PLZ HELP IM STUPID. A teacher surveyed her class to find out how many texts the students send in a week. She created this box plot to show the data. Find the interquartile range. 50 points!
Answers
Answer:
236
Step-by-step explanation:
The interquartile range is the right edge of the box minus the left edge of the box
The right edge of the box is 301
The left edge of the box is 65
301 -65 =236
The interquartile range is 236
Answer:
65
Step-by-step explanation:
To find interquartile range, you substract upper quartile( 130 in this problem) and the lower quartile(65 in this problem)
Finally, you get the answer 65.
Hope this helps!
Related Questions
 A central angle is best described as which of the following?
A.
It has a measure greater than 180 degrees.
B.
It is an angle that has its vertex on the circle.
C.
It is an angle that has its vertex at the center of a circle.
D.
It is part of the circumference of a circle.
Answers
Answer:
Answer C: It is an angle that has its vertex at the center of a circle.
Step-by-step explanation:
By definition of central angle, it is an angle whose vertex is at the geometric center of a circle.
Answer:
C.
It is an angle that has its vertex at the center of a circle.
A hot metal bar is submerged in a large reservoir of water whose temperature is 60°F. The temperature of the bar 20 s after submersion is 120°F. After 1 min submerged, the temperature has cooled to 100°F. A) Determine the cooling constant k.B) What is the differential equation satisfied by the temperature F(t) of the bar?C) What is the formula for F(t)?D) Determine the temperature of the bar at the moment it is submerged.
Answers
Answer:
A) cooling constant = 0.0101365
B) [tex]\frac{df}{dt} = k ( 60 - F )[/tex]
c) F(t) = 60 + 77.46[tex]e^{0.0101365t}[/tex]
D)137.46 ⁰
Step-by-step explanation:
water temperature = 60⁰F
temperature of Bar after 20 seconds = 120⁰F
temperature of Bar after 60 seconds = 100⁰F
A) Determine the cooling constant K
The newton's law of cooling is given as
= [tex]\frac{df}{dt} = k(60 - F)[/tex]
= ∫ [tex]\frac{df}{dt}[/tex] = ∫ k(60 - F)
= ∫ [tex]\frac{df}{60 - F}[/tex] = ∫ kdt
= In (60 -F) = -kt - c
60 - F = [tex]e^{-kt-c}[/tex]
60 - F = [tex]C_{1} e^{-kt}[/tex] ( note : [tex]e^{-c}[/tex] is a constant )
after 20 seconds
[tex]C_{1}e^{-k(20)}[/tex] = 60 - 120 = -60
therefore [tex]C_{1} = \frac{-60}{e^{-20k} }[/tex] ------- equation 1
after 60 seconds
[tex]C_{1} e^{-k(60)}[/tex] = 60 - 100 = - 40
therefore [tex]C_{1} = \frac{-40}{e^{-60k} }[/tex] -------- equation 2
solve equation 1 and equation 2 simultaneously
= [tex]\frac{-60}{e^{-20k} }[/tex] = [tex]\frac{-40}{e^{-60k} }[/tex]
= 6[tex]e^{20k}[/tex] = 4[tex]e^{60k}[/tex]
= [tex]\frac{6}{4} e^{40k}[/tex] = In(6/4) = 40k
cooling constant (k) = In(6/4) / 40 = 0.40546 / 40 = 0.0101365
B) what is the differential equation satisfied
substituting the value of k into the newtons law of cooling)
60 - F = [tex]C_{1} e^{0.0101365(t)}[/tex]
F(t) = 60 - [tex]C_{1} e^{0.0101365(t)}[/tex]
The differential equation that the temperature F(t) of the bar
[tex]\frac{df}{dt} = k ( 60 - F )[/tex]
C) The formula for F(t)
t = 20 , F = 120
F(t ) = 60 - [tex]C_{1} e^{0.0101365(t)}[/tex]
120 = 60 - [tex]C_{1} e^{0.0101365(t)}[/tex]
[tex]C_{1} e^{0.0101365(20)}[/tex] = 60
[tex]C_{1} = 60 * 1.291[/tex] = 77.46
C1 = - 77.46⁰ as the temperature is decreasing
The formula for f(t)
= F(t) = 60 + 77.46[tex]e^{0.0101365t}[/tex]
D) Temperature of the bar at the moment it is submerged
F(0) = 60 + 77.46[tex]e^{0.01013659(0)}[/tex]
F(0) = 60 + 77.46(1)
= 137.46⁰
Matt has $3 left in his pocket. He spent $6
on lunch, $7 on a poster, and $10 on a
T-shirt. How much money did he have at
the beginning of the day?
Answers
Answer:
$26.
Step-by-step explanation:
Let's say that Matt started out with x dollars.
x - 6 - 7 - 10 = 3
x - 13 - 10 = 3
x -23 = 3
x = 26
He had $26 at the beginning of the day.
Hope this helps!
Please help. I’ll mark you as brainliest if correct!
Answers
Answer:
Step-by-step explanation:
children=c
adults=a
c+a=359
a=359-c
2.75c+6a=1621
2.75 c+6(359-c)=1621
2.75 c+2154-6c=1621
-3.25 c=1621-2154
-3.25 c=-533
[tex]-\frac{325}{100} c=-533\\-\frac{13}{4} c=-533\\c=-533 \times \frac{-4}{13} =41 \times 4=164 \\children=164\\adults=359-164=195[/tex]
Consider the density curve plotted below:
Find PX < 6.4):
Find P(X> 4.8):
Answers
Answer:
[tex] P(X<6.4)= \frac{6.4*0.2}{2}= 0.64[/tex]
[tex] P(X>4.8) =1-P(X<4.8)= 1- \frac{4.8*0.15}{2}= 1-0.36= 0.64[/tex]
Step-by-step explanation:
Part a
We want to find:
[tex] P(X<6.4)[/tex]
And we just need to find the area below the curve until x=6.4, since we have a triangle we can do this:
[tex] P(X<6.4)= \frac{6.4*0.2}{2}= 0.64[/tex]
Part b
For this case we want to find this probability:
[tex] P(X>4.8)[/tex]
And we can use the complement rule and we got:
[tex] P(X>4.8) =1-P(X<4.8)= 1- \frac{4.8*0.15}{2}= 1-0.36= 0.64[/tex]
1. What is an inequality? Give one example of an inequality? How would you graph this? 2. What is a compound inequality? Give an example of "and" and an "or" inequality. 3. Identify the independent and dependent variables in the following situation: The more hours Beth studies, the higher the GPA she has.
Answers
Answer: see below
Step-by-step explanation:
1) An inequality is an equation that uses >, ≥, <, or ≤ instead of an equal sign.
Example: 3x + 2 ≥ 10
2) A compound inequality is when 2 inequalities are combined using either "and" or "or".
And → means it must satisfy both inequalitiesOr → means it must satisfy at least one of the inequalitiesExample: x > -2 and x < 4 rewrite as: -2 < x < 4
Graph: -2 o-----------------o 4 one line segment between the #'s
Example: x < -2 or x > 4
Graph: ←-----------o -2 4 o----------→ two lines in opposite directions
3) The GPA is dependent on the number of hours she studies.
Independent: hours Beth studies
Dependent: GPA
Which of the following equations is equivalent to 4/5a - 8 = 1/5?
Answers
Answer:
a = 10 1/4
Step-by-step explanation:
So with the following equation,
4/5a - 8 = 1/5,
we need to use the commutative property.
Which is the moving of whole numbers or variables.
So we add 8 to both sides.
4/5a = 41/5
Divide 4/5 by both sides
a = 10 1/4
So on of the equations could look like a = 10 1/4
Thus,
a = 10 1/4 could be one of the equations given which are equal to 4/5a - 8 = 1/5.
Hope this helps :)
Answer:
[tex]\huge\boxed{a=\dfrac{41}{4}=10\dfrac{1}{4}=10.25}[/tex]
Step-by-step explanation:
[tex]\dfrac{4}{5}a-8=\dfrac{1}{5}\qquad\text{multiply both sides by 5}\\\\5\!\!\!\!\diagup\cdot\dfrac{4}{5\!\!\!\!\diagup}a-(5)(8)=5\!\!\!\!\diagup\cdot\dfrac{1}{5\!\!\!\!\diagup}\\\\4a-40=1\qquad\text{add 40 to both sides}\\\\4a-40+40=1+40\\\\4a=41\qquad\text{divide both sides by 4}\\\\\dfrac{4a}{4}=\dfrac{41}{4}\\\\a=10.25[/tex]
A New York taxi service charges a $3.25 boarding rate in addition to its meter which is $2 for every mile. How much does it cost to ride in this cab for 1 mile? How much does it cost to ride in this cab for 20 miles?
Answers
Answer:
Hey there!
This can be modelled by an equation, y=2x+3.25
For one mile: y=2(1)+3.25, or y=5.25
For twenty miles: y=2(20)+3.25, or y=43.25
Hope this helps :)
During a camping trip, a group went one -third of the total distance by boat, 10km by foot and One – sixth of it by riding horses. Find the total distance of the trip.
Answers
Explanation:
Let d be the total distance
d = (1/3)d + 10 + (1/6)d
(6/6)d = (2/6)d + 60/6 + (1/6)d
6d = 2d + 60 + d
6d = 3d + 60
3d = 60
d = 60/3 = 20
subtract these polynomials (x^2+5x+2)- (5x^2-x-2)
Answers
Step-by-step explanation:
Here,
the given polynomials are;
(x^2+5x+2)-(5x^2-x-2)
now, when we open bracket of second polynomial we get,
=x^2+5x+2-5x^2+x+2
combining like terms and simplifying them we get;
=x^2-5x^2+5x+x+2+2
=-3x^2+6x+4.
Therefore, the answer is-3x^2+6x+4 or, taking - (minus) commo it will be -(3x2-6x-4).
Hope it helps....
Someone help me please
Answers
Answer:
3
Step-by-step explanation:
If the cube has 54 stickers across its six faces, and each face has the same number of stickers, first we can find the number of stickers in each face by dividing the number of stickers by the number of faces:
[tex]stickers\ per\ face = number\ of\ stickers / number\ of\ faces[/tex]
[tex]stickers\ per\ face = 54/6 = 9[/tex]
Each face has 9 stickers.
If each row and column has the same number of stickers, we can find the numbers of rows and columns by finding the square root of the number of stickers in the face:
[tex]\ number\ of\ rows = \sqrt{9} = 3[/tex]
If we have 3 rows, and each roll has the same number of stickers, the number of stickers per row or column is:
[tex]stickers\ per\ row = stickers\ per\ face / number\ of\ rows[/tex]
[tex]stickers\ per\ row = 9/3 = 3[/tex]
If sinθ = 12/13 and θ is an acute angle, find cotθ.
Answers
Answer:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
Step-by-step explanation:
We are given that:
[tex]\displaystyle \sin \theta = \frac{12}{13}[/tex]
Where θ is an acute angle, and we want to find cot(θ).
Recall that sine is the ratio of the opposite side over the hypotenuse. In other words, our opposite side is measures 12 units and our hypotenuse measures 13 units.
Find the adjacent side:
[tex]\displaystyle \begin{aligned} a^2 + b^2 & = c^2 \\ \\ (12)^2 + b^2 & = (13)^2 \\ \\ b & = 5\end{aligned}[/tex]
Hence, our adjacent side is 5, our opposite side is 12, and our hypotenuse is 13.
Recall that cotangent is the ratio of the adjacent side to the opposite side. Therefore:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
In conclusion:
[tex]\displaystyle \cot \theta = \frac{5}{12}[/tex]
Answer:
-5/12
Step-by-step explanation:
I just completed Quiz 2: Evaluation of Functions. Of which, this was one of the questions.
a guy wire makes a 67 degree angle with the ground. walking out 32 ft further grom the tower,the angle of elevation to the top of the tower is 39 degrees. find the height of the tower
Answers
Answer:
39.5 ft
Step-by-step explanation:
The mnemonic SOH CAH TOA reminds you of the relation between angles and sides of a right triangle.
Tan = Opposite/Adjacent
This lets us write two equations in two unknowns:
tan(67°) = AD/CD . . . . . . . . . . angle at guy point
tan(39°) = AD/(CD+32) . . . . . .angle 32' farther
__
Solving the first equation for CD and using that in the second equation, we can get an equation for AD, the height of the tower.
CD = AD/tan(67°)
tan(39°)(CD +32) = AD . . . . eliminate fractions in the second equation
tan(39°)(AD/tan(67°) +32) = AD
32·tan(39°) = AD(1 -tan(39°)/tan(67°)) . . . simplify, subtract left-side AD term
32·tan(39°)tan(67°)/(tan(67°) -tan(39°)) = AD . . . . divide by AD coefficient
AD ≈ 39.486 . . . . feet
The tower is about 39.5 feet high.
Amina sold 1/3 of her goats to a butcher and gave 1/6 of the remaining goats to her children. If she was left with 90 goats how many goats had she at the beginning?
Answers
Answer:
180 goats
Step-by-step explanation:
3/3-1/3=2/3.
2/3=4/6 remaining.
4/6-1/6=3/6 which also equals 1/2.
If 90=1/2 then 90*2=180.
Hope this helps!! <3
find the coordinate of W' after a 90° rotation of the triangle about the origin and then a reflection about the line y= -3
Answers
Answer:
(4, -8).
Step-by-step explanation:
If point W were to be rotated 90 degrees, it would rotate 90 degrees clockwise. The current point of W is (-2, 4). After a 90 degree rotation about the origin, the point will be (4, 2).
y = -3 is a horizontal line where y = -3. The y-value of the newly rotated point is 2. That is five units above the line where y = -3. So, a reflection would result in a y-value of y = -3 - 5 = -8. The x-value does not change.
So, the coordinate of W' is (4, -8).
Hope this helps!
8. Let X be the number of cars per minute passing a certain point of some road between 8am and 10am on a Sunday. Assume that X has a Poisson distribution with mean 5. Find the probability of observing 3 or fewer cars during any given minute.
Answers
Answer:
P (3 or fewer) =0.2650
Step-by-step explanation:
Mean = x` = 5
The Poisson distribution formula is given by
P(X) = e-ˣ` x`ˣ/ x!
The mean is 5 and the X takes the values 0,1,2,and 3 which means 3 or fewer, so we add the probability of all the values of X to get the desired Value of X.
P(3 or fewer ) = e-⁵ (5)³/3!+ e-⁵ (5)²/2! +e-⁵ (5)/1!+e-⁵ (5)⁰/0!
Putting the Values
P (3 or fewer) = 0.006737 . 125 / 6 + 0.006737 . 25 / 2 +0.006737 . 5 / 1 + 0.006737 . 1 / 1
P (3 or fewer) = 0.140374 + 0.08422+ 0.03369 +0.006737
P (3 or fewer) =0.2650
What is the first stepin solving the quadratic equations x2-40=0
Answers
Answer:
+40 to both sides of the = sign.
Step-by-step explanation:
x2-40=0
+40=+40
x2=40
/2=/2
x=20
Write an equation perpendicular to 5x+6y=18 that passes through the point (10,7)
Answers
Answer:
Step-by-step explanation:
6y = -5x + 18
y = -5/6x + 3
perp slope: 6/5
y - 7 = 6/5(x - 10)
y - 7 = 6/5x - 12
y = 6/5x - 5
Here, we are required to write an equation perpendicular to 5x + 6y = 18.
The equation perpendicular to 5x+6y=18 that passes through the point (10,7) is;6x - 5y = 25.
By rearranging 5x+6y=18 to resemble the end of a straight line; y = Mx + c; we have;y = (-5/6)x +3Therefore, slope of equation 5x + 6y = 18 is -5/6.
However, the product of the slopes of 2 perpendicular lines is -1.Therefore, m1m2 = -1
Therefore, the slope of the required line, m2 is;
m2 = -1/(-5/6)m2 = 6/5
Therefore, the equation of a line perpendicular to the equation 5x+6y=18 and passes through the point (10,7) is given as;
6/5 = (y - 7)/(x - 10).
By cross product; we have;
6x - 60 = 5y - 35
6x - 5y = 25.
Read more:
https://brainly.com/question/17619748
Find the value of x.
Answers
Answer:
[tex]\huge\boxed{y=\sqrt{55}}[/tex]
Step-by-step explanation:
ΔADC and ΔDBC are similar (AAA)
Therefore the cooresponging sides are in proportion:
[tex]\dfrac{AC}{CD}=\dfrac{CD}{BC}[/tex]
Substitute:
[tex]AC=6+5=11\\BC=5\\CD=y[/tex]
[tex]\dfrac{11}{y}=\dfrac{y}{5}[/tex] cross multiply
[tex](11)(5)=(y)(y)\\\\55=y^2\to y=\sqrt{55}[/tex]
One number is 2 more than another. The difference between their squares is 52. What are the numbers?
Answers
Answer:
The aprox, numbers:
4.1633 and 8.3266
Step-by-step explanation:
a = 2b
a² - b² = 52
then:
(2b)² - b² = 52
4b² - b² = 52
3b² = 52
b² = 52/3
b² = 17.333
√b² = √17.333
b = 4.1633 aprox.
a = 2b
a = 2*4.1633
a = 8.3266
Check:
8.3266² - 4.1633² = 52
69.333 - 17.333 = 52
Let x represent the number of times a student visits a gym in a one month period. Assume that the probability distribution of X is as follows: x 0 1 2 3 p(x) 0.17 0.33 0.32 0.18 Determine the probability the student visits the gym at most twice in a month. Report your answer to two decimal places.
Answers
Answer: Probability of visiting at most twice = 0.82
Step-by-step explanation: The probability distribution is of the form:
X 0 1 2 3
P(X) 0.17 0.33 0.32 0.18
It wants the probability of visiting the gym at most twice in a month, which means the probability of never going to the gym, P(X=0), or going once, P(X=1), or going twice, P(X=2).
Using the "OR" probability:
P(visiting at most twice) = P(X=0) + P(X=1) + P(X=2)
P(visiting at most twice) = 0.17 + 0.33 + 0.32
P(visiting at most twice) = 0.82
Therefore, the probability of visiting the gym at most twice in a month is 0.82 or 82%
The perimeter of a rectangular field is 344m . If the width of the field is 75m, what is its length?
Answers
Answer:
97 m
Step-by-step explanation:
Perimeter = 2 * (length + width); perimeter = 344, width = 75 (solving for length)
344 = 2(length + 75)
172 = length + 75
length = 97
rewrite (21+31).4 using the disbributive property of multiplication over addition
Answers
Answer: evaluate it is 52
Step-by-step explanation:
Which right circular cylinder has the greater volume?
r = 2
h = 4
r= 1
h = 8
O A) The red cylinder.
OB) The blue cylinder.
OC) They have the same volume
OD) There is not enough information to tell.
Answers
Answer:
r = 2
h = 4
vol for r = 2 and h = 4 has the greater volume
Step-by-step explanation:
vol for r = 2, h = 4
= pi * r ² * h
= 50
vol for r = 1, h= 8
= pi * r ² * h
= 25
therefore : vol for r = 2 and h = 4 has the greater volume
I need help!!! If none Of these are correct say none.
Answers
side angle side
explanation
because in two similar triangles the SAS congruence rule be obeyed
cual es la derivada de ()=√x sin
Answers
Answer:
[tex] f(x) =\sqrt{x} sin (x)[/tex]
And on this case we can use the product rule for a derivate given by:
[tex] \frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)[/tex]
Where [tex] f(x) =\sqrt{x}[/tex] and [tex] g(x) =sin (x)[/tex]
And replacing we have this:
[tex] f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)[/tex]
Step-by-step explanation:
We assume that the function of interest is:
[tex] f(x) =\sqrt{x} sin (x)[/tex]
And on this case we can use the product rule for a derivate given by:
[tex] \frac{d}{dx} (f(x)* g(x)) = f'(x) g(x) +f(x) g'(x)[/tex]
Where [tex] f(x) =\sqrt{x}[/tex] and [tex] g(x) =sin (x)[/tex]
And replacing we have this:
[tex] f'(x)= \frac{1}{2\sqrt{x}} sin (x) + \sqrt{x}cos(x)[/tex]
A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
Answers
Answer:A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
A cylinder fits inside a square prism as shown. For every cross section, the ratio of the area of the circle to the area of the square is or . Since the area of the circle is the area of the square, the volume of the cylinder equals the volume of the prism or (2r)(h) or πrh. the volume of the prism or (4r2)(h) or 2πrh. the volume of the prism or (2r)(h) or r2h. the volume of the prism or (4r2)(h) or r2h.
Step-by-step explanation:
The cylinder is given by A = pi/4 the volume of the prism or π/4 x (4r²h) or π x r² x h
What is a Cylinder?A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface. The center of the circular bases overlaps each other to form a right cylinder. The volume of a cylinder is
Volume of Cylinder = πr²h
Surface area of cylinder = 2πr ( r + h )
where r is the radius of the cylinder
h is the height of the cylinder
Given data ,
Area circle is A = πr²
Area square with side s = s²
The side of the square is equal to the diameter of the circle
Area square = D²
A diameter of square is always twice the radius
Area square = (2r)² = 2²r² = 4r²
So , on simplifying , we get
Area circle/Area square = (πr²)/(4r²)
Area circle/Area square = π/4
Now , The volume Prism = Area Square x h
Volume Prism = 4r²h
Volume of Cylinder= Area Circle x h
Volume of Cylinder = π x r² x h
So , Volume Cylinder/Volume Prism = π x r² x h/4r² x h
Volume of Cylinder/Volume of Prism = π/4
Volume of Cylinder = π/4 x Volume Prism
And , The volume of Cylinder = π/4 x (4r²h)
Hence , the volume of cylinder is V = π/4 x (4r²h)
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what is the answer to 100×338
Answers
Answer:
33800
Step-by-step explanation:
100 x 338 = 33800
Answer:
33800
Step-by-step explanation:
338x10=3380 then 3380x10=33800
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Good luck with your assignment...
Identify the type I error and the type II error that corresponds to the given hypothesis. The proportion of people who write with their left hand is equal to 0.22.
Which of the following is a type I error?
A. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
B. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually different from 0.29
C. Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
D. Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29
Answers
Answer:
Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.
Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.
Step-by-step explanation:
We are given the following hypothesis below;
Let p = proportion of people who write with their left hand
So, Null Hypothesis, [tex]H_0[/tex] : p = 0.22 {means that the proportion of people who write with their left hand is equal to 0.22}
Alternate Hypothesis, [tex]H_A[/tex] : p [tex]\neq[/tex] 0.22 {means that the proportion of people who write with their left hand is different from 0.22}
Now, Type I error states that we conclude that the null hypothesis is rejected when in fact the null hypothesis was actually true. Or in other words, it is the probability of rejecting a true hypothesis.
So, in our question; Type I error is to Reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is actually 0.29.
Type II error states that we conclude that the null hypothesis is accepted when in fact the null hypothesis was actually false. Or in other words, it is the probability of accepting a false hypothesis.
So, in our question; Type II error is Fail to reject the claim that the proportion of people who write with their left hand is 0.29 when the proportion is different from 0.29.
box with a a square base and open top must have a volume of 62,500 cm3. Find the dimensions of the box that minimize the amount of material used. sides of base
Answers
Answer:
The dimensions of the box that minimize the amount of material used is 39.69 cmStep-by-step explanation:
This problem is on the mensuration of solids, a box
we know that the volume of a box is give by the expression
[tex]Volume= L^3[/tex]
now to find the dimension of the box, we need to find L
Given data
volume = [tex]62,500 cm^3[/tex].
[tex]62,500 cm^3= L^3\\L=\sqrt[3]{62500} \\\L=39.69 cm[/tex]
Answer:
The dimensions of box that will minimize the amount of material used is [tex]39.69cm[/tex]
Step-by-step explanation:
Given information
Volume [tex]V=62500cm^3[/tex]
As given in question the box is of square shape:
So the volume will be
[tex]V=L^3[/tex]
where, L is the side of the square
[tex]V=L^3=62500\\L=\sqrt[3]{62500} \\L=39.69 cm\\[/tex]
Hence, The dimensions of box that will minimize the amount of material used is [tex]39.69cm[/tex].
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