(SAT Prep) Find the value of x.

Answer: x = 5, x = -7/2

Step-by-step explanation:

2x² - 3x - 35 = 0

Step 1: Find two values whose product = 2(-35) and sum = -3:  -10 & 7

Step 2: Replace the b-value of -3x with  -10x + 7x:

2x² - 10x   + 7x - 35 = 0

Step 3: Factor the first two terms and the second two terms:

2x(x - 5)  +7(x - 5) = 0

Step 4: Write the factored form:

Notice that the parenthesis are identical.  This is one of the factors. The outside values are the other factor:

Parenthesis: (x - 5)

Outside: (2x + 7)

Factored form: (x - 5)(2x + 7) = 0

Step 5: Set each factor each to zero and solve for x:

x - 5 = 0             2x + 7 = 0

   x - 5                      [tex]x=-\dfrac{7}{2}[/tex]

The solutions of the quadratic equation given as 2x² - 3x - 35 = 0 are x=5 and x =-3.5.

Given that:

2x² - 3x - 35 = 0

This is a quadratic equation.

It is required to find the solutions of this equation.

The solution of the quadratic equation of the form ax² + bx + c = 0 can be found using the quadratic formula:

[tex]x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}[/tex]

From the given equation:

a = 2

b = -3

c = -35

Substitute to the quadratic formula.

[tex]x=\frac{-(-3)\pm \sqrt{(-3)^2-4(2)(-35)}}{2(2)}[/tex]

  [tex]=\frac{3\pm \sqrt{9+280}}{4}[/tex]

  [tex]=\frac{3\pm \sqrt{289}}{4}[/tex]

  [tex]=\frac{3\pm 17}{4}[/tex]

So, the solutions are:

[tex]x=\frac{3+ 17}{4}=5[/tex], and [tex]x=\frac{3-17}{4}=-3.5[/tex]

Hence, the solutions are x =5, -3.5.

Learn more about Quadratic Formula here :

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Answer:

  (T, C, J) = (in dollars)

     (10000, 10000, 0),

     (15000, 4915.97, 84.03),

     (18181.82, 1680.67, 137.51)

Step-by-step explanation:

There are a number of ways to approach this question. We have chosen an approach that determines the investments required to achieve interest rate targets.

__

For an overall interest rate of I, the proportion that must be invested at rate I1 < I < I2 is ...

  proportion at I1 = (I2 -I)/(I2 -I1)

Similarly, the proportion that must be invested at I2 is what's left over. It can be computed similarly:

  proportion at I2 = (I -I1)/(I2 -I1)

__

We want an overall interest rate of $2000/$20000 = 10%.

Given available interest rates of 9%, 11%, and 130%, we need to have investments at a rate lower than 10% and at a rate higher than 10%.

If we use only the options for 9% and 11% (no junk bonds), then we can compute ...

  proportion at 9% = (11 -10)/(11 -9) = 1/2

  proportion at 11% = (10 -9)/(11 -9) = 1/2

1st Option:

  $10,000 in treasury bills; $10,000 in corporate bonds

__

Suppose we want to achieve a 13% return on our investments at 11% and 130%. Then the proportion invested at 9% will use this value for I2:

  proportion at 9% = (13 -10)/(13 -9) = 3/4

Of the remaining 1/4 of the money, we can achieve a 13% return by mixing the investments like this:

  proportion at 11% = (130 -13)/(130 -11) = 117/119

  proportion at 130% = (13 -11)/(130 -11) = 2/119

2nd option:

  $20,000 × 3/4 = $15,000 in treasury bills

  $5000 × 117/119 = $4,915.97 in corporate bonds

  The remaining amount, $84.03 in junk bonds

__

Let's suppose we want a 20% return on our investment in junk bonds and corporate bonds. Then the proportion of the money invested at 9% will be ...

  proportion at 9% = (20 -10)/(20 -9) = 10/11

And the proportion at 11% will be ...

  proportion at 11% = (130 -20)/(130 -11) = 110/119 . . . (of the remaining 1/11 of the funds)

3rd option:

  $20,000 × 10/11 = $18,181.82 in treasury bills

  $1,818.18 × 110/119 = $1,680.67 in corporate bonds

  The remaining amount, $137.51 in junk bonds

_____

Additional comment

The most that could be invested in Junk Bonds is $165.29. If the remainder is invested in Treasury Bills, then the overall return will be $2000. (You could consider this to be a 4th option.)

Answer:

BC = 10, AC= approximately 13.66 OR 5+5 √3

Step-by-step explanation:

Law of Sines

Answer:

Step-by-step explanation:

Using the following data:

H0:p=0.40 (null hypothesis)

Ha:p>0.40 (alternative hypothesis)

The p-value was determined to be 0.001.

a significance level of 5%

Since the p value (0.001) is less than the significance level (0.05), we will reject the null hypothesis and then we would conclude that the proportion of students that are nursing majors is greater than 0.4.

Answer:

p value= 0.131

Step-by-step explanation:

Since we have calculated the test statistic, we can now proceed to find the p-value for this hypothesis test.Using the test statistic and since the hypothesis test is a left tailed test, the p-value will then be the area under the standard normal curve to the left of the test statistic of -1.12.Using the Standard Normal table given above, the area under the standard normal curve to the left of the test statistic of -1.12 is 0.131 (rounded to 3 decimal places.Thus the p-value = 0.131.

Answer:

The 95 % confidence interval of the mean of the time playing video games. is

        [tex]15.67< \mu <17.52[/tex]

Step-by-step explanation:

From the question we are told that

      The sample size is [tex]n = 35[/tex]

        The sample mean is [tex]\= x = 16.6[/tex]

       The standard deviation is  [tex]\sigma = 2.8[/tex]

The confidence level is  95%  hence the level of significance is mathematically represented as

     [tex]\alpha = 100 - 95[/tex]

     [tex]\alpha = 5[/tex]%

      [tex]\alpha = 0.05[/tex]

Now the critical value of half of this level of significance obtained from the normal distribution table is  

       [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]

The  reason for the half is that we are considering the two tails of the normal distribution curve which we use to obtain the interval

Now the standard error of the mean is mathematically evaluated as

       [tex]\sigma _{\= x} = \frac{\sigma }{\sqrt{n} }[/tex]

substituting values  

     [tex]\sigma _{\= x} = \frac{2.8 }{\sqrt{35} }[/tex]

      [tex]\sigma _{\= x} = 0.473[/tex]

the 95 % confidence interval of the mean of the time playing video games.

is mathematically evaluated as

    [tex]\= x - (Z_{\frac{\alpha }{2} } * \sigma_{\= x }) < \mu < \= x - (Z_{\frac{\alpha }{2} } * \sigma_{\= x })[/tex]

substituting values

    [tex]16.6 - (1.96 * 0.473) < \mu < 16.6 + (1.96 * 0.473)[/tex]

     [tex]15.67< \mu <17.52[/tex]

Let's take a look at each term separately.

15a^2b^2:

15 has factors 1, 3, 5, 15

a x a

b x b

-24ab

-24 has factors 1, 2, 3, 4, 6, 8, 12, 24

a

b

Now, we can see what each of these terms has in common. Both have a 3 in their factor lists, as well as one a and one b.

Therefore, the greatest common factor is 3ab.

Hope this helps!! :)

Answer:

3ab

Step-by-step explanation:

[tex]15a^{2} b^{2} - 24ab[/tex] is divided by 3

[tex]5a^{2} b^{2} - 8ab[/tex] take away a and b once

hope this helped!!!

[tex]5ab - 8[/tex]

= 3ab

Answer:

42

Step-by-step explanation:

The permutation formula is P(n, r) = n! / (n - r)!. We know that n = 7 and r = 2 so we can write:

7! / (7 - 2)!

= 7! / 5!

= 7 * 6 * 5 * 4 * 3 * 2 * 1 / 5 * 4 * 3 * 2 * 1

= 7 * 6 (5 * 4 * 3 * 2 * 1 cancels out)

= 42

Answer:

[tex]\boxed{42}[/tex]

Step-by-step explanation:

Apply the permutation formula.

[tex]P(n,r)=\frac{n!}{ (n-r)!}[/tex]

[tex]P=number \: of \: permutations\\n=total \: number \: of \: objects \: in \: the \: set\\r=number \: of \: choosing \: objects \: from \: the \: set\\[/tex]

[tex]n=7\\r=2[/tex]

Plug in the values and evaluate.

[tex]P(7,2)=\frac{7!}{ (7-2)!}[/tex]

[tex]P(7,2)=\frac{7!}{ (5)!}[/tex]

[tex]P(7,2)=\frac{5040}{120}[/tex]

[tex]P(7,2)=42[/tex]

Answer:

251 inches

Step-by-step explanation:

c = 2πr

c = 2(3.14)(5) = 31.4

31.4 x 8 rev. = 251 inches

Answer: answer is: 1000000/19

Step-by-step explanation:

10/19 - 40k -> 10/19*40k= 400000/19

6/19- 60k -> 6/19*60k= 360000/19

3/19 - 80k -> 3/19*80k=240000/19

400000/19+360000/19+240000/19=1000000/19

answer is: 1000000/19

Answer: Its coefficient of variation = 0.316

Step-by-step explanation:

The formula to find the coefficient of variations:

Coefficient of variation: [tex](\dfrac{\sqrt{\text{variance}}}{\text{return}})[/tex]

Given: Asset X has

Variance = 10

Expected return = 10

then, coefficient of variation [tex]=\dfrac{\sqrt{10}}{10}=\dfrac{1}{\sqrt{10}}\approx0.316[/tex]

Hence, its coefficient of variation = 0.316

Answer:

The domain of the graph is all real numbers less than or equal to 0.

Step-by-step explanation:

Hello,

We know that we cannot take square root of negative numbers, so we must have

[tex]-x\geq 0 \ \text{ ***multiply by -1, it changes the inequality, so*** } \\ \\\large \boxed{\sf \ \ x\leq0 \ \ }[/tex]

So the domain of the graph is all real numbers less than or equal to 0.

For information, I attached the graph so that we can verify it.

Hope this helps.

Do not hesitate if you need further explanation.

Thank you

Answer:

The dentist should fail to reject the Null hypothesis

Step-by-step explanation:

From the question we are told that

       The sample size is  n =  400

       The  sample  mean is  [tex]\= x = 149[/tex]

       The  level of significance is  5%  = 0.05  

       The  Null hypothesis is  [tex]H_o : p = 0.40[/tex]

        The Alternative  hypothesis is  [tex]H_a : p < 0.40[/tex]

         The  p-value is  [tex]p-value = 0.131[/tex]

Looking at the given data we can see that the p-value is greater than the level of significance hence the dentist should fail to reject the Null hypothesis  

Answer:

The z-score is  [tex]z = 2.65[/tex]

The length of days is not unusual

Step-by-step explanation:

From the question we are told that

     The population mean is  [tex]\mu = 267.6 \ days[/tex]

     The standard deviation is  [tex]\sigma = 15.4 \ days[/tex]

      The value considered is  [tex]x = 309 \ days[/tex]

The z-score is mathematically represented as

           [tex]z = \frac{x - \mu}{\sigma }[/tex]

            [tex]z = \frac{309 - 267.6}{15.6 }[/tex]

           [tex]z = 2.65[/tex]

Now given that the z-score is not greater than 3  then we can say that the length of days is not unusual

(reference khan academy)

Answer:

[tex] P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)[/tex]

And using the probability mass function we got:

[tex]P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205[/tex]

[tex]P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117[/tex]

[tex]P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439[/tex]

[tex]P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098[/tex]

[tex]P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977[/tex]

And adding the values we got:

[tex] P(X\geq 6) = 0.377[/tex]

The best answer would be:

D. 0.377

Step-by-step explanation:

Let X the random variable of interest, on this case we now that:

[tex]X \sim Binom(n=10, p=0.5)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

For this case in order to pass he needs to answer at leat 6 questions and we can rewrite this:

[tex] P(X \geq 6) = P(X=6) +P(X=7) +P(X=8) +P(X=9) +P(X=10)[/tex]

And using the probability mass function we got:

[tex]P(X=6)=(10C6)(0.5)^6 (1-0.5)^{10-6}=0.205[/tex]

[tex]P(X=7)=(10C7)(0.5)^7 (1-0.5)^{10-7}=0.117[/tex]

[tex]P(X=8)=(10C8)(0.5)^8 (1-0.5)^{10-8}=0.0439[/tex]

[tex]P(X=9)=(10C9)(0.5)^9 (1-0.5)^{10-9}=0.0098[/tex]

[tex]P(X=10)=(10C10)(0.5)^{10} (1-0.5)^{10-10}=0.000977[/tex]

And adding the values we got:

[tex] P(X\geq 6) = 0.377[/tex]

The best answer would be:

D. 0.377

Answer:

P(A|B) = 1 / 6

Step-by-step explanation:

Assuming two fair sided dice with faces numbered 1 to 6.

By intuition, there can only be 6 possible outcomes, so probability is 1/6.

Illustration how to use conditional probability.

Given two events A, B, following is the equation of conditional probability

that A happens given B has already happened and observed.

P(A|B) = P( A intersect B ) / P(B)

In the given problem,

A = casting a double-six

B = casting a double

P(A) = (1 / 6) * (1 / 6) = 1/36

P(B) = (6/6) * (1/6) = 1/6

P(A|B) = 1/36 / (1/6) = 1/6

Answer:

A. -9

Step-by-step explanation:

If one of the variables were negative than, it would not be able to equal 2/7.

Answer:

y < -12

Step-by-step explanation:

Step 1: Subtract 15 on both sides

y + 15 - 15 < 3 - 15

y < -12

This inequality means the any number smaller than -12 would work. So:

-123415235 would work

-1234 would work

-46527 would work

2 would NOT work

6 would NOT work

Answer:

Step-by-step explanation:

[tex]y + 15 < 3[/tex]

Move constant to RHS and change its sign:

[tex]y < 3 - 15[/tex]

Calculate the difference

[tex]y < - 12[/tex]

Hope this helps..

Good luck on your assignment..

Answer:

Step-by-step explanation:

Equation given

tan(3B-32 ) = cot ( 5B +10 ) = tan [ 90 - ( 5B + 10 ) ]

tan(3B-32 ) = tan  (90 - 5B - 10 )

(3B-32 ) =  (90 - 5B - 10 )

8B = 32 + 80

B = 14° .

Answer:

This is an arithmetic sequence.

Step-by-step explanation:

The difference between the consecutive terms is constant => sequence is arithmetic.

4-2 = 2

6-4= 2

8-6 = 2

10-8 = 2

Step-by-step explanation:

It's an arithmetic sequences.

Formed by the n th term 2n.

As the difference is 2 between them.

let's find it, by formulae.

n th term = 2n

and so on.....

Therefore, it's an arithmetic sequence.

Hope it helps..

Answer:

I think D

Step-by-step explanation:

Verticle or horizontal line test, it would be a function either way

Answer:

A

Step-by-step explanation:

let y = f(x) and rearrange making x the subject, that is

y = [tex]\frac{19}{x^3}[/tex] ( multiply both sides by x³ )

x³y = 19 ( divide both sides by y )

x³ = [tex]\frac{19}{y}[/tex] ( take the cube root of both sides )

x = [tex]\sqrt[3]{\frac{19}{y} }[/tex]

Change y back into terms of x, then

[tex]f^{-1}[/tex] (x) = [tex]\sqrt[3]{\frac{19}{x} }[/tex] = [tex]\frac{\sqrt[3]{19} }{\sqrt[3]{x} }[/tex] → A

Answer:

the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Step-by-step explanation:

From the given information:

Let consider y to represent the number of years after 1999

Then the population in time (y) can be expressed as:

P(y) = 9400y + 924900

The average annual income can be written as:

A(y) = 1400y + 30388

The total personal income = P(y)  ×  A(y)

The rate at which the total personal income is rising is T'(y) :

T'(y) = P'(y)  ×  A(y)  + P(y)  ×  A'(y)

T'(y) = (9400y + 924900)' (1400y + 30388) + (9400y + 924900) (1400y + 30388)'

T'(y) = 9400(1400y + 30388) + (9400y + 924900) 1400

Since in 1999 y =0

Then:

T'(0) = 9400(1400(0) + 30388) + (9400(0) + 924900) 1400

T'(0) = 9400(30388) + (924900)1400

T'(0) = $1,580,507,200 billion

Therefore; the rate at which total personal income was rising in the area in 1999 is $1,580,507,200 billion

Answer:

The amount necessary to fund the withdrawal is $8798.820

Step-by-step explanation:

Here, we are interested in calculating the necessary amount to fund the withdrawal given in the question.

From the question, we can identify the following;

Principal amount, P= $850

Here, Period rate, i = 0.047/ 2 =0.0235

n = 6*2 = 12

Mathematically;

Present Value of an annuity, Ao=P* [1-(1+i)^{-n}]/i

Ao=850* [1-(1+0.0235)^{-12}] /0.0235

Ao = $8798.820

Answer:

[tex]\boxed{Option \ B}[/tex]

Step-by-step explanation:

In the triangle,

Hypotenuse = 13

Opposite = Perpendicular = 5

Adjacent = Base = 12

Now,

Cos B = [tex]\frac{Adjacent}{Hypotenuse}[/tex]

Cos B = 12/13

If the triangle is just like in the attached file!

Answer:

B) 12/13

Step-by-step explanation:

Answer:

1 + 1 = 2

Step-by-step explanation:

^

Answer:

no , it's happening to everyone , even I can't see it .

Answer:

14.6

Step-by-step explanation:

(A). STEP ONE: Calculate the mean

(1). Row one = (10 + 12 + 12 + 14 ) = 48/4 = 12.

(2). Row Two: (12 + 11 + 13 + 16 ) = 52/4 = 13.

(3). Row three : (11 + 13 + 14 + 14)/4 = 13.

(4). Row four: (11 + 10 + 7 + 8)/4 = 36/4 = 9.

(5). Row five: (13 +12 + 14 + 13)/4 = 52/4 = 13.

(B). STEP TWO:

- determine the maximum and minimum value for each row.

- for each row, maximum - minimum.

Maximum values for each row:

Row one = 14, row two= 16, row three = 14, row four = 11 and row five = 14.

Minimum value for each row:

Row one = 10, row two = 11, row three = 11, row four =7 and row five = 12.

DIFFERENCES in each row :

row one = 14 - 10 = 4, row two = 16 - 11 = 5, row three = 14 - 11 = 3, row four = 11 - 7 = 4 and row five = 14 -12 = 2.

(C). STEP THREE: Calculate the mean of all the rows = 60/5 = 12.

(D). STEP FOUR : Calculate the Average Range = 18/5 = 3.6.

(E). STEP FIVE : Calculate the UCL.

A = Average rage × 0.729 = 3.6 × 0.729.

B = overall mean = 12.

UCL = A + B = 14.6.

Answer:

a) $3700

b) $555

Step-by-step explanation:

The length of the loan is 3 years.

The interest after 3 years is $444.

The rate of the Simple Interest is 4%.

Simple Interest is given as:

I = (P * R * T) / 100

where P = principal (amount borrowed)

R = rate

T = length of years

Therefore:

[tex]444 = (P * 3 * 4) / 100\\\\444 = 12P / 100\\\\12P = 444 * 100\\\\12P = 44400\\\\P = 44400 / 12\\[/tex]

P = $3700

She borrowed $3700

b) If the simple interest was 5%, then:

I = (3700 * 5 * 3) / 100 = $555

The interest would be $555.

Answer:

a(n)= a(n+1)+4

Step-by-step explanation:

The first terms of this sequence are: 4,0, -4, -8, -12

Let 4 be a0 and 0 a1.

● a1-a0 = 0-4

●a1-a0 = -4

●a1 = -4+a0

So this relation links the first term with the second one.

replace 1 in a1 with n.

0 in a0 will be n-1

● an = -4+a(n-1)

Add one in n

● a(n+1) = a(n)-4

● a(n) = a(n+1)+4

Answer: 97

Step-by-step explanation:

Formula to compute the required sample size :

[tex]n= (\dfrac{\sigma\times z_{\alpha/2}}{E})^2[/tex]

, where [tex]\sigma[/tex] = standard deviation

E= Margin of error

[tex]z_{\alpha/2}[/tex] = Two tailed z-value.

Here, E= 20

[tex]\sigma[/tex] = 100

For 95% confidence level: [tex]z_{\alpha/2}[/tex] =1.96

Required sample size:

[tex]n=(\dfrac{100\times1.96}{20})^2\\\\=(5\times1.96)^2\\\\=96.04\approx97[/tex]

Hence, the required sample size : 97

Answer:

J = 32

E = 0

Step-by-step explanation:

E is the number of hours for the Escobar family

J is the number of hours for the Johnson family

E + J = 32

E * 20 + J * 30 = 960

Multiply the first equation by -20 so we can use elimination

-20 E -20 J = -640

Add this to the second equation

E * 20 + J * 30 = 960

-20 E -20 J = -640

---------------------------------

         10 J = 320

Divide by 10

J = 32

Now find E

E + J = 32

E  + 32 = 32

E = 0