please help me, marked as brainest

Answer:

Because there are other elements that get in touch with it. And over time with, evolution, erosion and temperature their particles tend to mix. So what once was very common became mixed over time.

The most common element throughout the Earth’s crust that are rarely found on their own will be "Astatine".

Thus the above answer is correct.

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Answer:

0

Explanation:

as Newton 1st Law said that every object will remain at rest or in uniform motion (constant speed) in a straight line unless compelled to change its state by the action of an external force

Net Force = 0

Answer:

they can be unpredictable until you think it

Explanation:

Answer:

A. primary waves

Explanation:

Answer:

Explanation:

The momentum of an object can be found by using the formula

momentum = mass × velocity

From the question we have

momentum = 2000 × 35

We have the final answer as

Hope this helps you

Horizontal motion is defined as a projectile motion in a horizontal plane depending upon the force acting on it. For a short distance, the vertical and horizontal components of a projectile are perpendicular and independent of each other.

Answer:

A projectile moves along its path with a constant horizontal velocity

Answer:

The net force acting on the object is 0 N

Explanation:

Newton's Second Law of Forces

The net force acting on a body is proportional to the mass of the object and its acceleration.

The net force can be calculated as the sum of all the force vectors in each rectangular coordinate separately.

The image shows a free body diagram where four forces are acting: two in the vertical direction and two in the horizontal direction.

Note the forces in the vertical direction have the same magnitude and opposite directions, thus the net force is zero in that direction.

Since we are given the acceleration a =0, the net force is also 0, thus the horizontal forces should be in equilibrium.

The applied force of Fapp=10 N is compensated by the friction force whose value is, necessarily Fr=10 N in the opposite direction.

The net force acting on the object is 0 N

Answer:

The degree of reflection whether faint or bright you see on the surface of an object is an indication that light particles had hit the surface. Since light is a wave and as part of its characteristics can get reflected. However, the amount of light reflected by a surface is dependent on the smoothness of the surface which can be shiny or dull, it can also be dependent on the nature of the surface which can be glass, water, and so on. So, from the question, you can see a faint reflection on the surface of a shiny plate or cup because of the smoothness of the surface which reflects the lights that hit it from a particular direction at the same angle.

Answer:

The rank of the frequencies from largest to smallest is

The largest frequency of oscillation is given by the string in option D

The second largest frequency of oscillation is given by the string in option B

The third largest frequency of oscillation is given by the string in option A

The smallest frequency of oscillation is given by the string in option C

Explanation:

The given parameters are;

The mass per unit length of all string, m/L = Constant

The tension of all the string, T = Constant

The frequency of oscillation, f, of a string is given as follows;

[tex]f = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L}[/tex]

Where;

T = The tension in the string

m = The mass of the string

L = The length of the string

n = The number of overtones

[tex]Therefore, \ {\sqrt{\dfrac{T}{m/L} } } = Constant \ for \ all \ strings = K[/tex]

For the string in option A, the length, L = 27 cm, n = 3 we have;

[tex]f_A = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 27} = \dfrac{2 \times K}{27} \approx 0.07407 \cdot K[/tex]

For the string in option B, the length, L = 30 cm, n = 4 we have;

[tex]f_B = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 30} = \dfrac{ K}{12} \approx 0.08 \overline 3\cdot K[/tex]

For the string in option C, the length, L = 30 cm, n = 3 we have;

[tex]f_C = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(3 + 1) \times K }{2 \times 30} = \dfrac{K}{15} \approx 0.0 \overline 6 \cdot K[/tex]

For the string in option D, the length, L = 24 cm, n = 4 we have;

[tex]f_D = \dfrac{(n + 1) \times \sqrt{\dfrac{T}{m/L} } }{2 \cdot L} = \dfrac{(4 + 1) \times K }{2 \times 24} = \dfrac{5 \times K}{48} \approx 0.1041 \overline 6 \cdot K[/tex]

Therefore, we have the rank of the frequency of oscillations of th strings from largest to smallest given as follows;

1 ) [tex]f_D[/tex] 2) [tex]f_B[/tex] 3) [tex]f_A[/tex] 4) [tex]f_C[/tex]

The order of the frequencies is  [tex]f_D>f_B>f_A>f_C[/tex]

The frequency of the standing wave in a string tied at both ends is given by:

[tex]f=\frac{nv}{2L}[/tex]

where n is the mode of frequency

v is the velocity of the wave

and L is the length of the string.

Now the velocity of a wave in a string tied at both ends is given by

[tex]v=\sqrt{\frac{T}{\mu}}[/tex]

where T is the tension and μ is the mass per unit length.

Since T and μ are the same for all the strings, velocity [tex]v[/tex] will be the same for all.

Now to find the mode of frequency we can calculate the number of nodes (including the nodes at the ends) in the given figure and subtract by 1. Nodes are the point where the amplitude of the wave is zero.

[tex]f_A=\frac{3v}{2\times27}=\frac{v}{18}\;s^{-1}\\\\f_B=\frac{4v}{2\times30}=\frac{v}{15}\;s^{-1}\\\\f_C=\frac{3v}{2\times30}=\frac{v}{20}\;s^{-1}\\\\f_D=\frac{4v}{2\times24}= \frac{v}{12}\;s^{-1}[/tex]

Hence, [tex]f_D>f_B>f_A>f_C[/tex]

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Answer:

A football flying through the air

Explanation:

when an object has projectile motion it is moving through the air

From the given options, the football flying through the air is the prime example of projectile motion. (option d)

Projectile motion refers to the motion of an object that is launched into the air and moves under the influence of gravity alone. It follows a curved path known as a projectile trajectory. Among the options provided, the example that best represents projectile motion is a football flying through the air.

When a football is kicked or thrown, it experiences an initial force that propels it forward. However, as soon as it leaves the kicker's or thrower's hand or foot, the only force acting on it is gravity. Gravity pulls the football downward, causing it to follow a curved path. The shape of the path depends on the angle at which the football is launched and its initial velocity.

During its flight, the football follows a parabolic trajectory, moving both horizontally and vertically. The horizontal component of its motion remains constant, while the vertical component experiences a downward acceleration due to gravity. This combination of horizontal and vertical motion creates the characteristic curved path of projectile motion.

Therefore, option (d) is correct.

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Answer:

Francium.

I hope it will be useful.

Answer:

553.74≤x≤578.26

Explanation:

The formula for calculating the confidence interval is expressed as

CI = xbar±(z×s/√n)

xbar is the mean = 562

s is the standard deviation = 26.1

n is the sample size = 35

z is the z score at 90% CI = 1.645

Substitute the values into the formula

CI = xbar±(z×s/√n)

CI = 561±(1.645×26.1/√35)

CI = 561±(1.645×4.412)

CI = 561±7.257

CI = {561-7.257, 571+7.257}

CI = {553.74, 578.26}

Hence the 90% confidence interval estimate of the name of the population is 553.74≤x≤578.26

Answer:

The horizontal component of the velocity is 49.85 m/s.

Explanation:

Rectangular Components of a Vector

A 2D vector can be expressed in several forms. The rectangular form gives its two components, one for each axis (x,y). The polar form gives the components as the pair (r,θ) being r the magnitude and θ the angle.

When the magnitude and angle of the vector are given, the rectangular components are calculated as follows:

[tex]v_x=v\cos\theta[/tex]

[tex]v_y=v\sin\theta[/tex]

Where v is the magnitude of the vector and θ is the angle with respect to the x positive direction.

The cart is moving at v=55 m/s at θ=25°, thus:

[tex]v_x=55\cos 25^\circ[/tex]

[tex]v_x=49.85\ m/s[/tex]

The horizontal component of the velocity is 49.85 m/s.

Answer:

4g

I hope it will be useful.

Explanation:

KE = (1/2)*m*v^2

Answer

I think it is 112 havent done this in a while but im pretty sure thats it Good luck

Explanation:

Answer:

The cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Explanation:

From the question given above, the following data were obtained:

Height to which the target is located = 50 m

Initial velocity (u) = 20 m/s

To know whether or not the cannon ball is able to hit the target, we shall determine the maximum height to which the cannon ball attained. This can be obtained as follow:

Initial velocity (u) = 20 m/s

Final velocity (v) = 0 (at maximum height)

Acceleration due to gravity (g) = 10 m/s²

Maximum height (h) =?

v² = u² – 2gh (since the ball is going against gravity)

0² = 20² – (2 × 10 × h)

0 = 400 – 20h

Collect like terms

0 – 400 = – 20h

– 400 = – 20h

Divide both side by – 20

h = – 400 / – 20

h = 20 m

Thus, the the maximum height to which the cannon ball attained is 20 m.

From the calculations made above, we can conclude that the cannon ball was not able to hit the target because the target is located at a height of 50 m whereas the cannon ball was only above to get to a height of 20 m.

Answer:

parasomnia

Explanation:

Answer:

a. 0.199 ms b. 5.03 kHz c. 0.1 mJ

Explanation:

a. The period of oscillation of an L-C circuit is T = 2π√(LC) where L = inductance = 20 mH = 20 × 10⁻³ H and C = capacitance = 0.005 mF = 5 × 10⁻⁶ F.

So, T = 2π√(LC)

= 2π√(20 × 10⁻³ H × 5 × 10⁻⁶ F)

= 2π√(100 × 10⁻¹¹)

= 2π√(10 × 10⁻¹⁰)

= 2π(3.16 × 10⁻⁵)

= 19.87 × 10⁻⁵

= 1.987 × 10⁻⁴ s

= 1.99 × 10⁻⁴ s

= 0.199 × 10⁻³ s

= 0.199 ms

b. frequency , f = 1/T where T = period = 0.199 × 10⁻³ s.

So, f = 1/0.199 × 10⁻³ s

= 5.03 × 10³ Hz

= 5.03 kHz

c. The electromagnetic energy E = 1/2Li² where L = inductance = 20 × 10⁻³ H and i = current = 100 mA = 0.1 A

So, E = 1/2Li²

= 1/2 × 20 × 10⁻³ H × (0.1 A)²

= 0.1 × 10⁻³ J

= 0.1 mJ

Answer: the answer is c

The difference between colloid and emulsion is that a colloid can form when any state of matter (solid, liquid or gas) combine with a liquid whereas an emulsion has two liquid components which are immiscible with each other.

Answer:

wrthfnhdghkyulyf

Explanation:

zdfhdfhghdhddddddddddddddddddddd

Answer:

KE 1025J

[tex] \frac{1}{2} m {v}^{2} \\ [/tex]

Explanation:

[tex] \frac{1}{2} \times 82 \times {5}^{2} [/tex]

1025J

Answer:

x = ~0.1289 m/s^2

Explanation:

We can use one of the kinematic formulas. We see that the equation doesn’t contain the final velocity, so we use the kinematic equation d = v_0t + (1/2)at^2.

Since the train started from rest, the initial velocity, v_0, is 0. Thus, the equation becomes:

d = (1/2)at^2

Note that 5 minutes is 300 seconds and 5.8 km is 5800 m. Substituting the values we are given, we get:

5800 m = (1/2)(x m/s^2)(300 s)^2 = (45000 s^2)(x m/s^2)

Dividing by 45,000 on both sides, we get:

x = ~0.1289 m/s^2

I hope this helps! :)

Answer:

the second one

Explanation:

Particle motion increases when solid particles are added to the system.

Answer:

90.82%digrash silsho

Answer:

when Metallic oxide reacts with water they form metallic hydroxide which are basic in nature

Answer:

I'm gonna say it's D

Explanation:

but when u do the experiment on in u head you'll actually find out that it is actually , indeterminable

Answer:

It's Newton's third law. For every known reaction, there is a equal and opposite reaction.

Explanation:

The mallet which hits the ball with an action force, the ball exerts a reaction force on the mallet as explained by the Newton's third law. Thus, the correct option is 3.

Newton's third law states that for every action (force) in nature there is an equal and opposite force or reaction. An example of third law of motion is that the mallet hits the ball with an action force, then the ball exerts a reaction.

If an object A exerts a force on the object B, then object B must also exert a force of equal magnitude and in the opposite direction back on object A. The law represents a certain symmetry in the nature that the forces always occur in pairs, and one body cannot exert a force on another without experiencing any kind of force itself.

Therefore, the correct option is 3.

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Answer:

R = 0.21 Ω

Explanation:

the formula:

R = r x l/A

R = (44 x 10-⁸ Ωm) x 1.5 / (π x (1 x 10-³ m)²)

R = 6.6 x 10-⁷ / 3.14 x 10-⁶

R = 0.21 Ω

Answer:

I think the the answer is creating and layout and template style     ( C )

Explanation:

I did it before and i was checking my notes and i wrote that down , Hope this Helps :)