Skajekjejejwjejekwjkekekekejeje

Answer:

He will have 8 50-cent coins

Step-by-step explanation:

Let x = the number of 10-cent coins

Let y = the number of 50-cent coins

x + y = 20         y = 20 - x

[Set up an equation] .10x + .50y = 6.80

[Multiply both sides by 100] 10x + 50y = 680

[Plug-in] 10x + 50(20 - x) = 680

[Multiply] 10x + 1,000 - 50x = 680

[Combine like terms & subtract 1,000 from both sides] -40x = -320

[Divide both sides by -40] x = 8 coins

Have a nice day! - hopefully this is correct, I got a bit turned around for a bit lol

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

1=56⁰

2=56⁰

3=68⁰

4=68⁰

5=56⁰

6=112⁰

7=180-124 Ans=56⁰

8=68+56 Ans=124⁰

9=68⁰

10=112⁰

11=124⁰

12=56⁰

Answer:

17, 19 and 21

Step-by-step explanation:

17 + 19 + 21 = 57

Answer:

The answer is -4a + 26b +3

Answer:

161oz = 10.0625 (then you round)

Step-by-step explanation:

Answer:66

Step-by-step explanation:

The magnitude of a vector a is the length of the vector.

We write it ||a||

We can draw a right triangle and apply the pythagoras theorem. The magnitude of a will be the hypotenuse :

||a||² = 3² + 3²

||a||² = 9 + 9

||a||² = 18

||a|| = √18 = √(9*2) = 3√2 ≈ 4.24

So the answeer is 4.24

Good Luck

Answer:

I can't see the problem I am blind but still very hard to see it's not quite clear

15 days

Step-by-step explanation:

The half-life equation is given as

[tex]m(t) = m(0)e^{-0.073t}[/tex] (1)

where m(0) is the initial mass of radioactive iodine at t = 0. To solve for the time t, let's put the exponential part on the left-hand side:

[tex]e^{-0.073t} = \dfrac{m(t)}{m(0)}[/tex]

Taking the natural logarithm of both sides to get

[tex]\ln{e^{-0.073t}} = \ln\left[\dfrac{m(t)}{m(0)}\right][/tex] (2)

Recall the following properties of logarithms:

[tex]\ln{A}^b = b\ln{A}[/tex]

[tex]\ln{e} = 1[/tex]

We can rewrite Eqn(2) as

[tex]-0.073t = \ln\left[\dfrac{m(t)}{m(0)}\right][/tex]

Solving for t, we get

[tex]t = -\dfrac{1}{0.073}\ln\left[\dfrac{m(t)}{m(0)}\right][/tex]

Since m(0) = 15 gm and m(t) = 5 gm, then the amount of time that elapses to reduce the mass down to 5 gm is

[tex]t = -\dfrac{1}{0.073}\ln\left(\dfrac{5\:\text{g}}{15\:\text{g}}\right)[/tex]

[tex]\:\:\:\:\:= 15\:\text{days}[/tex]

The expected value of the game is the mean value of the game

The expected value of the game is $9

For the first spinner;

For the second spinner;

So, the probability of spinning a 2 and a vowel is:

[tex]\mathbf{P(2\ and\ vowel) = \frac 14 \times \frac 14 = \frac{1}{16}}[/tex]

The earning for spinning a 2 and a vowel is $39.

So, the expected earning is:

[tex]\mathbf{Expected = 39 \times \frac{1}{16} = 2.4375}[/tex]

So, the probability of spinning a 2 and a consonant is:

[tex]\mathbf{P(2\ and\ consonant) = \frac 14 \times \frac 34 = \frac{3}{16}}[/tex]

The earning for spinning a 2 and a consonant is $26.

So, the expected earning is:

[tex]\mathbf{Expected = 26 \times \frac{3}{16} = 4.875}[/tex]

So, the probability of spinning a 1 and a vowel is:

[tex]\mathbf{P(1\ and\ vowel) = \frac 34 \times \frac 14 = \frac{3}{16}}[/tex]

The earning for spinning a 1 and a vowel is $9.

So, the expected earning is:

[tex]\mathbf{Expected = 9 \times \frac{3}{16} = 1.6875}[/tex]

So, the expected value of the game is:

[tex]\mathbf{Game =2.4375+ 4.875 + 1.6875}[/tex]

[tex]\mathbf{Game =9}[/tex]

Hence, the expected value of the game is $9

Read more about expected values at:

https://brainly.com/question/13499496

Answer:

[tex]f(-3)=343[/tex]

Step-by-step explanation:

[tex]f(x)=(\frac{1}{7} )^x[/tex]

Plug -3 into x and solve using the negative power rule:

[tex]x^{-a}=\frac{1}{x^a}[/tex]

[tex]f(-3)=(\frac{1}{7} )^{-3} \\\\f(-3)=\frac{1}{\frac{1}{7}^3 } \\\\f(-3)=\frac{1}{\frac{1}{343} } \\\\f(-3)=343[/tex]

Sorry, those fractions got very small. Let me know if I need to clarify anything there

Answer:

false i think

Step-by-step explanation:

16+1=17-1=16-2=14

Answer:

Drayven has more

Step-by-step explanation:

If you look at the fractions through a drawing you would see that my claim is correct.

Answer:

4x + 2y ≤ 20

Step-by-step explanation:

x = burger

y = fries

a.    4x + 2y ≤ 20      at most means ≤

~fractions

=============

5/6

= 5 ÷ 6

= 0,83333333333

rounded to

= 0,833 ✔️

~ nice to help you ^^

Answer:

⅚ = ...

= 5 ÷ 6

[tex] \approx \bold{0.833}[/tex]

11+x=48

x=48-11

x= 37

[tex] 😘 \: 😉 \: 😈 \; 😫 \: 😤 \: 😡 \: 😘[/tex]

Answer:

He will need 1 and 2/3 boxes

Step-by-step explanation:

1/5= 1/3 boxes

5/5= 1/3* 5 boxes

Hope this helps!

Let me know if it does

Answer:

48

Step-by-step explanation:

Step-by-step explanation:

It is represented by ,

=> y ≥ 1/4x -1

Answer:

234 millimeters^2 is the answer

Step-by-step explanation:

Answer:4x -9 >= -21

4x >= -12

x >= -12/4

x >= -3  

so this number line started with -3 and go away till + infinity  

hope this will help you

Answer:

D

Step-by-step explanation: srry if im wrong

a = 18

d = 16 - 18 = - 2

an = a + (n - 1) × d

an = 18 + (n - 1) × (-2)

an = 18 - 2n + 2

an = -2n + 20

Answer:

i wrote answer of the question 1 to 4 but i don't know the answer to 5

Answer: 1) (3,0) 2) (4,2) 3) (5,1) not sure about 4 and 5

1) (3,7/2) 2) (1,-4) 3) (-3,2) im bad at word problems, sorry.

Step-by-step explanation: all i can say without sounding confusing is divide on both sides!! <3

[tex]▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪[/tex]

Let's simply the given expression ~

I think it wants you to remove the squares.

See if this works :)

Answer:

-3/25

Step-by-step explanation:

[- 3 / 5 ] / 5

- 3

5

-------

5

1

-------------------

- 3 x 1 = -3

5 x 5 = 25

-------------------

-3 / 25

Answer:  6a3b3

Step-by-step explanation:

Reformatting the input:

Changes made to your input should not affect the solution:

(1): "0.6" was replaced by "(6/10)".

STEP 1:

Equation at the end of step 1

       6

 0-(((——•(a2))•b)•(0-(2•5ab2)))

      10

STEP 2:

           3

Simplify   —

           5

Equation at the end of step 2:

         3

 0 -  (((— • a2) • b) • ( -2•5ab2))

         5

STEP 3:

Equation at the end of step 3

        3a2

 0 -  ((——— • b) • ( -2•5ab2))

         5

STEP 4:

Multiplying exponential expressions :

4.1    a2 multiplied by a1 = a(2 + 1) = a3

Multiplying exponential expressions :

4.2    b1 multiplied by b2 = b(1 + 2) = b3

Canceling Out:

4.3      Canceling out  5  as it appears on both sides of the fraction line

Equation at the end of step 4:

 0 -  -6a3b3

STEP 5:

Final result :

 6a3b3