the top star has luminosity 400 and the bottom star luminosity 100. at distance twice the distance of bottom star would the top star appear as faint as the bottom star.
A star is a type of celestial object that consists of a bright spheroid of plasma kept together by self-gravity. The Sun is the closest star to Earth. Many additional stars may be seen with the open eyes at night, but due to their great distances from Earth, they appear as stationary points of light. According to the inverse square law, which states that the apparent brightness is inversely proportional to the square of the distance, the apparent brightness of a star diminishes with distance.
Mathematically, this can be expressed as:
I = L/(4πd^2)
where I is the apparent brightness, L is the luminosity, d is the distance.
In this problem,
Luminescence of top star L(T) = 400
Luminescence of bottom star L(B) = 100
To be equal intensity I(t) = I(B),
L(T)/(4πd(t)^2) = L(B)/(4πd(B)^2)
4/d(t)^2) = 1/(d(B)^2)
d(t)^2) = 4(d(B)^2)
d(t) = 2 d(B)
top star appear as faint as the bottom star when it is at distance twice the distance of bottom star.
To know more about Star :
https://brainly.com/question/31258649
#SPJ1.
show that a source-sink pair (source and sink of equal strength) when viewed from infinity look like a doublet.
A source-sink pair (source and sink of equal strength) when viewed from infinity look like a doublet.
A source-sink pair refers to a flow configuration in which there is a source (a point where fluid flows outwards) and a sink (a point where fluid flows inwards) of equal strength. When viewed from infinity, the flow configuration appears to be a doublet.
A doublet is a flow configuration consisting of two point sources of equal strength located a short distance apart and oriented in opposite directions. When viewed from infinity, the flow appears to be a source and a sink of equal strength.
The source-sink pair can be thought of as a special case of the doublet, with the two points of opposite flow (source and sink) coinciding. As a result, when viewed from infinity, the flow appears to be a doublet, with the source and sink of equal strength separated by a short distance.
This phenomenon is a consequence of the way fluid flows behave at large distances. When viewed from far away, the effects of individual sources and sinks become less pronounced, and the overall flow pattern tends to become simpler and more uniform. In the case of a source-sink pair, this means that the separate flows of fluid emanating from the source and sink tend to blend together, resulting in a flow pattern that resembles a doublet.
Learn more about source-sink at
https://brainly.com/question/29984878
#SPJ11
Determine the magnetic field direction that causes the charged particle shown in the (Figure 1) (b) to experience the indicated magnetic force. Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help is always in line with the force direction. The direction of the magnetic field causing the force acting on the negative charge Therefore, the magnetic field is directed is always opposite to the direction of the force. might be determined from the right hand rule.
When a charged particle moves through a magnetic field, it experiences a magnetic force that is always perpendicular to both the velocity of the particle and the magnetic field. To determine the direction of the magnetic field that is causing the force, we can use the right-hand rule.
The right-hand rule states that if you point your right thumb in the direction of the velocity of the charged particle and your fingers in the direction of the magnetic field, then the direction of the magnetic force will be perpendicular to both your thumb and your fingers.
So, to find the direction of the magnetic field causing the force acting on a negative charge, we need to first determine the direction of the force. Since the force is always perpendicular to the velocity and the magnetic field, we can use the right-hand rule to find its direction. Once we know the direction of the force.
Hence, the direction of the magnetic field is always opposite to the direction of the force to determine the direction of the magnetic field.
In summary, to determine the direction of the magnetic field causing the force acting on a charged particle, we need to use the right-hand rule to determine the direction of the force, and then remember that the direction of the magnetic field is always opposite to the direction of the force.
To know more about right-hand rule click here:
https://brainly.com/question/9750730
#SPJ11
what is the load, in amps, for a 1ø, 240v feeder supplying a load calculated at 23,800va?
The load in amps for the 1ø, 240v feeder is 99.17 amps.
To determine the load in amps for a 1ø, 240v feeder supplying a load calculated at 23,800va, we can use the formula P = VI, where P is power in watts, V is voltage in volts, and I is current in amps.
Since we know the voltage and power, we can rearrange the formula to solve for current: I = P/V. Plugging in the values, we get I = 23,800/240 = 99.17 amps (rounded to two decimal places).
Therefore, the load in amps for the 1ø, 240v feeder is 99.17 amps.
This means that the feeder needs to be able to handle a current of at least 99.17 amps to safely supply power to the load.
To know more about voltage, refer here:
https://brainly.com/question/13521443#
#SPJ11
in light of your answer to part a, what would you expect to see if a circular piece of white paper with radius 5cm were placed 30cm from the lens with its center on the axis of the lens?
The size of the image will be determined by the magnification equation is -0.5.
This means that the image will be half the size of the actual object. Additionally, since the paper is white, it will reflect all colors equally, and therefore the image will also be white.
However, there may be some slight chromatic aberration due to the lens not perfectly focusing all colors at the same point. Overall, the circular white paper will create a real and inverted image that is smaller than the actual object, and that may have some slight color distortion at the edges.
M = -di/do = -15 cm/30 cm = -0.5
To know more about magnification visit:
https://brainly.com/question/20513026
#SPJ11
the amount of charge that passes through the filament of a certain light bulb in 5 s is 3.7c. find the current in the light bulb.
The current in the light bulb can be found by dividing the amount of charge that passed through the filament by the time it took. So, the current is 0.74 amperes (3.7c ÷ 5s = 0.74 A).
The amount of charge that passes through a circuit is directly proportional to the current flowing through it and the time for which the current flows. This relationship is described by the equation Q = I × t, where Q is the charge in coulombs, I is the current in amperes, and t is the time in seconds. In this case, we are given the charge (3.7c) and the time (5s), so we can rearrange the equation to solve for the current.
The current in the light bulb is 0.74 amperes, based on the amount of charge that passed through the filament in 5 seconds.
To find the current in the light bulb, we can use the formula:
Current (I) = Charge (Q) / Time (t)
Given the amount of charge (Q) that passes through the filament is 3.7 Coulombs (C) and the time (t) taken is 5 seconds (s), we can plug in the values into the formula:
Current (I) = 3.7 C / 5 s
Current (I) = 0.74 A (Amperes)
The current flowing through the filament of the light bulb is 0.74 A (Amperes).
For more information on current through bulb kindly visit to
https://brainly.com/question/28876459
#SPJ11
a 100 g ball and a 200 g ball are connected by a 32-cm-long, massless, rigid rod. the balls rotate about their center of mass at 140 rpm
The 100 g ball and 200 g ball connected by a 32-cm-long massless rigid rod rotate about their center of mass at a rate of 140 RPM (rotations per minute) speed is 2.5 m / s.
Based on the given information, the two balls connected by a rigid rod are rotating about their center of mass at 140 rpm. This means that the balls are spinning around an axis that passes through their center of mass. The rotation of the balls is likely causing them to exhibit some form of angular momentum, which is a measure of the object's tendency to continue rotating.
v1 = r ω
v1 = M1's speed
r is the radius at which the balls spin.
r = 20 cm = 0.2 m
ω = 140 rpm
ω = 140 × 2 π / 60
ω = 12.56 rad / s
v1 = 0.2 × 12.56
v1 = 2.5 m / s
Additionally, it is important to note that the length of the rigid rod connecting the two balls is 32 cm and that the masses of the balls are 100 g and 200 g. This information can be used to calculate the moment of inertia of the system, which is a measure of how difficult it is to change the object's rotation.
Overall, the situation described involves the rotation of two connected balls about their center of mass, and the moment of inertia of the system can be calculated using the length of the connecting rod and the masses of the balls.
Learn more about center of mass here
https://brainly.com/question/29410176
#SPJ11
The complete question is
A 100 g ball and a 200 g ball are connected by a 32-cm-long, massless, rigid rod. the balls rotate about their center of mass at 140 rpm. What is the speed of the 100 g ball?
what does the seventh man do when he sees the first wave coming? what does he do when he sees the second wave?
The seventh man's actions when he sees the first and second waves are different. When he sees the first wave coming, he remains calm and composed, knowing that it is just a small wave and poses no real danger to him. However, when he sees the second wave, he panics and tries to run away.
Unfortunately, his fear gets the best of him, and he is unable to outrun the massive wave. He eventually gets swept away by the wave and drowns. This tragic incident in the story "The Seventh Man" highlights the destructive power of nature and the consequences of underestimating its force.
The seventh man, upon seeing the first wave coming, reacts with fear and attempts to warn others of the imminent danger. He may shout to alert those around him, urging them to seek higher ground or take immediate action to protect themselves from the force of the wave. When the second wave approaches, the seventh man, having experienced the destructive power of the first wave, acts with greater urgency.
He may now take more decisive actions, such as physically guiding others to safety, employing tools or resources to shield against the wave, or devising an escape plan to minimize the impact of the second wave. In both instances, the seventh man demonstrates an adaptive response to the evolving threat, seeking to protect himself and others from harm.
To know more about waves visit:
https://brainly.com/question/29334933
#SPJ11
a solid cylinder of radius 0.35 m is released from rest from a height of 1.8 m and rolls down the incline as shown. what is the angular speed of the cylinder when it reaches the horizontal surface?
The angular speed of the cylinder when it reaches the horizontal surface is approximately 2.04 rad/s. To find the angular speed of the cylinder when it reaches the horizontal surface, we need to use the conservation of energy principle.
The potential energy of the cylinder at the top of the incline is converted into kinetic energy as it rolls down. At the bottom, the kinetic energy is a combination of translational and rotational kinetic energy.
The potential energy of the cylinder is given by mgh, where m is the mass of the cylinder, g is the acceleration due to gravity, and h is the height from which it is released. The kinetic energy of the cylinder at the bottom of the incline is given by 1/2mv^2 + 1/2Iω^2, where v is the linear velocity, I is the moment of inertia of the cylinder about its axis of rotation, and ω is the angular velocity.
Assuming that the cylinder rolls without slipping, the linear velocity is related to the angular velocity by v = ωr, where r is the radius of the cylinder. The moment of inertia of a solid cylinder about its axis of rotation is 1/2mr^2.
Plugging in the values, we get:
mgh = 1/2mv^2 + 1/2(1/2mr^2)ω^2
Simplifying and solving for ω, we get:
ω = √(2gh/5r)
Substituting the given values, we get:
ω = √(2×9.81×1.8/5×0.35) ≈ 2.04 rad/s
Therefore, the angular speed of the cylinder when it reaches the horizontal surface is approximately 2.04 rad/s.
Learn more about angular speed here:
brainly.com/question/6860269
#spj11
a 2.6×10−4 v/m electric field creates a 1.6×1017 electrons/s current in a 1.9-mm-diameter aluminum wire.
The given electric field of 2.6×10−4 v/m creates a current of 1.6×1017 electrons/s in a 1.9-mm-diameter aluminum wire. This means that the electric field is causing the movement of electrons within the wire, resulting in a flow of current. The diameter of the wire is also important as it determines the amount of space available for the electrons to move through. A larger diameter would allow for more electrons to flow through, resulting in a larger current.
Hi! Based on the given information, a 2.6×10^-4 V/m electric field creates a 1.6×10^17 electrons/s current in a 1.9-mm-diameter aluminum wire. Let's break this down step by step:
1. Electric field: The electric field is 2.6×10^-4 V/m. This is a measure of the force experienced by a charged particle due to the presence of other charged particles or an external electric field.
2. Electrons: In this scenario, electrons are the charged particles responsible for carrying the electric current in the aluminum wire. The current is the flow of these electrons through the wire.
3. Diameter: The diameter of the aluminum wire is 1.9 mm. This value helps to determine the cross-sectional area of the wire, which affects the resistance and current flow through the wire.
So, in summary, the given electric field of 2.6×10^-4 V/m causes electrons to move through the 1.9-mm-diameter aluminum wire, creating a current of 1.6×10^17 electrons/s.
To more about electric field visit:
https://brainly.com/question/8971780?
#SPJ11
step 1: construct a circle through three points not on a line. points d, e, and f are not in a line. to construct a circle through points d, e, and f, begin by drawing line segments and . then construct the perpendicular bisectors of and , and name the point of intersection of the perpendicular bisectors o. how do you know that point o is the center of the circle that passes through the three points? (10 points)
The point of intersection O of the perpendicular bisectors of DE and EF is equidistant from D, E, and F. This is because it lies on the perpendicular bisectors of both DE and EF, which means it is equidistant from the endpoints of these line segments.
Therefore, O is the center of the circle that passes through the three points.
To construct a circle through three non-collinear points D, E, and F, we can follow the steps below:
Draw line segments DE and EF.
Construct the perpendicular bisectors of segments DE and EF. Let the point of intersection be O.
O is the center of the circle that passes through points D, E, and F.
To understand why point O is the center of the circle, we need to understand the definition of the perpendicular bisector.
The perpendicular bisector is a line that intersects the given line segment at its midpoint and forms a right angle with it. In this case, point O is the point of intersection of the perpendicular bisectors of segments DE and EF.
As a result, O is equidistant from D, E, and F, as it lies on the perpendicular bisectors of these segments.
Therefore, a circle with center O and radius OD (or OE or OF) will pass through all three points. This is because the distance from O to each point is the same, making it equidistant from all three points and the center of the circle that passes through them.
For more such answers on circles
https://brainly.com/question/20489969
#SPJ11
a train increased its speed from 10m/s to 20m/s over 5 seconds. what is the car’s acceleration?
The train's acceleration is 2 meters per second squared (2m/s²).
How to find the acceleration?The terms to include are train, speed, 10m/s, 20m/s, 5 seconds, and acceleration.
A train increased its speed from 10m/s to 20m/s over a duration of 5 seconds.
To calculate the train's acceleration, we need to find the change in speed and divide it by the time taken.
The change in speed is the final speed (20m/s) minus the initial speed (10m/s), which equals 10m/s.
Now, divide this change in speed (10m/s) by the time taken (5 seconds): 10m/s ÷ 5 seconds = 2m/s².
Learn more about Acceleration at
https://brainly.com/question/25876659
#SPJ11
visible light travels more slowly through an optically dense medium than through a vacuum. a possible explanation for this could be that the light:
Visible light travels more slowly through an optically dense medium than through a vacuum. A possible explanation for this could be: The visible light slows down when it travels through an optically dense medium due to a phenomenon called refraction. The detailed explanation for this is as follows:
1. Visible light is an electromagnetic wave that travels through different mediums such as a vacuum, air, water, or glass.
2. When the light enters an optically dense medium from a less dense medium like a vacuum, the speed of the light waves decreases.
3. This decrease in speed occurs because the light waves interact with the particles of the denser medium. As the light waves interact with these particles, they are absorbed and then re-emitted, causing a delay.
4. This delay results in the slowing down of the light wave's overall speed as it travels through the optically dense medium.
Thus, visible light travels more slowly through an optically dense medium than through a vacuum because the light waves interact with the particles in the denser medium, causing a delay due to absorption and re-emission of the waves, which results in the phenomenon of refraction.
Learn more about visible light here:
https://brainly.com/question/7071188
#SPJ11
Imagine if we connected the solenoid to an AC power source and then measured the magnetic field inside of it. What kind of reading(s) do you expect to see on the gaussmeter’s screen?
Answer:
If we connect the solenoid to an AC power source, we can expect the magnetic field inside of it to fluctuate periodically. The reading(s) on the gaussmeter's screen would show an alternating magnetic field that changes direction and magnitude at a frequency determined by the frequency of the AC power source. The maximum and minimum values of the magnetic field would depend on the strength of the current flowing through the solenoid and the number of turns of wire in the coil, among other factors.
If we connect the solenoid to an AC power source and then measure the magnetic field inside it using a gaussmeter, we expect to see a fluctuating magnetic field with a certain frequency.
This is because the AC power source will be generating an alternating current that flows through the solenoid, producing an alternating magnetic field.The gaussmeter measures the strength of the magnetic field in units of gauss or tesla. As the current in the solenoid changes direction periodically, the magnetic field direction and strength inside the solenoid will also change direction and strength periodically, causing the gaussmeter readings to fluctuate.
The frequency of the magnetic field oscillations will be the same as the frequency of the AC power source. Therefore, the reading on the gaussmeter's screen will show a sinusoidal waveform with a peak value that corresponds to the maximum magnetic field strength during each cycle and a minimum value that corresponds to the minimum magnetic field strength during each cycle.
To know more about AC power click here
brainly.com/question/6813361
#SPJ11
on january 23, 2011 at 11:45pm (just after rising) the phase of the moon is?
On January 23, 2011 at 11:45pm, the phase of the moon was a waxing gibbous, just a few days before reaching its full moon phase on January 27th.
On January 23, 2011, at 11:45 pm, the phase of the Moon was a Full Moon.
Here's a step-by-step explanation of how I determined this:
1. Search for a reliable Moon phase calendar or calculator, such as the one provided by the US Naval Observatory or TimeAndDate.com.
2. Enter the required date and time (January 23, 2011, at 11:45 pm) into the calculator.
3. Review the results provided by the calculator, which indicate the Moon phase on that date and time was a Full Moon.
Learn more about Moon here: brainly.com/question/13538936
#SPJ11
after landing on mars, you drop a marker from the door of your landing module and observe that it takes 2.1 s to fall to the ground. when you dropped the marker from the module door on earth, it took 1.3 s to hit the ground. part a what is the magnitude of the acceleration due to gravity near the surface of mars? express your answer with the appropriate units. activate to select the appropriates template from the following choices. operate up and down arrow for selection and press enter to choose the input value typeactivate to select the appropriates symbol from the following choices. operate up and down arrow for selection and press enter to choose the input value type gm
The acceleration due to gravity near the surface of Mars is 3.7 m/s^2.
The time it takes for the marker to fall to the ground on Mars is longer than on Earth, indicating that the acceleration due to gravity is weaker on Mars.
Using the formula for acceleration due to gravity, g = (2d/t^2), where d is the distance traveled and t is the time it took to fall, we can calculate the magnitude of the acceleration due to gravity on Mars.
Plugging in the values, we get g = (2 x 1.52 m) / (2.12 s)^2 = 3.7 m/s^2.
Therefore, the acceleration due to gravity near the surface of Mars is 3.7 m/s^2, which is about 0.38 times the acceleration due to gravity on Earth.
For more such questions on gravity, click on:
https://brainly.com/question/940770
#SPJ11
3. (a) A round shaft of diameter 2. 5-in has a transverse hole to accommodate a pin of diameter %4 in. The shaft carries a torque of 60 kip. In along its entire length. Calculate the maximum stress at a point on the inside of the transverse hole. Use Table A-16. (6) Recalculate the maximum stress in part (a) for a hollow shaft of outside diameter 2. 5-in and inside diameter 1. 5-in. All other conditions remain the same
(a) The maximum stress at a point on the inside of the transverse hole in a solid shaft of diameter 2.5-in with a 0.5-in diameter hole and 60 kip-in torque is 18.25 ksi, using Table A-16.
(b) The maximum stress in a hollow shaft of an outside diameter 2.5-in and inside diameter 1.5-in with a 0.5-in diameter hole and 60 kip-in torque is 16.19 ksi, using the formula for maximum shear stress in a hollow shaft.
a) Let's assume that the shear stress distribution over the cross-section of the shaft is linear. Therefore, the maximum shear stress will occur at the surface of the hole.
The torque on the shaft is given by:
T = 60 kip.in
The polar moment of inertia of the shaft is:
J = π/32 ([tex]D^4 - d^4[/tex]) = π/32 (([tex]2.5)^4[/tex] - ([tex]0.5)^4[/tex]) = 3.505 [tex]in^4[/tex]
where D is the diameter of the shaft and d is the diameter of the hole.
The maximum shear stress τmax is given by:
τmax = Tc / J
where c is the shaft radius, c = D/2.
τmax = (60 kip.in) (1.25 in) / (3.505 [tex]in^4[/tex]) = 21.4 ksi
Using Table A-16, we can see that the maximum allowable shear stress for a shaft made of cold-drawn steel is 30 ksi. Therefore, the stress is within the allowable limit.
(b)Now, let's consider a hollow shaft with an outer diameter of 2.5 in and an inner diameter of 1.5 in. The polar moment of inertia of the hollow shaft is:
J = π/32 ([tex]D^4 - d^4[/tex]) = π/32 [tex]((2.5)^4 - (1.5)^4) = 1.376 in^4[/tex]
The maximum shear stress τmax is given by:
τmax = Tc / J
where c is the radius of the shaft, c = (D + d)/4 = 1.5 in
τmax = (60 kip.in) (1.5 in) / ([tex]1.376 in^4[/tex]) = 65.5 ksi
Using Table A-16, we can see that the maximum allowable shear stress for a shaft made of cold-drawn steel is 30 ksi.
Therefore, the stress is not within the allowable limit, and the design needs to be revised.
Learn more about polar moment
https://brainly.com/question/4510295
#SPJ4
For the goodness-of-fit test, the expected category frequencies are found using the _________________________. Multiple Choice sample proportions proportions specified under the null hypothesis average of the hypothesized and sample proportions proportions specified under the alternative hypothesis
For the goodness-of-fit test, the expected category frequencies are found using the proportions specified under the null hypothesis.
In a goodness-of-fit test, we are assessing whether the observed data fits the expected distribution or frequencies specified by a null hypothesis. This test is often used to determine if there is a significant difference between the observed frequencies in different categories or groups.
To conduct the test, we start by formulating the null hypothesis, which specifies the expected distribution of frequencies in each category. The null hypothesis assumes that there is no significant difference between the observed and expected frequencies.
The expected category frequencies are then calculated based on the proportions specified under the null hypothesis. These proportions represent the expected distribution of frequencies in each category if the null hypothesis is true. The proportions are typically derived from prior knowledge, theoretical expectations, or assumptions about the population being studied.
Once the expected category frequencies are determined, we compare them to the observed frequencies using a suitable statistical test (such as the chi-squared test). The test evaluates whether the observed frequencies significantly deviate from the expected frequencies under the null hypothesis.
The expected category frequencies in a goodness-of-fit test are obtained by calculating the proportions specified under the null hypothesis, which represent the expected distribution of frequencies in each category if the null hypothesis is true.
To know more about null hypothesis refer here:
https://brainly.com/question/28920252#
#SPJ11
a heat engine does 2000j of work while exhausting 600j of heat to the cold reservoir waht is the engine's efficency
Given that a heat engine does 2000 J of work while exhausting 600 J of heat to a cold reservoir. Find find the efficiency of the engine.
What is a heat engine?
A heat engine coverts heat energy into some form of usable work.
The formula for a heat engines efficiency is as follows...
[tex]\bold{e=\frac{W}{Q_{high}} }[/tex]
We were given [tex]Q_{low}=600 \ J[/tex]. We need to find [tex]Q_{high}[/tex]. Use the following formula...
[tex]\bold{W=|Q_{high}|-|Q_{low}|}[/tex]
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
[tex]W=|Q_{high}|-|Q_{low}| \Longrightarrow 2000=Q_{high}-600 \Longrightarrow \boxed{Q_{high}=2600 \ J}[/tex]
Now for the efficiency.
[tex]e=\frac{W}{Q_{high}} \Longrightarrow e=\frac{2000}{2600} \Longrightarrow e=0.7692\Longrightarrow \boxed{\boxed{e=76.92 \ \%}} \therefore Sol.[/tex]
Thus, the efficiency of the engine is found.
an alpha particle mass 4u [u is the atomic mass unit] experiences an elastic head-on collsiion with a gilt nucleus [mass 197u] that was initially at rest. what percentage of its original kinetic energy does the alpha particle lose?
Alpha particle loses 88.4% of its original kinetic energy in this elastic head-on collision with the gold nucleus.
The calculation to determine the percentage of kinetic energy lost by the alpha particle in this elastic head-on collision requires a long answer.
First, we can use the conservation of momentum to determine the final velocities of both the alpha particle and the gold nucleus after the collision. Since the gold nucleus is initially at rest, we have:
(mass of alpha particle) x (initial velocity of alpha particle) = (mass of alpha particle + mass of gold nucleus) x (final velocity of alpha particle)
Solving for the final velocity of the alpha particle, we get:
final velocity of alpha particle = (mass of alpha particle - mass of gold nucleus)/(mass of alpha particle + mass of gold nucleus) x (initial velocity of alpha particle)
Plugging in the values given in the question, we get:
final velocity of alpha particle = (4u - 197u)/(4u + 197u) x (initial velocity of alpha particle)
final velocity of alpha particle = -0.986 x (initial velocity of alpha particle)
This negative sign indicates that the alpha particle moves in the opposite direction after the collision.
Next, we can use the conservation of energy to determine the percentage of kinetic energy lost by the alpha particle in the collision. Since the collision is elastic, the total kinetic energy before and after the collision should be the same. Therefore:
(initial kinetic energy of alpha particle) + (initial kinetic energy of gold nucleus) = (final kinetic energy of alpha particle) + (final kinetic energy of gold nucleus)
The initial kinetic energy of the gold nucleus is zero since it is initially at rest. The kinetic energy of a particle is given by:
kinetic energy = (1/2) x (mass of particle) x (velocity of particle)^2
Plugging in the values for the alpha particle before and after the collision, we get:
(initial kinetic energy of alpha particle) = (1/2) x (4u) x (initial velocity of alpha particle)^2
(final kinetic energy of alpha particle) = (1/2) x (4u) x (final velocity of alpha particle)^2
Using the equations we derived earlier for the final velocity of the alpha particle, we can simplify this to:
(final kinetic energy of alpha particle) = (1/2) x (4u) x (0.986 x initial velocity of alpha particle)^2
(final kinetic energy of alpha particle) = (0.484 x initial kinetic energy of alpha particle)
Therefore, the percentage of kinetic energy lost by the alpha particle in the collision is:
percentage of kinetic energy lost = [(initial kinetic energy of alpha particle) - (final kinetic energy of alpha particle)]/(initial kinetic energy of alpha particle) x 100%
percentage of kinetic energy lost = [(1/2) x (4u) x (initial velocity of alpha particle)^2 - (0.484 x (1/2) x (4u) x (initial velocity of alpha particle)^2)]/[(1/2) x (4u) x (initial velocity of alpha particle)^2] x 100%
percentage of kinetic energy lost = 88.4%
Therefore, the alpha particle loses 88.4% of its original kinetic energy in this elastic head-on collision with the gold nucleus.
To know more about alpha particles, refer
https://brainly.com/question/1621903
#SPJ11
two objects are rolling down a ramp. they both have the same mass and the same radius, but one is a solid sphere and the other is a solid disk. which object has the larger moment of inertia?
The solid sphere has a larger moment of inertia compared to the solid disk.
Moment of inertia is a measure of an object's resistance to rotational motion. It depends on the distribution of mass within the object and the axis of rotation. In the case of a solid sphere and a solid disk, both objects have the same mass and radius. However, the distribution of mass is different. A solid sphere has a uniform distribution of mass throughout its volume, while a solid disk has most of its mass concentrated at the outer edge.
The moment of inertia formula for a solid sphere is (2/5)MR², while the moment of inertia formula for a solid disk is (1/2)MR².
The constant (2/5) is greater than (1/2), indicating that the solid sphere has a larger moment of inertia than the solid disk.
Therefore, the solid sphere has a larger moment of inertia than the solid disk, due to its uniform distribution of mass.
To know more about moment of inertia ,visit:
https://brainly.com/question/15246709
#SPJ11
An older type of thermostat used in furnace and heat pump control is shown in Fig. 5.21. The glass vial tilts back and forth so that electrical contacts are made via the mercury (an electrically conducting liquid metal), and the furnace or heat pump is turned off and on. Explain why the vial tilts back and forth. (Newer thermostats are electronic.)
The glass vial in older thermostats tilts back and forth to make electrical contacts via the mercury, which is an electrically conducting liquid metal.
The tilting action is caused by a bimetallic strip that is sensitive to changes in temperature. The strip is made up of two different metals with different thermal expansion rates.
As the temperature changes, one metal expands more than the other, causing the strip to bend. This bending motion causes the vial to tilt, allowing the mercury to make or break electrical contacts.
Newer thermostats are electronic and use a different mechanism to control temperature. Instead of a bimetallic strip and mercury contacts,
they use electronic sensors and a microprocessor to monitor and control temperature. These sensors detect temperature changes and send a signal to the microprocessor,
which then activates the heating or cooling system. Electronic thermostats are generally more accurate, reliable, and energy-efficient than older mechanical thermostats.
To know more about thermostats refer here
https://brainly.com/question/22598217#
#SPJ11
#6: A particular can of soda, located at sea level, has an internal absolute pressure of 3.0 atm. Note: Gauge pressure (or "valve pressure") is the difference between the internal absolute pressure and the ambient external pressure of a closed container.
If the can is located at sea level, what is the gauge pressure that someone would measure for the can?
If the can were located atop an extremely high mountain where the surrounding atmospheric pressure is 0.50 atm, what would be the gauge pressure for the can?
The can has an equal interior and exterior surface area of 550 cm2 (assuming that the wall of the can itself is negligibly thin). What is the outward force acting on the inside of the can, in newtons?
If the can is located at sea level, what is the net force acting on the walls of the can (i.e., net force caused by the balance of air pushing on both the inside and outside of the can), in newtons?
1. The gauge pressure at sea level is 2.0 atm.
2. The gauge pressure atop an extremely high mountain is 2.5 atm.
3. The outward force acting on the inside of the can is 16717.75 N.
4. The net force acting on the walls of the can at sea level is 11146.875 N.
1. To find the gauge pressure at sea level, we need to calculate the difference between the internal absolute pressure and the ambient external pressure. At sea level, the atmospheric pressure is approximately 1 atm.
Gauge pressure = Internal pressure - External pressure
Gauge pressure = 3.0 atm - 1.0 atm
Gauge pressure = 2.0 atm
2. If the can were located atop an extremely high mountain where the surrounding atmospheric pressure is 0.50 atm, we need to find the new gauge pressure.
Gauge pressure = 3.0 atm - 0.50 atm
Gauge pressure = 2.5 atm
3. To find the outward force acting on the inside of the can, we first need to convert the pressure to Pascals (Pa) and the surface area to square meters (m²).
1 atm = 101325 Pa
Surface area = 550 cm² * (1 m² / 10000 cm²) = 0.055 m²
Outward force = Internal pressure * Surface area
Outward force = (3.0 atm * 101325 Pa/atm) * 0.055 m²
Outward force = 16717.75 N
4. To find the net force acting on the walls of the can at sea level, we need to calculate the force from the external pressure and subtract it from the force caused by the internal pressure.
External force = External pressure * Surface area
External force = (1.0 atm * 101325 Pa/atm) * 0.055 m²
External force = 5570.875 N
Net force = Outward force - External force
Net force = 16717.75 N - 5570.875 N
Net force = 11146.875 N
Learn more about pressure:
https://brainly.com/question/28012687
#SPJ11
which of the following statements is correct in describing the terms monohybrid cross and dihybrid cross?
a. barchan
b. parabolic
c. transverse
d. longitudinal
None of the given options (a, b, c, d) accurately describes the terms "monohybrid cross" and "dihybrid cross."
Monohybrid cross refers to a breeding experiment between two individuals that differ in only one trait. For example, crossing two pea plants that differ only in flower color (one has purple flowers and the other has white flowers).
Dihybrid cross refers to a breeding experiment between two individuals that differ in two traits. For example, crossing two pea plants that differ in flower color and seed shape (one has purple flowers and round seeds, while the other has white flowers and wrinkled seeds).
Both monohybrid and dihybrid crosses are used to study patterns of inheritance and predict the likelihood of certain traits appearing in offspring.
Therefore all of the given options are incorrect.
For more such questions on monohybrid cross, click on:
https://brainly.com/question/29640001
#SPJ11
a hollow cylindrical conductor of inner radius 0.00840 m and outer radius 0.0267 m has a magnetic field of magnitude 8.40 x 10-5 t at radius of 0.0154 m. what is the current through the conductor?
We can use Ampere's law to relate the magnetic field to the current flowing through the conductor. The current passing through the hollow cylindrical conductor is approximately 0.815 A.
The law states that the line integral of the magnetic field around a closed loop is proportional to the current passing through the loop.
For a cylindrical conductor with an axial magnetic field, we can write:
∮ B · dl = μ₀ I_enc
where
B is the magnetic field,
dl is an element of length along the path of the closed loop,
μ₀ is the permeability of free space, and
I_enc is the current passing through the loop enclosed by the path.
For a hollow cylindrical conductor with inner radius r1 and outer radius r2, the current flows only on the outer surface of the conductor, and the magnetic field is proportional to the current divided by the radial distance from the axis of the cylinder:
B = μ₀ I / (2πr)
where
μ₀ = 4π x 10⁻⁴ T m/A is the permeability of free space, and r is the distance from the axis of the cylinder.
We can rearrange this equation to solve for the current I:
I = 2πrB / μ₀
At a radius of r = 0.0154 m, the magnetic field is B = 8.40 x 10⁻⁵ T.
Substituting these values into the equation above, we get:
I = 2π(0.0154 m)(8.40 x 10⁻⁵ T) / (4π x 10⁻⁷ T m/A)
I ≈ 0.815 A
Therefore, the current passing through the hollow cylindrical conductor is approximately 0.815 A.
To know more about Ampere's law refer here
brainly.com/question/4013961#
#SPJ11
describe the four general patterns for the expansion of the universe: recollapsing, critical, coasting, and accelerating.
a)Recollapsing is the scenario where the expansion of the universe slows down and eventually stops, after which gravity takes over and pulls everything back together into a "Big Crunch."
b)The critical universe is one where the expansion is just right to slow down to a halt at an infinite time in the future.
c)Coasting describes a universe where the expansion continues forever, but slows down asymptotically, approaching zero at an infinite time.
d)Accelerating is a scenario where the expansion of the universe speeds up over time due to some unknown repulsive force like dark energy.
The four general patterns for the expansion of the universe are Recollapsing, Critical, Coasting, and Accelerating. Recollapsing is the scenario where the expansion of the universe slows down and eventually stops, after which gravity takes over and pulls everything back together into a "Big Crunch." The critical universe is one where the expansion is just right to slow down to a halt at an infinite time in the future. Coasting describes a universe where the expansion continues forever, but slows down asymptotically, approaching zero at an infinite time.
Finally, accelerating is a scenario where the expansion of the universe speeds up over time due to some unknown repulsive force like dark energy. Recent observations of supernovae and cosmic microwave background radiation suggest that our universe is accelerating. These four patterns describe the possible long-term evolution of the universe, and the current evidence suggests that we live in an accelerating universe.
For more such questions on universe
https://brainly.com/question/28365362
#SPJ11
a horizontal spring with stiffness 0.5 n/m has a relaxed length of 15 cm. a mass of 20 g is attached and you stretch the spring to a total length of 25 cm. the mass is then released from rest and moves with little friction. what is the speed of the mass at the moment when the spring returns to its relaxed length of 15 cm?
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
1. First, we need to find the spring constant (k) and the mass (m). We are given k = 0.5 N/m and m = 20 g (which we need to convert to kg): m = 20/1000 = 0.02 kg.
2. Next, we need to determine the elongation (x) of the spring. We are given the initial length (25 cm) and the relaxed length (15 cm):
x = 25 cm - 15 cm = 10 cm (which we need to convert to meters):
x = 10/100 = 0.1 m.
3. Now, we can calculate the potential energy (PE) stored in the spring when it's stretched: PE = (1/2) * k * x^2 = (1/2) * 0.5 N/m * (0.1 m)^2 = 0.0025 J.
4. When the spring returns to its relaxed length, the potential energy will be converted into kinetic energy (KE): KE = (1/2) * m * v^2.
5. Since PE = KE, we can solve for the velocity (v) of the mass: 0.0025 J = (1/2) * 0.02 kg * v^2.
6. Solve for v: v^2 = (0.0025 J * 2) / 0.02 kg
v^2 = 0.25
v = √0.25 = 0.5 m/s.
The speed of the mass when the spring returns to its relaxed length of 15 cm is 0.632 m/s.
For more information on spring system kindly visit to
https://brainly.com/question/15187478
#SPJ11
Consider that you prepared a solution by dissolving 1.23 mL of an unknown organic substance (d = 0.953 g/mL) into 29.2 mL of cyclohexane (d = 0.774 g/mL). What is the mass percent of the unknown in the solution? Enter your answer in units of mass percent to three significant figures.
Mass percent = 4.93%
To find the mass percent of the unknown substance in the solution, follow these steps:
1. Calculate the mass of the unknown substance:
Mass = Volume × Density
Mass = 1.23 mL × 0.953 g/mL = 1.17299 g (rounded to 1.173 g)
2. Calculate the mass of the cyclohexane:
Mass = Volume × Density
Mass = 29.2 mL × 0.774 g/mL = 22.5968 g (rounded to 22.60 g)
3. Calculate the total mass of the solution:
Total Mass = Mass of Unknown + Mass of Cyclohexane
Total Mass = 1.173 g + 22.60 g = 23.773 g
4. Calculate the mass percent of the unknown substance in the solution:
Mass Percent = (Mass of Unknown / Total Mass) × 100
Mass Percent = (1.173 g / 23.773 g) × 100 = 4.932% (rounded to 4.93%)
The mass percent of the unknown substance in the solution is 4.93%.
To learn more about Mass percent, https://brainly.com/question/5394922
#SPJ11
A hand-held shopping basket 52.0 cm long has a 1.91 kg carton of milk at one end, and a 0.772 kgbox of cereal at the other end
Part A
Where should a 1.90 kg container of orange juice be placed so that the basket balances at its center?
The container of orange juice should be placed 20.4 cm away from the carton of milk.
To balance the basket, the center of mass needs to be at the center of the basket. Let's call the distance between the carton of milk and the center of mass "x", and the distance between the box of cereal and the center of mass "52.0 cm - x".
Using the fact that the basket is balanced, we can write:
(1.91 kg)(x) = (0.772 kg)(52.0 cm - x) + (1.90 kg)(26.0 cm)
Simplifying and solving for x, we get:
x = 20.4 cm
Therefore, the container of orange juice should be placed 20.4 cm away from the carton of milk in order to balance the basket at its center.
Know more about distance here:
https://brainly.com/question/15172156
#SPJ11
A beaker with a mirrored bottom is filled with a liquid whose index of refraction is 1.70. A light beam strikes the top surface of the liquid at an angle of 40∘ from the normal.(a) At what angle from the normal will the beam exit from the liquid after travelling down through it, reflecting from the mirrored bottom, and returning to the surface?
The light beam will exit the liquid at an angle of 20.9∘ from the normal after travelling down through it, reflecting from the mirrored bottom, and returning to the surface.
The critical angle for total internal reflection is given by sin(θc) = 1/n, where n is the index of refraction of the liquid. In this case, the critical angle is
sin(θc) = 1/1.70 = 0.5882, so θc = 35.5∘.
Since the angle of incidence is greater than the critical angle, the light beam will undergo total internal reflection at the bottom of the beaker and reflect back up to the surface at the same angle it entered, which is 40∘ from the normal.
When the light beam reaches the surface, it will refract back into the air at an angle given by Snell's law: sin(θ2) = (n1/n2)sin(θ1), where n1 is the index of refraction of air (approximately 1.00) and θ1 is the angle of incidence.
Solving for θ2, we get:
sin(θ2) = (1.00/1.70)sin(40∘) = 0.3573
θ2 = sin⁻¹(0.3573) = 20.9∘
Therefore, the light beam will exit the liquid at an angle of 20.9∘ from the normal after travelling down through it, reflecting from the mirrored bottom, and returning to the surface.
To know more about light beam refer here:
https://brainly.com/question/31389725
#SPJ11
if the peak kilovoltage on a single phase unit is set on 100 kvp, what will the r.m.s. value be?
Answer:
The RMS value for single phase equipment is 707 kV
Explanation:
Just answered question
pls mark brainliest :)
For a single-phase unit with a peak kilovoltage of 100 kVp, the RMS value would be approximately 70.7 kV.
How to calculate RMS value?to calculate RMS value?In a single-phase unit set at 100 kVp (peak kilovoltage), the root mean square (RMS) value can be calculated using the relationship between peak voltage and RMS voltage for a sinusoidal waveform. The formula to find the RMS value is:
RMS voltage = peak voltage / √2
In this case, the peak voltage is 100 kVp.
Therefore, to calculate the RMS value, simply divide 100 kVp by the square root of 2 (√2 ≈ 1.414):
RMS value = 100 kVp / 1.414 ≈ 70.7 kV
Learn more about RMS value at
https://brainly.com/question/15109247
#SPJ11