Please help Thanks
there is a FRACTION symbol two variable symbols y and x

Step-by-step explanation:

step A is incorrect.

-40/5 does not equal to -40/-5.

-40/-5 is equal to 40/5 as we can simplify the negative 1 out.

Answer:

The correct answer is step A

Answer:

23.375 in^2

Step-by-step explanation:

To find the area of a rectangle or square, you need to multiple the length by the width.

The length: 8.5

Width: 11

8.5*11 = 93.5

Now we divide by 4

93.5/4

23.375

Answer: x=3

Step-by-step explanation:

shaded part is 5/6 of the full circle, so just make an equation.

5/6 pi r^2(formula to find area)=15/2 pi(area given)

cancel out pi and simplify

r^2=9

r=+-3 but cant be negative so r=3

The actual rocket height is 1080 inches and the height of the actual rocket is 90 feet.

If the 1/20 scale model of the rocket stands 54 inches high, we can find the height of the actual rocket by multiplying the height of the model by 20:

Actual rocket height = 54 inches x 20 = 1080 inches

In order to convert inches to feet, we divide by 12:

Actual rocket height = 1080 inches / 12 = 90 feet

Therefore, the height of the actual rocket is 90 feet.

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The 1/20 scale model of the rocket stood 54 inches high What was the height of the actual rocket?

(b) Find the height of the actual rocket in feet.

It will take about 711.12 minutes or approximately 11.85 hours to test all 400 units.

To find out how long it will take to test 400 units, we need to use the information given in the problem. We know that the quality expert can test 18 units in 32 minutes. We can use this information to find out how long it will take to test one unit.

First, we need to find out how many units can be tested in one minute:

18 units / 32 minutes = 0.5625 units per minute

This means that the quality expert can test 0.5625 units per minute. To find out how long it will take to test one unit, we can divide 1 by 0.5625:

1 / 0.5625 = 1.7778 minutes per unit

So it takes about 1.7778 minutes to test one unit. To find out how long it will take to test 400 units, we can multiply this value by 400:

1.7778 minutes per unit * 400 units = 711.12 minutes

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The domain of g(x) = log (7x - 10) is all real numbers greater than 10/7.

Set-builder notation: x > 10/7. Interval notation: (10/7,∞)

Given the function in the question:

g(x) = log( 7x - 10 )

For the function g(x) = log (7x - 10), the domain consists of all the possible values of x that can be plugged into the function without resulting in an undefined expression.

Here, the logarithm (in this case, (7x - 10) must be greater than zero, since the logarithm of zero or a negative number is undefined in the real numbers.

So we set the argument of the logarithm to be greater than zero, and solve for x:

7x - 10 > 0

Solve for x

7x - 10 + 10 > 0 + 10

7x > 10

Dividing both sides by 7:

7x/7 > 10/7

x > 10/7

Therefore, the domain of g(x) = log (7x - 10) is x > 10/7

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We have proven that m∠C = m∠A.

We have,

We are given that m∠A + m∠B = m∠B + m∠C.

We want to prove that m∠C = m∠A.

Using algebra,

We can subtract m∠B from both sides of the equation, which gives us m∠A = m∠C.

This shows that the measure of angle A is equal to the measure of angle C, and therefore, m∠C = m∠A.

We can also use the transitive property of equality to show that

m∠A = m∠B, since m∠A + m∠B = m∠B + m∠C, which implies that

m∠A = m∠C.

Therefore,

We have proven that m∠C = m∠A.

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Answer:

The item when it is costs $50 and there is a 55% item, as the cost would be $22.50

Step-by-step explanation:

Whenever a discount is offered on a certain item, we can find the new price of the item using the formula.

[tex]N(P)=O-(P*O)[/tex], where N(P) is the new price (price when discount is applied), P is the percentage (converted to a decimal to simplify the problem), and O is the old price (price before discount is applied)

First store:  Since the item costs $60 (O) at this store and there is a 60% discount (60% becomes 0.60 and is our P value), we can find the new price aka N(P):

[tex]N(0.60)=60-(0.60*60)\\N(0.60)=60-36\\N(0.60)=24[/tex]

Second store:  For this store, our O value is $50, and our P value is 0.55 (55% becomes 0.55):

[tex]N(0.55)=50-(0.55*50)\\N(0.55)=50-27.50\\N(0.55)=22.50[/tex]

Thus, the second store has the better price

C: the number of leaves is multiplied by 2 each week

Step-by-step explanation

The proper expression ought to be 5(2) ^ t =5(2)^{t}

where t speak to the number weeks after it planted.

On the off chance that we put to the time(t) we are going know how numerous clears out at first are. The calculation will be:

5(2)^{t}= 5(2)^{0} =5

This appear that coefficient 5 decide how much the takes off at first are.

Let see how the number going for distinctive esteem of t. On the off chance that its 1 week after plant, the leaf will ended up:

5(2)^{t}= 5(2)^{1} = 10

At that point the number of takes off 2 weeks after planted will be:

5(2)^{t}= 5(2)^{2}= 20

The number keeps twofold each week since coefficient 2 speaks to the proportion of the development of the work and the proportion decides how much takes off duplicated each week.

So, the reply will be C.

The value of t is given as 2.3 years.

we get the table for function as

t          f(t)

8    350

12   138

16   36

20    4

25   3.2

27    1.3

So it is better to model the data by using an exponential model

using a graphing calculator we get our model as

f(t)=a(b)^t

[tex]f(t)=\boldsymbol{3648.6915(0.7380)^t}[/tex]

we have an exponential decay, so we get a rate of decrease as

b=1-r

r=1-b=1-0.738=0.262=26.2\\%

So the number of polio cases is decreasing by 26.2% per year

The number of polio cases in 2014 is

t=2014-1980=34

f(34)=3648.6915(0.7380)^{34}=0.1991389

this is in thousands so we get the number of cases in 2014 approximately as

[tex]0.1191389*1000 \approx \boldsymbol{119} \textup{ cases}[/tex]

for 1 case of polio :

f(t)=0.001

3648.6915(0.738)^t=0.001

we get

[tex]t=\frac{\ln (\frac{0.001}{3648.6915})}{\ln(0.738)}\approx 50[/tex]

so we get year as

1980+50={2030},

to find half life

[tex]\frac{a}{2}=a(b)^t[/tex]

[tex]b^t=\frac{1}{2}[/tex]

[tex]0.738^t=\frac{1}{2}[/tex]

[tex]t=\frac{\ln (1/2)}{\ln (0.738)}\approx\boldsymbol{2.3} \textup{ years}[/tex]

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Answer:

$2,440 + $1,220 = $3,660

Step-by-step explanation:

If Amanda makes $61,000 a year, and she contributes 4% of her salary to her 401(k), that would be:

$61,000 x 0.04 = $2,440

Since her employer has a 50% match on the first 4% of her salary, they would contribute:

$2,440 x 0.5 = $1,220

Answer:

The answer is going to 5

Step-by-step explanation:

I hope this helps you

Answer:

B

Step-by-step explanation:

Vertex form is: y=a(x-h)²+k

Vertex would be (h,k)

Based on this, the only equation in vertex form is B

Answer:

Step-by-step explanation:

B is the easiest way to see vertex because that is the vertex form:

y=a(x-h)²+k     where (h,k) is the vertex

Vertex (2, 27)

The solutions for the system of equations " 3x²-2y²+5=0 and 2x²-y²+2=0" are :

First Solution : x = 1, y = 2

Second Solution : x = 1, y = -2

Third Solution : x = -1, y = 2

Fourth Solution : x = -1 , y = 2.

In order to solve the system of equations 3x²-2y²+5=0 and 2x²-y²+2=0, we use substitution method;

From the second equation, we solve for y² in terms of x²:

The second equation is : 2x² - y² + 2 = 0;

We get, y² = 2x² + 2

Substitute this expression for y² into the first equation:

We get,

3x² - 2(2x² + 2) + 5 = 0

3x² - 4x² - 4 + 5 = 0

-x² + 1 = 0

x² = 1

We get, x = ±1

Substitute these values of x into the equation for y²:

y² = 2x² + 2

For x = 1, y² = 4,

Which means the solution set is (1,2) and (1,-2),

For x = -1, y² = 4

the solution set is (-1,2) and (-1,-2).

Therefore, the solutions to the system of equations are (1, 2), (1,-2), (-1,2) and (-1, 2).

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Answer:

Step-by-step explanation:

no

The perimeter of the given triangle is 12.4x-8.0y+5.8z. Therefore, option C is the correct answer.

Given that, triangle has sides of lengths of (6.2x-9.4y) centimeters, (6.2x-2.5z) centimeters and (8.3z+1.4y) centimeters.

We know that, perimeter of triangle is sum of all the sides.

Now, perimeter = 6.2x-9.4y+6.2x-2.5z+8.3z+1.4y

= (6.2x+6.2x)+(-9.4y+1.4y)+(-2.5z+8.3z)

= 12.4x-8.0y+5.8z

Therefore, option C is the correct answer.

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The likelihood that he or she has a pet given that a student does not have a sibling is 60%. Therefore, the correct option is option D.

Let A denote the event that a student does not have a sibling.

Let B denote the event that a student has a pet.

Then A∩B will denote the event that the student does not have a sibling but he has a pet.

Let P denote the probability of an event in this question.

Then, we have to find the conditional probability of event B which means the likelihood of event B occurring based on the occurrence of event A.

P(B|A)

We know that:

[tex]P(B|A) = \frac{P(A\cap B)}{P(A)}[/tex]

Also from the table, we have:

P(A)=0.25

and P(A∩B)=0.15

Hence,

[tex]P(B|A) = \frac{0.15}{0.25}[/tex]

[tex]P(B|A) = \frac{3}{5}[/tex]

[tex]P(B|A) = 0.6[/tex]

which in percentage is:

0.6 * 100 = 60 %

Therefore, the likelihood that he or she has a pet too is 60% and the correct option is option D.

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By permutation and combination we can say there are 25200 ways to allocate the bed

Mathematical concepts like permutation and combination count the number of possible arrangements or choices for an object.

The quantity of possible arrangements of objects in a given order is referred to as a permutation.

Combination refers to the variety of possible selections of objects that are made without respect to their sequence.

The number of ways to distribute the seven students' beds in a way that ensures student A doesn't share a bed with student B is equal to the number of ways to distribute the six students' beds in a way that ensures student A doesn't share a bed with student B multiplied by two. (since there are two possible positions for student B).

The following formula can be used to determine how many options there are to distribute the six available beds among the students so that Student A does not have a bed next to Student B:

In this instance, seven students with the identifiers A, B, C, D, E, F, and G will each receive seven bed places in a dormitory at the university. Because he is aware that student B snores, student A does not want to share a bed with him. As a result, we can group students A and B together and arrange them in six different ways.

Then we can arrange the remaining students C, D, E, F and G in 5! ways. Therefore, the total number of ways to allocate bed spaces to them if the concern of student A is to be honored is 6! * 5! = 17,280 .

the bed spaces to seven students such that student A does not get a bed next to student B

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Answer:

A

Step-by-step explanation:

We have 20 marbles in the bag. The probability of a marble that is not green is 20/20.

So the probability of the randomly that the marble is not green is 20/20 or just 20.

For the given function 'g':

domain = (-4, -2) ∪ (1, 3]

range = (-5, 4]

If the function is defined as f(x) = y, then the values of x for which the value of function exists, the set of that values is said to be the domain of the function f.

If the function is defined as f(x) = y, then the set of all possible values of the function that is the set of all possible values of y is said to be the range of the function f.

Here given the graph of 'g'.

From the graph we can see that for -4 < x < -2 and 1 < x [tex]\le[/tex] 3 the function has graph.

So the domain = (-4, -2) ∪ (1, 3]

And it is clear that the value of y lies between -5 < y [tex]\le[/tex] 4.

So the range = (-5, 4].

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The dilation of the object is given by the coordinates:

(-6,-8)
(-2, 0)
(-2, -8)

A dilation is a function f from a metric space M into itself that fulfills the identity d=rd for all locations x, y in M, where d is the distance between x and y and r is some positive real integer.

For the first dilation

Original points are

(2,1)

(4,5)

(4,1)

Multiply by scale factor

(2,1) x 2 = (4,2)

(4,5) x 2 = (8, 10)

(4,1) x 2 = (8, 2)

This given us the coordinates of triangle B).

For the second dilation

(2,1)  

(4,5)

(4,1)
Adjust for the center of dilation which is (5,5)

(2,1)  less (5,5) = (-3, -4)

(4,5) less (5,5) = (-1, 0)

(4,1) less (5,5) =(-1, -4)

Multiply the New original point by scale factor

(-3, -4) x 2 = (-6,-8)
(-1, 0) x 2 = (-2, 0)

(-1, -4) x 2 = (-2, -8)

Thus, the new coordinates of the dilated triangle C are:

(-6,-8)
(-2, 0)
(-2, -8).

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Using the property of proportionality for the equation (6-x) : (7-x) :: (18-x) : (22-x), then, x = ⁶/₇.

Solving this problem by using the property of proportionality, which states that the ratio of the first two terms in a proportion is equal to the ratio of the last two terms. In this case:

(6-x) : (7-x) :: (18-x) : (22-x)

Solving for x, cross-multiply the ratios:

(6-x) x (22-x) = (7-x) x (18-x)

Expanding both sides:

132 - 28x + x² = 126 - 25x + x²

Simplifying, we get:

7x = 6

Therefore, x = ⁶/₇.

Thus, the solution to the proportion is:

(6-x) : (7-x) :: (18-x) : (22-x)

or

⁶/₇ : ¹/₇ :: ¹²/₇ : ¹⁶/₇

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Answer:

24

Step-by-step explanation:

14 + 17 + 21 + 28 +40 / 5

120 / 5

24

It is true that the product of the index [tex](b^9)^3 = b^2^7[/tex]

Indices track asset performance in finance and specify array elements in math and programming; their use varies by subject. Different methods refer to list, vector, or matrix elements. Power law of indices: larger number or letter must match.

This can be expressed mathematically as am+n.

Additionally, there are several Laws of Indices that provide rules for simplifying calculations or expressions involving powers of the same base.

The given question is true or false is [tex](b^9)^3[/tex]= [tex]b^27(b^9)^3[/tex] = [tex](b^9)^3 = b^2^7[/tex]

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a.  There are 4 sample points in the sample space.

a) There are 4 sample points in the sample space.

b) The tree diagram and sample space are:

HH (two heads)

HT (one head, one tail)

TH (one head, one tail)

TT (two tails)

c) The probability that no tails are tossed (two heads) is 1/4 or 0.25.

d) The probability that exactly one tail is tossed (HT or TH) is 1/2 or 0.5.

e) The probability that two tails are tossed is 1/4 or 0.25.

f) The probability that at least one tail is tossed (HT, TH, or TT) is 3/4 or 0.75.

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