Answer:
1) by using a protractor
2) by finding a point
3) by extending the line of the angle until it reaches the other side of the field.
Step-by-step explanation:
There are different methods he can use to draw the angle on the other side of the yard, three of which are the following:
1) he can use a protractor to measure the angle he drew. That way he can go to the other side of the field and measure the same angle there. So then he can draw the angle in the new location.
2) He can draw a line on the given angle and find a point that passes through that line. Then he can draw a perpendicular line to the origin of the angle until it reaches the other side of the yard. This perpendicular line will cross the other side of the yard. This point where the line crosses the other side of the yard will be the new origin. With this new origin find the point again and draw a line that goes through the new origin and the new point he found.
3) Depending on the dimensions of the field, he can draw extend the line of the angle in such a way that it reaches the other side of the field. Then the angle will be on the other side. He can then use a square to move it around to where he wants it to be.
The following box plot shows the number of years during which 40 schools have participated in an interschool swimming meet: A box and whisker plot is drawn using a number line from 0 to 10 with primary markings and labels at 0, 5, 10. In between two primary markings are 4 secondary markings. The box extends from 1 to 6 on the number line. There is a vertical line at 3.5. The whiskers end at 0 and 8. Above the plot is written Duration of Participation. Below the plot is written Years. At least how many schools have participated for more than 1 year and less than 6 years?
Answer:
Step-by-step explanation:
The box encloses data between the two quartiles, namely at least half of the data. If there are 40 schools, then half of them would be in the box, between 1 and 6.
see attached plot.
Answer:
really hard to tell what the box plot is like without an attachment so im gonna help u find it out anyway
Step-by-step explanation:
basically when u look at a box plot and the range the line in the middle is the median and then the max the lowest range the lower quartile and then the higher quartile you can find ur anser, simply find the median first, find where the lower quartile is and then the lowest number in the group thats in betweeen 1 and 6
Go step by step to reduce the radical. 288
Step-by-step explanation:
hope this helps if not well im rlly srry lol
What is the simplified form of the following expression?
[tex]2 (\sqrt[4]{16x}) - 2 (\sqrt[4]{2y} ) + 3 (\sqrt[4]{81x} ) - 4 (\sqrt[4]{32y} )[/tex]
We have
[tex]16=2^4\implies\sqrt[4]{16}=2[/tex]
[tex]81=3^4\implies\sqrt[4]{81}=3[/tex]
[tex]32=2^5\implies\sqrt[4]{32}=2\sqrt[4]{2}[/tex]
So
[tex]2\sqrt[4]{16x}-2\sqrt[4]{2y}+3\sqrt[4]{81x}-4\sqrt[4]{32y}[/tex]
is equivalent to
[tex]2^2\sqrt[4]{x}-2\sqrt[4]{2y}+3^2\sqrt[4]{x}-8\sqrt[4]{2y}[/tex]
which reduces to
[tex]13\sqrt[4]{x}-10\sqrt[4]{2y}[/tex]
Una compañía sabe que si produce "x" unidades mensuales su utilidad "u" se podría calcular con la expresión: u(x)=-0.04x^2+44x-4000 donde "u" se expresa en dólares. Determine la razón del cambio promedio de la utilidad cuando el nivel de producción cambia de 600 a 620 unidades mensuales. Recuerde que la pendiente de la recta secante a la gráfica de la función representa a la razón de cambio promedio.
Answer:
The ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
Step-by-step explanation:
The question is:
A company knows that if it produces "x" monthly units its utility "u" could be calculated with the expression: u (x) = - 0.04x ^ 2 + 44x-4000 where "u" is expressed in dollars. Determine the ratio of the average change in profit when the level of production changes from 600 to 620 units per month. Remember that the slope of the secant line to the graph of the function represents the average rate of change.
Solution:
The expression for the utility is:
[tex]u (x) = - 0.04x ^ {2} + 44x-4000[/tex]
It is provided that the slope of the secant line to the graph of the function represents the average rate of change.
Then the ratio of the average change in profit when the level of production changes is:
[tex]\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}[/tex]
Compute the values of u (x₁) and u (x₂) as follows:
x₁ = 600
[tex]u (x_{1}) = - 0.04x_{1} ^ {2} + 44x_{1}-4000[/tex]
[tex]= - 0.04(600) ^ {2} + 44(600)-4000\\=-14400+26400-4000\\=8000[/tex]
x₂ = 620
[tex]u (x_{2}) = - 0.04x_{2} ^ {2} + 44x_{2}-4000[/tex]
[tex]= - 0.04(620) ^ {2} + 44(620)-4000\\=-15376+27280-4000\\=7904[/tex]
Compute the average rate of change as follows:
[tex]\text{Average change in profit}=\frac{u(x_{2})-u(x_{1})}{x_{2}-x_{1}}[/tex]
[tex]=\frac{7904-800}{620-600}\\\\=\frac{-96}{20}\\\\=-\frac{24}{5}\\\\=-24:5[/tex]
Thus, the ratio of the average change in profit when the level of production changes from 600 to 620 units per month is -24 : 5.
10.
Find the length of the arc on a circle of radius r intercepted by a central angle 0.
r=20 cm,
e
1/4 radian
Answer:
Length of arc = 5 cm (Approx)
Step-by-step explanation:
Given:
Radius of circle = 20 cm
Angle = 1/4 radian
Find:
Length of arc
Computation:
Angle in degree = 1/4 radian × 180°π
Angle in degree = 1/4 × 180° / 22/7
Angle in degree = 14.31° Approx
Length of arc = (Ф / 360)2πr
Length of arc = (14.31 /360)2(22/7)(20)
Length of arc = 4.997 cm
Length of arc = 5 cm (Approx)
. What is half the next number in the pattern 1, 3, 9, 27, 81
A. 234
B. 67
D c. 468
0 0.76
Answer:
A. 243
Step-by-step explanation:
just multiply the next number by 3
81*3= 243
Answer:
[tex]\boxed{243}[/tex]
Step-by-step explanation:
The ratio can be found by dividing a term in the sequence by the previous term.
[tex]\frac{27}{9} =3[/tex]
Each term gets multiplied by 3 to get the next term.
[tex]81 \times 3 = 243[/tex]
I promise I will mark the brainiest
Answer:
[tex]\frac{9}{a - b}[/tex].
Step-by-step explanation:
a^2 - b^2 = 9
(a + b)(a - b) = 9
a + b = [tex]\frac{9}{a - b}[/tex].
ab = 3
a = 3/b
3/b + b = [tex]\frac{9}{\frac{3}{b} -b}[/tex]
3 + b^2 = [tex]\frac{9b}{\frac{3}{b}-\frac{b^2}{b} }[/tex]
3 + b^2 = [tex]\frac{9b}{\frac{3-b^2}{b} }[/tex]
3 + b^2 = [tex]9b * \frac{b}{-b^2 + 3}[/tex]
3 + b^2 = [tex]\frac{9b^2}{-b^2 + 3}[/tex]
(b^2 + 3)(-b^2 + 3) = 9b^2
-b^4 + 9 = 9b^2
b^4 + 9b^2 - 9 = 0
Let's say that b^2 = x
x^2 + 9x - 9 = 0
Hope this [somewhat] helps!
Answer:
Step-by-step explanation:
a²-b²=9
ab=3 then a=3/b
a²-b²=9
(a+b)(a-b)=9 ( the values has to b (3*3) or (9*1)
but since ab=3. so the value has to be (3*3)
(a+b)(a-b)=9
3*3=9
a+b=3
ab=3
To work out the area in m² of material required for a pair of curtains, a seamstress squares the height of the window in m and adds 0.5.
a) What area of material is required for a window of height 1.2meters?
b) What area of material is required for a window of height p meters?
c) if the area of material required is 2.75m²,what is the height of the window?
Answer:
a. Area = 1.94m²
b. Area = (p² + 0.5)m²
c. Height = 1.5m
Step-by-step explanation:
Given
Let H represents Height and A represents Area
From the first and second statements, we have that:
[tex]A = H^2 + 0.5[/tex]
a. Calculating Area When Height = 1.2
[tex]A = H^2 + 0.5[/tex]
Substitute 1.2 for H
[tex]A = 1.2^2 + 0.5[/tex]
[tex]A = 1.44 + 0.5[/tex]
[tex]A = 1.94[/tex]
Hence, the area is 1.94m²
b. Calculating Area When Height = p
[tex]A = H^2 + 0.5[/tex]
Substitute p for H
[tex]A = p^2 + 0.5[/tex]
Hence, the area is (p² + 0.5)m²
c. Calculating Height When Area = 2.75m²
[tex]A = H^2 + 0.5[/tex]
Substitute 2.75 for A
[tex]2.75 = H^2 + 0.5[/tex]
Subtract 0.5 from both sides
[tex]2.75 - 0.5 = H^2 + 0.5 - 0.5[/tex]
[tex]2.75 - 0.5 = H^2[/tex]
[tex]2.25 = H^2[/tex]
Take Square Root of both sides
[tex]\sqrt{2.25} = \sqrt{H^2}[/tex]
[tex]\sqrt{2.25} = H[/tex]
[tex]1.5 = H[/tex]
[tex]H = 1.5[/tex]
Hence, the height is 1.5m
Does anyone know the answer
Solution: C
Explanation:
Use the cosine rule
A^2=B^2+C^2-2BCcos a
5^2=8^2+8^2-2×8×8cos a
cos a=(25-64-64)÷(-2×64)
a=36.419°
approx = 36
Overnight the temperature in Alaska dropped from 3%
degrees Fahrenheit to twelve and a quarter degrees
Fahrenheit below zero. By how many degrees did the
cemperature drop overnight?**
A. 8 3/4 degrees
B. 9 3/4 degrees
C. 15 1/2 degrees
D. 15 3/4 degrees
Answer:
A. 8 3/4 degrees
Step-by-step explanation:
Alaska temperature dropped from 3 degrees Fahrenheit to twelve and a quarter degrees Fahrenheit below zero
12 1/4°F - 3°F
=8 3/4°F
The temperature dropped by 8 3/4°F
Find the probability of selecting none of the correct six integers in a lottery, where the order in which these integers are selected does not matter, from the positive integers not exceeding the given integers. (Enter the value of probability in decimals. Round the answer to two decimal places.) 40
Answer:
Probability of selecting none of the correct six integers:
a) 0.350
b) 0.427
c) 0.489
d) 0.540
Step-by-step explanation:
a) 40
Given:
Number of integers in a lottery 6
Order in which these integers are selected does not matter
To find:
Probability of selecting none of the correct six integers
Solution:
When the order of selection does not matter then we use Combinations.
Given integers = 40
Number of ways to choose 6 from 40.
Let A be the sample space of choosing digits 6 from 40.
Then using Combinations:
(n,k) = n! / r! (n-r)!
n = 40
r = 6
40C6
=(40,6) = 40! / 6! ( 40 - 6)!
= 40! / 6!34!
= 40*39*38*37*36*35*34! / 6!34!
= 2763633600 / 720
= 3838380
Let E be the event of selecting none of the correct six integers.
So using combinations we can find the total number of ways of selecting none of 6 integers from 40
n = 40 - 6 = 34
r = 6
34C6
=(34,6) = 34! / 6! ( 34 - 6)!
= 34! / 6! 28!
= 34 * 33 * 32 * 31 * 30 * 29 * 28! / 6! 28!
=968330880 / 720
= 1344904
Probability of selecting none of the correct six integers:
P(E) = E / A
= 1344904 / 3838380
= 0.350
Probability of selecting none of the correct six integers is 0.350
b) 48
Following the method used in part a)
(n,k) = n! / r! (n-r)!
n = 48
r = 6
48C6
=(48,6) = 48! / 6! ( 48 - 6)!
= 48! / 6! ( 42 )!
= 48*47*46*45*44*43*42! / 6!42!
= 8835488640 / 720
= 12271512
Let E be the event of selecting none of the correct six integers.
So using combinations we can find the total number of ways of selecting none of 6 integers from 48
n = 48 - 6 = 42
r = 6
42C6
= (42,6) = 42! / 6! ( 42 - 6)!
= 42! / 6! 36!
= 3776965920
= 5245786
P(E) = E / A
= 5245786/12271512
= 0.427
c) 56
(n,k) = n! / r! (n-r)!
n = 56
r = 6
56C6
=(56,6) = 56! / 6! ( 56- 6)!
= 56! / 6! ( 50 )!
= 56*55*54*53*52*51*50! / 6! 50!
= 23377273920/6
= 32468436
Let E be the event of selecting none of the correct six integers.
So using combinations we can find the total number of ways of selecting none of 6 integers from 56
n = 56 - 6 = 50
(50,6) = 50! / 6! ( 50- 6)!
= 50*49*48*47*46*45*44! / 44! 6!
= 11441304000 / 6
= 15890700
P(E) = E / A
= 15890700 / 32468436
= 0.489
d) 64
(n,k) = n! / r! (n-r)!
n = 64
r = 6
64C6
=(64,6) = 64! / 6! ( 64 - 6)!
= 64! / 6! ( 58 )!
= 64*63*62*61*60*59*58! / 6! 58!
= 53981544960 / 720
= 74974368
Let E be the event of selecting none of the correct six integers.
So using combinations we can find the total number of ways of selecting none of 6 integers from 64
n = 64 - 6 = 58
(58,6) = 58! / 6! ( 58- 6)!
= 58*57*56*55*54*53*52! / 52! 6!
= 29142257760/ 6
= 40475358
P(E) = E / A
= 40475358/ 74974368
= 0.540
The probability of selecting none of the correct six integers in a lottery is, 0.350.
Number of integers given = 40
So, Total outcomes for choosing 6 from 40 integers.
Number of arrangements [tex]=_{6}^{40}\textrm{C}[/tex]
[tex]=\frac{40!}{6!*34!} =3838380[/tex]
Since, we have to find probability of selecting none of the correct six integers in a lottery.
Remaining integer = 40 - 6 =34
Let favourable outcomes is selecting none of the correct six integers.
So, number of arrangements, = [tex]=_{6}^{34}\textrm{C}[/tex]
= [tex]\frac{34!}{6!*28!}=1344904[/tex]
Probability is defined as, divide favourable outcomes by total outcomes.
So, The probability of selecting none of the correct six integers in a lottery,
[tex]P=\frac{1344904}{3838380}=0.35[/tex]
Learn more:
https://brainly.com/question/13604758
Write these series with summation notation. 1,4,9,16...
Answer: [tex]\sum\limits_{i=1}^{n} n^2[/tex] , where n is a natural number.
Step-by-step explanation:
A series can be represented in a summation or sigma notation.
Greek capital letter, ∑ (sigma), is used to represent the sum.
For example: [tex]\sum\limits_{n=1}^{\infty} n=1+2+3+4+5+...[/tex], where n is a natural number.
The given series : 1,4,9,16 which can be written as [tex]1^2, 2^2, 3^2,...[/tex] .
So , we can write it as
[tex]\sum\limits_{n=1}^{\infty} n^2[/tex] , where n is a natural number.
Answer:
B=6
C=n^2
Just did the test
Step-by-step explanation:
Use cubic regression to find a function that fits the following points.
Answer:
Step-by-step explanation:
To use the regression function on your calculator, first hit STAT then choose 1:Edit by pressing ENTER. Then a table pops up. If it's not clear, arrow up to L1, hit CLEAR then ENTER and the table empties. Do the same with L2. Arrow left and right as needed to get from one column to the other. Then in L1 enter the x values one at a time, hitting ENTER after each. When all the x values are in, arrow over to L2 and enter the y values in the same way.
Next, hit STAT again, then right arrow over to CALC. Choose 6:CubicReg by either arrowing down to it or by pressing 6. If you have a TI 83+, the equation comes right up for you; if you have a TI 84+ or 84+CE, you have to arrow down to CALCULATE and hit ENTER to get your equation. The equation is
[tex]-2x^3+2x^2-4x+3[/tex] with a coefficient correlation (r-squared) value of 1 which means this is a perfect equation for this data and all the points you entered into the table fall perfectly on this curve.
2. Susan wants to use blue, yellow, green, and pink paint to decorate her house. She needs 3 times as much blue paint as yellow paint and ½ much yellow paint as green paint. She needs 3 ¼ gallons of pink paint, which is ¾ of a gallon more than the green paint she needs. How much paint does Susan need in all?
Answer:
B = Blue
Y = Yellow
G = Green
P = Pink
The info that we have is:
3*B = Y
(1/2)Y = G
P = (3 + 1/4) gal
P = G + 3/4 gal.
So we have 4 equations. The first step is replacing the third equation into the fourth equation, and get:
G + 3/4 gal = (3 + 1/4) gal
G = (3 + 1/4) gal - 3/4 gal = (2 + 2/4) gal
Now we can replace this into the second equation ((1/2)*Y = G) to find the value of Y.
(1/2)Y = (2 + 2/4) gal
Y = 2*(2 + 2/4) gal = (4 + 1)gal = 5 gal.
Now we can replace this into the first equation and get:
3*B = 5gal
B = 5/3 gal = (1 + 2/3)gal
So the total amount of paint used is:
T = P + G + Y + B = (3 + 1/4) gal + (2 + 2/4) gal + 5gal + (1 + 2/3)gal
T = (11 + 3/4 + 2/3)gal
T = (11 + 9/12 + 8/12)gal = (11 + 17/12)gal = (11 + 1 + 5/12)gal = (12 + 5/12) gal.
What are two possible measures of the angle below? On a coordinate plane, 2 rays form an angle. One ray sits on the x-axis in quadrant 1 and another sits on the y-axis between quadrants 3 and 4. –90° and 630° –45° and 630° –90° and 225° –45° and 225°
Answer:
–90° and 630°
Step-by-step explanation:
The described angle will be -90° plus any integer multiple of 360°. Possible values for the angle are ...
-90° and 630°
_____
Angles are conventionally measured counterclockwise from the positive x-axis. The angle shown in the attachment is measured clockwise, so represents a negative 90° angle.
Answer:
–90° and 630°
Step-by-step explanation:
The answer above is correct.
Julio’s rotation maps point K(–6, 9) to K’(9, 6). Which describes the rotation? 90 degrees clockwise rotation 180 degrees rotation 90 degrees counterclockwise rotation 270 degrees clockwise rotation
Answer: 90 degrees clockwise rotation
Step-by-step explanation:
Common rotations about Origin :
90° clockwise (x,y)→(y,-x)
90° counterclockwise (x,y)→(-y,x)
180° (x,y)→ (-x,-y)
270° clockwise (x,y)→(-y,x)
Given: Julio’s rotation maps point K(–6, 9) to K’(9, 6).
Rotation corresponding to this is (x,y) → (y,-x) since K(–6, 9) → K’(9, -(-6)) = K(9,6).
Therefore, Julio’s rotates 90° clockwise to map point K(–6, 9) to K’(9, 6).
so , correct answer is "90 degrees clockwise rotation".
Answer:
90 degrees clockwise
Step-by-step explanation:
EDGE2020
Please answer this question now
Answer:
825 or 500
Step-by-step explanation:
Depends, if it is talking about just an up-down, it is 500, but if it is just distance in general, it would be 825 because 325+500=825
Hope this will help
Music CD's cost $9 each, and movies cost $10 each. If you
spend $78 and buy 8 items, how many of each did you buy?
Answer:
2 CDs and 6 movies
Step-by-step explanation:
Let the number of CD you bought be x, and the number of movies you bought be y.
Since you bought 8 items in total,
x + y = 8 ______(1)
The sum of money spent is 78, so
9x + 10y = 78 ________(2)
From equation (1),
x = 8 - y ________(3)
Substitute (3) into (2),
9 (8-y) + 10y = 78
72 - 9y + 10y = 78
- 9y + 10y = 78-72
y = 6
Now substitute y=6 into (3).
x = 8 - y
x = 8-6
x = 2
Therefore, you bought 2 CDs and 6 movies.
Waves with an amplitude of 2 feet pass a dock every 30 seconds. Write an equation for a cosine function to model the height of a water particle above and below the mean water line. Explain your steps.
Answer:
The cosine function to model the height of a water particle above and below the mean water line is h = 2·cos((π/30)·t)
Step-by-step explanation:
The cosine function equation is given as follows h = d + a·cos(b(x - c))
Where:
[tex]\left | a \right |[/tex] = Amplitude
2·π/b = The period
c = The phase shift
d = The vertical shift
h = Height of the function
x = The time duration of motion of the wave, t
The given data are;
The amplitude [tex]\left | a \right |[/tex] = 2 feet
Time for the wave to pass the dock
The number of times the wave passes a point in each cycle = 2 times
Therefore;
The time for each complete cycle = 2 × 30 seconds = 60 seconds
The time for each complete cycle = Period = 2·π/b = 60
b = π/30 =
Taking the phase shift as zero, (moving wave) and the vertical shift as zero (movement about the mean water line), we have
h = 0 + 2·cos(π/30(t - 0)) = 2·cos((π/30)·t)
The cosine function is h = 2·cos((π/30)·t).
What is the explicit formula for this sequence?
Greetings from Brasil...
With the recursive formula, lets build the sequence:
A1 = 4
A2 = A1 - 7
A3 = A2 - 7
A4 = A3 - 7
A5 = A4 - 7
(...)
But pay attention to A3....
A3 = A2 - 7 but A2 = A1 - 7 , so rewriting A3
A3 = (A1 - 7) - 7 ⇒ A3 = A1 + 2.(- 7)
A4 = A3 - 7 ⇒ A4 = [(A1 - 7) - 7] - 7 = A1 + 3.(- 7)
A5 = {[(A1 - 7) - 7] - 7} - 7 = A5 + 4.(- 7)
so
An = A1 + (n - 1).(- 7)What is the solution to this equation?
X +8=-3
A. x=-11
B. x= 11
c. x= -5
D. x = 5
Answer:
Option A
Step-by-step explanation:
x + 8 = -3
x + 8 - 8 = -3 - 8
x = - 11
Answer:
A. x= -11
Step-by-step explanation:
We want to solve for x. Therefore, we must get x by itself on one side of the equation.
x+8= -3
8 is being added to x. The inverse of addition is subtraction. So, subtract 8 from both sides of the equation.
x+8-8=-3-8
x= -3-8
x= -11
Now let’s check our solution. Plug -11 in for x in the original equation.
x+8=-3
-11+8=-3
-3=-3
This checks out, so we know our solution is correct and A. x= -11 is the correct choice.
{b(1)=-2 {b(n)=b(n-1)-7 What’s the 3rd term?
Answer: the answer is b(5)
Step-by-step explanation:
To find the third term work backwards and plug it in. That was when you plug the solution of b(n-1) everything fits.
Answer:
b(3)=-16
Step-by-step explanation:
We have to figure out the second term
b(2)=b(1)-7
b(2)=-2-7
b(2)=-9
and now the third one
b(3)=b(2)-7
b(3)=-9-7
b(3)=-16
(Dividing polynomials ick!) Please help I'm failing summer class:)
Answer:
The answer is 9 (D).
Step-by-step explanation:
Hope this helps!
Please answer this question now
Since HJ is tangent to circle G, it forms a right angle with the radius that intersects it.
This means HG and HG are perpendicular and we have a right angle.
We have a (right) triangle with angle measurements 43 and 90, and we want to find the value of the last angle.
All the angles in a triangle must add up to 180, thus we can create the following equation to find the measurement of the last angle:
[tex]180-90-43[/tex]
[tex]=47[/tex]
The measure of angle G is 47 degrees. Let me know if you need any clarifications, thanks!
Answer:
<G = 47 degrees
Step-by-step explanation:
For this problem, we need to understand two things. This tangent on the circle, with a line drawn to the center, forms a right angle at H. Additionally, the sum of the angles of a triangle is 180. Now with these two things, let's solve.
<G = 180 - (43 + 90)
<G = 180 - 133
<G = 47 degrees
Hope this helps.
Cheers.
Please answer the question correct only if you know the answer
Use the law of cosines to solve for side g.
g^2 = e^2 + f^2 - 2*e*f*cos(G)
g^2 = 10^2 + 8^2 - 2*10*8*cos(57)
g^2 = 76.85775 ... make sure your calc is in degree mode
g = sqrt(76.85775)
g = 8.766855
g = 8.8
Mr.lopez wrote the equation 32g+8g-10g=150
Answer:
g=5
Step-by-step explanation:
32g+8g-10g=150
30g=150
g=5
How many minutes are in 324 hours?
Answer: 19440 minutes
Step-by-step explanation:
Hi there! Hopefully this helps!
--------------------------------------------------------------------------------------------------
Answer: There are 19440 minutes in 324 hours.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Since there are 60 minutes in each hour, we need to multiply the time value by 60. Like this:
324 x 60 = 19440.
A spherical mirror gives an image magnified 5 times at a distance 5 m. determine whether the mirror is convex or concave? How much will be the focal length of the mirror?
Answer:
a) The mirror is concave
b) The focal length of the mirror = -1.25m or -5/4 m
Step-by-step explanation:
a) Determine whether the mirror is convex or concave?
A concave mirror is a spherical mirror that it's magnification is equal to, less than or more than 1 while a convex mirror is a mirror whereby it magnification is always less than one.
From the above question we are told that the spherical mirror is magnified 5 times.
Hence, because the spherical mirror is magnified 5, it is a concave mirror.
b) Magnification = - image distance/ object distance
Magnification = 5
Image distance = 5m
Object distance = ???
5 = -5/Object distance
Object distance = -5/5
= -1m
Formula for focal length =
1/f = 1/v + 1/u
v = image distance = 5
u = object distance = -1
1/f = 1/5 +1/-1
1/f = 1/5 - 1
1/f = -4/5
f = -5/4
f = -1.25m
The focal length of the mirror = -1.25m
In a school, the ratio of students of class 9 to that of class 10 is 3:2. 30% of the students of class 9 and 10%of the students of class 10 were elected to the school student committee. What fraction of the total number of students of the two classes was selected to the school student committee?
Answer:
22% of the two classes were elected to the student committee
Step-by-step explanation:
Given
class 9 : class 10 = 3:2 = 60% : 40%
Total fraction = 60% * 30% + 40% * 10% = 18% + 4% = 22%
Represent the expression
(4 x 1,000) + (3 x 100) + (6 x
1/100) + (7x1000)
as a decimal number.
Answer:
The answer is 11 300.06
[tex](4 \times 1000) + (3 \times 100) + (6 \times \frac{1}{100}) + (7 \times 1000) [/tex]
[tex] = 4000 + 300 + \frac{6}{100} + 7000[/tex]
[tex] = 11 \: 300 + 0.06[/tex]
[tex] = 11 \: 300.06[/tex]