Answer:
work is shown and pictured
Correct Answer would be
D: (2,3)
Which graph shows the solution to the system of linear inequalities? y ≥ 2x + 1 y ≤ 2x – 2
The lines of the inequalities are parallel, and the system of inequalities do not have any solution.
How to determine the solution of the inequalitiesThe system of inequalities are given as:
y ≥ 2x + 1 y ≤ 2x – 2The inequality y ≥ 2x + 1 has the following characteristics:
A slope of 2A y-intercept of 1A closed line, where the upper region is shadedThe inequality y ≤ 2x – 2 has the following characteristics:
A slope of 2A y-intercept of -2A closed line, where the lower region is shadedSee attachment for the graphs of the system of inequalities
Read more about system of inequalities at:
https://brainly.com/question/9774970
Square root of 5 + square root of 3 the whole divided by sqaure root of 5 - square root of 3
Answer:
The answer is 4 + √15 .
Step-by-step explanation:
You have to get rid of surds in the denorminator by multiplying it with the opposite sign :
[tex] \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } [/tex]
[tex] = \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} - \sqrt{3} } \times \frac{ \sqrt{5} + \sqrt{3} }{ \sqrt{5} + \sqrt{3} } [/tex]
[tex] = \frac{ {( \sqrt{5} + \sqrt{3} ) }^{2} }{( \sqrt{5} - \sqrt{3} )( \sqrt{5} + \sqrt{3}) } [/tex]
[tex] = \frac{ {( \sqrt{5} )}^{2} + 2( \sqrt{5} )( \sqrt{3}) + {( \sqrt{3}) }^{2} }{ {( \sqrt{5}) }^{2} - { (\sqrt{3} )}^{2} } [/tex]
[tex] = \frac{5 + 2 \sqrt{15} + 3 }{5 - 3} [/tex]
[tex] = \frac{8 + 2 \sqrt{15} }{2} [/tex]
[tex] = 4 + \sqrt{15} [/tex]
42.
You were given the four numbers below and were asked to find the sum
of the first two numbers, the difference between the last two numbers,
the quotient when the sum is divided by the difference and the product
when the quotient is multiplied by 8. What is the final answer?
6458 2994
7013
6945
Answer:
1112
Step-by-step explanation:
6458 + 2994 = 9452
7013 - 6945 = 68
9452/68 = 139
139 * 8 = 1112
Which statement describes this system of equations? 9x – 6y = 15, 3x – 2y = 5 The equations in the system are equivalent equations. There is no solution to the system of equations. The system of equations has one solution at (3, 2). The system of equations has one solution at (5, 5).
Answer:
There is no solution to the systems of equation.
Step-by-step explanation:
Graph the system by using y=mx+b
Both systems are y=2/5x+5/2.
Answer:
that guy is wrong. its the first option.
Step-by-step explanation:
i just took it
What is the size of the matrix resulting from...
Answer:
1 x 3
Step-by-step explanation:
The order of the first matrix is 1 × 3
The order of the second matrix is 3 × 3
that is (1 × 3 ) × (3 × 3 )
The bold values at the ends of the orders give the order of the product, that is
1 × 3
Lettets a, b, c, and d are angle measures Which should equal 105 to prove false g
Answer:
a equals 105°
Step-by-step explanation:
angles in a straight line add up to 180°
a+75=180
a=180-75
a=105°
Expedia would like to test the hypothesis that the average round-trip airfare between Philadelphia and Paris is higher for a flight originating in Philadelphia when compared to a flight originating in Paris. The following data summarizes the sample statistics for round-trip flights originating in both cities. Assume that the population variances are equal.
Originating City
Philadelphia Paris
Sample mean $1,240 $1,060
Sample size 15 19
Sample standard
deviation $270 $240
If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris, the degrees of freedom for this hypothesis test are _____
(a) 33
(b) 32
(c) 34
(d) 28
Answer:
(b) 32
Step-by-step explanation:
From the information given :
sample mean of Philadelphia μ₁ = $1240
Sample size of Philadelphia n₁ = 15
Sample Standard deviation σ₁ = $270
sample mean of Paris μ₂ = $1,060
Sample size of Paris n₂ = 19
Sample Standard deviation of Paris σ₂ = $240
If Population 1 is defined as flights originating in Philadelphia and Population 2 is defined as flights originating in Paris;
the degrees of freedom for this hypothesis test can be calculated as;
degree of freedom df = n - 1
degree of freedom for both hypothesis test = (n₁ - 1 + n₂ -1)
degree of freedom for both hypothesis test = (n₁ + n₂ - 2)
degree of freedom for both hypothesis test = ( 15 + 19 - 2)
degree of freedom for both hypothesis test are 32
Determine the area under the standard normal curve that lies to the left of
(a) Z = 1.75, (b) Z=0.01, (c) Z= -0.01, and (d)Z = 1.29.
Click the icon to view a table of areas under the normal curve.
(a) The area to the left of Z= 1.75 is
(Round to four decimal places as needed.)
Answer:
a) 0.9599b) 0.5040c) 0.4960d) 0.9015Step-by-step explanation:
You did not provide the table, so I used a spreadsheet. Most have functions for finding the area under a standard normal curve.
Which describes the graph in words?
A. All numbers less than -10 and less than or equal to 8.
B. All numbers greater than -10 and less than 8
C. All numbers greater than or equal to -10 and less than or equal to 8
D. All numbers greater than -10 and less than or equal to 8.
D. All numbers greater than -10 and less than or equal to 8
5/9 + (1/9 + 4/5)=×
Answer:
22/15I hope it helps :)Step-by-step explanation:
[tex]\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)=x\\x=\frac{5}{9}+\left(\frac{1}{9}+\frac{4}{5}\right)\\\mathrm{Remove\:parentheses}:\quad \left(a\right)=a\\x=\frac{5}{9}+\frac{1}{9}+\frac{4}{5}\\\mathrm{Compute\:a\:number\:comprised\:of\:factors\\\:that\:appear\:in\:at\:least\:one\:of\:the\:following:}\\9,\:9,\:5\\=3\times \:3\times\:5\\\mathrm{Multiply\:the\:numbers:}\:3\times \:3\times \:5=45\\\frac{5}{9}=\frac{5\times \:5}{9\times \:5}=\frac{25}{45}\\[/tex]
[tex]\frac{1}{9}=\frac{1\times \:5}{9\times \:5}=\frac{5}{45}\\\\\frac{4}{5}=\frac{4\times \:9}{5\times \:9}=\frac{36}{45}\\\\x=\frac{25}{45}+\frac{5}{45}+\frac{36}{45}\\\\\mathrm{Since\:the\:denominators\:are\:equal,\\combine\:the\:fractions}:\\\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}\\\\x=\frac{25+5+36}{45}\\\\x=\frac{66}{45}\\\\x=\frac{22}{15}[/tex]
McKenzie has a bag contains six red marbles four blue marbles and 14 yellow marbles if she chooses one marble from the bag what is the probability that the marble is not yellow
Answer:
5/12
Step-by-step explanation:
Total number of marbles in the bag
6red+ 4blue + 14 yellow = 24 marbles
Not yellow marbles = 10 marbles
P ( not yellow ) = number of not yellow marbles / total marbles
=10/24
= 5/12
Answer:
5/12
Step-by-step explanation:
6 red marbles
4 blue marbles
14 yellow marbles
total marbles = 6 + 4 + 14 = 24 marbles
24 - 14 = 10 marbles
10 marbles are not yellow.
P(not yellow) = 10/24 = 5/12
Question 3
34° Celsius is equal to
o
Fahrenheit
Hi
Below the formulas to convert Celsius into Fahrenheit.
9/5 C +32 = degree in fahrenheit.
Where C is the degree in celsius. So have a try and find the answer.
what is the approximate radius of a sphere with a volume of 1436cm to power of 3
Answer:
The radius is 7 cmStep-by-step explanation:
Volume of a sphere is given by
[tex]V = \frac{4}{3} \pi {r}^{3} [/tex]
where r is the radius
From the question V = 1436 cm³
[tex]1436 = \frac{4}{3} \pi {r}^{3} [/tex]
Multiply through by 3
We have
[tex]4308 = 4\pi {r}^{3} [/tex]
Divide both sides by 4π
[tex] {r}^{3} = \frac{4308}{4\pi} [/tex]
[tex] {r}^{ 3} = \frac{1077}{\pi} [/tex]
Find the cube root of both sides
[tex]r = \sqrt[3]{ \frac{1077}{\pi} } [/tex]
r = 6.99
We have the final answer as
r = 7cmHope this helps
EXAMPLE 2 (a) Find y' if x3 + y3 = 18xy. (b) Find the tangent to the folium of Descartes x3 + y3 = 18xy at the point (9, 9). (c) At what point in the first quadrant is the tangent line horizontal?
(a) Via implicit differentiation, we get
[tex]x^3+y^3=18xy\implies 3x^2+3y^2y'=18y+18xy'[/tex]
Solve for [tex]y'[/tex]:
[tex]y'=\dfrac{18y-3x^2}{3y^2-18x}=\dfrac{6y-x^2}{y^2-6x}[/tex]
(b) Find the slope of the tangent line at (9, 9) by plugging in x = y = 9 into the equation above:
[tex]y'=\dfrac{6\cdot9-9^2}{9^2-6\cdot9}=-1[/tex]
Use the point-slope formula to find the equation of the line:
[tex]y-9=-1(x-9)\implies y=-x+18[/tex]
(c) The tangent line is horizontal when its slope is 0, so solve [tex]y'=0[/tex]:
[tex]\dfrac{6y-x^2}{y^2-6x}=0\implies6y-x^2=0\implies y=\dfrac{x^2}6[/tex]
Now substitute y in the equation for the folium to solve for x :
[tex]x^3+\left(\dfrac{x^2}6\right)^3=18x\cdot\dfrac{x^2}6[/tex]
[tex]x^3+\dfrac{x^6}{6^3}=3x^3[/tex]
[tex]\dfrac{x^6}{6^3}-2x^3=0[/tex]
[tex]x^3\left(\left(\dfrac x6\right)^3-2\right)=0[/tex]
[tex]\implies x=0\text{ or }x=6\sqrt[3]{2}[/tex]
x = 0 corresponds to y = 0 (plug x = 0 into the folium equation to see why), i.e. the origin. If you don't consider the origin to belong to the first quadrant, then we only keep
[tex]x=6\sqrt[3]{2}\implies y=6\sqrt[3]{4}[/tex]
The Ambell Company uses batteries from two different manufacturers. Historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours. Only 75% of the batteries from manufacturer 2 last for over 40 hours. A battery in a critical tool fails at 32 hours. What is the probability it was from manufacturer 2?
Answer:
The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625
Step-by-step explanation:
Given that:
60% of the batteries are from manufacturer 1
90% of these batteries last for over 40 hours
Let the number of the battery duration be n = 0.90
Therefore n' = 1 - 0.90 = 0.10
Let p = manufacturer 1 and q = manufacturer 2
q = 1 - p
q = 1 = 0.6
q = 0.4
Thus ; 40% of the batteries are from manufacturer 2
However;
Only 75% of the batteries from manufacturer 2 last for over 40 hours.
Let number of battery duration be m = 0.75
Therefore ; m' = 1 - 0.75 = 0.25
A battery in a critical tool fails at 32 hours.
Thus; the that the battery in a critical tool fails at 32 hours was from manufacturer 2 is:
[tex]= \dfrac{q \times m' }{ p \times n' + q \times m' }[/tex]
[tex]= \dfrac{0.4 \times0.25 }{ (0.6 \times 0.1) + (0.4 \times 0.25 ) }[/tex]
[tex]=\dfrac{0.1}{0.06+ 0.1}[/tex]
[tex]=\dfrac{0.1}{0.16}[/tex]
= 0.625
The probability that the battery in a critical tool fails at 32 hours was from manufacturer 2 is 0.625
The probability that the battery was from manufacturer 2 is 62.5%.
Since the Ambell Company uses batteries from two different manufacturers, and historically, 60% of the batteries are from manufacturer 1, and 90% of these batteries last for over 40 hours, while only 75% of the batteries from manufacturer 2 last for over 40 hours, if a battery in a critical tool fails at 32 hours, to determine what is the probability it was from manufacturer 2 the following calculation must be performed:
You must establish the percentage of failure of the total batteries, and determine what percentage of failures corresponds to each manufacturer. Manufacturer 1 = 60 x 0.1 = 6 Manufacturer 2 = 40 x 0.25 = 10 Total = 16 16 = 100 10 = X 100 x 10/16 = X 62.5 = X
Therefore, the probability that the battery was from manufacturer 2 is 62.5%.
Learn more in https://brainly.com/question/14461509
22,403 Check:
- 8,675
how i do this
Answer:
Hello!! :) The answer to your question is 13,728
Steps will be below.
Step-by-step explanation:
So we will subtract 22,403 and 8,675.
When we do that we will get 13,728
To check your answer we have to do the opposite of subtracting which will be adding.
This is how we check our work: the answer we got was 13,728...we have to take that answer and add it to 8,675 which will give us 22,403
(Both of the numbers are from the question)
At the bottom I attached a picture of how I did the subtracting and how I checked my work.
Sorry for my handwriting......if you can’t understand my handwriting, I attached another picture which is more clearer.
ANSWER TO YOUR QUESTION: 13,728
Brainliest would be appreciated! Thank you :3
Hope this helps! :)
Answer:
The answer is 13,728
Step-by-step explanation:
Check your work with addition.
need help with these 3 questions (giving brainiest if you can answer with equations)
Problem 10
Answer: approximately 57.39159 kmExplanation: You'll use the equation cos(28) = d/65 to solve for d to get d = 65*cos(28) = 57.39159 approximately. We use the cosine ratio because it ties together the adjacent and hypotenuse.
=====================================
Problem 11
Answer: approximately 10.46162 metersExplanation: This time we use the sine rule. We have the height as the opposite side (which is unknown, call it x) and the hypotenuse is the ladders length (11). So we have sin(72) = x/11 which solves to x = 11*sin(72) = 10.46162
=====================================
Problem 12
Answer: approximately 16.05724 cmExplanation: Now we use the tangent rule to connect the opposite and adjacent sides.
tan(37) = 12.1/x
x*tan(37) = 12.1
x = 12.1/tan(37)
x = 16.05724 approximately
In a small private school, 55 students are randomly selected from 1313 available students. What is the probability that they are the fivefive youngest students?
Complete Question
In a small private school, 5 students are randomly selected from 13 available students. What is the probability that they are the five youngest students?
Answer:
The probability is [tex]P(x) = 0.00078[/tex]
Step-by-step explanation:
From the question we are told that
The number of student randomly selected is r = 5
The number of available students is n = 13
Generally the number of ways that 5 students can be selected from 13 available students is mathematically represented as
[tex]n(k)=\left n} \atop {}} \right.C_r = \frac{n ! }{(n-r ) ! r!}[/tex]
substituting values
[tex]\left n} \atop {}} \right.C_r = \frac{13 ! }{(13-5 ) ! 5!}[/tex]
[tex]\left n} \atop {}} \right.C_r = \frac{13 * 12 * 11 * 10 * 9 *8! }{8 ! * 5 * 4 * 3 * 2 *1}[/tex]
[tex]\left n} \atop {}} \right.C_r = 1287[/tex]
The number of method by which 5 youngest students are selected is n(x) = 1
So
Then the probability of selecting the five youngest students is mathematically represented as
[tex]P(x) = \frac{n(x)}{n(k)}[/tex]
substituting values
[tex]P(x) = \frac{1}{1287}[/tex]
[tex]P(x) = 0.00078[/tex]
A bag of marbles contains 4 green marbles, 3 blue marbles, 2 red marbles, and 5 yellow marbles. How many total possible outcomes are there when choosing a marble from the bag?
Answer:
its 14/C
Step-by-step explanation:
i got i right on edg U^U
Answer:
16
Step-by-step explanation:
i did edge test yea dont be imma fake :***
may someone assist me?
Answer:
28
Step-by-step explanation:
Let x be the missing segment
We will use the proportionality property to find x
24/16 = 42/x
Simplify 24/16
24/16= (4×6)/(4×4)= 4/6 = 3/2
So 3/2 = 42/x
3x = 42×2
3x = 84
x = 84/3
x= 28
Consider the recursive function,
f(1) = 2
f(n) = 5•f(n − 1), for n > 2
Answer:
yes?
Step-by-step explanation:
??? can u say exactly what the question is please? thank you
Answer:
the question is:
Which statement is true?
A. The value of F(6) is 2 times the value of f(3).
B. The value of f(6) is 15 times the value of f(3).
C. The value of f(6) is 1/125 times the value of f(3).
D. The value of f(6) is 125 times the value of f(3).
Step-by-step explanation:
comment the answer below for everyone please.
Each marble bag sold by Carmen's Marble Company contains 3 purple marbles for every 4 blue marbles. If a bag has 28 blue marbles, how many purple marbles does it contain?
Answer:
21 purple marbles
Step-by-step explanation:
my explanation is i looked at it like a ratio so ¾= x/28
then i took 28 ÷ 4 which equals 7, then i took 7 and multiplied it by 3 which gave me 21, so the answer is 21 purple marbles
Construct a polynomial function with the stated properties. Reduce all fractions to lowest terms. Second-degree, with zeros of −7 and 6, and goes to −∞ as x→−∞.
Answer:
f( x ) = - x² - x + 42
Step-by-step explanation:
The polynomial function will have to include the zeroes with opposing signs, considering that when you isolate the value x say, you will take that value to the opposite side, changing the signs,
f(x) = (x + 7)(x - 6)
Now as you can see, x extends to negative infinity, such that,
f(x) = - (x + 7)(x - 6) - that negative makes no difference whatsoever on the zeroes of the function. All we want to do now is to expand this, and we receive out simplified solution.
Goal : [tex]expand\:-\:\left(x\:+\:7\right)\left(x\:-\:6\right)[/tex],
[tex]- xx+x\left(-6\right)+7x+7\left(-6\right)[/tex] = [tex]- xx-6x+7x-7\cdot \:6[/tex] = [tex]-\left(x^2+x-42\right)[/tex],
Expanded Solution : [tex]-x^2-x+42[/tex],
Polynomial Function : f( x ) = [tex]-x^2-x+42[/tex]
Help ASAP!!!!
Identify the correct trigonometry formula to use to solve for x.
Sin (angle) = opposite leg / hypotenuse
Sin(62) = 18/x
The answer is the third choice.
Rita ha decidido emprender un negocio de ventas de productos de protección personal, para lo cual tiene que inventir 1/3 de su dinero en mascarillas, 4/15 en guantes, 1/10 en protección facial y el resto en alcohol. ¿Que fracciónde dinero se invierte en alcohol?
Answer:
3/10
Step-by-step explanation:
Subtract the sum of 1/3, 4/15 and 1/10 from 1:
10/30 + 8/30 + 3/30 = 21/30, or 7/10
Then: 1 - 7/10 = 3/10
What is the Greatest Common Factor GCF between two expressions?
Answer:
The GCF is the largest expression that is factor of all expressions
Answer:
The GCF of two expressions is the greatest expression that is a factor of both the expressions.
Step-by-step explanation:
For example 7x² and 14x.
7x² = 1, 7, x, x
14x = 2, 7, x
The greatest common factor of the two expressions is 7x.
Software to detect fraud in consumer phone cards tracks the number of metropolitan areas where calls originate each day. It is found that 4% of the legitimate users originate calls from two or more metropolitan areas in a single day. However, 30% of fraudulent users originate calls from two or more metropolitan areas in a single day. The proportion of fraudulent users is 0.0130%. If the same user originates calls from two or more metropolitan areas in a single day, what is the probability that the user is fraudulent
Answer:
0.0009741
Step-by-step explanation:
The approach to solve this question is by the use of Baye’s theorem in conditional probability
Please check attachment for complete solution and explanation
Answer:
0.000974
Step-by-step explanation:
Let assume that;
P(Q) is the probability that the same user originated calls from two or more metropolitan areas in a single day
Also; Let consider M to be the event that denotes the legitimate users and N to be the event that denote the fraudulent users .
Then;
P(M) = 0.00013
P(N) = 1 - P(M)
P(N) = 1 - 0.00013
P(N) = 0.99987
P(Q|M) = 0.3
P(Q|N) = 0.4
The probability the same users originates calls from two or more metropolitan areas in a single day is calculated as follows:
P(Q) = (P(M) P(Q|M) ) + ( P(N) P(Q|N) )
P(Q) = ( 0.00013 × 0.3 ) + (0.99987 × 0.04 )
P(Q) = 0.000039 + 0.0399948
P(Q) = 0.0400338
However; The probability that the users is fraudulent given that the same users originates calls from two or more metropolitan areas in a single day is,
[tex]P(M|Q) = \dfrac{P(M) P(Q|M)}{(P(M) \ P(Q|M) ) + ((P(N) \ P(Q|N)) } \\ \\ \\ P(M|Q) = \dfrac{0.0001 \times 0.3}{0.0400338} \\ \\ \\ P(M|Q) = \dfrac{0.000039}{0.0400338} \\ \\ \\ \mathbf{P(M|Q) = 0.000974}[/tex]
Identify the lower class limits, upper class limits, class width, class midpoints, and class boundaries for the given frequency distribution. Also identify the number of individuals included in the summary.
Age (yr) when award was won: 25-34, 35-44, 45-54, 55-64, 65-74, 75-84, 85-94
Frequency: 29, 34, 16, 3, 5, 1, 2
Step-by-step explanation:
kindly find attached detailed information of the remaining information as requested for your reference
1. The lower class limit is the left number in the age column
i.e in the 25-34 the lower class limit is 25
2. The upper class limit is the right number in the age column
i.e in the 25-34 the lower class limit is 34
3. The class width is the difference between the class boundaries of a single class
class width = 34.5-24.5= 10
4. The number of individuals is= 29+34+16+3+5+1+2= 90
Select the correct answer.
Answer:
C. 5 × 3
Step-by-step explanation:
The order of a matrix is the number of rows and columns that a matrix has. Rows are listed first and columns are listed second. The matrix has 5 rows going across horizontally and 3 columns going down vertically.
So, the order of the matrix is 5 × 3.
Hope that helps.
Solve for qqq. 3\left(q+\dfrac43\right) = 23(q+ 3 4 )=2
pls answer this
Answer:
19/3Step-by-step explanation:
Given the expression [tex]3\left(q+\dfrac43\right) = 23[/tex], we are to find the value of q;
[tex]3\left(q+\dfrac43\right) = 23\\on\ expansion\\\\3q + 4/3(3) = 23\\\\3q+4 = 23\\\\subtract \ 4\ from \ both\ sides \ of \ the \ equation\\\\3q+4-4 = 23-4\\\\3q = 19\\\\Diviide \both\ sides \ by \ 3\\\\3q/3 = 19/3\\\\q = 19/3[/tex]
Hence the value of q is 19/3
Answer:
-2/3
Step-by-step explanation:
Don't worry about it, i got connections.