Quadrilateral ABCD is inscribed in a circle.
What is the measure of angle A?
Enter your answer in the box.
m/A=

The Quick Meals Diner served 131 child plates and 157 adult plates.

Let's use a system of two equations to represent the given information:

c + a = 288     (1)   // The number of child and adult plates served add up to 288

2.5c + 8.2a = 1614.9   (2)   // The total amount collected is the sum of the prices of all plates served

where c represents the number of child plates served and a represents the number of adult plates served.

We can use equation (1) to solve for c in terms of a:

c = 288 - a

Substituting this expression for c into equation (2), we get:

2.5(288 - a) + 8.2a = 1614.9

720 - 2.5a + 8.2a = 1614.9

5.7a = 894.9

a = 157

So, 157 adult plates were served. Substituting this value into equation (1), we get:

So, 157 adult plates were served. Substituting this value into equation (1), we get:

So, 131 child plates were served.

Therefore, The result is 131 child plates and 157 adult plates.

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Step-by-step explanation:

Toby's loan amount is $450 and the finance charge is $50 every two weeks. He rolls over the loan 4 times.

Total cost = $450 + ($50 x (1 + 4))

Total cost = $450 + ($50 x 5)

Total cost = $450 + $250

Total cost = $700

Therefore, the total cost of Toby's payday loan is $700.

Tabitha's loan amount is $300 and the finance charge is $40 every two weeks. She rolls over the loan 6 times.

Total cost = $300 + ($40 x (1 + 6))

Total cost = $300 + ($40 x 7)

Total cost = $300 + $280

Total cost = $580

Therefore, the total cost of Tabitha's payday loan is $580.

Sariah's loan amount is $500 and the finance charge is $45 every two weeks. She rolls over the loan 7 times.

Total cost = $500 + ($45 x (1 + 7))

Total cost = $500 + ($45 x 8)

Total cost = $500 + $360

Total cost = $860

Therefore, the total cost of Sariah's payday loan is $860

Answer:

#6.

Loan amount = $450

Finance charge = $50 every two weeks

Number of rollovers or renewals = 4

Total Cost = 450 + (50 x (1 + 4))

Total Cost = 450 + 250

Total Cost = $700

The total cost of Toby's loan is $700.

#7.

Loan amount = $300

Finance charge = $40 every two weeks

Number of rollovers or renewals = 6

Total Cost = 300 + (40 x (1 + 6))

Total Cost = 300 + 280

Total Cost = $580

The total cost of Tabitha's loan is $580.

#8.

Loan amount = $500

Finance charge = $45 every two weeks

Number of rollovers or renewals = 7

Total Cost = 500 + (45 x (1 + 7))

Total Cost = 500 + 360

Total Cost = $860

The total cost of Sariah's loan is $860.

The approximate area of Central Park is about 450 square blocks.

The given dimensions of the park stated in the question are

Length of Central Park = 50 blocks

Width of Central Park = 9 blocks

The approximate area of Central Park is the product of its length and width:

So, we have

Area of Central Park = Length x Width

When the given values are substituted into the the equation mentioned above, we obtain the subsequent expression

Area = 50 * 9

Evaluate

Area = 450

Hence, the approximate area is about 450 square blocks.

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The product of ((4)/(3)x-6) and ((5)/(6)x+(5)/(3)) as a trinomial in simplest form is (10/9)x^2 + (-10/9)x + (-10).

To express the product of ((4)/(3)x-6) and ((5)/(6)x+(5)/(3)) as a trinomial in simplest form, we need to multiply the two expressions together and then simplify. Here are the steps:

1. Distribute the first term of the first expression to the second expression: (4/3)x * (5/6)x + (4/3)x * (5/3) = (20/18)x^2 + (20/9)x
2. Distribute the second term of the first expression to the second expression: -6 * (5/6)x + -6 * (5/3) = (-30/6)x + (-30/3)
3. Combine the like terms: (20/18)x^2 + (20/9)x + (-30/6)x + (-30/3) = (20/18)x^2 + (-10/9)x + (-30/3)
4. Simplify the fractions: (10/9)x^2 + (-10/9)x + (-10)

So the product of ((4)/(3)x-6) and ((5)/(6)x+(5)/(3)) as a trinomial in simplest form is (10/9)x^2 + (-10/9)x + (-10).

The product of ((4)/(3)x-6) and ((5)/(6)x+(5)/(3)) as a trinomial in simplest form is (10/9)x^2 + (-10/9)x + (-10).

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We can conclude that -

The exponential function is of the form -

f(x) = eˣ

Given is to write the exponential growth and exponential decay equation.

{ 1 } -

The general exponential growth equation is -

[tex]$f(x)=a(1+r)^{x}[/tex]

{ 2 } -

The general exponential decay equation is -

[tex]$\frac {dN}{dt}= -\lambda N[/tex]

Option {A} and option {E} represent the exponential decay. Option {B}, {E} and {D} represent exponential growth.

Therefore, we can conclude that -

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Answer:

it’s 159 sorry

Step-by-step explanation:

10 to the second power is 10x10 which is 100 then 8 to the second power is 8x8 which is 64. 164-5 is 159, I apologize.

Step-by-step explanation:

Using the formula V = Pe^(rt), we have:

P = $741

r = 0.058 (since the interest rate is 5.8%)

t = 13

So, V = 741e^(0.05813) = $1613.87 (rounded to the nearest cent)

Therefore, the amount of money in the account after 13 years is $1613.87.

Answer:

Step-by-step explanation:

Answer: Y=6/5

Step-by-step explanation:

Y=1/4X+6/5

(set X to zero 1/4(0) = 0)

Y=0+6/5

Y=6/5

Answer:

Exact form: 121π

Decimal form: 380.1327111...

Step-by-step explanation:

The area of the circle is given by the formula A = πr², where A is the area of the circle and r is the radius.

Given the diameter of 22cm, we know that the radius is 11cm, as the radius is half the diameter.

We can then put this into the formula to find the area of the circle:

A = πr²

A = π * 11²

A = 121π

Note that the answer here is given in terms of π so it can be expressed in its exact form, as 121π is an irrational number roughly equivalent to 380.1327111... The answer you need to provide will depend on whether the question asks for the exact form, or to a certain number of decimal places / significant figures. If it the latter, you can round off the decimal answer as appropriate.

The solution to the given rational expressions is (z - 2)/(z^(2)+4z-12).

To subtract rational expressions with common denominators, we simply subtract the numerators and keep the same denominator.

In this case, our common denominator is (z^(2)+4z-12),  so we can subtract/add the numerators:

So, we will subtract the numerators, (z) - (2), and keep the same denominator:
(z)/(z^(2)+4z-12)-(2)/(z^(2)+4z-12) = (z - 2)/(z^(2)+4z-12)

Now, we can simplify the numerator by combining like terms:
(z - 2)/(z^(2)+4z-12) = (z - 2)/(z^(2)+4z-12)

Since the numerator and denominator cannot be simplified any further, this is our final answer:
(z - 2)/(z^(2)+4z-12)

Therefore, the solution to the subtraction of the given rational expressions is (z - 2)/(z^(2)+4z-12).

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No, 5x^2+y=0 is not a direct variation.

Direct variation is a relationship between two variables, x and y, where y is directly proportional to x, meaning that as x increases, y increases in proportion to x, and as x decreases, y decreases in proportion to x.

The equation 5x^2+y=0 does not satisfy this relationship since y is not directly proportional to x. As x increases or decreases, y may change in a non-proportional manner due to the presence of the constant term.

An example of a direct variation equation is y = kx, where k is a constant. In this equation, y is directly proportional to x, with a constant of proportionality k.

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The value of 8 cos(2x) accurate to 4 decimal places is -3.6009.

We can start by drawing a right triangle in Quadrant 1 with an angle x, where the opposite side is 13 and the adjacent side is 8.

Using the Pythagorean theorem, we can find the hypotenuse of the triangle:

 [tex]c^2 = a^2 + b^2\\ c^2 = 13^2 + 8^2\\ c^2 = 169 + 64\\ c^2 = 233\\ c = \sqrt{(233)}[/tex]

Now we can use trigonometric identities to find cos(2x):

[tex]cos(2x) = cos^2(x) - sin^2(x)[/tex]

We can find sin(x) using the triangle we drew earlier:

sin(x) = opposite / hypotenuse

sin(x) = 13 / [tex]\sqrt{(233)}[/tex]

And we can find cos(x) using the triangle as well:

cos(x) = adjacent / hypotenuse

cos(x) = 8 / [tex]\sqrt{(233)}[/tex]

Plugging these values into the identity for cos(2x):

[tex]cos(2x) = cos^2(x) - sin^2(x)\\cos(2x) = (8 / \sqrt{(233))^2} - (13 /\sqrt{(233))^2} \\cos(2x) = (64 / 233) - (169 / 233)\\cos(2x) = -105 / 233[/tex]

Finally, we can find 8 cos(2x):

8 cos(2x) = 8 * (-105 / 233)

8 cos(2x) = -3.6009 (rounded to 4 decimal places)

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The point where the two lines come together (1,1). Hence, x = 1 and y = 1 are the answers to the system of equations.

Algebraically speaking, an equation is a statement that shows the equality of two mathematical expressions. For instance, the two equations 3x + 5 and 14, which are separated by the 'equal' sign, make up the equation 3x + 5 = 14.

The technique of solving a system of equations involves calculating the unknown variables while maintaining the equations balanced on both sides. We solve an equation system by identifying the value of the variable that makes the condition of all the provided equations true.

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Answer: x=6, y=8

Using elimination means that we eliminate one of the variables in both equations which help find out the other variable, which we then substitute to find the whole equation.

    3x-4y=-14

+   3x+2y=-2

=>-4y=-14

+   2y=-2

=>-2y=-16

=>y=8

So to find x,

3x-4(8)=-14

=3x=-14+32

=x=18/3 so x=6

PLEASE MARK BRAINLIEST IF THIS HELPED!

The formula holds for k + 1.

What is mathematical induction?

Mathematical induction is a method of mathematical proof used to establish the truth of a statement for an infinite set of values.

To prove the formula for every positive integer n:

3 + 11 + 19 + 27 + ... + (8n - 5) = n(4n - 1)

using mathematical induction, we need to show two things:

Step 1: Base Case

When n = 1, we have:

3 = 1(4(1) - 1)

Simplifying the right-hand side gives:

3 = 3

So the formula holds for n = 1.

Step 2: Inductive Step

Now assume that the formula holds for some positive integer k, which means:

3 + 11 + 19 + 27 + ... + (8k - 5) = k(4k - 1)

We need to show that the formula also holds for k + 1. That is, we need to show that:

3 + 11 + 19 + 27 + ... + (8(k+1) - 5) = (k+1)(4(k+1) - 1)

Starting with the left-hand side of this equation:

3 + 11 + 19 + 27 + ... + (8(k+1) - 5)

= (3 + 11 + 19 + 27 + ... + (8k - 5)) + (8(k+1) - 5) (by adding the next term)

= k(4k - 1) + (8k + 3) (by substituting the formula for k)

[tex]= 4k^2 - k + 8k + 3[/tex]

[tex]= 4k^2 + 7k + 3[/tex]

Now, we simplify the right-hand side of the equation:

(k+1)(4(k+1) - 1)

= (k+1)(4k + 3)

[tex]= 4k^2 + 7k + 3[/tex]

We can see that the left-hand side and the right-hand side are equal.

Hence, the formula holds for k + 1.

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An ellipse has an equation equal to 9x^2-144x+16y^2+96y+495=0, the eccentricity of the curve is √7/4.

To compute the eccentricity of the curve of an ellipse, we must first complete the square for both x and y terms to put the equation in standard form.

Complete the square for x terms:
9x²- 144x + 495 = -16y² - 96y
9(x² - 16x) + 495 = -16(y² + 6y)
9(x²- 16x + 64) + 495 - 9(64) = -16(y² + 6y)
9(x - 8)² + 39 = -16(y² + 6y)

Complete the square for y terms:
9(x - 8)² + 39 = -16(y² + 6y)
9(x - 8)² + 39 = -16(y² + 6y + 9) + 16(9)
9(x - 8)² + 39 - 16(9) = -16(y + 3)²
9(x - 8)² - 105 = -16(y + 3)²

Move constant term to the right side of the equation and divide by -105:
9(x - 8)² - 16(y + 3)² = 105
-9(x - 8)²/105 + 16(y + 3)²/105 = 1
(x - 8)²/(105/9) + (y + 3)²/(105/16) = 1

Identify the values of a^2 and b^2:
a² = 105/9
b² = 105/16

Compute the eccentricity using the formula e = √(1 - (b²/a²)):
e = √(1 - ((105/16)/(105/9)))
e = √(1 - (9/16))
e = √(7/16)
e = √7/4

Therefore, the eccentricity of the curve is √7/4.

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The requested functions are:

a. (f+g)(x) = (3x^2-4x-14)/(x−3)

b. (f∙g)(x) = (3x+5)/(x−3)

c. (2f+3g)(x) = (6x^2+7x-21)/(x−3)

d. (3g−4f)(x) = (-12x^2+8x+57)/(x−3)

Given the functions f(x)=3x+5 and g(x)=1/(x−3), we can find the requested functions by applying the corresponding operations to the functions.

a. (f+g)(x) = f(x) + g(x) = (3x+5) + (1/(x−3)) = (3x(x−3)+5(x−3)+1)/(x−3) = (3x^2-4x-14)/(x−3)

b. (f∙g)(x) = f(x) ∙ g(x) = (3x+5) ∙ (1/(x−3)) = (3x+5)/(x−3)

c. (2f+3g)(x) = 2f(x) + 3g(x) = 2(3x+5) + 3(1/(x−3)) = (6x+10+3/(x−3)) = (6x(x−3)+10(x−3)+3)/(x−3) = (6x^2+7x-21)/(x−3)

d. (3g−4f)(x) = 3g(x) - 4f(x) = 3(1/(x−3)) - 4(3x+5) = (3-4(3x+5)(x−3))/(x−3) = (-12x^2+8x+57)/(x−3)

Therefore, the requested functions are:

a. (f+g)(x) = (3x^2-4x-14)/(x−3)

b. (f∙g)(x) = (3x+5)/(x−3)

c. (2f+3g)(x) = (6x^2+7x-21)/(x−3)

d. (3g−4f)(x) = (-12x^2+8x+57)/(x−3)

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Answer:

Step-by-step explanation:

4-5 would be less than 1 so it would be -1

Answer:

We can use the given formula to solve for the cost C:

P = R - C

We know that P = $49.32 and R = $81.18, so we can substitute these values into the formula:

$49.32 = $81.18 - C

Next, we can solve for C by isolating it on one side of the equation:

C = $81.18 - $49.32

C = $31.86

Therefore, it cost Zach $31.86 to make the jewelry he sold at the fair.

Answer:

12

Step-by-step explanation:

Its easy and right

Answer:

2

Step-by-step explanation:

For 4 and 6, the common factors are 1 and 2. Since 2 is the highest among the given factors, HCF will be 2 for 4 and 6.

F = Fran's income

W = Winston's income

[tex]F+W=80000\hspace{5em}\stackrel{ \textit{one quarter} }{\cfrac{W}{4}}=\stackrel{ \textit{one sixth} }{\cfrac{F}{6}} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{\textit{using the 1st equation}}{F+W=80000}\implies F=80000-W \\\\[-0.35em] ~\dotfill[/tex]

[tex]\stackrel{\textit{using the 2nd equation}}{\cfrac{W}{4}=\cfrac{F}{6}}\implies \stackrel{\textit{substituting from above}}{\cfrac{W}{4}=\cfrac{80000-W}{6}}\implies 6W=320000-4W \\\\\\ 10W=320000\implies W=\cfrac{320000}{10}\implies \boxed{W=32000}~\hfill \stackrel{ 80000~~ - ~~32000 }{\boxed{F=48000}}[/tex]

Answer:

[tex](5x-1)(x+4)[/tex]

Step-by-step explanation:

Given:

[tex]5x^2 +19x-4[/tex]

Factor the expression by grouping. First, the expression needs to be rewritten as [tex]5x^2 +ax+bx-4[/tex]. To find a and b, set up a system to be solved.

[tex]a+b=19[/tex]

[tex]ab=5(-4)=-20[/tex]

Since [tex]ab[/tex] is negative, a and b have the opposite signs. Since [tex]a+b[/tex] is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product [tex]-20[/tex].

[tex]-1,20[/tex]

[tex]-2,10[/tex]

[tex]-4,5[/tex]

Calculate the sum for each pair.

[tex]-1+20=19[/tex]

[tex]-2+10=8[/tex]

[tex]-4+5=1[/tex]

The solution is the pair that gives sum [tex]19[/tex].

[tex]a=-1[/tex]

[tex]b=20[/tex]

Rewrite [tex]5x^2+19x-4[/tex] as [tex](5x^2-x)+(20x-4)[/tex].

Factor out x in the first and 4 in the second group.

[tex]x(5x-1)+4(5x-1)[/tex]

Factor out common term [tex]5x-1[/tex] by using distributive property.

[tex](5x-1)(x+4)[/tex]

Therefore, [tex](5x-1)(x+4)[/tex].

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1) the probability that all three of them hit the target is 3/10,  none of them hit the target 1/40, only John hits the target 3/40, 2) a red marble is chosen from plastic X is 2/9, a white marble is chosen from plastic Y is 4/15, a red marble is chosen is 2/9,  a marble is chosen from plastic Y if it is known that it is red is 2/5.

1. a) The probability that all three of them hit the target is the product of their individual probabilities:
P(all three hit the target) = P(John hits the target) × P(Sam hits the target) × P(Grey hits the target)
= (3/4) × (1/2) × (4/5)
= 12/40
= 3/10

b) The probability that none of them hit the target is the product of their individual probabilities of not hitting the target:
P(none hit the target) = P(John doesn't hit the target) × P(Sam doesn't hit the target) × P(Grey doesn't hit the target)
= (1 - 3/4) × (1 - 1/2) × (1 - 4/5)
= (1/4) × (1/2) × (1/5)
= 1/40

c) The probability that only John hits the target is the product of his probability of hitting the target and the other two's probabilities of not hitting the target:
P(only John hits the target) = P(John hits the target) × P(Sam doesn't hit the target) × P(Grey doesn't hit the target)
= (3/4) × (1 - 1/2) × (1 - 4/5)
= (3/4) × (1/2) × (1/5)
= 3/40

2. The tree diagram for this game is as follows:

       Die
      /   \
     /     \
    /       \
   /         \
  /           \
 /             \
<3             >=3
/ \           / \
X   Y         X   Y
/ \ / \       / \ / \
R W R W      R W R W

a) The probability that a red marble is chosen from plastic X is the product of the probability of the die outcome being less than 3 and the probability of choosing a red marble from plastic X:
P(red from X) = P(die < 3) × P(red from X)
= (2/6) × (4/6)
= 8/36
= 2/9

b) The probability that a white marble is chosen from plastic Y is the product of the probability of the die outcome being greater than or equal to 3 and the probability of choosing a white marble from plastic Y:
P(white from Y) = P(die >= 3) × P(white from Y)
= (4/6) × (2/5)
= 8/30
= 4/15

c) The probability that a red marble is chosen is the sum of the probabilities of choosing a red marble from plastic X and from plastic Y:
P(red) = P(red from X) + P(red from Y)
= (2/9) + (4/15)
= 10/45
= 2/9

d) The probability that a marble is chosen from plastic Y if it is known that it is red is the probability of choosing a red marble from plastic Y divided by the probability of choosing a red marble:
P(Y | red) = P(red from Y) / P(red)
= (4/15) / (2/9)
= 12/30
= 2/5

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Throughout the hour, 70 percentage of customers add chocolate creamer to their coffee.

Find the proportion of consumers who selected chocolate creamer and add up all of the customers who visited throughout the hour to determine the appropriate percentage.

The number of clients who selected chocolate creamer is calculated by dividing the total number of customers by 100.

Here it is,

For one hour, the manager of a coffee shop counted the number of patrons who added vanilla or chocolate creamer to their coffee.

The question given is:

                         Vanilla      Chocolate    

Age 18 - 30            2               6

Age 30 +                4               8      

2 + 4 + 6 + 8 Equals 20 clients in this instance.

6 + 8 = 14 is the number of clients who select chocolate creamer.

Customers that used chocolate creamer made up: [14/20] / 100 = 70%

As a result, 70% of consumers at that time add chocolate creamer to their coffee.

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The complete question is:

The manager of a coffee shop recorded the number of customers who put vanilla creamer or chocolate creamer in their coffee during one hour and classified them by age. The results are shown in the table. Coffee Creamer. Vanilla. Chocolate. Age 18 to 30. 2, 6. Age 31 plus. 4, 8 What percentage of these customers put chocolate creamer in their coffee during this hour?

Answer:

70%

Step-by-step explanation:

i did the quiz lol

Answer:

Step-by-step explanation:

I'm guessing you need the volume of the bead with the hole.

We need to get the volume of two objects; a cube and a cylinder. We need the cylinder for the hole.

V(square) = 6^3

V(square) = 216 mm^3

V(cylinder) = pi(r^2)(h)

pi(1.5^2)(6)

Radius is half the diameter, and 6 represents the height, since it's as long as the cube.

V(cylinder) = 42.41 or 13.5pi

We need to do V(s) - V(c) to find the volume of the bead.

216 - 13.5pi = 173.588 or 173.59 or 173.6

I hope this helps!

156 customers are expected to wear a black shoe.

Probability can be defined as the ratio of the number of favorable outcomes to the total number of outcomes of an event.

We know that, probability of an event = Number of favorable outcomes/Total number of outcomes

As per the given data:

Customers with black shoes = 13 out of 30

Customers with brown shoes = 17 out of 30

Total customers in the mall = 360

Probability that a customer wears black shoes:

P(B) = 13/30 = 0.433

Number of customers out of 360 expected to wear black shoes:

= P(B) × 360

= 0.433 × 360

= 156 customers.

Hence, 156 customers are expected to wear a black shoe.

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Answer:

Step-by-step explanation:

you have 22 bucks and your mom took 2

22-2=20

My Answer:

22-2= 20, right? She can't drink anymore wine if you (shown as "i") used the remaining 20$. Tell me if this makes sense. No wine (none) is consumed if you have no money left.

Answer from Artificial Intellegence (to get another view on the question so you can figure out the best answer):

If you had 22 bucks and your mom took 2 dollars for her weekly wine tasting, you would have 20 dollars left. If you have 0 dollars left, this means your mom spent all of the remaining 20 dollars on wine. Assuming each wine bottle costs the same, we can divide the remaining 20 dollars by the cost of one wine bottle to find how many wine bottles your mom bought for her weekly wine tasting. Without knowing the exact cost of one wine bottle, we can't determine the exact number of wine bottles your mom drank.

In order for a number to be divisible by 12, it must be divisible by both 3 and 4.
To be divisible by 3, the sum of the digits must be divisible by 3.
7 + 7 + 3 + 1 + 8 + 6 + 2 + d + e = 34 + d + e

Since 34 is not divisible by 3, we need d + e to be a multiple of 3 in order for the sum to be divisible by 3.
Possible values for d + e are 3, 6, and 9.

To be divisible by 4, the last two digits of the number must be divisible by 4.
Therefore, we need de to be a multiple of 4.

Possible values for de are 12, 16, 32, 36, 52, 56, 72, 76, and 92.
Out of these, only 12, 36, 52, and 76 have a sum of digits that is a multiple of 3.

So the possible values for de are 12, 36, 52, and 76.
Therefore, the choices of the two-digit numbers de for which n is divisible by 12 are 12, 36, 52, and 76.

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