Answer:
The confidence interval is [tex]0.20644 < p <0.36984[/tex]
Step-by-step explanation:
From the question we are told that
The sample is n = 118
The confidence level is C = 95 %
The number of people with high blood pressure is k = 34
The proportion of those with high blood pressure is evaluated as
[tex]\r p = \frac{k}{n}[/tex]
substituting values
[tex]\r p = \frac{34}{118}[/tex]
[tex]\r p = 0.288136[/tex]
Given that the confidence level is 95% then the level of significance is evaluated as
[tex]\alpha = 100 -95[/tex]
[tex]\alpha = 5[/tex]%
[tex]\alpha = 0.05[/tex]
Now the critical values of [tex]\frac{\alpha }{2}[/tex] obtained from the normal distribution table is [tex]Z_{\frac{\alpha }{2} } = 1.96[/tex]
The reason we are obtaining values for is because is the area under the normal distribution curve for both the left and right tail where the 95% interval did not cover while is the area under the normal distribution curve for just one tail and we need the value for one tail in order to calculate the confidence interval
Now the margin of error is evaluated as
[tex]MOE = Z_{\frac{\alpha }{2} } * \sqrt{\frac{\r p (1- \r p)}{n} }[/tex]
substituting values
[tex]MOE = 1.96 * \sqrt{\frac{ 0.288136 (1- 0.288136)}{118} }[/tex]
[tex]MOE = 0.0817[/tex]
Thus the 95% confidence interval for the true percentage of all adults that have high blood pressure is evaluated as
[tex]\r p - MOE < p < \r p + MOE[/tex]
substituting values
[tex]0.288136 - 0.0817 < p <0.288136 + 0.0817[/tex]
[tex]0.20644 < p <0.36984[/tex]
Use the cubic model y = 6x3 - 5x2 + 4x – 3 to estimate the value of y when x = 2.
a 25
(b 33
c 48
d 79
Done
Try Again
-
Answer:
The answer is B.
Step-by-step explanation:
You have to substitute x = 2, into the equation of y :
[tex]y = 6 {x}^{3} - 5 {x}^{2} + 4x - 3[/tex]
[tex]let \: x = 2[/tex]
[tex]y = 6 {( 2)}^{3} - 5 {(2)}^{2} + 4(2) - 3[/tex]
[tex]y = 48 - 20 + 8 - 3[/tex]
[tex]y = 33[/tex]
Help with inequality
Answer:
1. x>20 2. x≤1 3.x<4 4.x>9 5.x≥-13
Interpret the standard deviation in this problem.Group of answer choicesWe expect most of the sampled heights to fall within 9.8 inches of their least squares predicted values.We expect most of the sampled heights to fall within 4.9 inches of their least squares predicted values.We expect most of the sampled dad's heights to fall within 4.9 inches of their least squares predicted values.We expect most of the sampled dad's heights to fall within 9.8 inches of their least squares predicted values.
Answer:
Hello some parts of your question is missing below is the missing part
suppose we use a person's dad's height to predict how short or tall the person will be by building a regression model to investigate if a relationship exists between the two variables. Suppose the regression results are as follows:
Least Squares Linear Regression of Height
Predictor
Variables Coefficient Std Error T P
Constant 20.2833 8.70520 2.33 0.0223
DadsHt 0.67499 0.12495 5.40 0.0002
R² 0.2673 Mean Square Error (MSE) 23.9235
Adjusted R² 0.2581 Standard Deviation 4.9000
Answer : We expect most of the sampled heights to fall within 9.8 inches of their least squares predicted values.
Step-by-step explanation:
standard deviation is the statistical measurement of the level at which a dataset disperses from its mean value
interpreting the standard deviation in this problem ,
given that the standard deviation is 4.9 inches, it simply means that the dataset heights will be either +4.9 inches or -4.9 inches away from the mean value. this means that most of the sampled Dad/'s height will fall within 9.8 inches of their least squares predicted values
A bike tire just ran over a nail, and it is losing pressure at a rate of 5% every minute. The tire pressure is currently 1,300 kilopascals. What will it be in 3 minutes? If necessary, round your answer to the nearest tenth.
Answer:
1,114.6 kPa
Step-by-step explanation:
P(t) = 1300 (0.95)^t
P(3) = 1300 (0.95)^3
P(3) = 1114.6
The 3rd degree Taylor polynomial for cos(x) centered at a = π 2 is given by, cos(x) = − (x − π/2) + 1/6 (x − π/2)3 + R3(x). Using this, estimate cos(86°) correct to five decimal places.
Answer:
The cosine of 86º is approximately 0.06976.
Step-by-step explanation:
The third degree Taylor polynomial for the cosine function centered at [tex]a = \frac{\pi}{2}[/tex] is:
[tex]\cos x \approx -\left(x-\frac{\pi}{2} \right)+\frac{1}{6}\cdot \left(x-\frac{\pi}{2} \right)^{3}[/tex]
The value of 86º in radians is:
[tex]86^{\circ} = \frac{86^{\circ}}{180^{\circ}}\times \pi[/tex]
[tex]86^{\circ} = \frac{43}{90}\pi\,rad[/tex]
Then, the cosine of 86º is:
[tex]\cos 86^{\circ} \approx -\left(\frac{43}{90}\pi-\frac{\pi}{2}\right)+\frac{1}{6}\cdot \left(\frac{43}{90}\pi-\frac{\pi}{2}\right)^{3}[/tex]
[tex]\cos 86^{\circ} \approx 0.06976[/tex]
The cosine of 86º is approximately 0.06976.
x/-8 ≥−5 solve for x
Answer:
x ≤ 40
Step-by-step explanation:
x/-8 ≥−5
Multiply each side by -8, remembering to flip the inequality
x/-8 *-8 ≤−5 *-8
x ≤ 40
Answer:
x ≥ 40
Step-by-step explanation:
[tex]\frac{x}{-8} \geq -5[/tex]
x ≥ -5 * -8
x ≥ 40
Check
40 / -8 ≥ -5
a tax of 0.19 dollars is imposed on each baga of potato chips that is sold. the tax generates revenue of approx 10,000 dollars and ddecreases the equilibrium wuantyiy of potato chips by 156 bags per day/ the tax creates a deadweight lsos of how many dollars
Answer:
The tax creates a deadweight loss of $29.64 dollars per day.
Step-by-step explanation:
a) A bag of potato chips generates $0.19 per bag
If 156 bags are not sold each day because of the imposed tax, the deadweight loss is calculated as follows:
156 x $0.19 = $29.64 per day
b) A deadweight loss is the inefficiency cost imposed by the tax because it causes decreases the equilibrium quantity of bags of potato chips sold each day by 156. By dislocating the equilibrium and the market forces, the tax makes the economy to suffer overall. This may imply that the rate of the tax was not economically reasonable. Unless a tax is imposed to discourage an activity or a consumption, the rate should not be so high as to create inefficiencies in the allocation of economic resources.
Select all the correct answers. Which of these pairs of functions are inverse functions?
Answer:
D
Step-by-step explanation:
an inverse function is a function that reverses another function for ex. if f(x)=y and g(y)=x.
Answer:
A and C
Step-by-step explanation:
You work in a machine design department and need to specify the diameter of a pin that slides back and forth through a hole. The hole diameter is specified as 0.500 inch with a tolerance of 0.010 inch. The maximum pun diameter must be 0.002 inch smaller than the minimum hole diameter. If the pin diameter has a tolerance of 0.010 inch what diameter in inches should you specify for the pin?
Answer:
B. 0.478
Step-by-step explanation:
The diameter of the pin is 0.478 inches as per specification.
What are Arithmetic operations?Arithmetic operations can also be specified by the subtract, divide, and multiply built-in functions.
The operator that perform arithmetic operation are called arithmetic operators.
+ Addition operation : Adds values on either side of the operator.
For example 4 + 2 = 6
- Subtraction operation : Subtracts right hand operand from left hand operand.
for example 4 -2 = 2
The hole diameter is specified as 0.500 inches with a tolerance of 0.010 inches.
The maximum pun diameter must be 0.002 inches smaller than the minimum hole diameter.
Diameter: d = 0.500 inch
Tolerance: t = 0.010 inch
Replacing the values:
⇒ dmax = 0.500 - 0.010 - 0.002 - 0.010
Apply the subtraction operation,
⇒ dmax = 0.478 inch
Hence, the diameter of the pin is 0.478 inches as per specification.
Learn more about Arithmetic operations here:
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How does the frequency of f(x) = cos(2x) relate to the frequency of the parent function cos x?
Answer:
The frequency of f(x) is two times the frequency of the parent function.
Step-by-step explanation:
We can say that the number that is beside the x is equal to [tex]2\pi *f[/tex], where f is the frequency.
Then, for the parent function, we get:
[tex]1 = 2\pi f_1[/tex]
or solving for [tex]f_1[/tex]:
[tex]f_1=\frac{1}{2\pi }[/tex]
At the same way, for f(x), we get:
[tex]2=2\pi f_2\\f_2=2(\frac{1}{2\pi })[/tex]
But [tex]\frac{1}{2\pi }[/tex] is equal to [tex]f_1[/tex], so we can write the last equation as:
[tex]f_2=2f_1[/tex]
It means that the frequency of f(x) is two times the frequency of the parent function.
Solve:
3/x -4>0
A.) x<4
B.) x>-4
C.) x>4
D.) x<-4
Answer:
x > 4
Step-by-step explanation:
2. A survey is being conducted of students’ residences. Data is gathered from a random sample of 1000 students. The data is summarized in the table below. Gender and Residence of Students Males Females Apartment off campus 50 90 Dorm room 150 210 With Parent(s) 100 50 Sorority/ Fraternity House 200 150 a) What is the probability that a student is female and lives in a dorm? ____________________ b) What is the probability that a student is female given that she lives in a dorm? __________
Answer:
Gender and Residence of Students
a) What is the probability that a student is female and lives in a dorm?
= 58.33%
b) What is the probability that a student is female given that she lives in a dorm?
= 21%
Step-by-step explanation:
a) Data and Calculations:
Gender and Residence of Students
Males Females Total
Apartment off campus 50 90 140
Dorm room 150 210 360
With Parent(s) 100 50 150
Sorority/ Fraternity House 200 150 350
Total 500 500 1,000
a) Probability that a student is female and lives in a dorm:
= number of females who live in a dorm divided by total number of students who live in a dorm * 100
= 210/360 * 100
= 58.33%
b) Probability that a student is female given that she lives in a dorm
= number of female students who live in a dorm divided by the total number of students * 100
= 210/1,000 * 100
= 21%
A = 100(1+r)^4
Expand the right of this formula.
appreciate your help with an explanation
Answer:
100r^4 + 400r^3 + 600r^2 + 400r + 100
Step-by-step explanation:
Expanding ( r + 1 )^4 gives :-
r^4 + 4r^3 + 6r^2 + 4r + 1
So multiplying 100 with r^4 + 4r^3 + 6r^2 + 4r + 1 gives :-
100r^4 + 400r^3 + 600r^2 + 400r + 100
A study was conducted to measure the effectiveness of hypnotism in reducing pain. The measurements are centimeters on a pain scale before and after hypnosis. Assume that the paired sample data are simple random samples and that the differences have a distribution that is approximately normal. Does hypnotism appear to be effective in reducing pain? In this example, μd is the mean value of the differences d for the population of all pairs of data, where each individual difference d is defined as the difference in the measurements on a pain scale before and after hypnosis. What is the test statistic for this hypothesis test?
Answer:
Step-by-step explanation:
Hello!
This is an example of a pared sample test, the experiment is based on two dependent variables:
X₁: centimeters on a pain scale before hypnosis
X₂: centimeters on a pain scale after hypnosis
Out of these two variables a new variable is determined Xd= X₁-X₂
If the variables have an approximate normal distribution then the variable resulting from their difference will also have an approximate normal distribution.
The claim is that "hypnosis reduced the pain" if so you'd expect the population mean of the difference to be less than zero, symbolically: μd<0
The statistic for this test is a paired sample t test:
[tex]t= \frac{\frac{}{X_d} - Mu_d}{Sd} ~t_{n-1}[/tex]
To calculate the sample mean and variance you have to calculate the difference between the pairs first.
[tex]\frac{}{Xd}[/tex]= ∑Dif/n
[tex]S_d^2= \frac{1}{n-1} [sumDif^2- \frac{(sumDif)^2}{n} ][/tex]
∑Dif= 6.4
∑Dif²= 12.64
[tex]\frac{}{Xd}[/tex]= 6.4/5= 1.28
[tex]S_d^2= \frac{1}{4} [12.64- \frac{(6.4)^2}{5} ]= 1.112[/tex]
Sd= 1.05
[tex]t_{H_0}= \frac{\frac{}{Xd}-Mu_d }{Sd} = \frac{1.28-0}{1.05} = 1.219= 1.22[/tex]
I hope this helps!
Safegate Foods, Inc., is redesigning the checkout lanes in its supermarkets throughout the country and is considering two designs. Tests on customer checkout times conducted in two stores where the two new systems have been installed result in the following summary of the data: System A System B Size 120 100 mean 4.1 minutes 3.4 minutes Standard Deviation 2.2 minutes 1.5 minutes Test at the 0.05 level of significance to determine whether the population mean checkout times of the two systems differ. Which system is preferred?
Use both the critical and p-value approach.
Hypotheses:
Decision rule:
Calculations:
Conclusions:
Answer:
the answer would be calculations
Step-by-step explanation:
because they have do determine if the check out times differ between the two systems so they need to calculate the difference between the two
Which of the following theorems verifies that CRV BYU?
A.
AA
B.
HL
C.
LL
D.
HA
Answer:
LL
Step-by-step explanation:
We have two right triangles
The two legs are congruent
We can use the LL congruence theorem
Solve the given integral equation for LaTeX: y(t)y ( t ). LaTeX: y(t)+9\displaystyle{\int_{0}^{t}e^{9(t-v)}y(v)\, dv}=\sin(3t)y ( t ) + 9 ∫ 0 t e 9 ( t − v ) y ( v ) d v = sin ( 3 t ) Group of answer choices LaTeX: y(t)=3\cos(3t)+9\sin(3t)-9 y ( t ) = 3 cos ( 3 t ) + 9 sin ( 3 t ) − 9 LaTeX: y(t)=3\cos(3t)+\sin(3t)-3 y ( t ) = 3 cos ( 3 t ) + sin ( 3 t ) − 3 LaTeX: y(t)=3\cos(3t)+\sin(3t) y ( t ) = 3 cos ( 3 t ) + sin ( 3 t ) LaTeX: y(t)=3\cos(3t)+9\sin(3t) y ( t ) = 3 cos ( 3 t ) + 9 sin ( 3 t ) LaTeX: y(t)=\cos(3t)+3\sin(3t)-3
Looks like the equation is
[tex]y(t)+9\displaystyle\int_0^te^{9(t-v)}y(v)\,\mathrm dv=\sin(3t)[/tex]
Differentiating both sides yields the linear ODE,
[tex]y'(t)+9e^{9(t-t)}y(t)=3\cos(3t)[/tex]
or
[tex]y'(t)+9y(t)=3\cos(3t)[/tex]
Multiply both sides by the integrating factor [tex]e^{9t}[/tex]:
[tex]e^{9t}y'(t)+9e^{9t}y(t)=3e^{9t}\cos(3t)[/tex]
[tex]\left(e^{9t}y(t)\right)'=3e^{9t}\cos(3t)[/tex]
Integrate both sides, then solve for [tex]y(t)[/tex]:
[tex]e^{9t}y(t)=\dfrac1{10}e^{9t}(\sin(3t)+3\cos(3t))+C[/tex]
[tex]y(t)=\dfrac{\sin(3t)+3\cos(3t)}{10}+Ce^{-9t}[/tex]
The given answer choices all seem to be missing C, so I suspect you left out an initial condition. But we can find one; let [tex]t=0[/tex], then the integral vanishes and we're left with [tex]y(0)=0[/tex]. So
[tex]0=\dfrac{0+3}{10}+C\implies C=-\dfrac3{10}[/tex]
So the particular solution is
[tex]y(t)=\dfrac{\sin(3t)+3\cos(3t)-3e^{-9t}}{10}[/tex]
The length of a rectangle is 7 more than the width. The area is 744 square centimeters. Find the length and width of the rectangle.
Answer:
the width of the rectangle is 24 centimeters and the length is 31 centimeters.
Step-by-step explanation:
We first have to write an equation for this, but let's just recall that the area of a rectangle is equal to the length times the width. A=L×W.
A is the area
L is the length
W is the width.
So, for our equation we can start out by putting that 744= ? times ?.
So, we are given that the length is 7 more than the width. We are going to have to translate that to represent the length.
We need a variable. Let's use the letter "W," the width of the rectangle.
W=W.
The length is 7 more than the width, so it is L=W+7.
Length represents the W+7
Width represents W.
Now, we can complete our equation.
744=W(W+7).
Simplify the expression.
744=[tex]W^{2}[/tex]+7W.
Alright, you may be thinking on how we are going to solve this problem. This equation correlates with quadratic functions.
Let's complete the square.
In a quadratic function, the standard from is y=[tex]ax^{2} +bx+c[/tex].
We need to find the c value.
We can do this by applying a formula. The formula states that c= b/2 and the whole thing squared. In other words, [tex](\frac{b}{2} )^{2}[/tex].
In this case, the b value is 7.
square 7, which is 49 and square 2 which is 4.
Now, the c value is 49/4.
We have now just created a perfect square trinomial.
Not only do we add 49/4 to W squared plus 7W, we also add 49/4 to 744.
744 plus 49/4 is 756/25.
Now, we have [tex]W^{2}+7w+\frac{49}{4} = 756.25[/tex]
Change W squared plus 7w plus 49/4 to a binomial squared.
Just take the square root of the a value, W, and 49/4 for c. the square root of W squared is W. the square root of 49/4 is 7/2.
Those values are to the power of 2.
In other words, [tex](W+\frac{7}{2})^{2} =756.25[/tex]
To isolate for W, take the square root of both sides.The square root of W plus 7/2 squared is just W+7/2. The square root of 756.25 is 27.5
There are two solutions for W because square roots be positive or negative, but we are dealing with positive since negative doesn't make sense with the context of the problem.
We have [tex]W+3.5 or \frac{7}{2}=27.5[/tex]
Isolate for W by subtracting both sides by 3.5 You get to W=24.
Therefore, the width of the rectangle is 24 centimeters.
Alright, we found the width. We now need to find the length. The problem stated that the rectangle was 7 more than the width. So, 24+7=31. Therefore, the length of the rectangle is 31 centimeters.
L=31cm
W=24cm.
I hope this was helpful! I wish you have an amazing day!
17. What is the most likely outcome of decreasing the wavelength of incident light on a diffraction grating? A. lines become narrower B. distance between lines increases C. lines become thicker D. distance between lines decreases
When the wavelength of a diffraction grating is decreased, the distance between lines decreases.
What is a diffraction grating?The diffraction grating is used to carry out interference experiments. It consists of a number of small lines that are constructed to be close to each other and produce an interference pattern.
The outcome of decreasing the wavelength of incident light on a diffraction grating is that the distance between lines decreases.
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HELP PLEASE ANYONE !!!!!
Answer:
B. -3x
Step-by-step explanation:
A term is defined as either a constant or a variable with a coefficient.
-3 is incorrect because there is no constant -3 in the expression.
-3x is correct because there is a -3x in the expression
(x + 4) is incorrect because that is a linear binomial and has yet to be distributed.
-7 is incorrect because it has to be distributed.
find the area under (sin x) bounded by x= 0 and x = 2π and x-axis
You probably want the unsigned area, which means you don't compute the integral
[tex]\displaystyle\int_0^{2\pi}\sin x\,\mathrm dx[/tex]
but rather, the integral of the absolute value,
[tex]\displaystyle\int_0^{2\pi}|\sin x|\,\mathrm dx[/tex]
[tex]\sin x[/tex] is positive when [tex]0<x<\pi[/tex] and negative when [tex]\pi<x<2\pi[/tex], so
[tex]\displaystyle\int_0^{2\pi}|\sin x|\,\mathrm dx=\int_0^\pi\sin x\,\mathrm dx-\int_\pi^{2\pi}\sin x\,\mathrm dx[/tex]
[tex]\displaystyle\int_0^{2\pi}|\sin x|\,\mathrm dx=(-\cos x)\bigg|_0^\pi-(-\cos x)\bigg|_\pi^{2\pi}[/tex]
[tex]\displaystyle\int_0^{2\pi}|\sin x|\,\mathrm dx=\boxed{4}[/tex]
Solve 2x^2 + x - 4 = 0
X2 +
Answer:
[tex]\large \boxed{\sf \ \ x = -\dfrac{\sqrt{33}+1}{4} \ \ or \ \ x = \dfrac{\sqrt{33}-1}{4} \ \ }[/tex]
Step-by-step explanation:
Hello, please find below my work.
[tex]2x^2+x-4=0\\\\\text{*** divide by 2 both sides ***}\\\\x^2+\dfrac{1}{2}x-2=0\\\\\text{*** complete the square ***}\\\\x^2+\dfrac{1}{2}x-2=(x+\dfrac{1}{4})^2-\dfrac{1^2}{4^2}-2=0\\\\\text{*** simplify ***}\\\\(x+\dfrac{1}{4})^2-\dfrac{1+16*2}{16}=(x+\dfrac{1}{4})^2-\dfrac{33}{16}=0[/tex]
[tex]\text{*** add } \dfrac{33}{16} \text{ to both sides ***}\\\\(x+\dfrac{1}{4})^2=\dfrac{33}{16}\\\\\text{**** take the root ***}\\\\x+\dfrac{1}{4}=\pm \dfrac{\sqrt{33}}{4}\\\\\text{*** subtract } \dfrac{1}{4} \text{ from both sides ***}\\\\x = -\dfrac{1}{4} -\dfrac{\sqrt{33}}{4} \ \ or \ \ x = -\dfrac{1}{4} +\dfrac{\sqrt{33}}{4}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
Simplify the rate:
46 cans of Soda / 8 people
Only enter the numeric amount:
Answer: 23 cans of soda/4 people.
or (23/4) cans of soda per person.
Step-by-step explanation:
So we have the rate:
46 cans of soda/ 8 people
First, 46 and 8 are multiples of 2, so we can divide both numerator and denominator by 2:
46/2 = 23
8/2 = 4
Then the rate can be:
23 cans of soda/4 people.
Now 23 is a prime number, so we can not simplify it furthermore
Find the x-value of the removable discontinuity of the function.
Answer:
x=2
Step-by-step explanation:
[tex]f(x)=\frac{x^2-4}{x^2-12x+20}[/tex]
Factor the numerator and denominator:
[tex]f(x)=\frac{(x-2)(x+2)}{(x-2)(x-10)}[/tex]
We can remove (x-2) from the function:
[tex]f(x)=\frac{x+2}{x-10}[/tex]
(x-2) is a removable discontinuity.
The x-value of x-2 is x=2.
Find the value of y.
Answer:
[tex] \sqrt{55} [/tex]Step-by-step explanation:
∆ BCD ~ ∆ DCA
[tex] \frac{bc}{dc} = \frac{dc}{ac} [/tex]
Plug the values:
[tex] \frac{5}{y} = \frac{y}{6 + 5} [/tex]
[tex] \frac{5}{y} = \frac{ y}{11} [/tex]
Apply cross product property
[tex]y \times y = 11 \times 5[/tex]
Calculate the product
[tex] {y}^{2} = 55[/tex]
[tex]y = \sqrt{55} [/tex]
Hope this helps...
Good luck on your assignment..
Can you help me with this.
Answer:
You would basically expand all the equations!
1. 7(4z+8b) is equal to 28z+56b.
2. 8(2x+3^2) is equal to 16x+72
3. 4(r+r+r+r) is equal to 4r+4r+4r+4r
4. 9(3+8x) is equal to 27+72x
5. 4^2(3+6f) is equal to 48+96t
6. (t+t+t)/4 is equal to t/4+t/4+t/4
7. 2(4s^3+2) is equal to 8s^3+4
8. 30(3x+4) is equal to 90x+120
9. 6(5a+9b) is equal to 30a+54b
10. 9(3x+5^4) is equal to 27x+5625
11. 7(c+c+c) is equal to 7c+7c+7c
12. 9(2+7f) is equal to 18+63f
13. 7^5(4g-8d) is equal to 67228g-134456d
Step-by-step explanation:
6. Find x. (2 pt)
48°
X
Answer:
x = 96
Step-by-step explanation:
Inscribed Angle = 1/2 Intercepted Arc
48 = 1/2 ( x)
Multiply by 2
96 = x
Answer:
[tex]\boxed{x=96}[/tex]
Step-by-step explanation:
Apply the inscribed angle theorem, where the measure of an inscribed angle is half the measure of the intercepted arc.
[tex]48=\frac{1}{2}x[/tex]
Multiply both sides by 2.
[tex]48(2)=\frac{1}{2}x(2)[/tex]
[tex]96=x[/tex]
[URGENT] (25 points) Ryan randomly drew a marble out of a bag of marbles, then put it back. He did
this 25 times. Of the 25 times he drew a red marble 6 times. He concluded
that the probability of drawing a red marble was
6/25
Answer:
Unpredictable
Step-by-step explanation:
Cuz if u look at it it is also random and u cant predict a random thing, so its quite simply unpredictable
5.-10. 20.-40.... determine if arithmetic,geometrical or neither
Answer:
It is a geometrical progression
Step-by-step explanation:
Geometric progressions have a constant number that they are multiplied by
To find that number you divide the 2nd term by the 1st term and also the 4th term by the 3rd term. ie,
[tex]\frac{-40}{20} = \frac{-10}{5} \\[/tex]
[tex]-2 = -2[/tex]
since they are both equal it is a G.P
Because they have a constant ratio.
Answer:
Geometric progression.
Step-by-step explanation:
I suppose you mean this equation:
5, -10, 20, -40, ...
For a geometric progression, an n^th term is given by:
[tex]a_{n}[/tex] = [tex]a_{n - 1}[/tex] × r
Where a is the first time, n is the term and r is the common ratio.
The common ratio here is -2 .
For instance to check the forth term;
[tex]a_{4}[/tex] = [tex]5_{4 - 1}[/tex] × -2 = 20 × -2 = -40
Phuong collects Persian and Oriental rugs in a ratio of 3:4. If Phuong has 84 Oriental rugs, how many rugs are in his collection?
Answer:
The answer is
147Step-by-step explanation:
Let the total number of rugs be x
To find the total number of rugs we must first find the total parts which is
3 + 4 = 7
4/7 of the total rugs are 84 Oriental rugs
Which is written as
[tex] \frac{4}{7} x = 84[/tex]
Multiply through by 7
[tex]7 \times \frac{4}{7} x = 84 \times 7[/tex]
Simplify
[tex]4x = 588[/tex]
Divide both sides by 4
[tex] \frac{4x}{4} = \frac{588}{4} \\ \\ \\ \\ x = 147[/tex]
The total number of rugs is 147Hope this helps you