Answer:
after 60 seconds = 1 minute ,they will together for the first time.
Step-by-step explanation:
Three bells toll at an interval of 4,5 and 6 second.
They will ring together at the time which will be the multiple of all the three time interval (i.e 4,5,6)
4 = 2*2
5= 5*1
6 = 2*3
LCM of these three number will be multiple of highest power of each prime number
highest power of 2 in the above problem 2^2
3 = 3
5 = 5
Thus, LCM 2^2 * 3*5 = 60
Thus, after 60 seconds they will together for the first time.
Then they will toll together after each interval of 60 seconds together.
Evaluate m²p - p (m - p ) if m= 3 and p = 5
Answer:
55
Step-by-step explanation:
m^2p - p(m - p), if m=3 and p=5.
So we plug those value into the correct space...
(3)^2 (5) - (5) (3 - 5)
9x5 - 5 x (-2)
45 - (-10)
45 + 10
55
HELP ASAP MONEY AND WAGES
Answer: $57,700.00
Step-by-step explanation:
Total Gross Annual income = $70,000
a) Pension at 5% = $70,000(0.05) = $3,500
b) Employee Insurance at 2.4% = $70,000(0.024) = $1,680
c) Income Tax at 0% for $0-$11,000 = $11,000(0) = $0
Income Tax at 8% for $11,000-$25,000 = $14,000(0.08) = $1,120
Income Tax at 12% for $25,000-$50,000 = $25,000(0.12) = $3,000
Income Tax at 15% for $50,000-$100,000 = $20,000(0.15) =$3,000
Total Income Tax = $7,120
Annual Net Income = Gross - Pension - Employee Insurance - Income Tax:
$70,000 - $3,500 - $1,680 - $7,120 = $57,700
Please help! I need help with this question!
Explanation:
The vertical angles at C are congruent with each other, so we have the necessary conditions to invoke the SAS congruence postulate:
∆BCA ≅ ∆ECD
BA ≅ ED by CPCTC (corresponding parts of congruent triangles are congruent)
A car rental agency advertised renting a car for $24.95 per day and $0.26 per mile. If Brad rents this car for 3 days, how many whole miles can he drive on a $200 budget ?
Answer:
481 whole miles
Step-by-step explanation:
Total cost would be 3 x 24.95 + 0.26m, where m is the miles driven.
Total cost has to be under or equal to $200, so
3 x 24.95 + 0.26m <= 200
74.85 + 0.26m <= 200 ( 3 x 24.95)
0.26m <= 125.15 ( subtract 74.85)
m <= 481.35 ( divide 0.26)
9. A open-sea diver dove down 42 ft. to harvest sponges. After rising 28 ft. how far was the diver from
the surface? (Hint: Drawing a diagram may help you answer this.)
Answer:
14 feet away from the surface. -14
Step-by-step explanation:
The diver was 42 feet below the surface.
He went up 28 feet.
We have to find out how far he is from the surface.
All you would do is subtract 42 - 28.
This would be 14 feet.
This means the diver is 14 feet away from the surface.
The diver is 14 feet away from the surface.
What is Unitary Method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units.
For Example, Let's say Ram spends 36 Rs. for a dozen (12) bananas.
12 bananas will set you back 36 Rs. 1 banana costs 36 x 12 = 3 Rupees.
As a result, one banana costs three rupees. Let's say we need to calculate the price of 15 bananas.
This may be done as follows: 15 bananas cost 3 rupees each; 15 units cost 45 rupees.
Given:
The diver was 42 feet below the surface.
He went up 28 feet.
So, after moving 28 feet up the remaining distance would be
= 42 - 28.
= 14 feet
Hence, the diver is 14 feet away from the surface.
Learn more about Unitary Method here:
https://brainly.com/question/22056199
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Tia measured the daily high temperature in Kats, Colorado for each of the 30 days in April. She then created both a dot plot and a box plot to display the same data (both diagrams are shown below). Which display can be used to find how many days had a high temperature above 15∘ C15, degrees, start text, C, end text
*see attachment below showing the dot plot and box plot created by Tia
Answer:
Dot plot
Step-by-step explanation:
In a dot plot, the temperature of a day is represented by 1 dot. There are 30 dots on the box plot shown in the attachment that was made by Tia.
This dot plot display makes it easier to find how many days had a temperature that is higher than 15°.
Thus, from the dot plot, we have:
2 dots representing 2 days having a temperature of 16°C each
2 days also have daily temperature of 17°C
2 days have temperature of 18°C as well, and
1 day has temperature of 19° C.
Therefore, the number of days that had a temperature above 15°C is 7 days.
Answer:
Dot Plot, Box Plot
Step-by-step explanation:
I got the other guy's answer wrong but mine is right =)
PLS HELP ME!!!! THIS IS URGENT
An equilateral triangle has three sides with equal length and three angles with equal measure. Given equilateral triangles, △ABC and △DEF complete the statements below.
Answer:
The answer is below
Step-by-step explanation:
An equilateral triangle is a triangle in which all the three sides are equal and all the angles are also equal. Each angle in an equilateral triangle is equal to 60°.
1) We cannot determine if the Two triangles are congruent because for congruence at least one side must be equal. Since we know that all the angles in both triangle ABC and DEF have the same measure of angle, we cannot finalize that they are congruent until the have at least one equal measure of length
ΔABC is not ≅ ΔDEF
2) All angles in an equilateral triangle are equal and is 60°. Therefore m∠E = 60°
3) Two triangles are said to be similar if they have the same shape and their sides have the same proportion. Since both triangle ABC and DEF have the same measure of angle, therefore they are similar. i.e
ΔABC ~ ΔDEF
An equilateral triangle is a triangle with all three sides of equal length and all angles are equal.
△ABC and △DEF are not congruent to each other.
∠E = 60 degree.
△ABC ≈ △DEF
Since, An equilateral triangle has three sides with equal length and three angles with equal measure.
1 . In triangle △ABC and △DEF , for congruency at least one side should be equal to apply ASA congruency rule.
ASA congruence state that , if two angles of one triangle, and the side contained between these two angles, are respectively equal to two angles of another triangle and the side contained between them, then the two triangles will be congruent.
2. Both triangles △ABC and △DEF are equilateral.
∠B = ∠E = 60 degree
3. Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion .
Similar triangles are the same shape, but not necessarily the same size.
So, triangles △ABC and △DEF are similar.
△ABC ≈ △DEF
Learn more:
https://brainly.com/question/16815166
What is the input if the output is -6?
Answer:
x=0,8
Step-by-step explanation:
We want to find the values of x when y = -6
There are two different values of x that give y = -6
The first is x=0
When f(0) = -6
The second is x=8
f(8) = -6
Answer:
0 or 8
Step-by-step explanation:
The output is -6
output = y
input = x
When y = -6, x = 0 or x = 8 (as shown in the graph).
A manufacturer of matches randomly and independently puts 23 matches in each box of matches produced. The company knows that one-tenth of 8 percent of the matches are flawed. What is the probability that a matchbox will have one or fewer matches with a flaw?
Answer:
0.9855 or 98.55%.
Step-by-step explanation:
The probability of each individual match being flawed is p = 0.008. The probability that a matchbox will have one or fewer matches with a flaw is the same as the probability of a matchbox having exactly one or exactly zero matches with a flaw:
[tex]P(X\leq 1)=P(X=0)+P(X=1)\\P(X\leq 1)=(1-p)^{23}+23*(1-p)^{23-1}*p\\P(X\leq 1)=(1-0.008)^{23}+23*(1-0.008)^{23-1}*0.008\\P(X\leq 1)=0.8313+0.1542\\P(X\leq 1)=0.9855[/tex]
The probability that a matchbox will have one or fewer matches with a flaw is 0.9855 or 98.55%.
Angle bcd is a circumscribed angle of circle a. What is the length of line segment ac?
Step-by-step explanation:
Answer:
The length of segment AC is 10 units ⇒ 1st answer
Step-by-step explanation:
Look to the attached figure
In circle A
∵ AB is a radius
∵ BC is a tangent to circle A at B
- The radius and the tangent are perpendicular to each other
at the point of contact
∴ AB ⊥ BC at point B
∴ m∠ABC = 90°
In ΔABC
∵ m∠B = 90°
∵ AB = 8 units
∵ BC = 6 units
- By using Pythagoras Theorem (Square the hypotenuse is
equal to the sum of the squares of the other two sides of
the triangle)
∵ (AC)² = (AB)² + (BC)²
∴ (AC)² = (8)² +(6)²
∴ (AC)² = 64 + 36
∴ (AC)² = 100
- Take √ for both sides
∴ AC = 10 units
The length of segment AC is 10 units
follow me plzzz
Answer:A
On edge.
Step-by-step explanation:
Please, help me with this. Solve X/6 = 7
Answer:
42
Step-by-step explanation:
Answer:
x = 42
Step-by-step explanation:
Given x/6 = 7
solution:
multiply both sides by 6
x/6*6 = 7*6
x = 42
Please help me to solve this . Thank you so much .
And if possible , could you explain the answer too ?
Base on the diagram , state
a) The point which is 2 cm from R and 4 cm from P
b) The point which is more than 2 cm from R and 4 cm from T
c) The location of a moving point X in the diagram such that it is less than 4 cm from P and more than 2cm from R
d) The location of a moving point Y in the diagram such that YR < 2 cm and YP < 4 cm
e)The location of a moving point Z in the diagram such that ZT > 4 cm , ZP > 4 cm and ZR > 2 cm
Answer:
a) N
b) L
c) area I
d) area II
e) area VI
Step-by-step explanation:
a) the points that are 2cm from R are Q, N, M, S. Then, points that are 4cm from P are K, N, R. So, the only one point that works for both is N.
b) the points that are >2cm from R are P, K, L, T. We do not count those are exactly 2cm from R. Then, points that are 4cm from T are R, M, L. Ans is L.
c) <4cm from P, are area I and II. Then area that are >2cm from R are I, VI, and V. So, the only area that works for both is I.
d) <2cm from R, are areas II, III, and IV. Then, <4cm from P, are areas I and II. So, the only one works for both is area II.
e) >4cm from T, are areas I, II, III, VI. Then, >4cm from P, are III, IV, V, VI. Finally, >2cm from R, are areas I, VI, V. The only one that works for all three conditions is area VI.
In a local ice sculpture contest, one group sculpted a block into a rectangular based pyramid. The dimensions of the base were 3 m by 5 m, and the pyramid was 3.6 m high. Calculate the amount of ice needed for this sculpture. A conical-shaped umbrella has a radius of 0.4 m and a height of 0.45 m. Calculate the amount of fabric needed to manufacture this umbrella. (Hint: an umbrella will have no base) A cone has a volume of 150 cm3 and a base with an area of 12 cm2. What is the height of the cone? Find the dimensions of a deck which will have railings on only three sides. There is 28 m of railing available and the deck must be as large as possible. A winter recreational rental company is fencing in a new storage area. They have two options. They can set it up at the back corner of the property and fence it in on four sides. Or, they can attach it to the back of their building and fence it in on three sides. The rental company has decided that the storage area needs to be 100 m2 if it is in the back corner or 98 m2 if it is attached to the back of the building. Determine the optimal design for each situation.
Answer:
1. The amount of ice needed = 18 m²
2. The amount of fabric needed to manufacture the umbrella is 0.76 m²
3. The height of the cone, is 3.75 cm
4. The dimensions of the deck are;
Width = 28/3 m, breadth = 28/3 m
The area be 87.11 m²
5. The dimensions of the optimal design for setting the storage area at the corner, we have;
Width = 10m
Breadth = 10 m
The dimensions of the optimal design for setting the storage area at the back of their building are;
Width = 7·√2 m
Breadth = 7·√2 m
Step-by-step explanation:
1. The amount of ice needed is given by the volume, V, of the pyramid given by V = 1/3 × Base area × Height
The base area = Base width × Base breadth = 3 × 5 = 15 m²
The pyramid height = 3.6 m
The volume of the pyramid = 1/3*15*3.6 = 18 m²
The amount of ice needed = 18 m²
2. The surface area of the umbrella = The surface area of a cone (without the base)
The surface area of a cone (without the base) = π×r×l
Where:
r = The radius of the cone = 0.4 m
l = The slant height = √(h² + r²)
h = The height of the cone = 0.45 m
l = √(0.45² + 0.4²) = 0.6021 m
The surface area = π×0.4×0.6021 = 0.76 m²
The surface area of a cone (without the base) = 0.76 m²
The surface area of the umbrella = 0.76 m²
The amount of fabric needed to manufacture the umbrella = The surface area of the umbrella = 0.76 m²
3. The volume, V, of the cone = 1/3×Base area, A, ×Height, h
The volume of the cone V = 150 cm³
The base area of the cone A = 120 cm²
Therefore we have;
V = 1/3×A×h
The height of the cone, h = 3×V/A = 3*150/120 = 3.75 cm
4. Given that the deck will have railings on three sides, we have;
Maximum dimension = The dimension of a square as it is the product of two equal maximum obtainable numbers
Therefore, since the deck will have only three sides, we have that the length of each side are equal and the fourth side can accommodate any dimension of the other sides giving the maximum dimension of each side as 28/3
The dimensions of the deck are width = 28/3 m, breadth = 28/3 m
The area will then be 28/3×28/3 = 784/9 = [tex]87\frac{1}{9}[/tex] =87.11 m²
5. The optimal design for setting the storage area at the corner of their property with four sides is having the dimensions to be that of of a square with equal sides of 10 m each as follows;
Width = 10m
Breadth = 10 m
The optimal design to have the storage area at the back of their building having a fence on only three sides, is given as follows;
Storage area specified = 98 m²
For optimal use of fencing, we have optimal side size of fencing = s = Side length of a square
s² = 98 m²
Therefore, s = √98 = 7·√2 m
Which gives the width = 7·√2 m and the breadth = 7·√2 m.
Solve. x2+5x−2=0 Enter your answers, as exact values, in the boxes. x = or x =
Answer:
[tex]x=\frac{-5+\sqrt{33} }{2}[/tex]
[tex]x=\frac{-5-\sqrt{33} }{2}[/tex]
Step-by-step explanation:
Using the quadratic formula in which a=1, b=5 and c=-2
[tex]x_1=\frac{-b+\sqrt{b^{2}-4ac } }{2a} \\x_2=\frac{-b-\sqrt{b^{2}-4ac } }{2a}\\x_1=\frac{-5+\sqrt{5^{2}-4(1)(-2) } }{2(1)}\\x_1=\frac{-5+\sqrt{33} }{21}\\x_2=\frac{-5-\sqrt{25+8 } }{2}\\x_2=\frac{-5-\sqrt{33} }{2}[/tex]
7 3/8 + (-4 1/2) ÷ (-5 2/3) Please Explain
Answer:
7 3/8 + (-4 1/2) ÷ (-5 2/3) = 8 23/136
Step-by-step explanation:
1) First I turned all the mix numbers into improper fractions:
7 3/8 ----> ( 7(8)+3/8) = 59/8, 4 1/2 ----> (4(2)+1/2) = 9/2, 5 2/3 ----> (5(3)+2/3) = 17/3
So now it should look like this: 59/8 + (-9/2)÷(-17/3)
2) Now our goal is to divide both of the improper fractions (-9/2)÷(-17/3),
- We first apply our fraction rule: -a/-b = a/b (when we have two negatives they cancel out each other and make a positive)
Our Case, From this:-9/2 ÷ -17/3 = To This: 9/2 ÷ 17/3
3) Now we can divide the fractions using this rule: a/b ÷ c/d = a times d / b times
Our Case, From This: 9/2 ÷ 17/3 To This: 9(3)/2(17) Which Gives Us: 27/34
(9 x 3 = 27, 2 x 17= 34)
So now it looks like this: 59/8 +27/34
4) Our look goal is to have the same denominator (which is the bottom part of the fraction) which are 8 and 34
To find it we find the LCM or Least Common Multiple of 8 and 34
(The LCM of a, b is the smallest positive number that is divisible by both a and b) which in this case a and b are 8 and 34
LCM is 136
5) We adjust our two fractions based on the LCM,
(Multiply each numerator ( top part of the fraction) by the same amount of needed to multiply its corresponding denominator to turn it to the LCM 136.
From This: 59/8 and 27/34 To This: 1003/136 and 108/36 ( 59(17)/8 (17) = 1003/136, 27(4)/34(4) = 108/306
6) Finally we can add the numerator (1003 and 108) together: 1003+108= 1111 and now we are left with 1111/136
Then we turn our improper fraction back into a mix number: 1111/138= 8 23/136
Answer:
[tex]\frac{1111}{136} = 8 \frac{23}{136}[/tex]
Step-by-step explanation:
We want to simplify:
[tex]7 \frac{3}{8} + \frac{ -4 \frac{1}{2} }{ -5 \frac{2}{3} }[/tex]
First, convert all the fractions to improper fractions:
[tex]\frac{59}{8} + \frac{ - \frac{9}{2} }{ - \frac{17}{3} } \\\\= \frac{59}{8} + \frac{27}{34}[/tex]
Find the LCM of the denominators:
[tex]\frac{(17 * 59) + (4 * 27)}{136} \\\\ = \frac{1003 + 108}{136}\\ \\= \frac{1111}{136} \\\\= 8 \frac{23}{136}[/tex]
Hey loves!!! This is my last question(for now).Please help.
Answer:
35 degrees.
Step-by-step explanation:
m < TSK = 180 - 22 - 123
= 180 - 145
= 35.
Colin has a pad with x pieces of paper on it. For his first class, he wrote on 5 fewer than half of the pieces of paper in the pad. He used 2 more sheets in his second class than in his first. How many sheets are left for his third class? ill give brainliest to the first answer
Answer:
Colin has 8 sheets left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = [tex]x[/tex]
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:
[tex]\text{Number of pieces of papers used for 1st class =} \dfrac{x}{2} -5 ...... (1)[/tex]
Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.
[tex]\text{Number of pieces of papers used for 2nd class =} \dfrac{x}{2} -5+2 = \dfrac{x}2 -3 ...... (2)[/tex]
Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class
[tex]\text{number of pieces of papers left for the third class = }x-(\dfrac{x}{2}-5)-(\dfrac{x}{2}-3)\\\Rightarrow x-\dfrac{x}2-\dfrac{x}2+5+3\\\Rightarrow x-x+5+3\\\Rightarrow 8[/tex]
So, the answer is:
Colin has 8 sheets left for his third class.
what is the solution for 4x-2=1?
Answer: [tex]x = \frac{3}{4}[/tex]
Step-by-step explanation:
[tex]4x-2=1\\Add(2)\\4x=3\\Divide(4)\\x=3/4[/tex]
Hope it helps <3
Answer:
[tex]\boxed{x=\frac{3}{4}}[/tex]
Step-by-step explanation:
[tex]4x-2=1[/tex]
Add 2 on both sides.
[tex]4x-2+2=1+2[/tex]
[tex]4x=3[/tex]
Divide both sides by 4.
[tex]\displaystyle \frac{4x}{4} =\frac{3}{4}[/tex]
[tex]\displaystyle x=\frac{3}{4}[/tex]
PLEASE HELP!!! URGENT!
Answer:
(D) [tex]p^{2} -9p+18[/tex]
Step-by-step Explanation:
Assuming that the equation [tex]x^{2} -2[/tex] = p, we can convert the equation into this.
[tex]p^{2} +18=9p[/tex]
We can convert [tex]9x^{2} -18[/tex] into 9p because [tex]x^{2} -2[/tex] × 9 = [tex]9x^{2} -18[/tex]
Now we simplify this equation.
We can subtract 9p from both sides of the equation.
[tex]p^{2} +18-9p = 0[/tex]
Re-ordering the equation gets us:
[tex]p^{2} -9p+18[/tex]
So, (D) [tex]p^{2} -9p+18[/tex] is equivalent to the original expression of [tex](x^{2} -2)^{2} + 18 = 9x^{2} -18[/tex]
i need help please eeeeeeee
Answer:
4262
Step-by-step explanation:
[tex]543+23+6+3690=\\500+40+3+20+3+6+3000+600+90=\\3000+600+500+90+40+20+6+3+3=\\3600+500+90+40+20+6+3+3=\\4100+90+40+20+6+3+3=\\4190+40+20+6+3+3=\\4230+20+6+3+3=\\4250+6+3+3=\\4256+3+3=\\4259+3=\\4262[/tex]
Drag each tile to the correct box. The graph shows a proportional relationship between the number of words Shania can type and the time it takes her to type them. What does these ordered pairs mean? (5, 150) (1, 30) (0, 0) _____ Shania types 30 words in 1 minute. --> ______ Shania types 120 words in 4 minutes. ---> ____ Shania types 150 words in 5 minutes. ---> _____ (I REALLY Need help on this ASAP! This is Half of my points. Please help me out!)
Answer: Shania types 30 words in 1 minute. --> (1, 30)
Shania types 120 words in 4 minutes. --> (4,120)
Shania types 150 words in 5 minutes. ---> (5, 150)
Step-by-step explanation:
In the given graph, At x-axis we have Time (minutes) which is an independent variable. On the other hand, at y-axis we have Words type which is dependent varaible.
Point on graph is written in the form (x,y)
So, points corresponding to
Shania types 30 words in 1 minute. --> (1, 30) [here x= 1 and y=30]
Shania types 120 words in 4 minutes. --> (4,120) [here x=4 and y=120]
Shania types 150 words in 5 minutes. ---> (5, 150)[here x= 5 and y=150]
Find each difference.
(6y4+3y2-7)-(12y4-y2+5)
Answer:
-6y^4 + 4y^2 - 12.
Step-by-step explanation:
(6y^4 + 3y^2 - 7) - (12y^4 - y^2 + 5)
= 6y^4 + 3y^2 - 7 - 12y^4 + y^2 - 5
= 6y^4 - 12y^4 + 3y^2 + y^2 - 7 - 5
= -6y^4 + 4y^2 - 12.
Hope this helps!
(x-2)^2 + (y-3)^2=25 up 2units
[tex](x-2)^2+(y-3)^2=25[/tex]
We are given this equation. The equation of a circle with radius r and center (h,k) takes the following form:
[tex](x-h)^2+(y-k)^2=r^2[/tex]
The center of the circle in the given equation is (2,3). Up 2 units would increase the y-value of the center by 2.
Thus, the center of the new circle will be (2,5). Putting this new center into the equation gives us:
[tex](x-2)^2+(y-5)^2=25[/tex]
Let me know if you need any clarifications, thanks~!
The base of a regular pyramid is a hexagon.
Answer:
96[tex]\sqrt{3}[/tex] cm²
Step-by-step explanation:
A hexagon can be cut into 6 equilateral triangles.
Using the half shown in the diagram to calculate the apothem a , and the exact value
sin60° = [tex]\frac{\sqrt{3} }{2}[/tex] , then
sin60° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{a}{8}[/tex] = [tex]\frac{\sqrt{3} }{2}[/tex] ( cross- multiply )
2a = 8[tex]\sqrt{3}[/tex] ( divide both sides by 2 )
a = 4[tex]\sqrt{3}[/tex] cm
The area (A) can be calculated using
A = [tex]\frac{1}{2}[/tex] pa ( p is the perimeter of the hexagon )
The sides of the hexagon measure 8 cm ( equilateral Δ has congruent sides )
p = 6 × 8 = 48 cm, so
A = [tex]\frac{1}{2}[/tex] × 48 × 4[tex]\sqrt{3}[/tex] = 96[tex]\sqrt{3}[/tex] cm²
f(x) = (x + 1)2
What is the domain of f?
Choose 1 answer:
All real values of x such that x = -1
All real values of such that > -1
All real values of x such that I + 0
All real values of x such that 2 > 0
غم عصتلحينلحصعالم
Answer:
all real numbers
Step-by-step explanation:
f(x) = (x + 1)^2
There is no restriction on x, so the domain is:
all real numbers
Can somone answer my question please: 3cm squared onverted to 100mm squared = 300cm squared?
Answer:
hi you can solve this sum by 4×side formula
Step-by-step explanation:
plz solve and check you equation
ASAP URGENT!! Will give BRAINLIEST!!! Using the sine rule work out angle x Look at attached image thx x
Answer: Sorry dont know
Step-by-step explanation:
1) Jo Anne needs to do a speech in her English class that can't be more than 4 minutes
long. She timed herself when she practiced last night and was within the time limit. In class,
her speech was 10 seconds less than the one that she did at home. What are the possible
times for her speech at school?
Answer:
( 0 < y < 23 / 6 ) mins
Step-by-step explanation:
Solution:-
We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.
The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:
( 0 < x < 4 ) minutes
Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:
[tex]10 s * \frac{min}{60 s} = \frac{1}{6} min[/tex]
The time taken by Jo Anne to complete her speech in English class can be represented as:
y = x - 1/6
Using the range of time that Jo Anne could take in delivering her speech in the class would be:
0 < x < 4
0 - 1/6 < y < 4 - 1/6
-1/6 < y < 23 / 6
Since time can not be less than zero. We correct the lower limit to " 0 " as follows:
( 0 < y < 23 / 6 ) mins
The possible times for her speech of her at school vary between 0 and 3:50 minutes.
Since Jo Anne needs to do a speech in her English class that can't be more than 4 minutes long, and she timed herself when she practiced last night and was within the time limit, and in class, her speech was 10 seconds less than the one that she did at home, to determine what are the possible times for her speech at school the following calculation must be performed:
If she in her house was within the time limit, at most her speech had a duration of 4 minutes, with which the maximum limit here is 3 minutes and 50 seconds.Therefore, the possible times for her speech of her at school vary between 0 and 3:50 minutes.Learn more in https://brainly.com/question/22690925
What is the x-intercept of the line 4x - 3y = 16?
What is the x-intercept of the line 10x - 5y = 40?
What is the x-intercept of the line y = -3x - 9?
Answer:
1.
[tex](x , y) = (4 ,\: 0)[/tex]
2.
[tex](4,0) = (x,y)[/tex]
3.
[tex](x,y) = ( - 3,0)[/tex]
I hope it helps :)
The solution to an inequality is given in set-builder notation as {x l x > two-thirds}. What is another way to represent this solution set?
Answer:
[tex](\frac{2}{3},\infty)[/tex]
Step-by-step explanation:
Set builder notation is a mathematical notation used to write the elements of a set stating the conditions that the elements of the set must satisfy. A solution set is also a way of defining solutions to equations and inequalities. A solution set contains a set of all variables for which the equation is true.
The notation {x l x > two-thirds} is a set of all real numbers greater than 2/3, it can also be represented as:
[tex](\frac{2}{3},\infty)[/tex]
Answer:
c) (two-thirds, ∞)
Step-by-step explanation:
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