Use undetermined coefficients to find the particular solution to
y' +41 -53 = - 580 sin(2t)
Y(t) = ______

Answers

Answer 1

To find the particular solution to this differential equation using undetermined coefficients, we first need to guess the form of the particular solution. Since the right-hand side of the equation is a sinusoidal function, our guess will be a linear combination of sine and cosine functions with the same frequency:

y_p(t) = A sin(2t) + B cos(2t)

We can then find the derivatives of this guess:

y'_p(t) = 2A cos(2t) - 2B sin(2t)
y''_p(t) = -4A sin(2t) - 4B cos(2t)

Substituting these into the differential equation, we get:

(-4A sin(2t) - 4B cos(2t)) + 41(2A cos(2t) - 2B sin(2t)) - 53(A sin(2t) + B cos(2t)) = -580 sin(2t)

Simplifying and collecting terms, we get:

(-53A + 82B) cos(2t) + (82A + 53B) sin(2t) = -580 sin(2t)

Since the left-hand side and right-hand side of this equation must be equal for all values of t, we can equate the coefficients of each trigonometric function separately:

-53A + 82B = 0
82A + 53B = -580

Solving these equations simultaneously, we get:

A = -23
B = -15

Therefore, the particular solution to the differential equation is:

y_p(t) = -23 sin(2t) - 15 cos(2t)

Adding this to the complementary solution (which is just a constant, since the characteristic equation has no roots), we get the general solution:

y(t) = C - 23 sin(2t) - 15 cos(2t)

where C is a constant determined by the initial conditions.
To solve the given differential equation using the method of undetermined coefficients, we need to identify the correct form of the particular solution.

Given the differential equation:
y'(t) + 41y(t) - 53 = -580sin(2t)

We can rewrite it as:
y'(t) + 41y(t) = 53 + 580sin(2t)

Now, let's assume the particular solution Y_p(t) has the form:
Y_p(t) = A + Bsin(2t) + Ccos(2t)

To find A, B, and C, we will differentiate Y_p(t) with respect to t and substitute it back into the differential equation.

Differentiating Y_p(t):
Y_p'(t) = 0 + 2Bcos(2t) - 2Csin(2t)

Now, substitute Y_p'(t) and Y_p(t) into the given differential equation:
(2Bcos(2t) - 2Csin(2t)) + 41(A + Bsin(2t) + Ccos(2t)) = 53 + 580sin(2t)

Now we can match the coefficients of the similar terms:
41A = 53 (constant term)
41B = 580 (sin(2t) term)
-41C = 0 (cos(2t) term)

Solving for A, B, and C:
A = 53/41
B = 580/41
C = 0

Therefore, the particular solution is:
Y_p(t) = 53/41 + (580/41)sin(2t)

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Related Questions

Isabella grows two types of pepper plants. The following dot plots show the numbers of peppers, rounded to the nearest
5
55, per plant for each type. Each dot represents a different plant. Compare the typical number of peppers per plant. In general, the

had more peppers, with

per plant

Answers

The possible values of x that satisfy the equation |x+5| = c are x = c - 5 and x = -c - 5.

what is algebra?

Algebra is a branch of mathematics that deals with mathematical operations and symbols used to represent numbers and quantities in equations and formulas.

How could you use a set of coin flips to simulate this situation?

Answers

Answer:

Let heads represent a person who exercises the given amount, and let tails represent a person who doesn’t. Because there are three people, flip the coin three times (once for each person) and note the results of each set of three flips. If all three flips land on tails, it would mean that all three randomly selected people do not exercise as much as 50% of Americans do.

Step-by-step explanation:

The ratios of successive numbers in the Fibonacci sequence eventually get closer to which number?


a.


1. 61


c.


2. 3


b.


1. 46


d.


1

Answers

The ratios of successive numbers in the Fibonacci sequence eventually get closer to a. 1.61


In mathematics, the Fibonacci sequence is a sequence in which each number is the sum of the two preceding ones. Numbers that are part of the Fibonacci sequence are known as Fibonacci numbers, commonly denoted Fn . The sequence commonly starts from 0 and 1, although some authors start the sequence from 1 and 1 or sometimes (as did Fibonacci) from 1 and 2.

The Fibonacci sequence is a series of numbers where each number is the sum of the two preceding ones, usually starting with 0 and 1 (0, 1, 1, 2, 3, 5, 8, 13, ...). When you take the ratio of successive numbers in the sequence (e.g., 5/3 or 8/5), it converges to approximately 1.618, also known as the Golden Ratio or Phi.

The closest option in your list is 1.61, which is option (a).

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a norman window is a window with a semicircle on top of a regular rectangular window as shown in the diagram.what should the dimensions of the rectangular part of the norman window be to allow in as much light as possible if there is only 12 ft of framing material available

Answers

Answer: The dimensions of the rectangular part of the Norman window that would allow in as much light as possible, given 12 feet of framing material available, are approximately 4 feet by 8 feet.

Explanation:

Let's assume that the height of the rectangular part of the Norman window is "h" and the width is "w". Then the diameter of the semicircle is also "w". The total amount of framing material needed is the sum of the perimeter of the rectangular part and half the circumference of the semicircle:

Perimeter of rectangular part = 2h + 2w

Circumference of semicircle = 1/2πw

Total framing material = 2h + 2w + 1/2πw

We want to maximize the amount of light entering the window, which is proportional to the area of the rectangular part of the window. The area of the rectangular part is given by:

Area of rectangular part = hw

Now we can use the constraint that there is only 12 feet of framing material available:

2h + 2w + 1/2πw = 12

Solving for h in terms of w:

h = (12 - 2w - 1/2πw)/2

Substituting this expression for h into the formula for the area of the rectangular part:

Area of rectangular part = w(12 - 2w - 1/2πw)/2

We can now use calculus to find the value of w that maximizes this area. Taking the derivative of the area with respect to w and setting it equal to zero:

d/dw[w(12 - 2w - 1/2πw)/2] = 0

Simplifying and solving for w:

w = 4π/(4 + π)

Substituting this value of w into the expression for h:

h = (12 - 2w - 1/2πw)/2

h ≈ 8

Therefore, the dimensions of the rectangular part of the Norman window that allow in as much light as possible, given 12 feet of framing material available, are approximately 4 feet by 8 feet.

Use Lagrange multipliers to find the indicated extrema, assuming that x, y, and z are positive.
Maximize: f(x, y, 2) = xyz
Constraint: × + y + z - 6 = 0
f = _____

Answers

To use Lagrange multipliers, we need to set up the Lagrangian function, Therefore, the maximum value of f(x,y,2) = xyz subject to the constraint x+y+z-6=0 is f(2,2,2) = 8.

L(x,y,z,λ) = xyz + λ(x+y+z-6)
Then we need to find the critical points of L by setting its partial derivatives equal to zero:
∂L/∂x = yz + λ = 0
∂L/∂y = xz + λ = 0
∂L/∂z = xy + λ = 0
∂L/∂λ = x + y + z - 6 = 0
Solving this system of equations, we get:
x = y = z = 2
λ = -4
This critical point satisfies the constraint, since 2+2+2-6 = 0. To check whether it is a maximum or minimum, we need to use the second partial derivative test:
∂²L/∂x² = 0, ∂²L/∂y² = 0, ∂²L/∂z² = 0
∂²L/∂x∂y = z, ∂²L/∂x∂z = y, ∂²L/∂y∂z = x

The Hessian matrix is:
| 0  z  y |
| z  0  x |
| y  x  0 |
At the critical point (2,2,2), the Hessian matrix is:
| 0  2  2 |
| 2  0  2 |
| 2  2  0 |
The eigenvalues of this matrix are -4, -4, and 8. Since the eigenvalues are not all positive or all negative, we cannot conclude whether the critical point is a maximum or minimum.
Therefore, the maximum value of f(x,y,2) = xyz subject to the constraint x+y+z-6=0 is f(2,2,2) = 8.

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Jamie McAllister is a wonderful rebounder for her high school basketball team. Of


her final 10 games, here are her rebound totals for each game:


8 12 8 11 15 6 9 8 10 13


1.


2.


From the collected data, what


is the mean number of


rebounds Jamie had per


game?


From the collected data, what


is the median number of


rebounds Jamie had for her


final 10 games?

Answers

Step-by-step explanation:

1. To find the mean number of rebounds Jamie had per game, we need to add up all the rebounds she had and then divide by the total number of games played:

Mean = (8 + 12 + 8 + 11 + 15 + 6 + 9 + 8 + 10 + 13) / 10

Mean = 100 / 10

Mean = 10

Therefore, the mean number of rebounds Jamie had per game was 10.

2. To find the median number of rebounds Jamie had for her final 10 games, we need to first arrange the data in order from least to greatest:

6, 8, 8, 8, 9, 10, 11, 12, 13, 15

Since there are an even number of data points, the median will be the average of the two middle values, which are 9 and 10:

Median = (9 + 10) / 2

Median = 9.5

Therefore, the median number of rebounds Jamie had for her final 10 games was 9.5.

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thank you !!!!!!!! (Choose ALL answers that are correct)

Answers

Answer:

a and b

Step-by-step explanation:

A and B is going to be your answer. Have a great day

The number of hours julie practices her violin each week, y, is 3 hrs more than the numbers of hours she studies, x. write an equation to show the relationship of the two activities.

Answers

The equation is y = x + 3 which shows the relationship of the two activities.

The equation to show the relationship between the number of hours Julie practices her violin each week (y) and the number of hours she studies (x) is:

y = x + 3

This means that the number of hours Julie practices her violin each week is equal to the number of hours she studies, plus three additional hours.

A linear equation is an equation that represents a straight line on a graph. It can be written in the form:

y = mx + b

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A scientist recorded the movement of a pendulum for 12 s. The scientist began recording when the pendulum was at its resting position. The pendulum then moved right (positive displacement) and left (negative displacement) several times. The pendulum took 6 s to swing to the right and the left and then return to its resting position. The pendulum’s furthest distance to either side was 7 in. Graph the function that represents the pendulum’s displacement as a function of time. (a) Write an equation to represent the displacement of the pendulum as a function of time. (B) Graph the function. (Please help me answer this for my friend. I am so baffled)

Answers

The equation for the displacement of the pendulum as a function of time is: displacement = 7 sin(π/3 t)

How to explain the equation

The motion of a pendulum can be modeled using a sine function:

displacement = A sin(ωt + φ)

where A is the amplitude (the furthest distance from the equilibrium point), ω is the angular frequency (related to the period T by ω = 2π/T), t is time, and φ is the phase angle (determines the starting point of the oscillation).

In this case, the pendulum has an amplitude of 7 inches and a period of 6 seconds (since it takes 6 seconds to swing to one side and then back to the other). Therefore, the angular frequency is:

ω = 2π/T = 2π/6 = π/3

The phase angle is 0, since the pendulum starts at its equilibrium position.

So, the equation for the displacement of the pendulum as a function of time is:

displacement = 7 sin(π/3 t)

where t is measured in seconds and the displacement is measured in inches.

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Zola wrote the area of the rectangle as `2a+3a+4a`.



amir wrote the area as `(2+3+4) a.





explain why they are both correct


please help as quickly as possible


assp

Answers

Both Zola and Amir are correct in writing the area of the rectangle. They have simply used different ways of expressing the same value.

Zola and Amir have both written the area of a rectangle using different algebraic expressions.

Zola wrote the area of the rectangle as `2a + 3a + 4a`, which can be simplified using the distributive property of multiplication:

2a + 3a + 4a = (2 + 3 + 4)a

Therefore, Zola's expression simplifies to `(2 + 3 + 4)a`, which is the same as Amir's expression.

Amir wrote the area of the rectangle as `(2 + 3 + 4) a`, which can also be simplified:

(2 + 3 + 4) a = 9a

Therefore, Amir's expression simplifies to `9a`, which is the same as the sum of the terms in Zola's expression.

Therefore, both Zola and Amir are correct in writing the area of the rectangle. They have simply used different ways of expressing the same value.

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Maryam scored 86. 7% on a test with 30 questions on


it. How many questions did Maryam get wrong?


Help!

Answers

Maryam answered 26 questions correctly and got 4 questions wrong on the test with 30 questions.

How many questions did Maryam answer incorrectly?

To find how many questions Maryam got wrong, we need to first determine how many questions she got right. Since she scored 86.7%, we can multiply the total number of questions by the percentage to get the number of questions she answered correctly.

86.7% of 30 questions is (86.7/100) * 30 = 26.01 questions.

Since Maryam cannot have answered a fractional number of questions correctly, we round down to the nearest whole number. Thus, she answered 26 questions correctly.

To find out how many questions she got wrong, we can simply subtract the number of questions she got right from the total number of questions. Therefore, Maryam got 30 - 26 = 4 questions wrong.

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Now that you are commuting to work every day, you are considering buying a new car. However, you are undecided if you should invest in a new car or just keep the one you have. You have heard that cars depreciate a lot, and you don't want to waste your hard earned money.


Let's do a little investigating to see if cars really do depreciate and if so, by how much.


Decide on a used automobile that you would like to purchase. Find the auto in an advertisement in the newspaper, car magazine, or internet. You must attach a copy of the advertisement to your work. The vehicle must be at least 3 years old

Answers

It's essential to consider the depreciation rate when deciding whether to invest in a new car or keep your current one.

Cars typically depreciate, and the amount can vary depending on factors such as make, model, and age.

For this example, let's assume you're interested in purchasing a 3-year-old used Honda Accord. I found an advertisement for this vehicle online, but since I cannot attach a copy here, please search for a similar advertisement and include it with your work.

It's common for new cars to depreciate by approximately 20-30% in the first year, and around 10-15% each subsequent year. So, a 3-year-old car may have already experienced around 40-60% of its total depreciation.

After researching, the used 3-year-old Honda Accord is priced at $18,000. If you compare it to the price of a new Honda Accord, which starts around $25,000, you can see that there has been a considerable depreciation in value.

In conclusion, cars do depreciate, and the rate can vary depending on the vehicle's age and other factors. In this case, a 3-year-old Honda Accord has already experienced significant depreciation, making it a more affordable option compared to buying a brand new car.

Considering depreciation can help you make an informed decision when deciding between a new or used car.

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The function f(x) = 2x + 7x{-1} has one local minimum and one local maximum. This function has a local maximum at x = with value and a local minimum at x = with value

Answers

The function has a local maximum at x = -√(2/7) with value -3√14 and a local minimum at x = √(2/7) with value 3√14.

To find the local maximum and minimum of the function f(x) = 2x + 7x⁻¹, we need to find the critical points of the function and then use the second derivative test to determine if they are local maxima or minima.

First, we find the derivative of f(x):

f'(x) = 2 - 7x⁻²

Setting f'(x) = 0, we get:

2 - 7x⁻² = 0

Solving for x, we get:

x = ±√(2/7)

Next, we compute the second derivative of f(x):

f''(x) = 14x⁻³

At x = ±√(2/7), we have:

f''(±√(2/7)) = ±∞

Since f''(±√(2/7)) has opposite signs at the critical points, ±√(2/7), we conclude that f(x) has a local maximum at x = -√(2/7) and a local minimum at x = √(2/7).

To find the values of the local maximum and minimum, we plug them into the original function:

f(-√(2/7)) = 2(-√(2/7)) + 7/(-√(2/7)) = -3√14

f(√(2/7)) = 2(√(2/7)) + 7/(√(2/7)) = 3√14

Therefore, the function has a local maximum at x = -√(2/7) with value -3√14 and a local minimum at x = √(2/7) with value 3√14.

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5+8(3+x) simplified please

Answers

Answer: 8x +29

Step-by-step explanation:

5+8(3+x)

5+8(x+3)

__________

5 + 8(x+3)

5+ 8x +25

_________

5+8x+ 24

29+8x

____

8x+29

I need someone to do this for me rq

Answers

Answer:

Step-by-step explanation:

The triangle area= 1/2 * the perpendicular height * breath

                           = 1/2*2*(3/4)

                          =0.75

What is the equation of the line that best fits the given data? A graph has points (negative 3, negative 3), (negative 2, negative 2), (1, 1. 5), (2, 2), (3, 3), (4, 4). A. Y = 2 x + 1 c. Y = x + 1 b. Y = x d. Y = negative x Please select the best answer from the choices provided A B C D Mark this and return

Answers

The equation of the line that best fits the given data is y = (5/6)x + 1/3

The equation of the line that best fits the given data can be found by using the slope-intercept form of a linear equation, which is y = mx + b, where m is the slope and b is the y-intercept. To find the slope, we can use the formula:

m = (y2 - y1) / (x2 - x1)

Using the points (1, 1.5) and (4, 4), we get:

m = (4 - 1.5) / (4 - 1) = 2.5 / 3 = 5/6

Now we can use one of the given points to find the y-intercept. Let's use the point (2, 2):

y = mx + b
2 = (5/6)(2) + b
2 = 5/3 + b
b = 2 - 5/3
b = 1/3

Therefore, the equation of the line that best fits the given data is:

y = (5/6)x + 1/3

The best answer is C. Y = x + 1.

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David is setting up camp with his friend Xavier. David and Xavier want to place their tents equal distance to the ranch where the mess hall is. A model is shown, where points D and X represent the location
tents and point R represents the ranch. DR = (12.3z + 12.4) meters (m) and XR= (10.5z+34) m.
D
X
R
What is the distance Xavier and David are from the ranch?

Answers

Therefore, the distance from both Xavier and David's tents to the ranch is: 151 meters and 159.6 meters.

What is equation?

An equation is a mathematical statement that shows the equality of two expressions, often separated by an equal sign (=). The expressions on either side of the equal sign can contain variables, constants, and mathematical operations. Equations are used to solve problems, find unknown values, and represent relationships between quantities in various fields such as mathematics, physics, engineering, and economics.

Here,

The distance from Xavier's tent to the ranch is XR = (10.5z + 34) meters.

The distance from David's tent to the ranch is DR = (12.3z + 12.4) meters.

Since David and Xavier want to place their tents at equal distances from the ranch, we can set these two expressions equal to each other and solve for z:

(10.5z + 34) = (12.3z + 12.4)

Simplifying this equation, we get:

1.8z = 21.6

z = 12

Therefore, the distance from both Xavier and David's tents to the ranch is:

XR = (10.5z + 34)

= (10.5 x 12 + 34)

= 151 meters

DR = (12.3z + 12.4)

= (12.3 x 12 + 12.4)

= 159.6 meters

So both tents are 151 meters away from the ranch.

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HELP!! A surfer recorded the following values for how far the tide rose, in feet, up the beach over a 15-day period.

5, 6, 7, 8, 9, 11, 12, 13, 14, 15, 16, 21, 22, 23, 24

Which of the following histograms best represents the data collected?

Answers

Answer:

Graph 2

Step-by-step explanation:

There is 1 from 1-5

There are 4 from 6-10

There are 5 from 11-15

There is 1 from 16-20

There are 4 from 21-25

Let f(x) = Show that there is no value c E (1,4) such that f'(c) = f(4) – f(1)/4-1. Why is this not a contradiction of the Mean Value Theorem?

Answers

Derivative f'(c) equals the average rate of change of f(x) over the interval [1, 4], which is given by (f(4) - f(1))/(4 - 1).

It's not a contradiction of the Mean Value Theorem, as we don't have sufficient information to confirm if the conditions for applying the MVT are met.

A more detailed explanation of the answer.

We need to discuss the Mean Value Theorem and determine if it's a contradiction for the given function.

Let f(x) be a continuous function on the interval [1, 4] and differentiable on the open interval (1, 4). According to the Mean Value Theorem (MVT), if these conditions are met, there exists a value c in the open interval (1, 4) such that the derivative f'(c) equals the average rate of change of f(x) over the interval [1, 4], which is given by (f(4) - f(1))/(4 - 1).

However, in your question, the function f(x) is not specified. We cannot determine whether f(x) is continuous on [1, 4] and differentiable on (1, 4) without knowing its specific form. Therefore, we cannot conclude that the MVT is applicable in this case.

So, it's not a contradiction of the Mean Value Theorem, as we don't have sufficient information to confirm if the conditions for applying the MVT are met. If you could provide the specific function f(x), we could further analyze the situation and determine if the MVT can be applied.

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2. Ryan is writing the program for a video game.


For one part of the game he uses the rule (x,y)â(x-3,y+8) to move points on the screen.


(a) What output does the rule give when the input is (-7,-3)? Show your work.


(b) What output does the rule give when the input is (10,-5)? Show your work

Answers

(a) When the input is (-7,-3), the rule (x,y) → (x-3,y+8) moves the point 3 units to the left and 8 units up.

So we can apply this rule to the input (-7,-3) as follows:

(-7,-3) → (-7-3,-3+8)

(-7,-3) → (-10,5)

Therefore, the output is (-10,5).

(b) When the input is (10,-5), the rule (x,y) → (x-3,y+8) moves the point 3 units to the left and 8 units up. So we can apply this rule to the input (10,-5) as follows:

(10,-5) → (10-3,-5+8)

(10,-5) → (7,3)

Therefore, the output is (7,3).

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3 cm on a map represents a distance of 60km. If the scale is expressed in the 1:m, then n​

Answers

The scale of the map can be written as:

1cm to 20km

How to find the scale of the map?

We want to find the distance that 1 cm in the map representes in the real world.

We know the relation:

3cm = 60km

We want to get a 1 in the left side, then we can divide both sides by 3 to get:

1cm = 60km/3

1cm = 20km

Then the scale of the map is 1cm to 20km

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PLEASE HELPPP
MEEE LAST QUESTION FOR THE DAY!

Answers

Answer:

There are 16 unit squares on the geoboard. Each unit square represents 5 meters, so the total area is 16*5 = 80 square meters.

Here is a diagram of the geoboard with the unit squares labeled:

[Image of a geoboard with 16 unit squares labeled]

I hope this helps! Let me know if you have any other questions.

Determine whether the series n² - 5 na tn - 6 n=1 is convergent or divergent using the Limit Comparison Test.

Answers

To use the Limit Comparison Test, we need to find a series whose behavior is well-known and similar to the given series. Let's consider the series aₙ = n². We have:

limₙ→∞ (aₙ / (n² - 5naₙ - 6)) = limₙ→∞ (n² / n²) = 1

Since this limit is finite and positive, and aₙ is a convergent series (by the p-series test with p = 2), we can apply the Limit Comparison Test and conclude that the given series is convergent.
To determine if the series ∑(n² - 5n) from n=1 to infinity is convergent or divergent using the Limit Comparison Test, we need to find a comparable series and then calculate the limit of the ratio between the two series as n approaches infinity.

Let's compare the given series to a simpler series ∑n² (n=1 to infinity). Now, we'll find the limit of the ratio:

Limit (n→∞) [(n² - 5n) / n²]

As n approaches infinity, the -5n term becomes insignificant compared to the n² term. So, the limit becomes:

Limit (n→∞) [n² / n²] = 1

Since the limit is a finite, nonzero value (1 in this case), the given series and the comparison series will have the same convergence behavior. We know that the series ∑n² (n=1 to infinity) is a divergent series, as it is a p-series with p=2 (less than or equal to 1). Therefore, the given series ∑(n² - 5n) from n=1 to infinity is also divergent.

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Mr. Cromleigh noticed that tickets were on sale for an upcoming game and wanted to take his mom. Tickets were 25% off for teachers and originally cost $45. He also had to account for a 5% sales tax. What was the total cost of the 2 tickets?

The 2 tickets cost --------------- dollars. He better ask his mom for a higher allowance!

Answers

The total cost of the two tickets is $70.88.

What is discount?

A discount is a reduction in the original price of an item or service. It is often used as a marketing strategy to increase sales by making the product more affordable or attractive to consumers. The amount of the discount is typically expressed as a percentage of the original price.

In the given question,

The cost of one ticket after a 25% discount is:

45 * 0.75 = $33.75

The cost of two tickets is:

2 * 33.75 = $67.50

Adding the 5% sales tax:

67.50 * 1.05 = $70.88

Therefore, the total cost of the two tickets is $70.88.

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1) Using the definition of the​ derivative, find f'(x). Then find f'(-3), f'(0), and f'(6) when the derivative exists.
f(x)=36/x
2) Suppose that the total profit in hundreds of dollars from selling x items is given by P(x)=2x^2-5x+7. Find the average rate of change of profit as x changes from 4-6.

Answers

f'(x) = -36/x²,  f'(-3) = -4,  f'(0) = Undefined , f'(6) = -1/6

The average rate of change of profit as x changes from 4-6 is 17.

Using the definition of the​ derivative, find f'(x). Then find f'(-3), f'(0), and f'(6) when the derivative exists. Given f(x) = 36/x. We need to find the derivative of f(x) to solve the problem.

To find the derivative of f(x), we use the quotient rule of differentiation.

(d/dx) (u/v) = [(v × du/dx) - (u × dv/dx)] / v²

The derivative of f(x) using the quotient rule is:

(d/dx)(36/x) = [(x × d/dx (36)) - (36 × d/dx(x))]/(x²)= [-36/x²]

So, f'(x) = -36/x²

Then we can find f'(-3), f'(0), and f'(6) when the derivative exists.

We know f'(x) exists if x ≠ 0.So, f'(-3) = -36/(-3)²= -4 f'(0) = Undefined (since x = 0) f'(6) = -36/6²= -1/6

Suppose that the total profit in hundreds of dollars from selling x items is given by P(x) = 2x² - 5x + 7. We need to find the average rate of change of profit as x changes from 4-6. We know that the average rate of change of a function f(x) over the interval [a, b] is: (f(b) - f(a)) / (b - a)Here, P(x) = 2x² - 5x + 7, a = 4, and b = 6.

So, the average rate of change of profit as x changes from 4-6 is:(P(6) - P(4)) / (6 - 4)=(2(6)² - 5(6) + 7 - 2(4)² + 5(4) - 7) / (6 - 4)= (72 - 30 - 8) / 2= 17

The average rate of change of profit as x changes from 4-6 is 17.

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The snow globe below is formed by a hemisphere and a cylinder on a cylindrical
base. The dimensions are shown below. The base is slightly wider than the globe
with a diameter of 10cm and height of 1cm.
10 cm
4cm
3cm
1cm
Part D: The globes are ordered by the retail store in cases of 24. Design a rectangular
case to hold 24 globes packaged in individual boxes. What is the minimum
dimensions and volume of your case.

Answers

The minimum dimensions of the box will be; 7 cm × 6 cm × 6 cm

Since the dimension is described as the measurement of something in physical space such as length, width, or height.

Given that the there will be maximum dimension when the height of the cylinder and the radius of the hemisphere are aligned together.

Maximum height = 4 cm + 3 cm = 7 cm

Maximum diameter = 2 × 3 cm = 6 cm

Therefore, we can see that the minimum dimensions of the box are :

7 cm × 6 cm × 6 cm.

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It takes Alex 22 minutes to walk from his home to the store. The function (x) - 2. 5x models the distance that Alex has walked in x minutes after leaving his house


to go to the store. What is the most appropriate domain of the function?

Answers

The most appropriate domain of the function is 0 ≤ x ≤ 22. This is because Alex can only walk from his home to the store within a maximum of 22 minutes, and the distance he walks can only be modeled within that time frame.

It is given that the function f(x) = 2.5x, which models the distance Alex walks in x minutes after leaving his house to go to the store. It takes him 22 minutes to walk from his home to the store. The most appropriate domain of the function is the range of x values that make sense in this context.

Step 1: Identify the minimum and maximum values for x.
In this case, the minimum value for x is when Alex starts walking, which is 0 minutes. The maximum value for x is when he reaches the store, which is 22 minutes.

Step 2: Express the domain as an interval.
The domain of the function can be written as an interval from the minimum to the maximum value, including both endpoints. Therefore, the domain is [0, 22].

Therefore, the most appropriate domain of the function f(x) = 2.5x, which models the distance Alex walks in x minutes after leaving his house to go to the store, is [0, 22].

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If α and β are the zeros of x^2-x+k, and 3α+2β=20, find k.

Answers

The solution of the given problem of quadratic equation comes out to be K thus has a value of 63/4.

What is quadratic equation?

Regression modelling uses the polynomial solutions x = ax² + b + c=0 for one-variable equations. The First Principle of Algebra states that there can only be one solution because it has an extra order. There are both simple and complex solutions available. As the name suggests, a "non-linear formula" has four variables. This implies that there may only be one squared word. In the equation "ax² + bx + c = 0.

Here,

We know that if and are the zeros of the quadratic equation x²-x+k then:

=> α + β = 1

=> αβ = k

Additionally, we are told that 3 + 2 = 20.

We may find as = 1 - by using the equation + = 1.

By replacing this expression for in terms of in the formula k = a, we obtain:

=> (1 - β)β = k

=> β² - β + k = 0

=> 3α + 2(1 - α) = 20

=> α = 6 - 2β/3

=> (6 - 2β/3)²- (6 - 2β/3) + k = 0

=> 4β² - 36β + 72 + 3k = 0

=> 3(6 - 2β/3) + 2β = 20

=> 4β/3 = 2

=> β = 3/2

=> 4(3/2)² - 36(3/2) + 72 + 3k = 0

When we simplify and find k, we obtain:

=>k = 63/4

K thus has a value of 63/4.

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What is the 5280th digit in the decimal expansion of 5/17

Answers

The second digit after the decimal point is 9. We repeat this process until we have found the 5280th digit:

```

0.294117647058823529...

               50

Calculate the decimal expansion?

To find the 5280th digit in the decimal expansion of 5/17, we need to find the first 5280 digits of the decimal expansion and then look at the 5280th digit.

To do this, we can use long division to divide 5 by 17. We start by dividing 5 by 17 to get the first digit after the decimal point:

```

0.294117647058823529...

```

We can see that the first digit after the decimal point is 2. To get the second digit, we multiply the remainder (5) by 10 and then divide by 17:

```

5 * 10 = 50

50 / 17 = 2 remainder 16

```

The second digit after the decimal point is 9. We repeat this process until we have found the 5280th digit:

```

0.294117647058823529...

               50

            -----

5 * 10 = 50 | 16.0000000000000000000000000000000000000000000000000000000000000000000000...

            0

           ---

             160

             153

             ---

               70

               68

               --

                20

                17

                --

                 30

                 17

                 --

                 130

                 119

                 ---

                  110

                  102

                  ---

                    80

                    68

                    --

                    120

                    119

                    ---

                      10

                       8

                      --

                       20

                       17

                       --

                        30

                        17

                        --

                        130

                        119

                        ---

                         110

                         102

                         ---

                           80

                           68

                           --

                           120

                           119

                           ---

                             10

                              8

                             --

                              20

                              17

                              --

                              30

                              17

                              --

                              130

                              119

                              ---

                               110

                               102

                               ---

                                 80

                                 68

                                 --

                                 120

                                 119

                                 ---

                                   10

                                    8

                                   --

                                   20

                                   17

                                   --

                                   30

                                   17

                                   --

                                   130

                                   119

                                   ---

                                    110

                                    102

                                    ---

                                      80

                                      68

                                      --

                                      120

                                      119

                                      ---

                                        10

                                         8

                                        --

                                        20

                                        17

                                        --

                                        30

                                        17

                                        --

                                        130

                                        119

                                        ---

                                         110

                                         102

                                         ---

                                           80

                                           68

                                           --

                                           120

                                           119

                                           ---

                                             10

                                              8

                                             --

                                             20

                                             17

                                             --

                                             30

                                             17

                                             --

                                             130

                                             119

                                             ---

                                              110

                                              102

                                              ---

                                                80

                                                68

                                                --

                                                120

                                                119

                                                ---

                                                  10

                                                   8

                                                  --

                                                  20

                                                  17

                                                  --

                                                  30

                                                  17

                                                  --

                                                  130

                                                  119

                                                  ---

                                                   110

                                                   102

                                                   ---

                                                     80

                                                     68

                                                     --

                                                     120

                                                     119

                                                     ---

                                                       10

                                                        8

                                                       --

                                                       20

                                                       17

                                                       --

                                                       30

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Garden canes have lengths that are normally


distributed with mean 208. 5cm and standard


deviation 2. 5cm. What is the probability of the length


of a randomly selected cane being between 205cm


and 210cm? Correct to 3 decimal places

Answers

The probability of the length of a randomly selected cane being between 205cm and 210cm is approximately 0.645 (rounded to 3 decimal places).

To find the probability of the length of a randomly selected cane being between 205cm and 210cm, we need to calculate the z-scores for these values and then use the standard normal distribution.

The z-score formula is given by:

z = (x - μ) / σ,

where x is the observed value, μ is the mean, and σ is the standard deviation.

For 205cm:

z1 = (205 - 208.5) / 2.5 = -1.4

For 210cm:

z2 = (210 - 208.5) / 2.5 = 0.6

Now, we can use a standard normal distribution table or a calculator to find the probability between these two z-scores.

Using a standard normal distribution table or a calculator, we find that the probability associated with z1 = -1.4 is approximately 0.0808, and the probability associated with z2 = 0.6 is approximately 0.7257.

To find the probability between these two z-scores, we subtract the probability corresponding to z1 from the probability corresponding to z2:

P(205cm < length < 210cm) ≈ P(z1 < z < z2) ≈ P(z < 0.6) - P(z < -1.4) ≈ 0.7257 - 0.0808 ≈ 0.6449.

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