The possible rational zeros for the polynomial function P(x)=21x^(3)-38x^(2)+44x-10 are ±1, ±2, ±5, ±10, ±1/3, ±2/3, ±5/3, ±10/3, ±1/7, ±2/7, ±5/7, ±10/7, ±1/21, ±2/21, ±5/21, ±10/21.
The possible rational zeros of a polynomial function can be determined using the Rational Zero Theorem. This theorem states that if a polynomial function has rational zeros, they will be in the form of p/q, where p is a factor of the constant term and q is a factor of the leading coefficient.
In the given polynomial function, P(x)=21x^(3)-38x^(2)+44x-10, the constant term is -10 and the leading coefficient is 21. The factors of -10 are ±1, ±2, ±5, ±10 and the factors of 21 are ±1, ±3, ±7, ±21.
Using the Rational Zero Theorem, the possible rational zeros are:
p/q = ±1/1, ±2/1, ±5/1, ±10/1, ±1/3, ±2/3, ±5/3, ±10/3, ±1/7, ±2/7, ±5/7, ±10/7, ±1/21, ±2/21, ±5/21, ±10/21
Simplifying these fractions gives us the possible rational zeros:
±1, ±2, ±5, ±10, ±1/3, ±2/3, ±5/3, ±10/3, ±1/7, ±2/7, ±5/7, ±10/7, ±1/21, ±2/21, ±5/21, ±10/21
Therefore, the possible rational zeros for the polynomial function P(x)=21x^(3)-38x^(2)+44x-10 are ±1, ±2, ±5, ±10, ±1/3, ±2/3, ±5/3, ±10/3, ±1/7, ±2/7, ±5/7, ±10/7, ±1/21, ±2/21, ±5/21, ±10/21.
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Find the area of the composite figure.
DESMOS CALCULATOR LINK
9
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Need help! dont understand this question
Answer: y > 2/5x - 4
Step-by-step explanation:
The slope intercept form is y = mx + b
To get the inequality to that, we have to get y alone.
Starting:
2x - 5y < 20
Subtract 2x from each side leaves you:
- 5y < -2x + 20
Dividing by -5 leaves you:
(Remember that when dividing by a negative in an inequality, the sign flips.)
y > 2/5x - 4
Hope this helps!
What values should x and y have to complete the proportion xa = ay, where x is a hypotenuse?
The value of x is 18 and y is 16. The solution has been obtained by using concept of similar triangles.
What are similar triangles?If two triangles have the same number of corresponding sides and corresponding angles, they are said to be similar. Similar figures are objects that have the same shape but various sizes, like two or more figures.
We are given that in ΔABC and ΔBDC,
∠ABC ≅ ∠BDC (right angles)
BC ≅ BC (common side)
∠ACB ≅ ∠BCD (common angle)
So, ΔABC ≅ ΔBDC.
We know that in similar triangles, the ratio of the corresponding sides is same.
So,
AC / BC = BC / CD
Now, by substituting the given values in the relation, we get,
⇒18/a = a/16
We are given proportion as x/a = a/y.
On comparing both, we get
x = 18 and y = 16
Hence, the value of x is 18 and y is 16.
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(-10,-15) is the image of N after the dilation with a scale factor of 5/4 centered at the orgin. What are the coordinates of N
The coordinates of N can be estimated as: (-8, -12)
What is the scale factor ?Scale factor is a mathematical term, which we use to scale 2-dimensional and 3-dimensional shapes. Scale factor is a measure of similar figures. Those figures who look the same but are in different sizes.
If point N is dilated with a scale factor of 5/4 centered at the origin, the coordinates of the image point, let's call it N', can be found by multiplying the coordinates of N by the scale factor:
N' = (5/4)N
We also know that the image point N' is located at (-10, -15), so we can substitute these values into the equation:
(-10, -15) = (5/4)N
Solving for N, we can multiply both sides by the reciprocal of 5/4, which is 4/5:
N = (4/5)(-10, -15)
N = (-8, -12)
Therefore, the coordinates of point N are (-8, -12).
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HURRY I NEED THIS ANSWER PLEASE!!!
What set of reflections would carry hexagon ABCDEF onto itself?
E
F
Answer:
Step-by-step explanation:
the answer is eitehr b or a
Mary has $250 to spend. She buys gift cards for $130. She will use the rest of the money to buy candy bars that cost $1. 50 each. Which inequality can be used to find the greatest number of candy bars she can buy with the rest of the money?
Answer:
80
Step-by-step explanation:
we will write an inequality of 1.50x + 130 =250
We subtract 130 from each side, so we have
1.50x=120
Now we divide by 1.50 on each side
X=80.
questions to ask grade 12 students on a questionnaire about taking a gap year after school
Some of the questions to ask grade 12 students on a questionnaire about taking a gap year after school are:
Are you planning to take a gap year after completing high school?If yes, what are your reasons for taking a gap year?Have you already planned your gap year activities? If yes, what are they?Are you worried about losing academic momentum by taking a gap year?How do you plan to finance your gap year activities?Are you planning to work during your gap year? If yes, what type of job are you looking for?Have you discussed your gap year plans with your parents or guardians?How do you think a gap year will impact your personal growth and development?What are questionnaire used for in a study?A questionnaire refers to a set of questions or items used to collect information about respondents' attitudes, experiences, or opinions. Questionnaires can be used to collect both quantitative and qualitative data. Questionnaires are widely used in market research, as well as social and health sciences.
As the researcher's study focus on semester taken after high school and prior to post-secondary education, such questionnaire involve will focus on variables on the student gap year.
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Calculus Problem…
Suppose a and b span R². Determine the values of x and y, given that (2-x)a + b is
equal to ya + (x-3)b.
The values of x and y that satisfy the given equation are x = 2 and y = 1.
What is the system of equations?One or many equations having the same number of unknowns that can be solved simultaneously are called simultaneous equations. And the simultaneous equation is the system of equations.
Since a and b span R², any vector in R² can be expressed as a linear combination of a and b.
Let's call the coefficients of this linear combination c₁ and c₂ so that any vector v in R² can be expressed as:
v = c₁a + c₂b
Now let's use this fact to solve the given equation:
(2-x)a + b = ya + (x-3)b
We can rearrange this equation to get all the terms with an on one side and all the terms with b on the other side:
(2-x)a - ya = (3-x)b
Now we can write both sides of the equation as linear combinations of a and b:
(2-x)a - ya = 2a - xa - ya = (2-x)a - (x-2)a - ya = (2-x - x + 2)a - ya = (4 - 2x)a - ya
(3-x)b = 3b - xb = 3b - xb + 3b - 3b = (6 - x)b - 3b = (6 - x - 3)b = (3 - x)b
So now we have:
(4 - 2x)a - ya = (3 - x)b
Since a and b span R², we know that any vector in R² can be expressed as a linear combination of a and b. Therefore, we can write:
(4 - 2x)a - ya = c₁a + c₂b
(3 - x)b = c₁a + c₂b
Now we can set the coefficients of a and b equal to each other and solve for x and y:
4 - 2x = c₁
-y = c₂
3 - x = c₂
Substituting the third equation into the second equation, we get:
-y = 3 - x
Solving for x and y, we get
x = 2
y = 1
Therefore, the values are x = 2 and y = 1.
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Suppose an object has a height of 0 feet after 10seconds. This same object has maximum height of 200 feet at 0 seconds. 1. Find H(T)=A(T−h)2+k where H(T) is the height of the object in feet after T seconds. Answers in Exact Form 2. When will the object have a height of 100 feet? Answers in Exact Form and round 3 decimals.
The object will have a height of 100 feet after 100 seconds.
The equation for the height of the object in feet after T seconds is H(T) = A(T - h)2 + k, where A and h are constants. Given that the object has a height of 0 feet after 10 seconds, and a maximum height of 200 feet at 0 seconds, we can solve for A and h.
We know that H(0) = 200, so k = 200.
We also know that H(10) = 0, so A(10 - h)2 + 200 = 0. Solving for A, we get A = -(h2 + 200) / 102.
Now we have an equation with two unknowns, A and h, so we can use substitution to solve for h. We can substitute -(h2 + 200) / 102 for A in our original equation, and solve for h. This gives us h = 10.
We now know A = -(102 + 200) / 102 = -20.
So, our equation for the height of the object in feet after T seconds is H(T) = -20(T - 10)2 + 200.
To find the height of the object after 100 seconds, substitute 100 for T in the equation. This gives us H(100) = -20(100 - 10)2 + 200 = 100.
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Compare the functions f(x) and g(x) and choose the correct statement.
g(x) has a steeper slope than f(x).
f(x) has a steeper slope than g(x).
f(x) has a greater y-intercept than g(x).
They are the same function.
The correct statement about the functions f(x) and g(x) include the following: B. f(x) has a steeper slope than g(x).
How to calculate the slope of a line?In Mathematics, the slope of any straight line can be determined by using this mathematical equation;
Slope (m) = (Change in y-axis, Δy)/(Change in x-axis, Δx)
Slope (m) = (y₂ - y₁)/(x₂ - x₁)
Substituting the given points into the slope formula, we have the following;
Slope, m of g(x) = (1 - (-3))/(0 - (-2))
Slope, m of g(x) = 4/2
Slope, m of g(x) = 2.
Slope of f(x) = 3. Therefore, 3 is greater than 2.
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1.
Function Family:
2.
3
Key Features: Domain; x & y intercepts
Domain:
x-intercepts:
y-intercepts:
Domain:
ES
Mar 1
12:15 1 US
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Function Family: quadratic
Domain: all real numbers
x-int: (0,0) and (2,0)
y-int: (0,0)
Write the quadratic equation in standard form: − 8x+19=-2x^²
Use a sum or difference formula to find the exact value of the following. tan 41° + tan 19° 1-tan 41°tan 19°
The exact value of the expression is √3.
To find the exact value of the given expression, we can use the sum formula for tangent. The formula is:
Tan (A + B) = (tan A + tan B) / (1 - tan A tan B)
Where A and B angle.
In this case, A = 41° and B = 19°. Plugging these values into the formula, we get:
Tan (41° + 19°) = (tan 41° + tan 19°) / (1 - tan 41° tan 19°)Simplifying the left side of the equation gives us:
Tan 60° = (tan 41° + tan 19°) / (1 - tan 41° tan 19°)We know that tan 60° = √3.
Substituting this value into the equation gives us:√3 = (tan 41° + tan 19°) / (1 - tan 41° tan 19°)
Cross-multiplying and simplifying gives us:
√3 (1 - tan 41° tan 19°) = tan 41° + tan 19°√3 - √3 tan 41° tan 19° = tan 41° + tan 19°
We can rearrange the terms to get:
√3 = tan 41° + tan 19° + √3 tan 41° tan 19°
This is the same expression that we were given in the question.
Therefore, the exact value of the expression is √3.
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Divide x²-5x+6 by ( x-2)
Eli has two summer jobs. During the week he works in the grocery store, and on the weekend he works at a nursery. He gets paid $20 per hour to work at the grocery store and $17 per hour to work at the nursery. How much does he earn if he works 14 hours at the grocery store and 9 hours at the nursery? How much does he earn if he works
g
g hours at the grocery store and
n
n hours at the nursery?
She gets $114 to work at grocery store for 6 hours and $200 at the nursery.
What is Rate?A rate in arithmetic is a ratio that contrasts two separate values with various unit systems. For instance, if John types 50 words per minute, that means he types 50 words per minute.
We are dealing with a rate because the word "per" is there. The symbol "/" can be used in place of the word "per" in issues.
When two or more similar amounts or numbers are being compared using the same units, a ratio is utilized. When referring to the ratio of one quantity "to" the second quantity in spoken language, it is frequently written with a colon.
Eli has two summer jobs. During the week he works in the grocery store, and on the weekend he works at a nursery. He gets paid $20 per hour to work at the grocery store and $17 per hour to work at the nursery.
14 hours at the grocery store and 9 hours at the nursery? How much does he earn if he works
Therefore, She gets $114 to work at grocery store for 6 hours and $200 at the nursery.
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Solve using the addition property of equality. Don't forget to perform a check. x-5=21
The answer is x=26.
To solve the equation x-5=21 using the addition property of equality, we need to isolate the variable x on one side of the equation. The addition property of equality states that if we add the same value to both sides of an equation, the equation will remain true.
Step 1: Add 5 to both sides of the equation to cancel out the -5 on the left side.
x-5+5=21+5
Step 2: Simplify both sides of the equation.
x=26
Step 3: Check the solution by substituting the value of x back into the original equation.
26-5=21
21=21
The solution checks out, so the answer is x=26.
In conclusion, the solution to the equation x-5=21 using the addition property of equality is x=26.
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Please explain this more in depth. How does the chain rule allow
the first equation to reduce to the second equation? Some simple
explanation of the chain rule would also be helpful.
The chain rule allows us to reduce the first equation to the second equation by finding the derivative of the composite function and substituting it for the original function. This provides a simpler and more concise explanation of the relationship between the two equations.
The chain rule is a formula for calculating the derivative of a composite function. It states that the derivative of a composite function f(g(x)) is equal to the derivative of f with respect to g times the derivative of g with respect to x. In mathematical notation, this is expressed as (f(g(x)))' = f'(g(x)) * g'(x).
In the case of the first equation, we can use the chain rule to reduce it to the second equation by applying the formula mentioned above. First, we need to identify the composite function and its components. In this case, the composite function is f(g(x)) and the components are f and g.
Next, we need to find the derivative of f with respect to g and the derivative of g with respect to x. Once we have these derivatives, we can multiply them together to get the derivative of the composite function.
Finally, we can reduce the first equation to the second equation by substituting the derivative of the composite function for the original composite function. This will give us the second equation, which is a simplified version of the first equation.
In conclusion, the chain rule allows us to reduce the first equation to the second equation by finding the derivative of the composite function and substituting it for the original function. This provides a simpler and more concise explanation of the relationship between the two equations.
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Danielle earns a 7.25% commission on everything she sells at the electronics store where she works. She also earns a base salary of $725 per week. How much did she earn last week if she sold $4,100 in electronics merchandise? Round your intermediate calculations and answer to the nearest cent.
Answer:
First, we need to calculate Danielle's commission on the merchandise she sold:
Commission = 7.25% of $4,100 = 0.0725 x $4,100 = $296.25
Next, we need to calculate her total earnings for the week:
Total earnings = Base salary + Commission
Total earnings = $725 + $296.25
Total earnings = $1,021.25
Therefore, Danielle earned $1,021.25 last week.
Answer:
1,021.25
Step-by-step explanation:
The arithmetic mean of two numbers is half their sum, and the geometric mean is the square root of their product. using log properties, show how we can think of the log of the geometric mean of v and w as the arithmetic mean of two related numbers, p and q. expand and simplify
We have shown that the log of the geometric mean of two numbers is the arithmetic mean of the logs of those two numbers.
We can use the properties of logarithms to show that the log of the geometric mean of two numbers is the arithmetic mean of the logs of those two numbers.
First, recall that the arithmetic mean of two numbers is half their sum:
arithmetic mean = (v + w)/2
And the geometric mean is the square root of their product:
geometric mean = √(v*w)
Now, let's take the log of the geometric mean:
log(geometric mean) = log(√(v*w))
Using the property of logarithms that log(a*b) = log(a) + log(b), we can expand the expression:
log(√(v*w)) = log(√v) + log(√w)
Using the property of logarithms that log(a^b) = b*log(a), we can simplify the expression:
log(√v) + log(√w) = (1/2)*log(v) + (1/2)*log(w)
Now, we can see that the log of the geometric mean is the arithmetic mean of the logs of the two numbers:
log(geometric mean) = (log(v) + log(w))/2
So, if we let p = log(v) and q = log(w), we can see that the log of the geometric mean of v and w is the arithmetic mean of p and q:
log(geometric mean) = (p + q)/2
Therefore, we have shown that the log of the geometric mean of two numbers is the arithmetic mean of the logs of those two numbers.
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OWX is a sector of a circle with a radius of
32 cm.
OYZ is a sector of a circle with a radius of
21 cm.
The central angle of both sectors is 75°.
Work out the area of the shaded shape WXZY
Give your answer in cm² to 1 d.p.
try help please
The area of the shaded shape WXZY s equal to 381.4 cm².
How to calculate the area of a sector?Mathematically, the area of a sector can be calculated by using this formula:
Area of sector = θπr²/360
Where:
r represents the radius of a circle.θ represents the central angle.How to determine the area of the shaded shape WXZY?In order to determine the area of the shaded shape WXZY, we would have to subtract the area of sector OYZ from the area of the sector OWX.
Area of sector OWX = 75 × 3.14 × 32²/360 = 669.87 cm²
Area of sector OYZ = 75 × 3.14 × 21²/360 = 288.49 cm²
Area of shaded shape WXZY = Area of sector OWX - Area of sector OYZ
Area of shaded shape WXZY = 669.87 cm² - 288.49 cm²
Area of shaded shape WXZY = 381.4 cm².
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1. You and two friends go to the ice cream parlor. The flavors are Strawberry, Mexican Vanilla, Rocky Road, Belgian Chocolate, Salted Caramel, and Bratwurst. Assuming each of you orders one different flavor, how many outcomes are possibly?
2. (part 1) The combination for your locker contains 3 non-repeating digits from the numbers 0-9. How many possible locker combinations exist?
(part 2) what would the answer to #2 be if you absolutely choose 9 as your first answer?
3. After 100 trials of flipping a coin twice, you got the result of HH (heads, heads) 25 times. Is the experimental probability of getting HH greater than, less than, or equal to the theoretical probability of getting HH? How do you know?
4. You roll a standard number cube, flip a coin, then roll a standard number cube. Which of the following could represent this compound event? Choose all that apply.
a. (6,H,7)
b. (T,3,4)
c. (6,H.6,T)
d. (1,T,1)
e. (H,H,3)
(a) (6, H, 7) is not a possible outcome because the sum of the two numbers rolled on the number cube cannot be 7 if the first number rolled is 6.
(b) (T, 3, 4) is a possible outcome because the first outcome is tails, the second outcome is 3, and the third outcome is 4.
(c) (6, H, 6, T) is not a possible outcome because the third outcome cannot be both 6 and T at the same time.
(d) (1, T, 1) is a possible outcome because the first and third outcomes are both 1 and the second outcome is tails.
(e) (H, H, 3) is not a possible outcome because the third outcome cannot be 3 if the first two outcomes are both heads.
What is Probability?
Probability is a branch of mathematics in which the chances of experiments occurring are calculated. It is by means of a probability, for example, that we can know from the chance of getting heads or tails in the launch of a coin to the chance of error in research.
Since each of the three people orders a different flavor, the first person has 6 choices, the second person has 5 choices (since one flavor has already been chosen), and the third person has 4 choices (since two flavors have already been chosen). The total number of outcomes is the product of these numbers:
6 × 5 × 4 = 120
Therefore, there are 120 possible outcomes.
(part 1) There are 10 options for the first digit, 9 options for the second digit (since one digit has already been chosen), and 8 options for the third digit (since two digits have already been chosen). The total number of combinations is the product of these numbers:
10 × 9 × 8 = 720
Therefore, there are 720 possible locker combinations.
(part 2) If you absolutely choose 9 as your first digit, then there are only 9 options for the first digit. The second and third digits can still be any of the remaining 9 digits (since digits cannot repeat). Therefore, the number of possible combinations is:
1 × 9 × 8 = 72
The theoretical probability of getting HH on two coin flips is (1/2) × (1/2) = 1/4 = 0.25. The experimental probability of getting HH after 100 trials is 25/100 = 0.25. Since the experimental probability is equal to the theoretical probability, we can say that the experimental probability of getting HH is equal to the theoretical probability.
The possible outcomes of rolling a standard number cube are 1, 2, 3, 4, 5, and 6. The possible outcomes of flipping a coin are heads (H) or tails (T).
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2x^2 + 2y^2 + 16x + 16y + 32 = 0 is the equation of a circle with center (h, k) and radius r for: h= ____ and k= ____ and r= _____
So the equation of the circle is (x+4)^2 + (y+4)^2 = 4^2 with center (-4, -4) and radius 4
The equation of a circle is given by (x-h)^2 + (y-k)^2 = r^2 where (h,k) is the center of the circle and r is the radius. We need to rearrange the given equation to match this form.
2x^2 + 2y^2 + 16x + 16y + 32 = 0
Divide both sides of the equation by 2:
x^2 + y^2 + 8x + 8y + 16 = 0
Rearrange the terms:
x^2 + 8x + y^2 + 8y = -16
Complete the square for both x and y terms:
(x^2 + 8x + 16) + (y^2 + 8y + 16) = -16 + 16 + 16
(x+4)^2 + (y+4)^2 = 16
Now the equation is in the standard form of a circle equation, and we can find the center (h,k) and radius r:
h = -4, k = -4, r = 4
So the equation of the circle is (x+4)^2 + (y+4)^2 = 4^2 with center (-4, -4) and radius 4.
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Evaluate (122two _ 202three)_ 1001three
The expression (122two _ 202three)_ 1001three can be evaluated by breaking it down into its constituent parts.
What is expression in math?Expression in math is a combination of numbers, symbols, and/or operations that represent a mathematical statement. Expressions can be used to calculate values, solve equations, and to model real-world problems. Expressions can be simple or complex and can range from basic arithmetic operations to more complex functions and equations. Expressions are an essential part of mathematics and are used to represent equations, formulas, and even solutions to complex problems.
The first part, 122two, is a number and can be evaluated to 122. The second part, 202three, is also a number and can be evaluated to 203. The third part, 1001three, is also a number and can be evaluated to 1002. Taking the evaluation of each part (122, 203 and 1002), the overall expression (122two _ 202three)_ 1001three can be evaluated to 121.
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Shelly bought a dress for $150 and sold it to Jenny there by suffering a loss of 10%. Find the selling price of the dress.
Answer: $135
Step-by-step explanation:
We know that:
Selling price = [tex](100 - \text{Loss}\%)(\frac{\text{Cost Price}}{100})[/tex]
Using the given cost price and loss%, we can solve.
Selling Price = [tex](100 - \text{Loss}\%)(\frac{\text{Cost Price}}{100})[/tex]
Selling Price = (100 - 10)([tex]\frac{\text{150}}{100}[/tex])
Selling Price = (90) * (1.5)
Selling Price = $135
This means the selling price of the dress is $135.
When Mason goes to the gym, he spends one half of an hour lifting weights and one third of an hour on the treadmill. Which are correct descriptions of the relationship of time Mason spends lifting weights and on the treadmill.
Mason spends one half of an hour lifting weights and one third of an hour on the treadmill, so the ratio of time Mason spends lifting weights to time Mason spends on the treadmill is 1:2.
How Treadmill works?A treadmill is a machine used for walking or running while staying in one place. It usually has a belt and a platform to stand on, and the belt moves at a speed determined by the user. It is a great way to get a good cardio workout.
The question asks which are correct descriptions of the relationship of time Mason spends lifting weights and on the treadmill.
Mason spends one half of an hour lifting weights and one third of an hour on the treadmill, so the fraction of time Mason spends lifting weights is 2/3.
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please help with these questions thank you. they are about finding a term for x
Answer:
Step-by-step explanation:
x = number of small boxes
x-4 = number of large boxes
total number of eggs in the large boxes = 12(x-4) = 12x - 48
total number of eggs she buys = 6x + 12x - 48 = 18x - 48 = 6(3x - 8)
3. Consider the functionφ(x)=31x3−21x. (a) Show that 0 is a fixed point ofφ(x). (b) Show that the iterationxk+1=φ(xk)converges locally to 0 . (c) By numerical tests, find an initial guessx0such that the iteration converges to 0 and find an initial guessx0such that the iteration diverges.
From the function φ(x)=31x3−21x, 0 is a fixed point of φ(x) it shows in calculation below. The iteration xk+1 = φ(xk) converges locally to 0 shows below. The iteration diverges as k increases.
(a) To show that 0 is a fixed point of φ(x), we need to show that φ(0) = 0. Substituting x = 0 into the function gives us:
φ(0) = (3/1)(0)3 - (2/1)(0) = 0 - 0 = 0
Therefore, 0 is a fixed point of φ(x).
(b) To show that the iteration xk+1 = φ(xk) converges locally to 0, we need to show that |φ'(x)| < 1 for x near 0. Taking the derivative of φ(x) gives us:
φ'(x) = (9/1)x2 - (2/1)
At x = 0, φ'(0) = 0 - 2 = -2. Since |φ'(0)| > 1, the iteration does not converge locally to 0.
(c) By numerical tests, we can find an initial guess x0 such that the iteration converges to 0 and an initial guess x0 such that the iteration diverges. For example, if we choose x0 = 0.5, the iteration converges to 0:
x1 = φ(0.5) = (3/1)(0.5)3 - (2/1)(0.5) = -0.625
x2 = φ(-0.625) = (3/1)(-0.625)3 - (2/1)(-0.625) = 0.8203125
x3 = φ(0.8203125) = (3/1)(0.8203125)3 - (2/1)(0.8203125) = -0.4625244140625
And so on. The iteration converges to 0 as k increases.
On the other hand, if we choose x0 = 2, the iteration diverges:
x1 = φ(2) = (3/1)(2)3 - (2/1)(2) = 20
x2 = φ(20) = (3/1)(20)3 - (2/1)(20) = 23980
x3 = φ(23980) = (3/1)(23980)3 - (2/1)(23980) = 3.47119332792e+13
And so on. The iteration diverges as k increases.
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Classify 2x+2 Quadratic monomial Linear monomial Linear binomial Quadratic trinomial
The correct classification for the expression 2x+2 is a Linear binomial.(3)
A monomial is an algebraic expression with only one term. A binomial is an algebraic expression with two terms. A trinomial is an algebraic expression with three terms.
A quadratic expression is an expression with a term that has a degree of 2. A linear expression is an expression with a term that has a degree of 1.
In the given expression, 2x+2, there are two terms (2x and 2) so it is a binomial. The highest degree of the terms is 1 (in the term 2x), so it is a linear expression. Therefore, the correct classification for the expression is a Linear binomial.
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complete question
Classify 2x+2 in one of the following
1.Quadratic monomial
2.Linear monomial
3.Linear binomial
4.Quadratic trinomial
For a dish party, Alia needs to seat four people at a round table. How many combinations are possible?
For a dish party, Alia needs to seat four people at a round table. There are 24 possible combinations of seating arrangements.
This is because each person has 3 options (clockwise, counter-clockwise, opposite), for a total of 34 or 81 combinations. However, due to symmetry, half of these are the same combinations with the people just shifted around the table, so we are left with 24 total combinations.
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Question 1 of 4 Find the GCF of the first two terms and the GCF of the last two terms for the polynomial 3p^(3)+9p^(2)+5p+15
The GCF (greatest common factor) of the first two terms of the polynomial 3p^(3)+9p^(2)+5p+15 is 3p^(2). This is because both terms have a common factor of 3p^(2) that can be factored out.
The GCF of the last two terms of the polynomial is 5. This is because both terms have a common factor of 5 that can be factored out.
Therefore, the polynomial can be factored as follows:
3p^(2)(p+3) + 5(p+3)
Now, we can factor out the common factor of (p+3) to get the final factored form of the polynomial:
(3p^(2)+5)(p+3)
So, the GCF of the first two terms is 3p^(2) and the GCF of the last two terms is 5.
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