Long flights at midlatitudes in the Northern Hemisphere encounter the jet stream, an eastward airflow that can affect a plane's speed relative to Earth's surface. If a pilot maintains a certain speed relative to the air (the plane's airspeed), the speed relative to the surface (the plane's ground speed) is more when the flight is in the direction of the jet stream and less when the flight is opposite the jet stream. Suppose a round-trip flight is scheduled between two cities separated by 4300 km, with the outgoing flight in the direction of the jet stream and the return flight opposite it. The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min. What jet-stream speed is the computer using

Answers

Answer 1

Answer:

103.52 km/h

Explanation:

We are given;

Distance between two cities; d = 4300 km

airspeed; v_as = 930 km/h

Difference in flight time; Δt = 61 min = 1.0167 h

Now, the equation of motion to find the distance is given as;

d = vt

Where v = v_as + v_js

v_as is the airspeed

v_js is the jet speed

Thus;

d = (v_as + v_js)t

Thus, time(t1) for outgoing flight is;

t1 = d/(v_as + v_js)

Meanwhile, time(t2) for the return flight, the jet stream velocity will be negative and time is;

t2 = d/(v_as - v_js)

Recall that Difference in flight time; Δt = 61 min.

Thus;

Δt = t2 - T1 = [d/(v_as - v_js)] - [d/(v_as + v_js)]

Factorizing out, we have;

Δt = d[1/(v_as - v_js)] - [1/(v_as + v_js)]

Furthermore, it gives;

Δt = d[(v_as + v_js - v_as + v_js)]/((v_as - v_js) × (v_as + v_js))

Δt = d(2v_js)/((v_as)² - (v_js)²)

Cross multiply to get;

(2dv_js)/Δt = ((v_as)² - (v_js)²)

(v_js)² + ((2dv_js)/Δt) - (v_as)² = 0

Plugging in values for d,v_as and Δt gives;

(v_js)² - ((2 × 4300 × v_js)/1.0167) - (930)² = 0

(v_js)² - (8458.7329v_js) - 864900 = 0

Using quadratic formula, we have;

v_js = 103.52 km/h

Answer 2

The airline computer advises an airspeed of 930 km/h, for which the difference in flight times for the outgoing and return flights is 61 min.  The jet stream speed obtained using the quadratic formula is  103.52 km/h.

Given:

Distance between two cities; d = 4300 km

airspeed; v(as) = 930 km/h

Difference in flight time; Δt = 61 min = 1.0167 h

Now, the equation of motion to find the distance is given as;

d = vt

Where v = v(as) + v(js)

d = v(as) + v(js)t

At time t₁, t₁ = d/v(as) + v(js)

At time t₂, t₂ = d/v(as) + v(js)

Recall that Difference in flight time; Δt = 61 min.

Δt =  d/v(as) + v(js) - d/v(as) + v(js)

Δt = d[(v(as) + v(js) - v(as) + v(js)]/((v(as) - v(js)) × (v(as) + v(js)))

Δt = d(2v(js))/((v(as))² - (v(js))²)

(2dv(js))/Δt = ((v(as))² - (v(js))²)

(v(js))² + ((2dv(js))/Δt) - (v(as))² = 0

(v(js))² - ((2 × 4300 × v(js))/1.0167) - (930)² = 0

(v(js))² - (8458.7329v(js)) - 864900 = 0

Using the quadratic formula, we have;

v(js) = 103.52 km/h

Therefore, The jet stream speed obtained using the quadratic formula is  103.52 km/h.

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D) 12 sodium, 4 phosphorus, 16 oxygen

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phosphorus: 4P - > 4

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Answer:

shortening its length.

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Answers

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A book sitting on a table has potential energy because of the gravitational pull of Earth. Which of the following would increase the potential energy of the book? A) Sliding it across the table C) Dropping it on the floor B) Opening it to the middle D) Lifting it to a high shelf

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Answer:

D) Lifting it to a high shelf

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It’s good how about you brother and sister
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Answer:

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Answer:

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Explanation:

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Recall the definition of average velocity:

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Answers

Answer:

32m

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Answers

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Answers

Answer:

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Answer:

Objects float in outer space because there is no gravitational force. The farther you get from earth, the less gravity.

Explanation:

Answer:

they float do to gravity

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here if you tossed a ball in the air it would come back down fast in space however it would only float up and stay do to gravity

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Answers

Answer:

Net force = 11340 N

Explanation:

Given that,

Mass of an automobile, m = 2100 kg

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Given parameters:

Mass on earth  = 50kg

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Mass on planet Xenon = ?

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Mass is the amount of matter contained in a particular substance.

Weight is the force on a body and it is derived from the product of mass and acceleration due to gravity.

         Weight  = mass x acceleration due to gravity

Planet Xenon has half the gravitational force of Earth.

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Why is it important for scientists to find better ways to store solar and wind energy?

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Answer:

Energy storage plays an important role in this balancing act and helps to create a more flexible and reliable grid system. For example, when there is more supply than demand, such as during the night when low-cost power plants continue to operate, the excess electricity generation can be used to power storage devices.

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I hope this helps you out and if your feeling generous plz mark brainliest it helps me a lot thank you:)

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1. Tectonic plates that move toward each other ...A Mantle
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Answers

Answer:

Its convergent

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There areas where plates move toward each other and collide Also known as compressional pr destructive boundaries.

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Answers

Answer:

meter, kilogram, second, ampere, Kelvin, candela, and mole.

Explanation:

these are all SI units.

If a car moves at a velocity of 1.45 x102 m/s for 1.8 x103
seconds. How far does the car go?

Answers

Answer:

The answer is

[tex]2.61 \times {10}^{5} \: \: m[/tex]

Explanation:

The distance covered by an object given it's velocity and time taken can be found by using the formula

distance = velocity × time

From the question

velocity = 1.45 × 10² m/s

time = 1.8 × 10³ s

We have

distance = 1.45 × 10² × 1.8 × 10³

We have the final answer as

[tex]2.61 \times {10}^{5} \: \: m[/tex]

Hope this helps you

Picture a long, straight corridor running east-west, with a water fountain located somewhere along it. Starting from the west end of the corridor, a woman walks a short distance east along the corridor and stops before reaching the water fountain. The distance from her to the fountain is twice the distance she has walked. She then continues walking east, passes the water fountain, and stops 60 m from her first stop. Now the distance from her to the fountain is twice the distance from her to the east end of the corridor. How long is the corridor

Answers

Answer:

The corridor's distance is "90 m".

Explanation:

She heads in the east directions but creates the first pause, meaning she crosses the distance 'x' in step 1. Now, provided that perhaps the distance by her to another fountain or waterfall just after the first stop is twice as far away she traveled. Because she moved the distance of 'x,' then, therefore, her distance towards the fountain of '2x.' She casually strolls and once again pauses 60 m beyond her stop. The gap about her to the waterfall during that time approximately twice the distance and her to the eastern end of the hallway.Assume her gap from either the east end of the platform seems to be 'y' at either the second stop, after which '2y' may become the distance between the 2nd pause and the waterfall.

Now,

⇒  [tex]2x + 2y = 60[/tex]

⇒  [tex]x + y = 30[/tex]

The total distance of the corridor will be:

=  [tex]x + 2x + 2y + y[/tex]

=  [tex]3\times (x + y)[/tex]

=  [tex]3\times 30[/tex]

=  [tex]90 \ m[/tex]

A bowling ball of mass m = 1.7 kg drops from a height h = 14.2 m. A semi-circular tube of radius r = 6.2 m rest centered on a scale. Write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the variables in the problem statement.

Answers

Answer:

W_net = mg + 2mgh/r

Explanation:

The forces applied in this motion of the bowling ball are both gravitational and centripetal forces.

Now, gravitational force is; F_g = mg

While centripetal force is; F_c = mv²/r

Since we want to express the net force in terms of the variables in the statement and we are not given "v", let's find an expression of v with the variables given.

Now, from Newton's equation of motion, at initial velocity of 0, v² = 2gh.

Thus;

F_c = 2mgh/r

Where;

m is ball mass

r is tube radius

h is fall height

Thus, the net force will be;

F_net = F_g + F_c

Now, Net force would be equal to the net weight that will be read on the scale.

Thus;

W_net = F_net = F_g + F_c

W_net = mg + 2mgh/r

At its lowest point, the net force of the bowling ball is equal to its net weight and this is given by [tex]F_{net} = mg + \frac{2mgh}{r}[/tex]

Given the following data:

Mass, m = 1.7 kg.Height, h = 14.2 meters.Radius, r = 6.2 meters.

To write an expression for the reading of the scale when the bowling ball is at its lowest point, in terms of the given variables:

The forces acting on the ball.

In this scenario, there are two (2) forces acting on the bowling ball and these include:

Centripetal forceGravitational force

Mathematically, centripetal force is given by this formula:

[tex]F_c = \frac{mv^2}{r}[/tex]     .....equation 1.

Mathematically, gravitational force is given by this formula:

[tex]F_g= mg[/tex]    ....equation 2.

Where:

m is the mass.g is the acceleration due to gravity.v is the velocity.

Next, we would derive an expression for the velocity of the ball by applying the Law of Conservation of energy:

[tex]P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\V^2=2gh[/tex] .....equation 3.

Substituting eqn. 3 into eqn. 2, we have:

[tex]F_c = \frac{m(2gh)}{r}\\\\F_c = \frac{2mgh}{r}[/tex]

At its lowest point, the net weight of the bowling ball is equal to its net force and this is given by this mathematical expression:

[tex]W_{net} = F_{net} = F_g + F_c\\\\F_{net} = mg + \frac{2mgh}{r}[/tex]

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