Solve the inequality
-6w-16>44

The 3 pack cost $9.45

3 single cartons would have cost: 3 x 4.20 = $12.60

Difference in cost: 12.60 - 9.45 = $3.15

Percent savings : 3.15/ 9.45 = 0.3333

0.333 x 109 = 33.33%

Round the answer as needed

Answer:

The tower is 73.4 m tall

Step-by-step explanation:

The height of the pole = 2.5 m

The shadow cast by the pole = 1.72 m

Shadow cast by tower = 50.5 m

To find the height of the tower, we proceed by finding the angle of elevation, θ, of the light source casting the shadows as follows;

[tex]Tan\theta =\dfrac{Opposite \ side \ to\ angle \ of \ elevation}{Adjacent\ side \ to\ angle \ of \ elevation} = \dfrac{Height \ of \ pole }{Length \ of \ shadow} =\dfrac{2.5 }{1.72}[/tex]

[tex]\theta = tan ^{-1} \left (\dfrac{2.5 }{1.72} \right) = 55.47 ^{\circ}[/tex]

The same tanθ gives;

[tex]Tan\theta = \dfrac{Height \ of \ tower}{Length \ of \ tower \ shadow} =\dfrac{Height \ of \ tower }{50.5} = \dfrac{2.5}{1.72}[/tex]

Which gives;

[tex]{Height \ of \ tower } = {50.5} \times \dfrac{2.5}{1.72} = 73.4 \ m[/tex]

Answer:

Step-by-step explanation:

If the second angle's measure is based on the first angle's measure, and the third angle's measure is also based on the first angle's measure, then the first angle is the main angle. We will call that x.

1st angle: x

2nd angle: x + 20%

3rd angle: x - 20%

By the Triangle Angle-Sum Theorem, all those angles will add up to 180, so:

x + (x + 20%) + (x - 20%) = 180 and

3x = 180 so

x = 60. That means that

2nd angle: 60 + (.2*60) which is

60 + 12 = 72 and

3rd angle: 60 - (.2*60) which is

60 - 12 = 48. Let's check those angles. If

∠1 = 60

∠2 = 72

∠3 = 48,

then ∠1 + ∠2 + ∠3 = 180 and

60 + 72 + 48 does in fact equal 180, so you're done!

Answer:

18- 14+8=3x

4+8=3x

12=3x

12/3=2x/3

x=4

Answer:

2/3, -8, -1/6, 4.

Step-by-step explanation:

Step-by-step explanation:

The rational root theorem states that if the leading coefficient is taken to be an and the constant coefficient is taken to be a0 the possible roots of the equation can be expressed as :

Now, from the given options, the possible choices can be :

A, B, C and E

D can be there because after taking any pair the rational root can't be 3

F can't be possible because an does't have 4 in its factors so denominator cannot be 4.

Answer:

58.5

Step-by-step explanation:

Distance = rate * time

so if it's 4.5 hours:

Distance = 13 mph* 4.5 hours

= 58.5 miles

Answer:

6√5

Step-by-step explanation:

We have to solve the expression [tex]\sqrt{180}[/tex]

Break 180 into its factors which are in the perfect square form.

Since, 180 = 9 × 4 × 5

                 = 3² × 2² × 5

Therefore, [tex]\sqrt{180}=\sqrt{3^{2}\times 2^{2}\times 5}[/tex]

                           = [tex]\sqrt{3^2}\times \sqrt{2^{2}}\times \sqrt{5}[/tex] [Since [tex]\sqrt{ab}=\sqrt{a}\times \sqrt{b}[/tex]]

                           = 3 × 2 × √5

                           = 6√5

Therefore, solution of the given square root will be 6√5.

Answer:

The standard form of the equation is y = -x/2 -2

Step-by-step explanation:

The standard form of equation of this line is expressing the line in the form;

y = mx + c

So let’s make a rearrangement to what we have at hand;

y + 7 = -1/2(x-10)

2(y + 7) = -1(x-10)

2y + 14 = -x + 10

2y = -x + 10 -14

2y = -x -4

divide through by 2

y = -x/2 -2

Answer:

4kg

Step-by-step explanation:

...../...../

2kg + half of its weight

so half of its weight = 2kg

so 2kg + 2kg= 4kg the weight of the fish

Answer:

The center is ( 1,-3) and the radius is 3

Step-by-step explanation:

The equation of a circle can be written in the form

( x-h)^2 + ( y-k) ^2 = r^2 where ( h,k) is the center and r is the radius

(x-1)^2 + (y+3)^2= 9

(x-1)^2 + (- -3)^2= 3^2

The center is ( 1,-3) and the radius is 3

Answer:

152.87 degree/seconds

Step-by-step explanation:

1 rotation = Circumference of a circle = 2πr

r = 15 inches

1 rotation = 2 × 3.14 × 15

94.2 inches.

We are told in the question that it takes 30 seconds to roll 100 feet along the ground

Convert feet to inches

1 feet = 12 inches

100 feet =

100 × 12 = 1200 inches.

Hence, if

94.2 inches = 1 rotation

1200 inches = X

Cross multiply

94.2 × X = 1200 × 1

94.2X = 1200

X = 1200/94.2

X = 12.738853503 rotations

Formula for Angular velocity = Number of rotations × 2π/time in seconds

Time = 30 seconds

12.738853503 × 2 × 3.14/30

= 2.6666666667 rotations per second

Converting Angular velocity to degree per second

= 2.6666666667 × 180/ π

= 2.6666666667 × 180/3.14

= 152.86624204 degree/seconds

Approximately to 2 decimal places

= 152.87 degree/seconds

Answer:  Perimeter = 8π  ≈ 25.12

                        Area = 12π ≈ 37.68

Step-by-step explanation:

This is a composite of two figures.

The bigger figure is a quarter-circle with radius (r) = 8 cm

The smaller figure is a quarter-circle with diameter = 8 cm --> r = 4

Perimeter of a quarter-circle = [tex]\dfrac{1}{4}(2\pi r)[/tex] = [tex]\dfrac{\pi r}{2}[/tex]

Perimeter of composite figure = bigger - smaller figure

[tex]P_{bigger}=2\pi(8)\quad = 16\pi\\P_{smaller}=2\pi(4)\quad =8\pi\\P_{composite}=16\pi-8\pi \\.\qquad \qquad = \large\boxed{8\pi}[/tex]

Area of a quarter-circle = [tex]\dfrac{1}{4}\pi r^2[/tex]

[tex]A_{bigger}=\dfrac{1}{4}\pi (8)^2\quad =16\pi\\\\A_{smaller}=\dfrac{1}{4}\pi (4)^2\quad =4\pi\\\\A_{composite}=16\pi-4\pi\\.\qquad \qquad = \large\boxed{12\pi}[/tex]

Answer:

Hey there!

Triangle PQT and RQT are congruent by AAS. AAS means that one side is congruent, and two angles are congruent.

Since these triangles share one side, then the side is congruent.

PR is a straight line, so if angle Q is 90 degrees, then the supplementary angle is also 90 degrees.

Finally, the diagram shows that angles R and P are congruent to each other.

Hope this helps :)

Answer:

Step-by-step explanation:

We'll just work on solving both so you can see what's involved in solving an absolute value equation. Because an absolute value is a distance, we can have that distance being both to the right on the number line of the number in question or to the left. For example, from 2 on the number line, the numbers that are 5 units away are 7 and -3. Using that logic, we will simplify the equation down so we can set up the 2 basic equations needed to solve for x.

If  [tex]3-2|.5x+1.5|=2[/tex] then

[tex]-2|.5x+1.5|=-1[/tex]  What you need to remember here is that you cannot distribute into a set of absolute values like you would a set of parenthesis. The -2 needs to be divided away:

[tex]|.5x+1.5|=.5[/tex]

Now we can set up the 2 main equations for this which are

.5x + 1.5 = .5  and .5x + 1.5 = -.5

Knowing that an absolute value will never equal a negative number (because absolute values are distances and distances will NEVER be negative), once we remove the absolute value signs we can in fact state that the expression on the left can be equal to a negative number on the right, like in the second equation above.

Solving the first one:

.5x = -1 so

x = -2

Solving the second one:

.5x = -2 so

x = -4

We want to find the other solution of the given absolute value equation.

The other solution is x = -4

We know that:

3 - 2*|0.5*x + 1.5| = 2

It has one solution given by:

- 2*|0.5*x + 1.5| = 2 - 3 = -1

|0.5*x + 1.5| = 0.5

0.5*x + 1.5 = 0.5

0.5*x = 0.5 - 1.5 = -1

0.5 = -1/x

Then we have x = -2

To get the other solution we need to remember that an absolute value equation can be written as:

|x - a| = b

or:

(x - a) = b

(x - a) = -b

Then the other solution to our equation comes from:

|0.5*x + 1.5| = 0.5

(0.5*x + 1.5) = -0.5

0.5*x = -0.5 - 1.5 = -2

x = -2/0.5 = -4

The other solution is x = -4

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Answer:

A

Step-by-step explanation:

[tex]f(x) = 20 {e}^{x} [/tex]

The function that could have the graph shown is:

f(x) = 20[tex]e^x[/tex]

Option A is the correct answer.

A function has an input and an output.

A function can be one-to-one or onto one.

It simply indicated the relationships between the input and the output.

Example:

f(x) = 2x + 1

f(1) = 2 + 1 = 3

f(2) = 2 x 2 + 1 = 4 + 1 = 5

The outputs of the functions are 3 and 5

The inputs of the function are 1 and 2.

We have,

The function:

f(x) = 20[tex]e^x[/tex]

If we graph this function we get a similar graph that is shown.

The coordinates of f(x) = 20 [tex]e^x[/tex] are:

To find the coordinates, we need to plug in different values of x into the function and calculate the corresponding y-values.

For example, when x = 0, we have:

f(0) = 20e^0 = 20(1) = 20

So one coordinate on the graph is (0, 20).

Similarly, when x = 1, we have:

f(1) = 20e^1 = 20e = 20(2.71828) ≈ 54.6

So another coordinate on the graph is (1, 54.6).

We can find more coordinates by plugging in other values of x and calculating the corresponding y-values.

Now,

As x increases, the function f(x) grows exponentially, meaning the y-values will increase very rapidly.

Thus,

The function f(x) = 20[tex]e^x[/tex] could have the graph shown.

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Answer:  Perimeter = 6π ≈ 18.84

                         Area = 15π ≈ 47.10

Step-by-step explanation:

This is a composite of a big semicircle with diameter of 10 --> radius (r) = 5

plus a medium semicircle with diameter of 6 --> r = 3

minus a small semicircle with diameter of 4 --> r = 2

Perimeter of a semicircle = [tex]\dfrac{1}{2}(2\pi r)=\pi r[/tex]

[tex]P_{big}=\pi (5)\quad =5\pi\\P_{medium}=\pi (3)\quad =3\pi\\P_{small}=\pi (2)\quad =2\pi\\P_{composite} =5\pi+3\pi -2\pi\\.\qquad \qquad =\large\boxed{6\pi}[/tex]

Area of a semicircle = [tex]\dfrac{1}{2}(\pi r^2)[/tex]

[tex]A_{big}=\dfrac{1}{2}\pi (5)^2\quad =12.5\pi\\\\A_{medium}=\dfrac{1}{2}\pi (3)^2\quad =4.5\pi\\\\A_{small}=\dfrac{1}{2}\pi (2)^2\quad =2\pi\\\\A_{composite} =12.5\pi+4.5\pi -2\pi\\\\.\qquad \qquad =\large\boxed{15\pi}[/tex]

Answer:

One

Step-by-step explanation:

y = 3 x - 5.

y = -x + 4.

x=9/4 and y=7/4

1 solution (9/4 , 7/4)

For a system of the equation to be an Independent Consistent System, the system must have one unique solution. The system of the equation has only one solution. Thus, the correct option is A.

Inconsistent System

For a system of equations to have no real solution, the lines of the equations must be parallel to each other.

Consistent System

1. Dependent Consistent System

For a system of the equation to be a Dependent Consistent System, the system must have multiple solutions for which the lines of the equation must be coinciding.

2. Independent Consistent System

For a system of the equation to be an Independent Consistent System, the system must have one unique solution for which the lines of the equation must intersect at a particular.

Given the two equations y=3x -5 and y=-x+4. If the two of the equations are plotted on the graph. Then it can be observed from the graph that there is only one intersection between the two lines.

Hence, the system of the equation has only one solution. Thus, the correct option is A.

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Answer:

The equation is  y = -x + 4

Step-by-step explanation:

This is a very trivial exercise:

The general equation of a line is given by:

y - y₁ = m(x - x₁)

where m = slope of the linear graph

From the given graph, it can be observed that the coordinate (x₁, y₁) and (x₂, y₂) are (0, 4) and (4, 0)

The slope, m = (y₂ - y₁)/(x₂ - x₁)

m = (0 - 4)/(4 - 0)

m = -4/4

m = -1

Substituting the values of (x₁, y₁) = (0, 4) and m = -1 into the general equation:

y - y₁ = m(x - x₁)

y - 4 = -1 (x - 0)

y - 4 = -x

y = -x + 4

Answer:

option D 25 is the right answer

Answer:  D) 25

Step-by-step explanation:

I graphed the coordinates and partitioned it into four triangles and one rectangle. Then I found the area for each partition.

The sum of the partitions is 25.

Answer:

1: 90º

2: 25º

Step-by-step explanation:

Hey there!

Well we know that all the middle angles are 90º right angles,

so we can conclude that angle 1 is 90º.

All the angles in a triangle add up to 180 so we can set up the following,

65 + 90 + x = 180

Combine like terms

155 + x = 180

-155 to both sides

x = 25º

So angle 2 is 25º.

Hope this helps :)

Answer:

Below

Step-by-step explanation:

From the kite you easily notice that 1 is a right angle so its mesure is 90°.

2 is inside a triangle. This triangke has two khown angles: a right one and a 65° one.

The sum of a triangle's angles is 180°.

● (2) + 90+65 = 180

● (2) +155 =180

● (2)= 180-155

●(2) = 25°

Answer:

[tex]$\arcsin\left(\frac{129\sqrt{2}}{250}\right)\approx 0.8179$[/tex]

Step-by-step explanation:

[tex]\alpha \text{ and } \beta \text{ in Quadrant I}[/tex]

[tex]$\tan(\alpha)=\frac{1}{7} \text{ and } \sin(\beta)=\frac{1}{\sqrt{10}}=\frac{\sqrt{10} }{10} $[/tex]

Using Pythagorean Identities:

[tex]\boxed{\sin^2(\theta)+\cos^2(\theta)=1} \text{ and } \boxed{1+\tan^2(\theta)=\sec^2(\theta)}[/tex]

[tex]$\left(\frac{\sqrt{10} }{10} \right)^2+\cos^2(\beta)=1 \Longrightarrow \cos(\beta)=\sqrt{1-\frac{10}{100}} =\sqrt{\frac{90}{100}}=\frac{3\sqrt{10}}{10}$[/tex]

[tex]\text{Note: } \cos(\beta) \text{ is positive because the angle is in the first qudrant}[/tex]

[tex]$1+\left(\frac{1 }{7} \right)^2=\frac{1}{\cos^2(\alpha)} \Longrightarrow 1+\frac{1}{49}=\frac{1}{\cos^2(\alpha)} \Longrightarrow \frac{50}{49} =\frac{1}{\cos^2(\alpha)} $[/tex]

[tex]$\Longrightarrow \frac{49}{50}=\cos^2(\alpha) \Longrightarrow \cos(\alpha)=\sqrt{\frac{49}{50} } =\frac{7\sqrt{2}}{10}$[/tex]

[tex]\text{Now let's find }\sin(\alpha)[/tex]

[tex]$\sin^2(\alpha)+\left(\frac{7\sqrt{2} }{10}\right)^2=1 \Longrightarrow \sin^2(\alpha) +\frac{49}{50}=1 \Longrightarrow \sin(\alpha)=\sqrt{1-\frac{49}{50}} = \frac{\sqrt{2}}{10}$[/tex]

The sum Identity is:

[tex]\sin(\alpha + \beta)=\sin(\alpha)\cos(\beta)+\sin(\beta)\cos(\alpha)[/tex]

I will just follow what the question asks.

[tex]\text{Find the value of }\alpha+2\beta[/tex]

[tex]\sin(\alpha + 2\beta)=\sin(\alpha)\cos(2\beta)+\sin(2\beta)\cos(\alpha)[/tex]

[tex]\text{I will first calculate }\cos(2\beta)[/tex]

[tex]$\cos(2\beta)=\frac{1-\tan^2(\beta)}{1+\tan^2(\beta)} =\frac{1-(\frac{1}{7})^2 }{1+(\frac{1}{7})^2}=\frac{24}{25}$[/tex]

[tex]\text{Now }\sin(2\beta)[/tex]

[tex]$\sin(2\beta)=2\sin(\beta)\cos(\beta)=2 \cdot \frac{\sqrt{10} }{10}\cdot \frac{3\sqrt{10} }{10} = \frac{3}{5} $[/tex]

Now we can perform the sum identity:

[tex]\sin(\alpha + 2\beta)=\sin(\alpha)\cos(2\beta)+\sin(2\beta)\cos(\alpha)[/tex]

[tex]$\sin(\alpha + 2\beta)=\frac{\sqrt{2}}{10}\cdot \frac{24}{25} +\frac{3}{5} \cdot \frac{7\sqrt{2} }{10} = \frac{129\sqrt{2}}{250}$[/tex]

But we are not done yet! You want

[tex]\alpha + 2\beta[/tex] and not [tex]\sin(\alpha + 2\beta)[/tex]

You actually want the

[tex]$\arcsin\left(\frac{129\sqrt{2}}{250}\right)\approx 0.8179$[/tex]

Answer:

ok bye guy................

Answer:

-3

Step-by-step explanation:

[tex]F(x)=-\,(-x)\\f(-3)=-(-(-3))\\f(-3)=-3[/tex]

Answer:

Step-by-step explanation:

Any non-parallel lines in the plane must intersect in one place; thus, there is one solution to the system of equations.

Answer:

x = 1

Step-by-step explanation:

Given

[tex]\frac{1}{2}[/tex] : [tex]\frac{2}{3}[/tex] = [tex]\frac{3}{4}[/tex] : x

Multiply all parts by 12 to clear the fractions

6 : 8 = 9 : 12x , simplifying

3 : 4 = 3 : 4x

Thus

4x = 4 ( divide both sides by 4 )

x = 1

Answer:

[tex] Area = 1,309.0 in^2 [/tex]

Step-by-step explanation:

Given:

∆TUV

m < U = 22°

TV = u = 47 in

m < V = 125°

Required:

Area of ∆TUV

Solution:

Find the length of UV using the Law of Sines

[tex] \frac{t}{sin(T)} = \frac{u}{sin(U)} [/tex]

U = 22°

u = TV = 47 in

T = 180 - (125 + 22) = 33°

t = UV = ?

[tex] \frac{t}{sin(33)} = \frac{47}{sin(22)} [/tex]

Multiply both sides by sin(33)

[tex] \frac{t}{sin(33)}*sin(33) = \frac{47}{sin(22)}*sin(33) [/tex]

[tex] t = \frac{47*sin(33)}{sin(22)} [/tex]

[tex] t = 68 in [/tex] (approximated)

[tex] t = UV = 68 in [/tex]

Find the area of ∆TUV

[tex] area = \frac{1}{2}*t*u*sin(V) [/tex]

[tex] = \frac{1}{2}*68*47*sin(125) [/tex]

[tex] = \frac{68*47*sin(125)}{2} [/tex]

[tex] Area = 1,309.0 in^2 [/tex] (to nearest tenth).

Answer:

C

Step-by-step explanation:

In a function, each domain has one range. But a range can have many domains.

Think about it like this:

Patty is eating dinner

Patty is swimming

Both can't happen at the same time.

But:

Patty is eating dinner

Leo is eating dinner

C has two domains of -3, each having different ranges.

Hope that helps, tell me if you need further info. =)

Answer:

C. C{(6,-9),(-3,6),(-3,-7),(-9, -2)}

Step-by-step explanation:

If you see the same x-coordinate used more than once, it is not a function.

Here, you only see this in choice C, where x = -3 for two points. That makes this relation not a function.

Answer: hypotenuse = [tex]c^{2} + b^{2}[/tex]

Step-by-step explanation: Pythagorean theorem states that square of hypotenuse (h) equals the sum of squares of each side ([tex]s_{1},s_{2}[/tex]) of the right triangle, .i.e.:

[tex]h^{2} = s_{1}^{2} + s_{2}^{2}[/tex]

In this question:

[tex]s_{1}[/tex] = [tex]c^{2}-b^{2}[/tex]

[tex]s_{2} =[/tex] 2bc

Substituing and taking square root to find hypotenuse:

[tex]h=\sqrt{(c^{2}-b^{2})^{2}+(2bc)^{2}}[/tex]

Calculating:

[tex]h=\sqrt{c^{4}+b^{4}-2b^{2}c^{2}+(4b^{2}c^{2})}[/tex]

[tex]h=\sqrt{c^{4}+b^{4}+2b^{2}c^{2}}[/tex]

[tex]c^{4}+b^{4}+2b^{2}c^{2}[/tex] = [tex](c^{2}+b^{2})^{2}[/tex], then:

[tex]h=\sqrt{(c^{2}+b^{2})^{2}}[/tex]

[tex]h=(c^{2}+b^{2})[/tex]

Hypotenuse for the right-angled triangle is [tex]h=(c^{2}+b^{2})[/tex] units

The expression for the length of the hypotenuse is [tex]c^2+ b^2 \ units[/tex].

Given that,

A right-angled triangle has shorter side lengths exactly [tex]c^{2} - b^{2}[/tex] and 2bc units respectively,

Where b and c are positive real numbers such that c is greater than b.

We have to determine,

An exact expression for the length of the hypotenuse?

According to the question,

The Pythagoras theorem states that the sum of the hypotenuse in the right-angled triangle is equal to the sum of the square of the other two sides.

A right-angled triangle has shorter side lengths exactly [tex]c^{2} - b^{2}[/tex] and 2bc units respectively,

Where b and c are positive real numbers such that c is greater than b.

Therefore,

The expression for the length of the hypotenuse is,

[tex]\rm (Hypotenuse)^2 = (c^2-b^2)^2+ (2bc)^2\\\\(Hypotenuse)^2 = c^4+ b^4 - 2c^2b^2 + 4c^2b^2\\\\(Hypotenuse)^2 = c^4+ b^4 +2c^2b^2 \\\\Hypotenuse = \sqrt{c^4+ b^4 +2c^2b^2}\\\\\ Hypotenuse = \sqrt{(c^2+ b^2)^2}\\\\ Hypotenuse = c^2+b^2 \ units[/tex]

Hence, The required expression for the length of the hypotenuse is [tex]c^2+ b^2 \ units[/tex].

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Answer:

112 weeks

Step-by-step explanation:

784/7=112

Answer:

112 weeks............

Answer:

y = StartFraction 5 Over 9 EndFraction

y=5/9

Step-by-step explanation:

Given:

x+6y=20

-x+3y=-15

x+6y=20. (1)

-x+3y=-15 (2)

From (1)

x=20-6y

Substitute x=20-6y into (2)

-x+3y=-15

-(20-6y)+3y = -15

-20+6y+3y = -15

9y=-15+20

9y=5

Divide both sides by 9

9y/9=5/9

y=5/9

y = StartFraction 5 Over 9 EndFraction

Answer:

y=-5/9

Step-by-step explanation:

9y=-5

---------- Divided by 9

9      9  

Y is equal to negative five over 9

Have a good day and stay safe!

Answer:

8

Step-by-step explanation:

3x^2 - 4

Let x = 2

3 * 2^2 -4

Exponents first

3 *4 -4

Then multiply

12 -4

Now subtract

8

[tex]\text{Plug in and solve:}\\\\3(2)^2-4\\\\3(4)-4\\\\12-4\\\\8\\\\\boxed{\text{D). 8}}[/tex]