Pleaseeee helppp!! The picture is below with answer choices

The electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

Electrical power is the rate at which electrical work is done.

The unit of electrical power is Watts.

The experiment will require a 24V Battery, a Lamp marked 24V, 100 W, a key, wires, a rheostat, a voltmeter and an ammeter.

The circuit is completed and the rheostat is adjusted to provide until the voltmeter reads 24V.

The ammeter reading is taken as well.

When the voltmeter reading is 24V, it can be seen that' the ammeter reading for current is approximately 4.2 A.

Calculating, the power of the lamp:

Power = 24 × 4.2 = 100 W

Therefore, the electrical power supplied to the lamp is 100W when the p.d. across it is 24V and the current is 4.2 A.

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Answer:

5

Explanation:

vf = vi + at

20 = 5 + 3a

3a = 15

a = 5

Answer:D

Explanation: temperature is the measure of hotness and coldness of a body.

Answer:

Approximately [tex]14\; {\rm m\cdot s^{-1}}[/tex].

Explanation:

The gravitational potential energy [tex]\text{GPE}[/tex] of this roller coaster is proportional to the height [tex]h[/tex] of the roller coaster.

The kinetic energy [tex]\text{KE}[/tex] of this roller coaster is proportional to the square of speed [tex]v[/tex].

The question states that the track is frictionless. Thus, during the descent, the [tex]\text{GPE}[/tex] of this roller coaster is turned into [tex]\text{KE}[/tex] without any energy loss.

When the roller coaster was at [tex](1/2)[/tex] of the the initial height, only[tex]1 - (1/2) = (1/2)[/tex] of the original [tex]\text{GPE}[/tex] was turned into [tex]\text{KE}[/tex]. The [tex]\text{KE}\![/tex] of this roller coaster at that height would be [tex]1 - (1/2) = (1/2)\![/tex] of the [tex]\text{KE}\!\![/tex] when the roller coaster is at the ground level.

The [tex]\text{KE}[/tex] of the roller coaster is proportional to [tex]v^{2}[/tex] (the square of speed [tex]v[/tex].) Thus, since the [tex]\text{KE}\![/tex] at [tex](1/2)[/tex] the initial height is [tex]1 - (1/2) = (1/2)\![/tex] the [tex]\text{KE}\!\![/tex] at the ground level, the [tex]v^{2}[/tex] at [tex](1/2)\![/tex] the initial height would also be [tex]1 - (1/2) = (1/2)\![/tex] the [tex]v^{2}\![/tex] at the ground level.

Since [tex]v = 20\; {\rm m\cdot s^{-1}}[/tex] at the ground level, [tex]v^{2} = (20\; {\rm m\cdot s^{-1}})^{2}[/tex] at the ground level. The [tex]v^{2}[/tex] at [tex](1/2)[/tex] the initial height would then be:

[tex](1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}[/tex].

Thus, the speed [tex]v[/tex] at [tex](1/2)[/tex] the initial height would be:

[tex]\begin{aligned}& \sqrt{(1 - (1/2))\times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{\frac{1}{2} \times (20\; {\rm m\cdot s^{-1}})^{2}} \\ =\; & \sqrt{200}\; {\rm m\cdot s^{-1}} \\ \approx\; & 14\; {\rm m\cdot s^{-1}}\end{aligned}[/tex].

The attractive force between sugar and flour by using Newton's law of gravitation is 14.229 × 10⁻¹¹ N.

This law states that every object in the universe attracts each other. The attractive force is directly proportional to the masses of two objects and inversely proportional to the square of the distance between them.

This law is applicable to all the objects with mass in the universe and hence it is called the Universal law of gravitation. It was proposed by Newton.

The attractive force, F =G (m₁×m₂ / r²). m₁,m₂ is the masses of two objects and r is the distance between two masses. G is the gravitational constant and is equal to 6.67×10⁻¹¹Nm²kg⁻².

From the given,

Gravitational constant,G = 6.67×10⁻¹¹Nm²kg⁻²

m₁ (mass of sugar) = 1.2 kg

m₂ (mass of flour) = 9.4 kg

r (distance of separation) = 2.3 m

The attractive force, F = G (m₁×m₂ / r²)

F =  6.67×10⁻¹¹×(1.2×9,4) / (2.3)²

 = 14.229 × 10⁻¹¹ N

Thus, the attractive force F = 14.23 × 10⁻¹¹ N.

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Hi there!

We can use the following equation to calculate the magnetic field inside of a solenoid:
[tex]B = \mu_0 ni[/tex]

B =  Magnetic Field Strength (T)
n = number of loops PER LENGTH

i = current through solenoid (A)
μ₀ = Permeability of free space (4π × 10⁻⁷ Tm/A)

First, we can solve for 'n' given 'N' (total # of loops) and L (length of solenoid).

[tex]n = \frac{N}{L} = \frac{200}{0.25} = 800[/tex]

Now, we can calculate the magnetic field:

[tex]B = (4\pi \times 10^{-7}) (800)(.29) = \boxed{2.915 \times 10^{-4} T}[/tex]

Answer:

transformers

Explanation:

A transformer is a device that increases or decreases voltage.

Explanation:

POTENTIAL energy is due to a mass's height above the earth and is equal to   m * g * h      

  130 kg  * 9.81 m/s^2  * 1000 m = 1275300 J

Answer:

a baseball hit with a baseball bat travels faster than a bowling ball hit with the same type of force

Explanation:

How Maria can correct her error is by changing the fourth point to "applies to accelerating objects.". Option D. This is further explained below.

Generally, Einstein’s special relativity is simply defined as how speed affects matter, time, and space.

In conclusion, The theory contains a method for defining the link between energy and matter using the speed of light.

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Answer:

Wave speed and wavelength

Explanation:

Answer:

Protostars

Explanation:

Distant galaxies we can see today with a redshift of z >> 6 emitted their light when the universe was expanding.

This term comprises of stars and interstellar matter that make up the universe.

, The farther a galaxy, the faster it is receding from Earth which depicts its expansion and makes it the most appropriate choice.

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Answer:

Increase distance

Explanation:

Gravity force = g m1 m2 / r^2

  so you can see that increasing the distance r^2   will make the force less

Answer: Increase the distance between the two objects.

Explanation:

Consider what features of objects affect the gravitational force exhibited.

For Andrea, whose mass is 48kg, thinks she's sitting at rest in her 5. 0m-long, her range  is mathematically given as

dv=1.95*10^{-37}ms^{-1}

Generally, the equation for the uncertainty principle is mathematically given as

mdxsv=h/2

Therefore

dv=h/(2mdx)

dv=1.054*10^{-39}/2*45*6

dv=1.95*10^{-37}ms^{-1}

In conclusion, range of her velocity

dv=1.95*10^{-37}ms^{-1}

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Answer:

because the moon is nearer to the earth compared to the stars which we require telescopes to observe

Answer:

warm rises cold sinks

Explanation:

Answer:

Part 1 = 0.03m, Part 2 = 1.4651J

Answer:

F = - K X

X =  -F / K = M g / K = 9.8 * 2.3 / 735 = .03 m = 3 cm

W = 1/2 K X^2

W = 1/2 * 735 N/m * .065^2 m^2 = 1.55 Joules

Answer:

right    

Explanation:

The up and down forces cancel

  then you are left with a    -200    and a  + 400

     resulting in a + 200   (to the right)

The time taken by a truck to fully stop will be 2 hours. The time taken is found with the help of Newtons second equation of motion.

Distance is a numerical representation of the distance between two objects or locations.

Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The given data Is;

u is the velocity of truck =  55 mph

v is the final velocity of truck = 0 mph

S is the distance travelled by the truck before stop= 302 feet

1 feet = 0.000189394 mile

302 feet = 302 × 0.000189394 mile= 0.057197 mile

From the Newtons's second equation of motion;

[tex]\rm v^2 = u^2-2as[/tex]

The formula for the acceleration is found as;.

[tex]a = \frac{v-u}{t}[/tex]

By rearranging the equation, we get;

[tex]\rm u^2 =2as \\\\ u^2 =2[ \frac{v-u}{t}]s \\\\ u = \sqrt{2[ \frac{v-u}{t}]s} \\\\ 55 = \sqrt{2[ \frac{55-0}{t}]} \\\\ 55= \frac{2 \times 55}{t} \\\\ t= 2 \ hour[/tex]

Hence, the time taken by a truck to fully stop will be 2 hours.

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The magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

The magnitude of the electrical force between two charges refers to the attractive or repulsive forces that exists between two charges separated by a given distance in an electric field.

The magnitude of the electrical force, F between the two charges q2 and q3 is given be my the formula below

[tex]F = \frac{K \times q_2 \times q_3}{d^{2}}[/tex]

Therefore, the magnitude of the electrical force between q2 and q3 is given as a ratio between the product of their charges and the square of the distance of separation.

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Answer:B .–1.1 × 10¹¹ N

Explanation:

Got it right on edge

Answer:

When in the graph the line is horizontal it states that the moving object is stationary

Explanation:

a. Jessica's has a greater linear speed.

b. The centripetal acceleration of Julie and her horse is 0.148 m/s².

Jessica's has a greater linear speed.

To answer the question, we need to know what Linear speed is.

This is the tangential speed at which an object in circular motion moves. It is given by v = rω where

Now, given that Jessica is riding on a merry-go-round on an outer horse that sits at a distance of 8.0 m from the center of the ride and Jessica's sister, Julie, is on an inner horse located 6.0 m from the ride's center. Also, the merry-go-round is moving at constant angular speed.

Since Linear speed v = rω and ω = constant,

So, v ∝ r.

So, the girl with the greater distance from the center of the merry-go-round would have the greater linear speed.

Since

Since

So, Jessica's has a greater linear speed.

The centripetal acceleration of Julie and her horse is 0.148 m/s².

Centripetal acceleration a = rω² where

Since the merry-go-round turns once every 40.0 s, we have that ω = 2π/40.0 s

= π/20.0 s

= 0.157 rad/s

Since a = rω²

Substituting the values of the variables into the equation, we have

a = rω²

a = 6.0 m × (0.157 rad/s)²

a = 6.0 m × 0.0247 rad²/s²

a = 0.148 m/s²

So, the centripetal acceleration of Julie and her horse is 0.148 m/s².

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When two surfaces slide against each other, a force called friction makes them stick very slightly together. Smooth surfaces, like ice and glass, are easy to slide over. They create very little friction. Rough surfaces like rock and sand create much more friction, and are easy to grip on to.

hope it helps...!!!

True, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.

The electric field in a capacitor separates the negative and positive charges in the dielectric material, this causes an attractive force between each plate and the dielectric.

The dielectric material can store electric energy due to its polarization in the presence of external electric field, which causes the positive charge to store on one electrode and negative charge on the other.

Thus, when charging a secondary cell, energy can be stored within a dielectric material using an electric field.

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