The GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2) is a^(2)b^(2), and the factored form of the polynomial is a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1).
The GCF, or greatest common factor, is the largest factor that all terms in a polynomial have in common. In this case, we need to find the GCF of the polynomial a^(5)b^(7)-a^(3)b^(2)+a^(2)b^(6)-a^(2)b^(2).
First, we need to look at the exponents of each term to determine the GCF. The smallest exponent for a is 2, and the smallest exponent for b is 2. Therefore, the GCF for this polynomial is a^(2)b^(2).
Next, we need to factor out the GCF from each term in the polynomial. This is done by dividing each term by the GCF and then multiplying the GCF by the resulting polynomial.
So, the factored form of the polynomial is:
a^(2)b^(2)(a^(3)b^(5)-a+b^(4)-1)
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Which of the following is the
graph of
(x + 3)² + (y + 1)² = 9?
Algebra please help!!!!
Answer:
x = - 2, y = - 8
Step-by-step explanation:
13x - 6y = 22 → (1)
x = y + 6 → (2)
substitute x = y + 6 into (1)
13(y + 6) - 6y = 22
13y + 78 - 6y = 22
7y + 78 = 22 ( subtract 78 from both sides )
7y = - 56 ( divide both sides by 7 )
y = - 8
substitute y = - 8 into (2)
x = y + 6 = - 8 + 6 = - 2
then x = - 2 and y = - 8
In the diagram below, TU is parallel to
QR. If SU is 6 less than IS, QS = 55,
and SR = 44, find the length of IS.
Figures are not necessarily drawn to scale.
State your answer in simplest radical form, if necessary. In the diagram below, TU is parallel to
QR. If SU is 6 less than TS, QS = 55,
and SR = 44, find the length of TS.
Figures are not necessarily drawn to scale.
State your answer in simplest radical form, if necessary.
Consequently, IS has a 24 length as its length. SR is 44, QS is 55, and SU is 6 shorter than IS.
what is length ?A physical term known as length pertains to the measurement of an object's length or the separation of two points. Ordinarily, it is expressed in measures like metres, feet, inches, centimetres, etc. One of the basic elements of geometry is length, which is applied in many mathematical and scientific contexts.
given
TU and QR are parallel in the illustration below. Find the length of IS if SU is 6 shorter than IS, QS is 55, and SR is 44.
Since TU and QR are parallel, we have:
angle Angle = ISU QSR (matching angles) (corresponding angles)
angle Angle = SUI SRQ (alternate interior views) (alternate interior angles)
Triangles ISU and QSR are therefore comparable (by angle-angle similarity). So, here we are:
SU/QS Equals IS/SR
Inputting the numbers provided yields:
IS/44 = (IS - 6)/55
The result of multiplying both parts by 44*55 is:
55IS = 44(IS - 6) (IS - 6)
If we simplify, we get:
11IS = 264
IS = 24
Consequently, IS has a 24 length as its length. SR is 44, QS is 55, and SU is 6 shorter than IS.
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Nick and jake ran a total of 27 miles combined. Nick ran 13 miles. How many did jake run?
If the slope is - 5 and the y-intercept is 4, what is the equation written in slope-intercept form ?
Group of answer choices
1.
y = - 5x + 4
2.
y = 4x - 5
3.
y - 4 = 5x
1.
y= -5x + 4
slope intercept form is y = mx + b (m) being the slope and (b) being the y intercept
I need help on this asap!
A system of inequalities to represent the constraints of this problem are x ≥ 0 and y ≥ 0.
A graph of the system of inequalities is shown on the coordinate plane below.
How to write the required system of linear inequalities?In order to write a system of linear inequalities to describe this situation, we would assign variables to the number of HD Big View television produced in one day and number of Mega Tele box television produced in one day respectively, and then translate the word problem into algebraic equation as follows:
Let the variable x represent the number of HD Big View television produced in one day.Let the variable y represent the number of Mega Tele box television produced in one day.Since the HD Big View television takes 2 person-hours to make and the Mega TeleBox takes 3 person-hours to make, a linear equation to describe this situation is given by:
2x + 3y = 192.
Additionally, TVs4U’s total manufacturing capacity is 72 televisions per day;
x + y = 72
For the constraints, we have the following system of linear inequalities:
x ≥ 0.
y ≥ 0.
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DUE TODAY HELP!!!!!!!!!!!!
What is the radius of the circle?
The radius of the circle is 13 units
How to determine the radius of the circleFrom the question, we have the following parameters that can be used in our computation:
The circle
Where we have
Center = (0, 0)
Point - (-5, 12)
The radius of the circle is the distance between the point and the center
So, we have
Radius = √[(0 + 5)² + (0 - 12)²]
Evaluate
Radius = 13
Hence, the radius is 13 units
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Find the unit rate.
9. 60 for 4 pounds
The unit rate is $_ per pound!
Answer:
2.40 per pound
Step-by-step explanation:
hope that's right
Given γ1 γ2 γ3 € C
(the three different from each other), check that they are
equivalent:
The triangle △ γ1 γ2 γ3 is equilateral and
γ1 γ2 + γ1 γ3 +γ2 γ3 = γ1^2 + γ2^2 + γ3^2
To show that the triangles are equivalent, we need to show that each triangle can be transformed into the other by a combination of translations, rotations, and reflections.
Let's assume that △ γ1 γ2 γ3 is an equilateral triangle, and γ1 γ2 + γ1 γ3 +γ2 γ3 = γ1^2 + γ2^2 + γ3^2.
First, we can translate the triangle so that γ1 is at the origin (0,0) in the complex plane. Then, we can rotate the triangle so that γ2 is on the positive real axis. This rotation can be achieved by multiplying each complex number by a suitable complex number of the form e^(iθ), where θ is the angle that γ2 makes with the positive real axis.
After this transformation, we have:
γ1 = 0
γ2 = r
γ3 = x + iy
where r is a positive real number and x, y are real numbers.
Using the fact that the triangle is equilateral, we have:
|γ2 - γ3| = |γ1 - γ3|
|r - x - iy| = |x + iy|
Squaring both sides and simplifying, we get:
r^2 + x^2 + y^2 - 2rx = x^2 + y^2
r^2 - 2rx = 0
This gives us x = r/2, and substituting this into the equation γ1 γ2 + γ1 γ3 +γ2 γ3 = γ1^2 + γ2^2 + γ3^2 gives:
r^2 + r(x + iy) + r(x - iy) = 3r^2
Simplifying this equation, we get:
r^2 = x^2 + y^2
which is equivalent to the equation we obtained earlier.
Therefore, we have shown that the two conditions are equivalent, and the triangles are equivalent under translations, rotations, and reflections.
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Write down these ratios 15 to 18 to 24 in their simplest forms
The ratios 15 to 18 to 24 in their simplest forms is 5:6:8.
To simplify the ratios 15:18:24, we need to divide all three numbers by their greatest common factor (GCF).
Find the GCF of 15, 18, and 24:
The factors of 15 are 1, 3, 5, and 15.
The factors of 18 are 1, 2, 3, 6, 9, and 18.
The factors of 24 are 1, 2, 3, 4, 6, 8, 12, and 24.
The largest factor that all three numbers share is 3, so the GCF is 3.
Divide all three numbers by 3:
15 ÷ 3 = 5
18 ÷ 3 = 6
24 ÷ 3 = 8
Write the simplified ratio:
The simplified ratio is 5:6:8.
Therefore, the simplified ratio of 15:18:24 is 5:6:8.
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Lester paid $31 for 5 pens and 4 books . A book costs $1.00 more than a pen .Stephan bought 6pens and 3 books at the same price . How much will Stephan pay
Answer: $30
Step-by-step explanation:
Let x be the cost of one pen
Then x + 1 will be the cost of one book
From the problem, we know that:
5x + 4(x + 1) = 31 (Lester paid $31 for 5 pens and 4 books. A book costs $1.00 more than a pen)
Simplifying the equation:
5x + 4x + 4 = 31
9x = 27
x = 3
So one pen costs $3 and one book costs $4.
Now we can find the cost for Stephan:
6 pens cost 6 x $3 = $18
3 books cost 3 x $4 = $12
So Stephan will pay $18 + $12 = $30.
Question 3 Determine the expense E for the production of an item when the price of $74.99 has been established. Fixed expenses are $59,000 and each unit produced costs $42.00 to make. The demand function has been determined to be a=67p+74,000
The expense E for the production of an item when the price of $74.99 has been established is $3,378,021.86.
To determine the expense E for the production of an item, we need to use the demand function and the given information about fixed expenses and cost per unit.
First, let's plug in the given price of $74.99 into the demand function to find the quantity demanded:
a = 67(74.99) + 74,000
a = 5,024.33 + 74,000
a = 79,024.33
Now that we know the quantity demanded, we can use this information to calculate the total cost of production. The total cost of production is the sum of the fixed expenses and the variable expenses (cost per unit multiplied by quantity demanded):
E = 59,000 + (42.00)(79,024.33)
E = 59,000 + 3,319,021.86
E = 3,378,021.86
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LINEAR EQUATIONS AND INEQUALITIES Additive property of equality with integers Solve for w. w-4=-6 w
The solution to the equation is w=-2. The additive property of equality with integers states that if a=b, then a+c=b+c for any integer c.
This property allows us to add the same number to both sides of an equation in order to isolate the variable and solve for it. In the equation w-4=-6, we can use the additive property of equality to add 4 to both sides in order to isolate the variable w:
w-4+4=-6+4
Simplifying gives us:
w=-2
Therefore, the solution to the equation is w=-2.
In HTML format, the answer would be:
The additive property of equality with integers states that if a=b, then a+c=b+c for any integer c. This property allows us to add the same number to both sides of an equation in order to isolate the variable and solve for it.
In the equation w-4=-6, we can use the additive property of equality to add 4 to both sides in order to isolate the variable w:
w-4+4=-6+4
Simplifying gives us:
w=-2
Therefore, the solution to the equation is w=-2.
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Find the value of x
26 26 6
[tex]\sqrt{26^{2} - 24^{2}} = \sqrt{(26-24)(26+24)} = \sqrt{2(50)} = \sqrt{100} = 10 \\[/tex]
[tex]x = \sqrt{10^{2} - 6^{2}} = \sqrt{100 -36} = \sqrt{64} = 8 \\[/tex]
[tex]\implies \bf x = 8[/tex]
Answer:
8
Step-by-step explanation:
Begin with the bigger right angle triangle
Hypotenuse is 26, second side is 24, third side is unknown (a)
26² - 24² = a²
676 - 576 =a²
100 = a²
Therefore a is 10
Now use the value of a which is 10 to solve the smaller triangle
Hypotenuse is 10, one side is 6, third side x is unknown
10²- 6²= x²
100 - 36 =x²
64 =x²
X is 8
A cone is 14cm deep and has a base radius of 9/2cm. Calculate to 2dp the volume of the cone that will fill the cone halfway
The volume of the cone that will fill the cone halfway is [tex]198.72 cm3[/tex] by the given base radius of 9/2cm and 14cm deep.
The formula for the volume of the cone is
[tex]V = (1/3)πr^2h[/tex]
where h is the height of the cone, r is its base's radius and is a mathematical constant roughly equal to 3.14159.
We must first determine the height of the cone that is filled halfway in to calculate the volume of the cone that will fill it halfway.
Half of the cone's entire height, or 14 cm divided by 2, or 7 cm, corresponds to the height of the half-filled cone.
The cone's base has a radius of 9/2 cm.
We can calculate the volume of the cone that will fill the cone halfway using the formula for a cone's volume as follows:
[tex]V = (1/3)πr^2h[/tex]
[tex]V = (1/3)π(9/2)^2(7) (7)[/tex]
[tex]V ≈ 198.72 cm^3[/tex] (rounded to 2 decimal places) (rounded to 2 decimal places)
Therefore, [tex]198.72 cm3[/tex] is the volume of the cone that will fill it halfway.
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PLEASE I NEED TO GET A HIGHER GRADE I REALLY NEED HELP PLEASE
Answer: practice 2. 8 inches practice 3. 220[tex]ft^2[/tex]
practice 4. 78° , 78° , 102° , 102 ° Practice 5. 12.5
Step-by-step explanation:
what is 3 to the power of 5 times six divided by 69=
Answer: The answer is 21.1304347826 or 21.13 rounded
Step-by-step explanation:
hope this helps
The sample space for tossing three fair coins is {hhh,hht,hth,htt,thh,tht,tth,ttt}. What is the probability of exactly two heads?
The probability of exactly two heads in tossing three fair coins is 3/8.
To find the probability of exactly two heads, we need to count the number of outcomes in the sample space that have exactly two heads and divide that by the total number of outcomes in the sample space.
In the sample space {hhh, hht, hth, htt, thh, tht, tth, ttt}, there are three outcomes that have exactly two heads: hht, hth, and thh.
So the probability of exactly two heads is 3/8.
In mathematical terms, this can be represented as:
P(exactly two heads) = number of outcomes with exactly two heads / total number of outcomes
P(exactly two heads) = 3 / 8
Therefore, the probability of exactly two heads in tossing three fair coins is 3/8.
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Convert the following phrase into a mathematical expression. Use x as the variable, and combine like terms.
Nine times a number, added to the sum of the number and one
The expression is _____.
The mathematical expression for the given phrase using x as the variable is:
9x + (x+1)
We can simplify this expression by combining like terms:
9x + x + 1 = 10x + 1
Therefore, the expression is 10x + 1.
determine the value of k for which the inequality 1/2
The only value of k that satisfies the given inequality and solution set is:
k = 0.
What is inequality?Inequality is defined as mathematical statements that have a minimum of two terms containing variables or numbers that are not equal.
We are given the inequality:
1/2 < k - 4x < 2k + 8
We are also given the solution set of the inequality:
{-3 < x < 2} and {-3 < x < 7/8}
We can simplify the inequality by adding 4x to all parts of the inequality:
1/2 + 4x < k < 2k + 8 + 4x
Next, we can use the given solution set to find the value of k that satisfies the inequality.
If x is between -3 and 2, then the largest possible value of 4x is 8, and the smallest possible value is -12. Therefore:
1/2 + 8 < k < 2k + 8 + 8
or
8.5 < k < 2k + 16
If x is between -3 and 7/8, then the largest possible value of 4x is 7/2, and the smallest possible value is -12. We have:
1/2 + 7/2 < k < 2k + 8 + 7/2
or
4 < k < 2k + 23/2
The intersection of these two solution sets is:
8.5 < k < 2k + 16
and
4 < k < 2k + 23/2
Simplifying the second inequality:
4 < k < 4 + 2k + 23/2 - 2k
or
4 < k < 23/2
Therefore, k must be between 8.5 and 23/2, inclusive.
However, we also need to check if k = 0 satisfies the inequality.
1/2 < 0 - 4x < 2(0) + 8
or
1/2 < -4x < 8
or
-1/8 > x > -2
The solution set {-1/8 > x > -2} is not the same as the given solution set, so k = 0 does not satisfy the inequality.
Therefore, the only value of k that satisfies the given inequality and solution set is:
k = 0.
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Write the radian measure of an angle coterminal to (15pi)/4 where your answer is between 0pi and 2pi
(7pi)/4
(15pi)/4
(7pi)/8
(9pi)/8
None of these are correct.
The radian measure of an angle coterminal to (15π)/4 is (7π)/4. The correct answer is A
To find an angle that is coterminal with (15π)/4 between 0 and 2π, we can subtract or add any multiple of 2π until we get an angle between 0 and 2π.
First, we can simplify (15π)/4 as follows:
(15π)/4 = (4π + π)/4 = π + (π/4)
Now, we can subtract 2π until we get an angle between 0 and 2π:
π + (π/4) - 2π = -π/4
Since -π/4 is negative, we can add 2π to get an angle between 0 and 2π:
-π/4 + 2π = (8π - π)/4 = (7π)/4
Therefore, an angle coterminal with (15π)/4 between 0 and 2π is (7π)/4. The correct answer is A
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¡A survey was conducted at an amusement park to determine the preferred activity of the patrons. Each person chose one activity. The results are shown in the table. Activity Roller coasters Shows Food Number of Patrons 36 12 18 Based on this information, which prediction about the preferred activity for the next 300 patrons is most reasonable? A The number of patrons who prefer shows will be 5 times the number of patrons who prefer food. B The number of patrons who prefer food will be 2 times the number of patrons who prefer shows. C The number of patrons who prefer roller coasters will be 4 times the number of patrons who prefer food. D The number of patrons who prefer roller coasters will be 2 times the number of patrons who prefer food.
Option D: The number of patrons who prefer roller coasters will be 2 times the number of patrons who prefer food.
How to obtain the proportions?The activities are given as follows:
Roller coasters.Shows.Foods.The number of patrons for each activity is given as follows:
Roller coasters: 36.Shows: 12.Foods: 18.Hence the proportions are:
Roller coasters: 36/66.Shows: 12/66.Foods: 18/66.For the next 300 patrons, the estimates are given as follows:
Roller coasters: 36/66 x 300 = 164.Shows: 12/66 x 300 = 54.5.Foods: 18/66 = 82.Hence option d is correct.
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The number of hours spent studying by students on a large campus in the week before a quiz follows a normal distribution with a standard deviation of 12.4 hours. How large of a sample is needed to ensure that the probability that the sample mean differs from the population mean by more or less then 2.0 hours is less than at a 90% confidence level? please show how you found critical value z
The sample size needed to ensure that the probability that the sample mean differs from the population mean by more or less then 2.0 hours is less than at a 90% confidence level is 127.
The sample size needed to ensure that the probability can be calculated using the formula:
n = (zα/2)2 2 / (E2)
Where n is the sample size, is the population standard deviation (12.4 hours in this case), E is the margin of error (2.0 hours in this case) and zα/2 is the critical value from a z-table corresponding to the 90% confidence level (1.645 in this case).
Thus, n = (1.645)2 (12.4)2 / (2.0)2 = 126.8
Therefore, the sample size needed to ensure that the probability that the sample mean differs from the population mean by more or less then 2.0 hours is less than at a 90% confidence level is 127.
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Find a formula for the power series of ()=6ln(1+), −1<<1
in the form ∑=1,[infinity]. Hint: First, find the power series for ()=6/(1+). Then integrate. (Express numbers in exact form. Use symbolic notation and fractions where needed. )
What is a_n?
The function of the power series f(x) = 6ln(1+x) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
And a_n = 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
The common ratio is the distance between each number in a geometric series. The proportion of a number or two consecutive numbers. The common ratio, which is the same for all numbers or common, is the number divided by the number that comes before it in the sequence.
To find the power series for f(x), we first need to find the power series for g(x) = 6/(1+x):
g(x) = 6/(1+x) = 6(1 - x + x² - x³ +...) (geometric series with common ratio -x)
Next, we integrate term by term:
∫ g(x) dx = ∫ 6(1-x+x²-x³+...) dx
= 6(x - x²/2 + x³/3 - x⁴/4 + ...) + C , where C is a constant.
Since we're only interested in finding the coefficients of the power series, we can ignore the constant term.
Thus, the power series for f(x) is:
f(x) = 6ln(1+x) = 6(x - x²/2 + x³/3 - x⁴/4 + ...) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n
where a_n = 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
Therefore, f(x) = 6ln(1+x) = ∑=1 , ∞ 6(-1)⁽ⁿ⁻¹⁾xⁿ/n.
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The coyote then jogs for 45 minutes at 7 miles/hour, then does a cool-down walk for 10
minutes at 3 miles/hour. How long was the coyote out exercising? If the coyote continually
went in a straight line, for his entire trip, what was his displacement?
a) The coyote was out exercising for 55 minutes since it jogged for 45 minutes and did a cool-down walk for 10 minutes.
b) For his entire trip, the coyote moving in a straight line continually had a displacement of 5.75 miles.
What is displacement?Displacement refers to the change in the position of an object.
Displacement is also defined as the length of the shortest distance from the initial to the final position of a point under motion.
The time spent jogging = 45 minutes
The average jogging speed = 7 miles/hour
The distance covered during jogging = 5.25 miles (7 x 45/60)
The time the coyote spent walking = 10 minutes
The average walking speed = 3 miles/hour
The distance covered walking = 0.5 miles (3 x 10/60)
a) The total time spent exercising = 55 minutes (45 + 10).
b) The displacement (total distance) of the coyote in 55 minutes = 5.75 miles (5.25 + 0.5).
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O is the center of the regular octagon below. Find its perimeter. Round to the nearest tenth if necessary.
The perimeter of the regular octagon with an apothem of 5 units will be 33.14 units.
Since, We know that;
All the sides of the regular polygon are congruent to each other. The perimeter of the regular polygon of n sides will be the product of the number of the side and the side length of the regular polygon.
P = (Side length) x n
Here, The Apothem of a regular octagon is 5 units.
Then the side length of the regular octagon is given as,
tan (360° / (2 × 8)) = (n/2) ÷ 5
tan 22.5° = n / 10
n = 4.142
Then, the perimeter is given as,
P = 8 x 4.142
P = 33.14 units
Thus, The perimeter of the regular octagon with an apothem of 5 units will be 33.14 units.
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Write an equation for a line perpendicular to y = - 5 x - 2 and passing through the point ( 10 , 5 ) . Express your answer in slope-intercept form. y =
For a line perpendicular to y = - 5 x - 2 and passing through the point ( 10 , 5 ), the equation in slope-intercept form is y = (1/5)x + 3.
To write an equation for a line perpendicular to y = -5x - 2 and passing through the point (10, 5), we first need to find the slope of the new line. The slope of a line perpendicular to another line is the negative reciprocal of the original line's slope. The slope of the original line is -5, so the slope of the new line is 1/5.
Next, we can use the point-slope form of an equation to write the equation for the new line. The point-slope form is y - y1 = m(x - x1), where m is the slope and (x1, y1) is a point on the line. Plugging in the values we have, we get:
y - 5 = (1/5)(x - 10)
Finally, we can rearrange this equation to put it in slope-intercept form, which is y = mx + b, where m is the slope and b is the y-intercept. To do this, we'll distribute the 1/5 and then add 5 to both sides of the equation:
y - 5 = (1/5)x - 2
y = (1/5)x + 3
So the equation for the new line is y = (1/5)x + 3. This is our final answer.
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A scale drawing of a spider is 5 centimeters long. The actual length of the spider is 4 inches. If one of the spiders legs is 4 cm in the drawing how long is the actual leg?
0.31 in
1.8in
4 in
3.2 in
A girl leaves a sandwich out for an experiment. After 4 days she sees that there are 71 bacteria. 3 days after that, she sees that there are 185 bacteria. Write an exponential equation to represent this situation.
The girl estimates that once there are 500 bacteria, the sandwich will be fully covered. How long, in days, will it take to reach 500 bacteria?
Answer:
approximately 10.3 days to reach 500 bacteria
Step-by-step explanation:
Let's use the formula for exponential growth to write an equation that represents the situation: N = N0 * e^(rt)
where N is the number of bacteria, N0 is the initial number of bacteria, e is Euler's number (approximately 2.718), r is the growth rate, and t is the time in days.
We know that after 4 days, the number of bacteria is 71, so we can plug these values into the equation to solve for the growth rate: 71 = N0 * e^(4r)
Similarly, after 7 days (4 + 3), the number of bacteria is 185: 185 = N0 * e^(7r)
Now we have two equations with two unknowns (N0 and r). We can divide the second equation by the first equation to eliminate N0: 185/71 = e^(3r)
Taking the natural logarithm of both sides, we get: ln(185/71) = 3r
Solving for r, we get: r = ln(185/71) / 3 ≈ 0.558
Now we can use the first equation and the growth rate we just found to solve for N0:
71 = N0 * e^(4 * 0.558)
N0 ≈ 11.7
So the initial number of bacteria was approximately 11.7.
To find out how long it will take to reach 500 bacteria, we can plug in the values we know into the equation and solve for t: 500 = 11.7 * e^(0.558t)
Dividing both sides by 11.7, we get: e^(0.558t) ≈ 42.74
Taking the natural logarithm of both sides, we get: 0.558t ≈ ln(42.74)
Solving for t, we get: t ≈ ln(42.74) / 0.558 ≈ 10.3 days
Therefore, it will take approximately 10.3 days for the sandwich to be fully covered with bacteria.
In Exercises 57-60 \( \square \), write the given system of linear equations as a matrix equation. 57. \( \left\{\begin{array}{r}3 x+2 y=-1 \\ 7 x-y=\quad 2\end{array}\right. \)
The matrix equation for Exercise 57 is:
\[ \begin{bmatrix} 3 & 2 \\ 7 & -1 \end{bmatrix} \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} -1 \\ 2 \end{bmatrix} \]
In Exercise 57, we are asked to write the given system of linear equations as a matrix equation.
To do this, we need to separate the coefficients of the variables and the constants from the equations and write them in matrix form. The coefficients of the variables will form the coefficient matrix, and the constants will form the constant matrix.
The coefficient matrix will be a 2x2 matrix, with the first row containing the coefficients of x and y from the first equation, and the second row containing the coefficients of x and y from the second equation. The constant matrix will be a 2x1 matrix, with the first row containing the constant from the first equation, and the second row containing the constant from the second equation.
So, the matrix equation for the given system of linear equations will be:
\[ \begin{bmatrix} 3 & 2 \\ 7 & -1 \end{bmatrix} \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} -1 \\ 2 \end{bmatrix} \]
Therefore, the matrix equation for Exercise 57 is:
\[ \begin{bmatrix} 3 & 2 \\ 7 & -1 \end{bmatrix} \begin{bmatrix} x \\ y \end{bmatrix} = \begin{bmatrix} -1 \\ 2 \end{bmatrix} \]
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