Pls hellppp

Jennifer wants to visit 4 different cities A,B,C and D on her vacation. If she will visit them one at a time, and completly random, what is thr probabitly that she will visit them in the exact order ABCD or DCBA?​

Answers

Answer 1

Answer: The probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]

Step-by-step explanation:

Given: Jennifer wants to visit 4 different cities A,B,C and D on her vacation.

If she visits in an order , total such orders will be [tex]4![/tex] = 4 x 2 x 3 x 1 =24.

Since probability = [tex]\dfrac{\text{Favourable outcomes}}{\text{total outcomes}}[/tex]

In this case favorable outcomes ( ABCD ,  DCBA)=  2

Total outcomes = 24

Required probability = [tex]\dfrac{2}{24}=\dfrac{1}{12}[/tex]

Hence, the probability that she will visit them in the exact order ABCD or DCBA =  [tex]\dfrac{1}{12}[/tex]


Related Questions

Simplifying Rational Expressions: I need answers for both 7 and 8 below. Answers for just one or the other is also fine.

Answers

Answer:

1. Option A 2. Option D

Step by step explanation

1. [tex] \frac{1}{1 - x} + \frac{x}{ {x}^{2} - 1} [/tex]

Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex] to rewrite the fractions

[tex] - \frac{1}{x - 1} + \frac{x}{(x - 1)(x + 1)} [/tex]

Write all numerators above the Least Common Denominator ( X - 1 ) ( X + 1 )

[tex] \frac{ - (x + 1) + x}{(x - 1)(x + 1)} [/tex]

When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression

[tex] \frac{ - x - 1 + x}{(x - 1)(x + 1)} [/tex]

Using [tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex] , simplify the product

[tex] \frac{ - x - 1 + x}{ {x}^{2} - 1 } [/tex]

Since two opposites add up to zero, remove them from the expression

[tex] \frac{ - 1}{ {x}^{2} - 1} [/tex]

So, Option A is the right option.

___________________________________

2.

[tex] \frac{ {x}^{2} - x - 12}{ {x}^{2} - 16} - \frac{1 - 2x}{x + 4} [/tex]

Write - X as a difference

[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{ {x}^{2} - 16 } - \frac{1 - 2x}{x + 4} [/tex]

Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression

[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Factor the expression

[tex] \frac{x(x + 3) - 4(x + 3)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Factor out X+3 from the expression

[tex] \frac{(x + 3)(x - 4)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Reduce the fraction with x-4

[tex] \frac{x + 3}{x + 4} - \frac{1 - 2x}{x + 4} [/tex]

Write all the numerators above the common denominator

[tex] \frac{x + 3 - ( 1- 2x)}{x + 4} [/tex]

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

[tex] \frac{x + 3 - 1 + 2x}{x + 4} [/tex]

Collect like terms

[tex] \frac{3x + 3 - 1}{x + 4} [/tex]

Subtract the numbers

[tex] \frac{3x + 2}{x + 4} [/tex]

Undefined at,

X + 4 = 0

Move constant to R.H.S and change its sign

[tex]x = 0 - 4[/tex]

Calculate

[tex]x = - 4[/tex]

So, the answer is :

[tex] \frac{3x + 2}{x + 4} [/tex] , undefined at X = -4 and 4

Hope this helps..

Best regards!!

PLEASE HELP. I WILL REWARD BRAINLY TO WHO EVER ANSWERS CORRECTLY. (ignore selected answer) Recalling the SAT scores are always expressed as multiples of 10, how many points did you get on the test?

Answers

Answer:

C

Step-by-step explanation:

Find the area of the semicircle need help asapp

Answers

Answer:

2 pi

Step-by-step explanation:

The radius is 2

The area of a circle is

A = pi r^2

We have 1/2 of a circle so

1/2 A = 1/2 pi r^2

         =1/2 pi ( 2)^2

         =1/2 pi *4

      = 2 pi

Identify the two tables which represent quadratic relationships

Answers

Answer:

Option (4) and Option (5)

Step-by-step explanation:

By calculating the second difference, if the second difference in a table is equal, table will represent the quadratic relationship.

In the given option, we analyze that table given in Option (4) will represent the quadratic relationship.

x             y             Ist difference [tex](y_2-y_1)[/tex]         IInd difference

0            4                      -                                             -

1            -4             -4 - (4) = -8                                     -    

2           -4             -4 - (-4) = 0                              0 - (-8) = 8

3            4              4 - (-4) = 8                                  8 - 0 = 8

Second difference of the terms in y are the same as 8.

Therefore, table of Option (4) represents the quadratic relationship.

Similarly, in Option (5) we will calculate the second difference of y terms.

x            y            Ist difference     IInd difference

0          -4                    -                            -

1           -8             -8 - (-4) = -4                 -

2          -10           -10 - (-8) = -2        -2 - (-4) = 2      

3          -10           -10 - (-10) = 0        0 - (-2) = 2

Here the second difference is same as 2.

Therefore, table of Option (5) will represent the quadratic relationship.

Answer:

Option 5 is wrong

Step-by-step explanation:

You are dealt two cards successively (without replacement) from a shuffled deck of 52 playing cards. Find the probability that the first card is a Heart and the second card is a Spade. Write your answer as a decimal rounded to four places if necessary.

Answers

Answer:

The probability that the first card is a Heart and the second card is a Spade is 0.064.

Step-by-step explanation:

A standard deck of 52 cards is shuffled and two cards are drawn without replacement.

The denominations of the cards are as follows:

Spades (S) = 13

Hearts (H) = 13

Diamonds (D) = 13

Clubs (C) = 13

Compute the probability of selecting a Heart first as follows:

[tex]P(H)=\frac{13}{52}=0.25[/tex]

Compute the probability of selecting a Spade second as follows:

[tex]P(S)=\frac{13}{51}=0.255[/tex]

Since the two cards are selected without replacement the second draw is independent of the other.

Then the probability that the first card is a Heart and the second card is a Spade is:

[tex]P(1st\ H\cap 2nd\ S)=P(H)\times P(S)[/tex]

                            [tex]=0.25\times 0.255\\=0.06375\\\approx 0.064[/tex]

Thus, the probability that the first card is a Heart and the second card is a Spade is 0.064.

the vertex of this parabola is at 4,-3 when the x value is 5 the y value is -6 what's the coefficient of the squared expression in the parabolas equation A-2 b2 c3 d-3

Answers

Answer:

d) -3

Step-by-step explanation:

The equation of a parabola in vertex form is given as:

y = a(x - h)² + k. Where (h, k) is the vertex of the parabola.

Given that the vertex of the parabola is at (4,-3) i.e h = 4 and k = -3.

The equation of the parabola is given as:

y = a(x - 4)² + (-3)

y = a(x² - 8x + 16) - 3

y = ax² - 8ax + 16a - 3

Given that when x = 5, y = -6. i.e:

-6 = a(5)² - 8a(5) + 16a - 3

- 6 = 25a - 40a + 16a - 3

-6 + 3 = a

a = -3

Consider the curve of the form y(t) = ksin(bt2) . (a) Given that the first critical point of y(t) for positive t occurs at t = 1 tells us that y '(0) = 1 y(0) = 1 y '(1) = 0 y(1) = 0 Given that the derivative value of y(t) is 3 when t = 2 tells us that y '(3) = 2 y '(0) = 2 y '(2) = 0 y '(2) = 3 (b) Find dy dt = kcos(bt2)·b2t (c) Find the exact values for k and b that satisfy the conditions in part (a). Note: Choose the smallest positive value of b that works.

Answers

Answer:

(a).   y'(1)=0  and    y'(2) = 3

(b).  [tex]$y'(t)=kb2t\cos(bt^2)$[/tex]

(c).  [tex]$ b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]

Step-by-step explanation:

(a). Let the curve is,

[tex]$y(t)=k \sin (bt^2)$[/tex]

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value [tex]x_{0}[/tex]  which lies in the domain of f where the derivative is 0.

Therefore,  y'(1)=0

Also given that the derivative of the function y(t) is 3 at t = 2.

Therefore, y'(2) = 3.

(b).

Given function,    [tex]$y(t)=k \sin (bt^2)$[/tex]

Differentiating the above equation with respect to x, we get

[tex]y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)][/tex]

Applying chain rule,

[tex]y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)[/tex]  

(c).

Finding the exact values of k and b.

As per the above parts in (a) and (b), the initial conditions are

y'(1) = 0 and y'(2) = 3

And the equations were

[tex]$y(t)=k \sin (bt^2)$[/tex]

[tex]$y'(t)=kb2t\cos (bt^2)$[/tex]

Now putting the initial conditions in the equation y'(1)=0

[tex]$kb2(1)\cos(b(1)^2)=0$[/tex]

2kbcos(b) = 0

cos b = 0   (Since, k and b cannot be zero)

[tex]$b=\frac{\pi}{2}$[/tex]

And

y'(2) = 3

[tex]$\therefore kb2(2)\cos [b(2)^2]=3$[/tex]

[tex]$4kb\cos (4b)=3$[/tex]

[tex]$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$[/tex]

[tex]$2k\pi\cos 2 \pi=3$[/tex]

[tex]2k\pi(1) = 3$[/tex]  

[tex]$k=\frac{3}{2\pi}$[/tex]

[tex]$\therefore b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]

The y'(1) =0, y'(2) = 3, and the  [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]  and value of b and k are [tex]\pi/2[/tex]  and  [tex]3/2\pi[/tex] respectively.

It is given that the curve  [tex]\rm y(t) = ksin(bt^2)[/tex]

It is required to find the critical point, first derivative, and smallest value of b.

What is a function?

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We have a curve:

[tex]\rm y(t) = ksin(bt^2)[/tex]

Given that the first critical point of y(t) for positive t occurs at t = 1

First, we have to find the first derivative of the function or curve:

[tex]\rm y'(t) = \frac{d}{dt} (ksin(bt^2))[/tex]

[tex]\rm y'(t) = k\times2bt\times cos(bt^2)[/tex]   [ using chain rule]

[tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]

y(0) = 0

y'(0) = 0

The critical point is the point where the derivative of the function becomes 0 at that point in the domain of a function.

From the critical point y'(1) = 0 ⇒  [tex]\rm kb2 \ cos(b) =0[/tex]

k and b can not be zero

[tex]\rm cos(b) = 0[/tex]

b = [tex]\rm \frac{\pi}{2}[/tex]

and y'(2) =3

[tex]\rm y'(2) = kb2\times 2 \times cos(b\times2^2) =3\\\\\rm 4kb \ cos(4b) =3[/tex](b =[tex]\rm \frac{\pi}{2}[/tex])

[tex]\rm 4k\frac{\pi}{2} \ cos(4\frac{\pi}{2} ) =3\\\\\rm2 \pi kcos(2\pi) = 3[/tex]

[tex]\rm2 \pi k\times1) = 3\\\rm k = \frac{3}{2\pi}[/tex]

Thus, y'(1) =0, y'(2) = 3, and the  [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]  and value of b and k are [tex]\pi/2[/tex]  and  [tex]3/2\pi[/tex] respectively.

Learn more about the function here:

brainly.com/question/5245372

FIRST CORRECT ANSWER GETS BRAINLIEST 50 PTS [tex](2x-5)^{2} +3(2x-5)-18[/tex]

Answers

Answer:

4x² -14x - 8

Step-by-step explanation:

(2x - 5)² + 3(2x-5) - 18

Expand brackets.

(2x-5)(2x-5) + 6x -15 - 18

2x(2x-5)-5(2x-5) + 6x - 33

4x² - 10x - 10x + 25 + 6x - 33

Combine like terms.

4x² -14x - 8

Answer:

4x^2 -14x -8

Step-by-step explanation:

( 2x-5)^2 + 3( 2x-5) -18

Foil

(2x-5)(2x-5) = 4x^2 -10x-10x +25 = 4x^2 -20x+25

Distribute

3( 2x-5) = 6x -15

( 2x-5)^2 + 3( 2x-5) -18

Replace with the foil and distribute

4x^2 -20x+25 +6x -15 - 18

Combine like terms

4x^2 -14x -8

Give an example of how you would solve an equation by completing the square. Describe the steps.

Answers

Answer:

Step-by-step explanation:

to solve an equation by completing the square in a quadratic formula

f(x)=ax²+bx+c

example :x²-6x-16=0

first rearrange if necessary, move the constant to one side .

x²-6x=16

second you find a new term to complete the square which is (b/2)², and add the term to both sides.(6/2)²=3²=9

x²-6x+9=16+9

x²-6x+9=25

third  factorize : find the common factor between 6 and 9 which is 3

x²-6x+9=25

(x-3)²=25

last solve for x: (x-3)²=25

x-3=√25

x=3±5

x=3+5=8 or 3-5=-2

Mrs. Jones decided to buy some pencils for her class. She bought 3 packages of pencils, and each package contained 72 pencils. There are 24 students in her class and she divided up the pencils so that each student had the same amount of pencils. If there are were no pencils left over, how many pencils did each student get?

Answers

Answer:

9 pencils

Step-by-step explanation:

Three triangles have sides of lengths 3, 4, and 5. Their respective perimeters are 6, 8 and 10. The triangles are similar to each other.
True or false

Answers

Answer:

'll tell you where the problem lies - it is IMPOSSIBLE to form triangles like this.

If the perimeter of the smallest triangle is 6 and one side is 3, then the sum of the other two sides can only be 6 - 3 = 3

One property to enable you to form a triangle is that NO ONE SIDE can be greater or equal to the sum of the other two sides. In the smallest triangle 1 side of length 3 equals the other two sides.

In the middle triangle one side of length "4" equals the sum of the other two sides and

In the large triangle one side of length "5" equals the other two sides.

Therefore when I say "triangle" above I am not actually correct because it is IMPOSSIBLE to form triangles with those dimensions of 1 side and with those perimeters

Someone pls help me I’m struggling

Answers

Answer:

2850

Step-by-step explanation:

We know that only 19% of people prefer the sedans, so we have to find 19% of 15,000. Set up a proportion: [tex]\frac{19}{100}=\frac{x}{15000}[/tex], cross multiply and get 2850.

Answer:

2850 sedans per month

Step-by-step explanation:

19 % want sedans

They expect to sell 15000 cars

Take the number of cars and multiply by the percent sedans

19% * 15000

Change to decimal form

.19*15000

2850

41 points * please help Write a linear equation - wil give brainlyist to first person

Answers

Answer:

C = 38n + 1750; 15,050

Step-by-step explanation:

We know that for each person, there's a fee of 38. That signifies that the n will be after 38. 1,750 is a one-time fee, so that's by itself. Plug it into the equation to get your first answer. Now, solve for b) by writing C = 38(350) + 1750; C = 15,050

Answer:

C = 38n + 1750; 15,050

Step-by-step explanation:

brainlist plzzzzzz


(04.02 LC)
What is the solution to the following system of equations?
X - 3y = 6
2x + 2y = 4

(-1, 3)
(3, -1)
(1, -3)
(-3, 1)​

Answers

Answer:

The solution is

( 3 , - 1)

Step-by-step explanation:

x - 3y = 6 ............ Equation 1

2x + 2y = 4 ............ Equation 2

Make x the subject in equation 1 and substitute it into equation 2

That's

x = 6 + 3y

2( 6 + 3y ) + 2y = 4

Expand and simplify

12 + 6y + 2y = 4

8y = - 8

Divide both sides by 8

y = - 1

Substitute y = - 1 into x = 6 + 3y

That's

x = 6 + 3(-1)

x = 6 - 3

x = 3

x = 3 y = - 1

( 3 , - 1)

Hope this helps you

Answer:

B. ( 3 , - 1)  

Step-by-step explanation:

x - 3y = 6 Equation 1

2x + 2y = 4  Equation 2

x = 6 + 3y

2( 6 + 3y ) + 2y = 4

12 + 6y + 2y = 4

8y = - 8

y = - 1

x = 6 + 3(-1)

x = 6 - 3

x = 3

x = 3 y = - 1

( 3 , - 1)

on a number cube (numbered 1-6) what is the probability of rolling a 3?

Answers

Answer:

1

Step-by-step explanation:

There is only one 3 on the cube

What is the value of the expression
below?
675 - (15 - 12)³ ÷ 3

A 216
C 666
B 224
D 678​

Plz help

Answers

Answer:

675 – (15-12) ³+3

675-3³ +3

675-27+3

651

Step-by-step explanation:

The value of the given expression is 666 which is the correct answer that would be an option (C).

What is the PEMDAS rule?

PEMDAS rule states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.

We have been given the expression below as:

675 – (15-12)³ ÷ 3

Using the PEMDAS rule to determine the evaluation of the given expression  

⇒ 675 – (15-12)³ ÷ 3

Apply the subtraction operation,

⇒ 675 - (3)³ ÷ 3

⇒ 675 - 27 ÷ 3

⇒ 675 - 27 / 3

Apply the division operation,

⇒ 675 - 9

Apply the subtraction operation,

⇒ 666

Therefore, the value of the given expression would be 666,

Learn more about the PEMDAS rule here :

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#SPJ6

Problem PageQuestion Two pools are being filled with water. To start, the first pool contains 720 liters of water and the second pool is empty. Water is being added to the first pool at a rate of 19.25 liters per minute. Water is being added to the second pool at a rate of 41.75 liters per minute. After how many minutes will the two pools have the same amount of water? minutes How much water will be in each pool when they have the same amount? liters

Answers

Answer:

After 32 minutes the two pools will have the same amount of water.

There will be 1,366 liters in each pool when they have the same amount of water.

Step-by-step explanation:

Hi, to answer this question we have to write a system of equations:

The first pool contains 720 liters of water, and it’s being added at a rate of 19.25 liters per minute.

First Pool = 720 +19.25 m

Where m is the number of minutes.

The second pool is empty, and Water is being added at a rate of 41.75 liters per minute

Second pool = 41.75m

Since both pools must have the same amount of water:

720 +19.25 m = 41.75m

Solving for m:

720 = 41.75m-19.25 m

720 = 22.5m

720/22.5 = m

32 = m

After 32 minutes the two pools will have the same amount of water.

Finally, we replace m=32 on any equation:

41.75m = 41.75 (32) = 1,336 liters

There will be 1,366 liters in each pool when they have the same amount of water.

Feel free to ask for more if needed or if you did not understand something.  

Please give me correct answer and fast answer it if know answer only

Answers

Answer:

Approximatley 5.8 units.

Step-by-step explanation:

We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

[tex]\frac{\sin(A)}{a}=\frac{\sin(B)}{b} =\frac{\sin(C)}{c}[/tex]

Replacing them with the respective variables, we have:

[tex]\frac{\sin(S)}{s} =\frac{\sin(T)}{t} =\frac{\sin(R)}{r}[/tex]

Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for t. Ignore the third term:

[tex]\frac{\sin(20)}{s}=\frac{\\sin(17)}{5}[/tex]

Solve for s, the unknown side. Cross multiply:

[tex]\frac{\sin(20)}{s}=\frac{\sin(17)}{5}\\5\sin(20)=s\sin(17)\\s=\frac{5\sin(20)}{\sin(17)} \\s\approx5.8491\approx5.8[/tex]

Katya has $20.00 to spend at her college bookstore, where all students receive a 20% discount . katya wants to purchase a copy of a book that normally sells for $22.50 plus 10% sales tax. how much dose the book sell for dose katya have enough money bc bc?

Answers

Answer:

Katie is correct. You would take 20% of $22.50 (22.5 multiplied by .2). You would get $4.50 off of the book with the discount. So you would subtract 4.5 from 22.5 and get $18. Then you would take 10% of $18 for the sales tax. (18 multiplied by .1). You would get $1.80 towards sales tax. you would then add $1.80 to $18 and get $19.80

Step-by-step explanation:

A school counselor surveyed 90 randomly selected students about thé langages they speak. Of thé students surveyed 16 speak more than one langage fluently. Bases on thèse résults, How many of thé 1800 students at thé school can be expected to speak more than one langage fluently

Answers

Answer: 320 students

Step-by-step explanation:

From the question, we are informed that a school counselor surveyed 90 randomly selected students about thé langages they speak and thé students surveyed 16 speak more than one langage fluently. This means that 16/90 speak more than one language.

When 1800 students are surveyed, the number of students that can be expected to speak more than one langage fluently will be:

= 16/90 × 1800

= 16 × 20

= 320 students

Pls help I can't understand ​

Answers

Answer:

A

Step-by-step explanation:

This shape is a trapezoid. We can divide into two parts: a triangle and a rectangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let A' be the area of the triangle.

● A'= (b*h)/2

b is the base and h is teh heigth.

b= 26-20 = 6 mm

● A'= (6*14)/2 = 42 mm^2

●●●●●●●●●●●●●●●●●●●●●●●●

Let A" be the area of the rectangle.

A"= L*w

L is the length and w is the width.

A"= 14*20

A"= 280 mm^2

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let A be the area of the trapezoid.

A= A'+A"

A= 42+280

A= 322 mm^2

The coordinates of point L on a coordinate grid are (−2, −4). Point L is reflected across the y-axis to obtain point M and across the x-axis to obtain point N. What are the coordinates of points M and N? M(2, 4), N(−2, −4) M(2, −4), N(−2, 4) M(−2, −4), N(2, 4) M(−2, 4), N(2, −4)

Answers

Answer:

M(2, −4), N(−2, 4)

Step-by-step explanation:

Transformation is the movement of a point from one place to another. If an object is transformed, all the points of the object are being changed. There are different types of transformation which are: Reflection, rotation, translation  and dilation.

Reflection of a point is the flipping of a point. If a point A(x, y) is reflected across the x axis, the new point is A'(x, -y). If a point B(x, y) is reflected across the y axis, the new point is A'(-x, y).

The coordinates of point L on a coordinate grid are (−2, −4), if Point L is reflected across the y-axis to obtain point M, the coordinates of M is at (2, -4).

if Point L is reflected across the x-axis to obtain point N, the coordinates of N is at (-2, 4).

Answer: M(2, −4), N(−2, 4) So D can i get branliest

Step-by-step explanation:

An urn contains 5 white and 10 black balls. A fair die is rolled and that numberof balls are randomly chosen from the urn. What is the probability that all of theballs selected are white? What is the conditional probability that the die landed on3 if all the balls selected are white?

Answers

Step-by-step explanation:

[tex]A[/tex]- all of the chosen balls are white [tex]E_{i}-[/tex] result of the die roll is [tex]i, \quad i \in\{1,2,3,4,5,6\}[/tex]

Probabilities:

since the die is fair:

[tex] P\left(E_{i}\right)=\frac{1}{6} \quad \text { for } \quad i \in\{1,2,3,4,5,6\} [/tex]

If the die rolls [tex]i[/tex] we choose a combination of [tex]i[/tex] balls, among 10 black and five white balls, therefore

\[ \begin{array}{c}

P\left(A \mid E_{1}\right)=\frac{\left(\begin{array}{c} 5 \\

1 \end{array}\right)}{\left(\begin{array}{c} 15 \\ 1 \end{array}\right)}=\frac{5}{15}=\frac{1}{3} \\ P\left(A \mid E_{2}\right)=\frac{\left(\begin{array}{c} 5 \\ 2 \end{array}\right)}{\left(\begin{array}{c} 15 \\ 2

\end{array}\right)}=\frac{10}{105}=\frac{2}{21} \\

P\left(A \mid E_{3}\right)=\frac{\left(\begin{array}{c} 5 \\ 3

\end{array}\right)}{\left(\begin{array}{c} 15 \\ 3

\end{array}\right)}=\frac{10}{455}=\frac{2}{91} \\

P\left(A \mid E_{4}\right)=\frac{\left(\begin{array}{c} 5 \\ 4

\end{array}\right)}{\left(\begin{array}{c} 15 \\ 4

\end{array}\right)}=\frac{1}{273} \\

P\left(A \mid E_{5}\right)=\frac{\left(\begin{array}{c} 5 \\ 5

\end{array}\right)}{\left(\begin{array}{c} 15 \\ 5

\end{array}\right)}=\frac{1}{3003} \\

P\left(A \mid E_{6}\right)=\frac{\left(\begin{array}{c} 5 \\ 6

\end{array}\right)}{\left(\begin{array}{c} 15 \\ 6

\end{array}\right)}=0

\end{array} \]

PLEASE HELP!!
Factor the polynomial [tex]x^2+6x+5[/tex]. Your answer can be written as [tex](x+A)(x+B)[/tex] where A

Answers

Step-by-step explanation:

[tex]a + b = 6[/tex]

[tex]ab = 1 \times 5 = 5[/tex]

[tex]a = 1 \: \: \: \: \: \: \: \: b = 5[/tex]

[tex]( {x}^{2} + x) + (5x + 5)[/tex]

[tex]x(x + 1) + 5(x + 1)[/tex]

[tex](x + 1)(x + 5)[/tex]

Hope this is correct and helpful

HAVE A GOOD DAY!

Find the​ (a) mean,​ (b) median,​ (c) mode, and​ (d) midrange for the data and then​ (e) answer the given question. Listed below are the weights in pounds of 11 players randomly selected from the roster of a championship sports team. Are the results likely to be representative of all players in that​ sport's league? 293 255 264 240 190 295 199 184 293 205 199

Answers

Answer:

A.) Mean = 237.9

B.) Median = 240

C.) Mode = 199

D.) Midrange = 239.5

Step-by-step explanation:

The given data are :

293 255 264 240 190 295 199 184 293 205 199

The mean = (sum of X) / f

Where frequency f = 11

X = 293 + 255 + 264 + 240 + 190 + 295 + 199 + 184 + 293 + 205 + 199

X = 2617

Substitute X and f into the formula

Mean = 2617/11

Mean = 237.9 approximately

B.) To get the median, you need to first rearrange the data, then pick the middle number.

184 190 199 199 205 240 255 264 293 293 295

The median = 240

C.) The mode is the highest frequency. That is the most occuring number

Mode = the two most occuring numbers are 199 and 293

D.) Range = highest number - lowest number

But midrange = (highest number + lowest number ) ÷ 2

Highest number = 295

Lowest number = 184

Substitute into the formula

Midrange = (295 + 184)/2

Midrange = 479/2

Midrange = 239.5

Please answer this question now correct

Answers

Answer:

Step-by-step explanation:

cosine law

a²=b²+c²-2(bc)cos44  (c=20, b=15)

a²=15²+20²-2(15*20)cos44

a=√15²+20²-2(15*20)cos44

a=13.91

a blue dice and a green dice are rolled. Find the probability that the blue is either 1 or 2 and the green is 1.

Answers

Answer:

2

Step-by-step explanation:

green

Answer: 2

Step-by-step explanation:

Can somebody please answer as many as possible?

Please and thankyou!

A quadrilateral is 360 degrees

I cant make a shape for any! Please help!

Answers

Answer:

Simply subtract the sum of the the three angles given from 360° in order to get the measure of the fourth angle!

Step-by-step explanation:

Una máquina llena 4 baldes de helado en 30 minutos, funcionando siempre a la misma velocidad Si ante un corte de luz, solo funcionó durante 45 minutos, ¿cuántos baldes habrá llenado?

Answers

Answer:

La máquina llenó:

6 baldes

Step-by-step explanation:

Por regla de tres:

4 baldes son a 30 minutos

M baldes son a 45 minutos

M = 45*4/30

M = 180/30

M = 6

here are members on the board of directors for a certain​ non-profit institution. a. If they must elect a​ chairperson, first vice​ chairperson, second vice​ chairperson, and​ secretary, how many different slates of candidates are​ possible? b. If they must form an ethics subcommittee of four​ members, how many different subcommittees are​ possible?

Answers

Answer: 1320; 495

Step-by-step explanation:

Explanation is in the attachment file

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