circle

[tex]\textit{equation of a circle}\\\\ (x- h)^2+(y- k)^2= r^2 \hspace{5em}\stackrel{center}{(\underset{}{h}~~,~~\underset{}{k})}\qquad \stackrel{radius}{\underset{}{r}} \\\\[-0.35em] ~\dotfill\\\\ (x-\stackrel{h}{3})^2+(y-\stackrel{k}{7})=169\implies (x-\stackrel{h}{3})^2+(y-\stackrel{k}{7})=\stackrel{ r }{13^2}[/tex]

so we have a circle centered at (3 , 7) with a radius of 13, Check the picture below.

so the line we want is the line in purple, which is tangential to the circle and therefore perpendicular to the blue line.

keeping in mind that perpendicular lines have negative reciprocal slopes, let's check for the slope of the blue line

[tex](\stackrel{x_1}{3}~,~\stackrel{y_1}{7})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{2}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{2}-\stackrel{y1}{7}}}{\underset{\textit{\large run}} {\underset{x_2}{15}-\underset{x_1}{3}}} \implies \cfrac{ -5 }{ 12 } \implies - \cfrac{5 }{ 12 } \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{~\hspace{5em}\textit{perpendicular lines have \underline{negative reciprocal} slopes}~\hspace{5em}} {\stackrel{slope}{ \cfrac{-5}{12}} ~\hfill \stackrel{reciprocal}{\cfrac{12}{-5}} ~\hfill \stackrel{negative~reciprocal}{-\cfrac{12}{-5} \implies \cfrac{12}{ 5 }}}[/tex]

so we're really looking for the equation of a line whose slope is 12/5 and it passes through (15 , 2)

[tex](\stackrel{x_1}{15}~,~\stackrel{y_1}{2})\hspace{10em} \stackrel{slope}{m} ~=~ \cfrac{12}{5} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{2}=\stackrel{m}{ \cfrac{12}{5}}(x-\stackrel{x_1}{15}) \\\\\\ y-2=\cfrac{12}{5}x-36\implies {\Large \begin{array}{llll} y=\cfrac{12}{5}x-34 \end{array}}[/tex]

Let's evaluate the limit using l'Hôpital's Rule when it is convenient and applicable:

The evaluated limit using l'Hôpital's Rule is 5.

Given limit,

lim (x -> 0) (sin(5x) / x)

Since both the numerator and denominator approach 0 as x approaches 0,

we can apply l'Hôpital's Rule.

Step 1: Differentiate the numerator and the denominator with respect to x.
- Derivative of sin(5x) with respect to x: 5*cos(5x)
- Derivative of x with respect to x: 1

Step 2: Apply l'Hôpital's Rule:
lim (x -> 0) (5*cos(5x) / 1)

Step 3: Evaluate the limit:
As x approaches 0, cos(5x) approaches cos(0) = 1.

Therefore, the limit is: 5*1 = 5

So, the evaluated limit using l'Hôpital's Rule is 5

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Answer:

y = 9

Step-by-step explanation:

• Parallel lines have equal slopes

calculate the slope m of  TU using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = T(- 7, 4 ) and (x₂, y₂ ) = U(- 2, - 6 )

[tex]m_{TU}[/tex] = [tex]\frac{-6-4}{-2-(-7)}[/tex] = [tex]\frac{-10}{-2+7}[/tex] = [tex]\frac{-10}{5}[/tex] = - 2

now calculate the slope of VW and equate to - 2

with (x₁, y₁ ) = V(8, 7 ) and (x₂, y₂ ) = W(7, y )

[tex]m_{VW}[/tex] = [tex]\frac{y-7}{7-8}[/tex] = [tex]\frac{y-7}{-1}[/tex]

now equating gives

[tex]\frac{y-7}{-1}[/tex] = - 2 ( multiply both sides by - 1 to clear the fraction )

y - 7 = 2 ( add 7 to both sides )

y = 9

The graph of the function will touch the x-axis at x = -5, but not cross it, and the behavior of the graph near x = -5 will be determined by the degree of the zero (which is 3 in this case).

The polynomial function that represents the volume of a sphere with radius x+5 is given by:

[tex]V(x) = (4/3)\pi (x+5)^3[/tex]

To find the multiplicity of the zero, we need to factor out the (x+5) term from the polynomial:

V(x) = (4/3)π(x+5)(x+5)(x+5)

We can see that the zero is x = -5, and it has a multiplicity of 3, since there are three factors of (x+5) in the polynomial.

This means that the graph of the function will touch the x-axis at x = -5, but not cross it, and the behavior of the graph near x = -5 will be determined by the degree of the zero (which is 3 in this case).

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Answer:

Problem 8:
Option C)       DE = √21

Problem 9:
Option C)     Perimeter = 30 cm

Step-by-step explanation:

1. Problem 8

Draw a line segment connecting the center of the circle, X, to A. This is the radius of the circle

The points ABX form a right triangle with AX as the hypotenuse and AB, BX as the legs of the right triangle

By the Pythagorean theorem
hypotenuse² = sum of the squares of the two legs

Plugging in line segment references

AX² = AB² + BX²

We are given AC = 8, BX = 3

Since the segment BX intersects AC at right angles, AB = BC = AC/2

So AB = 8/2= 4

Plugging these values into the Pythagorean formula
AX² = AB² + BX²

AX² = 4² +3²

AX² = 16 + 9

AX² = 25

Draw a line connecting X and D
The points DEX form a right triangle with DX as the hypotenuse and EX and DE as the legs

Again, by the Pythagorean theorem

DX² = DE² + EX²

But DX is the radius of the circle so it must be the same as AX

Substitute for DX in terms of AX
DX² = DE² + EX²

=> AX² = DE² + EX²

But AX² = 25 and EX = 2 giving EX² = 4

Therefore

AX² = DE² + EX² becomes
25 = DE² + 4

DE² = 25 - 4

DE² = 21

DE = √21

This is choice C

Problem 9

To find the perimeter, just add up the individual side lengths:

Perimeter = 10 + 8 + 7 + 5 = 30 cm

Option C

The opening of the pail has a diameter of approximately 55.4 inches (since it's twice the diameter of the base).

Based on the information you provided, it sounds like you have some great supplies for making sand castles at the beach with your friends.

Firstly, let's take a look at the pail. You mentioned that it has a base with a circumference of 87 inches, which means that the diameter of the base is approximately 27.7 inches (since circumference = pi x diameter). The pail is also 12 inches tall and has an opening on top that is twice the diameter of the base. Therefore, the opening has a diameter of approximately 55.4 inches (since it's twice the diameter of the base). With these measurements, you can use the pail to make some pretty big sand castles!

Next, you mentioned a plastic pyramid mold that has a square base with an edge that measures 6 inches and is 7 inches tall. This mold should be perfect for making pyramid-shaped sand castles. Just fill it with sand, pack it down, and carefully remove the mold to reveal your pyramid!

Finally, you mentioned an empty soup can with a diameter of 5.25 inches and is 6.5 inches tall. This can could be used to make cylindrical shapes in your sand castles. Simply pack sand around the can, press down firmly, and carefully remove the can to reveal your cylinder.

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The number of times that the little monsters will do an overhead press and a squat at the same instant  during the drill is: 3 times

We are told that, Rote tells the little monsters to carry out an overhead press every 12 seconds and then also a squat every 30 seconds.

Thus, prime factorization of 12: 2² x 3.

Thus, prime factorization of 30: 2 x 3 x 5.

For us to get the least common multiple, we will have to find the highest power of each of the prime factors that show up in either factorization. Therefore, we can say that the smallest common multiple of 12 and 30 are: 2² x 3 x 5 = 60

This tells us that the little monsters will carry out an overhead press and then a squat at the same instant for every 60 seconds.

For us to find how many times this will occur during the 200-second drill, we will then divide 200 by 60:

200 ÷ 60 = 3 remainder 20

This tells us that there will exist 3 complete cycles of both of the exercises during the 200-second drill, with an additional 20 seconds left over.

Therefore, we can say that the little monsters will do an overhead press and a squat at the same instant 3 times during the drill.

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In ΔMNO, possible values of ∠N are 64.6° and 115.4°.

To find the possible values of ∠N, follow these steps:

1. Since the sum of angles in a triangle is 180°, we first find ∠O by subtracting ∠M from 180°: 180° - 38° = 142°.

2. Next, we use the Law of Sines to find the sine of ∠N: sin(∠N) = (n * sin(∠O)) / m = (88 * sin(142°)) / 60.

3. Solve for sin(∠N), which gives us two possible values: sin(∠N) ≈ 0.8988 and sin(∠N) ≈ -0.8988.

4. Find the inverse sine (arcsin) of both values to get the possible angles for ∠N: arcsin(0.8988) ≈ 64.6° and arcsin(-0.8988) ≈ 115.4° (adding 180° to the negative result).

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Answer:

f¹(12) = 20

Step-by-step explanation:

f(-2) = 24

f(-1) = 17

f(0) = 12

f(1) = 9

f¹(x) = 2x - 4

f¹(12) = 20

In order for a triangle to be acute, the relationship that c² must have with a² + b² is c² < a² + b².

An acute triangle is a triangle in which all three angles are acute angles, which means they are less than 90 degrees. In other words, an acute triangle is a triangle with three acute angles.

To understand why the relationship between c^2 (the square of the longest side) and a^2 + b^2 (the sum of the squares of the other two sides) is important in determining whether a triangle is acute, we need to delve into the concept of the Pythagorean theorem.

The Pythagorean theorem states that in a right triangle, the square of the length of the hypotenuse (the longest side) is equal to the sum of the squares of the other two sides. Mathematically, it can be expressed as c^2 = a^2 + b^2, where c represents the hypotenuse, and a and b represent the other two sides.

In an acute triangle, the sum of the squares of the two shorter sides must be greater than the square of the longest side.

This can be visualized as follows: If we were to draw a right triangle with the shorter sides represented by segments a and b, and the longest side represented by segment c, the acute triangle would be formed by making the length of segment c shorter than the length determined by the Pythagorean theorem. This ensures that the angle opposite to the longest side remains acute.

On the other hand, if c^2 were equal to a^2 + b^2, we would have a right triangle, not an acute triangle. If c^2 were greater than a^2 + b^2, we would have an obtuse triangle since the angle opposite to the longest side would be greater than 90 degrees.

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Answer: y = 1.4

Step-by-step explanation:

if you write the equation it would be

-5y - 4 = -11

so first you would subtract 4 from -4 and -11 to cancel out the four.

so your equation would look like this -5y= -7

so now u would divide -5 by both sides to canceled out the -5

your equation should end up looking like

y=1.4

The distance where the ladder is touching the building for triangle 2 is 12 ft

From the question, we have the following parameters that can be used in our computation:

Ladder 1

Distance along the ground = 12 ft

Distance touching the ladder = 8 ft

Ladder 2

Distance along the ground = 18 ft

Distance touching the ladder = x

Using proportion of similar triangles, we have

x : 18 = 8 : 12

Express as fraction

x/18 = 8/12

So, we have

x = 18 * 8/12

Evaluate

x = 12

Hence, the distance where the ladder is touching the building for triangle 2 is 12 ft

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Answer:

12?

Step-by-step explanation:

Not too sure! I am in the middle of taking the test right now though

The height of the antenna is approximately 17 meters.

To solve for the height of the antenna, we need to use trigonometry. Let's call the height of the antenna "h".

First, we need to find the distance from point A to point B. We can use the angle of elevation from her eyes to the roof (17°) and the horizontal distance from the building (29m) to find the height of the building.

tan(17°) = height of building / 29m

height of building = 29m * tan(17°)

height of building = 8.20m

Now we can use the height of the building and the angle of elevation from her eyes to the top of the antenna (31°) to find the distance from point A to point B.

tan(31°) = h / 29m + 8.20m

h = (29m + 8.20m) * tan(31°)

h = 15.51m

Finally, we need to add the height of Bilquis' eyes to the height of the antenna to find the total height.

total height = h + 1.51m

total height = 17.02m

Therefore, the height of the antenna is approximately 17 meters.

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The next model airplane will be 16 feet long.

To find the length of Aura's next model airplane, we need to multiply the length of her first model airplane by 4, since she wants the next one to be 4 times as long as the first. Therefore, the length of her next model airplane would be:

4 feet (length of first model airplane) x 4 = 16 feet

So, the length of her next model airplane would be 16 feet.

Note that this assumes that Aura's first model airplane is the baseline for measurement and that the "4" in the question refers to a factor of 4, not an additional 4 feet. If the question were interpreted differently, the answer may be different.

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Answer:

Its 12

Step-by-step explanation:

1.   Following PEMDAS, we first solve the equation inside the parentheses.

       -4(-2) = 8

       -12 ÷ 3 = -4

       -20 + 4 = -16

2.    Now, we have the following expression:

       8 + (-4) + (-16)

 3.  Again, following PEMDAS, we solve the equation inside the parentheses first.

       8 + (-4) + (-16) = 8 - 4 - 16

  4. Finally, we solve the equation from left to right.

       8 - 4 - 16 = 8 - (4 + 16)

       8 - (20) = -12

Therefore, the value of the expression is -12.

The independent variable in the study is the  temperature of the water

The variable that the experimenter consciously modifies or changes is known as the independent variable.

The variable that is supposed to have an impact on the dependent variable is this one. After then, the dependent variable is assessed and recorded to see if it changes as a result of the independent variable's manipulation.

The temperature was changed before each trial hence the temperature was manipulated and that is the independent variable.

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Step-by-step explanation:

First start with the graph of    y = | x|

  then shift it RIGHT one unit

         | x -1 |

  then shift it DOWN one unit

  y=   |x-1| -1

Answer:

AEC is similar to BDC in terms of the type of triangle

That's all I can really say

I hope this helps :)

The point where line A intersects line B is [2, 10].

In Mathematics and Geometry, the point-slope form of a straight line can be calculated by using the following mathematical expression:

y - y₁ = m(x - x₁)

Where:

At data point (1, 10 1/3) and a slope of -1/3, a linear equation for this line can be calculated or determined by using the point-slope form as follows:

y - y₁ = m(x - x₁)

y - 10 1/3 = -1/3(x - 1)

y - 31/3 = -x/3 + 1/3

For Line B, we have:

y - y₁ = m(x - x₁)

y - (-2) = 1/3(x - (-34))

y + 2 = x/3 + 34/3

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The integral ∫(5/5)dx/√[86(x^2 - x^2)] converges to 5 since the denominator becomes 0 at x=0, which is not in the interval of integration [5,5].

We can start by simplifying the integrand

∫(5/5)dx/√[86(x^2 - x^2)]

Using the identity a^2 - b^2 = (a + b)(a - b), we can rewrite the denominator as

√[86(x^2 - x^2)] = √[86(x + x)(x - x)] = √[86] * √[x + x] * √[x - x] = √[86] * √[2x] * √[0] = 0

Therefore, the integrand is undefined when x = 0. Since the interval of integration is [5,5], which does not include 0, the integral is well-defined and converges to 5.

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