Please help me fast!

Answer:

1021

Step-by-step explanation:

1018×103=1018+3=1021

Answer:

A) 750+20P=C

B) No, it will not be $1200.  It will be $1950.  $1200 is only the cost for the people and does not include the room rental.

Step-by-step explanation:

A) 750+20P=C

B) 750+20(60)=C

750+1200=C

1950=C

No, it will not be $1200.  It will be $1950.  $1200 is only the cost for the people and does not include the room rental.

Answer:

a. C = 750 + 20P

b. If Sarah is inviting 60 people to the party,

L.H.S. = 750 + 20 x 60

= 750 + 1200

= 1950 dollars

R.H.S. = 1200

because L.H.S is not equal to R.H.S.

no she is wrong

Answer:

Mean

Step-by-step explanation:

The numbers have a very large range. So you should use the mean(or average) to get more accurate data.

Answer: 1/2, 2/10, and 3/15

Explanation: Let's find 3 fractions that are equivalent to 4/20.

To find 3 fractions that are equivalent to 4/20,

notice that 4/20 is not in lowest terms.

In this situation, let's first rewrite 4/20 so that it's in lowest terms.

To do this, we divide the numerator and denominator by the

greatest common factor of 4 and 20, which is 4, and we have 1/5.

Since 1/5 is equivalent to 4/20, we can use

1/5 to find more equivalent fractions.

If we multiply 1/5 by 2 in both the numerator and

denominator, we get the equivalent fraction 2/10.

If we multiply 1/5 by 3 in both the numerator and

denominator, we get the equivalent fraction 3/15.

So 4/20 is equivalent to 1/5, 2/10, and 3/15.

Note that these are just 3 possible answers.

There are many other fractions that are also equivalent to 4/20.

Answer:

a. Distance = 400 - 200t

b. see attached graph

c. A travelled 180 km, B travelled 220 km, both took 2 hours.

Step-by-step explanation:

Given

distance = 400

A = 90 km/h

B = 110 km/h

A & B drive towards each other

Solutions

a) equation

Let

t = elapsed time in hours,

D(t) = distance between two drivers

D(t) = 400 - (A+B) t  

D(t) = 400 - 200t  ......................(1)

b. graph : for graph, see attached figure.

c. Distance and time

Time:

solve for t with the distance D(t) = 0 using equation (1)

0 = 400 - 200 t

200t = 400

t = 2   hours

distance travelled by A = 2 hours * 90 km/h  = 180 km

distance travelled by B = 2 hours * 110 km/h  = 220 km

Answer: D

Step-by-step explanation:

In every other solution, x gets canceled out, so it has no impact on the equation.  Thus, A, B, and C all have either infinite or no solution, because they have 6x on both sides of the equation.

Further proof:

6x-6=15x+15

Add(6)

6x=15x+21

Subtract(15x)

-9x=21

Divide(-9)

x = -2 3/9

Hope it helps <3

Answer:

d) 6x - 6 = 15x + 15

Step-by-step explanation:

Well let’s solve.

a)

6x - 15 = 6x + 15

Lets use the communicative property which is the moving of numbers.

We can start with -15, so we do +15,

6x = 6x + 30

Then we can do -6x

0 = 30

This is a false statement meaning there is no solution.

b)

6x - 6 = 6x + 15

We can start by doing +6

6x = 6x + 21

-6x

0 = 21

Again, this is a false statement meaning this has no solutions.

c)

6x + 15 = 6x + 15

So we do -15

6x = 6x

If this is the case then there is infinitely many solutions.

d)

6x - 6 = 15x + 15

So we can start by doing +5p6

6x = 15x + 21

Then we can do -15x

-9x = 21

then we can do 21 / -9 which is -2 1/3.

x = -2 1/3

So this has one solution.

Answer:

Color, favorite pet, genre of music

Step-by-step explanation:

Categorical variables are simply statistical variables which are non - numeric, usually employed in characterization and groupings based on a certain number of fixed attributes, categories. In the options atated above, the categorical variables fall under a heading with a limited and fixed attributes such as color, pet and genre of music. However, options such as number of siblings and profit are purely numeric variables which can take up any numeric digits and allow for direct numeric computation. They are called quantitative variables.

Answer:

colors, genre of music, favorite pet

Answer:

[tex]\sum_{n=10}^{15}(n+\frac{3}{n})=\sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}[/tex]

Step-by-step explanation:

Given expression : [tex]\sum_{n=10}^{15}(n+\frac{3}{n})[/tex]

Solving further:

[tex]\sum_{n=10}^{15}(n+\frac{3}{n})[/tex]

[tex]\Rightarrow \sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}[/tex]

So,[tex]\sum_{n=10}^{15}(n+\frac{3}{n})=\sum_{n=10}^{15} n + \sum_{n=10}^{15} \frac{3}{n}[/tex]

So, Option A is true

Hence the given expression is equivalent to Option A

Answer:

a

Step-by-step explanation:

edg 21 ^u^

Answer:

Step-by-step explanation:

Given, Radius ( r ) = 6 units

Area of semi-circle = ?

Now, let's find the area of semi-circle:

[tex] \frac{1}{2} \pi \: {r}^{2} [/tex]

plug the values

[tex] = \frac{1}{2} \times 3.14 \times {6}^{2} [/tex]

Evaluate the power

[tex] = \frac{1}{2} \times 3.14 \times 36[/tex]

Calculate

[tex] = 56.52 \: [/tex] units²

hope this helps...

Best regards!!

Answer:

56.52

Step-by-step explanation:

6^2*3.14=113.04

113.04/2=56.52

For you, I am just going to give a small explanation but not too much

The QUESTION is not well presented

Name the sets of numbers to which the given number belongs.

[tex]\sqrt{25}[/tex]

N represents Natural Numbers

W represents Whole Numbers

Z represents Integers

QR represents Rational Numbers

IR represents Irrational Numbers

Answer:

a. N, W, Z, QR

Step-by-step explanation:

Given

[tex]\sqrt{25}[/tex]

Required

Select the set of number belongs to;

First, the expression needs to be evaluated

[tex]Expression = \sqrt{25}[/tex]

[tex]Expression = \±5[/tex]

Comparing the result of the expression to the given categories;

[tex]\±5[/tex] is a natural number

[tex]\±5[/tex] is a whole number

[tex]\±5[/tex] is an integer

[tex]\±5[/tex]  is rational because it can be expressed as ratios

Since [tex]\±5[/tex] is rational, it can't be irrational;

Hence, the correct option is A.

Answer:

The diameter is 1.

Step-by-step explanation:

The circumference is 3.14 units

C = pi * d

Using 3.14 for pi

3.14 = 3.14 d

Divide each side by 3.14

3.14/3.14 = 3.14 d/ 3.14

1 =d

Answer:

You can try substituting the 1's for different variables (E, D) in the formula , to get answers for each.

Answer:

[tex]\boxed{ \mathrm{y = \ negative \ 3 x + 3}}[/tex]

Step-by-step explanation:

The coordinates are (-6,0) and (-8,6)

Finding slope of the line

Slope = [tex]\frac{rise}{run} = \frac{y2-y1}{x2-x1}[/tex]

Slope = [tex]\frac{6-0}{-8+6}[/tex]

Slope =[tex]\frac{6}{-2}[/tex]

Slope = -3

Parallel lines have equal slopes.

So, the line which is parallel to this line is y = negative 3 x + 3

Answer:

[tex]\boxed{ \mathrm{y = \ negative \ 3 x + 3}}[/tex]

Step-by-step explanation:

The coordinates are given (-6, 0) and (-8, 6)

Find slope of the line.

[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m=\frac{6-0}{-8--6}[/tex]

[tex]m=\frac{6}{-2}[/tex]

[tex]m=-3[/tex]

Parralel lines have same slope.

y = mx + b

m = -3

Answer:

[tex]\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63[/tex]

Step-by-step explanation:

According to the trigonometric ratios in aright triangle :

[tex]\sin x =\dfrac{\text{Side opposite to x}}{\text{Hypotenuse}}\\\\\cos x =\dfrac{\text{Side adjacent to x}}{\text{Hypotenuse}}\\\\\tan x=\dfrac{\sin x}{\cos x}[/tex]

Given:  ΔBCA ~ ΔSTR

Since , corresponding angles of two similar triangles are equal.

So, ∠C = ∠T                            ...(i)    [Middle letter]

In triangle STR

[tex]\sin T=\dfrac{\text{Side opposite to T}}{\text{Hypotenuse}}\\\\=\dfrac{26.4}{30.9}\approx0.85\\\\\cos x =\dfrac{\text{Side adjacent to T}}{\text{Hypotenuse}}\\\\=\dfrac{16.2}{30.9}\approx0.52\\\\\tan T=\dfrac{\sin T}{\cos T}\\\\=\dfrac{0.85}{0.52}\approx1.63[/tex]  ...(ii)

From (i) and (ii), we have

[tex]\sin C\approx0.85\\\\\cos C \approx0.52\\\\\tan C\approx1.63[/tex]

Answer:

b)37.5

Step-by-step explanation:

the ratio 3:2 is the same as 1.5, so you  multiply 1.5 & 25 to get 37.5 units

The required measure of the perimeter of the ΔABC is 37.5 units. Option B is correct.

Given that,
ΔABC is similar to ΔMNO. The scale factor from ΔMNO to ΔABC is 3∕2. If the perimeter of ΔMNO is 25 units, what's the perimeter of ΔABC?

The scale factor is defined as the ratio of the modified change in length to the original length.

Here,
3/2ΔMNO =  ΔABC
The perimeter of the ΔABC = 3/2  The perimeter of the ΔMNO
The perimeter of the ΔABC  = 3 / 2 [25]
The perimeter of the ΔABC  = 37.5

Thus, the required measure of the perimeter of the ΔABC is 37.5 units. Option B is correct.

Learn more about Scale factors here:

https://brainly.com/question/22312172

#SPJ2

Answer:

The amount of nuts is 16 kg and cereal mixture is 44 kg to obtain 60 kg of a mix that will sell for $1.40 per kg

Step-by-step explanation:

Let

x=nuts at $2.50 per kg

y=cereal at $1 per kg

x+y=60 kg (1)

2.50x+y=1.40(60) (2)

From (1)

x=60-y

Substitute x=60-y into (2)

2.50x+y=1.40(60)

2.50(60-y)+y=84

150-2.5y+y=84

-1.5y=84-150

-1.5y=-66

Divide both sides by -1.5

y=44 kg

Substitute y=44 into (1)

x+y=60

x+44=60

x=60-44

=16

x=16 kg

a) The theoretical probability of landing on A or E is 2/5. This is because there are two sections we want to land on (either A or E) out of 5 sections total.

--------------------------

b) The empirical probability of landing on A or E is 3/10, which was reduced from 6/20. This is because there are 4+2 = 6 times we landed on either A or E out of 20 spins total.

--------------------------

c) Due to the nature of random events, the theoretical and empirical probabilities will not match up perfectly (basically every random experience will be different for each person). This is especially true for small sample sizes. However, as you do more spins, you should find that the empirical probabilities will slowly approach the theoretical probability. The theoretical probability is always going to be 2/5 for this problem; while the empirical probabilities will bounce around because of the nature of random chance.

Answer:

Connect every other intersection of an arc and the circle with a segment.

Step-by-step explanation:

Connect every other intersection of an arc and the circle with a segment.

Answer:

a) Connect every other intersection of an arc and the circle with a segment.

b) Connect the intersections of the diameters and the circle with a segment.

c) Connect every intersection of an arc and the circle with a segment.

d) Connect the intersections of the perpendicular bisector and the circle with a segment

HOPE THIS HELPS :)

Answer:

7 classmates

Step-by-step explanation:

The last person in the line is in position 35.

The Maria's leading classmate is in the position 35-23+1 = 13.

So, Maria's classmates are from position 13 to 19 (not including herself), and their number is 19-12 = 7 persons.

ANSWER.  Maria has 7 classmates  (not including herself).

Hope this helps.

Answer:

arithmetic; d = 3; 16.9

Step-by-step explanation:

4.9 - 1.9 = 3

7.9 - 4.9 = 3

10.9 - 7.9 = 3

13.9 - 10.9 = 3

--

13.9 + 3 = 16.9

Answer:

1. Arithmetic 2. 16.9

Step-by-step explanation:

To solve this problem you will need to know the difference between an arithmetic and a geometric.

   An arithmetic is a sequence where a person is adding the same number over and over again so lets say you start with 1 and the common difference (the number being added each time) is 2, the sequence will look something like this 1, 3, 5, 7, 9 and so on.

   A geometric sequence is when the same number is being multiplied over and over again. So lets say that the number we start with is 2 and you are multiplying by three every single time, so you would get a sequence looking like this 2, 6, 18, 54 and so on.

   We can see in the sequence that the number that is being added over and over again is 3 so the first answer is arithmetic.

Now that we know that the sequence is arithmetic and the common difference is 3 we can plug that into the equation and we will see that 13.9 + 3 is 16.9

RQP=ONP

Since R is the midpoint of MQ, then MR and RQ are equal.

Since R is the midpoint of MQ, then P must be the midpoint of NQ

The triangles are congruent and the trapezoid is three or those triangles.

RQR reflected is a triangle inside the trapezoid. The triangles at the left and right of the trapezoid are congruent.

Since all the triangles are the exact same, then they have the same height and same length.

So you connect them without like sliding a triangle up a little bit.

The 4 congruent triangles add up to be a parallelogram.

I don't know if this is what you learned in class or where ever you did learn it but this is my way (not where-I-learned-it-from's way).

Answer:

5

Step-by-step explanation:

When squaring the number 5 (i.e [tex]5^2[/tex] ) the answer is 25. [tex]5^{2}[/tex] is the same thing as 5 times 5. Basically with the square root, you are going backwards, so you are therefore finding the base of it all.

We have a square that has area of 25 square units. The question is: what is the side length? That would be 5 since 5*5 = 25. You would use guess and check if you weren't familiar with square roots. A better option is to use the square root function on the calculator.

Note: the square root undoes the squaring operation

Answer: the answer is b, thank me later

Answer:

The answer is option A

Step-by-step explanation:

The formula is

[tex]a(n + 1) = a(n) + 6[/tex]

a(1) = 11

The second term will be

a( 1 + 1) = a(1) + 6

a(2) = 11 + 6

= 17

The next term will be

a( 2 + 1) = a(2) + 6

a(3) = 17 + 6

= 23

The next term will be

a(3 + 1) = a(3) + 6

a(4) = 23 + 6

= 29

The next term will be

a(4 + 1) = a(4) + 6

a(5) = 29 + 6

= 35

So the sequence is

11 , 17 , 23 , 29 , 35

Hope this helps you

Answer:

  see the attached

Step-by-step explanation:

Step 1.

The sample size is the number of numbers. There are 10 of them.

  n = 10

The mean is the sum of the numbers (1240) divided by the number of them (10).

  [tex]\overline{x}=\dfrac{1240}{10}=124[/tex]

__

Step 2.

It is convenient to let a spreadsheet (or calculator) do the math. Enter the numbers and the formulas shown in the table, and let the spreadsheet do the rest.

  [tex]\sum{(x-\overline{x})^2}=1494[/tex]

The formulas for the sample variance and sample standard deviation are given. Fill in the numbers you have so far and do the indicated calculation.

  [tex]s^2=\dfrac{\sum{(x-\overline{x})^2}}{n-1}=\dfrac{1494}{9}=166\\\\s=\sqrt{166}\approx 12.88[/tex]

Answer:

  D) G

Step-by-step explanation:

E evaluates to 3.8 +0 = 3.8 . . . not an integer

F evaluates to 0 +0.5 = 0.5 . . . not an integer

G evaluates to -8 +0 = -8 . . . an integer

H evaluates to 9/0 = undefined . . . not an integer

__

Expression G evaluates to an integer.

Answer:

C.210

Step-by-step explanation:

360 degrees in a circle. 360-150=210

Answer:

In the year 2019 the number of new cars purchased will reach 15,000.

Step-by-step explanation:

t = 0 corresponds to the number of new cars purchased in 1998. If that is so, we can determine t ( time ) by making our quadratic equation here equal to 15,000 - considering that we want the year the number of cars reaches this value. t here is only the number of years to reach 15,000 cars, so we would have to add that value to 1998, to see the year that the cars will reach 15,000.

The " set up " should look like the following quadratic equation -

20t² + 135t + 3050 = 15,000 - Isolate 0 on one side,

20t² + 135t - 11950 = 0 - From here on let us solve using the quadratic equation formula,

[tex]t=\frac{-135+\sqrt{135^2-4\cdot \:20\left(-11950\right)}}{2\cdot \:20}:\quad \frac{-27+\sqrt{38969}}{8}[/tex],

[tex]t=\frac{-135-\sqrt{135^2-4\cdot \:20\left(-11950\right)}}{2\cdot \:20}:\quad -\frac{27+\sqrt{38969}}{8}[/tex] ... now as you can see we have two solutions, but time can't be negative, and hence our solution is the first one - about 21.3 years. 1998 + 21.3 = ( About ) The year 2019. Therefore, in the year 2019 the number of new cars purchased will reach 15,000.

Answer:

2019

Step-by-step explanation:

first you should change the statement into quadratic equation and replace c with 15000.

c=20t^2+135t+3050.

15000=20t^2+135t+3050

15000-3050=20t^2+135t

11950=20t^2+135t. then write the equation in standard quadratic form.

20t^2+135t-11950=0. after this you got 4 ways of solving the quadratic equation but I am just gone using quadratic formula:

-b+ - √b^2-4ac. a,b and C stand for the

2a. the coefficients

-135+ - √((135)^2-4(20)(-11950))

2(20)

-135+ - √(974225))

)) 40

-135 - 987 or -135+ 987

40. 40

-1122/40. or 852/40

- 28.05 or. 21.3

in this case we have to answer but time cannot be negative we take value 21.3(it is the approximate value)

so we add 21.3 to 1998 to find the year

>>21.3 + 1998 = 2019.3 but we write it as 2019 instead of 2019.3

Answer:

D. The quotient of the coordinates will be a coefficient in the equation.

Step-by-step explanation:

Given a line through (0,0) and (4,7)

the slope of the line is m = (7-0) / (4-0) = 7/4

The equation of the line is

y = mx

Therefore

The quotient of the coordinates will be a coefficient in the equation.

Answer:

D

Step-by-step explanation:

Answer:

x = 1, y = 2, z = 4

Step-by-step explanation:

(x + 4y – z = 5

2(3x – 2y + 2z = 7 )

6x - 4y + 4z = 14

7x + 3z = 19

3(2x – z= -2)

6x - 3z = -6

13x = 13

x = 1

6(1) - 3z = -6

-3z = -12

z = 4

(1) + 4y - 4 = 5

4y = 8

y = 2

Answer:

C

Step-by-step explanation:

Remember that when we have roots (like the square root here), then they can be written as fractional exponents.

Here, we have √2, which is equal to [tex]2^{1/2}[/tex], and we have ∛2, which is equal to [tex]2^{1/3}[/tex]. That means:

(√2)(∛2) = [tex]2^{1/2}*2^{1/3}[/tex]

By property of exponents, when we multiply two exponents with the same base (2 here), we can combine them into one exponent by adding the two powers:

[tex]2^{1/2}*2^{1/3}=2^{1/2+1/3}=2^{3/6+2/6}=2^{5/6}[/tex]

The answer is thus C.

~ an aesthetics lover

Answer:

c

Step-by-step explanation: