Answer:
[tex]Side\ B = 6.0[/tex]
[tex]\alpha = 56.3[/tex]
[tex]\theta = 93.7[/tex]
Step-by-step explanation:
Given
Let the three sides be represented with A, B, C
Let the angles be represented with [tex]\alpha, \beta, \theta[/tex]
[See Attachment for Triangle]
[tex]A = 10cm[/tex]
[tex]C = 12cm[/tex]
[tex]\beta = 30[/tex]
What the question is to calculate the third length (Side B) and the other 2 angles ([tex]\alpha\ and\ \theta[/tex])
Solving for Side B;
When two angles of a triangle are known, the third side is calculated as thus;
[tex]B^2 = A^2 + C^2 - 2ABCos\beta[/tex]
Substitute: [tex]A = 10[/tex], [tex]C =12[/tex]; [tex]\beta = 30[/tex]
[tex]B^2 = 10^2 + 12^2 - 2 * 10 * 12 *Cos30[/tex]
[tex]B^2 = 100 + 144 - 240*0.86602540378[/tex]
[tex]B^2 = 100 + 144 - 207.846096907[/tex]
[tex]B^2 = 36.153903093[/tex]
Take Square root of both sides
[tex]\sqrt{B^2} = \sqrt{36.153903093}[/tex]
[tex]B = \sqrt{36.153903093}[/tex]
[tex]B = 6.0128115797[/tex]
[tex]B = 6.0[/tex] (Approximated)
Calculating Angle [tex]\alpha[/tex]
[tex]A^2 = B^2 + C^2 - 2BCCos\alpha[/tex]
Substitute: [tex]A = 10[/tex], [tex]C =12[/tex]; [tex]B = 6[/tex]
[tex]10^2 = 6^2 + 12^2 - 2 * 6 * 12 *Cos\alpha[/tex]
[tex]100 = 36 + 144 - 144 *Cos\alpha[/tex]
[tex]100 = 36 + 144 - 144 *Cos\alpha[/tex]
[tex]100 = 180 - 144 *Cos\alpha[/tex]
Subtract 180 from both sides
[tex]100 - 180 = 180 - 180 - 144 *Cos\alpha[/tex]
[tex]-80 = - 144 *Cos\alpha[/tex]
Divide both sides by -144
[tex]\frac{-80}{-144} = \frac{- 144 *Cos\alpha}{-144}[/tex]
[tex]\frac{-80}{-144} = Cos\alpha[/tex]
[tex]0.5555556 = Cos\alpha[/tex]
Take arccos of both sides
[tex]Cos^{-1}(0.5555556) = Cos^{-1}(Cos\alpha)[/tex]
[tex]Cos^{-1}(0.5555556) = \alpha[/tex]
[tex]56.25098078 = \alpha[/tex]
[tex]\alpha = 56.3[/tex] (Approximated)
Calculating [tex]\theta[/tex]
Sum of angles in a triangle = 180
Hence;
[tex]\alpha + \beta + \theta = 180[/tex]
[tex]30 + 56.3 + \theta = 180[/tex]
[tex]86.3 + \theta = 180[/tex]
Make [tex]\theta[/tex] the subject of formula
[tex]\theta = 180 - 86.3[/tex]
[tex]\theta = 93.7[/tex]
aljebra questions anum counted the money she had in her purse and money box . When she doubbled the amount in her purse and add it to the amount in money box she gets rs 1700 . When she triples the amount in her purse and add in to money box she gets rs 2200. How much money does she have in her purse
Answer:
Money in her purse is Rs. 500.
Step-by-step explanation:
Let the money in her purse = Rs. [tex]x\\[/tex]
Let the money in her Money box = Rs. [tex]y[/tex]
As per question statement,
Double the money in her purse (i.e. [tex]2 \times x[/tex]) and add it to the amount in money box, she gets Rs. 1700.[tex]2x+y=1700[/tex] ........ (1)
Triple the money in her purse (i.e. [tex]3\times x[/tex]) and add it to amount in money box ([tex]y[/tex]), she gets Rs. 2200.[tex]3x+y=2200[/tex] ....... (2)
To find: Money in her purse = ? i.e. [tex]x=?[/tex]
Let us solve for [tex]x[/tex] using the two linear equations.
We can use substitution method here i.e. find value of one variable from one equation and then substitute that value in other equation.
Using equation (1), we get the value of [tex]y[/tex] as follows:
[tex]y=1700-2x[/tex]
Now, let us put this value of y in equation (2) to find the value of [tex]x[/tex]:
[tex]3x+1700-2x=2200\\\Rightarrow x+1700 = 2200\\\Rightarrow x=2200-1700\\\Rightarrow x = Rs.\ 500[/tex]
Money in her purse is Rs. 500.
At a local high school football game, twice the number of students attended as adults. If student tickets were $6.50, adult tickets were $9.00, and the total receipts for the game were $4972, how many students attended the game?
452 students
484 students
512 students
376 student
Answer:
454
Step-by-step explanation:
set up a system of equation
let y be the number of students
let x be the number of adults
because there are twice the amount of students attended as adults, we can use y=2x as one equation
the other equation will be 6.5y+9x=4972 because this represents the total amount of money
plug 2x for y : 6.5(2x)+9x=4972 : x=226
plug 226 in for the first equation : y=2(226) : y=452
The formula for the volume of a pyramid is =13ℎ
V
=
1
3
B
h
, where B is the area of the base and h is the height. Rearrange the formula to solve for the height (h).
Select one:
a. ℎ=3
h
=
3
V
B
b. ℎ=3
h
=
B
3
V
c. ℎ=3
h
=
V
3
B
d. ℎ=3
Answer:
h = V3B
Step-by-step explanation:
V = 1/3B · h
Divide volume by 1/3 B to get h by itself
V/1/3B = V3B
A steel wire, when bent in the form of a square, encloses an area of 121 sq cm. The same wire
is bent, in the form of a circle. Find the area of the circle.
Answer:
A = 49[tex]\pi[/tex]
Step-by-step explanation:
First, we need to find the length of the wire. We can calculate this because we are given the area of the square, so we can work backwards.
Use the area formula and plug in the numbers:
A = s²
121 = s²
11 = s
We can calculate the length of the wire by multiplying 11 by 4, which is 44.
Now, we know the circumference of the circle is 44 units because that is how long the wire is.
We can work backwards again to find the radius, using the circumference formula:
C = 2[tex]\pi[/tex]r
44 = 2[tex]\pi[/tex]r
22 = [tex]\pi[/tex]r
7 = r
Now, we can find the area of the circle:
A = [tex]\pi[/tex]r²
A = [tex]\pi[/tex](7)²
A = 49[tex]\pi[/tex]
Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him
Answer:
60 miles
Step-by-step explanation:
Ashok and Brian are both walking east along the same path; Ashok walks at a faster constant speed than does Brian. If Brian starts 30 miles east of Ashok and both begin walking at the same time, how many miles will Brian walk before Ashok catches up with him?
Statement 1. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own
Statement 2. If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds
Solution
A. Brian’s walking speed is twice the difference between Ashok’s walking speed and his own.
Let Brian speed=b
Ashok speed=a
Brian's walking speed=2(a-b)
b=2(a-b)
Divide both sides by 2
b/2=a-b
Ashok catches up in (time)= distance /( relative rate
=30/(a-b)
=30/(b/2)
=30÷b/2
=30*2/b
=60/b.
By that time Brian will cover a distance of
distance=rate*time
=b*60/b
=2(a-b)*60/2(a-b)
=60 miles
(2) If Ashok’s walking speed were five times as great, it would be three times the sum of his and Brian’s actual walking speeds.
5a=3(a+b)
5a=3a+3b
5a-3a=3b
2a=3b
Hi May I know how to solve this step by step please
Answer:
2, 3 , 5, 7
Step-by-step explanation:
2(x - 2)/3 < (x + 1)/2 < 3(5x + 6)/4
Considering:
2(x - 2)/3 < (x + 1)/2
<=>(2x - 4)/3 < (x + 1)/2
<=> (2x - 4)*2 < (x + 1)*3
<=> 4x - 8 < 3x + 3
<=> 4x - 3x < 8 + 3
<=> x < 11
Considering:
(x + 1)/2 < 3(5x + 6)/4
<=>(x + 1)/2 < (15x + 18)/4
<=>(x + 1)*4 < (15x + 18)*2
<=> 4x + 4 < 30x + 36
<=> 4x - 30x < 36 - 4
<=> -26x < 32
<=> 26x > -32
<=> x > -32/26
=> -32/26 < x < 11
The prime numbers satisfy the above inequalities: 2, 3 , 5, 7
did this several times but still didn't get the answer .pls do try this :)
Answer:
x=-15/2 and x=1
x=6 and x=3/4
Step-by-step explanation:
You have the following equations:
[tex]\frac{4x-3}{x+2}=\frac{2x}{x+5}[/tex]
[tex]\frac{2}{x-2}+\frac{3}{x}-\frac{9}{x+3}[/tex]
To solve both equations you can first multiply by the m.c.m of the denominators, and then solve for x, just as follow:
first equation:
[tex][\frac{4x-3}{x+2}=\frac{2x}{x+5}](x+2)(x+5)\\\\(4x-3)(x+5)=2x(x+2)\\\\4x(x)+4x(5)-3(x)-3(5)=2x(x)+2x(2)\\\\4x^2+20x-3x-15=2x^2+4x\\\\4x^2-2x^2+20x-3x-4x-15=0\\\\2x^2+13x-15=0[/tex]
In this case you use the quadratic formula:
[tex]x_{1,2}=\frac{-13\pm \sqrt{(13)^2-4(2)(-15)}}{2(2)}\\\\x_{1,2}=\frac{-13 \pm 17}{4}\\\\x_1=-\frac{15}{2}\\\\x_2=1[/tex]
Then, for the first equation the solutions are x=-15/2 and x=1
second equation:
[tex][\frac{2}{x-2}+\frac{3}{x}=\frac{9}{x+3}]x(x-2)(x+3)\\\\2x(x+3)+3(x-2)(x+3)=9x(x-2)\\\\2x^2+6x+3(x^2+3x-2x-6)=9x^2-18x\\\\2x^2+6x+3(x^2+x-6)=9x^2-18x\\\\2x^2+6x+3x^2+3x-18-9x^2+18x=0\\\\-4x^2+27x-18=0[/tex]
Again, you use the quadratic formula:
[tex]x_{1,2}=\frac{-27\pm \sqrt{(27)^2-4(-4)(-18)}}{2(-4)}\\\\x_{1,2}=\frac{-27\pm 21}{-8}\\\\x_1=6\\\\x_2=\frac{3}{4}[/tex]
Then, the solutions for the second equation are x=6 and x=3/4
Graph [tex]y=\frac{2}{3} x[/tex] Which of the following statements are true?
Answer:
A,C,D
Step-by-step explanation:
When b=0, there is a proportional relationship.
The slope in y=mx+b is the value next to x.
Using RISE/RUN when there is a change of 3 units in x, there is a change of 2 units in y.
Ans ASAP!! But one request can u give IN pic WITH steps?..... Plzlzlzlzlz?? 1rst one will be the BRAINLIEST.. But I want complete ans!
Answer:
The parts are 24 and 16
Step-by-step explanation:
Let's call the two parts x and y. We can write the following system:
x + y = 40 -- Equation 1
1/4x = 3/8y -- Equation 2
2x = 3y -- Equation 3 (Multiply Equation 2 by 8 to get rid of denominators)
2x + 2y = 80 -- Equation 4 (Multiply Equation 1 by 2)
3y + 2y = 80 -- (Substitute 2x = 3y into Equation 4)
5y = 80 -- (3y + 2y = 5y)
y = 16 -- (Divide by 5)
x + 16 = 40 -- (Substitute y = 16 into Equation 1)
x = 24 -- (Subtract 16)
HELP!! DISCRETE DATA
Answer:
Hey there!
Discrete Data is the number of friends you invited to your last birthday party.
Hope this helps :)
Answer:
a) The number of friends you invited to your last party.
Step-by-step explanation:
Let’s take a step back what is discrete, and what continuous?
Discrete
This is the type of data with certain whole numbers not 2.36 only 2 or 3.
Continuous
This is the data being specific like 1.373.
So a)
The is discrete because you can only have like 5 friends not 7.49 friends.
b)
This is continuous because height can be 5.26 feet.
c)
Time is continuous because there can be 4.3739 minutes.
d)
Weight is also continuous it can be 6339.373 pounds.
Factor the polynomial expression x2 + 5.
Answer:
Step-by-step explanation:
Please write this as x^2 + 5.
Roots are ±i√5.
The corresponding factors of x^2 + 5 are (x + i√5) and (x - i√5)
Which equation represents a line that is perpendicular to line FG? A. y=-1/2x+5 B. y=1/2x+2 C. y=-2x-3 D. y=2x-6
The equation of line which is perpendicular to the line FG is
y = -2x -3.
What is equation of line?
The equation of line is an algebraic form of representing the set of points, which together form a line in a coordinate system.
Formula for finding the equation of line from two points [tex](x_{1} ,y_{1} ) and (x_{2}, y_{2} )[/tex][tex](y -y_{1}) = \frac{y_{2}-y_{1} }{x_{2} -x_{1} } (x-x_{1} )[/tex]
What is the slope of two perpendicular lines?If [tex]m_{1}[/tex] be the slope of one line, then the slope of the perpendicular line is [tex]\frac{-1}{m_{1} }[/tex].
What is the slope intercept form of a line ?The slope intercept form of the line is given by y = mx + b
Where, m is the slope of a line.
According to the given question
We have a line FG and the coordinates of points F and G are (-5,1) and (9,8) respectively.
Therefore, the slope of the line FG = [tex]\frac{8-1}{9+5}=\frac{7}{14} =\frac{1}{2}[/tex]
⇒ The slope of the line which is parallel to line FG is -2
Now, from the given option of the equation of line , y = -2x -3 has a slope of -2 .
Hence, the equation of line which is perpendicular to the line FG is
y = -2x -3.
Learn more about the equation of a perpendicular line here:
https://brainly.com/question/20712656
#SPJ2
Find the sum of all integers between 550 and 850 which are divisible by 11.
Answer:
19008
Step-by-step explanation:
550 is equal to 11 multiplied by 50.
1. Solve for multiples of 11 between 550 and 850
11 · 51 = 561
11 · 52 = 572
11 · 53 = 583
11 · 54 = 594
11 · 55 = 605
11 · 56 = 616
11 · 57 = 627
11 · 58 = 638
11 · 59 = 649
11 · 60 = 660
11 · 61 = 671
11 · 62 = 682
11 · 63 = 693
11 · 64 = 704
11 · 65 = 715
11 · 66 = 726
11 · 67 = 737
11 · 68 = 748
11 · 69 = 759
11 · 70 = 770
11 · 71 = 781
11 · 72 = 792
11 · 73 = 803
11 · 74 = 814
11 · 75 = 825
11 · 76 = 836
11 · 77 = 847
2. Add the products together
= 19008
wht is the solution of the system defined be y =-x+5 and 5x+2y=14
Answer:
1.33,3.667
Step-by-step explanation:
Use y=mx+b for second system
which is y=5/2x+7
Now use substitution,graph, or elimination method.
PLEASE ANSWER THIS FAST Will the red square and the orange square always equal the blue square? What colored square is the hypotenuse?
Step-by-step explanation:
The area of the blue square will always equal the sum of the area of the orange and red rectanglesThe pythagorian theorem:
a²+b² = c²
now let a be the side of the red triangle and b the side of the orange one
so a² is the area of the red triangle and b² is the area of the orange one
Let c be the side of the blue rectangle
so c² is the area of it
then what we concluded is right
the hypotenuse is the blue side since it is the larger oneThe baseball team has a double-header on Saturday. The probability that they will win both games is 50%. The probability that they will win just the first game is 65%, What is the probability that the team will win the 2nd game given that they have already won the first game? (PLEASE SHOW YOU'RE WORK)
Answer:
77%
Step-by-step explanation:
Given the following :
Probability of winning both games = 50%
Probability of winning just the first game = 65%
Let the probability of winning the ;
First game = p(A) = 65%
Second game = p(B)
Both games = p(A and B) = 50%
What is the probability that the team will win the 2nd game given that they have already won the first game
The above question is a conditional probability question :
Probability of winning the second Given that they've already won the first = p(B | A)
p(B | A) = (A and B) / p(A)
p(B | A) = 50% / 65%
p(B | A) = 0.5 / 0.65
p(B | A) = 0.7692307
= 76.9% = 77%
An integer minus 5 times its reciprocal is
76
9
What is the integer?
Find the perimeter of a square with a diagonal of 15√2.
Answer:
15
Step-by-step explanation:
Answer:
21.213
Step-by-step explanation:
What is the maximum value of the function f(x)=-x^2+6x+1 (enter an exact number) rotate image to see the problem
Answer:
10
Step-by-step explanation:
f(x)=-x^2+6x+1
This is a parabola that opens downward( the - coefficient of x^2)
The maximumx is at the vertex
The x coordinate is at
-b/2a where ax^2 + bx +c a =-1 b=6 c=1
-6/(2*-1)
-6/-2 = 3
The x coordinate of the vertex is 3
f(3) = - (3)^2 +6(3)=1
= -9+18+1
= 10
The vertex is ( 3,10)
The maximum value is 10
Answer:
[tex]10[/tex]
Step-by-step explanation:
[tex]f(x)=-x^2+6x+1[/tex]
x coordinate:
[tex]\frac{-b}{2a}[/tex]
[tex]a=-1\\b=6[/tex]
[tex]\frac{-6}{2(-1)} \\\frac{-6}{-2}\\ =3[/tex]
y-coordinate:
[tex]f(3)=-(3)^2+6(3)+1\\f(3)=-9+18+1\\f(3)=10[/tex]
help me solve this Algebra problem please
Answer:
39858075
Step-by-step explanation:
Hello,
One basic way to see it is to compute the values.
75 = 25 * 3
225 = 75 * 3
675 = 225 * 3
etc ...
We can notice that this is multiplied by 3 every 10 years so we can compute as below.
year population
1970 25
1980 75
1990 225
2000 675
2010 2025
2020 6075
2030 18225
2040 54675
2050 164025
2060 492075
2070 1476225
2080 4428675
2090 13286025
2100 39858075
So the correct answer is 39858075
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
PLEASE ASAP There are 20 players on a soccer team. From them, a captain and an alternate captain have to be chosen. How many possibilities are there?
Answer: 380
Step-by-step explanation:
Total number of players = 20
To select a captain and a vice captain :
One captain from a total of 20 players :
20 combination 1 = 20C1 = 20 ways
Total number of players left after selecting a captain = 20 - 1 = 19
Number of players left from which to select a vice captain = 19
Therefore, one vice captain from a group of 19 players :
19 combination 1 = 19C1 = 19 ways
Therefore no of different possible ways to select a captain and a vice captain :
20C1 × 19C1 = 20 × 19 = 380 Ways
Suppose you are interested in testing wheter the mean earning of men in the general social survey is representative of the earning of the entire U.S. Male population. If there are 372 men in the general social survey sample and approximately 128 million men in the population, calculate the degrees of freedom for this single-sample t test.
Answer:
371
Step-by-step explanation:
According to the given situation the calculation of degrees of freedom for this single-sample t test is shown below:-
Degrees of freedom is N - 1
Where N represents the number of Men
Now we will put the values into the above formula.
= 372 - 1
= 371
Therefore for calculating the degree of freedom we simply applied the above formula.
In order to win a quiz contest, Olga must score more than 400400400 points. She earns 121212 points for each right answer, and loses 444 points for each wrong answer. Write an inequality that represents the number of right answers (R)(R)left parenthesis, R, right parenthesis and wrong answers (W)(W)left parenthesis, W, right parenthesis Olga can give to win the contest.
Answer: The number of points added for r right answers is 12r. The number of points taken away for w wrong answers is 4w, so Olga's total points will be
... 12r -4w
To win, she needs this number to be more than 400. Your inequality is ...
... 12r -4w > 400
Answer:12r -4w > 400
Step-by-step explanation:
Question 4. In the graph, lines f and g intersect at P(6,6). What is the area, in square units, of the shaded region? * E. 15 F. 21 G. 27 H. 30
Answer:
E
Step-by-step explanation:
i guess the dotted lines outline a square
so get the area of the square which is 6×6=36
then don't focus on the shaded part but unshaded you'll see two right angled triangles
[tex]a = 1 \div2b \times h[/tex]
you will get a total for both as 21
then get the area of the square 36-21=15
so the area becomes 15
PLEASE HELP!
What is the length of the shortest altitude in a triangle, if the lengths of the sides are 15 cm, 17 cm, 8 cm. NO DECIMALS
Answer:
The shortest altitude = 8 cm
Step-by-step explanation:
Where we have the sides given by
15 cm, 17 cm, 8 cm
From cosine rule, we have;
a² = b² + c² - 2×b×c×cos(A)
We have
For the side 15 cm,
15² = 17² + 8² - 2×17×8 cos A
-388 = -612×cos×A
A = 61.93°
17² = 15² + 8² - 2×15×8 ×cos B
0 = -240·cos B
B = 90°
Therefore, 17 is the hypotenuse side and 15 and 8 are the legs, either of which can be the height which gives the shortest altitude as 8 cm
What is the slope of the line through the points (2,8) and (5,7)
Answer:
-1/3
Step-by-step explanation:
The slope of the line can be found by
m = (y2-y1)/(x2-x1)
= ( 7-8)/(5-2)
= -1/3
Answer:
-1/3.
Step-by-step explanation:
The slope can be found by doing the rise over the run.
In this case, the rise is 8 - 7 = 1.
The run is 2 - 5 = -3.
So, the slope is 1 / -3 = -1/3.
Hope this helps!
(05.05)
Based on the graph, what is the initial value of the linear relationship?
-4
-3
5/3
5
Answer:
5
Step-by-step explanation:
The initial value is when x=0
When x=0, y =5
The initial value is 5
The height of a right cylinder is 3 times the radius of the base. The volume of the cylinder is 24π cubic units. What is the height of the cylinder? 2 units 4 units 6 units 8 units
Answer:
6 unitsStep-by-step explanation:
Let, Radius = r units
Height ( h ) = 3r units
Volume ( V ) = 24π units³
Now,
Let's find the height of the cylinder:
[tex]\pi {r}^{2} h \: = 24\pi[/tex]
[tex] {r}^{2} (3r) = 24[/tex]
Calculate the product
[tex]3 {r}^{3} = 24[/tex]
Divide both sides of equation by 3
[tex] \frac{3 {r}^{ 3} }{3} = \frac{24}{3} [/tex]
Calculate
[tex] {r}^{3} = 8[/tex]
Write the number in the exponential form with an exponent of 3
[tex] {r}^{3} = {2}^{3} [/tex]
Take the root of both sides of the equation
[tex]r = 2[/tex]
Replacing value,
Height = 3r
[tex] = 3 \times 2[/tex]
Calculate
[tex] = 6 \: units[/tex]
Hope this helps..
Best regards!!
Answer:
[tex]\boxed{6 \: \mathrm{units}}[/tex]
Step-by-step explanation:
The formula for volume of cylinder is:
[tex]V=\pi r^2 h\\V:volume\\r:radius\\h:height[/tex]
[tex]V=24\pi\\h=3r[/tex]
Solve for r.
[tex]24\pi =\pi r^2 (3r)[/tex]
Cancel [tex]\pi[/tex] on both sides.
[tex]24=3r^3[/tex]
Divide 3 on both sides.
[tex]8=r^3[/tex]
Cube root on both sides.
[tex]2=r[/tex]
The radius of the base is 2 units.
Solve for h.
[tex]24\pi =\pi (2)^2 h[/tex]
Cancel [tex]\pi[/tex] on both sides.
[tex]24=4h[/tex]
Divide both sides by 4.
[tex]6=h[/tex]
do these problems and get 100 points 1. Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. c 22 and 15 2 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. d 13.2 and 6.7 3 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. e 34 and 12 4 Given the lengths of two sides of a triangle, find the range for the length of the third side. (Range means find between which two numbers the length of the third side must fall.) Write an inequality. f 23 and 44
Answer:
[tex]7 < x < 37[/tex] -- Triangle 1
[tex]6.5 < x < 19.9[/tex] -- Triangle 2
[tex]22 < x < 46[/tex] -- Triangle 3
[tex]21 < x < 67[/tex] -- Triangle 4
Step-by-Step Explanation:
Given
2 sides of a triangle
1. 22 and 15
2. 13.2 and 6.7
3. 34 and 12
4. 23 and 44
Required
Determine the range of the third side in the above triangles
Triangle 1: 22 and 15
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]22 + x > 15[/tex]
[tex]22 + 15 > x[/tex]
[tex]15 + x > 22[/tex]
Solving
[tex]22 + x > 15[/tex]
Make x the subject of formula
[tex]x > 15 - 22[/tex]
[tex]x > -7[/tex]
Solving
[tex]22 + 15 > x[/tex]
[tex]37 > x[/tex]
Solving
[tex]15 + x > 22[/tex]
Make x the subject of formula
[tex]x > 22 - 15[/tex]
[tex]x > 7[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]37 > x[/tex] and [tex]x > 7[/tex]
Rewrite both inequalities
[tex]x < 37[/tex] and [tex]7 < x[/tex]
Combine the two inequalities
[tex]7 < x < 37[/tex]
Triangle 2: 13.2 and 6.7
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]13.2 + x > 6.7[/tex]
[tex]13.2 + 6.7 > x[/tex]
[tex]6.7 + x > 13.2[/tex]
Solving
[tex]13.2 + x > 6.7[/tex]
Make x the subject of formula
[tex]x > 6.7 - 13.2[/tex]
[tex]x > -6.5[/tex]
Solving
[tex]13.2 + 6.7 > x[/tex]
[tex]19.9 > x[/tex]
Solving
[tex]6.7 + x > 13.2[/tex]
Make x the subject of formula
[tex]x > 13.2 - 6.7[/tex]
[tex]x > 6.5[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]19.9 > x[/tex] and [tex]x > 6.5[/tex]
Rewrite both inequalities
[tex]x < 19.9[/tex] and [tex]6.5 < x[/tex]
Combine the two inequalities
[tex]6.5 < x < 19.9[/tex]
Triangle 3: 34 and 12
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]34 + x > 12[/tex]
[tex]34 + 12 > x[/tex]
[tex]12 + x > 34[/tex]
Solving
[tex]34 + x > 12[/tex]
Make x the subject of formula
[tex]x > 12 - 34[/tex]
[tex]x > -22[/tex]
Solving
[tex]34 + 12 > x[/tex]
[tex]46 > x[/tex]
Solving
[tex]12 + x > 34[/tex]
Make x the subject of formula
[tex]x > 34 - 12[/tex]
[tex]x > 22[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]46 > x[/tex] and [tex]x > 22[/tex]
Rewrite both inequalities
[tex]x < 46[/tex] and [tex]22 < x[/tex]
Combine the two inequalities
[tex]22 < x < 46[/tex]
Triangle 4: 23 and 44
Represent the third side with x
We'll make use of the following conditions to calculate the range of the third side;
[tex]23 + x > 44[/tex]
[tex]23 + 44 > x[/tex]
[tex]23 + x > 44[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 23 - 44[/tex]
[tex]x > -21[/tex]
Solving
[tex]23 + 44 > x[/tex]
[tex]67 > x[/tex]
Solving
[tex]23 + x > 44[/tex]
Make x the subject of formula
[tex]x > 44 - 23[/tex]
[tex]x > 21[/tex]
The next step is to dismiss the inequality with negative digit; So, we're left with
[tex]67 > x[/tex] and [tex]x > 21[/tex]
Rewrite both inequalities
[tex]x < 67[/tex] and [tex]21 < x[/tex]
Combine the two inequalities
[tex]21 < x < 67[/tex]
Eric completed 1/3 of his homework before dinner and then 2/7 after dinner. How much homework did Eric complete?
The homework completed by Eric will be equal to 13/21.
What is the fraction?
The fraction is defined as the division of the whole part into an equal number of parts.
To add fractions, you first have to set the denominators equal to each other. To do this, you find the LCD (least common denominator) of the two fractions until you find a shared number.
To do this, list out the multiples of each number (3x1=3,3x2=6,3x3=9, and so on. Do this also with 7) The LCD for 3 and 7 is 21. 3x7=21, and 7x3=21. You want to set each fraction’s denominator equal to 21.
You want to multiply each side of 1/3 by 7. 1/3 would become 7/21. You’d do this because 3x7=21, and if you multiply the bottom by you need to multiply the top by. 7x3=21 so you multiply both sides by 3 to get 6/21.
Now you have 7/21 and 6/21 and can add them. Now that they are equal, you can ignore the denominator and just add the numerators. 7+6=13 so Eric completed 13/21 of his homework.
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