Please HELP!!
Diagram's BELOW↓
1. What is the mass of the object experimented on in this situation?
a. 10 kg
b. 15 kg
c. 20 kg
d. 25 kg
2. What is the net force on this object?
a. 20 N to the left
b. 10 N up
c. 10 N down
d. 35 N to the right
Thank you in advance! Very appreciated! (I will mark brainliest) :)
Answers
2. 35n to the right
The mass of the object experimented in the situation will be equal to 20 kg in each case. Hence, option C is correct.
What is Acceleration?Acceleration is the rate at which the speed and orientation of a moving object change over time. When a spot or object moves faster or slower along a straight line, it is said to be accelerated. Even though the speed is constant, motion on a circle accelerates so because the direction is always shifting. Both by and to acceleration for all other types of motion.
It is a vector quantity because it has both magnitude and direction.
The given data as per the question is,
Force, F = 30 N
Acceleration, a = 1.5 m/s²
[tex]Force = mass*acceleration[/tex]
30 N = m × 1.5
m = 30/1.5
m = 20 kg.
Therefore, the mass of the object is 20 kg.
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Related Questions
A flea can jump with an initial velocity of 2.2 m/s at an angle of 21° with respect to the
horizontal.
Answers
Answer:
Explanation:
If no one can see it because the lights were out. Did the flea really jump?
What do you want here?
Max height (2.2sin21)²/ 2(9.8) = 3.2 cm
Time of flight 2(2.2sin21)/ (9.8) = 0.16 s
distance of flight (2.2cos21)(0.16) = 33 cm
WILL GIVE BRAINLIEST
An object with mass m dropped from height H, after travelling a distance and emerged horizontally from the bottom of the track with a velocity v and height of h. what is The work done due to friction while traveling through the track. could someone also please explain the difference between h and H
Answers
Answer:
I think d
Explanation:
how can I become a good science student ?
Answers
Answer:
Study hard , focus on your studies and alyways ask questions .
Study, revise, write notes, listen in class, don't let yourself be distracted by others, and do the work in class...maybe join stem or science club if you wanna
Hope this helped you- have a good day bro cya)
When a straw with liquid is covered by a finger and raised, the liquid does not leak
from the straw. Explain this using ideas of pressure exerted by particles.
Answers
Answer:
lol I don't know think u could help me with my mathematics
A 220g mass is on a frictionless horizontal surface at the end of a spring that has a force constant of 7.0N/m The mass is displaced 5 2m from its equilibrium position and then released to undergo simple harmonic motion.
At what displacement from the equilibrium position is the potential energy equal to kinetic energy?
Answers
Answer:
Explanation:
Your numbers seem wonky, so I'll just assume that the initial displacement is a distance A (Amplitude) from the equilibrium position. Spring constant = k
Initial potential energy is
PE = ½kA²
As potential energy and kinetic energy are constantly exchanging in SHM,
the position x where half of the original spring potential exists is found where
½kx² = ½(½kA²)
x² = ½A²
x = (√0.5)A
x ≈ 0.707A
just plug in your actual starting position A
With A = 5.2 cm
x = 3.67695... 3.7 cm
Speed depends on how far something travels and
Answers
Answer:
Speed depends on how far something is travelling and the time taken for the object to travel that distance
Explanation:
(In reference to the speed formula) Speed=[tex]\frac{Distance(m)}{Time(m/s)}[/tex]
Definition of speed:
Speed is the magnitude (unit) of the rate at which an object is moving.
(pls do correct me if I have any mistakes it makes a big difference to help each other out!)
A diffraction grating, ruled with 300 lines per mm, is illuminated with a white light source at normal incidence.
(i) What is the angular separation, in the third-order spectrum, between the 400 nm and 600 nm lines? [5]
(ii) Water (of refractive index 1.33) now fills the whole space between the grating and the screen. What is the angular separation, in the first-order spectrum, between the 400 nm and 600 nm lines? [5]
Answers
the expression for diffraction grating allows to find the results for the questions for the angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
The diffraction grating is a system formed by a large number of equally spaced lines whose diffraction is given by the expression.
d sin θ = m λ
Where d is the distance between two lines, θ is the angle of diffraction, the order of diffraction and λ is the wavelength.
i) Let's start by looking for the separation between two lines
Let's use a rule of direct proportions. If there are 300 lines in 1 mm, what distance is there between two lines.
d = 1 lines (1 mm / 300 lines) = 3,333 10⁻³ mm
d = 3.333 10⁻⁶ m
Let's find the angle of diffraction for the third order (m = 3) for each wavelength.
λ₁ = 400 nm = 400 10⁻⁹ m
sin θ₁ = [tex]\frac{m \ \lambda }{d}[/tex]m λ/ d
sin θ₁ = [tex]\frac{3 \ 400 \ 10^{-9} }{3.333 \ 10^{-6} }[/tex]
θ₁ = sin⁻¹ 0.3600
θ₁ = 0.368 rad
λ₂ = 600 nm = 600 10⁻⁹ m
sin θ₂ = [tex]\frac{3 \ 600 \ 10^{-9} }{3.333 \ 10^{-6} }[/tex]
θ₂ = sin⁻¹ 0.5401
θ₂ = 0.571 rad
The angular separation is
Δθ = θ₂ - θ₁
Δθ = 0.571 - 0.368
Δθ = 0.203 rad
ii) In this case, the separation between the network and the observation screen is filled with water.
When the rays leave the network they undergo a refraction process, for which they must comply with the relationship.
[tex]n_i \ sin \theta_1 = n_r \ sin \theta_r[/tex]
The incident side is in the air, therefore its refractive index is n_i = 1 and when it passes into the water with refractive index n_r = 1.33.
Let's start looking for the incident angles for the first order of diffraction.
m = 1
λ₁ = 400 nm
θ₁ = sin⁻¹ [tex]\frac{1 \ 400 \ 10^{-9}}{3.33 \ 10^{-6}}[/tex]
θ₁ = 0.120 rad
λ₂ = 600 nm
θ₂ = sin⁻¹¹ [tex]\frac{1 \ 600 \ 10^{-9} }{3.33 \ 10^{-6}}[/tex]
θ₂ = 0.181 rad
we use the equation of refraction.
[tex]\theta_r[/tex] = sin⁻¹ ([tex]\frac{n_i}{n_r} \ sin \ \theta_i[/tex] )
λ₁ = 400 nm
θ₁ = sin¹ ([tex]\frac{1 sin 0.120}{1.33}[/tex]
θ₁ = 0.090 rad
λ₂ = 600 nm
θ₂ =sin⁻¹ [tex]\frac{1 sin 0.181}{1.33}[/tex]
θ₂ = 0.1358 rad
The angular separation is
Δθ = 0.1358 - 0.090
Δθ = 0.046 rad.
In conclusion using the relation for the diffraction grating we can find the results for the questions about angular separation are:
i) The third order is Δθ = 0.203 rad.
ii) The first order with water is Δθ = 0.046 rad.
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in a closed system of a cannon and cannonball, which changes would both results in an increase in the kinetic energy of the cannonball when fired from the cannon?
A) decrease the mass of the cannon or decrease the mass of the cannonball
B) increase the mass of the cannon or decrease the mass of the cannonball
C) decrease the mass of the cannon or increase the mass of the cannonball
D) increase the mass of the cannon or increase the mass of the cannonball
Answers
Changes that would results in an increase in the kinetic energy of the cannonball in a closed system, when it is fired from the cannon is B:increase the mass of the cannon or decrease the mass of the cannonball.
A closed system can be considered one that is not been affected by external forces. With the conservation of momentum, there would be collisions as well inexplosions.This explains that when a cannon is fired, there would be gain of forward momentum by the cannon ball, while the cannon experience backward momentum.For the kinetic energy of the cannonball to increase, when fired from the cannon, then the mass is the cannon would be increased or the mass of the cannonball would be decreased.
Therefore, option B is correct.
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How much time does it take for a school bus traveling at 15 m/s north to get a distance of 600 meters north?
Possible answers:
40 seconds
9,000 seconds
615 seconds
0.025 seconds
Answers
Answer:
40s
Explanation:
You start your bicycle ride at the top of a hill moving East. You coast down the hill at a
constant acceleration of 2 m/s^2. When you get to the bottom of the hill you are moving at
18 m/s, and from there you pedal to maintain that velocity for one minute.
Answers
Answer:
198 meters
Explanation:
I'm not sure but hope it helps
4. What is the density of a block with a mass of 36 g and a volume of 9 cm?
O A 45 g/cm3
O B.27 g/cm
O 0.4 g/cm
O D. 0.25 g/cm
Answers
Answer:
0.4 g/cm
Explanation:
density (g cm ³) = mass (g)
÷
volume (cm³)
Answer:
C. 4 g/cm
Explanation:
Use the formula:
density = mass ÷ volume
mass = 36volume = 9Sub in the values:
density = 36 ÷ 9 = 4 g/cm
Answer = 4 g/cm
QUESTION 5 When 235U is bombarded with one neutron, fission occurs and the products are three neutrons, 94Kr and?
a. 139Ba
b. 141Ba
c. 139Ce
d. 139Xe
Answers
A machine whose efficiency is 75% is used to lift a load of 100m.calculate the effort put into the machine if it has a velocity ratio of 4.
Answers
Explanation:
M.A = load / Effort
efficiency = M.A/V.R X 100
75 = M.A / 4 X 100
75 = 25 X M.A
M.A = 75/25 = 3
M.A = load / effort
3 = 100/E
E = 100/3 = 33.333
A machine whose efficiency is 75% is used to lift a load of 100m. the effort needed to put into the machine is 33.33 meters if the velocity ratio is 4.
What is the mechanical advantage?Mechanical advantage is defined as a measure of the ratio of output force to input force in a system, It is used to analyze the forces in simple machines like levers and pulleys.
Mechanical advantage = output force(load) /input force (effort)
Simple machines like static pulleys, as well as a movable pulleys, provide a great amount of mechanical advantage.
A machine whose efficiency is 75% is used to lift a load of 100m.calc if it has a velocity ratio of 4.
As we know that the mechanical advantage of a machine is equal to the product of its efficiency and velocity ratio.
mechanical advantage = velocity ratio ×Efficiency
=4 × 0.75
= 3
The mechanical advantage is 3 , which means the ratio of load to effort is 3
load / effort = 3
100 m/effort =3
effort = 33.33 m
Thus, the effort put into the machine comes out to be 33.33 m.
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True or False
In newton's 2nd law, f=ma there is a correlation between the force and acceleration. This supports that there is a causal relationship that acceleration has on the net force.
Answers
Answer: See explanation
Explanation:
Please see attached picture. Due to the fact one of the words in the equation F=ma contains a word not allowed.
Two students were pushing a heavy sofa. One student pushed with a force of 200.0 N to the right, while the other pushed with a force of 150.0 N to the right. The floor exerted a frictional force of 100.0 N. If the sofa's mass is 91.0 kg, what is its acceleration? Round your answer to three significant figures.
Answers
Answer:
Explanation:
F = ma
a = F/m
a = (200.0 + 150.0 - 100.0) / 91.0
a = 250.0/91.0
a = 2.7472527...
a = 2.75 m/s²
what is an electrostatic phenomenon?
Answers
Answer:
Electrostatic phenomenon is a from the forces that electric charges exert on each other.
define potential difference as used in electricity
Answers
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit.
Potential difference is the difference in the amount of energy that charge carriers have between two points in a circuit. ... The energy is transferred to the electrical components in a circuit when the charge carriers pass through them. We use a voltmeter to measure potential difference (or voltage).
Which statement describes friction?
Answers
Answer:
include the statements pls so i can choose wich one it is and tell you
Explanation:
The pulley shown in the attached diagram has a diameter of 30 centimeters and a mass of 19 kilograms. The pulley is a solid disk with an axle through its center.
(a.) What is the moment of inertia of the pulley?
(b.) What is the magnitude of the net torque on the pulley about its axis
(c.) What is the direction of the net torque on the pulley?
(d.) What is the magnitude of the angular acceleration of the pulley?
(e.) What is direction of the angular acceleration?
Answers
Answer:
Explanation:
a) I = ½mR² = ½(19)(0.15²) = 0.21375 kg•m²
b) τ = Fnet(r) = (25 - 12)(0.15) = 1.95 N•m
c) CCW
d) a = τ/I = 1.95 / 0.21375 = 9.12280701... = 9.1 rad/s²
e) CCW
Which statement correctly describes the relationship between thermal energy and particle movement?(1 point)
As thermal energy increases, there is more particle movement.
As thermal energy increases, there is more particle movement.
As thermal energy increases, there is less particle movement.
As thermal energy increases, there is less particle movement.
As thermal energy increases, particle movement does not change.
As thermal energy increases, particle movement does not change.
As thermal energy increases, it is not possible to predict particle movement.
As thermal energy increases, it is not possible to predict particle movement.
Answers
Answer:
As thermal energy increases,there is more particle movement
A dry cell gives static electricity true or false?
Answers
Answer:
False
Explanation:
A 23 g bullet traveling at 230 m/s penetrates a 2.0 kg block of wood and emerges cleanly at 170 m/s. If the block is stationary on a surface with a coefficient of kinetic friction of 0.15 when hit, how far does it move after the bullet emerges?
Answers
The distance traveled by the wood after the bullet emerges is 0.16 m.
The given parameters;
mass of the bullet, m = 23 g = 0.023 gspeed of the bullet, u = 230 m/smass of the wood, m = 2 kgfinal speed of the bullet, v = 170 m/scoefficient of friction, μ = 0.15The final velocity of the wood after the bullet hits is calculated as follows;
[tex]m_1u_1 + m_2 u_2 = m_1v_1 + m_2v_2\\\\0.023(230) + 2(0) = 0.023(170) + 2v_2\\\\5.29 = 3.91 + 2v_2\\\\2v_2 = 1.38\\\\v_2 = \frac{1.38}{2} = 0.69 \ m/s[/tex]
The acceleration of the wood is calculated as follows;
[tex]\mu = \frac{a}{g} \\\\a = \mu g\\\\a = 0.15 \times 9.8\\\\a = 1.47 \ m/s^2[/tex]
The distance traveled by the wood after the bullet emerges is calculated as follows;
[tex]v^2 = v_0^2 + 2as\\\\v^2 = 0 + 2as\\\\v^2 = 2as\\\\s = \frac{v^2}{2a} \\\\s = \frac{(0.69)^2}{2(1.47)} \\\\s = 0.16 \ m[/tex]
Thus, the distance traveled by the wood after the bullet emerges is 0.16 m.
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Which of the following happens when a substance melts?
Answers
Answer:
hola como estas hablas español
Explanation:
A spring of spring constant k = 200 N m−1 is slowly extended from an extension of 3.0 cm to an extension of 5.0 cm. Calculate the work done by the extending force. 60
Answers
Answer:
31
Explanation:
No need
Is my answer correct
Answers
Answer:
it right congratulations
Answer:
A
Explanation:
Simply option A is correct
It's a bit of a common sense question
At the highest point it's velocity will be automatically 0 since it is in rest and so is the acceleration
Find the speed required to throw a ball straight up and it return 6 seconds later. Neglect air resistance
Answers
Answer:
the ball will go up 3s and down 3s
v=gt
where t=3s and g=9.8m/s^2
distance=v0(t)+(1/2)gt^2
where initial velocity (v0)=0
Explanation:
The speed required to throw a ball straight up and returns 6 seconds later would be 29.43 meters/seconds.
What are the three equations of motion?There are three equations of motion given by Newton,
v = u + at
S = ut + 1/2×a×t²
v² - u² = 2×a×s
As given in the problem we have to find the speed required to throw a ball straight up and it returns 6 seconds later,
S = ut + 1/2*a*t²
0 = u×6 + 0.5×(-9.81)×6²
0 = 6u - 176.8
6u = 176.8
u = 176.8/6
u = 29.43 meters / seconds
Thus, the speed required to throw a ball straight up and returns 6 seconds later would be 29.43 meters/seconds.
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Physical activities teaches an individual sense of responsibility and initiative.
True Or False
Answers
Answer:
true
Explanation:
Physical fitness is a personal responsibility so I would say true
A ball moving 2 ft/s rolls off a table (on earth) that is 32 inches high. How long will it take the ball to hit the floor answer
Answers
Answer:When the ball rolls off the edge of the table, it will continue moving forward at 2.0 m/s until it hits the floor.
Explanation:This is what I would say is the answer bc I had to do reasearch on a lot of this for my work this year so if its not im veery sorry
A uniform string of length 0.50 m is fixed at both ends. Find the
wavelength of the fundamental mode of vibration. If the wave
speed is 300 mis, find the frequency of the fundamental and next
possible modes.
Answers
Answer:
configuration of string:
Node - Antinode - Node or N-A-N
This is 1/2 wavelength since a full wavelength is N-A-N-A-N
f (fundamental) = V / wavelength
F0 = 300 m/s / 1 m = 100 / sec
F1 = 300 m/s / .5 m = 600 / sec
Each increase is a multiple of the fundamental since the wavelength
increases by 1/2 wavelength to keep nodes at both ends of the string
What is the mass of an object that is experiencing a net force of 225 N and an acceleration of 3.0 m/s^2?
Answers
Answer:
Mass of a object 75 Kilograms
Explanation:
Net force acting on an object, [tex]Fnet = 225N[/tex]
Acceleration produced, [tex]a = 3.0m/s^2[/tex]
According to Newton's second law :
F = m a
[tex]M =\frac{F}{a}[/tex]
[tex]m =\frac{225N}{300m/s^2}[/tex]
[tex]m= 75 Kg[/tex]
So, the mass of an object is 75kg.
Hence, this is the required solution.
Answer:
75 kg.
Explanation:
Net Force
[tex]\sf \longmapsto F_{net} = 225N[/tex]
Acceleration produced
[tex]\sf \longmapsto \: a = 3 .0 m / {s}^{2}[/tex]
According to Newton's 2nd Law –
F = m•a
[tex]\sf \longmapsto \: M = \frac{F}{A} [/tex]
[tex]\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } [/tex]
[tex]\sf \longmapsto \: M = \: 75 \: kg[/tex]
Therefore, the mass of an object is 75 kg.