The even_numbers function returns a space-separated string of all positive numbers that are divisible by 2, up to and including the maximum that's passed into the function. For example, even_numbers(6) returns “2 4 6”. Fill in the blank to make this work.

def even_numbers(maximum):
return_string = "" for x in ___: return_string += str(x) + " " return
return_string.strip() print(even_numbers(6)) # Should be 2 4 6 print(even_numbers(10)) # Should be 2 4 6 8 10 print(even_numbers(1)) # No numbers displayed print(even_numbers(3)) # Should be 2 print(even_numbers(0)) # No numbers displayed

Answer:

8

12

Explanation:

I made the code a bit easier to understand then worked out how it would go. Here's what I did.

number = 4

repeat until number = 8:

   write 2 * number

   number = number + 2

Following this itenary, we have, the system first writes "8" as it multipled 4 by 2. Number is now equal to 6.

Next repetition, the system writes "12" as it multipled 6 by 2. Now, number = 8. The proccess now stops as number is now equal to 8.

Answer:

Microsoft Internet explorer

Answer:

absolute

Explanation:

Use absolute references when you want different formulas to refer to the same cell.

When dragging rows and columns to replicate formulas in Microsoft Excel, absolute references are the cell references you wish to maintain constant. For instance, the value in cell J4 is necessary for each and every cell in column K.

The reference would go from J4 to J5, then J6, and so on if you dragged it along column K. References that are absolute don't alter when copied or filled. To maintain the consistency of a row and/or column, utilize an absolute reference.

By including a dollar sign, a formula designates an absolute reference. The column reference, the row reference, or both may come before it.

Therefore, when you want different formulas to refer to the same cell, use absolute references.

To learn more about absolute references, refer to the link:

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Answer:

The start menu in windows 10 has similarities.

Explanation:The windows 10 is start menu and start screen. Installed windows 10 on a PC, the start button after windows appear start menu.Windows app you can access windows apps right the menu. click the left display all apps installed your personal computer. click right to open a window app NEWS,MAIL, or CALENDAR. POWER button at the bottom of the left side, and display the to shut down and restart.

Right click your account name at the top the menu.You add files explorer to taskbar.Simply click the option you needed

This question is incomplete because the options are missing; here are the options for this question:

Which of the following is the most effective way for Velma to save money each month?

A. Automatically reroute a portion of her paycheck to her savings account.

B. Manually deposit 10% of her paycheck in her savings account.

C. Pay all of her bills and then place the remaining money in her savings account.

D. Pay all of her bills and then place the remaining money in her piggy bank.

The correct answer to this question is A. Automatically reroute a portion of her paycheck to her savings account.

Explanation:

In this case, Velma needs to consistently save money for her vacation as this guarantees she will have the money for the trip. This means it is ideal every month she contributes consistently to her savings for the vacation.

This can be better be achieved by automatically rerouting a part of her paycheck for this purpose (Option A) because in this way, every month the money for the vacations will increase and the amount of money will be consistent, which means Velma will know beforehand the money she will have for the vacation. Moreover, options such as using a piggy bank or paying the bills and using the rest for her savings, do not guarantee she will contribute to the savings every month, or she will have the money she needs at the end.

Answer:

#include <iostream>

#include <iomanip>

using namespace std;

int main()

{

   double side, height;

   cout<<"Enter the length of one of the sides of the base: ";

   cin>>side;

   cout<<"Enter the height: ";

   cin>>height;

   double area = side * side;

   double volume = area * height / 3;

   cout<<"The area of the base of the pyramid is: "<<area<<endl;

   cout<<"The height of the pyramid is: "<<height<<endl;

   cout<<"The volume of the pyramid is: "<<fixed<<setprecision(2)<<volume<<endl;

   return 0;

}

Pseudocode:

Declare side, height

Get side

Get height

Set area = side * side

Set volume = area * height / 3

Print area

Print height

Print volume

Explanation:

Include <iomanip> to have two decimal places

Declare the side and height

Ask the user to enter side and height

Calculate the base area, multiply side by side

Calculate the volume using the given formula

Print area, height and volume (use fixed and setprecision(2) to have two decimal places)

Answer:

alphabet = "abcdefghijklmnopqrstuvwxyz"

test_dups = ["zzz","dog","bookkeeper","subdermatoglyphic","subdermatoglyphics"]

test_miss = ["zzz","subdermatoglyphic","the quick brown fox jumps over the lazy dog"]

# From Section 11.2 of: # Downey, A. (2015). Think Python: How to think like a computer scientist. Needham, Massachusetts: Green Tree Press.

def histogram(s):

   d = dict()

   for c in s:

       if c not in d:

           d[c] = 1

       else:

           d[c] += 1

   return d

#Part 1 Write a function called has_duplicates that takes a string parameter and returns True if the string has any repeated characters. Otherwise, it should return False.

def has_duplicates(stringP):

   dic = histogram(stringP)

   for key,value in dic.items():

       if value>1:

           return True

   return False

# Implement has_duplicates by creating a histogram using the histogram function above. Write a loop over the strings in the provided test_dups list.

# Print each string in the list and whether or not it has any duplicates based on the return value of has_duplicates for that string.

# For example, the output for "aaa" and "abc" would be the following. aaa has duplicates abc has no duplicates Print a line like one of the above for each of the strings in test_dups.

print("***Implementation of has_duplicates fuction***")

for sTr in test_dups:

   if has_duplicates(sTr):

       print(sTr+": has duplicates")

   else:

       print(sTr+": has no duplicates")

#Part 2 Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string.

#The letters in the returned string should be in alphabetical order. Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet.

#It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter.

#The function missing_letters should combine the list of missing letters into a string and return that string.

def missing_letters(sTr):

   missingLettersList = []

   dic = histogram(sTr)

   for l in alphabet:

       if l not in dic:

           missingLettersList.append(l)

   missingLettersList.sort()

   return "".join(missingLettersList)

#Write a loop over the strings in list test_miss and call missing_letters with each string. Print a line for each string listing the missing letters.

#For example, for the string "aaa", the output should be the following. aaa is missing letters bcdefghijklmnopqrstuvwxyz

#If the string has all the letters in alphabet, the output should say it uses all the letters.

#For example, the output for the string alphabet itself would be the following. abcdefghijklmnopqrstuvwxyz uses all the letters

#Print a line like one of the above for each of the strings in test_miss.

print("\n***Implementation of missing_letters fuction***")

for lTm in test_miss:

   sTr = missing_letters(lTm.replace(" ",""))

   if sTr!="":

       print(lTm+" is missing letters "+sTr)

   else:

       print(lTm +" uses all the letters")

Answer:

Natural language processing

Explanation:

NLP, because many people can use a device better when they can talk to it just like it is another person. Some systems that use an NLP are voice assistants such as Alexa and Siri.

Answer:

nxlskshwhhwwlqlqoejebx znznxjslaa

Answer:

sports = ["football", "basketball", "volleyball", "baseball", "swimming"]

last = sports[-3:]

print(last)

Explanation:

*The code is in Python.

Create a list called sports

Create a variable called last and set it to the last three elements of the sports list using slicing

Print the last

Answer:

There is a problem in the given code in the following statement:

Problem:

punctuation = r"[.?!,;:-']"

This produces the following error:

Error:

bad character range

Fix:

The hyphen - should be placed at the start or end of punctuation characters. Here the role of hyphen is to determine the range of characters. Another way is to escape the hyphen - using using backslash \ symbol.

So the above statement becomes:

punctuation = r"[-.?!,;:']"  

You can also do this:

punctuation = r"[.?!,;:'-]"  

You can also change this statement as:

punctuation = r"[.?!,;:\-']"

Explanation:

The complete program is as follows. I have added a print statement print('string1:',string1,'\nstring2:',string2) that prints the string1 and string2 followed by return string1 == string2  which either returns true or false. However you can omit this print('string1:',string1,'\nstring2:',string2) statement and the output will just display either true or false

import re  #to use regular expressions

def compare_strings(string1, string2):  #function compare_strings that takes two strings as argument and compares them

   string1 = string1.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   string2 = string2.lower().strip()  # converts the string1 characters to lowercase using lower() method and removes trailing blanks

   punctuation = r"[-.?!,;:']"  #regular expression for punctuation characters

   string1 = re.sub(punctuation, r"", string1)  # specifies RE pattern i.e. punctuation in the 1st argument, new string r in 2nd argument, and a string to be handle i.e. string1 in the 3rd argument

   string2 = re.sub(punctuation, r"", string2)  # same as above statement but works on string2 as 3rd argument

   print('string1:',string1,'\nstring2:',string2)  #prints both the strings separated with a new line

   return string1 == string2  # compares strings and returns true if they matched else false

#function calls to test the working of the above function compare_strings

print(compare_strings("Have a Great Day!","Have a great day?")) # True

print(compare_strings("It's raining again.","its raining, again")) # True

print(compare_strings("Learn to count: 1, 2, 3.","Learn to count: one, two, three.")) # False

print(compare_strings("They found some body.","They found somebody.")) # False

The screenshot of the program along with its output is attached.

Following are the modified program to the given question:

Program Explanation:

Program:

import re #import package

def compare_strings(string1, string2):#defining a method compare_strings that takes two parameters

   string1 = string1.lower().strip()#defining a variable string1 that converts and holds string value into lower case  

   string2 = string2.lower().strip()#defining a variable string1 that converts and holds string value into lower case

   punctuation = r'[^\w\s]'#defining a variable that holds value

   string1 = re.sub(punctuation, '', string1)#using the variable that calls the sub method that checks parameter value with punctuation variable value  

   string2 = re.sub(punctuation, '', string2)#using the variable that calls the sub method that checks parameter value with punctuation variable value  

   return string1 == string2#using return keyword that check string1 value equal to string2

print(compare_strings("Have a Great Day!", "Have a great day?")) # calling method that prints the return value

print(compare_strings("It's raining again.", "its raining, again")) # calling method that prints the return value

print(compare_strings("Learn to count: 1, 2, 3.", "Learn to count: one, two, three.")) # calling method that prints the return value

print(compare_strings("They found some body.", "They found somebody.")) # calling method that prints the return value

Output:

Please find the attached file.

Learn more:

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Answer:

I am writing a C++ program. Let me know if you want the program in some other programming language.

#include <iostream> //to use input output functions

using namespace std; // to identify objects like cin cout

int main(){  //start of main() function body

int n; // number of asterisks

cout<<"how many asterisks do you want to print? "; //asks user how many asterisks it should print

   cin>>n; // reads the value of number of asterisks that user want to print

   for( int i=0; i< n; i++)    { //loop to display the number of asterisks in output

       printf("*");    } } // print * asterisks

Explanation:

I will explain how the for loop works.

Suppose the user entered 3 as number of asterisks that user wants to print.

So n=3

Now for loop has a variable i that is initialized to 0. For loop checks if the value of i is less than that of n. It is true because i=0 and n=3 and 0<3. So the body of the loop executes. This prints the first asterisk *

Then the value of i is incremented to 1 and becomes i=1

At next iteration loop again checks if value of i is less than n. It is true because i=1 and n=3 and 1<3. So the body of the loop executes. This prints the second asterisk **

Then the value of i is incremented to 1 and becomes i=2

At next iteration loop again checks if value of i is less than n. It is true because i=2 and n=3 and 2<3. So the body of the loop executes. This prints the third asterisk ***

Then the value of i is incremented to 1 and becomes i=3

At next iteration loop again checks if value of i is less than n. This time it evaluates to false because i=3 and n=3 so 3=3. So the loop ends and the output is

***

The output screenshot is attached.

Answer:

RAM is used to store programs and data the CPU needs. ROM has prerecorded data and is used to boot the computer

Explanation:

Answer:

<Head>the appears the "<body>" of a web page.

<Heading> the appears the body of the web page.

Explanation:<Head> it contains that provides the information about web page.

<Heading> it contains such as the title,date, summary.

<Heading> are the<h1>,<h2>,tags

it provides the title and subtitles of the web page.

<Heading>

</Heading>

Head is element is metadata.

Heading is element is actual element.

Answer:

Head>the appears the "<body>" of a web page.

<Heading> the appears the body of the web page.

Explanation:

Answer:

Following are the program to this question:

import java.util.*;//import package for user input

class Interest //defining class Interest

{

   static double rate_of_interest = 5.00;//defining static double varaibale  

   public static double Invest_value()//defining method Invest_value

   {

           double invest;//defining double variable invest

           Scanner inc = new Scanner(System.in);//creating Scanner class object  

           System.out.print("Enter investment value: ");

           invest = inc.nextDouble();//input value in invest variable

           return invest;//return invest value

  }

  public static double calculated_Amount(double invest)//defining method calculated_Amount that accept parameter

  {

           double amount;//defining double variable

           amount = invest+ (invest * (rate_of_interest/100));//use amount to calculat 5 % of invest value

           return amount;//return amount value

  }

   public static void main(String[] as)//defining main method

   {

   double investment_value;//defining double variable

   investment_value= Invest_value();//use investment_value to hold method Invest_value value

   System.out.println("The 5% of the invest value: "+ calculated_Amount(investment_value));//use print method to print calculated_Amount value

  }

}

Output:

Enter investment value: 3000

The 5% of the invest value: 3150.0

Explanation:

In the above program a class "Interest", is defined inside the class a static double variable "rate_of_interest"  is declared that store a double value, in the next step, two methods "Invest_value and calculated_Amount" is declared.

In the "Invest_value" method, scanner class object is created for input value in the "invest" variable and the "calculated_Amount" accepts an "invest" value in its parameter and calculate its 5% and store its value in the "amount" variable.

Inside the main method, the "investment_value" is declared that holds the "Invest_value"  method value and pass the value in the "investment_value" variable in the "calculated_Amount" method and prints its return value.

Answer:

Here is the function PrintSongsShorterThan() which prints all the songs from the album shorter than the value of the parameter songDuration.

void Album::PrintSongsShorterThan(int songDuration) const {

unsigned int i;

Song currSong;  

cout << "Songs shorter than " << songDuration << " seconds:" << endl;  

for(int i=0; i<albumSongs.size(); i++){  

currSong = albumSongs.at(i);  

if(currSong.GetDuration()<songDuration){  

currSong.PrintSong();     } } }

Explanation:

I will explain the working of the for loop in the above function.

The loop has a variable i that is initialized to 0. The loop continues to execute until the value of i exceeds the albumSongs vector size. The albumSongs is a Song type vector and vector works just like a dynamic array to store sequences.

At each iteration the for loop checks if the value of i is less than the size of albumSongs. If it is true then the statement inside the loop body execute. The at() is a vector function that is used to return a reference to the element at i-th position in the albumSongs.  So the album song at the i-th index of albumSongs is assigned to the currSong. This currSong works as an instance. Next the if condition checks if that album song's duration is less than the specified value of songDuration. Here the method GetDuration() is used to return the value of duration of the song. If this condition evaluates to true then the printSong method is called using currSong object. The printSong() method has a statement cout << name << " - " << duration << endl;  which prints/displays the name of the song with its duration.

If you see the main() function statement: musicAlbum.PrintSongsShorterThan(210);

The musicAlbum is the Album object to access the PrintSongsShorterThan(210) The value passed to this method is 210 which means this is the value of the songDuration.

As we know that the parameter of PrintSongsShorterThan method is songDuration. So the duration of each song in albumSongs vector is checked by this function and if the song duration is less than 210 then the name of the song along with its duration is displayed on the output screen.

For example if the album name is Anonymous and the songs name along with their duration are:

ABC 400

XYZ 123

CDE 300

GHI 200

KLM 100

Then the above program displays the following output when the user types "quit" after entering the above information.

Anonymous                                                                              

Songs shorter than 210 seconds:                                                                        

XYZ - 123                                                                                                              

GHI - 200                                                                                                              

KLM - 100

Notice that the song name ABC and CDE are not displayed because they exceed the songDuration i.e. 210.

The output is attached.

Answer:

4 times

Explanation:

It will be executed for values 1,2,3 and 4 for i.

Answer:

See below

Explanation:

Under this topic of functions, this question has been precisely answered in a word file and attached as an image herewith (in proper format). Visualizations and CEO incomes are some of the applications of this concept.

The response to this part shows the relation between total pay and raw compensation.

Hope that answers the question, have a great day!

Answer:

Find the explanation below.

Explanation:

1. Industry 4.0 -automation revolution is a term first used in Germany in 2011 to describe the fourth generation of the industrial revolution. It is the incorporation of digitalized procedures that use smart technology that can work in real-time to industrial production. This means that the machines used in production can independently interact between themselves to accomplish tasks that would otherwise have needed human involvement.

2. My opinion regarding this industrial revolution is that it is a welcome development for businesses because it will help them execute projects at faster rates and limit some working expenses.

3. Unskilled and Semi-skilled workers will be badly affected by this revolution because tasks ordinarily performed by them would be mostly taken over by these machines. This means that companies would most likely lay off these workers whose jobs would now be performed by machines. Job regulation agencies would do well to seek ways to intervene for this group of workers. They may also have to improve their skills if they want to remain relevant to their jobs.

The revolution, however, would be favorable for high-skilled workers because they would be needed to perform jobs such as the maintenance and programming of these machines.

Answer: 1 is A

2 is D

Explanation:

Answer:

The program written in Python is as follows

def fibonac(N):

    series = ""

    for i in range(0,N+1):

         series = series + str(i) + ","

   return series[:-1]

N = int(input("Number: "))

print(fibonac(N))

Explanation:

This line defines the function fibonac

def fibonac(N):

This line initializes variable "series" to an empty string

    series = ""

This line iterates through the passed argument, N

    for i in range(0,N+1):

This line determines the Fibonacci sequence

         series = series + str(i) + ","

Lastly, this line returns the Fibonacci sequence

   return series[:-1]

The main starts here

The firs line prompts user for input

N = int(input("Number: "))

This line prints the Fibonacci sequence

print(fibonac(N))

Answer:

A. OCSP

Explanation:

Online Certificate Status Protocol (OCSP) is an Internet Protocol that is used as an alternative for CRL and is used to obtain the revocation status of a digital certificate.

A certificate revocation list (CRL) is a set of digital certificates that have been rendered invalid/revoked by the Certificate Authority (CA) because they can no longer be trusted.

Because an OCSP response uses less data than a CRL, it would be best suited to the administrator's needs.

Answer:

A printer is connected locally on Computer1 and is shared on the network. Computer2 installs the shared printer and connects to it. Computer1 considers the printer to be a(n) _____local___________ printer, and Computer2 considers the printer to be a(n) _____network___________ printer.

Explanation:

Any printer installed directly to Computer 1 is a local printer.  If this printer is then shared with computers 2 and 3 in a particular networked environment, it becomes a shared printer.  For these other computers 2 and 3, the shared printer is a network printer, because it is not locally installed in each of them.  There may be some features which network computers cannot use on a shared printer, especially if the printer can scan documents.

Answer:

Op code table.

Explanation:

In Computer programming, an Op code is the short term for operational code and it is the single instruction which can be executed by the central processing unit (CPU) of a computer.

The conversion of symbolic op codes such as LOAD, ADD, and SUBTRACT to binary makes use of a structure called the Op code table. The Op code can be defined as a visual representation of the entire operational codes contained in a set of executable instructions.

An Op code table is arranged in rows and columns which basically represents an upper or lower nibble and when combined depicts the full byte of the operational code. Each cells in the Op code table are labeled from 0-F for the rows and columns; when combined it forms values ranging from 00-FF which contains information about CPU cycle counts and instruction code parameters.

Hence, if the operational code table is created and sorted alphabetically, the binary search algorithm can be used to find an operational code to be executed by the central processing unit (CPU).

Answer:ffffffffffffgggggg

Explanation:vvvc

Answer: CSIRT

Explanation: CSIRT is team that specializes in day to day cyber incidents  

The CSIRT is responsible for creating and testing the incident response plan.

CSIRT is the Computer emergency response team. One of the key areas for the efficient operation of a corporation is the legal department. Professionals face enormous challenges, particularly when you take into account the need for other bodies within the company itself.

We can list the reviews of the CSIRT procedures that are conducted through this department as one of its key responsibilities. This department also has the responsibility of comprehending the actions that the CSIRT will take to ensure that they comply with all applicable federal, state, and local laws and regulations.

Therefore, the incident response strategy must be written and tested by the CSIRT.

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Answer:

The answer is "disagree"

Explanation:

The system analyst is responsible, who uses research and methods of solving industrial problems with IT. He or she may act as representatives of change that identify, that process improvements needed design systems for such improvements, or inspire us to use systems.

Answer:

b. SIEM.

Explanation:

In this scenario, an organization is struggling to differentiate threats from normal traffic and access to systems. A security engineer has been asked to recommend a system that will aggregate data and provide metrics that will assist in identifying malicious actors or other anomalous activity throughout the environment. The solution the engineer should recommend is the Security information and event management (SIEM).

Security information and event management is an enterprise software that provides a holistic view and analyzes activity from various resources across an entire information technology (IT) infrastructure.

The SIEM is used to aggregate important data from multiple source such as servers, routers, firewall, switches, domain controllers, antivirus software and analyzes the data to detect any threat, deviation from the norm, as well as investigate in order to take appropriate actions. Some examples of the SIEM system are IBM QRadar, Splunk, LogRhythm etc.

Answer:

1. Yes

2. No

Explanation:

1 Note that the term BIOS (Basic input and Output System) refers to instructions that controls a computer device operations. Thus, devices that shows up in BIOS should be in device manager.

2. Not all devices listed in devcie manager of a computer system will be listed in BIOS.

Answer:

Image processing operations implemented with filtering include smoothing, sharpening, and edge enhancement.