Pls I need help urgently. Find the Lewis dot structure for water and ethanol and examine the structures and identify which part is partial negative and partial positive.

Explanation:

Refer to pic..........

The number of the moles of hydrogen must be removed from the vessel to increase the concentration of nitrogen to 1. 1 M is 0.334 mol.

The chemical equation is as follows :

                 N₂ (g)      +  3H₂ (g)  ⇄   2NH₃ (g)

Initial        1.00 M   0.50 M     0.25 M

Change   + 0.1                        -0.1 M

Eq.             1.1 M        x               0.05 M

The equilibrium concentration is as :

Kc = [NH₃]² / [  N₂ ] [H₂]³

Kc = (0.25)² / (1) (0.50)³

of Kc = 0.50

Kc = [NH₃]² / [  N₂ ] [H₂]³

0.50 = (0.05)² / (1.1) (x)³

x = 0.166 M

The number of the moles of the hydrogen removed = 0.50 - 0.166

The number of the moles of the hydrogen removed = 0.334 mol of H₂.                        

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C2H4 is the limiting chemical because the ratio of C2H4 to O2 is below the stoichiometric ratio.and the reaction's percent yield is 40.7%.

The limiting reagent or reactant in a chemical process is the one that controls how much product is created. Because elements and compounds respond in an equilibrium chemical formula according to their mole ratios, a limiting reactant is necessary.

C2H4 + O2 CO2 + H2O can be used to calculate the limiting reagent and percent output.

C2H4 has a mass of 170.9 g.

O2 has an overall volume of 52.75 L.

The amount of CO2 generated is 64.1 g.

Calculating the amounts (in moles) of each reactant and comparing them to the stoichiometric ratio in the balanced solution will help us identify the limiting reagent.

The molecular mass of C2H4 can be used to determine how much is present:

17.9 g C2H4 divided by (2 x 12.01 g/mol + 4 x 1.01 g/mol) results in 3.58 mol C2H4.

The ideal law of gases can be used to determine the quantity of O2:

PV/RT equals (1 atm)(52.75 L)/(0.0821 L atm/mol K)(298 K) = 2.16 mol O2 for n(O2).

Then, C2H4:O2 = 3.58 mol; 2.16 mol; 1.66 mol; 1

C2H4 to O2 stoichiometric ratio is 1 to 3.

C2H4 is the limiting reactant because the ratio of C2H4 to O2 is lower than the stoichiometric ratio. This implies that the O2 will exhaust itself completely before the C2H4 does as well.

We can use the mole fraction of C2H4 to CO2 in the balanced equation to calculate the potential yield of CO2:

1 mol C2H4 results in 1 mol CO2.

Theoretically, 3.58 mol C2H4 1 mol CO2/1 mol C2H4 44.01 g/mol = 157.3 g CO2 is the output of CO2.

To determine the percent yield, multiply the result by 100% after dividing the real yield by the theoretical yield:

(Actual yield / Theoretical yield) / 100% = Percent return

The amount of CO2 that actually occurred is 64.1 g. The percent yield is therefore: Percent yield = (64.1 g/157.3 g) 100% = 40.7%

As a result, C2H4 serves as the limiting reactant, and the reaction's percent yield is 40.7%.

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Consequently, 4.50 milligrams of KCl yields 216 g of O2 from 4 moles of KClO3, which in turn produces 6 mole of O2. Potassium chloride is created in amounts of 0.0408 mol KCl.

A suspicious mole, on the other hand, is asymmetrical, that means that when it is split in half, its two sides have a different appearance. The typical characteristic of benign moles is circular borders. Wavy borders are frequently seen on moles that have malignancy. If the border isn't smooth, get your belongings out of there.

2 mol KClO3 / 3 mol O2, which equals 4 mol KClO3 / x.

The answer to the equation for x is: x = (3 mol O2 4 mol KClO3) / 2 mmol KClO3 = 6 mol O2.

As a result, 4 moles ions KClO3 result in 6 moles of O2.

2.50 mol KClO3 / 2.50 mol KCl = 2.50 mol KClO3 / x

The  to the equation for x is: x = (2 mol KCl 4.50 mol KClO3) / 2 mol KClO3 = 4.50 mol KCl.

We can calculate the amount of O2 produced using the mole fraction of KClO3 to O2 now that we know humans have 4.50 mole of KCl:

2.50 mol KClO3/3.0 mol O2 ≈ 4.50 mol KClO3/x

In order to find x, we must divide 3 mol O2 by 4.50 mol KClO3 and 2 mol KClO3 by 6.75 mol O2.

In order to translate from moles to grams, we can utilize the molecular concentration of oxygen:

216 g O2 is produced by multiplying 6.75 mol O2 by 32.00 g/mol.

Hence, 216 g of O2 are created from 4.50 moles of KCl.

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The mass of NaCl is 58.5 g

The mole is a fundamental unit of measurement used in chemistry to express the amount of a substance. One mole of a substance is defined as the amount of that substance that contains the same number of entities, such as atoms, molecules, or ions, as there are in 12 grams of carbon-12. This number is known as Avogadro's number and is approximately 6.02 x 10^23.

Number of moles of NaOH = 40 g/40 g/mol = 1 mole

Since the reaction is 1:1

Mass of NaCl formed = 1 moles * 58.5 g/mol = 58.5 g

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Answer:

First, we need to calculate the molarity of the solution:

Molarity = moles of solute / liters of solution

We know the mass of solute (5.00 g) and the volume of solution (20.0 mL = 0.0200 L). To find the moles of solute, we need to divide the mass by the molar mass of NaCl:

moles of NaCl = 5.00 g / 58.44 g/mol = 0.0855 mol

Now we can calculate the molarity:

Molarity = 0.0855 mol / 0.0200 L = 4.28 M

The molarity of the solution is less than the molarity of a saturated NaCl solution at room temperature (5.98 M), so the solution is unsaturated.

Answer:

I'm pretty sure its A

Explanation:

I hope this helps

C. It must have a full or partial charge.

When a particle dissolves in water, it becomes surrounded by water molecules. The polarity of water molecules allows them to interact with other polar molecules, including ions or molecules that have a full or partial charge.

These interactions between the charged particle and water molecules help to break apart the intermolecular forces holding the particle together and allow it to dissolve in water.

Particles that lack a full or partial charge, such as those with nonpolar covalent bonds or areas of neutral charge, typically do not dissolve well in water.

These types of particles do not have a strong attraction to the polar water molecules and do not experience the same breaking of intermolecular forces that charged particles do.

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The type of energy being transferred to the pot to make the water boil is heat energy. The heat energy is transferred from the stove to the pot, which then transfers the heat energy to the water molecules.

Simply said, sound energy is a result of vibrations passing through a substance. Sound waves can travel through solids, liquids, and gases. When a force, such as sound or pressure, causes an item or substance to vibrate, the result is sound energy. Waves of that energy pass through the substance. We refer to the sound waves as kinetic mechanical energy.

The wind chime's rich, bright tones or its high, delicate tingling Traffic noises include the rumbling of engines, screeching tyres, loud radios, and squeaking brakes. infants' cries and babbling. As the water molecules absorb the heat energy, they begin to move faster and eventually reach a point where they turn into vapor, causing the water to boil.

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Answer: Highly Inflammable. Natural gas is a highly flammable substance that can cause significantly more damage should there be an accident. ...

Greenhouse Gas Emissions. ...

Non-Renewable. ...

Not Easy to Use. ...

Expensive Pipelines.

Explanation:

the percent by mass of cashews and almonds can be determined by the Percentage by mass of X = (mass of X / total mass of mixed nuts) x 100%

A possible plan to determine the percentage by mass of cashews and almonds in a jar of mixed nuts could be:

Obtain a sample of the mixed nuts and weigh it to determine the total mass of the sample.

Separate the cashews and almonds from the rest of the nuts in the sample.

Weigh the separated cashews and record the mass.

Weigh the separated almonds and record the mass.

Calculate the percentage by mass of cashews and almonds in the mixed nuts by using the following formulas:

Percentage by mass of cashews = (mass of cashews / total mass of mixed nuts) x 100%

Percentage by mass of almonds = (mass of almonds / total mass of mixed nuts) x 100%

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Indeed, 2N + 2H results from n2 + 3H2.An oxidation reaction is a process that involves chemical addition of oxygen, and a reduction reaction is a process that involves a removal of oxygen.

Redox reactions are those in which there is a change in the oxidation number, with both a gain and a drop in number.The reaction called non-redox if this fails to take place.

You must figure out each atom's oxidation values prior to and following the reaction in order to identify what happens toward which elements inside a redox reaction.The prospective charge of the an atom in its cationic state is represented by oxidation numbers.In a reaction, an atom is reduced if its oxidation number falls.

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The compounds that would form precipitates are; CuCO3 and Ca(OH)2 and  ZnS

Some compounds form precipitates in aqueous solutions because their solubility decreases as the temperature or concentration of the solution changes. When the solubility limit of the compound is reached, the excess solid particles will no longer dissolve and will start to form a solid precipitate.

Precipitation reactions can be useful in analytical chemistry for detecting and identifying ions in solution. They can also be used in industrial processes, such as the purification of metals and the removal of impurities from wastewater.

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If 6. 5 moles of nitrogen gas react with 17. 8 moles of hydrogen gas, mass of ammonia that would be produced is 34g.

In the reaction N2 + 3H2 → 2NH3, 6.5 moles of nitrogen gas and 17.8 moles of hydrogen gas will react to produce 2 moles of ammonia. To calculate the mass of ammonia produced, we can use the formula:

Mass = moles x molar mass

So, in this case, the mass of ammonia produced would be:

Mass = 2 moles x 17 g/mol = 34 g

The mass of one mole of a material, given in grams per mole (g/mol), is known as molar mass. It is computed by multiplying the atomic masses of all the atoms in a molecule or formula unit.

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The pH of a solution that has a [OH-] = 5.8 x 10⁻⁹ is 5.76.

What is pH?

A pH scale is a tool for measuring acids and bases. The scale ranges from 0-14. Range of 0-6 represents acids and range of 8-14 represents bases. The value of pH 7 represents neutral solution.

pH = -log [H+]

Also, pH = 14 - pOH

Given,

[OH-] = 5.8 x 10⁻⁹

pOH = -log [OH-]

pOH = 9 - 0.763 = 8.23

Hence, pH = 14 - 8.23 = 5.76

Therefore, the pH of a solution that has a [OH-] = 5.8 x 10⁻⁹ is 5.76.

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The statement "Positive ∆H means that the reaction tends to go forwards. Negative ∆H means that the reaction tends to go in reverse" is generally true.

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The number of moles in 20g of Ne is 1 mole.

The mole is an amount unit similar to familiar units like pair, dozen, gross, etc. It provides a specific measure of the number of atoms or molecules in a bulk sample of matter.

A mole is defined as the amount of substance containing the same number of atoms, molecules, ions, etc. as the number of atoms in a sample of pure 12C weighing exactly 12 g.

Given,

Mass of Ne = 20g

Molar mass of Ne = 20 g/mole

Moles = mass ÷ molar mass

              = 20 ÷ 20

               = 1 mole

Therefore, the number of moles in 20g of Ne is 1 mole.

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The question has spelling mistake. Probably the question is:

Calculate the number of moles in 20g of neon.

The electron that has returned to ground state is 5.

In the case of an atom, the ground state refers to the lowest possible energy level that an electron can occupy. This is the energy level closest to the nucleus and is often referred to as the "1s" orbital.

Electrons can occupy higher energy levels by absorbing energy and moving to an excited state, but they will naturally return to the ground state by releasing the excess energy in the form of electromagnetic radiation, such as light.

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Answer:

To determine the formula mass of the gas, we can use the ideal gas law:

PV = nRT

where P is the pressure of the gas, V is the volume of the container, n is the number of moles of gas, R is the ideal gas constant, and T is the temperature of the gas in Kelvin.

First, we need to convert the given temperature of 27°C to Kelvin:

T = 27°C + 273.15 = 300.15 K

Next, we can rearrange the ideal gas law to solve for the number of moles of gas:

n = PV/RT

where P = 300.0 kPa, V = 25.0 L, R = 8.31 J/(mol·K), and T = 300.15 K.

n = (300.0 kPa)(25.0 L)/(8.31 J/(mol·K) x 300.15 K) ≈ 30.12 mol

Now, we can calculate the molar mass (formula mass) of the gas using its mass and the number of moles:

molar mass = mass / number of moles

where the mass is given as 96.0 g.

molar mass = 96.0 g / 30.12 mol ≈ 3.19 g/mol

Therefore, the formula mass of the gas is approximately 3.19 g/mol.

Explanation:

Answer:

3.19

Explanation:

Answer:

I think it is Al2O3

Answer:

735,000

Explanation:

75 × 9.8

Answer:

you can use the formula for heat capacity to calculate the change in temperature:

Q = m * c * ΔT

where Q is the heat added, m is the mass of the substance, c is the specific heat capacity of the substance, and ΔT is the change in temperature.

Plugging in the values given, we get:

10 J = 0.002 kg * 0.129 J/(g·°C) * ΔT

Simplifying and solving for ΔT, we get:

ΔT = 10 J / (0.002 kg * 0.129 J/(g·°C))

ΔT = 308.53 °C

Therefore, the temperature of the gold increases by approximately 308.53 °C when 10 J of heat is added to 2 g of gold.

Answer: " I have one mole of baseballs "

Explanation:

In the following ions, the one which is soluble in water when paired with Ca²+, according to the solubility rules chart is Cl-.

What is solubility rules chart?

Solubility is applicable to many laboratory processes and is also important in medicine. Some ions can be toxic when they separate in a solution but are helpful as part of a compound.

Solubility rules chart is a chart that helps us to find which anion is soluble in water with which cation.

Given is the Ca²⁺ cation and according to the solubility rules chart, Chloride (Cl⁻) - soluble in water

Hydroxide (OH⁻) - very slightly soluble

Carbonate (CO3²⁻) - insoluble

Sulfate (SO4²⁻) - very slightly soluble

Therefore, in the following ions, the one which is soluble in water when paired with Ca²+, according to the solubility rules chart is Cl-.

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Answer:

Chloride (Cl-)

Explanation:

They are all formed from ancient organic material that was buried under many layers of sediment and not allowed to decay.

What are organic materials?

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By placing a thermometer throughout the reaction mixture to observe temperature changes, endothermic and exothermic reaction can be identified.

Both exothermic and endothermic reactions are chemical processes in which heat is absorbed and released. Photosynthesis is a nice example of such an endothermic process. An example of just an exothermic process is combustion.

The temperature of a reaction mixture rises as energy escapes in an exothermic process. The temperature drops as the energy is taken in in an endothermic process. Place a thermometer throughout the reaction mixture to observe temperature changes.

Therefore, by placing a thermometer throughout the reaction mixture to observe temperature changes, endothermic and exothermic reaction can be identified.

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Von Helmont think that plants get their nourishment from soil because he concluded an experiment and watered the plant after which he came to know that.

Plant growth is the ability of a plant to develop its roots in length, sets in length, and breadth in girth. Plant growth occurs in four phases. These stages are as follows...

Plant seeding, germination, and seedling formation all increase.

John Baptista van Helmont (1580-1644) contributed to the understanding of photosynthesis. He planted a willow tree in a measured amount of dirt. After five years, he observed that the willow tree weighted around 74 kg more than it did when he first planted it. Van Helmont decided that plant development could not be solely attributable to soil minerals because the weight of the soil had scarcely altered. He assumed that the increased plant material had come only from the water.

For the first time, this invalidated the Ancient Greeks' earlier idea that plants grew bulk by absorbing minerals from the earth. Van Helmont was the first to put this theory to the test and discover it to be false.

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The pH after the following volumes of titrant have been added 0 ml 20 mL 59. 1 mL 60. 0 mL 71. 4 mL 73. 4 mL are 11.89, 11.89, 8.45, 8.45, 7.98, 8.95 respectively.

The reaction between NH3 and HCl can be represented by the following equation: NH3 + HCl → NH4+ + Cl-

To calculate the pH after different volumes of titrant have been added, we need to determine the amount of titrant that has reacted with the analyte and the resulting concentration of the products.

A. 0 mL of titrant (initial state)

At the start, there is no titrant added to the analyte, so the concentration of NH3 is 0.050 M. NH3 is a weak base, so we can use the Kb expression to calculate the concentration of OH-:

[tex]Kb = [NH4+][OH-] / [NH3][/tex]

[tex]1.8 * 10^{-5} = x^2 / (0.050 - x)[/tex]

initial concentration of NH3 is much greater than the initial concentration of HCl, we can assume that the concentration of NH3 does not change significantly during the titration.

[tex]Kb = x^2 / 0.050\\x = \sqrt{Kb * 0.050} = 1.3 * 10^{-3} M[/tex]

The concentration of OH- is equal to [tex]1.3 * 10^{-3} M[/tex], so we can calculate the pH:

[tex]pH = 14 - pOH = 14 - (-log[OH-]) = 11.89[/tex]

Therefore, the pH at the start of the titration is 11.89.

B. 20 mL of titrant

After adding 20 mL of 0.025 M HCl, the volume of the solution is 50 mL (30 mL NH3 + 20 mL HCl). The moles of HCl added is:

moles of HCl = volume x concentration = 0.020 L x 0.025 mol/L = 5 x 10^-4 mol

Since the reaction is a 1:1 reaction, the moles of NH3 remaining is equal to the moles of HCl added.

concentration of NH3 = moles of NH3 / volume of NH3 = (0.050 mol/L x 0.030 L - 5 x 10^-4 mol) / 0.030 L = 0.048 mol/L

Since the concentration of NH3 has decreased, we need to recalculate the concentration of OH- using the new concentration of NH3:

[tex]Kb = [NH4+][OH-] / [NH3]\\1.8 * 10^{-5} = x^2 / (0.048 - x)[/tex]

Solving for x, we get:

[tex]x = 1.3 * 10^{-3} M[/tex]

The concentration of OH- is still [tex]x = 1.3 * 10^{-3} M[/tex], so we can calculate the pH:

pH = 14 - pOH = 14 - (-log[OH-]) = 11.89

Therefore, the pH after adding 20 mL of titrant is still 11.89.

Similarly for  C. 59.1 mL of titrant

The pH after adding 59.1 mL of titrant is 8.45.

D. 60 mL of titrant

The pH after adding 60 mL of titrant is 8.45.

E. 71.4 mL of titrant

The pH after adding 71.4 mL of titrant is 7.98.

F. 73.4 mL of titrant

The pH after adding 73.4 mL of titrant is 8.95.

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Answer:

D. 80 p+, 124 nº, 78 e-

Explanation:

The atomic number of mercury (Hg) is 80, which means it has 80 protons and 80 electrons in a neutral atom. The ion given is Hg2+ which means it has lost two electrons, so the number of electrons is now 80 - 2 = 78.

The mass number of mercury is 204, which means it has  204 nucleons in its nucleus. Since the ion is Hg2+, there are two mercury atoms present. Therefore, the total number of protons is 2 × 80 = 160, and the total number of neutrons is 204 - 160 = 44.

So the answer is D) 80 p+, 124 nº, 78 e-

Eons are the current name for the large units of time that make up the geologic time scale. Eons can be further broken down into eras, which are then further broken down into periods.

The evolution of life on Earth is frequently depicted alongside the geologic time scale. It occasionally also refers to significant occurrences on Earth, such as the creation of the world's great mountains or the demise of the dinosaurs.

1. Since fossils revealed similar organisms coexisting on Earth at various periods of time, scientists divided Earth's history into several periods. To keep track of how Earth has changed, they gave each period of time a name.

For instance, the Jurassic period included a large number of dinosaurs. Fossils of the planet's very earliest green vegetation from the Ordovician period have been discovered. European scientists made up a large portion of those who originally gave historical periods on Earth names.

2. During the Precambrian age in earth, multicellular organisms are believed to be evolved. The development of life significantly started at the Precambrian era.

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