Um reservatório possui inicialmente R litros de água, por conta de um vazamento, perde 5 litros a cada minuto. Indique a lei de formação de uma função que expressa a quantidade de água no reservatório em função do tempo

Answer:

Pretty simple!

Step-by-step explanation:

First, you need to know about exponential functions. They are like linear functions, but either increase or decrease their rate as they go further along the x-axis.

Linear functions take a simple form: Just a line. Not really much to it!

Their equation is: [tex]y=mx+b[/tex]

Yeah! Now onto Exponential Functions.

Exponential functions are very interesting. This could be that they are hard to solve sometimes, or that I spent over half a year studying them.

Their Graphs usually look like a line that keeps getting lower or higher as they progress.

Essentially, if they keep getting higher and higher(Y-axis wise), this means that they are increasing. Likewise, if they keep getting lower and lower, this means they are decreasing. Pretty simple, right?

Now, to state the slope over each part. To do that, I'm pretty sure you have to find two points that describe that area, use the formula for slope(Below), and I would think you are done.

[tex]m=\frac{y_{1} -y_{2} }{x_{1} -x_{2}}[/tex]

Hope this helps, and please correct me if I'm wrong!

Stay Safe!

Answer: probability of getting two 5s =0.04

probability of getting at least one 5 =0.36

probability of getting a total score greater than 5 =0.6

Step-by-step explanation:

Total outcomes on 1 spinner = 5

Then , total outcomes of spinning it 2 times=  [tex]5\times5 = 25[/tex]

Number of outcomes for getting two 5's = 1

Then, the probability of getting two 5s [tex]=\dfrac{\text{Favorable outcomes of getting two 5's }}{\text{Total outcomes}}[/tex]

[tex]=\dfrac{1}{25}=0.04[/tex]

Number of outcomes for getting at least one 5 [ {(1,5),(2,5),(3,5),(4,5),(5,5), (5,1), (5,2), (5,3), (5,4)} ] =9

Then, the probability of getting at least one 5[tex]=\dfrac{\text{Favorable outcomes of getting at least one 5 }}{\text{Total outcomes}}[/tex]

[tex]=\dfrac{9}{25}=0.36[/tex]

Number of outcomes for getting a total score of 5, [ {(1,4),(4,1),(2,3),(3,2)} ] =4

Then, the probability of getting a total score of 5,[tex]=\dfrac{\text{Favorable outcomes of getting a total score of 5 }}{\text{Total outcomes}}[/tex]

[tex]=\dfrac{4}{25}[/tex]

Number of outcomes for getting a total score greater than 5 [ {(1,5),(5,1),(2,4),(4,2),(2,5), (5,2), (3,4),(4,3), (3,5), (5,3), (3,3), (4,5), (5,4), (4,4), (5,5)} ] =15

Then, the probability of getting a total score greater than 5,[tex]=\dfrac{\text{Favorable outcomes of getting a total score greater than 5 }}{\text{Total outcomes}}[/tex]

[tex]=\dfrac{15}{25}=\dfrac{3}{5}=0.6[/tex]

Answer:

Below

Step-by-step explanation:

To write this function in the standard form simplify it.

● -4(x+2)(x+3)

● -4 (x^2+3x+2x+6)

●-4(x^2+5x+6)

●-4x^2-20x-24

Answer:

y = -4(x+2.5)²+1

Step-by-step explanation:

Standard form is given by f(x) = a(x-h)²+k, where (h,k) is the vertex. We are already given a = -4, and if we graph the equation given, we can see that the vertex is (-2.5, 1). So, we can set up the equation y = -4(x+2.5)²+1.

Answer:

B

Step-by-step explanation:

A coin has two sides so there is a 50% chance of getting heads or tails.

Answer:

a) 1/4

b) 3/4

c) 1/4

Step-by-step explanation:

Possible outcomes of two tosses of a coin:

HH

HT

TH

TT

There is a total of 4 possible outcomes.

p(event) = (number of desired outcomes)/(total number of possible outcomes)

a) 2 heads

HH     <-------  1 desired outcome

HT

TH

TT

p(2 heads) = 1/4

b) at least 1 head

HH   \  

HT      }     <------ 3 desired outcomes

TH    /

TT

p(at least 1 head) = 3/4

c) no heads

HH

HT

TH

TT    <------- 1 desired outcome

p(no heads) = 1/4

Answer:

y + c ÷ m = x

Step-by-step explanation:

You start of with:

y = mx - c

We can get rid of the + c by putting it on the other side. When a number goes to the other side it does the opposite, so the - will become a +. It will end up as:

y + c = mx

We just need x on itself so we need to get ride of m. In this sum, mx means that they are multiplying together, we need to make that divide. So we take m on the other side and make it divide. This brings us to x on itself.

(y+c) ÷ m = x

Hope this helps.

x can be changed into the subject of the formula as x = (y + c) / m.

An equation is the statement of two expressions located on two sides connected with an equal to sign. The two sides of an equation is usually called as left hand side and right hand side.

Subject of an equation is that variable we are going to find out.

The given equation is y = mx - c.

Here y is the subject.

We need to rewrite the equation to make x the subject.

y = mx - c

Adding c on both sides,

y + c = mx - c + c

y + c = mx

Dividing both sides by m, we get,

(y + c) / m = mx / m

(y + c) / m = x

Hence the given formula y = mx - c can be rewritten to make x the subject as x = (y + c) / m.

To learn more about Equations, click here :

https://brainly.com/question/10413253

#SPJ3

Answer:

Is this what you are looking for....

Answer:

x=±√3 or ±1.732

Step-by-step explanation:

5x²-9=6

5x²=6+9

5x²=15

x=±√15/5

x=±√3

Answer:  19)  117°                    20) 53°

               21)  229°                   22) 119°

               23) 155°                    24) 323°

Step-by-step explanation:

Use Pythagorean Theorem to find r:     x² + y² = r²

19) x = [tex]-\sqrt{17}[/tex] ,  y = 8,    r = 9

     [tex]\cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{-\sqrt{17}}{9} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{-\sqrt{17}}{9}\bigg)\rightarrow \quad \theta = \large\boxed{117^o}[/tex]

20) x = 3,   y = 4,   r = 5

      [tex]\cos \theta=\dfrac{x}{r} \rightarrow \quad \cos \theta =\dfrac{3}{5} \rightarrow \quad \theta = cos^{-1}\bigg(\dfrac{3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{53^o}[/tex]

21) x = [tex]-\sqrt7[/tex],   y = -3,   r = 4

    [tex]\sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{4} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{4}\bigg)\rightarrow \quad \theta = \large\boxed{229^o}[/tex]    

22) x = [tex]-\sqrt{15}[/tex],   y = 7,   r = 8

     [tex]\tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{7}{-\sqrt{15}} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{7}{-\sqrt{15}}\bigg)\rightarrow \quad \theta = \large\boxed{119^o}[/tex]

23) x = -13,   y = 6,   r = [tex]\sqrt{205}[/tex]

     [tex]\tan \theta=\dfrac{y}{x} \rightarrow \quad \tan \theta =\dfrac{6}{-13} \rightarrow \quad \theta = tan^{-1}\bigg(\dfrac{6}{-13}\bigg)\rightarrow \quad \theta = \large\boxed{155^o}[/tex]

24) x = 4,    y = -3,   r = 5

     [tex]\sin \theta=\dfrac{y}{r} \rightarrow \quad \sin \theta =\dfrac{-3}{5} \rightarrow \quad \theta = sin^{-1}\bigg(\dfrac{-3}{5}\bigg)\rightarrow \quad \theta = \large\boxed{323^o}[/tex]

For the point [tex](-\sqrt{17},8)[/tex], [tex]cos\theta=0.4581[/tex]

For the point [tex](3,4)[/tex], [tex]cos\theta=0.6[/tex]

For the point [tex](-\sqrt7,-3)[/tex], [tex]sin\theta=-0.75[/tex]

For the point [tex](-\sqrt{15},7)[/tex], [tex]tan\theta=-1.807[/tex]

For the point [tex](-13,6)[/tex], [tex]tan\theta=-0.4615[/tex]

For the point [tex](4,-3)[/tex], [tex]sin\theta=-0.6[/tex]

For ratios [tex]sin\theta[/tex] and [tex]cos\theta[/tex], we need to calculate the hypotenuse of the right-angled triangle. For the ratio [tex]tan\theta[/tex], we can directly make use of the coordinate points.

For the point [tex](-\sqrt{17},8)[/tex]

[tex]r=\sqrt{17+8^2}=9[/tex]

[tex]cos\theta=\dfrac{x}{r}\\\\=-\dfrac{\sqrt{17}}{9}\approx0.4581[/tex]

For the point [tex](3,4)[/tex]

[tex]r=\sqrt{3^2+4^2}=5[/tex]

[tex]cos\theta=\dfrac{x}{r}\\\\=\dfrac{3}{5}=0.6[/tex]

For the point [tex](-\sqrt7,-3)[/tex]

[tex]r=\sqrt{7+(-3)^2}=4[/tex]

[tex]sin\theta=\dfrac{y}{r}\\=-\dfrac{3}{4}=-0.75[/tex]

For the point [tex](-\sqrt{15},7)[/tex]

[tex]tan\theta=\dfrac{y}{x}\\=-\dfrac{7}{\sqrt{15}}=-1.807[/tex]

For the point [tex](-13,6)[/tex]

[tex]tan\theta=\dfrac{y}{x}\\=-\dfrac{6}{13}=-0.4615[/tex]

For the point [tex](4,-3)[/tex]

[tex]r=\sqrt{4^2+(-3)^2}=5[/tex]

[tex]sin\theta=\dfrac{y}{r}\\=-\dfrac{3}{5}=-0.6[/tex]

Learn more about trigonometry here: https://brainly.com/question/23686339

Answer:

There is no relationship, except they do intersect at the point (1, -1). Hope this helps :)

Brainliest?

Both given lines are going to intersect at ( 1,-1 ) that's it.

A line section that can connect two places is referred to as a segment.

The line is here! It extends endlessly in both directions and has no beginning or conclusion.

In other words, a line segment is just part of a big line that is straight and going unlimited in both directions.

Given that

Line 1 ; 5x +y = 4

Line 2 ;  20 + 4y = 16 ⇒ y = -1

At  y = -1  the first line is

5x  - 1  =  4 ⇒ x = 1

So,

It is clear that line 1 has a point ( 1 .-1 ) and line 2 also passes

through it hence there will an intersection.

For more about line segment

https://brainly.com/question/25727583

#SPJ5

Answer:

  f(x) = x^3 -5x^2 +25x -125

Step-by-step explanation:

For zero x=a, one of the factors is (x -a). If the polynomial has integer coefficients, its complex roots come in conjugate pairs. So, the roots are ...

  roots: -5i, 5i, 5

  factors: (x -(-5i))(x -5i)(x -5)

Multiplying these out gives your polynomial as ...

  f(x) = (x^2 +25)(x -5)

  f(x) = x^3 -5x^2 +25x -125

Hey There!!

Your correct choice will be C.

Step-by-step explanation:

Because, The cosine function is just the sine function translated 90° to the left, so it's a sinusoid. So, They named after the function sine. By ♡Itsbrazts♡

Answer:

Step-by-step explanation:

y=cos(x)-2

Answer:

Ф=144

Ф =s/r ( Ф is the central angle,s is the arc length, r is the radius)

find r:

radius =circumference/2π=1/2π=0.16

Ф=(2/5) /(1/2π)=4π/5=144 degree (π=180)

Ф in degrees: 144 degrees

Answer:

This question is about half-angle trigonometric identities, which are specific formulas that help us to solve problems with half-angles.

In this case, if you need a half-angle identity for the tangent, you could use

[tex]tan(\frac{x}{2} )=\frac{sin(x)}{1+cos(x)}[/tex]

[tex]tan(\frac{x}{2})=\frac{1-cos(x)}{sin(x)}[/tex]

[tex]tan(\frac{x}{2})=\sqrt{\frac{1-cos(x)}{1+cos(x)} }[/tex]

Therefore, the right identity must satisfy the expression above.

Answer:

In picture

Step-by-step explanation:

a. true

b. false ( angles should equal 180 125+65=190)

c. true

d. true

e. true

Answer:

StartFraction 24 Over 65 EndFraction

Step-by-step explanation:

Total number of students = 26

Number of boys = 10

Number of girls = 26-10

=16

Eduardo has to pull two names out of the hat without replacing them.

First name

Probability= Favourable outcome/Total outcome

Probability of girls=16

Total probability=26

Eduardo has to pull two names out of the hat without replacing them.

Probability= Favourable outcome/Total outcome

=16/26

=8/13

For the second name:

Without replacement of the first hat

Probability of girls=16-1=15

Total probability=26-1=25

Probability= Favourable outcome/Total outcome

=15/25

=3/5

Probability of both of Eduardo's partner for the group project will be girls=8/13*3/5

=24/65

StartFraction 24 Over 65 EndFraction

Answer:

B.) 24/65

Step-by-step explanation:

Took the test

Step-by-step explanation:

Here,

ABCD is rhombus,

AB=9s+29

CD =10s -18

now, AB=CD (opposite side of rhombus is parallel and equal)

or,9s +29=10s-18

or, 10s -9s= 29+18.

The value of s is 47.

Therefore, the measure of AB is 9×47+29.

=452.

Hope it helps...

Answer:

2m  

4

−2m  

3

−26m  

2

−23m+20

Step-by-step explanation:

Answer:5c-3d

Step-by-step explanation: Collect the like terms such as 6c ,-c and 4d,-7d

Answer:

5c - 3d

Step-by-step explanation:

6c + 4d - c - 7d

Group like terms

6c - c + 4d - 7d

Add similar elements : 6c - c = 5c

5c + 4d - 7d

Add similar elements : 4d - 7d = - 3d

5c - 3d

I hope this helps

Answer:

8 ft

Step-by-step explanation:

We can use ratios to solve

tree                          Otis

--------------------  = --------------

tree shadow          Otis shadow

tree                   4 ft

-------------- = ----------------

9 ft                   4.5 ft

Using cross products

4.5 tree = 4* 9

4.5 tree = 36

Divide each side by 4.5

tree = 36/4.5

tree =8

Answer:

33

Step-by-step explanation:

15019 / 53 = 283 R20

53 − 20 = 33

He needs 33 more trees so that every row can have the same number of trees.

Answer:

x=-7  x=4

Step-by-step explanation:

(X-2)(x+5)=18

FOIL

x^2 +5x -2x-10 =18

Combine like terms

x^2 +3x -10 = 18

Subtract 18 from each side

x^2 +3x -10 -18 = 0

Combine like terms

x^2 +3x -28 =0

Factor

What two numbers multiply to -28 and add to 3

7*-4 = -28

7+-4 = 3

( x+7) ( x-4) =0

Using the zero product property

x+7 =0  x-4=0

x=-7  x=4

Answer:

1) A. y= (20 - 2x) /5

2) C. 141.3

3) True ( Your answers are here.)

Answer:

1. is A 2. is C 3. is I believe True

Step-by-step explanation:

1.

2x + 5y = 20

-2x          -2x

5y = 20 - 2x

/5          /5

Answer: y = 20 - 2x /5

2.

V = πr^2h

π=3.14  r=3  h=5

3.14*3^2*5

1.413*10^2 which = 141.3

3.

I am not completely sure but I think it is True

Hope this helps

Answer: 2.2532

Step-by-step explanation:

From the table attached :

Expected probability = sum of p(x) * x ; wher P-X) is the probability of x

E(p(x), x) = (0*0) + (1 * 0.06) *(2*0.1) + (3 * 0.16) * (4 *0.16)+ (5*0.26) * (6 *0.08) + (7 * 0.13) + (8 * 0.05)

Pp(x) * x) = 2.2532

Therefore, the expected value of the distribution is 2.2532

Answer:

544 cups

Step-by-step explanation:

1 gallon consists of about 16.0047 cups, 34x16 is 544

Answer:

GH = 9 units

Step-by-step explanation:

Given HI = 4b - 5 and HI 3, then

4b - 5 = 3 ( add 5 to both sides )

4b = 8 ( divide both sides by 4 )

b = 2

Thus

GI = 5b + 2 = 5(2) + 2 = 10 + 2 = 12

GH = GI - HI = 12 - 3 = 9

Answer:

The difference between the two throws is 6/7 yards

Step-by-step explanation:

Beatrice throw=1 7/14 yards

Tilly throw=9/14 yards

Difference between the two throws=Beatrice throw - Tilly throw

=1 7/14 - 9/14

=21/14 - 9/14

= 21-9/14

=12/14

=6/7 yards

The difference between the two throws is 6/7 yards

Hey there! I’m happy to help!

Let’s first subtract 4 from 20 to see how much was lost.

20-4=16

Now, we see that 16 is a certain percent of twenty that we want to find. When talking about percents, the word “is” represents an equal sign. So, we can write this equation. We will have p represent our prevent.

16=20p (16 is a certain percent of 20)

Now, we solve by dividing both sides of the equation by 20 to isolate the p.

p=0.8

0.8 is 80% or 4/5, so 4/5 of the dam water has been lost.

Have a wonderful day! :D

Answer:

a. 0.6975

b. 0.25

c. The events are independent and inclusive

Step-by-step explanation:

a. The proportion of five-star football recruits in the nation that go to universities in the three most competitive athletic conferences = 75%

Therefore, the probability of a five-star football recruits chooses to go to a university in the three most competitive athletic conferences p(A) = 75% or 0.75

The proportion of the times five-star football recruits get full football scholarships = 93%

Therefore, the probability that a five-star football recruit get full football scholarships p(B) = 93% or 0.93

Therefore, the probability that a randomly selected five-star recruit who chooses one of the best three conferences will be offered a full football scholarship can be written as -the probability that a randomly selected five-star recruit who chooses one of the best three conferences and will be offered a full football scholarship is therefore;

p(A) ∩ p(B) = p(A) × p(B) = 0.75×0.93 = 0.6975

b. The probability that a randomly selected five star recruit will not select a university from one of the three best conferences = 1 - p(A) = 1 - 0.75 = 0.25

c. The events are independent as the given probability of occurrence of one event does not alter the probability of the other event

The events are inclusive events are exclusive events as P(A)and P(B) can take place simultaneously.

Answer:

SL = KR

Step-by-step explanation:

We're given two different lengths, both of which are on other sides of KL. Now, since these two givens are congruent, and we're overlapping it over a new line, the lines SL and KR are going to be congruent.

Answer:

10) [tex]10v^2-19v+6[/tex]

11) [tex]15x^3-7x^2-29x+20[/tex]

Step-by-step explanation:

Well first let's make the box.

10)

Look at the image below ↓

[tex]10v^2-19v+6[/tex]

11)

Look at the image below ↓

[tex]15x^3-7x^2-29x+20[/tex]

Thus,

number 10 is [tex]10v^2-19v+6[/tex] and number 11 is [tex]15x^3-7x^2-29x+20[/tex].

Hope this helps :)