The rewritten rational expression with the indicated denominator of (6x^2) is (10x) / (6x^2). This is because when we multiply both the numerator and denominator of a rational expression by the same quantity, the value of the expression remains the same.
In this case, by multiplying the numerator and denominator of the original expression (5) / (2x) by 5, we get (10x) / (6x^2). We multiplied both the numerator and denominator by 5 because the denominator of the target expression (6x^2) is twice the denominator of the original expression (2x).
This means that the numerator of the target expression should be double the numerator of the original expression. Hence, by multiplying the numerator and denominator of the original expression by 5, we get the target expression.
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Multiply the binomials: (i) 2a-9 and 3a+4 (ii) x-2y and 2x-y (iii ) kl+lm and k-l (iv) m^(2)-n^(2) and m+n
The multiplied the binomials of
2a-9 and 3a+4 is 6a²- 19a - 36. x-2y and 2x-y is 2x² - 5xy + 2y² kl+lm and k-l is k²l - l²m - kl² + lmk m²-n² and m+n is m³ + m²n - mn² - n³Multiplying binomials involves using the distributive property to multiply each term in one binomial by each term in the other binomial.
(i) 2a-9 and 3a+4
(2a-9)(3a+4) = 2a(3a) + 2a(4) - 9(3a) - 9(4) = 6a²+ 8a - 27a - 36 = 6a² - 19a - 36
(ii) x-2y and 2x-y
(x-2y)(2x-y) = x(2x) + x(-y) - 2y(2x) - 2y(-y) = 2x² - xy - 4xy + 2y² = 2x^(2) - 5xy + 2y²
(iii) kl+lm and k-l
(kl+lm)(k-l) = kl(k) + kl(-l) + lm(k) + lm(-l) = k^(2)l - kl²+ lmk - l²m = k²l - l²m - kl² + lmk
(iv) m²-n² and m+n
(m²-n²)(m+n) = m²(m) + m²(n) - n²(m) - n²(n) = m³ + m²n - mn² - n²
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In the diagram, PQ is parallel to RS.
Find the measure of
Write your answer and your work or explanation in the space below.
The measure of <TAV is [tex]92^{o}[/tex].
What are supplementary angles?A set of given angles is said to be supplementary if on addition of the measure of the angles, it gives [tex]180^{o}[/tex].
In the given diagram, given that PQ is parallel to RS, it can be observed that;
<SCU ≅ <ACB (definition of vertically opposite angles)
Thus, <ACB = [tex]18^{o}[/tex]
<QAC = <BCA (alternate angle property)
So that,
<QAC = [tex]18^{o}[/tex]
But,
<TAP ≅ <QAC (definition of vertically opposite angles)
So that;
<BAP + <PAT + <TAV = [tex]180^{o}[/tex] (sum of angles on a straight line)
Then,
70 + 18 + <TAV = 180
<TAV = 180 - 88
= 92
<TAV = [tex]92^{o}[/tex]
The measure of <TAV = [tex]92^{o}[/tex].
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Could someone help me with these problems?
Answer:
too blurry
Step-by-step explanation:
A fair 20-sided die is rolled 60 times, and the value of chi-square is computed using expected counts of 3 for each face. If this process is repeated many times, the shape of the distribution of the values of chi-square should be...
A) uniform
B) bimodal
C) skewed left
D) skewed right
E) approximately normal
The correct answer is E) approximately normal.
When the process of rolling a fair 20-sided die 60 times and computing the value of chi-square using expected counts of 3 for each face is repeated many times, the distribution of the values of chi-square should be approximately normal. This is because the chi-square distribution is a special case of the gamma distribution, and as the degrees of freedom increase, the chi-square distribution approaches a normal distribution. In this case, the degrees of freedom are 19 (20-1), which is a relatively large number, so the distribution should be approximately normal.
To summarize, the repeated process of rolling a fair 20-sided die 60 times and computing the value of chi-square using expected counts of 3 for each face will result in an approximately normal distribution of the values of chi-square.
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Card Name (APR %) Existing Balance Credit Limit Mark2 (6.5%) $475.00 $3,000.00 Bee4 (10.1%) $1,311.48 $2,500.00 You have $450.00 each month to pay off these two credit cards. You decide to pay only the interest on the lower interest card and the remaining amount to the higher interest card. Complete the following two tables to help you. Lower Interst Card (Payoff Option) Month 1 2 3 4 5 6 7 8 9 10 Principal Interest Accrued Payment End-of-month balance Higher Interest Card Month 1 2 3 4 5 6 7 8 9 10 Principal Interest Accrued Payment End-of-month balance 1) How long does it take to pay off the higher interest card? 2) What is the amount of the last payment on the higher interest card? Why? 3) At the end of the month that you pay off the higher interest card, after you have started to pay down your debt on the lower interest card, what is the balance of the lower interest card? Why? 4) Rework the problem so that you pay off the lower interest card first. 5) How much money do you save by paying off the higher interest card first?
-
I really need help on this one
1. 9 months 2) $163.06, because it is the remaining balance after paying off the principal and interest accrued for that month. 3) $348.16, because it is the balance remaining on the lower interest card after paying off the higher interest card and making the monthly payment for that month. 4) 9 months 5) $168.79, because it is the difference between the total amount paid to each card when paying off the higher interest card first versus paying off the lower interest card first.
What is interest ?Interest is the fee paid for the use of borrowed money, usually expressed as a percentage of the borrowed amount.
According to given information :Based on the payment plan described, it will take 12 months to pay off the higher interest card.The amount of the last payment on the higher interest card will be $173.01. This is because the remaining balance after 11 months of payments will be $173.01, which is the amount needed to fully pay off the card.At the end of the month that you pay off the higher interest card, the balance of the lower interest card will be $404.17. This is because during the first 11 months, only the interest was being paid on the lower interest card, so the balance remained the same. However, in the month that the higher interest card is paid off, the full $450 payment will be applied to the lower interest card, reducing the balance by $45.83 to $404.17.If the lower interest card is paid off first, the payment plan and balances would be as follows: Lower Interst Card (Payoff Option) Month 1 2 3 4 5 6 7 8 9 10 Principal Interest Accrued Payment End-of-month balance $475.00 $6.46 $6.46 $6.46 $6.46 $6.46 $6.46 $6.46 $6.46 $6.46 $0.00 Higher Interest Card Month 1 2 3 4 5 6 7 8 9 10 Principal Interest Accrued Payment End-of-month balance $1,311.48 $10.69 $10.69 $10.69 $10.69 $10.69 $10.69 $10.69 $10.69 $10.69 $0.00. Under this payment plan, the lower interest card is paid off in 10 months, and then the remaining payments are applied to the higher interest card, which is paid off in an additional 2 months.By paying off the higher interest card first, you save a total of $141.27 in interest charges over the course of the payment plan.Therefore, 1. 9 months 2) $163.06, because it is the remaining balance after paying off the principal and interest accrued for that month. 3) $348.16, because it is the balance remaining on the lower interest card after paying off the higher interest card and making the monthly payment for that month. 4) 9 months 5) $168.79, because it is the difference between the total amount paid to each card when paying off the higher interest card first versus paying off the lower interest card first.
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The common tangent of a certain compound curve is parallel to its long chord. Its 546m long chord makes an angle of 18° and 12° with the shorter and longer tangents, respectively. Determine the length (m) of the common tangent.
The common tangent of the compound curve is parallel to its long chord. This means that the angle between the common tangent and the long chord is 0°. The long chord makes an angle of 18° with the shorter tangent and 12° with the longer tangent. We can use the law of sines to determine the length of the common tangent.
Let's call the length of the common tangent x, the length of the long chord L, the angle between the common tangent and the long chord θ, the angle between the long chord and the shorter tangent α, and the angle between the long chord and the longer tangent β.
Using the law of sines, we have:
x/sin(θ) = L/sin(α+β)
Substituting the given values, we have:
x/sin(0°) = 546/sin(18°+12°)
Simplifying the equation, we get:
x = 546*sin(0°)/sin(30°)
Since sin(0°) = 0 and sin(30°) = 0.5, we have:
x = 546*0/0.5
x = 0
Therefore, the length of the common tangent is 0m.
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Please help me with this math problem!! Will give brainliest!! :)
Answer:
area=66
perimeter=42
Step-by-step explanation:
area = (12 x 3) + (5 x 6)
=36 + 30
=66
perimeter = 12 +9 +5 +6 +7 +5
=42
How many milliliters of a 100:1000 solution would you need to obtain 40g of active ingredient? Select one: a. 0.4mL b. 4mL c. 400mL d. 40mL
To obtain 40g of active ingredient from a 100:1000 solution, you would need 400mL of the solution. The correct answer is option c. 400mL. A 100:1000 solution means that there are 100g of active ingredient in 1000mL of the solution. To find out how many milliliters of the solution you need to obtain 40g of active ingredient, you can use the following proportion:
100g/1000mL = 40g/x mL
Cross-multiplying gives:
100g * x mL = 40g * 1000mL
Simplifying and solving for x gives:
x = (40g * 1000mL)/100g
x = 400mL
Therefore, you would need 400mL of the 100:1000 solution to obtain 40g of active ingredient.
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List 3 values that would make this inequality true. 4 + g ≥ 9 ____,____,____
One possible set of values that would make the inequality true is:
g = 5
g = 0
g = -1
When we substitute these values into the inequality, we get:
4 + 5 ≥ 9 (true)
4 + 0 ≥ 9 (false)
4 + (-1) ≥ 9 (false)
Therefore, the values that make the inequality true are g = 5, g = 0, and g = -1.
Question 4 1 pts Use the following functions to evaluate each expression
f (x) = x² + 1 g(x) = 1 / (2 - X )
a.) (f + g)(0) = ____
b.) (f . g)(0) = ____
[tex](f+g)(x)= f(x) .g(x)[/tex][tex](f+g)(0) = f(0)+g(0) = 1+\frac{1}{2} = \frac{3}{2}[/tex][tex]g(0) = \frac{1}{2-0} =\frac{1}{2}[/tex]Answer:
Step-by-step explanation:
We are given:
[tex]f(x) = x^{2} +1\ ;g(x) = \frac{1}{2-x}[/tex]
We need to find:
a) [tex](f+g)(0)[/tex]
b) [tex](f.g)(0)[/tex]
[tex]f(0) = 0^{2} +1 = 1[/tex]
[tex]g(0) = \frac{1}{2-0} =\frac{1}{2}[/tex]
a) we know that
[tex](f+g)(x)= f(x) +g(x)[/tex]
[tex](f+g)(0) = f(0)+g(0)[/tex]
Using the value of f(0) and g(0)
we get
b) we know that
[tex](f+g)(x)= f(x) .g(x)[/tex]
[tex](f+g)(x)= f(x) .g(x) = (1)(\frac{1}{2}) =\frac{1}{2}[/tex]
So we have answer for a) 3/2 and for b) 1/2
Using the expressions to evaluate each function we are left with the following:
(f + g)(0) = 1.5(f · g)(0) = 0.5
To evaluate the expressions, we simply need to substitute the value of x with 0 in the given functions and then perform the indicated operations. For part a, we need to add the functions f and g, and for part b, we need to multiply them:
(f + g)(0) = f(0) + g(0) = (0² + 1) + (1 / (2 - 0)) = 1 + (1 / 2) = 1.5
(f · g)(0) = f(0) * g(0) = (0² + 1) * (1 / (2 - 0)) = 1 * (1 / 2) = 0.5
In conclusion, we have that (f + g)(0) = 1.5 and (f · g)(0) = 0.5.
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Add: (x^(2)-4x+9)/(x^(2)+9x+20)+(x-37)/(x^(2)+9x+20) Solution These two fractions have the same denominator, s
The polynomial is (x - 4)(x - 7)/(x + 4)(x + 5).
The question asks to add the two fractions (x^(2)-4x+9)/(x^(2)+9x+20) and (x-37)/(x^(2)+9x+20). To solve this problem, we can first simplify the denominator by factoring the polynomial:
Denominator: (x^(2)+9x+20) = (x + 4)(x + 5)
Now, we can rewrite the two fractions with this new denominator:
(x^(2)-4x+9)/(x + 4)(x + 5) + (x-37)/(x + 4)(x + 5)
Then, we can use the distributive property to expand the fractions and combine like terms:
(x^(2)-4x+9 + x-37)/(x + 4)(x + 5)
= (x^(2) - 3x - 28)/(x + 4)(x + 5)
Finally, we can simplify the numerator by combining like terms:
= (x^(2) - 3x - 28)/(x + 4)(x + 5)
= (x - 4)(x - 7)/(x + 4)(x + 5)
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The graph of function g in terms of x is made by starting with the graph f(x)= square root of x reflecting across the x asis, and then translating to the right 7 units. Write an equation for g (x)
The equation of the graph of the function g(x) is -√(x-7).
What distinguishes a reflection from a translation?Turns are frequently used to refer to reflection, which is when an object is flipped over a line without affecting its size or shape. The preimage is flipped over a line in a rigorous transition known as a reflection, but its size and shape are left unchanged. Flips is another name for reflections.
A figure can be translated if it is moved in any direction without altering its size, form, or orientation. A hard transformation called a translation alters the preimage's position but not its size, shape, or orientation. Slides are another name for translations.
Given that, f(x)= square root of x, that is:
f(x) = √x
Reflect the graph over x-axis we have:
Reflecting f(x) across the x-axis gives us -f(x) = -√x.
Translating -f(x) = -√x 7 units to the right gives us -f(x-7) = -√(x-7).
Hence, the equation of the graph of the function g(x) is -√(x-7).
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1/2x² + 3/8x -2 solve using completing the square
The solution of the equation 1/2x² + 3/8x - 2 using completing the square method are: 1.66 or -2.41.
What is the solution of the quadratic equation?
To solve the equation 1/2x² + 3/8x -2 using completing the square method, follow these steps:
Step 1: Move the constant term to the right-hand side
1/2x² + 3/8x = 2
Step 2: Multiply both sides by 2 to clear the fraction
x² + 3/4x = 4
Step 3: Add the square of half of the coefficient of x to both sides of the equation
x² + 3/4x + (3/8)² = 4 + (3/8)²
The left-hand side is now a perfect square, specifically (x + 3/8)².
Step 4: Simplify the right-hand side of the equation
x² + 3/4x + 9/64 = 256/64 + 9/64
x² + 3/4x + 9/64 = 265/64
Step 5: Take the square root of both sides
x + 3/8 = ±√(265)/8
Step 6: Solve for x
x = -3/8 ± √(265)/8
x = 1.66 or - 2.41
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If u1,u2,u3 are linearly independent, show that v1,v2,v3 are also linearly independent if v1=u1+u2,v2=u1+u3,v3=u2+u3
Yes, if u1, u2, and u3 are linearly independent, then v1, v2, and v3 will also be linearly independent.
To show this, assume that v1, v2, and v3 are linearly dependent. This means that there are scalars a,b, and c, such that:
a*v1 + b*v2 + c*v3 = 0
Since v1 = u1 + u2, v2 = u1 + u3, and v3 = u2 + u3, the equation above can be rewritten as:
a*(u1 + u2) + b*(u1 + u3) + c*(u2 + u3) = 0
Simplifying, this gives us:
(a + b + c)*u1 + (a + c)*u2 + (b + c)*u3 = 0
But since u1, u2, and u3 are linearly independent, the coefficients (a + b + c), (a + c), and (b + c) must all be equal to 0. This implies that a = b = c = 0, meaning that the original equation must be equal to 0. This means that v1, v2, and v3 are linearly independent.
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Use inspection to describe the inequality's solution set. Do not solve the ineque (x-8)^(6)<=0
The inequality's solution set can be described by inspection as x <= 8.
What is inequality?Inequality is the unequal treatment of people based on factors such as race, gender, class, or other social characteristics. It is often seen as unfair and can lead to social and economic disparities.
This is because the inequality (x-8)^(6)<=0 is asking when the quantity (x-8) raised to the 6th power is less than or equal to zero.
Since any number raised to an even power will always be positive or zero, the only way for this inequality to be true is when (x-8) is equal to zero. This occurs when x = 8. Therefore, the solution set is x <= 8.
To summarize, the inequality's solution set is:
x <= 8
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Salve the mquation. If there is more than one solution, separate them with a momm |9a+5|=68
The solution to the equation |9a+5|=68 is a = 7, -8.111. To solve the equation |9a+5|=68, we can use the property of absolute value that states that |x| = x or |x| = -x. This means that we can set up two equations to solve for a:
9a+5 = 68 or 9a+5 = -68
Now we can solve each equation separately:
9a+5 = 68
9a = 63
a = 7
9a+5 = -68
9a = -73
a = -8.111
So the solutions are a = 7 and a = -8.111. We can write these solutions separated by a comma as follows:
a = 7, -8.111
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In a coordinate plane, shade the region that consists of all points that have positive x-and y-coordinates whose sum is less than 5. Write a system of three inequalities thatdescribes this region.
The system of three inequalities that describes this region is:x > 0y > 0x + y < 5
In a coordinate plane, the region that consists of all points that have positive x-and y-coordinates whose sum is less than 5 is the triangular region in the first quadrant bounded by the x-axis, y-axis, and the line x + y = 5. The system of three inequalities that describes this region is:x > 0y > 0x + y < 5Explanation:To find the region that consists of all points that have positive x-and y-coordinates whose sum is less than 5, we need to first graph the line x + y = 5 on a coordinate plane. This line has a slope of -1 and passes through the points (0,5) and (5,0). The region that we are looking for is the triangular region in the first quadrant bounded by the x-axis, y-axis, and this line.To write a system of three inequalities that describes this region, we need to consider the following facts:- All points in this region have positive x-coordinates, so x > 0.- All points in this region have positive y-coordinates, so y > 0.- All points in this region have x-and y-coordinates whose sum is less than 5, so x + y < 5.Therefore, the system of three inequalities that describes this region is:x > 0y > 0x + y < 5
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Use the properties of kites to answer the questions.
a. If AB = 8x-2, and AD = 6x+4, solve for AD.
b. If mPlease show your work.
The values of the length and angle are;
AD = 22 units
m < ADC = 106 degrees
How to determine the valuesThe properties of a kite are given as;
It has one pair of opposite angles that are equalThe shorter diagonal forms two equal isosceles trianglesThe longer diagonal forms two equal or congruent trianglesThe diagonals are perpendicular to each otherIt has two adjacent and equal sidesFrom the information given, we have that;
AB = 8x - 2
AD = 6x + 4
Equate the sides
8x - 2 = 6x + 4
collect like terms
2x = 6
x = 3
AD = 22 units
Also,
m < ABC = m < ADC
Substitute the values
12x + 10 = 15x - 14
collect like terms
-3x = -24x
x = 8
m < ADC = 106 degrees
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Answer: AD = 22 units
Step-by-step explanation:
m < ADC = 106 degrees
AB = 8x - 2
AD = 6x + 4
Equate any sides
8x - 2 = 6x + 4
Collect terms
2x = 6
x = 3
AD = 22 units
m < ABC = m < ADC
Substitute the values
12x + 10 = 15x - 14
Collect terms
-3x = -24x
x = 8
m < ADC = 106 degrees
Find all solutions of the equation: 2 cos x-1-0
I NEED HELP ASAP!
The solutions to the cosine functions are x = π/3 + 2nπ or x = 5π/3 + 2nπ, where n is an integer and x = 3π/4 + 2nπ or x = 5π/4 + 2nπ, where n is an integer.
What are the solutions of the equation1. 2 cos x - 1 = 0
Adding 1 to both sides and dividing by 2, we get:
cos x = 1/2
This equation has solutions for x of π/3 and 5π/3 (plus any integer multiple of 2π, since the cosine function is periodic with period 2π).
Therefore, the solutions are:
x = π/3 + 2nπ or x = 5π/3 + 2nπ, where n is an integer.
2. 5 cos x + 3√2 = 3 cos x + 2√2
Subtracting 3 cos x and 2√2 from both sides, we get:
2 cos x = -√2
Dividing by 2, we get:
cos x = -√2/2
This equation has solutions for x of 3π/4 and 5π/4 (plus any integer multiple of 2π).
Therefore, the solutions are:
x = 3π/4 + 2nπ or x = 5π/4 + 2nπ, where n is an integer.
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What is the weighted mean, if each unit has the following weightings? (4 pts) Trigonometry counts for 25% Algebra counts for 15% Statistics counts for 10% Financial Math counts for 12% Linear Functions counts for 20 % Quadratic Functions counts for 18% Use the chart provided to organize your work for this question.
The weighted mean is a type of average that takes into account the relative importance of each data point. In this case, each unit has a different weighting, so we need to take that into account when calculating the weighted mean. Here is how to calculate the weighted mean:
1. Multiply each unit's weighting by its corresponding value.
2. Add up all of the products from step 1.
3. Divide the sum from step 2 by the sum of all the weightings.
Using the chart provided, here is how to calculate the weighted mean for this question:
Unit Weighting Value Product
Trigonometry 25% x 0.25x
Algebra 15% y 0.15y
Statistics 10% z 0.1z
Financial Math 12% a 0.12a
Linear Functions 20% b 0.2b
Quadratic Functions 18% c 0.18c
Weighted mean = (0.25x + 0.15y + 0.1z + 0.12a + 0.2b + 0.18c) / (0.25 + 0.15 + 0.1 + 0.12 + 0.2 + 0.18)
Weighted mean = (0.25x + 0.15y + 0.1z + 0.12a + 0.2b + 0.18c) / 1
Weighted mean = 0.25x + 0.15y + 0.1z + 0.12a + 0.2b + 0.18c
So the weighted mean is a combination of the values of each unit, weighted by their relative importance.
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How would you modify the statement of the limit of a rational function?
This would give us a modified statement of the limit, which would be "the limit of the rational function as x approaches 4".
What is rational function?A rational function is a type of mathematical function that can be expressed as the ratio of two polynomials. It can be written in the form f(x) = p(x)/q(x), where p(x) and q(x) are polynomials with q(x) not equal to zero. Rational functions are used to model many real-world phenomena, such as the rate of change of a quantity with respect to another. They can also be used to solve complex equations and to analyze the behavior of a system.
The statement of the limit of a rational function can be modified by substituting different values for the variable and determining the resulting limit. For example, if the limit of the rational function is as x approaches 3, then we can substitute x = 4 and determine the resulting limit. This would give us a modified statement of the limit, which would be "the limit of the rational function as x approaches 4".
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14x + 2 is equivalent to 16x True or False
Answer:
false
Step-by-step explanation:
the pothagirum therum say that theres many reason its false
Answer: True
Step-by-step explanation:
True because we do not know the letters value, so in this case you only add the numbers 14 and 2. You will end up with the answer 16x after adding the letter/valuable.
Watch help video Solve for all values of x : (1)/(x-1)-1=(x)/(x-1) Answer: Submit Answer
The is no solution of the equation (1)/(x-1)-1=(x)/(x-1).
To solve for all values of x in the equation (1)/(x-1)-1=(x)/(x-1), we can follow these steps:
1. Multiply both sides of the equation by (x-1) to eliminate the denominators:
1 - (x-1) = x
2. Simplify the left side of the equation:
- x + 2 = x
3. Add x to both sides of the equation to isolate the variable on one side:
2 = 2x
4. Divide both sides of the equation by 2 to solve for x:
x = 1
Therefore, the solution for x is 1.
When we plug x = 1 back into the original equation, we get a denominator of 0, which is undefined. This means that there are actually no solutions for this equation.
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Alexis is traveling to Egypt this summer and needs to exchange 750 US Dollars to Egyptian pounds.
How many Egyptian pounds will Alexis receive with the following exchange rate?
1 USD = 18.48 Egyptian pounds
Enter the correct answer in the box.
( ) Egyptian pounds
Answer:
13,860 egyptian pounds
Answer:
Step-by-step explanation:
1 USD = 18.48 Egyptian pounds
∴ 750 USD = 750 × 18.48 Egyptian pounds
= 13860 Egyptian pounds
In the drawing, >ℎ
. Which statement about the volumes of the two cylinders is true?
Answer: As the two cylinders have the same height, the cylinder with the greater radius will have the greater volume. Therefore, the statement "The cylinder with radius has a greater volume than the cylinder with radius /2" is true.
Step-by-step explanation:
difierence between 220 and the age of the person. The uppet limit is found by using 65% of the dilterence. Complete parts a throoph d. a. Find formulas for the upper and lower limits (U and L ) as finear equations involving the age x U= (Use integers or decimals for any tumbers in the equaton. Do nol factor.) L= (Use integers or decimals for any numbers in the equation. Do not factor.) b. What is the target heart rate zone for a 40 -year-old? For a 40-year-odd person, the lower limit is and the upper limit is beats per minule. c. What is the target hean nate zone for a 60 -year-eld? For a 60-year-old person, the lower limit is and the ueper linit is beatt per minute. d. Two wemen in an aerobics dass slop to take their pulse and find that they have the same pulse. One woman is 34 years older than the other and is working at the upper imit of har target heart rate zone. The younger woman is woking at the lower limit of her target hewrt rate zone. What are the ages of the two women, and what is their pulse? The age of the younger woman is approximately years and that of older woman is approximiely years. (Round to Een nearedt integers as needed) Their pulse is agproximately beats per minute. (Round to the nearest integor as neoded)
a. The formula for the upper limit (U) is U = 220 - x, where x is the age of the person. The formula for the lower limit (L) is L = 0.65(220 - x).
b. For a 40-year-old person, the lower limit is L = 0.65(220 - 40) = 117 beats per minute and the upper limit is U = 220 - 40 = 180 beats per minute.
c. For a 60-year-old person, the lower limit is L = 0.65(220 - 60) = 104 beats per minute and the upper limit is U = 220 - 60 = 160 beats per minute.
d. Let x be the age of the younger woman and y be the age of the older woman. Since the older woman is 34 years older than the younger woman, we have y = x + 34. Since the older woman is working at the upper limit of her target heart rate zone and the younger woman is working at the lower limit of her target heart rate zone, we have U = L. Substituting the formulas for U and L, we get 220 - y = 0.65(220 - x). Substituting y = x + 34, we get 220 - (x + 34) = 0.65(220 - x). Simplifying and solving for x, we get x = 38. Therefore, the age of the younger woman is approximately 38 years and that of the older woman is approximately 72 years. Their pulse is approximately U = 220 - 72 = 148 beats per minute.
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A circle with center C and a radius of 10 inches (in) is shown above. Rounded to the nearest tenth of an inch, what is the length of arc XYZ
The length of the arc XYZ is 59.3 inches .
How to find the length of an arc?The radius of the circle is 10 inches. The central angle that subtend the arc is 340 degrees.
Therefore, the length of the arc xyz can be found as follows:
length of an arc = ∅/ 360 × 2πr
where
∅= central angler = radius of the circlelength of an arc(xyz) = 340 / 360 × 2 × 3.14 × 10
length of an arc(xyz) = 21352 / 360
length of an arc(xyz) = 59.3111111111
length of an arc(xyz) = 59.3inches
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Problem-2: A matrix, M, is given. Obtain the inverse of this matrix using Matlab. Note that you are not allowed to use Matlab inv() command. M=[\begin{array}{ccc}6&8\\1&4\end{array}\right]
Method of inverse of matrix is given:
To obtain the inverse of the given matrix, M, without using the Matlab inv() command, you can use the following steps:
1. Compute the determinant of M, which is equal to 2.
2. Create the matrix of cofactors by taking the transpose of the matrix formed by the cofactors of the elements of M.
3. Divide each element of the cofactor matrix by the determinant of M, in this case 2, to obtain the inverse of M.
Therefore, the inverse of M is given by the following matrix: M-1 = [\begin{array}{ccc}\frac{4}{2}&-\frac{8}{2}\\-\frac{1}{2}&\frac{6}{2}\end{array}\right]
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PLSS PICK A ANSWER CHOICE PLEASE AND THXXSSSS
XOXOXOXO HURRY
Answer: I believe its A.
Step-by-step explanation:
Select all the correct answers. Which equations represent functions? 2x + 3y = 10 4x = 16 2x − 3 = 14 3y = 18 14.6 = 2x
The equations that represent functions are:
1) 2x + 3y = 10
2) 3y = 18
What is a function?Functions are relations which give a particular output for each input. The characteristic that every input is associated with exactly one output defines a function as a relationship between a set of inputs and a set of allowable outputs. Specific input is supplied to a function in order to produce a specific result. To determine if a curve is a function or not, apply the vertical line test. Any curve that intersects a vertical line at more than one point is not a function.
Let us look into each equation.
1) 2x + 3y = 10
Here for each input of x, we get only one output y.
So this is a function.
2) 4x = 16
This is not a function because there can be multiple values of y for a single value of x.
3) 2x − 3 = 14
This is also not a function because there can be multiple values of y for a single value of x.
4) 3y = 18
This is a function because there is only one value of y for exactly one value of x. Also, considering the vertical line test, the curve is a straight horizontal line which intersects with a given vertical line only once. So it is a function.
5)14.6 = 2x
This is also not a function because there can be multiple values of y for a single value of x.
Therefore the equations that represent functions are:
1) 2x + 3y = 10
2) 3y = 18
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