Stephanie bought two rugs. One rug is 15 feet long, and the other rug is 142 feet long. Each rug has a width of 10 feet.
What is the total area in square feet of the two rugs?
A 175 ft²
B 155 ft²
C 147.5 ft²
D 302.5 ft²
*please help me​

The total amount in the acount in 5 years is approximately $13,321.76.

The formula accrued amount in a compounded interest is expressed as;

[tex]A = P( 1 + \frac{r}{n} )^{n*t}[/tex]

Where A is accrued amount, P is principal, r is interest rate and t is time.

Given that:

First, convert R as a percent to r as a decimal

r = R/100

r = 5.75/100

r = 0.0575

Plug the given values into the above formula and solve for A.

[tex]A = P( 1 + \frac{r}{n} )^{n*t}\\\\A = 10000( 1 + \frac{0.0575}{12} )^{(12*5)}\\[/tex]

A = $13,321.76

Therefore, the accrued amount is $13,321.76.

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The expression 0 + 10 = 10 is an examle of the identity property of 0

From the question, we have the following parameters that can be used in our computation:

The list of options

The identity property of 0 states that

A number added to 0 equals to the number

Mathematically, we have

a + 0 = 0

The options are not clear

So, I will give another example of this property

The expression 0 + 10 = 10 is an examle of the identity property of 0

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Roger and Trish can complete 11/30 of the math homework in 1 hour if they work together.

What is an expression?

An expression is a sentence that has at least two numbers/variables and at least one math operation.

According to the given information:

Let the total amount of work in the math homework is 1.

In one hour, Roger can finish 1/6 of the work, and Trish can finish 1/5 of the work.

If they work together for 1 hour, then the total amount of homework they can finish is the sum of the parts each of them can finish in one hour:

1/6 + 1/5 = 5/30 + 6/30 = 11/30

So together they can finish 11/30 of the homework in one hour.

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Six types of costs are:

For assets attained in exchange for a deferred payment contract, the asset should be documented at its fair worth, which is the prevailing market rate. If establishing the fair value of the asset proves to be impracticable, the asset should be recorded based on the current value of upcoming payments due under the deferred payment agreement, stated using an apposite interest rate.

Generally, assets acquired in exchange of other non-monetary commodities should be appraised at their fair worth. If the truthful appraisal of the exchanged assets is uncertain, the assets should be noted down according to the seized amount of the items provided, including any received or paid cash during the transaction.

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Answer:

it is the opposite way around

Step-by-step explanation:

The solutions to the equation 100+ (n - 2)² = 149 are n = 9 and n = -5

From the question, we have the following parameters that can be used in our computation:

The equation 100+ (n - 2)² = 149

Express as

100+ (n - 2)² = 149

Subtract 100 from both sides of the equation

So, we have the following representation

(n - 2)² = 49

Take the square root of both sides

n - 2 = 7 and n - 2 = -7

Add 2 to both sides

n = 9 and n = -5

Hence, the solutions to the equation 100+ (n - 2)² = 149 are n = 9 and n = -5

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The first term a₁ of the geometric series is equal to 121.5

For a geometric series when the common ratio |r| > 1, then we use the formula for the sum of nth term:

Sₙ = a(rⁿ - 1)/(r - 1)...(1)

The nth term aₙ = arⁿ⁻¹

Thus for Sₙ = 4860 and aₙ = 3280.5, the value of a₁ can be derived as follows:

aₙ = arⁿ⁻¹

aₙ = arⁿ/r = 3280.5

rⁿ = a(r × 3280.5)/a

rⁿ = 9841.5/a

putting 9841.5/a for rⁿ in equation (1) we have;

Sₙ = a[(9841.5/a) - 1]/(r - 1)

Sₙ = (9841.5 - a)/(r - 1)

recall Sₙ = 4860 and r = 3 so;

(9841.5 - a)/2 = 4860

a = 9841.5 - 2(4860)

a = 121.5

Therefore, the first term a₁ of the geometric series is equal to 121.5

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The sum expression [tex][2(4 + \frac9n)^4](\frac9n) + ... + [2(4 + \frac{9n}n)^4](\frac9n)[/tex] using the sigma notation is [tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

From the question, we have the following parameters that can be used in our computation:

[tex][2(4 + \frac9n)^4](\frac9n) + ... + [2(4 + \frac{9n}n)^4](\frac9n)[/tex]

From the above expression, we can see that the different expression in each term is

9/n

So, we introduce a variable

Assuming the variable is i, the i-th term of the expression would be[tex]t(i) = [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

When represented using the sigma notation, we have

[tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

Hence, the sum expression using the sigma notation is [tex]\sum\limits^{n}_{i=1} [2(4 + \frac{9i}n)^4](\frac9n)[/tex]

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Answer: 34,650 permutations

In order to properly solve a system of linear equations utilizing matrices, you must abide by the below instructions:

First, create a matrix representation of the system of equations.  

Second, generate an augmented matrix by merging the coefficient matrix together with the constant matrix.

Third, apply elementary row operations in order to transform the augmented matrix into either row echelon or reduced row echelon form.

Fourth, use back substitution to accurately determine the variable values.

Ultimately, enter this solution into the original equation in order to obtain the primary variable value.

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Solving linear equations using matrices involves steps ranging from creating an augmented matrix, performing row operations, back substitution, and then interpreting results

To solve a system of linear equations using matrices, follow these step-by-step instructions:

Step 1: Write the system of linear equations in matrix form.
Represent the coefficients of the variables as a matrix (called the coefficient matrix), and the constants on the right side of the equations as another matrix (called the constant matrix).

Step 2: Create the augmented matrix.
Combine the coefficient matrix and the constant matrix into a single matrix by appending the constant matrix as an additional column. This combined matrix is called the augmented matrix.

Step 3: Perform row operations to achieve row-echelon form.
Use row operations (swapping rows, multiplying a row by a constant, or adding/subtracting rows) to manipulate the augmented matrix into row-echelon form. Row-echelon form has zeroes below the diagonal and non-zero elements on the diagonal.

Step 4: Perform back-substitution.
Starting from the last row of the row-echelon form matrix, solve for the variables using back-substitution. Substitute the values of the variables you find into the previous rows to determine the remaining variable values.

Step 5: Interpret the results.
Once you have solved all the variables, you have found the solution to the system of linear equations. If there are infinitely many solutions or no solutions, this will be indicated by the row-echelon form.

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Answer:

[tex]f(t) = 8e^{0.223144t}[/tex]

The length of the Green Route in miles is 64 miles.

Miles is a unit of linear measurement. It is traditionally defined as 5,280 feet, or 1,760 yards, and is equivalent to 1.609 kilometers. Miles are commonly used to measure long distances, such as the distance between two cities. They are also used to measure the lengths of roads and other paths. Miles are one of the most commonly used units of measurement in the United States.

The length of the Green Route in miles can be calculated by subtracting the total mileage traveled on the Blue Route from the total mileage traveled on both routes.

Total miles traveled on Monday = 38 miles
Total miles traveled on Tuesday = 80 miles

Total miles traveled on the Blue Route = 5 + 11 = 16 miles

Therefore, the total miles traveled on the Green Route = 80 - 16 = 64 miles

Therefore, the length of the Green Route in miles is 64 miles.

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The x-intercepts of the given function y = -3x(4-x) are x = 0 and x = 4.

As we know that the x-intercept is defined as an intercept that is located at the x-axis of the plane, is the location or coordinate from where the line crosses

To determine the x-intercepts of a function, we need to set y=0 and solve for x.

In this case, we have:

y = -3x(4-x)

0 = -3x(4-x)

0 = 3x(x-4)

Therefore, the x-intercepts occur when either 3x=0 or x-4=0.

Solving for x, we get:

3x = 0, x = 0

x - 4 = 0, x = 4

Therefore, the x-intercepts of y=-3x(4-x) are x=0 and x=4.

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The area of the triangle is 128 square inches.

To find the area of a triangle, you can use the formula:

Area = (1/2) * base * height

In this case, the base of the triangle is 32 inches and the height is 8 inches.

Plugging these values into the formula, we get:

Area = (1/2) * 32 * 8

Area = 16 * 8

Area = 128 in²

So, the area of the triangle is 128 square inches.

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A triangle is shown in the image. A triangle with a height of 8 inches. The height is perpendicular to the base labeled 32 inches. The side from the top of the perpendicular side to the base is labeled 28 inches. What is the area of the triangle? 256 in2 224 in2 128 in2 112 in2

Answer:

f'(x) = 2x, so f'(-2) = 2(-2) = -4.

Answer:6.25%

Step-by-step explanation:

Answer:

The heights and shadows of the objects are legs of similar right triangles. We can use these similar triangles to set up a proportion to solve for the height of the building.

2.9 / 1.26 = x / 47.25

x = 108.75 m

The number of feet of fencing that will be needed ​is illustrated below

The feet of fencing that will be needed ​is the perimeter of the fence

To find the perimeter of a composite figure, we need to add up the lengths of all the sides of the figure.

In this case, we add the side lengths of the rectangle to the side lengths of the right triangle and subtracting the common lengths between both shapes

Take for instance, we have

So, we have

Fencing = 2 * (4 + 5) + 3 + 4 + 5 - 2 * 4

Fencing = 22 units

So, the amount of fencing for the assumed dimensions is 22 units

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The price that the insurance company should charge for a one-year extended warranty on a Prego SUV is $402.

To determine the price that the insurance company should charge for a one-year extended warranty on a Prego SUV, the company needs to calculate the expected value of the repair costs and then add their desired profit to it.

Let's assume that the price for the warranty is x dollars. Then, the expected value of the repair costs for the insurance company would be:

(0.50)(0) + (0.35)($500) + (0.12)($1500) + (0.03)($4000) = $352

This means that on average, the insurance company can expect to pay out $352 in repair costs for each policy sold. To make an average profit of $50 per policy, the insurance company should charge:

x = $352 + $50 = $402

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The value of tan A is 0. 667. Option B

To determine the value of the identity, we need to take note of the different trigonometric identities.

these identities are;

We also have that the ratio for the tangent identity is expressed as;

tan θ= opposite/adjacent

From the information given, we have that;

The hypotenuse is 18.03, the side opposite to angle A is 10, and the side adjacent to angle A is 15

Then, for the identity, we have;

tan A = 10/15

Divide the values

tan A = 0. 667

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The x-coordinate of this point is -1, so cos(5π) = cos(900 degrees) = -1.

The y-coordinate of this point is -1, so sin(-9π/2) = sin(-810 degrees) = -1.

The y-coordinate of this point is 1, so sin(183π/2) = sin(16,470 degrees) = 1.

It should be noted that go find cos(5π), we first need to convert 5π to degrees. We know that π radians is equal to 180 degrees, so 5π radians is equal to 5π × (180/π) = 900 degrees. The x-coordinate of this point is -1, so cos(5π) = cos(900 degrees) = -1.

Also, to find sin(-9π/2), we first need to convert -9π/2 to degrees. We know that π radians is equal to 180 degrees, so -9π/2 radians is equal to -9π/2 × (180/π) = -810 degrees. The y-coordinate of this point is -1, so sin(-9π/2) = sin(-810 degrees) = -1.

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The range of the monthly rainfall data for the cities is approximately 7 centimeters.

To find the range of the data from the given box plot, we need to determine the highest and lowest values of the dataset. Looking at the box plot, we can see that the "H" represents the high outlier and the "□" represents the low outlier. The vertical line at the bottom of the box represents the minimum value and the vertical line at the top of the box represents the maximum value of the dataset within the interquartile range.

Using the scale on the x-axis, we can estimate the minimum value to be around 0.5 centimeters and the maximum value to be around 7.5 centimeters. The high outlier is located at around 8 centimeters and the low outlier is located at around 0 centimeters.

Therefore, the range of the data is the difference between the highest and lowest values, which is:

range = maximum value - minimum value = 7.5 - 0.5 = 7 centimeters

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Expressing the expansion of the logarithm in terms of log y, we can write: log(8x^2) = log(8) + 2*log(y), where y = x

Using the logarithmic identity that states log(a^b) = b*log(a), we can expand log(8x^2) as:

log(8x^2) = log(8) + log(x^2)

Note that a  logarithmic identity is a mathematical relationship or equation that involves logarithms.

We can further simplify log(x^2) as:

log(x^2) = 2*log(x)

Therefore, we can write:

log(8x^2) = log(8) + 2*log(x)

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Answer:

[tex]x^2 + 10x+25[/tex]

Step-by-step explanation:

(x + 5)^2 is the same as (x + 5)(x + 5), which is what you call a binomial expression, since two terms (x + 5) are being multiplied by each other.  You can multiply any binomial expression using the FOIL method, where you multiply the first (F), outer (O), inner (I), and last terms and simplify at the end:

First terms:  x * x

Outer terms:  x * 5

Inner terms:  5 * x

Last terms:  5 * 5

Simplifying:

[tex](x * x) + (x * 5) + (5 * x) + (5 * 5)\\x^2+5x+5x+25\\x^2+10x+25[/tex]

The value of the function g(f(-4)) = 536. Option D

From the information given, we have that the functions are;

f(x)= 4x+5

g(x) = 4x^2 -5x - 3

To determine the composite function,  g(f(-4)), we need to first determine the value of the function f(x) at -4

Now, substitute the value, we have;

f(-4) = 4(-4) + 5

expand the bracket, we get;

f(-4) = - 16 + 5

Add the values

f(-4) = -11

Now, substitute the value in the function g(x), we have that;

g(f(-4)) = 4(-11)² - 5(-11) - 3

find the square and expand the bracket

g(f(-4)) =484 + 55 - 3

Subtract the values, we have;

g(f(-4)) = 536

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Ari will need 3.6 pound of seed.

We are Given that total number of pounds of grass seed needed

9

Let number of pounds of Bermuda seeds is x

Let number of pounds of Fescue seeds is y

Then sum of both gives equation:

x+y=9

y=9-x...(i)

Given that cost of 1 pound of Bermuda seed = $4.80

Then cost of x pound of Bermuda seed = $4.80x

The cost of 1 pound of Fescue seed = $3.50

Then cost of y pound of Fescue seed = $3.50y

The total cost will be 4.80x + 3.50y

Now combining all three parts, we get equation:

4.80x+3.50y=4.02 x 9

4.80x+3.50y=36.18...(ii)

4.80x+3.50y=36.18

4.80x+3.50(9-x)=36.18

4.80x+31.5-3.50x=36.18

4.80x-3.50x=36.18-31.5

1.3x=4.68

x=3.6

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Answer:

  (x -2)(x -4)

Step-by-step explanation:

You want to factor x² - 4x -2x +8.

We recognize that the product of the coefficients of the two linear terms is equal to the contant, so this is more easily factored by not combining like terms prior to factoring.

Grouping the terms in pairs, we find we can factor each pair:

  (x² -4x) + (-2x +8)

  = x(x -4) -2(x -4) . . . . . these terms have a common factor of (x -4)

  = (x -2)(x -4) . . . . . . . factored form of the expression

The calculated area of the triangle B is 1.8 square units

From the question, we have the following parameters that can be used in our computation:

Triangle A and B

Where

Area of A = 1/2 base * height

Sp, we have

Area of A = 1/2 * 2 * 5

Next, we have

Area of B = Area of A * Scale factor^2

Using the above as a guide, we have the following:

Area of B = 1/2 * 2 * 5 * (3/5)^2

Evaluate

Area of B = 1.8

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In light of this, the 95% confidence interval for is (100.67, 111.33) as s is the sample standard deviation, n is the sample size.

A collection of information's values' standard deviation serves as a gauge for how much variance or dispersion there is. It is a statistical word used to describe the degree to which the individual data points depart as from mean or average value that is contained in the data set. By taking taking square root of the variance—the sum of the squared deviations amongst each point in the data and the mean—we can determine the standard deviation. While a high standard deviation suggests that the data points are widely dispersed, a modest standard deviation suggests that the statistics are close to the mean.

given

(a) When the sample size, n, is 16, we can apply the following formula to create a 95% confidence interval regarding the population mean, :

x ± tα/2 * (s/√n)

where t/2 is the crucial value from the t-distribution with n-1 degrees of freedom and a confidence level of 95%, and x is the sample mean, s is the sample standard deviation, n is the sample size.

We determine that t0.025,15 = 2.131 using a t-distribution table or calculator.

When we enter the values, we obtain:

106 ± 2.131 * (10/√16)

which is equivalent to:

106 ± 5.33

In light of this, the 95% confidence interval for is (100.67, 111.33) as s is the sample standard deviation, n is the sample size.

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