Answer:
[tex]molarity =6.9\times 10^{-3}\ M\\[/tex]
Explanation:
We know that , the reaction of HCl and NaOH is given as follows
[tex]NaOH+HCl=NaCl +H_2O[/tex]
Given that
Pressure = 111 mm Hg
[tex]P=111\times 13.6\times 10^{-3}\times 9.81\times 1000=14.809\ kPa[/tex]
Temperature = 20°C
T=20+273=293 K
Volume= 221 m L
V=0.221 L
Number of moles of HCl is given as follows
[tex]n=\dfrac{P\times V}{R\times T}\\n=\dfrac{0.148\times 0.221}{0.821\times 293}=1.3\times 10^{-4}\ moles[/tex]
From the above reaction we can say that
Number of moles of HCl=Number of moles of NaOH
Volume of NaoH is given as follows
V=18.7 = 0.0187 L
Therefore molarity
[tex]molarity =\dfrac{n}{V_{NaOH}}\\molarity =\dfrac{1.3\times 10^{-4}}{0.0187}=6.9\times 10^{-3}\ M\\molarity =6.9\times 10^{-3}\ M\\[/tex]
The table shows the conditions during two trials of a reaction.
Answer:
The correct option is;
The reaction pathway for the trials is different
Explanation:
The effect of a catalyst in a chemical reaction is to increase the rate of a reaction by changing the pathway or mechanism of the reaction and/or to lower the transition state's energy thereby lowering the activation energy of the reaction
The pathway of the reaction is changed by the catalyst by the formation of intermediate compounds by the catalyst which require lower activation energy to form the products than the original non-catalyzed reactants. In the process the catalyst is regenerated, thereby, not taking part in the reaction.
How did Bohr describe the arrangement of particles within an atom?
A. Protons and electrons form the nucleus, with neutrons
orbiting it.
O B. Neutrons make up the atom's nucleus, with electrons and
protons orbiting it.
c. Protons make up the atom's nucleus, with electrons and
neutrons orbiting it.
O D. Protons and neutrons form the nucleus of the atom, with
electrons orbiting it.
Bohr describe the arrangement of particles within an atom by: O D. Protons and neutrons form the nucleus of the atom, with electrons orbiting it.
Who is Niels Bohr?This hypothesis states that the atom's core is a small, compact, positively charged nucleus. Protons which have a positive charge and neutrons which are neutral are both found in the nucleus.
Specific energy levels or electron shells are where the negatively charged electrons orbit the nucleus. Due to the quantization of these energy levels, only a limited number of discrete energy states are accessible to electrons.
Therefore the correct option is D.
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Match each term below with its definition or description.
1 The point in a titration when the added amount of standard reagent is equal to the amount of analyte being titrated.
2 The analyte is titrated with the standard reagent and the volume of standard solution required to complete the reaction is measured.
3 A reagent that is pure and stable, which can be used directly after weighing.
4 The analyte that is being analyzed in the titration.
5 Standard reagent is added in excess to ensure complete reaction with the analyte. The excess reagent is then titrated with a second standard reagent.
6 A solution, whose concentration is known, often made from a reagent of known purity.
7 The standard reagent of known concentration that is added from a buret to the analyte solution.
8 The analyte does not react directly with the titrant so it is converted to another form which will react with the titrant.
9 The point in a titration when a change in the analyte solution is observed, indicating equivalency.
10 It is added to the analyte solution and aids in the observation of the completion of the reaction.
a) End Point
b) Indicator
c) Direct Titration
d) Back Titration
e) Indirect Titration
f) Primary Standard
g) Standard Solution
h) Titrand
i) Equivalence Point
j) Titrant
Answer:
1. Equivalence point
2. Direct titration
3. Primary standard
4. Titrand
5. Back titration
6. Standard solution
7. Titrant
8. Indirect titration
9. End point
10. Indicator
Explanation:
1. The equivalence point is the tiration point at which the quantity or moles of the added titrant is sufficient or equal to the quantity or moles of the analyte for the neutralization of the solution of the analyte.
2. Direct titration is a method of quantitatively determining the contents of a substance
3. A primary standard is an easily weigh-able representative of the mount of moles contained in a substance
4. A titrand is the substance of unknown concentration which is to be determined
5. The titration method that uses a given amount of an excess reagent to determine the concentration of an analyte is known as back titration
6. A standard solution is a solution of accurately known concentration
7. A titrant is a solution that has a known concentration and which is titrated unto another solution to determine the concentration of the second solution
8. Indirect titration is the process of performing a titration in athe reverse order
9. The end point is the point at which the indicator indicates that the equivalent quantities of the reagents required for a complete reaction has been added
10 An indicator is a compound used to visually determine the pH of a solution.
The titration has been the neutralization reaction in which the titrand and the titrant react to form the salt and the water and help in the determination of the qualitative and quantitative properties.
What is an Endpoint?In a titration reaction, the endpoint has been the point at which the equivalent amount of reagent has been completely neutralized.The Indicator has been the chemical that changes to indicate the endpoint of the reaction.Direct titration involves the reaction for the quantitative determination of the substances.The back titration can be given as the reaction in which the excess reagent is used to titrate the second standard reagent in the reaction.Indirect titration can be given as the reaction of the analyte to convert to another form and then the analysis with the titrant.The primary standard has been the known concentration of the pure and stable weighing reagent.The standard solution has been the solution of the known concentration in the reaction.Titrand has been the unknown sample that has to be analyzed.The equivalence point is the concentration point at which the quantity of titrant added to the titrand has been equal.Titrant has been the known concentration of sample that has been added to equivalent the unknown sample.Learn more about titration here:
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May I know how to balance this
Answer:
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
Explanation:
Let's start by counting how many molecules we have on each side.
Reactants
C - 5
H - 12
O - 2
Products
C - 1
O - 3
H - 2
We have to balance both sides. Since we have 5 carbon atoms on the reactants side and 1 carbon atom on the products side, we'll start with that. Write 5 as the coefficient for CO₂ to balance the carbons.
C₅H₁₂ + O₂ → 5CO₂ + H₂O
Now that the carbons are balanced, let's look at the hydrogens. There's 12 on the reactants side and 2 on the products side. To balance the hydrogens, we have to write 6 as the coefficient for H₂O.
C₅H₁₂ + O₂ → 5CO₂ + 6H₂O
Now the hydrogens are balanced. All that's left to do is balance the oxygens. Let's start by counting how many atoms we have on each side.
Reactants
C - 5
H - 12
O - 2
Products
C - 5
H - 12
O - 16
So, to balance the number of atoms on both sides, write 8 as the coefficient for O₂.
C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O
Lastly, let's check to make sure everything is balanced.
Reactants
C - 5
H - 12
O - 16
Products
C - 5
O - 16
H - 12
Both sides are balanced. Therefore, the balanced chemical equation is: C₅H₁₂ + 8O₂ → 5CO₂ + 6H₂O.
Hope that helps.
Answer:
[tex]\boxed{C_{5}H_{12} + 8O_{2} -->5CO_{2} + 6H_{2}O}[/tex]
Explanation:
Part 1: Count the number of atoms on each side per element
To start, count the number of atoms per element on both sides of the equation.
Left Side
C - 5 atoms
H - 12 atoms
O - 2 atoms
Right Side
C - 1 atom
H - 2 atoms
O - 3 atoms
Part 2: Balance carbon atoms
Now, with this information, you can begin finding out how to properly balance both sides of the equation.
You need 5 carbon atoms on the left, so place a coefficient of 5 in front of the [tex]CO_{2}[/tex] product. This will balance the carbons. Do not place a coefficient in front of the [tex]C_{5}H_{12}[/tex] reactant - none are necessary!
Then, you can update your counts for your atoms.
Left Side
C - 5 atoms
H - 12 atoms
O - 2 atoms
Right Side
C - 5 atoms
H - 2 atoms
O - 11 atoms
The updated equation will look like this:
[tex]\boxed{C_{5}H_{12}+O_{2} --> 5CO_{2} + H_{2}O}[/tex]
Part 3: Balance hydrogen atoms
Now, balance the hydrogen atoms. Place a coefficient of 6 in front of the [tex]H_{2}O[/tex] product. This will balance the hydrogen atoms.
Once again, update the atom counts:
Left Side
C - 5 atoms
H - 12 atoms
O - 2 atoms
Right Side
C - 5 atoms
H - 12 atoms
O - 16 atoms
The updated equation will look like this:
[tex]\boxed{C_{5}H_{12} +O_{2}--> 5CO_{2} +6H_{2}O}[/tex]
Part 4: Balance oxygen atoms
To fully balance the equation, place a coefficient of 8 in front of the [tex]O_{2}[/tex] reactant. This will equalize the amount of oxygen atoms on both sides of the equation.
The updated equation will look like this:
[tex]\boxed{C_{5}H_{12} + 8O_{2} --> 5CO_{2} + 6H_{2}O}[/tex]
Part 5: Check the equation and atom counts
Now, update the atom counts one last time to make sure they are equal.
Left Side
C - 5 atoms
H - 12 atoms
O - 16 atoms
Right Side
C - 5 atoms
H - 12 atoms
O - 6 atoms
They are equal, so you may proceed.
Part 6: Check if reductions are necessary
If the equations coefficients can all be divided by a common divisor (i.e., 3), follow up with that step. However, any equation that has a reactant or product without a coefficient, skip this step entirely.
This equation falls into that category, so you may proceed past it.
Your final equation will look like this: [tex]\boxed{C_{5}H_{12} + 8O_{2} -->5CO_{2} + 6H_{2}O}[/tex]
A molecule of chlorine has atoms of the same element, and a molecule of carbon dioxide has different kinds of atoms. Based on this information, chlorine is and carbon dioxide is .
Answer:
chlorine is element and carbon dioxide is compound
Answer:
The correct answer would be that Chlorine is an Element and Dioxide is an Compound.
Why are the oxidation and reduction half-reactions separated in an
electrochemical cell?
Answer:
Electrochemical cells typically consist of two half-cells. The half-cells separate the oxidation half-reaction from the reduction half-reaction and make it possible for current to flow through an external wire.
Explanation:
Why do you think the landscape varies so much throughout the United States?
Answer:
hi there
you're answer would be:
The landscape varies greatly throughout the United States due to geology and weather. Things like volcanoes, the Ice Age, floods, rain, winds and drought have made an impact on the land.
hope this answer correct
A 35 gram of saturated solution is distilled out completely. If the solubility of the solute is 110, find the amount of residue solute snd distilled water
Answer:
3850g
Explanation:
Solubility is the amount of solute dissolved in a solvent.
Solubility is mass of solute÷mass of solvent
The solvent is 35grams
Solute?
Solubility of solute is 110
110=x/35
= 110 × 35
The amount of residue solute is 3850g
Which of these is an example of something a civil engineer would deal with?
A. The rebuilding and redesign of the dam in Louisiana after
Hurricane Katrina
B. A gauge that reads the strength of an earthquake
C. The new hybrid cars that are more environmentally friendly and
reduce oil consumption
D. The design of the Discovery space shuttle
Answer:
A
Explanation:
civil deals with desighning, construction work of natural or physical environment and a fits guess
why ammonium is not a molecular ion
Answer:
See below
Explanation:
Ammonium [tex](NH_{4}^+)[/tex] is not a molecular ion because it is just a poly-atomic ion. A molecular ion has a "negative or positive charge" as a whole but the positive charge on here is not on the whole. So, it is a poly-atomic ion and not molecular ion.
The radioactive isotope used for carbon dating is
1. Carbon 12
2. Carbon 13
3. Carbon 15
4. Carbon 14
Carbon 14 would be your answer, however if it's more than one answer it would also be Carbon 12, so yeah. Your best bet would be Carbon 14.
A tank originally had 12.0 atm, was 3.9L at 25C. If the tank is heated to 591C what is the new pressure ?
Answer:
34.79 atm.
Explanation:
The following data were obtained from the question:
Initial pressure (P1) = 12 atm
Initial temperature (T1) = 25 °C
Final temperature (T2) = 591 °C
Final pressure (P2) =...?
Note: the volume of the tank is constant.
Next, we shall convert celsius temperature to Kelvin temperature. This can be obtained as follow:
Temperature (K) = Temperature (°C) + 273
T(K) = T (°C) + 273
Initial temperature (T1) = 25 °C
Initial temperature (T1) = 25 °C + 273 = 298 K.
Final temperature (T2) = 591 °C
Final temperature (T2) = 591 °C + 273 = 864 K.
Finally, we shall determine the new pressure as follow:
Initial pressure (P1) = 12 atm
Initial temperature (T1) = 298 K.
Final temperature (T2) = 864 K.
Final pressure (P2) =...?
P1/T1 = P2/T2
12/298 = P2/864
Cross multiply
298 x P2 = 12 x 864
Divide both side by 298
P2 = (12 x 864)/298
P2 = 34.79 atm.
Therefore, the new pressure is 34.79 atm.
(Help please!! important test!!!) What property of matter are you measuring if you are using a triple beam balance? (2 points)
volume,
gravity,
mass, or
size
Answer:
mass
Explanation:
The triple beam balance is an instrument used to measure mass very precisely.
A container initially holds 5.67 x 10^10-2 mol of propane and has a volume of V1. The volume of the container was increased by adding an additional 2.95 x 10^-2 mol of propane to the container, so that the container has a final volume of 1.93 L. If the temperature and pressure are constant, what was the initial volume of the container ,V1?
Answer:
The initial volume of the container was 1.27L
Explanation:
Avogadro's law states that under the same pressure and temperature, equal moles of gases occupies equal volume. The equation is:
V₁n₂ = V₂n₁
Where V is volume and n moles of 1, initial state and 2, final state.
In the problem, initial moles are 5.67x10⁻², final moles after the addition are:
5.67x10⁻² + 2.95x10⁻² = 8.62x10⁻² moles
And, after the addition, the volume is 1.93L.
Replacing in Avogadro's law:
V₁×8.62x10⁻² moles = 1.93L×5.67x10⁻² moles
V₁ = 1.27L
The initial volume of the container was 1.27LA 2.00L flask was filled with 4.00 mol of HI at a certain temperature and given sufficient time to react. At equilibrium the concentration of H2 was 0.400 M. Find the equilibrium concentrations of I2 and HI and then find the Keq at this temperature.
Answer:
The equilibrium concentration of I₂ is 0.400 M and HI is 1.20 M, the Keq will be 0.112.
Explanation:
Based on the given information, the equilibrium reaction will be,
2HI (g) ⇔ H₂ (g) + I₂ (g)
It is given that 4.00 mol of HI was filled in a flask of 2.00 L, thus, the concentration of HI will be,
= 4.00 mol/2.00 L
= 2.00 mol/L
Based on the reaction, the initial concentration of 2HI is 2.00, H₂ is 0 and I₂ is O. The change in the concentration of 2HI is -x, H₂ is x and I₂ is x. The equilibrium concentration of 2HI will be 0.200-x, H₂ is x and I₂ is x.
It is given that at equilibrium, the concentration of H₂ or x is 0.400 M.
Now the equilibrium concentration of HI will be,
= 2.00 -2x
= 2.00 - 2 × 0.400
= 1.20 M
The equilibrium concentration of I₂ will be,
I₂ = x
= 0.400 M
The equilibrium constant (Keq) will be,
Keq = [H₂] [I₂] / [HI]²
= (0.400) (0.400) / (1.20)²
= 0.112
Thus, the Keq of the reaction will be 0.112.
During which two minute time period is the temperature of the water changing fastest? Select one: a. 0-2 minutes b. 2-4 minutes c. 4-6 minutes d. 6-8 minutes Clear my choice
Answer:
b. 2-4
Explanation:
Look at the slope of the line, between 0-2 and 4-6 the slope is only 10, but between 2-4 the slope is 20, so that's when the temperature is changing the fastest. In the same time it took for the water to increase by 20 degrees between 0-2 and 4-6, the temperature of the water increased by 40 degrees between 2-4 so that's when the change is the fastest.
g When a 2.75g sample of liquid octane (C8H18) is burned in a bomb calorimeter, the temperature of the calorimeter rises from 22.0 °C to 41.5 °C. The heat capacity of the calorimeter, measured in a separate experiment, is 6.18 kJ/°C. Determine the ΔE for octane combustion in units of kJ/mol octane.
Answer:
The correct answer is 5021.25 kJ/mol octane
Explanation:
The heat absorbed by the calorimeter is given by:
heat absorbed = Ccal x ΔT
Given:
Ccal = 6.18 kJ/ºC (heat capacity of calorimeter)
ΔT= Final temperature - initial temperature = 41.5ºC-22.0ºC = 19.5ºC
We first calculate the heat absorbed:
heat absorbed = 6.18 kJ/ºC x 19.5ºC = 120.51 kJ
The change in internal energy (ΔE) is equal to the heat absorbed by the calorimeter. In order to determine ΔE in kJ/mol we have to divide the heat into the number of moles of octane (C₈H₁₈) burned in the calorimeter.
Molecular weight (C₈H₁₈) = (12 g/mol x 8) + (1 g/mol x 18) = 114 g/mol
Moles of C₈H₁₈= mass/molecular weight= (2.75 g)/(114 g/mol)= 0.024 moles
Finally, we calculate ΔE:
ΔE = heat absorbed/moles of octane = (120.51 kJ)/(0.024 mol octane) = 5021.25 kJ/mol octane
A nursing home is installing their own bulk oxygen system due to their large volume of consumption. OSHA regulation 29 CFR 1910.104(b)(2)(iii) requires owners of bulk oxygen systems to provide noncombustible surfacing in areas where liquid oxygen might leak during operation of the system or during the filling of a storage container. If the nursing home provides an asphalt surface in areas where oxygen could potentially leak, will it be in compliance with the workplace regulation regarding oxygen? Explain your answer
Answer:
NO! It would be in violation of the workplace regulation regarding oxygen.
Explanation:
Bulk oxygen systems convey liquified oxygen which is of geat use and importance in institutions like a nuirsing home.
Liquified oxygen is gaseos oxygen that has been condensed under high presures into liquid form. It is transported via a complex system of vaporizers, storage tanks and pipes around the facility it is needed. Liquified oxygen is oxygen- rich.
Asphalt is a petroleum derivative that is often used to in coating surfaces and tarring roads.
Its primry constituent is Carbon with minor constitunets like sulphur, nirogen, oxygen. As a petrolem derivative, it is very combustible.
In the event of an oxygen leak on an asphalt surtface, oxygen acting as an oxidizing agent can combine with asphalt in the presence of air, to cause a large fire.
Hence, asphalt surfacing in areas of oxygen leaks, would not be in compliance with the workplace regulation as it has the potential of causing a fire in the nursing home.
The electron configurations of two unknown elements x and y are shown. X: 1s2 2s2 2p6 Y: 1s2 2s2 2p6 3s2 3p6 Which statement is most likely correct about the two elements? A) They will react because X can give up two electrons B) They will react because X and Y can share two pairs of electrons to become stable C) They will not react because both have a complete outermost shell and are stable D) They will not react because both will give up one electron. to become stable.
Answer:
B) They will react because X and Y can share two pairs of electrons to become stable
Explanation:
The electron configurations of two elements x and y are given :
X: 1s2 2s2 2p6
Y: 1s2 2s2 2p6 3s2 3p6
The statement that is true for both the elements is that, they both will react as they both can share two pairs of electrons to become stable.
To become stable the outermost shell or p orbital should have 8 electrons, so element X can gain 2 atoms to become stable.
Element Y can also react as it can also share two atoms to fulfill its 3p orbital and will stable.
Hence, the correct option is "B".
Choose all of the orbitals that can form a σ bond to the orbital displayed below (side-by-side, in the orientation shown).
Answer:
s orbital
Explanation:
The orbital shown is a py orbital. py orbitals overlap side by side with s orbital to form a sigma bond. Looking at the direction of the Px and py orbitals, overlap of these with a py orbital can only lead to the formation of a pi bond.
However, the s orbital being spherically symmetric overlaps with py orbital in such a manner that a sigma bond is formed. The s orbital overlaps with one of the lobes of the py orbital.
Sigma bonds are formed by end to end overlap of atomic orbitals. It is the strongest type of covalent bond.
HELP ME ASAP PLISSSSS
Answer:
In this titration, solution P (that contains hydrochloric acid) is added into the conical flask that contains sodium hydroxide drop by drop. The indicator (phenolphthalein) changes color when all the NaOH is completely neutralized.
i) Solution P contains hydrochloric acid. Hydrochloric acid is the chemical that reacts with sodium hydroxide to give salt and water.
This type of reaction is called neutralization.
ii) Under alkaline conditions, phenolphthalein appears pink in color. When the solution becomes neutral or acidic, it is colorless.
So, the color change of the mixture at the end point is from pink to colorless.
iii) same explanation from question i,
HCl (aq) + NaOH (aq) --> NaCl (aq) + H2O (l)
iv) no. of moles = volume (in dm3) x concentration
hence,
no. of moles of NaOH used = 25/1000 x 0.1
= 0.0025 mol
From the equation in (iii), since the mole ratio of HCl : NaOH = 1:1, meaning 1 mole of HCl reacts completely with 1 mole of NaOH.
This also means that the no. of moles of NaOH reacted equals to the no. of moles of HCl needed to react with it, which is 0.0025 mol.
Given the concentration of HCl in solution P is 0.1 mol /dm3. (pls correct me if I misunderstood your comment),
if v is the volume of HCl needed,
0.0025 = 0.1 v
v = 0.025 dm3
also = 25 cm3
Answer:
In this titration, solution P (that contains hydrochloric acid) is added into the conical flask that contains sodium hydroxide drop by drop. The indicator (phenolphthalein) changes color when all the NaOH is completely neutralized.
i) Solution P contains hydrochloric acid. Hydrochloric acid is the chemical that reacts with sodium hydroxide to give salt and water.
This type of reaction is called neutralization.
ii) Under alkaline conditions, phenolphthalein appears pink in color. When the solution becomes neutral or acidic, it is colorless.
So, the color change of the mixture at the end point is from pink to colorless.
Explanation:
What is the freezing point of a solution of 1.43 g mgcl2 in 100 g of water? Kf for water is 1.86°c/m for water.
Answer:
Change in T = i x m x kf. Where i is the number of particles the compound dissociates, m is the molality, and kf is the constant specific to water. MM of MgCl2 = 95.21 g/mol
MgCl2 will form three atoms....i = 3......1Mg + 2Cl
kf = 1.86
moles of MgCl2 = 1.43g/95.21 = 0.015
m = moles solute/ kg solvent = 0.015/.1kg = .15m
Change in T = (3)(.15)(1.86) = .838
This is the depression of the freezing point of water, it is negative because the water's new freezing point is its normal freezing point minus the change in T.
0 - .838 = -.838
Explanation:
Ethylene, a gas found in nature, is commonly used to ripen bananas and other fruits. Which compound is ethylene?
H2C — CH2
НО
НО
Н
Н
0
С — С
Н
Н
ОН — СЕ С — Н
Answer:
C2H4
Explanation:
cause the compound of ethylene is C2H4
Ethylene is a hydrocarbon gas with the chemical formula C₂H₄. It is a simple molecule that consists of two carbon atoms and four hydrogen atoms and is also known as ethene. The skeletal structure is CH₂=CH₂.
What is ethylene ?Ethylene is a colorless and odorless gas that is the simplest member of the olefin class of hydrocarbons, with the chemical formula C₂H₄. It is an important organic compound and is widely used in industry.
Ethylene is primarily used to produce polyethylene, which is one of the most common plastic materials in the world. It is also used as a fuel in some industrial processes, as a refrigerant, and as a precursor to other chemicals.
It is an important plant hormone and is involved in various physiological processes such as fruit ripening, senescence, and abscission. Ethylene is naturally produced by plants, but it can also be produced artificially and is commonly used in agriculture to ripen fruits and vegetables.
Thus, the ethylene compound is CH₂=CH₂.
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sodium has 11 protons 12 neutrons. what is the isotope nation
Answer:
these are two atoms which have the same number of protons but different number of neutrons
What do we call matter made you of only one kind of atom?
And Atoms have weight and take up space
Answer:
Matter is any substance, if it is made up of only one kind of atom, then it is an element. Elements consists of atoms with the same weight and same number of protons in the nuclei.
It's urgent! Any kind soul please help me ASAP!
Answer:
a white precipitate of barium chloride is formed as displacement reaction takes place.
Which of the following is a halogen?
O A. Neon (Ne)
B. Iodine (1)
O C. Oxygen (0)
O D. Potassium (K)
Answer:
[tex]\boxed{\mathrm{Iodine}}[/tex]
Explanation:
Halogens are elements in group 17 or 7 in the periodic table.
Iodine is a halogen.
Therefore, iodine, an Halogen
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Plz solve mcqs#04 with full detailed.note
Answer:
The correct option is;
(B) 1 s², 2s², 2p⁶, 3s², 3p³
Explanation:
The electron configuration is the outline of the electron arrangement about a nucleus
In the systemic pattern of electron arrangement within an atom, there are, s, p, d, f orbitals
The maximum number of electrons in an s, p and d orbital = 2, 6, and 10 respectively
Based on Aufbau's principle the electrons are arranged based on the order of their energy level
The charge is presented by the number of electrons in the outermost shell, an element able to form an ion of charge of -3 will gain 3 electrons to complete its outermost shell
Among the options given, option B is the only option that has the capacity to take the electrons to complete the number of electrons in the p orbital outermost shell to 6 from 3, that is 3p³ + 3e⁻→ 3p⁶.
Suppose a 22.092 g sample of a 1:1 mixture of acetylferrocene and ferrocene was separated by column chromatography, and the recovered fractions weighed 9.017 g (acetylferrocene) and 8.075 g (ferrocene), what was the percent recovery of acetylferrocene?
Answer:
81.6%
Explanation:
mass of acetylferrocene and ferrocene mixture = 22.092 g
mass ratio acetylferrocene and ferrocene mixture = 1 : 1
The sum of the ratios = 2, therefore the mass of each compound will be half the mass of the mixture
mass of each compound in the sample mixture = 1/2 * 22.09 2= 11.046 g
mass of recovered acetylferrocene = 9.017 g
percentage recovery = mass recovered/mass in sample * 100%
percentage recovery of acetylferrocene = (9.017 g / 11.046 g) * 100%
percentage recovery of acetylferrocene = 81.6%
The concentration of phenylephrine hydrochloride in a prefilled syringe is 10 mg/mL. What is the percentage concentration (w/v) of phenylephrine in the injection. (Answer must be numeric; no units or commas; round the final answer to the nearest WHOLE number.)
Answer:
The percentage concentration (w/v) of phenylephrine in the injection is 1 %.
Explanation:
The percentage concentration in w/v of the phenylephrine hydrochloride can be calculated as follows:
[tex]\%^{w}/_{v} = \frac{m}{V} \times 100[/tex]
Where:
m: is the mass of the solute in grams
V: is the volume of the solution in milliliters
The concentration of the phenylephrine hydrochloride is 10 mg/mL, so the percentage concentration is:
[tex]\%^{w}/_{v} = \frac{m}{V} \times 100[/tex]
[tex]\%^{w}/_{v} = \frac{10 \cdot 10^{-3} g}{1 mL} \times 100[/tex]
[tex]\%^{w}/_{v} = 1 \%[/tex]
Therefore, the percentage concentration (w/v) of phenylephrine in the injection is 1 %.
I hope it helps you!