Answers
According to the George Washington Carver quotation, most mistakes are the result of those who prefer to find reasons not to take responsibility for their acts.
To put it another way, people who find reasons to blame others instead of accepting responsibility for their own failings and making changes tend to deflect blame from themselves. The remark implies that taking personal responsibility and being accountable for one's actions are essential for success, even when there may be instances where external forces do contribute to failures. Overall, although this remark may be viewed as a generalization, it does emphasize the need of accepting responsibility for one's actions and attempting to solve challenges rather than finding reasons to blame others.
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Related Questions
Ocean tides are caused by the ______________ pull of the _______ and the _______. The moon
has the __________ effect on the tides. When the Sun, moon and earth are in a straight line, we
have __________ tides. When the Sun, moon and earth are at right angles we have _________
tides. Spring tides are especially _________ tides while neap tides are especially _________
tides.
Answers
Ocean tides are caused by the gravitational pull of the Moon and the Sun. The moon has the strongest effect on the tides. When the Sun, Moon, and Earth are in a straight line, we have spring tides. When the Sun, Moon, and Earth are at right angles, we have neap tides. Spring tides are especially high tides while neap tides are especially low tides.
Ocean tides are caused by the gravitational pull of the moon and the sun on the Earth's oceans. The moon has a greater effect on tides than the sun because it is closer to the Earth.
When the Sun, moon, and Earth are in a straight line, we have higher high tides and lower low tides, which are called spring tides.
When the Sun, moon, and Earth are at right angles, we have less extreme tides, which are called neap tides.
Spring tides occur during a full moon and a new moon, while neap tides occur during a first quarter and a third quarter moon. Spring tides are especially strong tides because the gravitational pull of the moon and the sun are working together to pull the oceans in the same direction. Neap tides are weaker tides because the gravitational pull of the moon and the sun are working against each other, which leads to a lesser tidal range.
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A 1.0-cm tall object is 10 cm in front of a converging lens that has a 30 cm focal length.
Calculate the image position and image height using the thin lens and magnification equations.
Answers
The image distance is -15 cm.
Height of the object, h = 1 cm
Object distance, v = 10 cm
focal length, f = 30 cm
According to thin lens equation,
1/f = 1/u + 1/v
So, 1/u = 1/f - 1/v
1/u = (1/30) - (1/10)
Therefore, the image distance,
u = 30 x 10/(10 - 30)
u = -15 cm
The magnification of converging lens,
M = -u/v = h'/h
Therefore, the height of the image,
h' = h(-u/v)
h' = 1 x -(-15/10)
h' = 1.5 cm
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Determine the force exerted on your hand as you catch a .168 kg ball moving at 16 m/s. Assume the time of contact is .025 s
Answers
Answer:
To determine the force exerted on your hand, we can use the impulse-momentum theorem which states that the change in momentum of an object equals the impulse exerted on it. The impulse is the product of the force and the time of contact. Therefore, we have:
Initial momentum = m * v = 0 (since your hand is initially at rest)
Final momentum = m * vf (where vf is the final velocity of the ball after being caught)
Change in momentum = Final momentum - Initial momentum = m * vf
Impulse = F * t (where F is the force exerted on your hand)
By the impulse-momentum theorem, we have:
m * vf = F * t
Solving for F, we get:
F = m * vf / t
Given, m = 0.168 kg, v = 16 m/s, and t = 0.025 s
Final velocity, vf = 0 m/s (since the ball comes to rest after being caught)
Substituting the values, we get:
F = 0.168 kg * 0 m/s / 0.025 s
F = 0 N
Therefore, the force exerted on your hand when catching a 0.168 kg ball moving at 16 m/s in 0.025 s is 0 N.
Explanation:
A tank filled with water is moving down an inclined
surface with an angle of 15 degree. If
the tank decelerates (slows down) at a= 3.83 m/s2
determine the angle of the free surface relative to the
horizontal direction after deceleration.
Answers
The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.
Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:
KE = (1/2)mv²
where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:
PE = mgh
where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:
(1/2)mv² = mgh
Solving for v, we get:
v = √(2gh)
When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:
t = v/a
The distance traveled by the tank during this time is:
s = (1/2)at²
[tex]=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}[/tex]
The angle of the free surface relative to the horizontal direction after deceleration is given by:
[tex]\theta' = tan^{-1}\dfrac{s}{h}[/tex]
Substituting the values of v and s, we get:
[tex]\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}[/tex]
Substituting the given values of h and a, we get:
[tex]\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2[/tex]
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the refraction index of the first water solutionis equal to 1.3. The second water solution of the same substance has the refraction index of 1.43. How many times does the concentration of the second solution higher than the first one? The refraction index for water is equal to 1.33.
Answers
The refraction index of the first water solution is equal to 1.3. The second water solution of the same substance has the refraction index of 1.43.
The concentration of a solution is not directly related to its refractive index, so we cannot use the given values of refractive indices to calculate the concentration of the two solutions. However, we can use the refractive indices to compare the densities of the two solutions.
When light passes from a medium with a lower refractive index to one with a higher refractive index, it bends towards the normal. Conversely, when light passes from a medium with a higher refractive index to one with a lower refractive index, it bends away from the normal. The amount of bending depends on the refractive indices of the two media and the angle of incidence.
In this problem, we can assume that the light ray is traveling through air, which has a refractive index close to 1. We can use Snell's law to find the angle of refraction at the first interface
sin(θ1) = (n1/n2) * sin(θ2)
Where θ1 is the angle of incidence, θ2 is the angle of refraction, n1 is the refractive index of air (close to 1), and n2 is the refractive index of the first water solution (given as 1.3).
Assuming that the angle of incidence is small, we can use the small angle approximation sin(θ) ≈ θ, and rearrange the equation to get
θ2 ≈ (n1/n2) * θ1
θ2 ≈ (1/1.3) * θ1
θ2 ≈ 0.769 * θ1
At the second interface, the light ray is passing from the first water solution (refractive index of 1.3) to the second water solution (refractive index of 1.43). Using Snell's law again, we get
sin(θ2) = (n2/n3) * sin(θ3)
Where θ3 is the angle of refraction in the second water solution, and n3 is the refractive index of the second water solution (given as 1.43).
Assuming small angles again, we can use sin(θ) ≈ θ and rearrange the equation to get
θ3 ≈ (n2/n3) * θ2
θ3 ≈ (1.3/1.43) * 0.769 * θ1
θ3 ≈ 0.707 * θ1
The indicated angle is the angle of deviation between the incident and emergent rays, which is the sum of the two refraction angles
θ_indicated = θ1 + θ3
θ_indicated ≈ θ1 + 0.707 * θ1
θ_indicated ≈ 1.707 * θ1
We don't know the value of θ1, but we can still make a comparison between the two solutions. Since the angle of deviation depends on the density of the medium, we can say that the second water solution is denser than the first one, because it has a higher refractive index. The amount of the difference in density can be calculated by taking the ratio of the squares of the refractive indices
[tex](n2/n1)^{2}[/tex] = [tex](1.43/1.3)^{2}[/tex] ≈ 1.172
This means that the second solution is about 1.172 times denser than the first one.
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Which is TRUE of the number of doctors per 10,000 people in the United States?
OA. The United States has more doctors than any other nation.
OB.
It is significantly better in urban areas than rural.
O C.
It is very low compared to the numbers in the developing world.
O D.
It is not an accurate measure of the quality of health care in the United States.
Answers
What is true about the number of doctors is D. It is not an accurate measure of the quality of health care in the United States.
What should you know about the numbers of doctors in the United states?The number of doctors per 10,000 people simply tells us the phyiscian proportion in the united states.
But does it suggest that the quality of healthcare in America is way better than many other places? No.
There are Many other factors, Like as access to healthcare facilities, healthcare infrastructure, affordability, and the overall health of the population, contribute to the quality of healthcare in a country.
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Based on the picture, which of the following statements is true?
A
Layer E was deposited after the intrusion of C
B
Intrusion C occurred before the movement on H
C
Layer D was deposited after the movement on H
D
Layer F was deposited before the intrusion of C
Answers
Answer:
A
Layer E was deposited after the intrusion of C B
Please help with these 4 questions
Answers
The amount of time which the impetus was implemented is 3.04 seconds.
The momentum of the automobile is 34124.26 kg*m/s.
How to calculate the valueIn order to figure out the time, the following formula for impulse can be applied: impulse = force x time. Reformulating and rearranging this equation, we reach the derivative of time = impulse / force. With the provided calculations of 536.49 N*s divided by 176.32 N, these figures conclude that the amount of time which the impetus was implemented is 3.04 seconds.
Additionally, we can use the formula of momentum = mass x velocity to further determine the vehicular testament of import. When applying these specified numbers of 2546.9 kg and 13.4 m/s respectively, the momentum of the automobile is 34124.26 kg*m/s.
momentum = 2546.9 kg x 13.4 m/s
= 34124.26 kg
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A nonconducting rod with a uniformly distributed charge
+Q. The rod forms a half-circle with radius R and produces an
electric field of magnitude Earc at its center of curvature P. If
the arc is collapsed to a point at distance R from P (Fig. b),
what is the magnitude of the electric field at P?
Answers
Answer:
It will be same as the length of arc
Explanation:
See we can see that the magnitude of force is equal to the magnitude of the arc so it is equal
2. Hallar las dimensiones de K, sabiendo que F: fuerza, V: velocidad, y que la siguiente fórmula es dimensionalmente correcta: K = F.V + Q Donde: F: Fuerza = [MLT-2] V : Velocidad = [L.T-1]
Answers
The dimensions of K are [tex][ML^2T^{-3}].[/tex]
The dimensions of K can be found by analyzing the dimensions of each term in the formula K = F.V + Q.
The dimension of the first term of the F.V is given by:
[tex][MLT^{-2}] * [LT^{-1}] = [ML^2T^{-3}][/tex]
The dimension of the second term Q is unknown, but we know it must be the same as the dimension of K to ensure that the formula is dimensionally correct. Therefore, we can write:
K = [tex][ML^2T^{-3}] + [Q][/tex]
Since K has the dimension of energy, which is [tex][ML^2T^{-2}][/tex], we can equate the dimensions of K and simplify:
[tex][ML^2T^{-2}] = [ML^2T^{-3}] + [Q][/tex]
[Q] =[tex][ML^2T^{-2}] - [ML^2T^{-3}][/tex]
[Q] = [tex][ML^2T^{-3}][/tex]
Therefore, the dimensions of K are [tex][ML^2T^{-3}].[/tex] as calculated above.
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--The complete question is,
Find the dimensions of K, knowing that F represents force, V represents velocity, and that the following formula is dimensionally correct: K = F.V + Q, where: F represents force and has dimensions of [M L T^-2], V represents velocity and has dimensions of [L T^-1].--
The objective lens and the eyepiece of a microscope are 16.5 cm apart. The objective lens has a magnification of 64× and the eyepiece has a magnification of 10 ×. Assume that the image of the objective lies very close to the focal point of the eyepiece.
Part A) Calculate the overall magnification of the microscope.
Part B) Calculate the focal length of the eyepiece.
Part C) Calculate the focal length of the objective.
Answers
M = M_objective x M_eyepiece
M = 64 x 10
M = 640
Therefore, the overall magnification of the microscope is 640×.
Part B) The magnification of the eyepiece is given by:
M_eyepiece = f_objective / (f_objective + d)
where f_objective is the focal length of the objective lens, and d is the distance between the objective lens and the eyepiece. Since the image of the objective lies very close to the focal point of the eyepiece, we can assume that d is equal to the focal length of the eyepiece, which we will denote as f_eyepiece. Substituting these values into the equation above, we get:
10 = f_objective / (f_objective + f_eyepiece)
We can rearrange this equation to solve for f_eyepiece:
f_eyepiece = f_objective / 10 - 1
The magnification of the objective lens is given by:
M_objective = f_eyepiece / (f_eyepiece - d)
Substituting the value of d, we get:
M_objective = f_eyepiece / (f_eyepiece - f_eyepiece)
M_objective = 1
Therefore, the magnification of the objective lens is 1×. We can use this value to solve for f_objective:
M = M_objective x M_eyepiece
640 = 1 x 10 x (f_objective / (f_objective + f_eyepiece))
Substituting the expression for f_eyepiece that we derived earlier, we get:
640 = 10 x f_objective / (f_objective / 9)
640 = 90
Solving for f_objective, we get:
f_objective = 14.06 cm
Therefore, the focal length of the objective lens is 14.06 cm.
'State the appropriate serving size for a 3 to
5-year-old child for each of the following foods:
a. milk
b. dry cereal
c. fruit
d. vegetable
e. bread
2. Where can a program director locate information about state licensing requirements that address nutrition and food services for young children?
3. Name four sensory qualities that contribute to food's appeal.
4. What are two advantages of using fresh fruits and vegetables in season?
5. List two strategies the menu planner can use to control food costs.
Answers
Based on my own known, the right serving size for a 3 to 5-year-old child are:
a. milk - A single cup
b. dry cereal - 1/2 cup
c. fruit - 1/2 cup
d. vegetable - 2 leafty
e. bread - 1 slice of bread.
What is the serving size?A program director can find state licensing requirements for nutrition and food services for young children on their state's education or health department website.
The four sensations that contribute to food appeal are appearance, aroma, taste, and texture. Using fresh seasonal produce is cheaper and more flavorful. To control food costs, menu planners can use less expensive ingredients and reduce waste.
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Question 10 (1 point)
How many minutes are played in a men's Water Polo match?
four 7-minute quarters
four 6-minute quarters
one 90-minute game
two 20-minute halves
a
b
Od
Review Answers
Answers
The numbers of minutes that were played in a men's Water Polo match is option A: four 7-minute quarters
What is the game about?A water polo game for men comprises of four quarters with each one spanning for 8 minutes of effective play time. Between the initial and subsequent quarters, there is a breather of two minutes, followed by a halftime of five minutes, and then a two-minute interlude between the third and fourth quarters.
The clock ceases to tick during breaks, upon scoring a goal, when the ball is beyond the limits, or when the referee whistles for an offense. The overall duration of a men's water polo game can fluctuate based on the number of interruptions that take place during the match.
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Airport runways are generally designed with a buffer zone around 300 m long beyond the runway end, to accommodate aircraft that land too fast or too far down the runway and go off the end. Where that's not possible, airports are increasingly installing so-called Engineered Material Arresting Systems (EMAS) to prevent runaway aircraft from entering nearby roads, neighborhoods, or waterways. One such system, at an airport, consists of a 132-m -long bed of crushable cement blocks. What average force must this system exert on a 55- Mg jetliner that enters the arrestor bed at 37 m/s if the jet is to stop 100 m into the bed?
Answers
The magnitude of the force is 366,250 N, which is the average force that the EMAS must exert on the jetliner to stop it within the 132-m long bed of crushable cement blocks.
First, we need to calculate the initial kinetic energy of the jetliner:
[tex]= KEi = (1/2)mv^2 \\= (1/2)(55,000 kg)(37 m/s)^2[/tex]
= 48,372,500 J
Next, we can calculate the final kinetic energy of the jetliner:
[tex]= KEf = (1/2)mv^2= (1/2)(55,000 kg)(0 m/s)^2[/tex]
[tex]= 0 J[/tex]
The change in kinetic energy is then:
ΔKE = KEf - KEi = -48,372,500 J
Since the EMAS acts over a distance of 100 m, the average force it exerts is:
[tex]F = \Delta KE/d \\= (-48,372,500 J) / (132 m) \\= -366,250 N[/tex]
The negative sign indicates that the force is acting in the opposite direction to the motion of the jetliner, as it is slowing it down.
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What is the wavelength of a radio wave traveling in a vacuum that has a frequency of 6.50x107Hz?
Answers
The wavelength of a radio wave traveling in a vacuum that has a frequency of 6.50 x [tex]10^{7}[/tex] Hz.
The speed of electromagnetic waves in a vacuum is constant and is equal to 299,792,458 meters per second (m/s). The formula for calculating the wavelength of a wave is
Wavelength = speed of light / frequency
Substituting the given values, we get
Wavelength = 299,792,458 m/s / 6.50 x [tex]10^{7}[/tex] Hz
Wavelength = 4.61 meters
Hence, the wavelength of the radio wave is 4.61 meters when it travels in a vacuum with a frequency of 6.50 x [tex]10^{7}[/tex] Hz.
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A tank filled with water is moving down an inclined
surface with an angle of 15 degree. If
the tank decelerates (slows down) at a= 3.83 m/s2
determine the angle of the free surface relative to the
horizontal direction after deceleration.
Answers
The angle of the free surface relative to the horizontal direction after deceleration is approximately 20.2 degrees.
Let's assume that the tank has a mass of m, the angle of the inclined surface is θ, and the height of the inclined surface is h. The initial kinetic energy of the tank is given by:
KE = (1/2)mv²
where v is the initial velocity of the tank. When the tank reaches the top of the inclined surface, its potential energy is given by:
PE = mgh
where g is the acceleration due to gravity (9.81 m/s²). Since there is no change in the total energy of the system (tank + water), we can equate the initial kinetic energy to the final potential energy:
(1/2)mv² = mgh
Solving for v, we get:
v = √(2gh)
When the tank decelerates with an acceleration of a, its velocity decreases at a rate of a m/s². The time taken for the tank to come to a complete stop is given by:
t = v/a
The distance traveled by the tank during this time is:
s = (1/2)at²
[tex]=\dfrac{1}{2} (\dfrac{v}{a})^2a = \dfrac{v^2}{2a}[/tex]
The angle of the free surface relative to the horizontal direction after deceleration is given by:
[tex]\theta' = tan^{-1}\dfrac{s}{h}[/tex]
Substituting the values of v and s, we get:
[tex]\theta' = tan^{-1}\dfrac{\sqrt{2gh}^2}{2ah}\\\\ = tan^{-1}\dfrac{2h}{3a}[/tex]
Substituting the given values of h and a, we get:
[tex]\theta' = tan^{-1}\dfrac{2(9.81)sin(15)}{3.83}\\ = 20.2[/tex]
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A wave travels through a rope at a speed of 2.1 m/s and has a wavelength of 0.15 m. The wave then passes into a spring where it
travels at a speed of 5.0 m/s. The wave's wavelength in the spring is
m.
Answers
The wavelength of the wave in the spring is 0.357 m.
What is wavelenth?Wavelength is the length of a complete revolution of a wave.
To calculate the wavelength of the wave in the spring, we use the formula below
Formula:
v'/λ' = v/λ........................ Equation 1Where:
v' = Speed of the wave in the ropeλ' = Wavelength of the wave in the ropev = Speed of the wave in the springλ = Wavelength of the wave in the springFrom the question,
Given:
v' = 2.1 m/sλ' = 0.15 mv = 5.0 m/sSubstitute these values into equation 1 and solve for λ
2.1/0.15 = 5.0/λλ = (5×0.15)/2.1λ = 0.357 mHence, the wavelength is 0.357 m.
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The frequency of microwaves in a microwave oven is 2450 MHz . What is the mode number for electromagnetic standing waves in a 42.9- cm -wide microwave oven?
Answers
The mode number for the electromagnetic standing waves in a 42.9-cm-wide microwave oven with a frequency of 2450 MHz is 7.
The mode number of standing waves in a microwave oven can be found using formula:
n = 2L/λ
λ = c/f
where c is the speed of light in vacuum and f is frequency of the microwaves.
We are given frequency of microwaves as 2450 MHz. Converting this to SI units, we get:
[tex]f = 2.45 * 10^9 Hz[/tex]
The speed of light in vacuum is approximately [tex]3.00 *10^8 m/s[/tex].
Now we can calculate wavelength:
[tex]\lambda = c/f \\\lambda = (3.00 * 10^8 m/s) / (2.45 * 10^9 Hz) \\\lambda = 0.1225 m[/tex]
We are also given the width of the microwave oven as 42.9 cm, which we convert to meters:
L = 0.429 m
Now we can calculate the mode number:
[tex]n = 2L/\lambda \\n = 2(0.429 m) / 0.1225 m \\n = 7[/tex]
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How has information technology impacted the economy? Choose three answers.
Answers
Information technology has greatly impacted the economy, leading to increased productivity, efficiency, and innovation across industries.
The widespread adoption of information technology in the business world has led to a significant transformation in the way companies operate. Through the use of computers, software, and other digital tools, businesses are now able to streamline their operations, automate processes, and access vast amounts of data that can inform decision-making.
This has resulted in increased productivity, efficiency, and cost savings for companies. Additionally, information technology has facilitated the rise of new industries, such as e-commerce and digital marketing, while also enabling existing industries to adapt and innovate in response to changing market conditions.
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--The complete question is, How has information technology impacted the economy?--
The components of vectors and are given as follows:
Ax = 7.6Bx = -5.1
Ay = -9.2By = -6.8
What is the magnitude of the vector difference - ?
Answers
The magnitude of the vector difference is approximately 12.98.
To find the magnitude of the vector difference, we need to subtract the components of vector B from the components of vector A and then find the magnitude of the resulting vector.
The components of the vector difference, C = A - B, are given by:
Cx = Ax - Bx = 7.6 - (-5.1) = 12.7
Cy = Ay - By = -9.2 - (-6.8) = -2.4
The magnitude of vector C is given by:
|C| = √(C² + Cy²)
Substituting the values of Cx and Cy, we get:
|C| = √(12.7² + (-2.4)²) = √(162.25 + 5.76) = √168.01
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A group of students have decided to build an electric motor. Their motor looks similar to the one in this diagram: They would like their motor to spin faster. Name two ways to
improve the design of their motor. Explain how each of these will cause the motor to spin
faster.
Answers
Increasing the voltage delivered to an electric motor is one approach to get it to spin more quickly.
How can the electric motor spin faster?
Increasing the voltage will result in a greater magnetic field being produced by the motor, which will then result in a stronger torque being applied to the rotor. The rotor will spin more quickly as a result because the motor's speed and torque are inversely related.
It is crucial to remember that raising the voltage above the motor's recommended voltage can cause overheating and motor damage.
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If a 641.6 grams mass on a spring has a period of 0.52 seconds, what is the spring constant of the spring?
Answers
T = 2π√(m/k)
where T is the period, m is the mass, and k is the spring constant.
Rearranging this equation, we get:
k = (4π²m) / T²
Substituting the given values, we get:
k = (4π² * 0.6416 kg) / (0.52 s)²
k = 25.18 N/m
Therefore, the spring constant of the spring is 25.18 N/m.
explain magnetic flux
Answers
Gender inequality in Machenical Engeenering
Answers
Gender inequality in mechanical engineering can manifest through biased hiring practices, limited opportunities for women to advance to leadership roles, and a lack of representation in the industry.
Despite efforts to promote gender equality, women are still underrepresented in the field of mechanical engineering. This can be due to a variety of factors, including biased hiring practices, limited opportunities for career advancement, and a lack of representation in the industry.
To address these issues, it is important for companies and organizations to promote diversity and inclusion initiatives, such as actively recruiting women and people of diverse backgrounds, providing mentorship and networking opportunities, and advocating for policies that support work-life balance and equal pay. By creating a more inclusive environment, the field of mechanical engineering can attract and retain more talented individuals and foster innovation and growth.
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A student eats a dinner rated as 2000 calories. He wishes to do an equivalent amount of work in the gymnasium by lifting a 50 kg mass. How many times must he raise the weight to expend this much energy? Assume he raised the weight a distance 2 m each time and that no work is done when the weight is dropped to the floor. 1 food calorie = 10 ^ 3 * cal 1cal = 4.186
Answers
Answer:
By using work energy theorem
Intake energy = work out
Intake energy = (number of lifting barbell) x (work done per lifting)
Ei = n x W
Ei = nW
Now
Work per lifting = Force x displacement
W = (mg) x (displacement)
W = (50 x 9.8) x (2)
W = 980 J
Now
Ei = n x W (Ei = 2000 Cal = 2 kilocalory = 8368 Joule)
8368 = n x 980
n = 8.53
Aprrox 8 times he should raise barbell to expend 2000 calory.
Explanation:
What is the boiling point of this substance
Answers
A marathon runner is running the race with a speed of 15 m/s. She completed the race within 15 minutes. What is the distance covered by the athlete if the speed is doubled?
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A marathon runner is running the race with a speed of 15 m/s. She completed the race within 15 minutes.
We can start by using the formula
Distance = speed x time
We know that the marathon runner is running with a speed of 15 m/s and completed the race in 15 minutes, which is equivalent to 900 seconds (15 min x 60 s/min). Therefore, we can calculate the distance covered by the athlete as
Distance = 15 m/s x 900 s = 13,500 meters
Now, we need to find the distance covered by the athlete if the speed is doubled. Let's call this new distance d' and new speed s'.
s' = 2 x 15 m/s = 30 m/s
We can use the same formula to calculate the new distance covered
d' = s' x t
Where t is the same for both distances, as the runner completed the race in the same amount of time.
t = 900 s
d' = 30 m/s x 900 s = 27,000 meters
Hence, if the speed of the marathon runner is doubled, she would cover a distance of 27,000 meters.
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Three objects are moving along a straight line as shown in Figure 8.1. Taking the positive direction to be to the right, what is the total momentum of this system?
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Taking the positive direction to be to the right, the total momentum of this system is - 14kg-m/s
Option B is correct.
What is momentum?momentum is described as the product of the mass and velocity of an object and a vector quantity possessing a magnitude and a direction.
momentum = mass x velocity
momentum 1 = 5 x 8kg = 40 kg-m/s
momentum 2 = 4 x 15 kg = 60 kg-m/s
momentum 3 = 2 x 3kg = 6 kg-m/s
Taking the positive direction to be to the right, the total momentum of this system is momentum 1 - momentum 2 + momentum 3
total momentum = 40 kg-m/s - 60 kg-m/s + 6 kg-m/s
total momentum = -20kg-m/ + 6 kg-m/s
total momentum = - 14 kg-m/s
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Section 14.1 Assessment
Reviewing Concepts
1. What conditions must exist in order for a
force to do work on an object?
2.
What formula relates work and power?
3. How much work is done when a vertical force
acts on an object moving horizontally?
Critical Thinking
4. Applying Concepts A desk exerts an
upward force to support a computer resting
on it. Does this force do work? Explain.
6. Comparing and Contrasting You carry
two heavy bags of groceries upstairs to your
kitchen. Will you do more work on the bags if
you carry them up one at a time? Explain.
Math Practice
7. How much work does a 25-newton
force do to lift a potted plant from the
floor to a shelf 1.5 meters high?
8. You lift a large bag of flour from the
floor to a 1-meter-high counter, doing
100 joules of work in 2 seconds. How
much power do you use to lift the bag
of flour?
5. Predicting Two cars have the same weight,
but one of the cars has an engine that provides
twice the power of the other. Which car can
make it to the top of a mountain pass first?
Which car does more work to reach the pass?
swer assessment questions 1-8 on page 416 (above) in the following space.
Answers
The engine that provides twice more power will make it first
The car with the twice more power does more work
What is the formula?When a vertical force acts on an object moving horizontally, the work done by the force depends on the angle between the force and the displacement of the object. If the force is perpendicular to the displacement, no work is done, since the force does not contribute to the displacement of the object.
The work done is the same as the gravitational potential energy and this is;
W = F h
F = Force
h = height of the object
Thus;
W = 25 * 1.5
= 37.5 J
Then;
Power = Work done/Time
= 100 J/ 2 s
= 50 W
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1.00 kg of ice at -24.0°C is placed
in contact with a 1.00 kg block of a
metal at 5.00°C. They come to
equilibrium at -8.88°C. What is
the specific heat of the metal?
Answers
1.00 kg of ice at -24.0°C is placed in contact with a 1.00 kg block of a metal at 5.00°C. They come to equilibrium at -8.88°C.
We can use the principle of conservation of heat to solve this problem. The heat lost by the metal must equal the heat gained by the ice.
The heat lost by the metal is given by
Q1 = m1c1ΔT1
Where m1 is the mass of the metal, c1 is its specific heat, and ΔT1 is the change in temperature.
The heat gained by the ice is given by
Q2 = m2c2ΔT2
Where m2 is the mass of the ice, c2 is its specific heat, and ΔT2 is the change in temperature.
Since the two objects come to thermal equilibrium, we can set Q1 equal to Q2
m1c1ΔT1 = m2c2ΔT2
Solving for c1, we get
c1 = m2c2ΔT2 / (m1ΔT1)
By putting these values we get
c1 = (1.00 kg)(2.06 kJ/kg·K)(-24.0°C - (-8.88°C)) / [(1.00 kg)(5.00°C - (-8.88°C))]
c1 = 0.902 kJ/kg·K
Hence, the specific heat of the metal is 0.902 kJ/kg·K.
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