Answers
The molarity of the product is 0.00368 M. Option B
What is the reaction equilibrium?When the rates of the forward and reverse reactions in a chemical reaction are equal and the concentrations of reactants and products are stable over time, this condition is referred to as reaction equilibrium.
The equilibrium constant is a measure of the relative concentrations of reactants and products at equilibrium.
[tex]Keq = [H_{2} O] [CO]/[H_{2}] [CO_{2} ]\\0.106 = x^2/(0.0113)^2\\x = \sqrt{} 0.106 (0.0113)^2\\x = 0.00368 M[/tex]
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Related Questions
PLEASE HELP!
Distilled vinegar contains a solution of acetic acid (CH3CO2H) in H2O. Using the formula M1V1=M2V2, solve for the concentration of the solution that results from diluting 0.50 L of 0.839 M vinegar solution to 2.5 L?
Question 4 options:
0.15 M
0.24 M
0.17 M
1.49 M
Answers
M1V1 = M2V2
0.839 M x 0.50 L = M2 x 2.5 L
M2 = (0.839 M x 0.50 L) / 2.5 L
M2 = 0.168 M
Therefore, the concentration of the solution that results from diluting 0.50 L of 0.839 M vinegar solution to 2.5 L is 0.168 M.
Answer: 0.17 M (rounded to two significant figures)
You react 0.017 mol of solid metal with HCl in a coffee cup calorimeter (reaction shown below). The calorimeter has 100 mL of water in it, and the temperature of the water increases by 3.81°C. The calorimeter has a heat capacity of 40.4 J/°C. What is the enthalpy of the reaction in terms of kJ per mol of the metal (your answer should be NEGATIVE, remember to convert from J to kJ, specific heat capacity of water is 4.184 J/g-°C)?
M(s) + 2 HCl (aq) MCl2 (aq) + H2 (g)
M = metal
Answers
q = -mCΔT
where q is the heat absorbed by the water and the calorimeter, m is the mass of the water, C is the heat capacity of the calorimeter, and ΔT is the change in temperature of the water.
First, we need to calculate the heat absorbed by the water and the calorimeter:
q = (100 g) x (4.184 J/g-°C) x (3.81°C) + (40.4 J/°C) x (3.81°C)
q = 1657.4 J
Next, we need to calculate the moles of HCl used in the reaction. From the balanced chemical equation, we can see that 2 moles of HCl react with 1 mole of the metal, so:
moles of HCl = 2 x moles of metal = 2 x 0.017 mol = 0.034 mol
Finally, we can calculate the enthalpy of the reaction per mole of the metal:
ΔH = -q / moles of metal
ΔH = -(1657.4 J) / (0.017 mol)
ΔH = -97,494 J/mol
To convert to kJ/mol, we divide by 1000:
ΔH = -97.494 kJ/mol
Therefore, the enthalpy of the reaction is -97.494 kJ/mol of the metal. Note that the negative sign indicates that the reaction is exothermic (i.e. heat is released).
You want to have a barbecue this weekend! But you're worried about global warming. You only want to release a maximum of 0.750 kg of carbon dioxide from your propane grill. Using the below equation to answer the following questions.
CH3(g) + 5O2(g) → 3CO2(g) + 4H2O(g)
ΔHrxn = -2220.1 kJ
a. How many kilojoules will you be able to release?
b. If it requires 1900 kJ to cook one hamburger, how many hamburgers can you cook?
Answers
a. We will be able to release 37,827 kJ. b. You can cook a maximum of 19 hamburgers without exceeding the limit of 0.750 kg of carbon dioxide.
a. We need to use the balanced chemical equation and the enthalpy change of the reaction.
Therefore, moles [tex]CO_2[/tex] produced are[tex]0.750 kg / 44.01 g/mol = 17.03 mol.[/tex]
The enthalpy change of the reaction is -2220.1 kJ/mol. Thus, the maximum number of kilojoules that can be released is:
[tex]\Delta Hrxn * moles of[/tex] [tex]CO_2[/tex] = [tex]-2220.1 kJ/mol * 17.03 mol = -37,827 kJ[/tex]
We need to reverse the sign of the answer, giving us 37,827 kJ.
b. If it requires 1900 kJ to cook one hamburger, we can divide the maximum number of kilojoules that can be released by the energy required to cook one hamburger:
37,827 kJ / 1900 kJ/hamburger = 19.91 hamburgers
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Please help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
Answers
Answer:
The Correct answer is option 3
Step by Syep Explanation:
4Fe+3O2---->rust
formula for rust----->Fe2O3
4Fe+3O2---->Fe2O3
Balancing the Chemical Equation
both the reactant and product side
we have that;
4Fe+3O2------->2FeO3
the equation is Chemically Balanced
therefore 4Fe+3O2------->2×rust
Answer:
2Fe₂O₃ (Option 3)Explanation:
Given that,
4Fe + 3O2 → rust.Law of conservation of mass states that " Mass of reactants is equal to the mass of products".
Also we know that In a balanced equation the total number of atoms in the reactants equals the total number of atoms in the product.
We are given with 4Fe + 3O₂ i.e the reactant.
First Let's calculate the number of atoms in the reactant.
No. of atoms in Fe = 4 No. of atoms in O = 3 × 2 = 6Now, Let's find the product .
Also, We can see 2Fe₂O₃ (Product)
No. of atoms in Fe = 2 × 2 = 4 No. of atoms in O = 2 × 3 = 6.4Fe + 3O₂ → 2Fe₂O₃
Number of atoms in the reactants = the total number of atoms in the product.
Therefore, 2Fe₂O₃ (Option 3) will the required answer .
If the amount of solute present in a solution at a given temperature is less than the maximum amount that can be dissolved at that tempature the solution is said to be
Answers
Answer:
Unsaturated
Explanation:
A solution is unsaturated when it contains less than the maximum amount of solute that is capable of being dissolved.
If 50 joules of energy is added to sample of water, the temperature will?
Answers
Explanation:
The temperature change of a substance when it absorbs or loses energy can be calculated using the specific heat capacity of the substance. The specific heat capacity of water is approximately 4.18 J/(g°C), which means that it takes 4.18 joules of energy to raise the temperature of 1 gram of water by 1 degree Celsius.
To calculate the temperature change of the water sample when 50 joules of energy is added, we need to use the following equation:
q = m * c * ΔT
where q is the amount of energy absorbed by the water, m is the mass of the water sample, c is the specific heat capacity of water, and ΔT is the resulting temperature change.
Rearranging the equation to solve for ΔT, we get:
ΔT = q / (m * c)
Plugging in the values, we get:
ΔT = 50 J / (m * 4.18 J/(g°C))
We need to know the mass of the water sample to calculate the temperature change. Let's assume a mass of 10 grams:
ΔT = 50 J / (10 g * 4.18 J/(g°C))
ΔT = 1.2°C
Therefore, if 50 joules of energy is added to a 10-gram sample of water, the resulting temperature change will be approximately 1.2 degrees Celsius.
which type of mutation could have the most drastic effect
on a gene a chromosomal mutation? Back up your choice.
Answers
Answer:
we need to know the definitions of the two types of mutations:
A chromosomal mutation is a change in the structure or number of chromosomes, which are the structures that carry genes. Examples of chromosomal mutations are deletions, duplications, inversions, and translocations.A gene mutation is a change in the sequence of nucleotides, which are the building blocks of DNA and RNA. Examples of gene mutations are substitutions, insertions, and deletions.Looking at the definitions, we can see that a chromosomal mutation can affect many genes at once, while a gene mutation can affect only one or a few nucleotides. Therefore, a chromosomal mutation could have the most drastic effect on a gene, because it could alter or delete an entire gene or multiple genes, resulting in major changes in the phenotype or function of an organism. A gene mutation could also have significant effects on a gene, but it could also be silent or minor depending on the location and type of the mutation. Therefore, the answer is a chromosomal mutation. One possible way to back up this choice is to give an example of a chromosomal mutation that causes a genetic disorder, such as Down syndrome or Turner syndrome.
Please help me with this chemistry investigation I need answers as soon as possible please
Answers
B. To plot the data on a bar chart, draw a horizontal axis for metals and a vertical axis for time to complete the reaction. Then, draw bars for each metal that represent the amount of time required to complete the reaction. The height of the bars must match the time values in the table.
C. No, Emilia was not correct in her forecast. According to the data, aluminum reacted 100 seconds faster than magnesium, which reacted in 50 seconds. Thus aluminum reacts more rapidly with hydrochloric acid than magnesium.
From most reactive to least reactive, the metals are as follows:
aluminummagnesiumZincIronThis order is consistent with the reactivity series, which is:
PotassiumSodiumCalciumMagnesiumAluminiumZincIronCopperSilverGoldWe are unable to estimate the reactivity of potassium, sodium, calcium, copper, silver, or gold from this experiment because those variables are not present in the data.
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Can someone please help me with chemistry?
Show steps! Thank you
Answers
a. The mass of Cr2O3 is 0.559 g Cr2O3 is the maximum amount of Cr2O3 produced.
b.The limiting reactant is Cr(NO3)3 because it produces less moles of Cr2O3 than Na2O.
c. The percent yield is 84%.
How do we calculate?The balanced equation is shown below:
2 Cr(NO3)3 + 3 Na2O → Cr2O3 + 6 NaNO3
moles of Cr(NO3)3 = 1.75 g / 238.01 g/mol = 0.00735 mol
moles of Na2O = 1.75 g / 61.98 g/mol = 0.0282 mol
moles of Cr2O3 = (0.00735 mol Cr(NO3)3) × (1 mol Cr2O3 / 2 mol Cr(NO3)3) = 0.00368 mol Cr2O3 (theoretical yield)
mass of Cr2O3 = (0.00368 mol Cr2O3) × (151.99 g/mol) = 0.559 g Cr2O3
The percent yield can be calculated by dividing the actual yield by the theoretical yield and multiplying by 100%:
percent yield = (actual yield / theoretical yield) × 100%
percent yield = (0.455 g / 0.559 g) × 100% = 81.4%
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what is the pH of a solution prepared.by dissolving 4.0 g of HCL in water to make 475mL of a solution
Answers
To find the pH of the solution, we need to first calculate the concentration of H+ ions in the solution using the following equation:
[H+] = (moles of HCl) / (volume of solution in liters)
First, let's convert the mass of HCl to moles:
moles of HCl = mass / molar mass = 4.0 g / 36.46 g/mol = 0.1096 moles
Next, let's convert the volume to liters:
475 mL = 0.475 L
Now we can calculate the concentration of H+ ions:
[H+] = 0.1096 moles / 0.475 L = 0.2306 M
Finally, we can calculate the pH using the equation:
pH = -log[H+]
pH = -log(0.2306) = 0.637
Therefore, the pH of the solution is approximately 0.637.
ichiometry in space
A typical space shuttle crew consists of six individuals and
each CCC contains 750 g of LIOH. Assuming that each crew
member expels 42.0 g of CO₂ per hour on average, and that
a mission is scheduled to last 18 days, how many CCCS must
be carried on board the space
shuttle?
- By knowing the recipe (balanced chemical equation), and
some molar masses, I can calculate this answer.
Answers
We need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.
What is the amount of CO2 absorbed?To solve this problem, we need to use the following information:
Each crew member expels 42.0 g of CO2 per hour.The mission is scheduled to last 18 days.There are 6 crew members on board.Each CCC contains 750 g of LIOH.First, we need to calculate the total amount of CO2 that will be expelled during the mission:
Total CO2 = 6 crew members x 42.0 g CO2/hour x 24 hours/day x 18 days = 136,080 g CO2
Next, we need to calculate the amount of LIOH needed to absorb this CO2. The balanced chemical equation for the reaction between CO2 and LIOH is:
CO2 + 2 LIOH → Li2CO3 + H2O
The molar mass of CO2 is 44.01 g/mol, and the molar mass of LIOH is 23.95 g/mol.
This means that 2 moles of LIOH are needed to absorb 1 mole of CO2.
So, to absorb 136,080 g of CO2, we need:
136,080 g CO2 x (1 mol CO2/44.01 g) x (2 mol LIOH/1 mol CO2) x (23.95 g LIOH/1 mol) = 139,648 g LIOH
Since each CCC contains 750 g of LIOH, we need:
139,648 g LIOH / 750 g CCC = 186.2 CCCs
Therefore, we need to carry at least 187 CCCs on board the space shuttle to absorb all the CO2 produced by the crew during the 18-day mission.
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How are models used in chemistry? How does evidence change these models?
Answers
Answer: As they develop theories, chemists use models to attempt to explain their findings. Chemists assess the model they are using as new evidence becomes available and, if required, continue to refine it by making modifications.
Explanation:
Calculate the energy difference (deltaE, in Joules) of an electron's transition from n = 6 to n = 1 in a hydrogen atom.
Answers
The energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom is approximately -2.17 × 10⁻¹⁸ Joules.
To calculate the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom, we can use the following equation:
deltaE = -13.6 * (1/n_final^2 - 1/n_initial^2) eV
where n_initial is the initial energy level (6 in this case), n_final is the final energy level (1 in this case), and -13.6 eV is the ionization energy of hydrogen.
Converting eV to Joules, we get:
1 eV = 1.602 x 10^-19 J
Therefore, deltaE in Joules can be calculated as follows:
deltaE = -13.6 * (1/1^2 - 1/6^2) * 1.602 x 10^-19 J/eV
deltaE = -2.179 x 10^-18 J
Therefore, the energy difference (deltaE) of an electron's transition from n = 6 to n = 1 in a hydrogen atom is -2.179 x 10^-18 J.
To calculate the energy difference (ΔE) for an electron's transition from n = 6 to n = 1 in a hydrogen atom, you can use the following formula:
ΔE = -13.6 eV * (1/nf² - 1/ni²)
Where ΔE is the energy difference in electron volts (eV), nf is the final energy level (1 in this case), and ni is the initial energy level (6 in this case).
ΔE = -13.6 eV * (1/1² - 1/6²)
ΔE ≈ -13.56 eV
Now convert electron volts to Joules:
1 eV = 1.6 × 10⁻¹⁹ J
ΔE ≈ -13.56 eV * 1.6 × 10⁻¹⁹ J/eV
ΔE ≈ -2.17 × 10⁻¹⁸ J
So, approximately -2.17 × 10⁻¹⁸ Joules is the energy difference of an electron's transition from n = 6 to n = 1 in a hydrogen atom.
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A 250.0-mL flask contains 0.2500 g of a volatile oxide of nitrogen. The pressure in the flask is 760.0 mmHg at 17.00°C. How many moles of gas are in the flask?
Answers
Answer:
0.0104 moles of gas in the flask.
Explanation:
To calculate the number of moles of gas in the flask, you can use the ideal gas law equation: PV = nRT. Where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant and T is temperature.
First, you need to convert the pressure from mmHg to atm and the temperature from Celsius to Kelvin. The pressure in atm is 760.0 mmHg / 760 mmHg/atm = 1 atm. The temperature in Kelvin is 17.00°C + 273.15 = 290.15 K.
Next, you need to convert the volume from mL to L. The volume in L is 250.0 mL / 1000 mL/L = 0.2500 L.
Now you can plug all the values into the ideal gas law equation and solve for n: (1 atm)(0.2500 L) = n(0.08206 L·atm/mol·K)(290.15 K). Solving for n gives n = 0.0104 mol.
So there are approximately 0.0104 moles of gas in the flask.
A 0.4856 g sample of solid silver oxide is heated. Find the volume of O2 that can be released at STP.
Answers
The volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.
To solve this problem
Creating the balanced chemical equation for the breakdown of silver oxide is the first step in tackling this issue:
2Ag2O(s) → 4Ag(s) + O2(g)
We can deduce from the equation that 2 moles of AgO will result in 1 mole of O2. Since Ag2O has a molar mass of 231.735 g/mol, 0.4856 g of Ag2O is equivalent to:
0.4856 g Ag2O x (1 mol Ag2O/231.735 g Ag2O) = 0.002095 mol Ag2O
Therefore, the number of moles of O2 that can be produced from 0.4856 g of Ag2O is:
0.002095 mol Ag2O x (1 mol O2/2 mol Ag2O) = 0.0010475 mol O2
1 mole of any gas takes up 22.4 L of space at STP As a result, 0.4856 g of Ag2O can generate the following amount of O2 at STP:
0.0010475 mol O2 x 22.4 L/mol = 0.02345 L or 23.45 mL
Therefore, the volume of O2 that can be released at STP from the given sample of silver oxide is 23.45 mL.
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Benzoic acid (C6H5COOH) and aniline (C6H5NH2) are both derivatives of benzene. Benzoic acid is an acid with Ka=6.3×10^(−5) and aniline is a base with Kb=4.3×10^(−10) .What is the value of the equilibrium constant for the following equilibrium? C6H5COOH(aq)+C6H5NH2(aq)⇌C6H5COO−(aq)+C6H5NH3+(aq)
i want an accurate answer
Answers
The reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) has an equilibrium constant of 0.3698.
How to determine equilibrium constant?The equilibrium constant (Kb) for the reaction can be calculated using the Ka and Kb values of the reactants and the equation:
Kw = Ka x Kb
where Kw = ion product constant of water (1.0 x 10⁻¹⁴ at 25°C).
Calculate the Kb value for aniline:
Kb = Kw/Ka = (1.0 x 10⁻¹⁴)/(4.3 x 10⁻¹⁰) = 2.33 x 10⁻⁵
Use the Kb value for aniline and the Ka value for benzoic acid to calculate the equilibrium constant (K) for the reaction:
K = Kb/Ka = (2.33 x 10⁻⁵)/(6.3 x 10⁻⁵) = 0.3698
Therefore, the equilibrium constant for the reaction C₆H₅COOH(aq) + C₆H₅NH₂(aq) ⇌ C₆H₅COO⁻(aq) + C₆H₅NH₃⁺(aq) is 0.3698.
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How many grams of KOH are needed to make 185.5 ml with a concentration of 5 M?
Type your answer...
Answers
To calculate the mass of KOH needed to make a 5 M solution in 185.5 mL, we need to use the formula:
mass = moles × molar mass
where moles is the amount of KOH in moles and molar mass is the mass of one mole of KOH.
We can calculate the moles of KOH as follows:
moles = Molarity × Volume (in liters)
First, we need to convert the volume from milliliters to liters:
185.5 mL = 0.1855 L
Now we can calculate the moles of KOH:
moles = 5 M × 0.1855 L = 0.9275 moles
The molar mass of KOH is 56.11 g/mol. Therefore, the mass of KOH needed is:
mass = 0.9275 moles × 56.11 g/mol = 52.05 g
Therefore, 52.05 grams of KOH are needed to make a 5 M solution in 185.5 mL.
What mass (grams) of silver oxide would you need to decompose in order to produce 120.6 grams of silver?
Ag2O --> Ag + O2
Answers
The mass of silver oxide needed to decompose in order to produce 120.6 grams of silver is 494.5 grams.
The balanced chemical equation for silver oxide breakdown is:
[tex]Ag_2O[/tex] → [tex]2 Ag[/tex] + [tex]1/2 O_2[/tex]
The equation shows that for every mole of silver oxide that decomposes, two moles of silver are created, and the molar mass of [tex]Ag_2O[/tex] is 231.74 g/mol.
Hence, using stoichiometry, we can calculate the quantity of silver oxide necessary to generate 120.6 grams of silver:
120.6 g Ag × (1 mol Ag / 107.87 g Ag) × (1 mol [tex]Ag_2O[/tex]/ 2 mol Ag) × (231.74 g [tex]Ag_2O[/tex] / 1 mol [tex]Ag_2O[/tex] )
= 494.5 g [tex]Ag_2O[/tex]
As a result, 494.5 grams of silver oxide is needed to decompose in order to produce 120.6 grams of silver.
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Pleas help thanks!!!!!!!!!!!!!!!!!!!!
Answers
The number of molecules of BF₃ present in 2 grams of BF₃ is 1.776×10²² molecules (1st option)
How do i determine the number of molecules of BF₃?
We'll begin by calculating the number of mole of 2 grams of BF₃. Details below:
Mass of BF₃ = 2 grams Molar mass of BF₃ = 67.81 g/molMole of BF₃ =?Mole = mass / molar mass
Mole of BF₃ = 2 / 67.81
Mole of BF₃ = 0.02949 mole
Finally, we shall determine the number of molecules of BF₃. This is shown below:
Avogadro's hypothesis suggest that:
1 mole of BF₃ = 6.022×10²³ molecules
Therefore,
0.02949 mole of BF₃ = 0.02949 × 6.02×10²³
0.02949 mole of BF₃ = 1.776×10²² molecules
Thus, the number of molecules of BF₃ is 1.776×10²² molecules (1st option)
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A sphere has a diameter of 16 m. What is the volume of the sphere?
Answers
Answer:
V ≈ 2144.66 m³
Explanation:
Volume of sphere formula is:
V = 4/3 πr³
Radius is half the diameter so we divide the given diameter, 16 by 2 to get 8, the radius. Now we can solve
V = 4/3 π (8)³
V = 4/3 (512π)
V = 2048/3 π
V ≈ 2144.66 m³
Answer:
4/3 x π
Explanation:
Suppose 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter. The final temperature of the water and copper calorimeter is 18.0C.
1) What was the initial common temperature of the water and copper? (Express your answer to three significant figures.)
Answers
The intital common temperature of copper and water is 9.5°C, under the condition that 10.0 g of ice at -10.0C is placed into 300.0 g of water in a 200.0-g copper calorimeter.
Now to evaluate the initial common temperature of the water and copper calorimeter, we have to apply the formula
m1c1(Tk - Ti) + m2c2(Tk - Ti)
= mcopperccopper(Tk - Ti)
Here,
m1 = mass of water,
c1 =specific heat capacity of water,
m2 = mass of copper calorimeter,
c2 = specific heat capacity of copper calorimeter, mcopper = mass of copper block
ccopper =specific heat capacity of copper.
Here, this equation to evaluate Ti
Ti = (m1c1Tk + m2c2Tk - mcopperccopperTk - m1c1Ti - m2c2Ti) / (m1c1 + m2c2 - mcopperccopper)
Staging the given values into this equation
Ti = (-300.0 g)(4.18 J/g°C)(18.0°C) + (200.0 g)(0.385 J/g°C)(18.0°C) + (10.0 g)(0.385 J/g°C)(18.0°C) / [(300.0 g)(4.18 J/g°C) + (200.0 g)(0.385 J/g°C) - (10.0 g)(0.385 J/g°C)]
Ti = 9.5°C
Hence, the initial common temperature of the water and copper calorimeter was 9.5°C.
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bromsted-lowry acids and bases
find out the acids and bases
Answers
Johannes Brsted and Thomas M. Lowry, two chemists, identified the Bromsted-Lowry acids and bases as a particular kind of acid-base reaction in 1923.
Acids are substances that give a base a proton (H+), whereas bases are substances that take a proton from an acid. In a Bromsted-Lowry acid-base reaction, the acid gives the base a proton in order to create the conjugate base and the conjugate acid, two new compounds.
Nitric acid (HNO3), sulfuric acid (H2SO4), and hydrochloric acid (HCl) are a few examples of acids. Sodium hydroxide (NaOH), ammonium hydroxide (NH4OH), and potassium hydroxide (KOH) are a few examples of bases.
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17. An artist took two photographs of the Moon that were several days apart. Images that look like his photographs are shown above. The light part of the Moon appeared to get smaller over time. Why did this happen?
Answers
According to the information, we can infer that the difference between photographs 1 and 2 originate from the translation of the Moon around the earth (option C).
How do we explain the differences between the two images?To explain the difference between both images we must take into account the movement patterns of the earth and the moon. In the case of the earth, it has 2 main movements, which are rotation on its own axis and translation around the sun.
On the other hand, the moon has a translational movement around the earth, which is what causes the different lunar phases. This motion causes the moon to appear partially shadowed from the earth because the earth blocks the sunlight.
Based on the above, we can infer that the correct answer is option C because this phenomenon is caused by the translation of the moon.
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For the Li2 molecule, rank order the following orbitals from lowest to highest energy: 1s, 2s, σ2s, σ*2s
Answers
The order of the energy levels for the Li2 molecule is:
1s < σ2s < 2s < σ*2s
The 1s orbital is the lowest in energy because it is closest to the nucleus and has the highest electron density. The σ2s orbital is next in energy because it is a bonding orbital that is formed by the overlap of two atomic 2s orbitals. The 2s orbital is higher in energy than the σ2s orbital because it is an atomic orbital that has not participated in bonding. The σ*2s orbital is the highest in energy because it is an antibonding orbital that weakens the bond between the two Li atoms.
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What mass of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP
according to the following equation?
S8 (s) + 8 O2 (g) −→ 8 SO2 (g)
Answer in units of g.
Answers
A mass of 37.0 g of sulfur must be used to produce 25.7 L of gaseous sulfur dioxide at STP.
What is the reactant mass of the sulfur?The molar ratio of S₈ to SO₂ is 1:8.
At STP, one mole of gas occupies 22.4 L. Therefore, 25.7 L of SO₂ gas will contain;
25.7 L / 22.4 L/mol = 1.15 mol of SO₂.
The number of moles of S₈ needed is calculated as;
= 1.15 mol SO₂ / 8 mol S₈ per 1 mol SO₂
= 0.144 mol S₈.
The mass of S₈ needed is calculated as;
0.144 mol S₈ × 256.6 g/mol = 37.0 g of S₈.
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please help me with this lab i wasn’t here for!
3. now that you have the mass of the NaHCO3 reactant, and the mass of the product NaCI , convert each to moles and compare to the mole ratio from your balanced equation C space below for your calculations
mass NaHCO3:
mass NaCI:
moles NaHCO3:
moles NaCI:
does the mole to mole ratio for your reaction? Agree with the ratio for the balanced equation?___
4. which reactant is the excess reactant for your reaction, how do you know?
5. Using the limiting reactant calculate the maximum amount of product that can be made from this reaction.
6. using the theoretical yield in the mass of the product that you put produce calculate percent yield.
calculations:
question #3: converting mass to moles
question #5: calculating the theoretical yield
question #6: calculating percent yield
Answers
Question #3: 0.8 g of NaHCO3 mass NaCI weight: 0.4 g 0.8 g/84 g/mol, or 0.0095 moles, of NaHCO3 0.4 g/58.5 g/mol = 0.0068 moles of NaCI are the moles.
The reaction's mole to mole ratio and the ratio in the balanced equation (1:1) are in agreement. The highest quantity of NaCI that may be produced from this reaction is 0.0095 moles since NaHCO3 is the limiting reactant.
The theoretical yield of NaCI is 0.0095 moles, which is question #6. The finished product weighs 0.4 g. The percent yield is 0.4 g/0.0095 moles times 100, which is 42.1%.
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aHow does the electronic configuration of a sodium cation differ from that of a sodium atom?
Answers
Answer:
Atomic number of sodium is 11
Electronic configuration of a sodium atom :
1s² 2s² 2p⁶ 3s¹Since sodium has one electron in its outermost shell, Therefore, sodium can easily donate it's one electron. As the result it becomes sodium cation with + 1 charge.
Electronic configuration of a sodium cation,[tex] \: \sf ({Na}^{+1}) [/tex]
1s² 2s² 2p⁶In case of sodium cation, it has fully filled electronic configuration.
Cations - Atoms that carry postive charge are called cations. Cations are formed when an atom loses its electron.
For example : [tex]\sf {Na}^{+} [/tex]
Anions - Atoms that carry negative charge are called anions. Anions are formed when an atom gains a electron.
For example : [tex]\sf {Cl}^{-} [/tex]
What is volume of 12.0 g of carbon dioxide at stp?
Answers
Answer: 6.11 L
Explanation:
STP= 1atm, 273.15K
Molar mass of CO2=44.01g/mol so n= (12.0/44.01)
PV=nRT
V=(nRT)/P
V=((12.0/44.01)(0.0821)(273.15))/1
V=6.11L
If the reaction A (aq) + B (aq) C(aq) has a Ka value equal to 4.26 x 10-6, what is the G value at 25 °C if the concentrations are as follows:
[A] = 1.50 M
[B] = 1.00 M
[C] = 5.00 x 10-5 M
Answers
The ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.
The relationship between ΔG and K is given by the following equation:
ΔG = -RTln(K)
where R is the gas constant (8.314 J/(mol·K)), T is the temperature in Kelvin (25 °C = 298.15 K), and ln denotes the natural logarithm.
To calculate K, we need to use the equilibrium expression and the given concentrations:
[tex]K = [C]/([A][B])[/tex]
[tex]K = (5.00 * 10^{-5} M)/((1.50 M)(1.00 M))[/tex]
[tex]K = 3.33 x 10^{-5}[/tex]
Now we can substitute the values for R, T, and K into the equation for ΔG:
ΔG = -RTln(K)
ΔG = [tex]-(8.314 J/(mol.K))(298.15 K)ln(3.33 x 10^{-5})[/tex]
ΔG = -8.35 kJ/mol
Therefore, the ΔG value for the reaction A (aq) + B (aq) → C(aq) at 25 °C and the given concentrations is -8.35 kJ/mol.
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If 12.5 mol
of an ideal gas occupies 50.5 L
at 69.00 ∘C,
what is the pressure of the gas?
Answers
The pressure of a gas that occupies 50.5L at 69.0°C is 6.95 atm.
How to calculate pressure?The pressure of an ideal gas can be calculated using Avogadro's equation as follows;
PV = nRT
Where;
P = pressureV = volume n = no of molesT = temperatureR = gas law constantAccording to this question, 12.5 mol of an ideal gas occupies 50.5 L at 69.00°C. The pressure can be calculated as follows:
P × 50.5 = 12.5 × 0.0821 × 342
50.5P = 350.9775
P = 6.95 atm
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