The graph below shows a company's profit f(x), in dollars, depending on the price of erasers x, in dollars, sold by the company: Part A: What

Answer:

- 0.8

Step-by-step explanation:

The first thing we want to do here is simplify the expression -

[tex]\frac{3}{5}[/tex]( 2x + 5 ) - 2x, Distribute the " [tex]\frac{3}{5}[/tex] " to elements within the parenthesis

= [tex]\frac{3}{5}[/tex] [tex]*[/tex] 2x + [tex]\frac{3}{5}[/tex] [tex]*[/tex] 5 - 2x, Focus on simplifying the expression " [tex]\frac{3}{5}[/tex] [tex]*[/tex] 2x + [tex]\frac{3}{5}[/tex] [tex]*[/tex] 5 "

= [tex]2\cdot \frac{3}{5}x+5\cdot \frac{3}{5}[/tex] - 2x

= [tex]\frac{6x}{5}+3[/tex] - 2x, Combine fractions

= [tex]-\frac{4x}{5}[/tex] + 3

= [tex]-\frac{4}{5}[/tex]x + 3

So we have our simplified expression "  [tex]-\frac{4}{5}[/tex]x + 3, " with [tex]-\frac{4}{5}[/tex] being the coefficient of x. Our requirements are that this fraction should be expressed as a decimal, so we can simply divide the numerator by the denominator to figure that out,

- 4 / 5 = - 0.8,

Solution = - 0.8

Answer: The percentage of bags will the inspector reject = 15.87%

Step-by-step explanation:

Given, The weights of apple bags are normally distributed  with a mean of 5 pounds and a standard deviation of 0.25 pound.

i.e. [tex]\mu=5[/tex] and [tex]\sigma=0.25[/tex]

Let X be the weight of any random apple bag.

Since an inspector  weighs each bag and rejects all bags that weigh less than 4.75 pounds.

Then, the probability of bags will be rejected = probability that bags weigh less than 4.75 pounds.

[tex]=P(X<4.75)\\\\=P(\dfrac{X-\mu}{\sigma}<\dfrac{4.75-5}{0.25})\\\\=P(z<-1)\ \ \ [z=\dfrac{X-\mu}{\sigma}][/tex]

[tex]=1-P(z<1)\\\\=1-0.8413\ \ \ [\text{By z-value table}]\\\\=0.1587=15.87\%[/tex]

Hence, the percentage of bags will the inspector reject = 15.87%

Answer:

add 10 on both sides

7<X

So X has to be bigger than 7

So 8,9,10, and 1000 can all be X.

Step-by-step explanation:

Answer:

7 < x

Step-by-step explanation:

the inequality is -3< x-10

any number that is greater than 7 can be a solution

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The multiplier for 1% would be 1.01

Multiply her distance from yesterday by this value

new distance = 10.75 x 1.01

new distance = 10.8575

I'm assuming you'd want the answer to 2 d.p (however, you can round accordingly if needed otherwise)

Subtract the two values

10.8575 - 10.75 = 0.1075

So, to 2 d.p your answer would be 0.11 km

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- Ally ✧    

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Answer:

179,5 inches³

Step-by-step explanation:

Hello !

d = 2r => r = d/2 = 7in/2 = 3.5 inches

V = 4π·r³/3

= 4·3.14·(3.5in)³/3

= 538.51in³/3

≈  179,5 inches³

Answer:

its 3 units.

Step-by-step explanation:

Answer: 3 units

Step-by-step explanation:

Points A and B have the same y value.  Thus, subtract the x-values from each other to get 5 - 2 = 3.

Hope it helps <3

Answer:

Christine needs to drive 250 miles for the two plans to cost the same

Step-by-step explanation:

For answering the question correctly and helping Christine, we will use the following equation:

x = number of miles driven

Cost of the first plan = 0.60x

Cost of the second plan = 50 + 0.40x

How many miles would Christine need to drive for the two plans to cost the same?

Cost of the first plan = Cost of the second plan

0.60x = 50 + 0.40x

0.60x - 0.40x = 50 (Subtracting 0.40x at both sides)

0.20x = 50

x = 50/0.2

x = 250 miles driven

Christine needs to drive 250 miles for the two plans to cost the same.

Answer:

I think The answer is B

Step-by-step explanation:

The anne's friends studied hard and got high marks higher than john's friends

Answer:

A) True

B) False

C) True

D) True

Step-by-step explanation:

Answer:

A) [tex]\boxed{\sf 700 \ pepperoni \ pizzas}[/tex]

B) See the attached file!

Step-by-step explanation:

Total pizza sales in the pie chart = 175+60+35+130

=> 400 total Pizzas

Out of these 400, there are 175 pepperoni pizzas

So,

Pepperoni Pizzas = 175/400 = 7/16 (Simplest form)

So,

Among 1600 pizzas, pepperoni pizzas would be:

=> [tex]\frac{7}{16} * 1600[/tex]

=> 7 * 100

=> 700 pepperoni pizzas

Part B)

See the attached file:

Answer:

[tex]\sf a) \ 700 \\ b) \ \sf view \: attachment[/tex]

Step-by-step explanation:

Part A:

Calculate the total parts:

[tex]130+175+60+35[/tex]

[tex]=400[/tex]

Out of 400 pizzas, 175 are pepperoni.

[tex]\frac{175}{400}[/tex]

The sales remain constant, if the total number of sold pizzas reaches 1600 then:

[tex]\frac{175}{400} \times 1600[/tex]

[tex]=700[/tex]

Out of the 1600 pizzas sold, 700 would be pepperoni.

Part B:

(attachment)

Pepperoni pizza:

[tex]\frac{200}{200+100+50+50} =\frac{1}{2}[/tex]

Hamburger pizzas:

[tex]\frac{100}{200+100+50+50} =\frac{1}{4}[/tex]

Veggie and cheese pizzas:

[tex]\frac{50}{200+100+50+50} =\frac{1}{8}[/tex]

Answer:

(2,4), (6,4), (2,-2), (6,-2)

Step-by-step explanation:

To dilate a figure multiply 2(x,y)

2(1,2)  = (2,4)

2(3,2) = (6,4)

2(1,-1) = (2,-2)

2(3,-1) = (6,-2)

Hope this helps!   Ξ

Answer:

2.7

Step-by-step explanation:

2.5/5.8 = BD/6.2

BD = 2.7

Answer: 2.7

Step-by-step explanation: 2.5/5.8 = BD/6.2

BD = 2.7

Answer:

528

Step-by-step explanation:

PEMDAS:

In this math problem, you would multiply 34 and 15 before adding 18.

[tex]18+34*15=\\\\18+510=\\\\\boxed{528}[/tex]

Brainliest Appreciated.

Answer:

528

Step-by-step explanation:

BODMAS

Multiplication first.

34 x 15= 510

Then addition:

510 + 18= 528

Answer:

Independent: Amount of hours she works

Dependent: Amount of money she makes

Step-by-step explanation:

The independent variable is the part of the equation that changes. In this case the only thing that changes is how long she works, the amount of money she charges and what she is doing does not change.

The dependent variable is what you measure in the equation. In this case, the amount of money she makes depends on the amount of time she works.

Answer:

Step-by-step explanation:

The number of hours worked, h, could be zero or greater:  [0, 40), where "40" is the upper cap on the number of hours she works.

The range consists of all possible total earnings amounts:  [$0, $1000).

Answer:

See below.

Step-by-step explanation:

The domain of a relation are simply its x-values, while the range of a relation are its y-values.

1)

We have the relation:

{(-7,2), (-2,2), (0,1), (4,5)}

Again, the domain of this relation are the x-values. Therefore, the domain is:

{-7, -2, 0, 4}

The range of this relation are the y-values. Therefore, the range is:

{2, 1, 5}

Note that even though the 2 repeats, we only count it once because it's the same.

2)

We have the relation:

{(-4,-1), (-3,-3), (-3,4), (-1,-1), (1,4)}

The domain are the x-values. Therefore, the domain is:

{-4, -3, -1, 1}

Again, the -3 repeats so we only count it once.

And the range would be the y-values:

{-3, -1, 4}

It's customary to place them in ascending order.  

Answer:

If there are two set A and B. All the elements of set A are called domain and all elements of set B are range.And element of B which are maping with set A elements are codomain

Step-by-step explanation:

domains are -7,-2,0,4

range are 2,1,5

I hope this is helpful for you

Answer:

[tex]x=19[/tex]

Step-by-step explanation:

First, note that Angle X and angle Y are angles formed when two parallel lines  are being cut by a transversal. This makes Angle X and Y consecutive interior angles. Consecutive interior angles are supplementary.

Therefore:

[tex](3x-5)+(90+2x)=180[/tex]

[tex]5x-5=90[/tex]

[tex]5x=95[/tex]

[tex]x=19[/tex]

Explanation:

RB and SB are 22 units. Since they are both equal, this means the chords NL and OQ are the same length. This is true whenever the chords are the same distance away from the center.

NL = 28, so OQ = 28 as well.

Furthermore, the radius BP cuts chord OQ in half (because BP is perpendicular to OS), which means OS = 28/2 = 14. We are also told that OS = 4x-22

Therefore,

4x-22 = 14

4x = 14+22

4x = 36

x = 36/4

x = 9

Answer:

the answer is c

Step-by-step explanation:

when expanded the first three coefficients are 1 4 6

Answer:   CCCCCc

1,4 and 6

Step-by-step explanation:

Answer:

[tex]\boxed{a*b = 1.60 * 10^2}[/tex]

[tex]\boxed{a/b = 7.53 * 10^{-14}}[/tex]

[tex]\boxed{c/a = 1.59 * 10^{13}}[/tex]

Step-by-step explanation:

a = [tex]3.47 * 10^{-6}[/tex]

b = [tex]4.61 * 10^7[/tex]

c = [tex]5.52*10^7[/tex]

Finding a*b:

a*b =( [tex]3.47 * 10^{-6}[/tex] )*( [tex]4.61 * 10^7[/tex])

= (3.47*4.61) * ([tex]10^{-6}*10^7[/tex])

When bases are same, powers are to be added

= 15.997 * [tex]10^{-6+7}[/tex]

= 15.997 * [tex]10^1[/tex]

= 159.97

Rounding it off

=> 1.60 * 10²

Finding a/b:

=> [tex]\frac{3.47*10^{-6}}{4.61*10^7}[/tex]

Using rule of exponents [tex]a^m/a^n = a^{m-n}[/tex]

=> 0.753 * [tex]10^{-6-7}[/tex]

=> [tex]7.53*10^{-1}*10^{-13}[/tex]

=> [tex]7.53 * 10^{-1-13}[/tex]

=> 7.53 * 10⁻¹⁴

Finding c/a:

=> [tex]\frac{5.52 * 10^7}{3.47*10^{-6}}[/tex]

=> 1.59 * [tex]10^{7+6}[/tex]

=> 1.59 * 10¹³

Answer:

a × b = 1.60 × 10^2

a/b = 7.52 × 10^-14

c/a = 1.59 × 10^13

Step-by-step explanation:

a = 3.47 × 10^-6

b = 4.61 × 10^7

c = 5.52 × 10^7

Solve a × b

(3.47 × 10^-6) × (4.61 × 10^7)

When bases are same in multiplication, we add the exponents.

15.9967 × 10^1

Decimal point is after first non-zero digit. Round to hundredths.

1.60 × 10^2

Solve a/b

(3.47 × 10^-6)/(4.61 × 10^7)

When bases are same in division, subtract the exponents.

3.47/4.61 × 10^-14

0.75271149674 × 10^-14

Decimal point is after first non-zero digit. Round to hundredths.

7.52 × 10^-14

Solve c/a

(5.52 × 10^7)/(3.47 × 10^-6)

When bases are same in division, subtract the exponents.

5.52/3.47 × 10^13

1.59077809798 × 10^13

Round to hundredths.

1.59 × 10^13

Answer:

1/36

Step-by-step explanation:

1/6x1/6=1/36

Answer:

9

Step-by-step explanation:

Speed of the train is:

And average speed is:

Comparing the two above, we see  y= 9

Answer:

Max would be 4y meters ahead by 4pm

Step-by-step explanation:

What we want to calculate here is the difference in the distance they have covered by 4pm given the speed at which they traveled.

Mathematically, distance = speed * time

The time is just the difference between 12 noon and 4pm which is 4 hours

Let’s tackle Max’s

He’s biking at x km/h, so the distance he would have covered by 4pm would be 4 * x = 4x meters

Now let’s tackle Sven

Sven is biking at a speed which is y mph less than Max’s x mph

Thus his speed would be (x-y) mph

His distance covered would be 4(x-y) meters

Now the difference between their bikes distance at 4pm would be;

4x - [4(x-y)]

= 4x -(4x -4y)

4x -4x + 4y

= 4y

Hence, Max would be 4y meters ahead by 4pm

By 4 pm, Max would be 4y meters far ahead of Sven.

Distance is defined as the product of speed and time.

distance = speed × time

To determine the difference in the distance they have covered by 4 pm given the speed at which they traveled.

Given that, Max and Sven bike away from home in the same direction starting at noon

The time is the difference between the 4 hours between noon and 4 o'clock.

Max's current speed of x km/h,

The distance he would have traveled by 4 pm as

⇒ 4 × x

⇒ 4x meters

Max is biking at x mph while Sven is going y mph slower.

Max would therefore be going at (x-y) mph.

Max's distance covered would be 4(x-y) meters

At 4 p.m., the distance between their bikes would be as:

⇒ 4x - [4(x-y)]

⇒ 4x -(4x -4y)

⇒ 4x -4x + 4y

⇒ 4y

Hence, By 4 pm, Max would be 4y meters far ahead of Sven.

Learn more about distance here:

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Answer:

-7 8/10  =  b

Step-by-step explanation:

Rewrite 4 1/3b as (11/3)b, and rewrite 10.4 as 104/10.  Then we have:

(11/3)b + b = 6b - 104/10.

This simplifies to b( (11/3) + 1 - 6) = 104/10, or

                             b(11/3 - 15/3) = 104/10, or

                             b( -4/3 ) = 104/10

Multiplying both sides by -3/4 isolates b, as desired:

                                                     -3(104)

                             (-3/4)(-4/3)b = -------------

                                                        4(10)

Then b = -312/40, or -156/20, or -78/10, or -7 8/10  =  b

The value of b from the expression given will be b= -7 8/10 .

A system of equations is two or more equations that can be solved to get a unique solution. the power of the equation must be in one degree.

We have been given an expression as;

4 1/3b + b = 6b–10.4

Rewrite 4 1/3b as (11/3)b, and rewrite 10.4 as 104/10, Then we have:

(11/3)b + b = 6b - 104/10.

This simplifies as;

b( (11/3) + 1 - 6) = 104/10, or

b(11/3 - 15/3) = 104/10, or

b( -4/3 ) = 104/10

Multiplying both sides by -3/4 isolates b, as desired:

-3(104)

(-3/4)(-4/3)b = -4(10)

Then b = -312/40,

or -156/20,

or -78/10,

or -7 8/10  =  b

Therefore the value of b from the expression given will be b= -7 8/10 .

Learn more about equations here;

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Answer:

31t 2,446 lb 2oz

Step-by-step explanation:

24t+7t=31t

1,507+938=2,445 lb

12 oz+6 oz=18 oz = 1 lb + 2oz (16 oz in a pound)

31t+2,445 lb+1 lb + 2oz=

31t 2,446 lb 2oz

To find the minimum value of function 1, we need to find the vertex. The formula for the x-coordinate of the vertex is -b/2a, which is -1 in this equation. However, to find minimum and maximum values, we need to look at the y-coordinate. f(-1) is 4, which we know is a minimum (rather than a maximum), because the leading coefficient is positive -- so the parabola opens upwards. So, the minimum value of f(x) is 4, and the coordinate is (-1, 4).

From the table, the minimum value of g(x) is 3, and the coordinate is (0, 3).

Therefore, function 2 has the lowest minimum value, with coordinates (0, 3).

Answer:

c) quadrant III

Step-by-step explanation:

I will be quick in this question:

[tex]\text {For }y<0 \Rightarrow \text{Quadrant III or Quadrant IV}[/tex]

[tex]\text {For }x<0 \Rightarrow \text{Quadrant II or Quadrant III}[/tex]

What both have in common?

So, the answer is Quadrant III.

Answer:

Quadrant III

Step-by-step explanation:

x < 0 is the area to the left of the y-axis, and y < 0 is the area beneath the x-axis.  This point is therefore located in Quadrant III.

Answer:  

3/10

Step-by-step explanation:

Answer:

f(30) represents the total cost when the car is driven 30 miles

Step-by-step explanation:

f(30) is the y value when x= 30

Since x represents miles, f(30) is the y value of the function when you drive a car 30 miles, basically how much it will cost.

We solve this by plugging 30 in for x:

f(30)= 90 + 0.11(30)

f(30)= 90 + 3.3

f(30)= 93.3

Thus, renting a car for a day and driving it 30 miles costs $93.30

Answer:

Step-by-step explanation:

From your equations in Part A, we can write the matrix equation as ...

  [tex]\left[\begin{array}{ccc}9&3&1\\25&5&1\\36&6&1\end{array}\right] \cdot\left[\begin{array}{c}a&b&c\end{array}\right] = \left[\begin{array}{c}8&\frac{20}{3}&5\end{array}\right][/tex]

For the purpose of finding the inverse matrix (which we don't really need to do to solve this), it is convenient to use an augmented matrix that will give both the matrix inverse and the solution.

  [tex]\left[\begin{array}{ccc|ccc|c}9&3&1&1&0&0&8\\25&5&1&0&1&0&\frac{20}{3}\\36&6&1&0&0&1&5\end{array}\right][/tex]

For the first step in the solution, we'll divide the first row by 9, then subtract 25 times that from the second row, and 36 times that from the third row. The goal of this step is to make the first column be 1, 0, 0. The result is ...

  [tex]\left[\begin{array}{ccc|ccc|c}1&\frac{1}{3}&\frac{1}{9}&\frac{1}{9}&0&0&\frac{8}{9}\\0&-\frac{10}{3}&-\frac{16}{9}&-\frac{25}{9}&1&0&-\frac{140}{9}\\0&-6&-3&-4&0&1&-27\end{array}\right][/tex]

For the second step in the solution, we'll multiply the second row by -3/10, then subtract 1/3 times that from the first row and add 6 times that to the third row. The goal of this step is to make the second column be 0, 1, 0. The result is ...

  [tex]\left[\begin{array}{ccc|ccc|c}1&0&-\frac{1}{15}&-\frac{1}{6}&\frac{1}{10}&0&-\frac{2}{3}\\0&1&\frac{8}{15}&\frac{5}{6}&-\frac{3}{10}&0&\frac{14}{3}\\0&0&\frac{1}{5}&1&-\frac{9}{5}&1&1\end{array}\right][/tex]

For the third step in the solution, we'll multiply the third row by 5, then add 1/15 of that to the first row and -8/15 of that to the second row. The goal of this step is to make the third column be 0, 0, 1. The result is ...

  [tex]\left[\begin{array}{ccc|ccc|c}1&0&0&\frac{1}{6}&-\frac{1}{2}&\frac{1}{3}&-\frac{1}{3}\\0&1&0&-\frac{11}{6}&\frac{9}{2}&-\frac{8}{3}&2\\0&0&1&5&-9&5&5\end{array}\right][/tex]

The middle section of this augmented matrix is the inverse of the coefficient matrix:

  [tex]A^{-1}=\left[\begin{array}{ccc}\frac{1}{6}&-\frac{1}{2}&\frac{1}{3}\\-\frac{11}{6}&\frac{9}{2}&-\frac{8}{3}\\5&-9&5\end{array}\right][/tex]

The right section of the augmented matrix is the solution set:

  [tex]X=\left[\begin{array}{c}a\\b\\c\end{array}\right]=\left[\begin{array}{c}-\frac{1}{3}\\2\\5\end{array}\right][/tex]

__

The equation of the parabola is ...

  [tex]\boxed{y=-\dfrac{1}{3}x^2+2x+5}[/tex]

__

The ball will hit the ground when y=0. The values(s) of x can be found from the quadratic formula:

  x = (-b±√(b²-4ac))/(2a) = (-2±√(2²-4(-1/3)(5)))/(2(-1/3))

  x = (2 ± √(32/3))/(2/3) = 3±√24 = {-1.899, 7.899}

It will take about 7.90 seconds for the ball to hit the ground.

Answer:c

Step-by-step explanation:

becuase it minus so we can get rid of a and b, and since d is not the equation to find absolute value, it is not correct