Answer:
Hey there!
-6 ft is 6 ft below sea level.
Hope this helps :)
What is the quotient of the synthetic division problem below, written in
polynomial form?
________
-3 | 1 6 10 3
Answer:
c) x² + 3x + 1
Step-by-step explanation:
-3 / 1 6 10 3
-3 -9 -3
1 3 1 0
Answer: x² + 3x + 1
Step 1: Carry down the first number 1 as it is
Step 2: Multiply 1 by -3 (1 * -3 = -3) and write this -3 under the next number 6 and then add. 6 + (-3) = 3
Step 3: Multiply this 3 by -3 (3 * -3 = -9) and write this -9 under the next number 10 and then add.10 +[-9] = 1
Step 4: Multiply 1 by -3 (1 * -3 = -3) and write this -3 under the next number 3 and then add. -3 +[-3] = 0
What is the function rule represented by the following table? x y 0 0 1 -2 -2 4 y = -x - 1 y = -2x y = x - 3 y = -3x + 2
Answer:
[tex]y = -2x[/tex]
Step-by-step explanation:
Given
x || 0 || 1 || -2
y || 0 || -2 || 4
Required
Determine the function rule
First, we have to determine the slope of the function using;
[tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]
Where x and y represent any two corresponding values of x and y
When x = 0; y = 0 [tex](x_1,y_1)[/tex]
When x = 1; y = -2 [tex](x_2,y_2)[/tex]
Substitute these values in [tex]m = \frac{y_1 - y_2}{x_1 - x_2}[/tex]
[tex]m = \frac{0 - (-2)}{0 - 1}[/tex]
[tex]m = \frac{0 +2}{0 - 1}[/tex]
[tex]m = \frac{2}{- 1}[/tex]
[tex]m = -2[/tex]
Next, is to determine the function rule; using slope intercept form as follows;
[tex]y - y_1 = m(x - x_1)[/tex]
Take any corresponding values of x and y as x1 and x2
When x = -2; y = 4
[tex]y - y_1 = m(x - x_1)[/tex] becomes
[tex]y - 4 = -2(x - (-2))[/tex]
[tex]y - 4 = -2(x + 2)[/tex]
Open the bracket
[tex]y - 4 = -2x -4[/tex]
Add 4 to both sides
[tex]y - 4 + 4 = -2x - 4 + 4[/tex]
[tex]y = -2x[/tex]
Hence, the function rule is [tex]y = -2x[/tex]
Answer:
y = -2 x - 1
Step-by-step explanation:
Question 8 Multiple Choice Worth 1 points)
(03.08 MC)
Two different plants that grow each month at different rates are represented by the functions f(x) and g(x). In what month does the height of the
f(x) plant exceed that of the g(x) plant?
Month (x) f(x) = 3* g(x) = 5x + 12
1
3
17
2.
9
22
O Month 3
O Month 4
O Month 5
O Month 6
Answer:
Option B.
Step-by-step explanation:
Note: The function f(x) is not in correct format it must be [tex]f(x)=3^x[/tex].
It is given that two different plants that grow each month at different rates are represented by the functions f(x) and g(x).
Let as consider the two functions,
[tex]f(x)=3^x[/tex]
[tex]g(x)=5x+12[/tex]
Now, table of values is
Month(x) [tex]f(x)=3^x[/tex] [tex]g(x)=5x+12[/tex]
1 3 17
2 9 22
3 27 27
4 81 32
From the above table it is clear that in first and second month the height of the f(x) plant is less than of g(x).
In month 3, heights are equal.
In month 4, height of the f(x) plant exceed that of the g(x) plant.
Therefore, the correct option is B.
Jenny has nine marbles, but her best friend Susie gives her ten more! However, the neighborhood bully, Danny, steals four marbles from her. Jenny's marbles are all of very high quality, so she trades each of her marbles for three of John's marbles apiece. The very next day is Jenny's birthday so she receives seven marbles from her parents, and finally gives two to her sister. How many marbles does she have now?
Answer:
Jenny has 50 marbles
Step-by-step explanation:
I find it easiest to right down the numbers as I read the question,
(9+10-4) x3 +7-2
Alice is building a caterpillar habitat for some caterpillars she found in her back yard. She plans to cover all sides of the habitat with screen so the caterpillars get plenty of fresh air. What is the total amount of screen that Alice will need for her habitat? Give an exact answer (do not round).
Answer:
SA = 3.04m²
Step-by-step explanation:
SA = 2 x ( Length x Width + Width x Height + Length x Height )
SA = 2 x ( 0.4 x 1 + 0.4 x 0.8 + 1 x 0.8 )
SA = 2 x ( 0.4 + 0.32 +0.8)
SA = 2 x 1.52
SA = 3.04 m²
I wish this could help you !
Answer:
3.04 is the correct answer =)
Step-by-step explanation:
How many different 2-digit numbers are there with the following property: the tenth digit is greater than the units digit?
Step-by-step explanation:
2 digit numbers are beetween 10 and 99
We are looking for numbers in wich the unit digits is less than the ten digit
we can make notice something about this numbers
1020304050607080900 is the smallest postive integer so all these numbers satisfy the condition
so we have now 9 numbers
here is another remark :
0 < 1 < 2 < 3 <4 <5 <6 < 7 < 8 < 9numbers from 91 to 99 satisfy the condition except 99
so here are 8 other numbers
numbers from 80 to 89 satisfy the condition except 88 and 89
so here are 7 other numbers
the numbers that satisfy the keeps decreasing by 1 each time
8 (91⇒98) 7 81⇒88 + 806 71⇒76 + 705 61⇒ 65 +604 51⇒ 54 + 50 3 41⇒ 43 + 402 31⇒32 + 301 21 + 20so the total number of numbers that satisfy the condition
9+8+7+6+5+4+3+2+1= 45
Katrina owns a dance studio and offers four classes a day for $28.00 each, with 10 people maximum per class. If she decides to offer a 25% discount on the two morning classes offered one day, and all four classes reach the maximum number of people attending, how much money will Katrina make that day?
Answer:
$980
Nvm you have to multiply 98 by 10 since there are 10 participants. :)
Step-by-step explanation:
Well, first we wanted to find how much the morning classes cost together. You have to $28 multiplied with 75/100. I am multiplying it with 75/100 instead of 25/100 because the discount cuts off the 25% and the 75% is what you still have to pay. This will give you 2100/100 which is $21. Now you have to multiply $21 with 2 since there are two morning classes. $21 x 2 equals $42. Total for Morning Classes is $42.
Now the other two classes don't have a discount. So all you have to do is $28 x 2 or $28 + $28. This gives you $56. Total for The Other Classes is $56.
Last Step:
Total for Morning Classes + Total for the Other Classes = $56 + $42
= $98
Hope that helped! :)
Answer:
$ 980
Step-by-step explanation:
Discount for morning session = 25 % of 28 = 0.25 * 28 = $ 7
Fees for morning class = 28 - 7 = $ 21
Maximum people in one session = 10
Money earned in the morning sessions = 2 * 21 * 10 = $ 420
Money earned in the evening sessions = 2 * 28 * 10 = $ 560
Total money earned that day = 420 + 560 = $ 980
Identify the coefficient of 12b5.
Given the value [tex]12b^{5}[/tex] ; the coefficient of b is 12.
The Coefficient is a numerical value or constant which is used to multiply a variable; from the value given above ;
The variable is b ;
The Coefficient = 12 ; the coefficient is the value which is used fo multiply the variable b.
The power is the value to which the variable is raised.
Hence,
The Coefficient is 12 ; it is the value which multiplies the variable 'b' and the power is 5
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Graph the line with: a slope of -5 and y intercept of 4. PLEASE HELP
The y intercept of 4 means the graph crosses the vertical y axis at 4. More specifically this location is (0,4)
Start at (0,4) and move down 5 units and then move to the right 1 unit. You should arrive at (1,-1). The movement rule of "down 5, over to the right 1" is taken exactly from the slope of -5 = -5/1.
After plotting the two points (0,4) and (1,-1), draw a straight line through them both. Extend this line as far as you can in either direction. The graph is now completed.
In summary, this line goes through (0,4) and (1,-1)Side note: The equation of this line is y = -5x+4. It is in slope intercept form.
The graph of the linear equation y = -5x + 4 is in the image at the end.
How to graph the linear equation?Here we want to do the graph of a line where the slope is -5 and the y-intercept is 4.
Then we can write the line as:
y = -5x + 4
To graph the line, we need to find two points on the line, to find these points just evaluate the function in two values.
if x = 0
y = -5*0 + 4
y = 4 ---> we have the point (0, 4)
if x = 1
y = -5*1 + 4 = -1 ---> we have the point (1, -1)
Now graph these two points and connect them with a line, you will get a graph like the one below.
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If you're good at bearings please help me
A plane, P, takes off from an airport, A, at 10:15 a, and flies on a bearing S30E at a speed of 700 km/h
Question one
How far due south of the airport, A, is the plane at 1:45 pm?
Question two
What's the compass bearing of the airport from the plane then?
Answer:
Question one
2121.76 km
Question two
(N30°E)
Step-by-step explanation:
The given information are;
The time the plane takes off = 10:15 a.m.
The direction of flight of the plane = S30E
The speed of flight of the plane = 700 km/h
Question one
The of flight at 1:45 p.m. - 10:15 a.m = 3.5 hours
The distance traveled South by the plane is the product of the y-component of the velocity and the time of travel of the plane
The y-component of the velocity = v×cos(θ) = 700 × cos(30) = 350·√3 km/h
The distance traveled = 350·√3 km/h × 3.5 = 2121.76 km
Question two
The compass bearing of the airport the plane is North 30° West (N30°E).
FIRST GET BRAINNLEST Noam spins the spinner below 1000 times. Predict how many times the spinner landed on red.
Answer:
1/4
Step-by-step explanation:
Given:
Colors
Yellow 1
Red 1
Blue 2
Total 4
Required:
Times that the spinner landed on red=?
Formula:
Probability=Successful outcome ÷ Possible outcome.
Solution:
Probability=Successful outcome ÷ Possible outcome
Probability=1÷4
Probability=1/4
Hope this helps ;) ❤❤❤
Answer:
about 125 times
Step-by-step explanation:
Suppose you deposit a principal amount of p dollars in a bank account that pays
compound interest. If the annual interest rate r (expressed as a decimal) and the bank
makes interest payments n times every year, the amount of money A you would have
after t years is given by:
A = P[1+ (r/n)]"
Find the account balance after 20 years if you started with a deposit of $1000, and the
bank was paying 4% interest compounded quarterly (4 times a year). Round your
answer to the nearest cent.
Answer:
Answer:
$2216.72
Step-by-step explanation:
Simply plug in your known variables into the formula:
a = 1000
r = 0.04 (4%)
n = 4
t = 20
A = 1000(1 + 0.04/4)⁴⁽²⁰⁾
A = 1000(1 + 0.01)⁸⁰
A = 1000(1.01)⁸⁰
A = 1000(2.21672)
A = 2216.72
Andrew is about to leave for school. if he walks at the speed of 50 meters per minute he will arrive 3 minutes after the bell rings. if he runs at the speed of 80 meters per minute he will arrive 3 minutes before the bell rings. in how many minutes will the bell ring?
================================================
Explanation:
x = time it takes for the bell to ring, time is in minutes
d = distance from his house to the school, in meters
distance = rate*time
If Andrew walks at a speed of 50 meters per minute, then he'll be 3 minutes late. This means he took x+3 minutes to get to class. The x represents the amount of time it takes if he arrived on time, then the +3 is those 3 minutes he is late. We then write
d = 50(x+3)
d = 50x+150
If he runs to school, then he's 3 minutes early. So he took (x-3) minutes to get to class. His rate is 80 meters per minute
d = 80(x-3)
d = 80x-240
We're referring to the same distance (d) value, which allows us to perform substitution to solve the two equations we formed
80x-240 = 50x+150
80x-50x = 150+240
30x = 390
x = 390/30
x = 13
Andrew has 13 minutes to get to class.
-------------------
Checking the answer:
If he walks at a speed of 50 m per minute, then he'll be 3 minutes late. So he really took 13+3 = 16 minutes to arrive. His distance traveled is d = r*t = 50*16 = 800 meters.
If he ran 80 m per minute, and is 3 minutes early, then he took 13-3 = 10 minutes to get to class. His distance is the same as before d = r*t = 80*10 = 800 meters. The fact we get 800 both times helps confirm we have the right answer.
Andrew has 13 minutes to get to class.
What is Algebra?Algebra is the part of mathematics that helps represent problems or situations in the form of mathematical expressions.
In algebra, we use numbers like 2, −7, 0.068 etc., which have a definite or fixed value. In algebra we use variables like x, y, and z along with numbers.
Now, let x be the time it takes for the bell to ring.
let d be the distance from his house to the school, in meters
distance = speed*time
If Andrew walks at a speed of 50 meters per minute, then he'll be 3 minutes late.
So, Andrew took x+3 minutes to get to class.
Here in the expression +3 shows that she is late.
So,
d = 50(x+3)
d = 50x+150
Now, If he runs to school, then he reached 3 minutes early.
So, toe get in class he will take (x-3) minutes
Here -3 show the child reached early
d = 80(x-3)
d = 80x-240
Since the distance is same.
So, the two equations are equal.
80x-240 = 50x+150
80x-50x = 150+240
30x = 390
x = 390/30
x = 13
Hence, Andrew has 13 minutes to get to class.
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Are the arcs below congruent?
A. No, because the ares do not have the same measure.
B. There is not enough information to determine.
C. No because the ares are not oriented the same
D. Yes because the ares have the same measure.
Answer:
A
Step-by-step explanation:
Answer:
B
You do not have enough information to solve the question.
HLP ! HLP ! Please and thank you
Answer:
Yes, it is an exponential function. The base is 2.
Step-by-step explanation:
As you can see, the function is f(x) = 2^(2x).
Since there is an exponent, the function is exponential. Graphing functions is another way to make sure if it's exponential or not.
The base is 2 because 2x, the exponent, is applied to it.
---
I hope this helps, let me know if you have any questions.
8 elementary classes will be chosen to participate in a school lunch survey. There are 23 elementary classes in the school. In how many ways can the classes be chosen?
Answer:
490,314
Step-by-step explanation:
This is a combinations problem. The formula is n!/(n-r)!xr!
This is 23!/(23-8)!x8!=
23!/15!x8!=
19,769,460,480/40,320=
490,314
Using the combination formula, it is found that the classes can be chosen in 490,314 ways.
The order in which the classes are chosen is not important, hence the combination formula is used to solve this question.
What is the combination formula?[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by:
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this problem, 8 classes are chosen from a set of 23, hence:
[tex]C_{23,8} = \frac{23!}{8!(15)!} = 490314[/tex]
The classes can be chosen in 490,314 ways.
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help me pls
Tell whether lines m and n must be parallel from the given
Information. If they are, state your reasoning.
Answer:
The first one isn't the second one is.
Step-by-step explanation:
In the first one, they have to be equal because they're corresponding angles so m and n are parallel.
In the second one, m<2 and m<3 would be supplementary and add up to 180 degrees if the lines were parallel and since they don't add up to 180, the lines are not parallel.
Using the ruler postulate, find the distance between-9 and 2.
Answer:
11
Step-by-step explanation:
SOMEONE PLS HELP PRECALCULUS
Sine is negative in quadrants 3 and 4, when y < 0.
Tangent is negative for quadrants 2 and 4, when y/x < 0. Basically when x and y differ in sign (one is positive, the other is negative)
The common quadrant mentioned is quadrant 4.
Quadrant 4 has angles that are between 270 degrees and 360 degrees
So we have [tex]270^{\circ} < \theta < 360^{\circ}[/tex]
Answer: Choice DWhat is the measure of Angle X W Y? Triangle X W Y. The exterior angle to angle W is 74 degrees. 16 degrees 74 degrees 106 degrees 116 degrees
The exterior of angle XWY is 74 degrees, so the angle XWY itself is 180-74 = 106 degrees. The two angles form a 180 degree straight line or angle.
Answer:
the answer is 74
Step-by-step explanation:
i did the cumulative test
EXPERTS ONLY its not 0 or 128 In how many ways can you put seven marbles in different colors into four jars? Note that the jars may be empty.
Answer: 16384
Step-by-step explanation:
Given, Total jars = 4
Total marbles = 7
Since we need to put marbles in 4 different jars, we need to choose a jar each time.
Possible choices for jars =4
Number of time we need to choose = number of marbles
So, by fundamental counting principle, we have
Total ways to put 7 marbles in 4 jars = [tex]4\times4\times 4\times 4\times4\times 4\times 4[/tex]
[tex]=4^7\\\\=16384[/tex]
Hence, the required number of ways =16384
Write the following decimals as fractions.
Answer:
5a. 0.2823 = 2823/10000 5b. 0.5474 = 2737/5000
6a. 0.3484 = 871/2500 6b. 0.5 = 1/2
7a. 0.11 = 1/9 7b. 0.1224 = 153/1250
urgent!! - What is the perimeter of a parallelogram, if it's area is 36 cm2 and the distances between the point of intersection of the diagonals and the sides are 2 cm and 3 cm?
Answer:
30 cm
Step-by-step explanation:
The distance from the intersection of the diagonals (center of the parallelogram) to one side is half the height when that side is considered the base.
So, if the height is 2×(2 cm) = 4 cm, and the area is 36 cm², the base for that height must be ...
(36 cm²)/(4 cm) = 9 cm.
Similarly, if the height is 2×(3 cm) = 6 cm, the base for that height is ...
(36 cm²)/(6 cm) = 6 cm.
These "bases" are the side lengths of the parallelogram, so its perimeter is ...
P = 2(s1 +s2) = 2(9 cm +6 cm) = 30 cm
The perimeter of the parallelogram is 30 cm.
(b) Graph the equation x – 2y = 3
Answer:
Hey there!
Look at the image below ↓
Hope this helps :)
The graph of the given equation x – 2y = 3 is attached below.
How to find the function which was used to make graph?A graph contains data of which input maps to which output.
Analysis of this leads to the relations which were used to make it. If we know that the function crosses x axis at some point, then for some polynomial functions, we have those as roots of the polynomial.
We are given that the equation as;
x – 2y = 3
Therefore, it can be write as;
-2y = -x + 3
-y = -x/2 + 3
Here the slope is -1/2.
Hence, the graph of the given equation x – 2y = 3 is attached below.
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Find the mean of the data in the bar chart below.
puppets
Puppets made by each puppeteer
5
Number of puppets
0
Alex
Kalin
Bruce
Davi
Puppeteer
Just look at the picture
Answer:
2.5
Step-by-step explanation:
the mean, better known as the average, can be found by finding the sum of all numerical data and dividing by the amount of your data. so 1+4+3+2=10 and 10 divided by 4=2.5
Answer:
2.5
Step-by-step explanation:
Which congruence theorems can be used to prove ΔEFG ≅ ΔJHG? Select two options.
Triangles E F G and J H G are connected at point G. Sides F G and and G H are congruent. Sides E F and H J are parallel.
HL
SAS
SSS
ASA
AAS
ASA and AAS
Step-by-step explanation:
We do not know if these are right triangles; therefore we cannot use HL to prove congruence.
We do not have 2 or 3 sides marked congruent; therefore we cannot use SSS or SAS to prove congruence.
We are given that EF is parallel to HJ. This makes EJ a transversal. This also means that ∠HJG and ∠GEF are alternate interior angles and are therefore congruent. We also know that ∠EGF and ∠HGJ are vertical angles and are congruent. This gives us two angles and a non-included side, which is the AAS congruence theorem.
Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate interior angles and are congruent. Again we have that ∠EGF and ∠HGJ are vertical angles and are congruent; this gives us two angles and an included side, which is the ASA congruence theorem.
The congruence theorems that can be used to prove ΔEFG ≅ ΔJHG are; ASA and AAS
It is impossible to know if these are right triangles from the information given;
On this note, only one side of each triangle is marked congruent;
Hence, we are unable use SSS or SAS to affirm congruence.
Additionally, since EF is parallel to HJ. Therefore, line EJ is a transversal. This also means that ∠HJG and ∠GEF are alternate (z-angles) interior angles and are therefore congruent. Similarly, ∠EGF and ∠HGJ are vertical angles and are congruent. We have therefore established the AAS congruence theorem.Since EF and HJ are parallel and EJ is a transversal, ∠JHG and ∠EFG are alternate (z-angles) interior angles and are congruent. Similarly, ∠EGF and ∠HGJ are vertical angles and are congruent; This gives us two angles and an included side, which is the ASA congruence theorem.Read more on congruence theorems:
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5. a) A business company made a profit of Rs 24,00,000 in the last year. The management decided to distribute 20 % bonus from the profit to its 30 employees.
( i ) Find the bonus amount received by each employee.
(ii) By what percent should the bonus be increased so that each employee can receive Rs 20,000?
(iii) What should be the profit of the company so that it can provide Rs 20,000 to each employee at 20 % bonus?
Answer:
a) = Rs 16000
b) = 5%
c) = Rs 30,000,000
10% = 24,000,00/10 = Rs 240,000
20% = 240,000 x 2 = Rs 480,000
480,000/30 = Rs 16000
b) The bonus percentage needs to be increased by 5%
explanation:
Since every worker needs Rs 20000 we need to times it by 30
20000 x 30 = Rs 600,000
600,000 - 480,000 = Rs 120,000
Now we need to find the percentage of Rs 120,000
10% = Rs 240,000
5% = 240,000 divide by 2 = Rs 120,000
This is the best I can do for now please let me know if you understood the answer!
Answer:
1.Rs.16000
2.Bonus rate:25%
3.profit:Rs.3000000
Step-by-step explanation:
Case 1
Profit=Rs.2400000
Bonus Rate:20%
No.of employees =30
Now,
Bonus = (Bonus Rate of Profit) / no. Of employees
= 20% of Rs.2400000 / 30
= Rs. 16000
Case 2
Bonus=Rs.20000
Profit=Rs.2400000
Bonus rate=?
Now,
Bonus=bonus rate of profit / no. Of employees
Or,Rs. 20000 = Bonus rate × Rs. 2400000/30
Or, Rs. 20000=Bonus rate × Rs. 80000
Or,Rs.20000/Rs.80000 = Bonus rate
Bonus rate = 1/4=25%
Case 3
Bonus=Rs.20000
Bonus Rate = 20%
Now,
Bonus = bonus Rate of profit / no.of employees
Or, Rs. 20000 = 20% × Profit / 30
Or, Rs. 20000 × 30 / 0.2 = profit
Profit= Rs. 3000000
I hope it helped you
To solve the equation w/8 - 4 = 20, you would first add 4 to each side and then divide each side by 8. TrueFalse
Answer:
False
Step-by-step explanation:
The first part is correct because adding 4 to each side will help isolate the variable w, but since w is divided by 8 already you would want to multiply by 8 instead, so dividing each side by 8 would not work.
Suppose the function ƒ(t) = et describes the growth of a colony of bacteria, where t is hours. Find the number of bacteria present at 5 hours. Question 11 options: A) 79.432 B) 8.155 C) 59.598 D) 148.413
Answer:
The number of bacteria present at 5 hours is 148.413
Step-by-step explanation:
Function: [tex]f(t)=e^t[/tex]
This function describes the growth of a colony of bacteria, where t is hours.
We are supposed to find the number of bacteria present at 5 hours.
So, Substitute t = 5
So, the number of bacteria present at 5 hours =[tex]e^5[/tex]
The number of bacteria present at 5 hours = 148.413
So, Option D is true
Hence the number of bacteria present at 5 hours is 148.413
ordered pair please help
Answer:
PLS PLS DO MARK MY ANSWER AS THE BRAINLIEST......
Step-by-step explanation:
P - ( 2, -3) - 4TH QUADRANT
Q - (-3,-2) - 3RD QUADRANT
R - (1,3) - 1ST QUADRANT
S -(-2,2) - 2ND QUADRANT
Answer:
P - ( 2, -3) - 4TH QUADRANT
Q - (-3,-2) - 3RD QUADRANT
R - (1,3) - 1ST QUADRANT
S -(-2,2) - 2ND QUADRANT