Lines $m_{1}$, $m_{2}$, $l_{1}$ and $l_{2}$ are coplanar, and they are drawn such that $l_{1}$ is parallel to $l_{2}$, and $m_{2}$ is perpendicular to $l_{2}$. If the measure of angle 1 is 50 degrees, what is the measure in degrees of angle 2 in the figure below?

a) [tex]\frac{8}{2}[/tex]

b) [tex]\frac{9}{4}[/tex]

c) [tex]\frac{3}{-1}[/tex]

Step-by-step explanation:

[tex]a + b = 6[/tex]

[tex]ab = 1 \times 5 = 5[/tex]

[tex]a = 1 \: \: \: \: \: \: \: \: b = 5[/tex]

[tex]( {x}^{2} + x) + (5x + 5)[/tex]

[tex]x(x + 1) + 5(x + 1)[/tex]

[tex](x + 1)(x + 5)[/tex]

Hope this is correct and helpful

HAVE A GOOD DAY!

Answer:

(x - 7)² + (y - 4)² = 49

Step-by-step explanation:

Given

Equation: x² + y² = 49

Required:

New Equation when translated 7 units right and 4 units up

Taking it one step at a time.

When the equation is translated 7 units right, this implies a negative unit along the x axis.

The equation becomes

(x - 7)² + y² = 49

When the equation is translated 4 units up, this implies a negative unit along the y axis.

(x - 7)² + (y - 4)² = 49

The expression can be further simplified but it's best left in the form of

(x - 7)² + (y - 4)² = 49

Answer:

A.) Mean = 237.9

B.) Median = 240

C.) Mode = 199

D.) Midrange = 239.5

Step-by-step explanation:

The given data are :

293 255 264 240 190 295 199 184 293 205 199

The mean = (sum of X) / f

Where frequency f = 11

X = 293 + 255 + 264 + 240 + 190 + 295 + 199 + 184 + 293 + 205 + 199

X = 2617

Substitute X and f into the formula

Mean = 2617/11

Mean = 237.9 approximately

B.) To get the median, you need to first rearrange the data, then pick the middle number.

184 190 199 199 205 240 255 264 293 293 295

The median = 240

C.) The mode is the highest frequency. That is the most occuring number

Mode = the two most occuring numbers are 199 and 293

D.) Range = highest number - lowest number

But midrange = (highest number + lowest number ) ÷ 2

Highest number = 295

Lowest number = 184

Substitute into the formula

Midrange = (295 + 184)/2

Midrange = 479/2

Midrange = 239.5

Answer:

Sine angle of <ACB = 38.68°

Step-by-step explanation:

Hello,

To solve this problem, we need a good representation of the sides and the angle.

See attached document for better illustration.

Assuming it's a right angled triangle,

AC = hypothenus

AB = opposite

BC = adjacent

AC = 40

BC = 25

AB = 25

From trigonometric ratios

Sinθ = opposite/ hypothenus

Sinθ = AB / AC

Sinθ = 25 / 40

Sinθ = 0.625

θ = sin⁻¹0.625

θ = 38.68°

Sine angle of <ACB = 38.68°

Answer:  243 cm²

Step-by-step explanation:  If the diameter is 18, the radius is 9. Each square is  9×9, so 81 cm² for each.   Multiply:  81×3 = 243

Or take the length times width  to get area  27×9= 243

Answer:

Option B.

Step-by-step explanation:

From the given venn diagram it is clear that

[tex]A={1,2}[/tex]

[tex]B={1,2,3,4,5,6}[/tex]

[tex]A\cap B={1,2}[/tex]

Since the intersection of A and B is non-empty, therefore by conditional probability

[tex]P(B|A)=\dfrac{P(A\cap B)}{P(A)}[/tex]

[tex]P(B|A)\cdot P(A)=P(A\cap B)[/tex]

[tex]P(A\cap B)=P(B|A)\cdot P(A)[/tex]

Therefore, the correct option is B.

Replace f(x) with 0 and solve for x. We do this because the x intercepts always occur when y = 0. Keep in mind that y = f(x).

f(x)=x^3-9x^2+20x

0=x^3-9x^2+20x

x^3-9x^2+20x = 0

x(x^2-9x+20) = 0 .... factor out GCF x

x(x-5)(x-4) = 0 ... factor the stuff inside

x = 0 or x-5 = 0 or x-4 = 0 ... zero product property

x = 0 or x = 5 or x = 4

Answer:

1

Step-by-step explanation:

There is only one 3 on the cube

Answer:

Simply subtract the sum of the the three angles given from 360° in order to get the measure of the fourth angle!

Step-by-step explanation:

Answer:

[tex]\boxed{\sqrt{37} }[/tex]

Step-by-step explanation:

Use Pythagorean theorem.

Create a right triangle, with legs of length 6 and 1 units. Find the length of hypotenuse.

[tex]6^2+1^2 =c^2 \\36+1=c^2 \\37=c^2 \\c=\sqrt{37}[/tex]

Answer:

When you use Pythagorean theorem, the answer is √37.

Step-by-step explanation:

Answer:

3. time = 6.4999  approximately 6.5 years

4. $2235.35

5.  $ 3950

Step-by-step explanation:

4. amount of interest =  final amount - principle= 7535.35 - 5300 = 2235.35

5. principle = final amount - interest earned = 4435.25 - 485.25 = 3950

Answer:

2850

Step-by-step explanation:

We know that only 19% of people prefer the sedans, so we have to find 19% of 15,000. Set up a proportion: [tex]\frac{19}{100}=\frac{x}{15000}[/tex], cross multiply and get 2850.

Answer:

2850 sedans per month

Step-by-step explanation:

19 % want sedans

They expect to sell 15000 cars

Take the number of cars and multiply by the percent sedans

19% * 15000

Change to decimal form

.19*15000

2850

Answer:

The number is 3

Step-by-step explanation:

The fraction is 11/36

let

x = no. added to the numerator

2x = no. added to denominator

We have,

x+11/2x+36=1/3

Cross multiply

3(x+11) = (2x + 36)

3x + 33 = 2x + 36

Collect like terms

3x - 2x = 36 - 33

x=3

The number is 3

Check:

3+11/6+36=1/3

14/42=1/3

Answer:

The Answer is the first option

Step-by-step explanation:

If you take the 3x-4>5

than: 3x>5+4

3x>9

x>9/3

x>3

Answer:

C) Yes, since the slopes are the same and the y-intercepts are different.

Step-by-step explanation:

You need to have both equations in slope-intercept form.

4x - 6y = -6

-6y = -4x - 6

y = 2/3x + 1

The two equations are

y = 2/3x + 1

y = 2/3x - 17

For lines to be parallel, the slopes must be equal.  The y-intercepts don't matter.

Since the lines have the same slopes but different y-intercepts the answer is C.

Step-by-step explanation:

The coordinates of the feasible region are:(In clockwise direction)

(200, 200)

(300, 200)

(500, 0)

(300, 0)

Answer:

if its according to the graph but not according to the function then

domain = {x:-4<x<8}

range = {y:y<16}

Answer:

a) [tex]\boxed{4m^2+20m+25}[/tex]

b) [tex]\boxed{m^2-m+\frac{1}{4} }[/tex]

Step-by-step explanation:

a) [tex](2m+5)^2[/tex]

Using formula [tex](a+b)^2 = a^2+2ab+b^2[/tex]

=> [tex](2m)^2 + 2(2m)(5)+(5)^2[/tex]

=> [tex]4m^2+20m+25[/tex]

b) [tex](m-\frac{1}{2} )^2[/tex]

Using Formula [tex](a-b)^2 = a^2-2ab+b^2[/tex]

=> [tex](m)^2 - 2(m)(\frac{1}{2} ) + (\frac{1}{2} )^2[/tex]

=> [tex]m^2-m+\frac{1}{4}[/tex]

Answer:

a) [tex]\boxed{4m^2 + 20m + 25}[/tex]

b) [tex]\boxed{m^2 - m + \frac{1}{4} }[/tex]

Step-by-step explanation:

[tex](2m + 5)^2[/tex]

[tex](2m + 5) (2m + 5)[/tex]

Use FOIL method.

[tex]2m(2m + 5)+5(2m + 5)[/tex]

[tex]4m^2 + 10m + 10m + 25[/tex]

[tex]4m^2 + 20m + 25[/tex]

[tex](m - \frac{1}{2} )^2[/tex]

[tex](m- \frac{1}{2})(m- \frac{1}{2})[/tex]

Use FOIL method.

[tex]m(m- \frac{1}{2})- \frac{1}{2}(m- \frac{1}{2})[/tex]

[tex]m^2- \frac{1}{2} m- \frac{1}{2}m+ \frac{1}{4}[/tex]

[tex]m^2-m+ \frac{1}{4}[/tex]

Answer:

(a).   y'(1)=0  and    y'(2) = 3

(b).  [tex]$y'(t)=kb2t\cos(bt^2)$[/tex]

(c).  [tex]$ b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]

Step-by-step explanation:

(a). Let the curve is,

[tex]$y(t)=k \sin (bt^2)$[/tex]

So the stationary point or the critical point of the differential function of a single real variable , f(x) is the value [tex]x_{0}[/tex]  which lies in the domain of f where the derivative is 0.

Therefore,  y'(1)=0

Also given that the derivative of the function y(t) is 3 at t = 2.

Therefore, y'(2) = 3.

(b).

Given function,    [tex]$y(t)=k \sin (bt^2)$[/tex]

Differentiating the above equation with respect to x, we get

[tex]y'(t)=\frac{d}{dt}[k \sin (bt^2)]\\ y'(t)=k\frac{d}{dt}[\sin (bt^2)][/tex]

Applying chain rule,

[tex]y'(t)=k \cos (bt^2)(\frac{d}{dt}[bt^2])\\ y'(t)=k\cos(bt^2)(b2t)\\ y'(t)= kb2t\cos(bt^2)[/tex]  

(c).

Finding the exact values of k and b.

As per the above parts in (a) and (b), the initial conditions are

y'(1) = 0 and y'(2) = 3

And the equations were

[tex]$y(t)=k \sin (bt^2)$[/tex]

[tex]$y'(t)=kb2t\cos (bt^2)$[/tex]

Now putting the initial conditions in the equation y'(1)=0

[tex]$kb2(1)\cos(b(1)^2)=0$[/tex]

2kbcos(b) = 0

cos b = 0   (Since, k and b cannot be zero)

[tex]$b=\frac{\pi}{2}$[/tex]

And

y'(2) = 3

[tex]$\therefore kb2(2)\cos [b(2)^2]=3$[/tex]

[tex]$4kb\cos (4b)=3$[/tex]

[tex]$4k(\frac{\pi}{2})\cos(\frac{4 \pi}{2})=3$[/tex]

[tex]$2k\pi\cos 2 \pi=3$[/tex]

[tex]2k\pi(1) = 3$[/tex]  

[tex]$k=\frac{3}{2\pi}$[/tex]

[tex]$\therefore b = \frac{\pi}{2} \text{ and}\ k = \frac{3}{2\pi}$[/tex]

The y'(1) =0, y'(2) = 3, and the  [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]  and value of b and k are [tex]\pi/2[/tex]  and  [tex]3/2\pi[/tex] respectively.

It is given that the curve  [tex]\rm y(t) = ksin(bt^2)[/tex]

It is required to find the critical point, first derivative, and smallest value of b.

It is defined as a special type of relationship and they have a predefined domain and range according to the function.

We have a curve:

[tex]\rm y(t) = ksin(bt^2)[/tex]

Given that the first critical point of y(t) for positive t occurs at t = 1

First, we have to find the first derivative of the function or curve:

[tex]\rm y'(t) = \frac{d}{dt} (ksin(bt^2))[/tex]

[tex]\rm y'(t) = k\times2bt\times cos(bt^2)[/tex]   [ using chain rule]

[tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]

y(0) = 0

y'(0) = 0

The critical point is the point where the derivative of the function becomes 0 at that point in the domain of a function.

From the critical point y'(1) = 0 ⇒  [tex]\rm kb2 \ cos(b) =0[/tex]

k and b can not be zero

[tex]\rm cos(b) = 0[/tex]

b = [tex]\rm \frac{\pi}{2}[/tex]

and y'(2) =3

[tex]\rm y'(2) = kb2\times 2 \times cos(b\times2^2) =3\\\\\rm 4kb \ cos(4b) =3[/tex](b =[tex]\rm \frac{\pi}{2}[/tex])

[tex]\rm 4k\frac{\pi}{2} \ cos(4\frac{\pi}{2} ) =3\\\\\rm2 \pi kcos(2\pi) = 3[/tex]

[tex]\rm2 \pi k\times1) = 3\\\rm k = \frac{3}{2\pi}[/tex]

Thus, y'(1) =0, y'(2) = 3, and the  [tex]\rm y'(t) = kb2t \ cos(bt^2)[/tex]  and value of b and k are [tex]\pi/2[/tex]  and  [tex]3/2\pi[/tex] respectively.

Learn more about the function here:

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Answer:

A

Step-by-step explanation:

This shape is a trapezoid. We can divide into two parts: a triangle and a rectangle.

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let A' be the area of the triangle.

● A'= (b*h)/2

b is the base and h is teh heigth.

b= 26-20 = 6 mm

● A'= (6*14)/2 = 42 mm^2

●●●●●●●●●●●●●●●●●●●●●●●●

Let A" be the area of the rectangle.

A"= L*w

L is the length and w is the width.

A"= 14*20

A"= 280 mm^2

■■■■■■■■■■■■■■■■■■■■■■■■■■

Let A be the area of the trapezoid.

A= A'+A"

A= 42+280

A= 322 mm^2

Answer:

Approximatley 5.8 units.

Step-by-step explanation:

We are given two angles, ∠S and ∠T, and the side opposite to ∠T. We need to find the unknown side opposite to ∠S. Therefore, we can use the Law of Sines. The Law of Sines states that:

[tex]\frac{\sin(A)}{a}=\frac{\sin(B)}{b} =\frac{\sin(C)}{c}[/tex]

Replacing them with the respective variables, we have:

[tex]\frac{\sin(S)}{s} =\frac{\sin(T)}{t} =\frac{\sin(R)}{r}[/tex]

Plug in what we know. 20° for ∠S, 17° for ∠T, and 5 for t. Ignore the third term:

[tex]\frac{\sin(20)}{s}=\frac{\\sin(17)}{5}[/tex]

Solve for s, the unknown side. Cross multiply:

[tex]\frac{\sin(20)}{s}=\frac{\sin(17)}{5}\\5\sin(20)=s\sin(17)\\s=\frac{5\sin(20)}{\sin(17)} \\s\approx5.8491\approx5.8[/tex]

Answer: 320 students

Step-by-step explanation:

From the question, we are informed that a school counselor surveyed 90 randomly selected students about thé langages they speak and thé students surveyed 16 speak more than one langage fluently. This means that 16/90 speak more than one language.

When 1800 students are surveyed, the number of students that can be expected to speak more than one langage fluently will be:

= 16/90 × 1800

= 16 × 20

= 320 students

Answer:

b=-a

Step-by-step explanation:

Answer:

12/25

Step-by-step explanation:

There were a total of 48 males, so 48/100 = 12/25.

+---------------+------+--------+-------+

|           | Male | Female | Total |

+---------------+------+--------+-------+

| Prefers Dogs  | 36 | 20 | 56   |

+---------------+------+--------+-------+

| Prefers Cats  | 10   | 26 | 36   |

+---------------+------+--------+-------+

| No Preference | 2 | 6  | 8   |

+---------------+------+--------+-------+

| Total         | 48   | 52     | 100   |

+---------------+------+--------+-------+

Answer:

675 – (15-12) ³+3

675-3³ +3

675-27+3

651

Step-by-step explanation:

The value of the given expression is 666 which is the correct answer that would be an option (C).

PEMDAS rule states that the order of operation starts with the calculation enclosed in brackets or the parentheses first. Exponents (degrees or square roots) are then operated on, followed by multiplication and division operations, and then addition and subtraction.

We have been given the expression below as:

675 – (15-12)³ ÷ 3

Using the PEMDAS rule to determine the evaluation of the given expression  

⇒ 675 – (15-12)³ ÷ 3

Apply the subtraction operation,

⇒ 675 - (3)³ ÷ 3

⇒ 675 - 27 ÷ 3

⇒ 675 - 27 / 3

Apply the division operation,

⇒ 675 - 9

Apply the subtraction operation,

⇒ 666

Therefore, the value of the given expression would be 666,

Learn more about the PEMDAS rule here :

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Answer:

X rounded to the nearest degree can me calculated based on parallel lines or if there is a straight line bisected by a line, 180 degress is a staright line. There is not enough info nor a picture to give a direct answer.

Answer:

its D

Step-by-step explanation:

Answer:

2

Step-by-step explanation:

green

Answer: 2

Step-by-step explanation:

Answer:

Step by step explanation

1. [tex] \frac{1}{1 - x} + \frac{x}{ {x}^{2} - 1} [/tex]

Use [tex] \frac{ - a}{b} = \frac{a}{ - b} = - \frac{a}{b} [/tex] to rewrite the fractions

[tex] - \frac{1}{x - 1} + \frac{x}{(x - 1)(x + 1)} [/tex]

Write all numerators above the Least Common Denominator ( X - 1 ) ( X + 1 )

[tex] \frac{ - (x + 1) + x}{(x - 1)(x + 1)} [/tex]

When there is a ( - ) in front of an expression in parentheses , change the sign of each term in the expression

[tex] \frac{ - x - 1 + x}{(x - 1)(x + 1)} [/tex]

Using [tex](a - b)(a + b) = {a}^{2} - {b}^{2} [/tex] , simplify the product

[tex] \frac{ - x - 1 + x}{ {x}^{2} - 1 } [/tex]

Since two opposites add up to zero, remove them from the expression

[tex] \frac{ - 1}{ {x}^{2} - 1} [/tex]

So, Option A is the right option.

___________________________________

2.

[tex] \frac{ {x}^{2} - x - 12}{ {x}^{2} - 16} - \frac{1 - 2x}{x + 4} [/tex]

Write - X as a difference

[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{ {x}^{2} - 16 } - \frac{1 - 2x}{x + 4} [/tex]

Using [tex] {a}^{2} - {b}^{2} = (a - b)(a + b)[/tex] , factor the expression

[tex] \frac{ {x}^{2} + 3x - 4x - 12 }{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Factor the expression

[tex] \frac{x(x + 3) - 4(x + 3)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Factor out X+3 from the expression

[tex] \frac{(x + 3)(x - 4)}{(x - 4)(x + 4)} - \frac{1 - 2x}{x + 4} [/tex]

Reduce the fraction with x-4

[tex] \frac{x + 3}{x + 4} - \frac{1 - 2x}{x + 4} [/tex]

Write all the numerators above the common denominator

[tex] \frac{x + 3 - ( 1- 2x)}{x + 4} [/tex]

When there is a (-) in front of an expression in parentheses, change the sign of each term in the expression

[tex] \frac{x + 3 - 1 + 2x}{x + 4} [/tex]

Collect like terms

[tex] \frac{3x + 3 - 1}{x + 4} [/tex]

Subtract the numbers

[tex] \frac{3x + 2}{x + 4} [/tex]

Undefined at,

X + 4 = 0

Move constant to R.H.S and change its sign

[tex]x = 0 - 4[/tex]

Calculate

[tex]x = - 4[/tex]

So, the answer is :

[tex] \frac{3x + 2}{x + 4} [/tex] , undefined at X = -4 and 4

Hope this helps..

Best regards!!

Answer:

Look at the image below