Answer:
The correct answer is C
Explanation:
In this problem we must remember that charges of the same sign repel and of the same sign attract.
Generator G induces a charge in the closest spheres C, otherwise the charge is negative, therefore in the furthest sphere F, with the ac that is in contact, a positive charge is formed, they do not indicate that the spheres It is in contact with Earth, so the charges remain on them.
As the spheres move away from the generator, the load is redistributed, they return to their initial load, that is, they remain Neutral since no load left or entered the spheres, there was only a redistribution due to the proximity of the generator.
The correct answer is C
A stone of mass 1kg is thrown at 10m/s upwards making an angle of 37°with the horizontal from a building that is 20m high. Using the law of conservation of energy calculate the speed wjen the stone hits the ground.
Answer:
31.68 m/s
Explanation:
The law of conservation of energy states that energy is not lost or gained it is just converted, in this example, since it is not given any resistance from the wind, you'd have two variables Speed on the Y-axis and on the X-axis, since both of them would result in the same decrease and increase with against gravity, it doesn't matter the value of both.
As the stone continues to go upwards it will continue to lose speed due to de-acceleration from the gravity acting on it, similarly, it will continue to gain Potential energy, instead of kinetic energy, when it reaches its highest point the speed on Y will be "0" and the free fall will start, since the up and down movement will be equal in time the and acceleration would be equal -9.81 m/s and 9.81 m/s because the only acceleration you have is gravity, you only need to calculate how much speed will gain a rock accelerating at 9.81 m/s falling 20 m:
[tex]H=\frac{1}{2}g*t^{2} \\\frac{20}{1/2*9.81} =t^{2} \\\\t^{2} =4.08\\t=\sqrt{4.08} \\t=2.21[/tex]
Now we just add the time accelerating:
[tex]Vf=Vo+at\\Vf=10 m/s+ 2.21*9.81\\Vf=10 m/s+21.68\\Vf=31.68 m/s[/tex]
pls help everything is in the pic
Answer:
c
Explanation:
4.The equation for Kinetic Energy is 1/2 x m x v2. Calculate the KE when the mass is 5 kg and the velocity is 4 m/s.
a.2 joules
b.10 joules
c.20 joules
d.40 joules
Explanation:
KE = ½mv²
= ½ × 5 × 4²
= ½ × 5 × 16
= ½ × 80
= 40 J
if you make a sound by tapping on a glass of water what is the order of vibration
A. glass - water - air
C. air - water - glass
B. water - glass - air
Answer:
A.) glass water air
Explanation:
hope this helps :) have a great day!!
Answer:
A.) glass - water - air
good luck, i hope this helps :)
How do we know that an object has accelerated?
When a wave hits an object,energy from the wave is both absorbed and reflected off the object
A. True
B. False
P.S pls help
Solids have a definite shape and volume this is because
A 1 800-kg pile driver is used to drive a steel I-beam into the ground. The pile driver falls 4.60 m before coming into contact with the top of the beam, and it drives the beam 13.6 cm farther into the ground before coming to rest. Using energy considerations, calculate the average force the beam exerts on the pile driver while the pile driver is brought to rest.
Answer:
F = 614913.88 N
Explanation:
We are given;
Mass of pile driver; m = 1800 kg
Height of fall of pole driver; h = 4.6 m
Depth driven into beam; d = 13.6 cm = 0.136 m
Now, from energy equations and applying to this question, we can write that;
Workdone = Change in potential energy
Formula for workdone is; W = F × d
While the average potential energy here is; W = mg(h + d)
Thus;
Fd = mg(h + d)
Where F is the average force exerted by the beam on the pile driver while in bringing it to rest.
Making F the subject, we have;
F = mg(h + d)/d
F = 1800 × 9.81 × (4.6 + 0.136)/0.136
F = 614913.88 N
Using Figure 2, what is the momentum of Train Car A before the collision?
A
180,000 kg*m/s
B
0 kg*m/s
C
11,250 kg*m/s
D
4 kg*m/s
Answer:
Option A. 180000 Kgm/s.
Explanation:
From the question given above, the following data were obtained:
For Train Car A:
Mass of train car A = 45000 Kg
Velocity of train car A = 4 m/s
Momentum of train car A =?
For Train Car B:
Mass of train car B = 45000 Kg
Velocity of train car B = 0 m/s
Momentum is simply defined as the product of mass and velocity. Mathematically, it can be expressed as:
Momentum = mass × velocity
With the above formula, the momentum of train car A before collision can be obtained as follow:
Mass of train car A = 45000 Kg
Velocity of train car A = 4 m/s
Momentum of train car A =?
Momentum = mass × velocity
Momentum = 45000 × 4
Momentum of train car A = 180000 Kgm/s
A constant electric field of 5.00 N/C points along the positive x-direction. An electron, initially at rest, moves a distance of 2.00 m in this space. How fast is the electron moving after its 2.00 m journey
Answer:
1.875 x 10⁶ m /s .
Explanation:
Force on electron = E e where E is electric field and e is charge on electron
acceleration generated = Ee / m where m is mass of the electron .
Putting the values
acceleration generated = 5 x 1.6 x 10⁻¹⁹ / 9.1 x 10⁻³¹
= .879 x 10¹² m /s²
v² = u² + 2 as , initial velocity u = 0 , displacement s = 2 m
v² = 0 + 2 x .879 x 10¹² x 2
v = 1.875 x 10⁶ m /s .
Astronomers discover a planet orbiting around a star similar to our sun that is 35 light years away. How fast must a rocket ship go if the round trip is to take no longer than 70 years in time for the astronauts aboard
Answer:
[tex]v = 0.7071c[/tex]
Explanation:
Given
Distance to the planet = 35 light years. So, the entire distance is: 2 * 35 = 70.
[tex]\triangle{x'} = 70[/tex]
[tex]T_0 = 70\ years[/tex] i.e time of travel of the ship.
For the observer on earth, the time is:
[tex]T' = \gamma T_0[/tex]
The required speed so that it does not take more than 70 years is then calculated using:
[tex]\triangle x' = vT'[/tex]
Substitute [tex]T' = \gamma T_0[/tex]
[tex]\triangle x' = v\gamma T_0[/tex]
[tex]\gamma = \frac{1}{\sqrt{1 - v^2/c^2}}[/tex]
So, we have:
[tex]\triangle x' = \frac{vT_0}{\sqrt{1 - v^2/c^2}}[/tex]
Make v the subject of formula.
Square both sides
[tex]\triangle x'^2 = \frac{v^2T^2_0}{1 - v^2/c^2}[/tex]
Cross Multiply
[tex](1 - \frac{v^2}{c^2}) *\triangle x'^2 = v^2T^2_0[/tex]
Divide both sides by [tex]\triangle x'^2[/tex]
[tex](1 - \frac{v^2}{c^2}) = \frac{v^2T^2_0}{\triangle x'^2}[/tex]
Divide through by [tex]v^2[/tex]
[tex](\frac{1}{v^2} - \frac{v^2}{v^2*c^2}) = \frac{v^2T^2_0}{v^2\triangle x'^2}[/tex]
[tex]\frac{1}{v^2} - \frac{1}{c^2} = \frac{T^2_0}{\triangle x'^2}[/tex]
Make [tex]\frac{1}{v^2}[/tex] the subject
[tex]\frac{1}{v^2} = \frac{T^2_0}{\triangle x'^2} + \frac{1}{c^2}[/tex]
Inverse both sides
[tex]v^2 = \frac{1}{\frac{T^2_0}{\triangle x'^2} + \frac{1}{c^2}}[/tex]
Take square root of both sides
[tex]v = \sqrt{\frac{1}{\frac{T^2_0}{\triangle x'^2} + \frac{1}{c^2}}}[/tex]
Substitute values for [tex]T_0[/tex] and [tex]\triangle x[/tex]
[tex]v = \sqrt{\frac{1}{\frac{70^2}{(70c)^2} + \frac{1}{c^2}}}[/tex]
[tex]v = \sqrt{\frac{1}{\frac{70^2}{70^2*c^2} + \frac{1}{c^2}}}[/tex]
[tex]v = \sqrt{\frac{1}{\frac{1}{c^2} + \frac{1}{c^2}}}[/tex]
[tex]v = \sqrt{\frac{1}{\frac{2}{c^2}}}[/tex]
[tex]v = \sqrt{\frac{c^2}{2}}[/tex]
[tex]v = c\sqrt{\frac{1}{2}}[/tex]
[tex]v = c * 0.7071[/tex]
[tex]v = 0.7071c[/tex]
The all-digital touch-tone phones use the summation of two sine waves for signaling. Frequencies of these sine waves are defined as 697, 770, 852, 941, 1209, 1336, 1477, and 1633 Hz. Since the sampling rate used by the telecommunications is 8000 Hz, convert those eight analog frequencies into digital frequencies of radians and cycles.
Two masses are suspended by cord that passes over a pulley with negligible mass. The cord also has negligible mass. One of the masses, m1, has a mass of 7.0 kg and the other mass, m2, has a mass of 3.0 kg. The pulley turns on a shaft through the center of the pulley and supports the pulley and all the masses. The vertical force of the shaft on the pulley that supports the whole system is
Answer: F = 98N
Explanation: The shaft have to sustain the pulley, the cord and the two masses. The pulley and the cord have negligible masses, so, they have negligible weight.
The two masses have two vertical forces acting on them: force of traction because of the cord and force due to gravitational force, also known as weight.
So, the vertical force the shaft has to support is the sum of the weight of each mass:
[tex]F_{net}=F_{g}_{1}+F_{g}_{2}[/tex]
[tex]F_{net}=m_{1}.g+m_{2}.g[/tex]
[tex]F_{net}=g(m_{1}+m_{2})[/tex]
[tex]F_{net}=9.8(7+3)[/tex]
[tex]F_{net}=[/tex] 98
The vertical force that supports the whole system is 98 N.
A girl standing on a bridge throws a stone vertically downward with an initial velocity of 15.0 m/s into the river below. If the stone hits the water 2.00 seconds later, what is the height of the bridge above the water
Answer:
the height of the bridge above the water is 49.6 m.
Explanation:
Given;
initial velocity of the stone, u = 15 m/s
time of motion of the stone, t = 2 s
The height of the bridge above the water is calculated from the following kinematic equation as follows;
h = ut + ¹/₂gt²
h = (15 x 2) + ¹/₂(9.8)(2²)
h = 30 + 19.6
h = 49.6 m
Therefore, the height of the bridge above the water is 49.6 m.
PLEASEEEE HELP MEEEEE!!!!
Answer:
D. Yes
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m mb
m
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m
n
nn
n
n
n
j
j
jj
Giving 50 points exactly 50 point and making brainles and if answered wrong I will report and get you kicked out
Draw a picture showing how Heat is added, released, and transferred from one object to another. Also, draw a picture explaining how sublimation or deposition works. please you can draw in your book and take a picture and post it
Answer:
i hope this helps i did'nt quiet understand the secound one. I hope youcan see my picture well .
Explanation:
sincerily, MEMC3891
Solar flares are disturbances on the Sun’s surface that send large amounts of energy away from the Sun’s surface. These disturbances can often interfere with technology here on Earth. What statement BEST describes the cause of solar flares?
Answer:
with that boom and that boom glare boom that boom glare with that boom the tha ba glare boom that boom glare with that.
Explanation:
5. Friction has two components __________ and ___________.
Answer:
static friction and kinetic friction.
Explanation:
The current supplied by a battery in a portable device is typically about 0.122 A. Find the number of electrons passing through the device in two hours.
Earth has seasons because _____.
it rotates on its axis as it moves around the sun
the temperature of the sun changes
its axis is tilted
the distance between Earth and the sun changes
Answer:
c, its axis is tilted
maybe
As it works its way around the sun, its tilted axis exposes different parts of earth.
C would be it because the roation of Earth on its axis doesn't have anything to do with the exposer of the revolution on its axis
How can you describe the orbital period (planetary year) of each planet?
Answer:
How can you describe the orbital period (planetary year) of each planet?
A year is defined as the time it takes a planet to complete one revolution of the Sun, for Earth this is just over 365 days. This is also known as the orbital period. Unsurprisingly the the length of each planet's year correlates with its distance from the Sun.
Explanation:
Answer: The orbital period is how long it takes a plane to fulfill its "revolution"(365 days)
Explanation:
If the gravitational constant is extremely weak, how is the force of gravity on earth so strong?
list 5 types of food that should be consumed daily in a healthy diet.Give an example of each type.
Answer:
vegetables and legumes or beans
fruit
lean meats and poultry, fish, eggs, tofu, nuts and seeds, legumes or beans
grain (cereal) foods, mostly wholegrain or high cereal fibre varieties
milk, yoghurt, cheese or alternatives, mostly reduced fat.
Explanation:
Foods are grouped together because they provide similar amounts of key nutrients. For example, key nutrients of the milk, yoghurt, cheese and alternatives group include calcium and protein, while the fruit group is a good source of vitamins, especially vitamin C.
The nucleus of 8Be, which consists of 4 protons and 4 neutrons, is very unstable and spontaneously breaks into two alpha particles (helium nuclei, each consisting of 2 protons and 2 neutrons).
(a) What is the force between the two alpha particles when they are 6.60 ✕ 10−15 m apart? N
(b) What is the initial magnitude of the acceleration of the alpha particles due to this force? Note that the mass of an alpha particle is 4.0026 u. m/s2
Answer:
a) F = 21.16 N, b) a = 3.17 10²⁸ m / s
Explanation:
a) The outside between the alpha particles is the electric force, given by Coulomb's law
F = [tex]k \frac{ q_1 q_2}{r^2}[/tex]
in that case the two charges are of equal magnitude
q₁ = q₂ = 2q
let's calculate
F = [tex]9 \ 10^9 \ \frac{ (2 \ 1.6 \ 10^{-19} )^2 }{ (6.60 \ 10^{-15} )^2 }[/tex]
F = 21.16 N
this force is repulsive because the charges are of the same sign
b) what is the initial acceleration
F = ma
a = F / m
a = [tex]\frac{21.16}{4.0026 \ 1.67 \ 10^{-27} }[/tex]21.16 / 4.0025 1.67 10-27
a = 3.17 10²⁸ m / s
this acceleration is in the direction of moving away the alpha particles
Two objects are located on an airtrack (you may assume there is no friction). The magnitude of the charge on object A is 5 times higher than on object B, and object A also has a 6 times higher mass than object B (the picture is not scale or necessarily in the correct direction). Each object is accelerating in the direction of the arrows.
a. Draw a system schema.
b. Draw the force body diagrams for each charge and identify all newton 3d law pairs.
c. Write (in symbolic form) expressions for the net force on each object.
d. Find how many times faster/slower the acceleration of object B is compared to object A?
Answer:
Explanation:
From the information given:
The schematic diagram for the system and the force body diagrams for each charge can be seen in the image attached below
(c)
The symbolic expressions for the net force on each object is as follows:
[tex]N_A = m_Ag \\ \\ F_{net}, A= F_A = \dfrac{kQ_AQ_B}{r^2}[/tex]
[tex]N_B = m_Bg \\ \\ F_{net}, B= F_B = \dfrac{kQ_AQ_B}{r^2}[/tex]
(d) From above
[tex]F_A =F_B[/tex]
[tex]m_Aa_A = m_Ba_B \\ \\ (6m_B)a_A = m_B a_B[/tex]
[tex]a_B = 6a_A[/tex]
High-voltage power lines are a familiar sight throughout the country. The aluminum wire used for some of these lines has a cross-sectional area of 4.8 x 10-4 m2. What is the resistance of 14 kilometers of this wire
Answer:
Explanation:
For resistance of a wire , the formula is as follows
R = ρ L / S
where ρ is specific resistance , L is length and S is cross sectional area
Given L = 14 000 m ,
S = 4.8 x 10⁻⁴ m²
specific resistance of aluminum = 2.8 x 10⁻⁸ ohm-meter
Putting the values in the formula
R = 2.8 x 10⁻⁸ x 14 x 10³ / (4.8 x 10⁻⁴ )
R = 0.8167 ohm .
= .82 ohm .
Question: How did NASA use Newton's Laws to land the Perseverance lander,
safely
on Mars?
Please help asap.
Answer:
If the thrust is increased, the aircraft accelerates and the velocity increases. This is the second part sited in Newton's first law; a net external force changes the velocity of the object. The drag of the aircraft depends on the square of the velocity. So the drag increases with increased velocity.
A 12 V battery is connected across a device with variable resistance. As the resistance of the device increases, determine whether the following quantities increase, decrease, or remain unchanged. HINT (a) The current through the device. increases decreases remains unchanged (b) The voltage across the device. increases decreases remains unchanged (c) The power consumed by the device. increases decreases remains unchanged
Answer:
a) DECREASE, b) INCREASE, c) power remains constant
Explanation:
The resistance and the battery are connected in series.
a) How the current changes when the resistance changes
V = I R
I = V / R
I = 12 / R
if the resinification increases, the current must DECREASE
b) when you check the expression
V= I R
, if R increases the voltage of the INCREASE
c) the power in an electric circuit is
P = I V
Let's analyze this expression, the voltage increases linearly with the increase in resistance and the current decreases linearly with the increase in r, for which the two effects are compensated and the dissipated power remains constant
If the magnetic force is 3.5 × 10–2 N, how fast is the charge moving?
Answer:
D
Explanation:
Took it on edg
The speed of the charge at the given magnetic force and field is determined as 1.1 x 10⁴ m/s.
Speed of the chargeThe speed of the charge is calculated as follows;
F = qvBsinθ
v = F/qBsinθ
where;
F is the magnetic forceB is magnetic fieldv is speed of the chargev = (3.5 x 10⁻²)/(8.4 x 10⁻⁴ x 6.7x 10⁻³ x sin35)
v = 10,842.33 m/s
v ≅ 1.1 x 10⁴ m/s
Learn more about speed of charge here: https://brainly.com/question/24116470
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The resolution of a lens can be estimated by treating the lens as a circular aperture. The resolution is the smallest distance between two point sources that produce distinct images. This is similar to the resolution of a single slit, related to the distance from the middle of the central bright band to the firstorder dark band; however, the aperture is circular instead of a rectangular slit which introduces a scale factor. Suppose the Hubble Space Telescope, 2.4 m in diameter, is in orbit 90.4 km above Earth and is turned to look at Earth. If you ignore the effect of the atmosphere, what is the resolution of this telescope for light of wavelength 557 nm?
Answer:
y = 2.56 10⁻² m
Explanation:
The resolution of this telescope is given by the Rayleigh criterion, for the phenomenal diffraction the first minimum for a linear slit is in
a sin θ = λ
in general the angles are very small, so we approximate
sin θ = θ
we substitute
θ = λ / a
in the case of circular slits we must use polar coordinates, which introduces a numerical factor, leaving the equation
θ = 1.22 [tex]\frac{\lambda }{D}[/tex]
where D is the diameter of the circular opening
In this case they indicate the lens diameter D = 2.4 m, the observation distance r = 90.4 km = 90.4 10³ m
how angles are measured in radians
θ = y / r
we substitute
y / r = 1.22\frac{\lambda }{D}
y = 1.22 \frac{\lambda r }{D}
let's calculate
y = [tex]1.22 \frac{ 557 \ 10^{-9} \ \ 90.4 \ 10^{3} }{2.4}[/tex]
y = 2.56 10⁻² m
this is the minimum distance that can differentiate two objects on Earth