Answer:
A. 6 feetStep-by-step explanation:
[tex]A=\pi r^2\\Area = 36\pi\\r = ?\\36\pi = \pi r^2\\Divide \:both \:sides \:of\: the \:equation\: by\: \pi\\\frac{36\pi}{\pi} = \frac{\pi r^2}{\pi} \\r^2 = 36\\Find\: the\: square\: root\: of\: both\: sides\: \\\sqrt{r^2} =\sqrt{36} \\\\r = 6\: feet\\[/tex]
Help please!! Thank you
Answer:
D. 6
Step-by-step explanation:
here, as given set Q consists { 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36}
and set Z contains {3, 6, 9, 12, 15, 18, 21,24, 27, 30, 33, 36, .... }
so be comparing both, we can see that the numbers 6, 12, 18, 24, 30 and 36 is repeated.
can i please get help with this
Step-by-step explanation:
Intersecting secant angles theorem: The angle between two secants is half the difference of the intersected arcs.
52 = ½ (x − 38)
x = 142
Arc angles add up to 360.
360 = 80 + 38 + z + x
z = 100
Tangent-chord theorem: The angle between a tangent and a chord is half the intercepted arc angle.
y = x/2
y = 71
Use arrow notation to describe the translation of point PC-9, 5) to point P4-6, 7).
A (x,y) → (x - 3,7 - 2)
B (x,y) → (x + 3y - 2)
C (x,y) → (x + 3y + 2)
D (x,y) → (x - 3y + 2)
In a survey, 24 people were asked how much they spent on their child's last birthday gift. The results were roughly bell-shaped with a mean of $31 and standard deviation of $6. Construct a confidence interval at a 80% confidence level.
Answer:
29.4≤μ≤32.6
Step-by-step explanation:
The datas given from the questions are as shown:
Number of people n = 24
Mean xbar= $31
Standard deviation σ = $6
Confidence Interval formula is expressed as:
CI = xbar ± Z(σ/√n)
Z value for 80% confidence interval is 1.282
Substituting the values into the Confidence Interval formula will give;
CI = 31 ± 1.282{6/√24}
CI = 31 ± 1.282(1.225)
CI = 31 ± 1.57045
CI = 31+1.57045 and 31-1.57045
CI = (29.42955, 32.57045)
CI = (29.4, 32.6) to 1dp
The confidence interval will be within the range 29.4≤μ≤32.6
4 1/2 +1 3/5 (in the simplest form)
6 1/10
Step-by-step explanation:
4 + 1/2+1+3/5
5+1+1/10=6 1/10
Does the median represent the center of the data? A. The median represents the center. B. The median does not represent the center because it is the smallest data value. C. The median does not represent the center because it is the largest data value. D. The median does not represent the center because it is not a data value. E. There is no median age
Answer:
A. The median represents the center.
Step-by-step explanation:
In statistics and probability theory, the median value is the middle value or center value in a group of data values or numbers. To find the median, the values have to be placed in value order, from smallest to largest. The center number would be the median. The number lies between the higher half and the lower half. Therefore the median represents the center of the data values.
What is the greatest prime you must consider to test whether 7066 is prime?
Answer:
Step-by-step explanation:
The square root of 7066 is 84.0595....
Therefore the largest number we must test is 84, seeing as now we have proven we do not need to test any numbers greater than 84.0595...
That means, we only need to test prime numbers smaller than 84 to see if they go into 7066.
84 isn't prime. But 83 is prime.
Therefore, the greatest prime that needs to be considered for divisibility is 83.
Answer:
The numbers 7066 is not prime .
But we easily know when a number is prime when we divide it by the first prime numbers; 2, 3, 5, 7, 11.
Step-by-step explanation:
It is known with certainty that a number is prime when it is only divisible by and by unity.
But in this case, that number, when divided by other numbers less than the one, shows that when dividing into the remainder, it gives zero, which means that it is not only divisible by itself or by the unit, but also by other numbers.
for example; 7066/2=3533 , the remainder is zero;
determining probability of events. please help!
A necklace was on sale for 20% discount off the original price of
$1250.00. What was the final sale price if 12.5% VAT has to be
paid?
Answer:
= $ [tex] \mathsf{1125}[/tex]Step-by-step explanation:
[tex] \mathrm{Given}[/tex],
[tex] \mathrm{Discount\% = 20\%}[/tex]
[tex] \mathrm{Marked \: price = 1250}[/tex]
[tex] \mathrm{Now \: let's \: find \: the \: discount \: amount}[/tex]
[tex] \mathrm{discount \: amount = dis\% \: of \: MP}[/tex]
[tex] \mathrm { = 20\% \: of \: 1250}[/tex]
[tex] \mathrm{ = 250}[/tex]
[tex] \mathrm{let's \: find \: the \: selling \: price}[/tex]
[tex] \mathrm{ = MP \: - \: discount \: amount}[/tex]
[tex] \mathrm{ = 1250 - 250}[/tex]
= $ [tex] \mathrm{1000}[/tex]
[tex] \mathrm{lets \: find \: the \: Vat \: amount}[/tex]
[tex] \mathrm{vat \: amount = vat\% \: of \: sp}[/tex]
[tex] \mathrm{ = 12.5\% \: of \: 1000}[/tex]
= $ [tex] \mathrm{ 125}[/tex]
[tex] \mathrm{Now \: finally \: let's \: find \: the \: selling \: price \: with \: vat}[/tex]
[tex] \mathrm{selling \: price \: + \: vat \: amount}[/tex]
[tex] \mathrm{ = 1000 + 125}[/tex]
= $ [tex] \mathrm{1125}[/tex]
Therefore, The final sale of the necklace is $ 1125
Hope I helped
Best regards!
plzz help brainliest thanks and 20 points Look at the cups shown below (images are not drawn to scale): A cone is shown with width 2 inches and height 3 inches, and a cylinder is shown with width 2 inches and height 7 inches. How many more cubic inches of juice will cup B hold than cup A when both are completely full? Round your answer to the nearest tenth. 18.8 cubic inches 21.9 cubic inches 25.1 cubic inches 32.6 cubic inches
Answer:
18.8 cubic inches
Step-by-step explanation:
1. Solve for the volume of Cup A. (volume of a cone = 1/3πr² · h)
1/3 · 3.14 · 1² · 3 = 3.14 in³
2. Solve for the volume of Cup B (volume of a cylinder = πr² · h)
3.14 · 1² · 7 = 21.98 in³
3. Subtract the volume of Cup A from Cup B
21.98 - 3.14 = 18.84
4. Round 18.84 to the nearest tenth
18.84 → 18.8 in.³
Answer:
18 .8
Step-by-step explanation:
got it right on test
A backpacking company requires each camper to bring a lantern to go on a trip. The company supplies 4 extra in case any lanterns get lost or broken. If 13 campers go on the trip, how many lanterns will they bring?
Answer:
17 lanterns.
Step-by-step explanation:
There are 13 campers with one lantern each, so that will be 13 * 1 = 13 lanterns.
The company supplies 4 extra lanterns for the whole group.
So, they will bring 13 + 4 = 17 lanterns.
Hope this helps!
Identify an equation in point-slope form for the line perpendicular to
y= - 1/3x - 6 that passes through (-1,5).
O A. y + 1 = 3(x - 5)
O B. y + 5 = 1/3(x - 1)
O C. y - 5 = 3(x + 1)
O D. y - 5 = - 1/3(x + 1)
Answer:
hope you get it....sorry for any mistake calculations
Tessa solves the equation below by first squaring both sides of the equation HELP PLEASE
Answer:
-7Step-by-step explanation:
[tex] \sqrt{ {x}^{2} - 3x - 6} = x - 1[/tex]
Squaring on both sides:
[tex] {x}^{2} - 3x - 6 = {(x - 1)}^{2} [/tex]
Use the formula:[tex] {(a - b)}^{2} = {a}^{2} - 2ab + {b}^{2} [/tex]
[tex] {x}^{2} - 3x - 6 = {x}^{2} - 2x + 1[/tex]
Combine like terms.
[tex] {x}^{2} - {x}^{2} - 3x + 2x = 1 + 6[/tex]
[tex] - 3x + 2x = 7[/tex]
Calculate
[tex] - x = 7[/tex]
[tex]x = - 7[/tex]
Hope this helps...
Good luck on your assignment..
Answer:
-7
Step-by-step explanation:
Khan academy
Determine whether the following sampling is dependent or independent. Indicate whether the response variable is qualitative or quantitative. A researcher wishes to compare of and She obtains a random sample of who and determines each Determine whether the following sampling is dependent or independent. A. B. The sampling is independent because an individual selected for one sample does dictate which individual is to be in the second sample. C. The sampling is dependent because an individual selected for one sample does not dictate which individual is to be in the second sample. D. Indicate whether the response variable is qualitative or quantitative. A. The variable is because it . B. The variable is because it . C. The variable is because it . D. The variable is because it .
Answer:
The sampling is dependent because an individual selected for one sample does dictate about which individual to be selected in the second sample.
The variable is qualitative because it classifies the individual.
Step-by-step explanation:
The sample is dependent as the second individual selected in the sample is dependent on the first individual selection. The sample selection is not random and is dictated. The variables selected are qualitative in nature because they identify the quality of response variable which is non numerical in nature.
Find the value of EB
Answer:
31Step-by-step explanation:
Given,
AD = 38
EB = 7x - 4
FC = 6x - 6
Now, we have to find the value of X
[tex]eb \: = \frac{1}{2} (ad \: + fc \: )[/tex] ( Mid segment Theorem )
Plug the values
[tex]7x - 4 = \frac{1}{2} (38 + 6x - 6)[/tex]
Calculate the difference
[tex]7x - 4 = \frac{1}{2} (32 + 6x)[/tex]
Remove the parentheses
[tex]7x - 4 = \frac{32}{2} + \frac{6x}{2} [/tex]
[tex]7x - 4 = 16 + 3x[/tex]
Move variable to L.H.S and change its sign
Similarly, Move constant to R.H.S and change its sign
[tex]7x - 3x = 16 + 4[/tex]
Collect like terms
[tex]4x = 16 + 4[/tex]
Calculate the sum
[tex]4x = 20[/tex]
Divide both sides of the equation by 4
[tex] \frac{4x}{4} = \frac{20}{4} [/tex]
Calculate
[tex]x = 5[/tex]
The value of X is 5
Now, let's find the value of EB
EB = 7x - 4
Plug the value of X
[tex] = 7 \times 5 - 4[/tex]
Calculate the product
[tex] = 35 - 4[/tex]
Calculate the difference
[tex] = 31[/tex]
The value of EB is 31
Hope this helps..
Best regards!!
6th grade math help me, please :)
Answer:
B. 168 students
Step-by-step explanation:
Given that there are a total of 600 students.
28% of the students pack their lunch.
To find:
Total number of students who pack their lunch = ?
Solution:
Percentage of a given number is calculated using the following method.
[tex]y\%[/tex] of a number [tex]x[/tex] is given by:
[tex]x \times \dfrac{y}{100}[/tex]
i.e. multiply the number by percentage to be found and divide by 100.
So, we have to find 28% of 600 here, to find the answer to the question.
[tex]\therefore[/tex] Number of students who pack their lunch is given as: (Multiply the given number 600 with 28 and divide by 100.)
[tex]600 \times \dfrac{28}{100}\\\Rightarrow 6 \times 28\\\Rightarrow \bold{168}[/tex]
So, the correct answer is:
B. 168
Hi any help is appreciated. Just wanna graduate:))
Answer: C
Step-by-step explanation:
h · k(x) = 2(3x - 5)(-2x + 1)
= (6x - 10)(-2x + 1)
= -12x² + 6x + 20x - 10
= -12x² + 26x - 10
Answer:
C
Step-by-step explanation:
h(x) × k(x)
= 2(3x - 5)(- 2x + 1) ← expand factors using FOIL
= 2(- 6x² + 3x + 10x - 5)
= 2(- 6x² + 13x - 5) ← distribute parenthesis by 2
= - 12x² + 26x - 10 → C
Add the following polynomials, then place the answer in the proper location on the grid.
2x3 - 4x2 + 6x - 3
29 +6x2 - 8x + 12
- 3x3 + 2x2 - 4x - 7
Help ????????
Answer:
[tex] x^3 - 6x + 2 [/tex]
Step-by-step explanation:
The given polynomials can be added together by adding like terms together as shown below:
=> Add together, the coefficient of all terms that have the power of 3.
[tex] (2x^3) + (x^3) + (-3x^3) [/tex]
[tex] 2x^3 + x^3 - 3x^3 [/tex]
[tex] 3x^3 - 3x^3 [/tex]
[tex] x^3 [/tex]
=> [tex] (-4x^2) + (6x^2) + (2x^2) [/tex]
[tex] -4x^2 + 8x^2 [/tex]
[tex] 4x^2 [/tex]
=> [tex] (6x) + (-8x) + (-4x) [/tex]
[tex] 6x - 8x - 4x [/tex]
[tex] -6x [/tex]
=> [tex] (-3) + (12) +(-7) [/tex]
[tex] -3 + 12 - 7 [/tex]
[tex] 2 [/tex]
The answer = [tex] x^3 - 6x + 2 [/tex]
Answer:
4x^2-6x+2
Step-by-step explanation:
Find exact value of cos
Work Shown:
[tex]\sin^2 \theta + \cos^2 \theta = 1\\\\\left(\frac{3}{10}\right)^2 + \cos^2 \theta = 1\\\\\frac{9}{100} + \cos^2 \theta = 1\\\\\cos^2 \theta = 1 - \frac{9}{100}\\\\\cos^2 \theta = \frac{100}{100}-\frac{9}{100}\\\\\cos^2 \theta = \frac{91}{100}\\\\\cos \theta = \sqrt{\frac{91}{100}} \ \text{ cosine positive in Q1}\\\\\cos \theta = \frac{\sqrt{91}}{\sqrt{100}}\\\\\cos \theta = \frac{\sqrt{91}}{10}\\\\[/tex]
Answer:
√91/10
Step-by-step explanation:
sin 0.3 is equal to 18(approximate value)
cos18°=0.951
which is √91/10
several years ago ravi invested in some gold gold is currently valued at $2737 per ounce which is 70% more than rafa originally paid for it what was the purchase price of the gold
Answer:
Original price is $1610
Step-by-step explanation:
2737=1.7*Original price
divide each side by 1.7
Original price=1610
Hope this helps!
Find the number c that satisfies the conclusion of the Mean Value Theorem on the given interval. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE.) f(x)
Answer:
2.25
Step-by-step explanation:
The computation of the number c that satisfied is shown below:
Given that
[tex]f(x) = \sqrt{x}[/tex]
Interval = (0,9)
According to the Rolle's mean value theorem,
If f(x) is continuous in {a,b) and it is distinct also
And, f(a) ≠ f(b) so its existance should be at least one value
i.e
[tex]f^i(c) = \frac{f(b) - f(a)}{b -a }[/tex]
After this,
[tex]f(x) = \sqrt{x} \\\\ f^i(x) = \frac{1}{2}x ^{\frac{1}{2} - 1} \\\\ = \frac{1}{2}x ^{\frac{-1}{2}[/tex]
[tex]f^i(x) = \frac{1}{{2}\sqrt{x} } = f^i(c) = \frac{1}{{2}\sqrt{c} } \\\\\a = 0, f (a) = f(o) = \sqrt{0} = 0 \\\\\ b = 9 , f (b) = f(a) = \sqrt{9} = 3\\[/tex]
After this,
Put the values of a and b to the above equation
[tex]f^i(c) = \frac{f(b) - f(a)}{b - a} \\\\ \frac{1}{{2}\sqrt{c} } = \frac{3 -0}{9-0} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{3}{9} \\\\ \frac{1}{\sqrt[2]{c} } = \frac{1}{3} \\\\ \sqrt[2]{c} = 3\\\\\sqrt{c} = \frac{3}{2} \\\\ c = \frac{9}{4}[/tex]
= 2.25
The true average diameter of ball bearings of a certain type is supposed to be 0.5 in. A one-sample t test will be carried out to see whether this is the case. What conclusion is appropriate in each of the following situations?
(a) n 15 t 1.66 a 0.05
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(b) n 15 t 1.66 a 0.05
Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(c) n 26, t 2.55 a 0.01
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
(d) n 26, t 3.95
A. Reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
B. Reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
C. Do not reject the null hypothesis. There is not sufficient evidence that the true diameter differs from 0.5 in
D. Do not reject the null hypothesis. There is sufficient evidence that the true diameter differs from 0.5 in
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
C
b
C
c
C
d
A
Step-by-step explanation:
From the question we are told that
The population mean is [tex]\mu = 0.5 \ in[/tex]
Generally the Null hypothesis is [tex]H_o : \mu = 0. 5 \ in[/tex]
The Alternative hypothesis is [tex]H_a : \mu \ne 0.5 \ in[/tex]
Considering the parameter given for part a
The sample size is n = 15
The test statistics is t = 1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = 2.145[/tex]
We are making use of this [tex]t_{\frac{\alpha }{2} }[/tex] because it is a one-tail test
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that [tex]t < t_{\frac{\alpha }{2} }[/tex] so the null hypothesis would not be rejected
Considering the parameter given for part b
The sample size is n = 15
The test statistics is t = -1.66
The level of significance [tex]\alpha = 0.05[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 15- 1[/tex]
[tex]df = 14[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.05 }{2} ,14} = -2.145[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} ,df }[/tex] the we see that t does not lie in the area covered by [tex]t_{\frac{\alpha}{2} , df }[/tex] (i.e the area from -2.145 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part c
The sample size is n = 26
The test statistics is t = -2.55
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = 2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha }{2} }[/tex] the we see that t does not lie in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we fail to reject the null hypothesis
Considering the parameter given for part d
The sample size is n = 26
The test statistics is t = -3.95
The level of significance [tex]\alpha = 0.01[/tex]
The degree of freedom is evaluated as
[tex]df = n- 1[/tex]
[tex]df = 26- 1[/tex]
[tex]df = 25[/tex]
Using the critical value calculator at (social science statistics web site )
[tex]t_{\frac{\alpha}{2} ,df } = t_{\frac{0.01 }{2} ,25} = -2.787[/tex]
Looking at the value of t and [tex]t_{\frac{\alpha}{2} }[/tex] the we see that t lies in the area covered by [tex]t_{\alpha , df }[/tex] (i.e the area from -2.787 downwards on the normal distribution curve ) hence we reject the null hypothesis
6th grade math , help me please :)
Answer:
(a) 3:5
(b) 15
Step-by-step explanation:
Well first we need to create a ratio for the 5 shades squares and 3 non+shaded squares.
It is asking for unshaded first so our ratio will be,
3:5
(a) 3:5
So if there is 9 unshaded how many shaded is there.
Well we can just make the following ratio 9:x
So 9/3 = 3
Meaning 3*5 = 15
So x = 15
(b) 15
Answer:
a) 3/5
b) 15
Step-by-step explanation:
(a)
unshaded: 3
shaded: 5
unshaded to shaded: 3/5
(b)
There are now 3 unshaded squares. You need 9 unshaded squares, so you need to have three times as many total squares as you have now.
Add two more lines just like the given line.
Each new line will have 5 shaded and 3 unshaded squares.
Now you have a total of 9 unshaded and 15 shaded squares.
Leechtown Co. has 4.3% coupon bonds on the market with 18 years left to maturity. The bonds make annual payments. If the bond currently sells for $870, what is its YTM? (Do not round intermediate calculations. Round the final answer to 2 decimal places.) Yield to maturity %
Answer:
YTM = 5.45%
Step-by-step explanation:
Here, we are interested in calculating the yield to maturity.
Mathematically;
Annual coupon=1000*4.3%=43
YTM=[Annual coupon+(Face value-Present value)/time to maturity]/(Face value+Present value)/2
=[43+(1000-870)/18]/(1000+870)2
=5.45%
PLEASE HELP QUICK! Determine x value of: sqrt x + 8 - sqrt x - 4 = 2
Answer:
x=8
Step-by-step explanation:
[tex]\sqrt{x+8}-\sqrt{x-4}=2\\\sqrt{x+8}=2+\sqrt{x-4}\\\left(\sqrt{x+8}\right)^2=\left(2+\sqrt{x-4}\right)^2\\x+8=x+4\sqrt{x-4}\\8=4\sqrt{x-4}\\8^2=\left(4\sqrt{x-4}\right)^2\\64=16x-64\\x=8[/tex]
Quick!!! Urgent!!!!!!!!!
Answer:
my best answer for this is B. False.
I calculated as fast as i can.
Show all work for 135 points (90 points + brainliest = 135 pts)
Answer:
(a) 5/7 chance
(b) 2/7 chance
(c) 5/7 chance
Step-by-step explanation:
Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)
Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)
(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.
(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)
(c) The complement of Event Y is 1-4/7=5/7 chance.
Answer:
a) 5/7 chance
(b) 2/7 chance
(c) 5/7 chance
Step-by-step explanation:
Event X: There are 3 letters that come before "D". A, B, and C. There is a 3 out of 7 chance of picking one of those letters. (3/7)
Event Y: There are 4 letters in "C A G E". Those 4 letters are in the 7 first letters of the alphabet meaning that they are in our pile of tiles. There is a 4 out of 7 chance of picking one of those letters. (4/7)
(a) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 5/7 chance of either Event X or Event Y happening since tiles "A" and "C" are included in both events.
(b) Since there is a 3/7 chance of Event X happening and a 4/7 chance of Event Y happening, there is a 2/7 chance of both X and Y happening since there are only 2 tiles that are the same in both events, "A" and "C". (We are only allowed to pick one tile)
(c) The complement of Event Y is 1-4/7=5/7 chance.
A group of children is trying to share a pile of stickers. If every
child gets two stickers, there will be 7 stickers left over. If two
children do not get any stickers, then each of the remaining
children will get exactly 3 stickers.
How many children are in the group?
Answer:
7 children
Step-by-step explanation:
Answer:
7 children is the correct answer
and you follow me if you can't I will unfollow you
Solving exponential functions
Answer:
Option B
an increasing exponential graph
*4.8.21
Question Help
O
After the release of radioactive material into the atmosphere from a nuclear power plant in a country in 2000, the hay in that country was contaminated by a radioactive
isotope (half-life 7 days). If it is safe to feed the hay to cows when 14% of the radioactive isotope remains, how long did the farmers need to wait to use this hay?
The farmers needed to wait approximately days for it to be safe to feed the hay to the cows.
(Round to one decimal place as needed.)
ות
nts
Enter your answer in the answer box and then click Check Answer.
All parts showing
Clear All
Check Answer
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here to search
O
Answer:
19.9 days
Step-by-step explanation:
The amount remaining after d days is ...
a = (1/2)^(d/7)
We want to find d when a = 0.14
log(a) = (d/7)log(1/2)
d = 7·log(0.14)/log(1/2) ≈ 19.855 ≈ 19.9
The farmers need to wait about 19.9 days for it to be safe.