Select the two statements that are true about the equation y − 10 = 60(x − 40).

A. The slope of the line is 10.
B. The slope of the line is 60.
C. One point on the line is (40, 10).
D. One point on the line is (10, 60).

Answer:

Step-by-step explanation:

The difference is the filling rate with both lines open:

The pool is 2/3 full and needs filling the remainder, 1/3.

Time required to fill:

Answer:

33.176

Step-by-step explanation:

Answer:

the equation is not completed

Answer:

-20

Step-by-step explanation:

Multiply 4x5 which is 20 but since 5 is negative then it's -20

Answer: The time is 20:15 on a military time clock.

Step-by-step explanation:

The equation of a line is written as t = ax + b where a is the slope and b is the y-intercept.

Using the slope and y intercept given the equation is:

Y = 3x + 2

Answer:

48

Step-by-step explanation:

6 + 14 ÷ 7

= 8

= 8 _ 2× 3

= 8_ 6

=8×6

=48

Derivatives can be calculated from graphed functions.

The values of the derivatives are:

The given parameter is:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Start by calculating the equations of f(x) and g(x)

Graph f(x)

The slopes of f(x) are: 3/2 and -3/2

So, the equations are:

[tex]\mathbf{f(x) = \frac{3}{2}x,\ 0 \le x \le 2}[/tex]

[tex]\mathbf{f(x) = -\frac{3}{2}x,\ x \ge 2}[/tex]

Graph g(x)

The slope of g(x) is: -1/2

So, the equation is:

[tex]\mathbf{g(x) = -\frac 12x}[/tex]

For x = 1 and x = 2, we have:

So, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = \frac{3}{2}x\ 0 \le x \le 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = \frac{3}{2}(-\frac{1}{2}x)}[/tex]

Open brackets

[tex]\mathbf{h(x) = -\frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = -\frac{3}{4}}[/tex]

So:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex]

[tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex]

For x = 3, we have:

[tex]\mathbf{h(x) = f(g(x))}[/tex]

Where:

[tex]\mathbf{f(x) = -\frac{3}{2}x\ x \ge 2}[/tex] and [tex]\mathbf{g(x) = -\frac 12x}[/tex]

[tex]\mathbf{h(x) = f(g(x))}[/tex] becomes

[tex]\mathbf{h(x) = -\frac{3}{2}(-\frac{1}{2}x)}[/tex]

[tex]\mathbf{h(x) = \frac{3}{4}x}[/tex]

Differentiate

[tex]\mathbf{h'(x) = \frac{3}{4}}[/tex]

Substitute 3 for x

[tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Hence, the values of the derivatives are:

[tex]\mathbf{h'(1) = -\frac{3}{4}}[/tex], [tex]\mathbf{h'(2) = -\frac{3}{4}}[/tex] and [tex]\mathbf{h'(3) = \frac{3}{4}}[/tex]

Read more about graphed functions at:

https://brainly.com/question/11804653

Answer:

metric po

Step-by-step explanation:

measurements and metric units of measure

Answer:

4u³

Step-by-step explanation:

2/3u × 4/2u² = 4/3u³

4/3u³ × 3/1 = 4u³

Answer:

Step-by-step explanation:

Answer:

your answer is 3/15

Step-by-step explanation:

if im wrong pls let me know

Answer:

29in

pls give brainliest tq

have a great day

Answer:

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

Step-by-step explanation:

(p2qr+pq2r+pqr2)((−p)(q)+qr+−pr)

(p2qr)((−p)(q))+(p2qr)(qr)+(p2qr)(−pr)+(pq2r)((−p)(q))+(pq2r)(qr)+(pq2r)(−pr)+(pqr2)((−p)(q))+(pqr2)(qr)+(pqr2)(−pr)

−p3q2r+p2q2r2−p3qr2−p2q3r+pq3r2−p2q2r2−p2q2r2+pq2r3−p2qr3

−p3q2r−p3qr2−p2q3r−p2q2r2−p2qr3+pq3r2+pq2r3

[tex]\large\underline{\sf{Solution-}}[/tex]

Given that:

[tex]\sf\longmapsto(p^2qr+pq^2r+pqr^2)(-pq+qr-pr)[/tex]

Opening the brackets,

[tex]\sf\longmapsto p^2qr(-pq+qr-pr) + pq^2r(-pq+qr-pr) + pqr^2(-pq+qr-pr)[/tex]

Opening the next brackets,

[tex]\sf\longmapsto p^2qr(-pq)+ p^2qr(qr)- p^2qr(pr) + pq^2r(-pq)+ pq^2r(qr)- pq^2r(pr) + pqr^2(-pq)+ pqr^2(qr)- pqr^2(pr)[/tex]

So,

[tex]\sf\longmapsto -p^3q^2r+ p^2q^2r^2- p^3qr^2 - p^2q^3r+ pq^3r^2- p^2q^2r^2-p^2q^2r^2+ pq^2r^3- p^2qr^3[/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3+ p^2q^2r^2-2p^2q^2r^2 [/tex]

[tex]\sf\longmapsto -p^3q^2r- p^3qr^2 - p^2q^3r+ pq^3r^2+ pq^2r^3- p^2qr^3- p^2q^2r^2 [/tex]

Hence, the product is,

[tex]\longmapsto\bf -p^3q^2r- p^3qr^2 - p^2q^3r- p^2qr^3+ pq^3r^2+ pq^2r^3 - p^2q^2r^2 [/tex]

Answer: January, because negative numbers are positive numbers' opposite; so -11.4 < -10.4

Answer: POSSIBLY B

Step-by-step explanation:

Answer:

Coordinates A and B: (1, 0) and (3, 0)

Coordinates of P: (0, 3)

Coordinates of Q: (2, -1)

Step-by-step explanation:

You're pretty much given the x-intercepts from the original equation.

y = (x - 1)(x - 3). So to get the x-intercepts (points A and B), y has to equal 0. So,

0 = (x - 1)(x - 3).

and y = 0 when x equals 1 and 3. Because anything multiplied by 0 equals 0. So substituting 1 for the value of x, for example, we get:

0 = (1 - 1)(1 - 3)

0 = 0 * (-2)

So there are your x-intercepts, points A and B.

Now,

Expand the brackets of the equation.

y = (x - 1)(x - 3) becomes

y = x^2  -  4x  + 3

You get the y-intercept (point P) by substituting 0 for the value of x. Doing so gives:

y = 0^2 - 4*0 + 3

y = 0 - 0 + 3

y = 3

So, we have our y-intercept (0, 3).

Point Q, the x-coordinate of the vertex is calculated with the equation -b/2a

Taking our expanded equation: x^2 - 4x + 3

which is of the form ax^2 + bx + c

So we find the values of a, b and c and input the values into the equation

a = 1

b = -4

c = 3

So, inputting these into the vertex equation, gives:

-(-4) / 2 * 1

4 / 2

2

So we have the x-coordinate of the vertex. Now that we know that, we can just substitute it into the expanded equation to give the y-coordinate:

y = 2^2 - 4*2 + 3

y = 4 - 8 + 3

y = -1

So there's our y-coordinate, and now we have both the x and y coordinate for the vertex, point Q. (2, -1).

Answer:

-6

11

Step-by-step explanation:

-6n-5=31

-6n=36

n=-6

-28=-3n+5

3n=5+28

3n=33

n=11

Answer:

x=-3, That is the x value of the vertex, and it is a vertical parabola.

Answer:

11x + 5

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

the converse of alternate interior angles theorem states that if two lines are intersected by a transversal forming congruent alternate interior angles then the lines are parallel.

Answer:

Step-by-step explanation:

[tex] {115}^{o} = {(4k + 5)}^{o} + {(6k + 10)}^{o} \\ [/tex]

An exterior angle of a triangle is equal to the sum of its two interior opposite angles.

[tex] {115}^{o} = {(4k + 5)}^{o} + {(6k + 10)}^{o} \\ {115}^{o} = 4k + 5 + 6k + 10 \\ {115}^{o} = 10k + 15 \\ {115}^{o} - 15 = 10k \\ {100}^{o} = 10k \\ \frac{100}{10} = k \\ {10}^{o} = k \\ [/tex]

Answer:

A. A reflection over the x-axis

Answer:

this is A, a reflection over the x axis

Answer:

turning point: (1, 4)

Roots: (-1, 0), (3, 0)

Step-by-step explanation:

The turning point is the vertex of the parabola, which occurs at point (1, 4).   The roots are the areas where the graph crosses the x-axis, referred to as the x-intercepts. The graph crosses the x-axis at points (-1, 0) and (3, 0).

Answer:

the answer is 1.6

Step-by-step explanation:

Answer:

3. Lotion

2. Suspension

1. Capsule

Explanation:

If we replaced y with 3 in choice A, then we get

2y-3 = 6

2(3)-3 = 6

6-3 = 6

3 = 6

which is a false statement. So choice A's solution is not y = 3. We can cross choice A off the list. The same applies with choices B and D as well.

Choice C is the answer because,

11y+4 = 37

11(3)+4 = 37

33+4 = 37

37 = 37

which is true. This confirms choice C.

Answer:

Step-by-step explanation:

x ≥ 1

Hope this helps!

close circle = ≥ or ≤

open circle = > or <

positive number = going to the right

negative number = going to the left

1. 5 x 4 = A. 20

2.

[tex] \frac{2}{5} \times 25 = 2 \times 5 = 10[/tex]

the answer is D. 25

3.

[tex] \frac{3}{5} \div 15 = \frac{3}{5} \times \frac{1}{15} = \frac{1}{5} \times \frac{1}{5} = \frac{1}{25} [/tex]

the answer is A. 1/25

4.

[tex]4 \div \frac{1}{2} = 4 \times \frac{2}{1} = 8[/tex]

the answer is C. 8

5.

[tex]9 \div \frac{1}{3} = 9 \times \frac{3}{1} = 27[/tex]

the answer is D. 27

6.

[tex]20 \div \frac{1}{4} = 20 \times \frac{4}{1} = 80[/tex]

the answer is D. 80

7.

[tex] \frac{9}{10} \div \frac{1}{2} = \frac{9}{10} \times \frac{2}{1} = \frac{18}{10} = \frac{9}{5} = 1 \frac{4}{5} [/tex]

the answer is C. 1 4/5

8.

[tex]9 \div \frac{3}{2} = 9 \times \frac{2}{3} = \frac{18}{ 3} = 6[/tex]

the answer is B. 6

9.

[tex] \frac{3}{4} \div \frac{3}{8} = \frac{3}{4} \times \frac{8}{3} = 2[/tex]

the answer is A. 2

Step-by-step explanation:

Given equations :-

Substitute (2) in (1) :-