1. The probability that exactly 12 students drive to school is 0.169.
2.The probability that more than 15 students drive to school is 0.027.
3. The probability that no more than 10 students drive to school is 0.004.
4. The mean and standard deviation of the sample are 13.6 and 2.4, respectively.
5. The percentage falling within 1 standard deviation of the mean is approximately 68%, which satisfies the empirical rule for normal distributions.
This problem involves the binomial distribution, since each student either drives to school (success) or does not (failure), and the probability of success is given as 0.68 for each student.
(1) The probability that exactly 12 students drive to school is given by the binomial probability mass function:
P(X = 12) [tex]= (20 choose 12) * (0.68)^12 * (1 - 0.68)^(20 - 12) = 0.169[/tex]
(2) The probability that more than 15 students drive to school is given by the complement of the probability that at most 15 students drive to school:
P(X > 15) = 1 - P(X <= 15) = 1 - sum[(20 choose i) * [tex](0.68)^i * (1 - 0.68)^{20 - i)}[/tex] for i = 0 to 15.
This is approximately 0.027.
(3) The probability that no more than 10 students drive to school is given by the cumulative distribution function:
P(X <= 10) = sum[(20 choose i) * [tex](0.68)^i * (1 - 0.68)^{20 - i}[/tex] for i = 0 to 10. This is approximately 0.004.
(4) The mean of the binomial distribution is given by the formula np, where n is the sample size and p is the probability of success.
Thus, the mean is 200.68 = 13.6.
The standard deviation of the binomial distribution is given by the formula sqrt(np(1-p)), which is approximately 2.4.
(5) The percentage falling within one standard deviation of the mean is approximately 68% by the empirical rule, which is the same as the percentage of students who drive to school in the university.
However, the empirical rule applies to normal distributions, and the binomial distribution is not exactly normal.
Nonetheless, for large sample sizes, the binomial distribution can be approximated by a normal distribution using the central limit theorem, which would make the empirical rule applicable.
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Brian makes the following claim: "If a function f :R + R is bijective, it must be either strictly increasing or strictly decreasing" a) Prove Brian is wrong Hint: Consider piecewise functions b) Bandar now claims the opposite direction: "If a function f :R → R is strictly in- creasing or strictly decreasing, it must be bijective". Is Bandar correct? Show your reasoning.
If the function is strictly increasing or strictly decreasing, it must also be surjective, and hence bijective.
What is an inequality equation?
An inequality equation is a mathematical statement that compares two expressions using an inequality symbol such as < (less than), > (greater than), ≤ (less than or equal to), or ≥ (greater than or equal to).
a) To prove Brian wrong, we can provide a counterexample of a bijective function that is neither strictly increasing nor strictly decreasing.
Consider the function f: R → R defined as:
f(x) = x for x ≤ 0
f(x) = x + 1 for 0 < x ≤ 1
f(x) = x − 1 for 1 < x
This function is bijective, as it maps every real number to a unique value, and is continuous everywhere except at x = 0 and x = 1.
However, it is neither strictly increasing nor strictly decreasing since it is constant on the interval (-∞, 0), increasing on the interval (0, 1), and decreasing on the interval (1, ∞).
b) Bandar is not entirely correct. A strictly increasing or strictly decreasing function is indeed injective (one-to-one), but it may not be surjective (onto), and hence may not be bijective.
For example, the function f(x) = x + 1 is strictly increasing but not onto, since there is no real number x such that f(x) = 0.
However, if we restrict the domain and range of the function to a closed interval, say [a, b], then a strictly increasing or strictly decreasing function would be bijective on that interval.
This follows from the intermediate value theorem, which states that a continuous function that maps an interval [a, b] to R takes on every value between f(a) and f(b).
Therefore, if the function is strictly increasing or strictly decreasing, it must also be surjective, and hence bijective.
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solve this problem and I will give a brain list to whoever's work is correct with the correct answer and explaintion on how they got it.
Answer:
Step-by-step explanation:
Answer: 128.67041523
Evaluate the triple integral x dv where E is the solid bounded by the paraboloid x = 7(y^2) + 7(z^2) and x=7.
The triple integral x dV over the solid E is (7π/20)√7. We need to evaluate the triple integral x dV over the solid E, where E is the solid bounded by the paraboloid x = 7(y^2) + 7(z^2) and the plane x=7.
We can express the solid E as:
E = {(x, y, z) | 0 ≤ x ≤ 7, 0 ≤ y^2 + z^2 ≤ x/7 }
Then the integral can be set up as:
∭E x dV = ∫0^7 ∫0^√(x/7) ∫-√(x/7-y^2)^(x/7-y^2) x dz dy dx
We integrate first with respect to z:
∫-√(x/7-y^2)^(x/7-y^2) x dz = x(√(x/7-y^2) - (-√(x/7-y^2))) = 2x√(x/7-y^2)
Now, we can substitute this expression and evaluate the integral with respect to y:
∫0^√(x/7) ∫-√(x/7-y^2)^(x/7-y^2) x dz dy = 2x ∫0^√(x/7) √(x/7-y^2) dy
Making the substitution y = (x/7)sin(t), dy = (x/7)cos(t)dt, we get:
∫0^√(x/7) √(x/7-y^2) dy = (x/7) ∫0^π/2 √(1-sin^2(t)) cos(t) dt
Using the substitution u = sin(t), du = cos(t)dt, we obtain:
∫0^√(x/7) √(x/7-y^2) dy = (x/7) ∫0^1 √(1-u^2) du = (x/7) (π/4)
Substituting this expression into the integral for y, we obtain:
∫0^7 2x(√(x/7-y^2)) dy dx = 2 ∫0^7 x(√(x/7))(x/7)(π/4) dx
= (π/2) ∫0^7 x^(3/2)/7 dx = (π/20)(7^(5/2) - 0) = (7π/20)√7
Therefore, the triple integral x dV over the solid E is (7π/20)√7.
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what is a residual? for a given set of data (paired observations of x and y), how many residuals are there?
A residual is the difference between the observed value of y and the predicted value of y (y-hat) based on the regression equation.
In other words, it is the amount of variation in the data that is not explained by the regression model. For a given set of data with paired observations of x and y, there is one residual for each observation. These residuals are used to assess the accuracy of the regression model and can help identify outliers or areas where the model may need to be improved.
A residual is the difference between an observed value of a dependent variable (y) and its predicted value, based on a regression model. In a given set of data with paired observations of x and y, the number of residuals will be equal to the number of observations. So, if you have n paired observations, there will be n residuals.
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Find the minimum and maximum values of the function subject to the given constraint. (If an answer does not exist, enter DNE.) f(x, y) = 49x^2 + 9y^2, xy = 4 fmin = fmax =
The minimum and maximum values of f subject to the given constraint are both 196.
We can use the method of Lagrange multipliers to find the minimum and maximum values of the function subject to the given constraint. Let's define the Lagrangian function L as:
[tex]L(x, y, λ) = 49x^2 + 9y^2 + λ(xy - 4)[/tex]
Taking partial derivatives of L with respect to x, y, and λ and setting them equal to zero, we get:
∂L/∂x = 98x + λy = 0
∂L/∂y = 18y + λx = 0
∂L/∂λ = xy - 4 = 0
From the first equation, we get y = -98x/λ. Substituting this into the second equation, we get x = ±2√(2/3) and y = ∓4√(3/2) (note that we have two solutions due to the ± sign). Substituting these values into the Lagrangian function, we get:
[tex]f(x, y) = 49x^2 + 9y^2 = 196[/tex]
Therefore, the minimum and maximum values of f subject to the given constraint are both 196.
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Y=-2x+3
Y=3-2x
_(2,-1)
Answer:
the two equations are equal you simply just move the -2x and 3 same equation written differently
What is the median of the data represented by the stem and leaf plot below?
The median of the data represented by the stem and leaf plot is 23.
To find the median of the data represented by the stem and leaf plot, we first need to understand what median is. Median is the middle value in a dataset when the data is arranged in order. If there is an even number of values, then the median is the average of the two middle values.
In this particular stem and leaf plot, we can see that the data is already arranged in order. To find the median, we count the number of values in the dataset. In this case, we have a total of 17 values. Since 17 is an odd number, we know that the median is the value in the exact middle of the dataset.
To find the value in the middle, we count half of the total number of values. Half of 17 is 8.5, so we need to find the 9th value in the dataset.
Looking at the plot, we can see that the 9th value is 23.
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The screenshot explains it all
There are between 14.24 million and 19.86 million teens in the U.S. who, according to estimates, will value helping others highly as adults.
a. Since the margin of error is 13.3%, we can construct a 95% confidence interval as follows:
Point estimate = 81%
Margin of error = 13.3%
Lower limit = 81% - 13.3% = 67.7%
Upper limit = 81% + 13.3% = 94.3%
Therefore, the interval that is likely to contain the exact percentage of all U.S. teenagers who think that helping others who are in need will be very important to them as adults are between 67.7% and 94.3%.
b. To estimate the number of teenagers in the U.S. who think helping others will be very important to them as adults, we can use the point estimate of 81%.
Number of teenagers who think helping others will be very important = 81% of 21.05 million
= 0.81 x 21.05 million
= 17.05 million
Using the margin of error, we can construct a range for our estimate:
Lower limit = 67.7% of 21.05 million = 14.24 million
Upper limit = 94.3% of 21.05 million = 19.86 million
Therefore, the estimate for the number of teenagers in the U.S. who think helping others will be very important to them as adults is between about 14.24 million and 19.86 million.
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given the following anova table for three treatments each with six observations: source sum of squares df mean square treatment 1,134 error 1,122 total 2,256 what is the computed value of f? multiple choice 8 7.22
A. The computed value of F is approximately 7.58, given the following ANOVA table for three treatments each with six observations, we need to find the computed value of F.
To calculate the F-value, follow these steps:
1. Identify the given values in the ANOVA table:
- Treatment sum of squares: 1,134
- Error sum of squares: 1,122
- Total sum of squares: 2,256
- Number of treatments: 3
- Number of observations per treatment: 6
2. Calculate the degrees of freedom (df) for treatment and error:
- Treatment df = (number of treatments - 1) = (3 - 1) = 2
- Error df = (number of treatments * (number of observations per treatment - 1)) = (3 * (6 - 1)) = 15
3. Calculate the mean square for treatment and error:
- Mean square treatment = (treatment sum of squares) / (treatment df) = 1,134 / 2 = 567
- Mean square error = (error sum of squares) / (error df) = 1,122 / 15 ≈ 74.8
4. Calculate the F-value:
- F-value = (mean square treatment) / (mean square error) = 567 / 74.8 ≈ 7.58
The computed value of F is approximately 7.58, which is not among the provided multiple-choice options of 8 or 7.22.
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Complete Question:
given the following Anova table for three treatments each with six observations: source sum of squares df mean square treatment 1,134 error 1,122 total 2,256 what is the computed value of f ?
A. 7.48
B. 7.84
C. 8.84
D. 8.48
3. Find the coordinates of the center and the radis for the circle. x^2+y^2-2x–4y-20 = 0
To find the coordinates of the center and the radius for the circle, we will first rewrite the given equation in the standard form for a circle: (x - h)^2 + (y - k)^2 = r^2, where (h, k) are the coordinates of the center, and r is the radius.
Given equation: x^2 + y^2 - 2x - 4y - 20 = 0
Step 1: Group x and y terms separately.
(x^2 - 2x) + (y^2 - 4y) = 20
Step 2: Add the square of half of the coefficients of x and y terms to complete the square.
(x^2 - 2x + 1) + (y^2 - 4y + 4) = 20 + 1 + 4
Step 3: Rewrite as a square of binomials.
(x - 1)^2 + (y - 2)^2 = 25
So, the coordinates of the center are (1, 2), and the radius of the circle is 5.
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what statistical tests are available for analyzing the results of an experiment with just one independent variable?
The T-test, product-moment correlation, Chi-square are available for analyzing the results of an experiment with just one independent variable
Depending on the type of data and research issue being investigated, statistical tests such as the t-test, product-moment correlation, and chi-square can be used to examine the outcomes of an experiment with only one independent variable. A frequent statistical test for comparing the means of two groups is the t-test. It may be used to compare the means of two groups, such as a control group and an experimental group, in an experiment with one independent variable.
A statistical method for determining the degree and direction of a linear relationship among two continuous variables is product-moment correlation, sometimes referred to as Pearson correlation. When looking at the relationship between two continuous variables, it may be utilized to analyse outcomes of an experiment using a single independent variable. A statistical technique which is chi-square test examines if there is a meaningful correlation between two category variables. When analysing connection among two categorical variables, it may be used to evaluate outcomes of an experiment using a single independent variable.
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By writing f(x) as a sum of partial fractions and thereby obtaining the Maclaurin series in a different way, show that an explicit formula for the nth Fibonacci number is
By writing f(x) as a sum of partial fractions and
By writing the function f(x) as a sum of partial fractions, an explicit formula for the nth Fibonacci number can be derived. The Fibonacci sequence is defined recursively as follows:
F₀ = 0, F₁ = 1, and Fn = Fn-1 + Fn-2 for n ≥ 2.
By expressing the generating function f(x) = x / (1 - x - x²) as a sum of partial fractions, we can obtain a power series representation. Manipulating the resulting series allows us to derive an explicit formula for the nth Fibonacci number.
This approach provides an alternative method to derive the formula and demonstrates the connection between the generating function and the Fibonacci sequence. The explicit formula obtained through this process can be useful in various mathematical and computational applications involving Fibonacci numbers.
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Calculate the volume of the solid obtained by rotating the region bounded by the parabola 28 y = x² and the square root function y= √28x around the x-axis
The volume of the solid obtained by rotating the region bounded by the parabola 28y = x² and the square root function y= √28x around the x-axis is 392π/3.
To find the volume of the solid, we use the method of cylindrical shells.
Consider a vertical strip of thickness dx at a distance x from the y-axis. The strip has height (y₂ - y₁) where y₂ is the value of the square root function and y₁ is the value of the parabola.
From the equation of the square root function, we have:
y₂ = √(28x)
From the equation of the parabola, we have:
y₁ = x²/28
Therefore, the height of the strip is:
(y₂ - y₁) = √(28x) - x²/28
The circumference of the cylindrical shell at x is:
2πr = 2πy₁ = 2π(x²/28)
Thus, the volume of the shell is:
dV = 2π(x²/28) * [√(28x) - x²/28] dx
To find the total volume, we integrate dV from x = 0 to x = 28:
V = ∫₀²⁸ 2π(x²/28) * [√(28x) - x²/28] dx
Simplifying and evaluating the integral, we get:
V = 392π/3
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Question 1-4 are homework.
The sphere pictured below has a radius of 5 in. What is its volume,
rounded to the
nearest tenth.
Like
example 1
I JUST WANT THE ANSWER THAT I CNA PUT IN THE GREEN BOX
Answer:
113.1 inches
Step-by-step explanation:
Using V=4/3 pi r^3, you can use a calculator and just find the volume.
help with this pleaseeeeee
The area of the sector with diameter of 6 km and central angle of 78 degrees is 6.13 km²
How to solve an equation?An equation is an expression that can be used to show the relationship between two or more numbers and variables using mathematical operators.
The area of a figure is the amount of space it occupies in its two dimensional state.
The area of a sector with a central angle of Ф and diameter of d is
Area of sector = (Ф/360) * π * diameter²/4
Given that diameter = 6 km and Ф = 78°;
Area of sector = (78/360) * π * 6²/4 = 6.13 km²
The area of the sector is 6.13 km²
The area and circumference are 7.0165 m² and 9.42 m²
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True or False. If it is true, briefly explain. Otherwise, give a counterex- ample. [4 marks] (a) Any spanning set of a subspace S of R" is a basis for S. (b) If a matrix A can be reduced to a reduced row echelon form R, then col(A) = col(R). (c) If a matrix A can be reduced to a reduced row echelon form R, then row(A) = row(R). (d) The dimnesion of NulA is the number of variables in the equation AX = 0.
A spanning set of a subspace S of R^n is not always a basis for a) False. A spanning set may not be linearly independent, which means it may not form a basis for the subspace. For example, in R², {(1,0), (0,1), (1,1)} is a spanning set for the subspace S={(x,y)∈R² : x=y}, but it is not linearly independent, so it is not a basis for S.
b) True. Row operations do not change the column space of a matrix, so if A can be reduced to R by row operations, then the columns of A and R span the same space. Moreover, R is in reduced row echelon form, which means that the columns of R form a basis for col(A).
c) True. Row operations do not change the row space of a matrix, so if A can be reduced to R by row operations, then the rows of A and R span the same space. Moreover, R is in reduced row echelon form, which means that the rows of R form a basis for row(A).
d) True. The null space of A is the set of all solutions to the homogeneous equation AX=0. By the rank-nullity theorem, dim(NulA)=n-r, where n is the number of variables and r is the rank of A. Since A is in reduced row echelon form, the number of nonzero rows is equal to the rank of A, which means that r is the number of pivot variables, which is the same as n-d, where d is the number of free variables. Therefore, dim(NulA)=d=n-r.
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7. In the video we looked at a Riemann sum for the area under the curve of the function f(x) = x^2 on the interval (0,1).
We showed that the Right-Riemann sum R. (using n rectangles) is Rn= 1/n^3(1^2+2^2 +3^3 +…….+ n^2)
(a) Express the sum Rn using summation notation.
Rn = 1/n^3 * Σ(i^2) from i=1 to n can be expressed as the sum Rn using summation notation
Riemann sum for the area under the curve of the function f(x) = x^2 on the interval (0,1). Right-Riemann sum Rn was 1/n^3(1^2+2^2+3^3+...+n^2).
A series can be represented in a compact form, called summation or sigma notation. The Greek capital letter, ∑ , is used to represent the sum.
To express the sum Rn using summation notation, you can write it as follows:
Rn = 1/n^3 * Σ(i^2) from i=1 to n
This notation means you're summing the squares of i (i^2) for each value of i from 1 to n, and then multiplying the result by 1/n^3.
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A communication signal is given by the function y = sin t/ t
The task is to: a) Derive and equation for dy/dt using the Quotient Rule.
The Quotient Rule is a formula used to find the derivative of a function which is the ratio of two other functions. In this case, we are given a function y that is a ratio of sin t and t:
This is the equation for dy/dt, the derivative of the communication signal function y with respect to t, using the Quotient Rule.
Let me know if you have any further questions.
Step 1: Identify the functions u(t) and v(t) in the given function y(t). In this case, u(t) = sin(t) and v(t) = t.
Step 2: Find the derivatives of u(t) and v(t) with respect to t. The derivative of u(t) with respect to t, denoted as u'(t), is cos(t). The derivative of v(t) with respect to t, denoted as V (t), is 1.
Step 3: Apply the Quotient Rule, which states that if y = u/v, then dy/dt = (v * u' - u * v') / (v^2).
Step 4: Substitute the expressions for u, v, u', and v' into the Quotient Rule equation:
dy/dt = (t * cos(t) - sin(t) * 1) / (t^2)
Step 5: Simplify the expression:
dy/dt = (t * cos(t) - sin(t)) / (t^2)
So, the derived equation for dy/dt using the Quotient Rule is dy/dt = (t * cos(t) - sin(t)) / (t^2).
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our best submission for each question part is used for your score. MY NOTES ASK YOUR TEACHER PRACTICE ANOTHER (-/2 Points DETAILS SCALCET8M 7.4.002.0/3 Submissions Used Wote out the form of the partial fraction decomposition of the function (as in this example) Do not determine the numerical values of the coefficients. () X-22 2 + x - 72 (b) x2 + x + 72
For each question part, the best submission is used for scoring. In the case of this question, we are asked to write out the form of the partial fraction decomposition of two functions without determining the numerical values of the coefficients. For part (a), the function is (x-2)^2 + x - 72 and for part (b), the function is x^2 + x + 72.
To write out the form of the partial fraction decomposition, we first need to factor the denominators of each function. For part (a), we can factor the denominator as (x-9)(x+7). For part (b), we can factor the denominator as (x+9)(x+8).
Next, we need to determine the unknown coefficients in the partial fraction decomposition. However, the question instructs us not to determine the numerical values of the coefficients, so we simply need to write out the form of the decomposition. For part (a), the partial fraction decomposition would have the form:
A/(x-9) + B/(x+7)
And for part (b), the partial fraction decomposition would have the form:
C/(x+9) + D/(x+8)
Overall, the key thing to remember is that we are only being asked to write out the form of the decomposition, not to determine the actual numerical values of the coefficients.
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The set B={[1 0 −3 0],[0 0 1 −1],[0 0 0 −2]} is a basis of the space of upper-triangular 2×2 matrices. Find the coordinates of M=[−2 0 −6 4] with respect to this basis.
Given the basis B = {[1 0 -3 0], [0 0 1 -1], [0 0 0 -2]} for the space of upper-triangular 2x2 matrices, we want to find the coordinates of M = [-2 0 -6 4] with respect to this basis.
Let's express M as a linear combination of the basis vectors:
M = a[1 0 -3 0] + b[0 0 1 -1] + c[0 0 0 -2]
Comparing the corresponding components of M and the basis vectors, we get:
-2 = a,
0 = 0,
-6 = -3a + b,
4 = -b - 2c.
Now, solving this system of linear equations:
-2 = a => a = -2,
-6 = -3(-2) + b => -6 = 6 + b => b = -12,
4 = -(-12) - 2c => 4 = 12 - 2c => 2c = 8 => c = 4.
So, the coordinates of M with respect to the basis B are (-2, -12, 4).
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Do the following. (Round the answers to six decimal places.)(a)Find the probability of being dealt an "aces over kings" full house (three fours and two threes).(b)Find the probability of being dealt a full house.
(a) The probability of being dealt an "aces over kings" full house is 0.00001846.
(b) The probability of being dealt a full house is 0.00144058
(a) To be dealt an "aces over kings" full house, we must have three aces and two kings, or three kings and two aces. The total number of ways to choose three aces from four is (4 choose 3) = 4, and the total number of ways to choose two kings from four is (4 choose 2) = 6.
Alternatively, the total number of ways to choose three kings from four is (4 choose 3) = 4, and the total number of ways to choose two aces from four is also (4 choose 2) = 6. Therefore, the total number of "aces over kings" full houses is:
4 * 6 + 4 * 6 = 48
The total number of five-card hands is (52 choose 5) = 2,598,960. Therefore, the probability of being dealt an "aces over kings" full house is:
P("aces over kings" full house) = 48 / 2,598,960 ≈ 0.00001846
(b) To be dealt a full house, we can have one of two possible situations: either we have three cards of one rank and two cards of another rank, or we have three cards of one rank and two cards of a third rank (i.e., a "three of a kind" and a "pair" that do not match in rank).
The total number of ways to choose one rank for the three cards is (13 choose 1) = 13, and the total number of ways to choose the rank for the two cards is (12 choose 1) = 12 (since we cannot choose the same rank as the three cards).
Alternatively, we can choose the rank for the three cards as (13 choose 1) = 13 and the rank for the three cards as (4 choose 3) = 4, and then choose the rank for the two cards as (12 choose 1) = 12 and the rank for the two cards as (4 choose 2) = 6 (since we cannot choose the same rank as the three cards or the same rank as each other).
Therefore, the total number of full houses is:
13 * 12 + 13 * 4 * 12 * 6 = 3,744
Therefore, the probability of being dealt a full house is:
P(full house) = 3,744 / 2,598,960 ≈ 0.00144058
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a village of 25,000 people has 5000 births and 500 deaths. what is the growth rate for this village?
The growth rate in a village of 25,000 people has 5000 births and 500 deaths is 18%
The growth rate is the parameter that shows the increase in the population in the village. It is described as the ratio of change in population to the original population.
Change in population = Number of births - Number of death
Number of birth = 5000
Number of death = 500
Change in population = 4500
Original population = 25,000
Growth rate = [tex]\frac{4500}{25000}[/tex] * 100%
= 0.18 * 100%
= 18%
With an increase of 4,500 to the population of 25,000 of the village the growth rate is 18%.
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Evaluate the given integral by changing to polar coordinates. ∬Ry2x2+y2dA, where R is the region that lies between the circles x2+y2=a2 and x2+y2=b2 with 0
3.
An above ground round swimming pool has the dimensions of 4.5 ft tall and a diameter
of 18 feet. How much water will it take to fill it completely? Use 3.14 = π Show your work and
include correct units.
The amount of water required to fill the round cylindrical swimming pool completely is 1144.53 ft³
What is the volume of a cylinder?
The shape of the round swimming pool takes a cylindrical shape and the volume of the cylinder can be expressed as: pi multiplied by the sqaure of radius multiplied by the height of the cylinder.
Mathematically, we have:
The volume V of the cylinder = pi × r² × h
Here, radius = diameter/2radius = 18 ft/2 = 9 ftThe volume of the cylinder = 3.14 × 9² × 4.5
The volume of the cylinder = 1144.53 ft³
Therefore, we can conclude that the amount of water required to fill the round cylindrical swimmin pool completely is 1144.53 ft³.
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Indicate which property is illustrated in Step 2.
Step 2: 8 plus parentheses -8 + 10x parentheses -3 x + 3 equals 0
A.
distributive property
B.
inverse property of addition
C.
associative property
D.
commutative property
The property illustrated in Step 2 is the "associative property of addition". which is the correct answer would be an option (C).
What is the Associative Property of Addition?The associative property of addition is a rule which states that when adding three or more numbers, we can arrange them in any configuration, and the resultant sum is unaffected by how they are arranged.
[tex]\text{(a + b) + c = a + (b + c)}[/tex]
The property illustrated in Step 2 is the "associative property of addition". This property states that the order in which we add numbers does not affect the result of the addition.
In Step 2, we use the associative property to rearrange the terms in the expression so that we can more easily apply the distributive property in the next step.
Hence, the correct answer would be option (C).
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Alex has a pile of two pence coins he swapped exactly half of them for the same number of 10 pence coins now she has £4.20 how much money did she originally have ?
The amount of money that Alex originally had would be = £8.4
How to calculate the original amount of money owed by Alex?To calculate the original amount of money that Alex has, the following should be carried out;
Th coins owned by Alex is arranged in piles of coins.
The quantity of coins in piles that is owed by Alex = 2 pence.
Half of the pile of coin = £4.20 = 10 pence.
The original amount she owns = 2 × 4.20 = £8.4
Therefore, the original amount of money that is owned by Alex would be = £8.4
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For f(x) = x² + 1 and g(x) = √8 - x, find a. (fog)(x); b. the domain of f o g . a. (f o g)(x) =…
(Simplify your answer.)
For f(x) = x² + 1 and g(x) = √8 - x, the domain of f o g is x ≤ √8
To find (f o g)(x), we need to substitute g(x) into f(x) wherever we see x. Therefore, (f o g)(x) = f(g(x)) = f(√8 - x) = (√8 - x)² + 1 = 9 - 2√8x + x²
To simplify further, we can write (f o g)(x) as: (f o g)(x) = (x - √8)² + 1
Now, to find the domain of f o g, we need to look at the domain of g(x) and make sure that the input of g(x) does not result in any values that are outside the domain of f(x). The domain of g(x) is all real numbers such that √8 - x ≥ 0, which means x ≤ √8. Therefore, the domain of f o g is x ≤ √8.
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Preventing fatigue crack propagation in aircraft structures is an important element of aircraft safety. An engineering study to investigate fatigue crack inn cyclically loaded wing boxes reported the following crack lengths (in mm): 2.13, 2.96, 3.02, 1.82, 1.15, 1.37, 2.04, 2.47 and 2.60. Calculate the sample average and sample standard deviation. Construct a dot diagram of the data.
To calculate the sample average and sample standard deviation, we can use the following formulas: Sample average (x bar) = (sum of all values) / (number of values)
Sample standard deviation (s) = sqrt((sum of (each value - sample average)^2) / (number of values - 1))
Using these formulas, we get:
x bar = (2.13 + 2.96 + 3.02 + 1.82 + 1.15 + 1.37 + 2.04 + 2.47 + 2.60) / 9
= 2.09 mm
To calculate the sample standard deviation, we first need to find the sum of (each value - sample average)^2:
(2.13 - 2.09)^2 + (2.96 - 2.09)^2 + (3.02 - 2.09)^2 + (1.82 - 2.09)^2 + (1.15 - 2.09)^2 + (1.37 - 2.09)^2 + (2.04 - 2.09)^2 + (2.47 - 2.09)^2 + (2.60 - 2.09)^2
= 0.0193 + 0.6809 + 0.7276 + 0.0256 + 0.7696 + 0.3364 + 0.0036 + 0.1624 + 0.2131
= 2.9385
Using this value and the number of values (9), we can calculate the sample standard deviation:
s = sqrt(2.9385 / (9 - 1))
= sqrt(0.3673)
= 0.6061 mm
To construct a dot diagram of the data, we can simply plot each value on a number line. Here is a dot diagram of the given data:
|
| o
| o o
| o o
| o o o o
---+-------------------
1.0 1.5 2.0 2.5 3.0
Crack Length (mm)
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Check these answers.
Answer: Good but 2
Step-by-step explanation:
2 is wrong rectangle is how much?
a local repair shop charges $109 per hour to fix cars. a new water pump costs $249.98. how many hours does the mechanic work, if the total cost of installing a new water pump is $849.48?
So it takes the mechanic 5.5 hours to install the new water pump. This is a relatively straightforward calculation
To solve this problem, we need to first figure out the Price of the mechanic's labor. We know that the water pump costs $249.98, so we subtract that from the total cost of installation, which is $849.48.
This gives us a total labor cost of $599.50. Next, we need to figure out how many hours of labor that corresponds to. We know that the shop charges $109 per hour, so we can divide the total labor cost by the hourly rate: $599.50 ÷ $109/hour = 5.5 hours.
So it takes the mechanic 5.5 hours to install the new water pump. This is a relatively straightforward calculation, but it's important to understand the relationship between cost, hours, and charges in order to arrive at the correct answer. In general, when you're dealing with service charges and hourly rates,
it's important to keep track of both the cost and the time involved. By doing so, you can ensure that you're getting a fair deal and that you're not overpaying for services. In this case, we can see that the total cost of installation is higher than the cost of the water pump alone,
which tells us that the labor charges are significant. However, by doing the math, we can see that the hourly rate is reasonable and that the total labor cost corresponds to a reasonable amount of time for the mechanic to complete the job.
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