(1-j9)x+(2+j10)y=4+j3

(2-j2)x+(7-j6)y=-5+j17

What is the magnitude of x?

The drops per minute for the vancomycin infusion is 75 drops per minute (rounded to the nearest whole number).

To solve for drops per minute, we need to know the total volume of the infusion, the time it will take to infuse, and the drop factor of the tubing.

Total volume of infusion = 250 ml

Time to infuse = 2 hours = 120 minutes

Drip factor = 60 gtt/ml

To calculate the drops per minute, we can use the formula:

(drops/min) = (total volume in ml ÷ time in minutes) x drip factor

Substituting the values we have:

(drops/min) = (250 ÷ 120) x 60

(drops/min) = 1.25 x 60

(drops/min) = 75

This is the rate at which the infusion should be administered using the selected tubing to deliver 1 g of vancomycin over 2 hours every 12 hours. It is important to ensure that the drops per minute are monitored throughout the infusion to ensure that the rate is appropriate and to avoid potential complications.

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Answer:

27 cubic inches

Since each of the 6 faces of a cube have the same size, we know that each edge of the cube is √9 = 3 inches. Therefore the volume of the cube is 3 in x 3 in x 3 in = 27 cubic inches.on:

There are 439 integers between 1 and 1000 that are divisible by at least one of 5, 6, or 7.

To solve this problem, we need to use the principle of inclusion-exclusion. We first find the number of integers divisible by 5, 6, or 7 individually, and then subtract the number of integers divisible by the pairwise combinations of these numbers, and finally add back the number of integers divisible by all three of them.

The number of integers divisible by 5 between 1 and 1000 is 200 (5, 10, 15, ..., 995, 1000). The number of integers divisible by 6 between 1 and 1000 is 166 (6, 12, 18, ..., 996). The number of integers divisible by 7 between 1 and 1000 is 143 (7, 14, 21, ..., 994).

To find the number of integers divisible by the pairwise combinations, we need to find the least common multiple (LCM) of each pair. The LCM of 5 and 6 is 30, and there are 33 integers between 1 and 1000 that are divisible by 30. The LCM of 5 and 7 is 35, and there are 28 integers between 1 and 1000 that are divisible by 35. The LCM of 6 and 7 is 42, and there are 23 integers between 1 and 1000 that are divisible by 42.

To find the number of integers divisible by all three, we need to find the LCM of 5, 6, and 7, which is 210. There are 14 integers between 1 and 1000 that are divisible by 210.

Using the principle of inclusion-exclusion, the total number of integers between 1 and 1000 that are divisible by at least one of 5, 6, or 7 is:

200 + 166 + 143 - 33 - 28 - 23 + 14 = 439

Therefore, there are 439 integers between 1 and 1000 that are divisible by at least one of 5, 6, or 7.

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The range of children in these households is from 0 to 8, as those are the minimum and maximum values in the data set. The range indicates the spread of the data, and in this case, it shows that there is a wide range of children in Anmol's neighborhood, from households with no children to households with 8 children.

To find the range of children in Anmol's neighborhood, we need to identify the highest and lowest numbers in the data set and then subtract the lowest from the highest. Here's the step-by-step explanation:

1. Organize the data set: 0, 0, 2, 1, 2, 8, 3, 0, 0, 0, 2, 1, 2, 8, 3, 0, 0
2. Identify the highest number of children in a household: 8
3. Identify the lowest number of children in a household: 0
4. Subtract the lowest number from the highest number: 8 - 0

The range of children in the households in Anmol's neighborhood is 8.

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The p-value of the test for the hypothesis that mothers with low socioeconomic status deliver babies with different birth weights is 0.0505.

Based on the information you provided, the first step is to state the null and alternative hypotheses.

The null hypothesis is that the mean birth weight of babies born to low SES mothers is the same as the population mean, while the alternative hypothesis is that there is a significant difference.

Assuming that all the conditions are met, we can use a t-test since the sample size is less than 30 and the population standard deviation is not known.

Using a t-distribution table with 99 degrees of freedom (n-1), we can find that the t-score for a one-tailed test with a significance level of 0.05 is approximately 1.660.

Calculating the t-score for the given sample, we get:

t = (115 - μ) / (s / √n)

Where μ is the population mean, s is the sample standard deviation, and n is the sample size.

Since the null hypothesis assumes that μ = 115, we can substitute the values and get:

t = (115 - 115) / (s / √100) = 0

Therefore, the t-score is 0.

Next, we calculate the p-value using the t-distribution table and the one-tailed test. Since the t-score is 0, the area to the right of the t-score is 0.5. Therefore, the p-value is:

p-value = 0.5 - 0.4495 = 0.0505

Rounding to four decimal places, the p-value is 0.0505.

So, the p-value of their test is 0.0505.

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The population in the long run is a. infinity.

To find the population in the long run, we need to analyze the function P(t) = 2001 - 501 + 30t, where t represents years after the industry moved to town.

Given the options, we can check for the long run by calculating the limit as t approaches infinity.

Step 1: Simplify the function.
P(t) = 1500 + 30t

Step 2: Calculate the limit as t approaches infinity.
lim (t→∞) (1500 + 30t)

As t approaches infinity, the term 30t will also approach infinity. Therefore, the population in the long run will approach infinity.

Hence, the population in the long run is a. infinity.

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To answer these questions, we can use the Empirical Rule, also known as the 68-95-99.7 rule, which applies to normally distributed data.

According to the Empirical Rule:

1. Approximately 68% of the data falls within one standard deviation of the mean.

2. Approximately 95% of the data falls within two standard deviations of the mean.

3. Approximately 99.7% of the data falls within three standard deviations of the mean.

Given that the average speed is 48 mph and the standard deviation is 12 mph, we can use this information to estimate the percentage of vehicle speeds within certain ranges.

1. The range between 36 and 60 mph corresponds to one standard deviation below the mean (36 mph) to one standard deviation above the mean (60 mph). Since one standard deviation covers approximately 68% of the data, we can estimate that approximately 68% of the vehicle speeds were between 36 and 60 mph.

2. To estimate the percentage of vehicle speeds that exceeded 60 mph, we can consider

the range beyond one standard deviation above the mean (60 mph). Since the Empirical Rule states that approximately 68% of the data falls within one standard deviation of the mean, this means that approximately (100% - 68%) = 32% of the data lies beyond one standard deviation above the mean.

However, to calculate the percentage exceeding 60 mph, we need to consider speeds above two standard deviations from the mean since the range of interest is above 60 mph. Therefore, we estimate that approximately (32% / 2) = 16% of the vehicle speeds exceeded 60 mph.

So, the answers are:

1. Approximately 68% of the vehicle speeds were between 36 and 60 mph.

2. Approximately 16% of the vehicle speeds exceeded 60 mph.

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If repetitions are allowed, the largest possible result for the standard deviation would occur when we choose the same number four times. In other words, if we choose 4 four times, the standard deviation would be 0 because all of the numbers are the same and there is no deviation from the mean.

However, if we want to choose four different numbers, the largest possible standard deviation would occur if we choose one number twice and two other numbers once each. For example, if we choose 1, 2, 2, and 3, the standard deviation would be approximately 0.829. This is because the formula for standard deviation takes into account the differences between each number and the mean of all the numbers chosen.

In general, the larger the range of numbers to choose from, the larger the possible standard deviation. This is because there are more potential combinations of numbers that could have a high deviation from the mean. Additionally, allowing repetitions also increases the potential for deviation since the same number can be chosen multiple times.

Overall, the largest possible standard deviation when choosing four numbers from 1 to 5 with repetitions allowed would be 0 if we choose the same number four times, or approximately 0.829 if we choose two numbers twice and two other numbers once each.

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the equations for the osculating, normal, and rectifying planes at t = -π/3 are: Osculating plane: -x + √3y + 2√3 = 0, Normal plane: √3x - y - 2√3 = 0 and Rectifying plane: x + √3y - 2 = 0

To find r(-π/3), we substitute t = -π/3 into the given vector equation:

r(-π/3) = (cos(-π/3))i + (sin(-π/3))j - k

= (1/2)(i - √3j) - k

= (1/2)i - (√3/2)j - k

To find r'(t), we take the derivative of r(t) with respect to t:

r'(t) = (-sin t)i + (cos t)j + 0k

= (-sin t)i + (cos t)j

To find r''(t), we take the derivative of r'(t) with respect to t:

r''(t) = (-cos t)i - (sin t)j + 0k

= (-cos t)i - (sin t)j

We can now find the unit tangent vector T(t) by dividing r'(t) by its magnitude:

| r'(t) | = √(sin^2 t + cos^2 t) = 1

T(t) = r'(t)/| r'(t) |

= (-sin t)i + (cos t)j

To find the unit normal vector N(t), we divide r''(t) by its magnitude:

| r''(t) | = √(cos^2 t + sin^2 t) = 1

N(t) = r''(t)/| r''(t) |

= (-cos t)i - (sin t)j

Finally, we can find the binormal vector B(t) by taking the cross product of T(t) and N(t):

B(t) = T(t) × N(t)

= (-sin t)i + (cos t)j × (-cos t)i - (sin t)j

= -cos t k

At t = -π/3, we have:

r(-π/3) = (1/2)i - (√3/2)j - k

T(-π/3) = (1/2)i + (√3/2)j

N(-π/3) = (-√3/2)i + (1/2)j

B(-π/3) = -1/2 k

To find the equations for the osculating, normal, and rectifying planes, we use the following formulas:

Osculating plane: (r - r(t)) · r'(t) = 0

Normal plane: (r - r(t)) · r''(t) = 0

Rectifying plane: T(t) · (r - r(t)) = 0

Substituting the values of r(-π/3), r'(t), and r''(t), we get:

Osculating plane: (x - 1/2)(-1/2) + (y + √3/2)(√3/2) + (z + 1)(0) = 0

-x/4 + √3y/4 + √3/2 = 0

-x + √3y + 2√3 = 0

Rectifying plane: (1/2)(x - 1/2) + (√3/2)(y + √3/2) + (0)(z + 1) = 0

x/2 + √3y/2 - 1 = 0

x + √3y - 2 = 0

Therefore, the equations for the osculating, normal, and rectifying planes at t = -π/3 are:

Osculating plane: -x + √3y + 2√3 = 0

Normal plane: √3x - y - 2√3 = 0

Rectifying plane: x + √3y - 2 = 0

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The Nyquist-Shannon sampling theorem, also known as the sampling theorem, states that if the sampling rate is greater than or equal to twice the maximum frequency of the signal being sampled, then the original signal can be perfectly reconstructed from its samples.

The maximum frequency of the signal is also referred to as the Nyquist frequency, which is half of the sampling rate. The theorem is often used in digital signal processing, data compression, and other applications where analog signals are converted into digital signals.

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Answer:

it c

Step-by-step explanation:

it well retun but it L to q but P in the way so that answer wod be c

The area of the surface is (2/3)π.

We can solve this problem using a double integral. First, we need to find the limits of integration for x and y. From the equation x + y + z = 1, we get:

z = 1 - x - y

Substituting this into the equation x² + 7y² ≤ 1, we get:

x² + 7y² ≤ 1 - z² + 2xz + 2yz

Since we want to find the area of the surface, we need to integrate over x and y for each value of z that satisfies this inequality. The limits of integration for x and y are given by the ellipse x² + 7y² ≤ 1 - z² + 2xz + 2yz, so we can write:

∫∫[x² + 7y² ≤ 1 - z² + 2xz + 2yz] dA

where dA is the area element.

To evaluate this integral, we can change to elliptical coordinates u and v, defined by:

x = √(1 - z²) cos u

y = 1/√7 √(1 - z²) sin u

z = v

The limits of integration for u and v are:

0 ≤ u ≤ 2π

-1 ≤ v ≤ 1

The Jacobian for this transformation is:

J = √(1 - z²)/√7

So the integral becomes:

∫∫[u,v] (x² + 7y² )J du dv

Substituting in the values for x, y, z, and J, we get:

∫∫[u,v] [(1 - z²) cos² u + 7/7 (1 - z²) sin² u] √(1 - z²)/√7 du dv

Simplifying, we get:

∫∫[u,v] [(1 - z²) (cos² u + sin² u)] (1/√7) dz du dv

= ∫∫[u,v] [(1 - z²)/√7] dz du dv

= (2/3)π

Therefore, the area of the surface defined by x + y + z = 1, x² + 7y² ≤ 1 is (2/3)π.

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The value of Area of triangle is,

A = 38 units²

Given that;

Coordinates of STU are,

S = (2, 6)

T = (5, 2)

U = (- 7, - 7)

Hence, Midpoint of S and T is, X

X = (2 + 5) /2 , (6 + 2)/2

X = (3.5, 4)

We know that;

The distance between two points (x₁ , y₁) and (x₂, y₂) is,

⇒ d = √ (x₂ - x₁)² + (y₂ - y₁)²

Hence, Distance between S and T is,

d = √(5 - 2)² + (2 - 6)²

d = √9 + 16

d = √25

d = 5

And, Distance between U and X is,

d = √(3.5 - (-7))² + (4 - (-7))²

d = √110.25 + 121

d = √231.25

d = 15.2

Thus, Area of triangle is,

A = 1/2 × ST × UX

A = 1/2 × 5 × 15.2

A = 38 units²

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The answer to the fraction 6/7 - 4/5 is 2/35.

To subtract fractions with different denominators, we need to find a common denominator.

The common denominator for 7 and 5 is 35, hence:

6/7 - 4/5

= (6*5)/(7*5) - (4*7)/(5*7)

= 30/35 - 28/35

Now, we can subtract the numerators and keep the common denominator:

= (30 - 28)/35

= 2/35

Hence, the answer to 6/7 - 4/5 is 2/35.

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part a.

The mean age of Kylie's cousins is 14.8.

part b.

The complete table is shown below:

8   -6.8    46 .24

11   -3.8   14.44

16   1.2     1.44

19   4.2    17.64

20   5.2    27.04

The squared difference is Σ(P) = 106.8

part c.

The population standard deviation is 4.12.

The standard deviation is a measure of the amount of variation or dispersion of a set of values.

standard deviation (σ) =√(Σ(P) / N)

standard deviation (σ) = √(106.8 / 5)

standard deviation (σ)  = 4.1

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The mean and standard deviation obtained from simulations may differ from the true mean

standard deviation of a negative binomial distribution with parameters $r=0.6$ and $p=10$. However, with a large number of simulations, the mean and standard deviation from the simulations should approach the true mean and standard deviation of the distribution.

In general, the mean of a negative binomial distribution with parameters $r$ and $p$ is $r \cdot (1-p)/p$, and the standard deviation is $\sqrt{r \cdot (1-p)/p^2}$.

These formulas can be used to calculate the true mean and standard deviation of a $nb(0.6,\ 10)$ distribution.

Comparing the simulated mean and standard deviation to the true values can help assess the accuracy of the simulation results.

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In the situation, if you took another sample of 157 students and asked them for measurements of thumb and height, it is unlikely that you would get the exact same F ratio.

The F ratio is a statistical value that compares the variance between groups to the variance within groups. Here's why it might be different:

1. Sampling variability: Since you are taking another sample of 157 students, there is a chance that the measurements will be slightly different from the original sample. The new sample might have students with different thumb lengths and heights, which could lead to different variances and thus a different F ratio.

2. Measurement errors: Even if the actual relationship between thumb length and height remains constant, the process of measuring these variables can introduce errors. Errors in measurement can cause discrepancies in the data, leading to a different F ratio.

3. Population diversity: If the new sample is drawn from a different population, there could be differences in the relationship between thumb length and height in that population. This would also result in a different F ratio.

To summarize, while it is possible to get a similar F ratio in a new sample, it is unlikely that the F ratio would be exactly the same due to sampling variability, measurement errors, and potential population differences.

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a. The magnitude of the force required to keep the car from sliding down the hill is approximately 327 pounds.

b. The magnitude of the force of the car against the hill is approximately 3685 pounds.

a. To find the magnitude of the force required to keep the car from sliding down the hill, we need to use the formula:

force = weight * sin(angle)

where weight is the weight of the car and angle is the angle of the hill.

Plugging in the given values, we get:

force = 3700 * sin(5.30)

force = 326.8 pounds

Therefore, the magnitude of the force required to keep the car from sliding down the hill is approximately 327 pounds.

b. The magnitude of the force of the car against the hill is equal to the component of the car's weight that is perpendicular to the hill. This can be found using the formula:

force = weight * cos(angle)

Plugging in the given values, we get:

force = 3700 * cos(5.30)

force = 3684.6 pounds

Therefore, the magnitude of the force of the car against the hill is approximately 3685 pounds.

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The terms a0, a1, a2, and a3 for each sequence are as follows: a.) 1, -2, 4, -8 b.) 3, 3, 3, 3 c.) 7, 11, 15, 19 d.) 1, 0, 8, -2

a.) an = (-2)^n

To find the terms, simply substitute the values of n into the equation.

a0 = (-2)^0 = 1
a1 = (-2)^1 = -2
a2 = (-2)^2 = 4
a3 = (-2)^3 = -8

b.) an = 3

Since the sequence is constant, all terms will have the same value.

a0 = 3
a1 = 3
a2 = 3
a3 = 3

c.) an = 7 + 4n

To find the terms, substitute the values of n into the equation.

a0 = 7 + 4(0) = 7
a1 = 7 + 4(1) = 11
a2 = 7 + 4(2) = 15
a3 = 7 + 4(3) = 19

d.) an = 2n + (-2)^n

To find the terms, substitute the values of n into the equation.

a0 = 2(0) + (-2)^0 = 0 + 1 = 1
a1 = 2(1) + (-2)^1 = 2 - 2 = 0
a2 = 2(2) + (-2)^2 = 4 + 4 = 8
a3 = 2(3) + (-2)^3 = 6 - 8 = -2

So, the terms a0, a1, a2, and a3 for each sequence are as follows:

a.) 1, -2, 4, -8
b.) 3, 3, 3, 3
c.) 7, 11, 15, 19
d.) 1, 0, 8, -2

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Complete question:

Q: What are the terms a0 ,a1 , a2 , and a3 of the sequence[an] , where an equals

a.) (-2)n?

b.) 3?

c.) 7 + 4n

d.)2n + (-2)n ?

Before coming to a stop, the pendulum swings 192 feet in total.

The lengths of the arcs form a geometric sequence. Let's call the length of the first arc "a" and the common ratio "r". Then, we have:

First arc: a = 48

Third arc: ar² = 27

We can use the ratio of the third and first arcs to solve for the common ratio "r":

(ar²)/a = 27/48

r² = (27/48)

Now we can use the formula for the sum of an infinite geometric series to find the total distance traveled by the pendulum. The formula is:

S = a / (1 - r)

where S is the sum of the series, a is the first term, and r is the common ratio.

Substituting the values we have:

S = 48 / (1 - √(27/48))

Simplifying:

S = 48 / (1 - (3/4))

S = 48 / (1/4)

S = 192

Therefore, the pendulum travels a total distance of 192 feet before coming to a rest.

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The digits 6, 3, 5, 2, and 8 may be combined to create 120 distinct 4-digit numbers.

To find the number of different 4-digit numbers that can be formed using the digits 6, 3, 5, 2, and 8, we can use the permutation formula:

nPr = n! / (n - r)!

where r is the number of digits we must select in order to make a 4-digit number and n is the total number of digits available.

In this instance, we have a total of 5 digits to pick from, and we must select 4 of them in order to create a 4-digit number. As a result, we have:

n = 5

r = 4

Plugging these values into the formula, we get:

nPr = 5! / (5 - 4)!

nPr = 5! / 1!

nPr = 5 x 4 x 3 x 2

nPr = 120

Therefore, there are 120 different 4-digit numbers that can be formed using the digits 6, 3, 5, 2, and 8.

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The new triangle will we get by a scale factor of 1/2 from a centre of enlargement (10,2)

To enlarge a triangle by a scale factor of 1/2 from a center of enlargement,

Plot the coordinates of the triangle on a graph.

Draw a line from each vertex of the triangle to the center of enlargement.

Measure the length of each line and multiply it by the scale factor of 1/2.

Using the same angle as the original line, draw a new line from each vertex that is the length determined in step 3.

The new vertices of the triangle are where these new lines intersect.

Hence, the new triangle will we get by a scale factor of 1/2 from a centre of enlargement (10,2)

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The value of m + p is related to the function f(x) and the values of x and m.

Given the function f(x) = -3(x - m)^2 + p and the point T(2, 5) on the parabola, let's find m + p when f(x) = -3(x - m)^2 + p.

Step 1: Substitute the coordinates of the point T(2, 5) into the function.

5 = -3(2 - m)^2 + p

Step 2: Expand and simplify the equation.

5 = -3(4 - 4m + m^2) + p
5 = -12 + 12m - 3m^2 + p

Step 3: Rearrange the equation to solve for m and p.

3m^2 - 12m + p = 7

Now, we have one equation with two unknowns, which cannot be solved for specific values of m and p. However, the question asks for m + p, which we can express in terms of the given function f(x).

The question asks to find m + p when f(x) = -3(x - m)^2 + p. Since we cannot find specific values for m and p, we can instead write an equation relating f(x), m, and p:

m + p = f(x) + 3(x - m)^2

This equation shows how m + p is related to the function f(x) and the values of x and m.

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Answer:

Step-by-step explanation: The number to its right should be considered to round the given number to the nearest thousandth. If that number is greater than 5 then +1 is added to the existing number in the thousandth place, if that number is less than 5 then the thousandth number remains the same. if the number is 5 then the second number on the right is considered to round off this number and then the thousandth number is rounded off

If the linearity assumption is violated, you would see a non-linear pattern or uneven distribution of residuals in the residual plot.

If the linearity assumption is violated, you might see the following in a residual plot:

1. There are more negative values in one part of the range and more positive values in another part of the range. This indicates that the relationship between the variables is not linear, as the residuals are not evenly distributed across the whole range.

2. The positive and negative values are scattered across the whole range, but the points show a non-linear pattern (e.g., a curve or a U-shape). This suggests that a linear model may not adequately represent the relationship between the variables.

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In the Second European Stroke Prevention Study, researchers aimed to determine if adding an anticlotting drug called dipyridamole to aspirin treatment would be more effective in preventing strokes among patients who had already experienced one.

The study consisted of four groups with varying treatments and recorded the number of patients who had a stroke during the two-year study period.

Here is a summarized two-way table of the data:

| Group | Treatment      | Number of Patients | Number who had a stroke |
|-------|----------------|--------------------|-------------------------|
| 1     | Placebo        | 1649               | 250                     |
| 2     | Aspirin        | 1649               | 206                     |
| 3     | Dipyridamole   | 1654               | 211                     |
| 4     | Both (Aspirin and Dipyridamole) | 1650 | 157                     |

The table displays the treatment administered to each group, the number of patients in each group, and the number of patients who experienced a stroke during the study. From the data, it is evident that the group receiving both aspirin and dipyridamole (Group 4) had the lowest number of strokes (157), suggesting that the combined treatment may be more effective than either drug alone or a placebo in preventing strokes among patients with a history of stroke.

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The volume of a square pyramid is given by the formula: V = (1/3) * b^2 * h

where b is the base length and h is the height.

In this case, the base is a square with sides of length 2.75 inches, so the base area is:

b^2 = 2.75^2 = 7.5625 square inches

The height of the pyramid is also 2.75 inches.

Therefore, the volume of the ornament is:

V = (1/3) * 7.5625 * 2.75 = 6.5391 cubic inches

Rounding to the nearest hundredth, the approximate volume of the ornament is:

V ≈ 6.54 cubic inches

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Inform Chase of the 87% confidence interval for the proportion of vampires in Vladistad and Morganopolis.

The 87% confidence interval for the proportion of people who are vampires in each city within the country of Transylvania, we need to use a statistical formula that takes into account the sample proportions, sample sizes, and the level of confidence.

However,

Since we only have information on the vampire proportions in two cities (Vladistad and Morganopolis), we cannot directly calculate the confidence interval for each city separately.

One option is to pool the sample proportions from both cities and use the combined proportion to calculate the confidence interval.

This assumes that the true proportion of vampires is the same in both cities, which may or may not be a valid assumption depending on other factors such as the sample sizes, sampling methods, and potential differences between the cities.

To pool the sample proportions, we can use the following formula:

Pooled proportion = (number of vampires in Vladistad + number of vampires in Morganopolis) / (sample size in Vladistad + sample size in Morganopolis)

Plugging in the numbers, we get:

Pooled proportion = (0.18 x n1 + 0.11 x n2) / (n1 + n2)

Where n1 and n2 are the sample sizes in Vladistad and Morganopolis, respectively.

Without knowing the sample sizes, we cannot calculate the pooled proportion or the confidence interval.

Therefore, we need more information or data to provide Chase with a confidence interval for the proportion of vampires in each city.

For similar question on confidence interval:

https://brainly.com/question/29680703

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Answer:

840

Step-by-step explanation:

To find the LCM of a set of numbers, we can use different methods such as prime factorization method or listing multiples method 1.

In this case, we can use the listing multiples method to find the LCM of the first eight positive integers 1. We list out the multiples of each number until we find a common multiple that is divisible by all of them.

Multiples of 1: 1, 2, 3, 4, 5, 6, 7, 8, ...

Multiples of 2: 2, 4, 6, 8, ...

Multiples of 3: 3, 6, ...

Multiples of 4: 4, 8, ...

Multiples of 5: 5, ...

Multiples of 6: 6, ...

Multiples of 7: 7, ...

Multiples of 8: 8, ...

We can see that the smallest common multiple that is divisible by all of them is 840.

I hope this helps!