Researchers studied a random sample of high school students who participated in interscholastic athletics to learn about the risk of lower-extremity injuries (anywhere between hip and toe) for interscholastic athletes. Of 997 participants in girls' soccer, 79 experienced lower-extremity injuries. Of 1,664 participants in boys' soccer, 156 experienced lower-extremity injuries. (a) Write null and alternative hypotheses about sex and the risk of a lower-extremity Injury while playing interscholastic soccer. Null hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are related variables. Alternative hypothesis: Sex and risk of a lower-extremity Injury in interscholastic soccer are not related variables. Null hypothesis: Sex and risk of a lower extremity injury in interscholastic soccer are explanatory variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are not explanatory variables. Null hypothesis: Sex and risk of a lower extremity injury in interscholastic soccer are not explanatory variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are explanatory variables. Null hypothesis: There is a weak relationship between sex and risk of a lower-extremity injury in interscholastic soccer. Alternative hypothesis: There is a strong relationship between sex and risk of a lower-extremity injury in interscholastic soccer Null hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are not related variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are related variables. (b) For these data, the value of the chi-square statistic is 1. 63, and the p-value for the chi-square test is 0. 202. Based on these results, state a conclusion about the two variables in this situation and explain how you came to this conclusion. The p-value is greater than the 1. 63 X standard for significance, so there is not sufficient evidence to be able to conclude that the variables are related. (c) For each sex separately, calculate the percent of participants who had a lower-extremity injury. (Round your answers to one decimal place. ) girls 7. 9 % boys 9. 4 % Explain how the difference between these percentages is consistent with the conclusion you stated in part (b). These percentages are fairly similar , which suggests that sex and risk of a lower-extremity injury in interscholastic soccer are not related

Answers

Answer 1

a) Null hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are not related variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are related variables. So the option E is correct.

b) There is insufficient information to draw the conclusion that the variables are connected even though the value is greater than the 0.05 threshold for significance.

c) The difference between these percentage are fairly similar which suggests that sex and risk of lower-extremity Injury in  interscholastic soccer are not related.

a) The null and alternative hypotheses about sex and the risk of a lower-extremity Injury while playing interscholastic soccer is:

Null hypothesis: Sex and lower-extremity injury risk in interscholastic soccer are unrelated factors. Alternative hypothesis: sex and the likelihood of sustaining a lower-extremity injury in collegiate soccer are associated variables.

So the option E is correct.

b) The conclusion is that there is no significant relationship between the gender of the athlete and the risk of lower-extremity injuries. This conclusion is based on the fact that the chi-square statistic (1.63) and the corresponding p-value (0.202) are both greater than the 1.63 X standard for significance. This indicates that there is not enough evidence to show that the variables are related.

c) Of 997 participants in girls' soccer, 79 experienced lower-extremity injuries. Of 1,664 participants in boys' soccer, 156 experienced lower-extremity injuries.

Girls = 79/997 × 100 = 7.92%

Boys = 156/1664 × 100 = 9.38%

The difference between the two percentages is consistent with the conclusion that there is no significant relationship between the gender of the athlete and the risk of lower-extremity injuries because the difference between the two percentages is small.

This indicates that the risk of lower-extremity injuries is relatively similar for both boys and girls, which is consistent with the conclusion that there is no significant relationship between gender and the risk of lower-extremity injuries.

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The complete question is:

Researchers studied a random sample of high school students who participated in interscholastic athletics to learn about the risk of lower-extremity injuries (anywhere between hip and toe) for interscholastic athletes. Of 997 participants in girls' soccer, 79 experienced lower-extremity injuries. Of 1,664 participants in boys' soccer, 156 experienced lower-extremity injuries.

(a) Write null and alternative hypotheses about sex and the risk of a lower-extremity Injury while playing interscholastic soccer.

A. Null hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are related variables. Alternative hypothesis: Sex and risk of a lower-extremity Injury in interscholastic soccer are not related variables.

B. Null hypothesis: Sex and risk of a lower extremity injury in interscholastic soccer are explanatory variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are not explanatory variables.

C. Null hypothesis: Sex and risk of a lower extremity injury in interscholastic soccer are not explanatory variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are explanatory variables.

D. Null hypothesis: There is a weak relationship between sex and risk of a lower-extremity injury in interscholastic soccer. Alternative hypothesis: There is a strong relationship between sex and risk of a lower-extremity injury in interscholastic soccer

E. Null hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are not related variables. Alternative hypothesis: Sex and risk of a lower-extremity injury in interscholastic soccer are related variables.

(b) For these data, the value of the chi-square statistic is 1. 63, and the p-value for the chi-square test is 0. 202. Based on these results, state a conclusion about the two variables in this situation and explain how you came to this conclusion. The p-value is greater than the 1. 63 X standard for significance, so there is not sufficient evidence to be able to conclude that the variables are related.

(c) For each sex separately, calculate the percent of participants who had a lower-extremity injury. (Round your answers to one decimal place. ) girls 7.9% boys 9.4%. Explain how the difference between these percentages is consistent with the conclusion you stated in part (b). These percentages are fairly similar , which suggests that sex and risk of a lower-extremity injury in interscholastic soccer are not related


Related Questions

College enrollment of 41,000 increases by 7% every year.

Answers

The exponential function showing the relationship between y and t is y = 41,000 x (1.07)^t

How to determine the exponential function

From the question, we have the following parameters that can be used in our computation:

Initial value, a = 41,000

Rate = 7% increment

The exponential function for the college enrollment y of the college, in dollars, after t years can be expressed as:

y = a(1 + r)^t

Substitute the known values in the above equation, so, we have the following representation

y = 41,000 x (1 + 7%)^t

Evaluate

y = 41,000 x (1.07)^t

Where 1.07 is the factor by which the college enrolment increases

Hence, the function is y = 41,000 x (1.07)^t

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Kaylin buys a greeting card for 3.79. She then buys 4 postcards that all cost the same amount. The total cost is 5.11. How much is each postcard? Show your work.

Answers

Answer:

0.33

Step-by-step explanation:

5.11-3.79= total for 4 postcards

then answer divided by 4 postcards

y = -4x+6
find the perpendicular line that passes through (-7,5)
find equation of parallel line that passes through (-7,5)

Answers

The equation of the parallel line is y = -4x - 23.

To find the equation of the perpendicular line that passes through (-7, 5), we need to first find the slope of the given line y = -4x + 6. The slope of this line is -4. The slope of a perpendicular line is the negative reciprocal of the original slope, so the slope of the perpendicular line is 1/4.

Next, we can use the point-slope form of an equation to find the equation of the perpendicular line:

y - y1 = m(x - x1)

y - 5 = (1/4)(x - (-7))

y - 5 = (1/4)(x + 7)

y = (1/4)x + 9/4 + 5

y = (1/4)x + 29/4

The equation of the perpendicular line is y = (1/4)x + 29/4.

To find the equation of the parallel line that passes through (-7, 5), we can use the same slope as the original line, -4, and the point-slope form of an equation:

y - y1 = m(x - x1)

y - 5 = -4(x - (-7))

y - 5 = -4(x + 7)

y = -4x - 28 + 5

y = -4x - 23

The equation of the parallel line is y = -4x - 23.

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Help me, please. Please provide a clear answer

Answers

Answer:

see explanation

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180°

sum the 3 angles and equate to 180

4x + 21 + x - 10 + 2x + 8 = 180

7x + 19 = 180 ( subtract 19 from both sides )

7x = 161 ( divide both sides by 7 )

x = 23

Then angles in triangle are

4x + 21 = 4(23) + 21 = 92 + 21 = 113°

x - 10 = 23 - 10 = 13°

7x + 8 = 7(23) + 8 = 161 + 8 = 169°

the only 2 possible angle measures are A and E

values of x : -6-(4x)/(x+2)=(8)/(x+2)

Answers

There are no values of x that satisfy the equation -6-(4x)/(x+2)=(8)/(x+2).

To find the values of x for the equation -6-(4x)/(x+2)=(8)/(x+2), we need to follow the following steps:

Multiply both sides of the equation by (x+2) to eliminate the fractions:
(x+2)(-6-(4x)/(x+2))=(x+2)(8)/(x+2)

Simplify the equation:
-6(x+2)-4x=8

Distribute the -6:
-6x-12-4x=8

Combine like terms:
-10x-12=8

Add 12 to both sides:
-10x=20

Divide both sides by -10:
x=-2

However, we need to check our answer to make sure it does not result in a zero denominator in the original equation. If we plug in x=-2 into the original equation, we get a zero denominator, which is not allowed. Therefore, there are no values of x that satisfy the equation.

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Graph f(x) = (x+1) (x-5)

Answers

The graph of the quadratic function is on the image at the end.

How to graph the quadratic function?

Here we have the quadratic function:

f(x) = (x + 1)*(x - 5)

To graph this, we need to find some points of the parabola and then connect them.

So let's evaluate the function.

if x = -1

f(-1) = (-1 + 1)*(-1 - 5) = 0

if x = 0

f(0) =  (0 + 1)*(0 - 5) = -5

if x = 1

f(1) =  (1 + 1)*(1 - 5) = 2*-4 = -8

if x = 5 then:

f(5) =   (5 + 1)*(5 - 5) = 0

So we have the points (-1, 0), (0, -5), (1, -8) and (5, 0).

With these we can graph the parabola (you can try to find more points to get a better graph).

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A circle moves through 145 degrees in 25 seconds. If the radius
of the circle is 21 cm, find the linear and angular speeds.

Answers

The linear speed of the circle is 2.125 cm/s and the angular speed of the circle is 0.1012 rad/s.

The linear speed of the circle can be found by calculating the length of the arc traveled in 25 seconds. The length of an arc is given by the formula L = rθ, where r is the radius of the circle and θ is the central angle in radians. Converting the given angle from degrees to radians, we have:

θ = 145 degrees * π/180 = 2.53 radians

Substituting the values into the formula, we get:

L = 21 cm * 2.53 = 53.13 cm

Therefore, the linear speed of the circle is:

v = L/t = 53.13 cm/25 s = 2.125 cm/s

The angular speed of the circle can be found by dividing the central angle by the time taken to travel that angle. Therefore, the angular speed of the circle is:

ω = θ/t = 2.53 radians/25 s = 0.1012 rad/s

Hence, the linear speed of the circle is 2.125 cm/s and the angular speed of the circle is 0.1012 rad/s.

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last year there were 129 pies baked for the bake sale. this year there were b pies baked. using b write an expression for the total numbers of ingredients and pies baked in the two years

Answers

Answer:

Step-by-step explanation:

Assuming that the number of ingredients per pie is constant, we can write an expression for the total number of ingredients and pies baked in the two years as:

Total number of ingredients = (129 x ingredients per pie) + (b x ingredients per pie)

Total number of pies baked = 129 + b

So, if we let "i" represent the number of ingredients per pie, we can write the expression as:

Total number of ingredients = (129 x i) + (b x i)

Total number of pies baked = 129 + b

Note that without knowing the value of "i," we cannot simplify this expression any further.

Apply Cramer's Rule to solve the system of equations, -- 3.79 +33 = 1 2-12 4.- 3.3 = 0 If it is not possible to use Cramer's rule, indicate that using the checkbox -1 IL 12 It is not possible to use C

Answers

It is not possible to use Cramer's Rule to solve the system of equations you provided. This is because Cramer's Rule can only be applied to systems of linear equations that have the same number of equations as there are unknowns.

In the system you provided, there are four equations but only two unknowns. This means that Cramer's Rule cannot be applied.

Instead, you can use other methods such as substitution or elimination to solve the system. However, it is important to note that with more equations than unknowns, it is possible that there may be no solution or an infinite number of solutions.

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98. A blue whale weighs up to \( 1.8 \times 10^{6} \mathrm{~kg} \). How much will 12 blue whales weigh?

Answers

12 blue whales will weigh [tex]\( 2.16 \times 10^{7} \mathrm{~kg} \)[/tex].

The weight of 12 blue whales will be the product of the weight of a single blue whale and the number of blue whales. To find the product, we simply multiply the weight of a single blue whale by the number of blue whales.

So, the weight of 12 blue whales will be:

[tex]\( 1.8 \times 10^{6} \mathrm{~kg} \) × 12 = \( 2.16 \times 10^{7} \mathrm{~kg} \)[/tex]


Therefore, 12 blue whales will weigh [tex]\( 2.16 \times 10^{7} \mathrm{~kg} \)[/tex]

What is multiplication?

Multiplication refers to binary operations in which different numerical sets are established. In mathematics the process of multiplication is elementary in several operations, it is also accompanied by addition, subtraction and division. Multiplication is the opposite of division.

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3. What is the relationship between <8 and <4?
7
1 2
3 4
6
8
Ocorresponding angles
Oalternate exterior angles
Osame-side interior angles
Oalternate interior angles
(1 point)

Answers

The relationship between ∠8 and ∠4 include the following: A. corresponding angles.

What are corresponding angles?

In Mathematics, corresponding angles can be defined as a postulate (theorem) which states that corresponding angles are always congruent when the transversal intersects two (2) parallel lines. This ultimately implies that, the corresponding angles will be always equal (congruent) when a transversal intersects two (2) parallel lines.

By applying corresponding angles theorem to lines l and m, we have the following:

8 ≅ ∠4

3 ≅ ∠7

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pls answer this question only even numbers like 2,4,6....

Answers

Answer:

image is blur dear!!!

Step-by-step explanation:

given trinomial. If the trinomial cannot be factored, indicate "Not Factorable". x^(2)+12x+35 to enter your answer (opens in new window ) 2 Points

Answers

The given trinomial x^(2)+12x+35 is factorable. It's factors would be (x+7)(x+5).

To factor this trinomial, we need to find two numbers that multiply to 35 and add to 12. The two numbers that satisfy this condition are 7 and 5. Therefore, we can factor the trinomial as follows:

x^(2)+12x+35 = (x+7)(x+5)

So, the factored form of the given trinomial is (x+7)(x+5).

Therefore, the answer is (x+7)(x+5).

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What is the quotient of (−168) ÷ (−14) ÷ (−3)?

please help

Answers

Answer:

= -4

Step-by-step explanation:

To solve this expression, we need to perform the division in the correct order, following the rules of mathematical operations. We can simplify the expression as follows:

(-168) ÷ (-14) ÷ (-3) = (-168) ÷ [(-14) x (-3)] [dividing by a negative number is the same as multiplying by its reciprocal]

= (-168) ÷ 42

= -4

Therefore, the quotient of (-168) ÷ (-14) ÷ (-3) is -4.

Simplify: 27 − 3 exponent 3 + 4 x 2 exponent 2 − 6.

Answers

Answer:

10

Step-by-step explanation:

27-[tex]3x^{3}[/tex]+(4 x [tex]2x^{2}[/tex]) - 6

= 27 - 27 + (4 x 4) - 6

= 0 + 16 - 6

= 10

Answer: 10

Step-by-step explanation:

27 - 3^3 + 4 × 2^2 - 6

= 27 - 27 + 4 × 4 - 6 (since 3^3 = 27 and 2^2 = 4)

= 0 + 16 - 6= 10

Therefore, the simplified value of the expression is 10.

RETIREMENT INCOME A retiree deposits S dollars into an account that earns interest at an annual rate r compounded continuously, and annually withdraws W dollars. a. Explain why the account changes at the rate dt/dV=rV−W where V(t) is the value of the account t years after the account is started. Solve this separable differential equation to find V(t). Your answer will involve r,W, and S. b. Frank and Jessie Jones deposit $500,000 in an account that pays 5\% interest compounded continuously. If they withdraw $50,000 annually, what is their account worth at the end of 10 years? c. What annual amount W can the couple in part (b) withdraw if their goal is to keep their account unchanged at $500,000 ?

Answers

V(t)=S ert-W/r

a. The rate at which the account changes (dt/dV) is equal to the interest rate (r) times the value of the account (V) minus the amount withdrawn (W). This can be written mathematically as dt/dV=rV-W. This is a separable differential equation, which can be solved by integrating both sides of the equation with respect to time. The solution is V(t)=S ert-W/r.



b. The value of the Jones' account at the end of 10 years can be found using the solution V(t) from part a: V(10)=500,000 e5%x10-50,000/5% = $387,468.51.



c. To keep their account unchanged at $500,000, the Jones' must withdraw an annual amount W such that V(t)=500,000. From the solution V(t)=S ert-W/r, we can solve for W: W = 500,000e5%x10 - 500,000/5% = $47,613.30.

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prisim A is similar to prisim B. The volume prisim a is 2080 cm3. what is the volume of prisim B?

Answers

Answer:

2080cm^3

Step-by-step explanation:

A vector u and a set S are given. If possible, write u as a linear combination of the vectors in S.
U = [1]. S = {[1}, [0}}
[1] {[0] [1]}

Answers

vector u can be written as a linear combination of the vectors in set S with the scalars a = 1 and b = 0.

To write vector u as a linear combination of the vectors in set S, we need to find scalars a and b such that:

u = a[1] + b[0]

Substituting the values of vector u and the vectors in set S into this equation, we get:

[1] = a[1] + b[0]

This equation can be simplified to:

[1] = [a] + [0]

Since the scalar b is being multiplied by the zero vector, it will always equal the zero vector, and can therefore be eliminated from the equation. This leaves us with:

[1] = [a]

We can see that the scalar a must equal 1 in order for this equation to be true. Therefore, vector u can be written as a linear combination of the vectors in set S as follows:

u = 1[1] + 0[0]

In conclusion, vector u can be written as a linear combination of the vectors in set S with the scalars a = 1 and b = 0.

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Jill's gym class lasted 50 minutes. She walked around the school track for the first 15 minutes. Then, she played kickball for 25 minutes. She got to play on the playground for the rest of class. After kickball, how long did Jill get to play on the playground?

Answers

Jill played for 10 mins. 25+15=40 50-40=10

Select each expression that is equivalent to 3/16 if x = 3/4
I need an answer ASAP.
A. 2x+1/16
B.3/4 to the power of 2 - 6/16
D. x-1/4
E 2x-x2-3/4

Answers

Option (b) "3/4 to the power of 2 - 6/16" is the expression that is  equivalent to 3/16.

What are expressions?

A formula is a set of two or more numbers or variables and one or more mathematical operations. This mathematical operation is addition, subtraction, multiplication, or division. The formula has the following structure:

The expression is (number/variable, arithmetic operator, number/variable).

Solution according to the given information:

Given, x = 3/4

Option(a): 2x+1/16 = (2×3/4) +1/16

                              = 3/2 + 1/16

                              =25/16

Which is not equal to 3/16

Option(b): (3/4)² - 6/16 = 9/16 - 6/16 = 3/16

Which is equivalent to 3/16

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7.1 Bellwork
1 of 31 of 3 Items
Question
Classify each polygon by the number of sides. Then say whether it is convex or concave, regular or not regular.



shape:
, convex or concave:
, regular or not regular:
.

Answers

The polygons are classified as :-

1.CONVEX

2.CONCAVE

3.CONCAVE

4.REGULAR

5.CONCAVE

6.IRREGULAR

What are polygons?

A polygon is a geometrical figure, with finite sides and angles, they can be regular and irregular.

Regular Polygon

A regular polygon is that which has all its sides and angles equal, for example an equilateral triangle and a square.

Irregular Polygon

A irregular polygon is that which has all its sides and angles unequal,

For example, a scalene triangle, a rectangle, a kite, etc.

Convex Polygon

A Convex polygon is that which has all its angles less than 180 degrees,

Concave Polygon

A Concave polygon is that which has its angles greater than 180 degrees,

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The complete question attached

Two fire towers are located 5 miles apart on a straight road. They both spot the same fire on the north side of the road and report its location in terms of angles from the road. From the tower A, the fire is 22 degrees. From the tower B (5 miles east of tower A), the fire is 37 degree. How far from tower B is the point on the road closest to the fire? Please sketch and show the fire location. The point on the road closest to the fire will be on a line to the fire directly perpendicular to the road. Round to two decimal places

Answers

Tower B is 2.34 miles far from the point on the road closest to the fire.

The point on the road closest to the fire can be found by drawing a line perpendicular to the road that passes through the fire location. Let x be the distance from tower B to this point. Then, using trigonometry, we can find that the distance from tower A to the fire location is x/tan(22) and the distance from tower B to the fire location is (5 - x)/tan(37). Since the fire location is the same from both towers, these distances must be equal, so we can set up the equation x/tan(22) = (5 - x)/tan(37) and solve for x, which is approximately 2.34 miles.

To sketch the fire location, draw a straight road with two fire towers located 5 miles apart. From tower A, draw a line at an angle of 22 degrees towards the north side of the road to represent the direction of the fire location. From tower B, draw a line at an angle of 37 degrees towards the same side of the road. The point where these two lines intersect represents the location of the fire. Draw a line perpendicular to the road passing through this point to find the closest point on the road to the fire.

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Pls give simple working

Answers

Answer:

Step-by-step explanation:

f(x)=x^4−x^2+9

The difference between the digits of a two -digit number is 1. The number itself is one more than five times the sum of its digits. If the unit digit is greater than the tens digit, find the number.

Answers

The number is 63. The difference between the digits of a two-digit number is 1.

What is number?

Number is a mathematical object used to count, measure, and label. Numbers can be represented in a variety of forms, such as numerals, symbols, or words. Numbers are fundamental to mathematics, and all other areas of science and technology. They are used to represent amounts of money, measurements, dates, and amounts of time. Numbers are also used to identify objects and people, and to create equations and formulas. Number is essential for understanding the world around us.

To solve this, the first thing to do is find the sum of the digits. Since the number is one more than five times the sum of its digits, the sum of the digits is (63/5)-1=12.5-1=11.5. This means that the tens digit is 11 and the unit digit is 11 + 1 = 12. Therefore, the two-digit number is 63.

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What is the slope of the line that contains the points (2, -8) and (-4, 4)? PLAAA HEELLO MEEEEE

Answers

Answer:

-2

Step-by-step explanation:

[tex]m=\frac{4-(-8)}{-4-2} \\m=\frac{4+(+8)}{-4-2} \\m=\frac{12}{-6} \\m=\frac{2}{-1} \\m=-2[/tex]

Given the polynomial 3x^(3) - 4x^(2) + 9x - 12, rewrite the polynomial as a product of binomials.

Answers

The polynomial  3x³ - 4x² + 9x - 12 as a product of binomials is (3x - 4)(x² + 3).

To rewrite the polynomial 3x³ - 4x² + 9x - 12 as a product of binomials, we need to factor the polynomial. One method to do this is by grouping. Here are the steps:

1. Group the first two terms and the last two terms: (3x³ - 4x²) + (9x - 12)
2. Factor out the common factor from each group: x²(3x - 4) + 3(3x - 4)
3. Notice that (3x - 4) is a common factor in both groups, so we can factor it out: (3x - 4)(x² + 3)
4. Now we have the polynomial rewritten as a product of binomials: (3x - 4)(x² + 3)

Therefore, the polynomial 3x³ - 4x² + 9x - 12 can be rewritten as (3x - 4)(x² + 3).

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The diameter of a circle is 4 m. Find its area to the nearest whole number.

Answers

2 square times π = 12.56637 = 13

What is the standard equation of this ellipse: Vertices: (0,12)
(0,-12) Foci: (0,8) (0,-8). Why do I keep getting
(x^2)/80+(y^2)/144?

Answers

The standard equation of this ellipse is x²/144 + y²/80 = 1.

The standard equation of an ellipse is (x-h)²/a² + (y-k)²/b² = 1, where (h,k) is the center of the ellipse, a is the semi-major axis, and b is the semi-minor axis.

In this case, the center of the ellipse is (0,0) since the vertices and foci are both on the y-axis. The distance between the vertices is 24 (12 - (-12)), so the semi-major axis is 12. The distance between the foci is 16 (8 - (-8)), so the distance between the center and each focus is 8. Using the formula c² = a² - b², where c is the distance between the center and each focus, we can solve for b:

c² = a² - b²
8² = 12² - b²
64 = 144 - b²
b² = 80

So the equation of the ellipse is (x-0)²/12² + (y-0)²/80 = 1, or x²/144 + y²/80 = 1.

You keep getting (x²)/80 + (y²)/144 because you are switching the values of a and b. The semi-major axis should be in the denominator of the x term, and the semi-minor axis should be in the denominator of the y term.

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Identify and explain any restrictions on the variablex in the expression √6x-2

Answers

The restriction on the variablex is that it must be greater than or equal to 1/3. If x is less than 1/3, the expression √6x-2 will not be a real number.

The restrictions on the variablex in the expression √6x-2 are determined by the fact that the square root of a negative number is not a real number. Therefore, the expression under the square root must be greater than or equal to zero. This gives us the following inequality:

6x-2 ≥ 0

Solving for x, we get:

6x ≥ 2

x ≥ 2/6

x ≥ 1/3

So the restriction on the variablex is that it must be greater than or equal to 1/3. If x is less than 1/3, the expression √6x-2 will not be a real number.

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Evaluate the function f(x)=x²-3x - 8 at the given values of the independent variable and simplify. a. f(8) b. f(x+9) c. f(-x) a. f(8) = (Simplify your answer.) b. f(x + 9) = (Simplify your answer.) c. f(-x) = (Simplify your answer.)

Answers

Answer:

Step-by-step explanation:

Given: [tex]f(x)=x^{2} -3x - 8[/tex]

To find:

a) f(8)

To find f(8), replace x with 8 in f(x)

[tex]f(8) = 8^{2} -3(8) -8 = 32[/tex]

b)  f(x+9)

To find f(x+9), replace x with x +9 in f(x)

[tex]f(x+9) = (x +9)^{2} -3(x +9) -8 = x^{2} +18x+81-3x-27-8=x^{2} +15x+46[/tex]

c) f(-x)

To find f(-x), replace x with -x in f(x)

[tex]f(x)=(-x)^{2} -3(-x) - 8 =x^{2} +3x-8[/tex]

This is how we simplify these expressions.

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