The critical points of h(x,y) occur wherever its partial derivatives [tex]h_x[/tex] and [tex]h_y[/tex] vanish simultaneously. We have
[tex]h_x = 8-4y-8x = 0 \implies y=2-2x \\\\ h_y = 10-4x-12y^2 = 0 \implies 2x+6y^2=5[/tex]
Substitute y in the second equation and solve for x, then for y :
[tex]2x+6(2-2x)^2=5 \\\\ 24x^2-46x+19=0 \\\\ \implies x=\dfrac{23\pm\sqrt{73}}{24}\text{ and }y=\dfrac{1\mp\sqrt{73}}{12}[/tex]
This is to say there are two critical points,
[tex](x,y)=\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\text{ and }(x,y)=\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)[/tex]
To classify these critical points, we carry out the second partial derivative test. h(x,y) has Hessian
[tex]H(x,y) = \begin{bmatrix}h_{xx}&h_{xy}\\h_{yx}&h_{yy}\end{bmatrix} = \begin{bmatrix}-8&-4\\-4&-24y\end{bmatrix}[/tex]
whose determinant is [tex]192y-16[/tex]. Now,
• if the Hessian determinant is negative at a given critical point, then you have a saddle point
• if both the determinant and [tex]h_{xx}[/tex] are positive at the point, then it's a local minimum
• if the determinant is positive and [tex]h_{xx}[/tex] is negative, then it's a local maximum
• otherwise the test fails
We have
[tex]\det\left(H\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)\right) = -16\sqrt{73} < 0[/tex]
while
[tex]\det\left(H\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)\right) = 16\sqrt{73}>0 \\\\ \text{ and } \\\\ h_{xx}\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-8 < 0[/tex]
So, we end up with
[tex]h\left(\dfrac{23+\sqrt{73}}{24},\dfrac{1-\sqrt{73}}{12}\right)=-\dfrac{4247+37\sqrt{73}}{72} \text{ (saddle point)}\\\\\text{ and }\\\\h\left(\dfrac{23-\sqrt{73}}{24},\dfrac{1+\sqrt{73}}{12}\right)=-\dfrac{4247-37\sqrt{73}}{72} \text{ (local max)}[/tex]
10 pounds of egg whites. You have 6 ounces to make one serving. How many servings can you make?
In ΔPQR, sin P = 0.2, sin R = 0.2 and r = 12. Find the length of p.
9514 1404 393
Answer:
p = 12
Step-by-step explanation:
The sines of the opposite angles are the same, so the lengths of the sides are the same.
p = 12
_____
The law of sines tells you ...
p/sin(P) = r/sin(R)
p/0.2 = 12/0.2 . . . . . . substitute given values
Multiply by 0.2 to get ...
p(0.2/0.2) = 12(0.2/0.2)
p = 12
Name the red line. Select ALL that apply.
1. PN
2. PW
3. WN
4. line d
5. NW
6. line P
Answer:
1. PN
Step-by-step explanation:
Complete the equations.
28{,}770\div 10^2 =28,770÷10
2
=28, comma, 770, divided by, 10, squared, equals
28{,}770\div 10^3 =28,770÷10
3
=28, comma, 770, divided by, 10, cubed, equals
28{,}770\div 10^4 =28,770÷10
4
=28, comma, 770, divided by, 10, start superscript, 4, end superscript, equals
Answer:
a) 28,770 ÷ 10 ^ 2 = 287.7
b) 28,770 ÷ 10 ^ 3 = 28.77
c) 28,770 ÷ 10 ^ 4 = 2.877
One year, an athlete won a gold medal with a long jump of some
meters. Several years later, another athlete won a gold medal with a
long jump of 7.12 meters. The second jump was 0.13 meters longer
than the first. How long was the first jump? Write an equation
and solve.
Answer:
6.99 meters
Step-by-step explanation:
For this we have to use subtraction:
So if the second jump was .13 meters longer then the first and we know the second jump was 7.12 meters, we have to subtract 7.12 by .13 to get the length of his/her's first long jump. So our equation is 7.12-.13=length of first jump. So we end up getting 6.99=length of first jump.
Hope this helps! :D
A certain product is marked down to $64.75 after a 12.5% decrease. Determine the original price. (4 points)
$72.85
$74.00
$76.6
ANSWER QUICK PLS!
if the actual distance from San Antonio to Houston is approximately 188 miles use the length of the line segments indicated in the figure along with the similar triangles to approximate.
a: The actual distance from Dallas to Houston = _ miles
b: The actual distance from Dallas to San Antonio = _ miles
9514 1404 393
Answer:
a) 235 mi
b) 259 mi
Step-by-step explanation:
The scale factor from the map to the real world is apparently ...
(SA-H actual)/(SA-H map) = (188 mi)/(3 in) = 62 2/3 mi/in
Then the actual distance from Dallas to Houston is ...
(3.75 in)(62 2/3 mi/in) = 235 mi
And from Dallas to San Antonio, the distance is ...
(4.125 in)(62 2/3 mi/in) = 258.5 mi ≈ 259 mi
Simplify. 3√-28
A 2i√7
B 12i√7
C 61√7
D -6i√7
Answer:
C
Step-by-step explanation:
We want to simplify the expression:
[tex]\displaystyle 3 \sqrt{-28}[/tex]
Rewrite:
[tex]\displaystyle = 3 \sqrt{ 4\cdot 7 \cdot -1}[/tex]
Rewrite:
[tex]\displaystyle = 3 \cdot \sqrt{4} \cdot \sqrt{7} \cdot \sqrt{-1}[/tex]
Simplify. Let i = √(-1). Hence:
[tex]\displaystyle = 3 \cdot \left(2\right) \cdot \left(i\right) \cdot \sqrt{7}[/tex]
Multiply:
[tex]\displaystyle = 6i\sqrt{7}[/tex]
In conclusion, our answer is C.
S
Tami put 14 chocolate chips in a batch
of 10 cookies. How many chocolate
chips will be used with 40 cookies?
Chocolate
Chips
14 28 42 [?]
Cookies 10 20 30 40
Answer:
56 chocolate chips will be used with 40 cookies.
Step-by-step explanation:
14 chocolate chips = 10 cookies
? chocolate chips = 40 cookies
Variable x = number of chocolate chips for 40 cookies
14/10 = x/40
Cross multiply:
14 × 40 = 10 × x
560 = 10x
56 = x
What is the measurement??
Answer:
83°
.......................
Answer:
83
Step-by-step explanation:
Pls help A card is drawn from a standard deck of 52 cards. What is the probability of drawing a face card (jack, king, or queen) or a black card?
Answer:
probability is 32/52 or about 0.615
Step-by-step explanation:
There are 12 face cards
of the remaining 52 - 12 = 40 cards, half of them are black
so 12 + 40/2 = 32 cards would be considered successful
what is the answer for this
Answer: The highlighted digit 8 is in the tens place. The value of the 8 is 80
Step-by-step explanation:
The value of the 8 is 80 becuse it is in the tens place.
Calculus please help
Answer:
The balloon is rising at a rate of 50π/3 feet per minute.
Step-by-step explanation:
A weather balloon is rising vertically while being observed from a point who is exactly 300 feet away from the spot directly beneath the ground.
This is represented in the diagram below.
We want to find the rate at which the balloon is rising (i.e. find dh/dt) when the angle between the ground and the observer is π/6 (i.e. when θ = π/6), and is increasing at a rate of π/24 radians per minute (i.e. when dθ/dt = π/24).
Write a ratio relating the variables:
[tex]\displaystyle \tan \theta = \frac{h}{300}[/tex]
Take the derivative of both sides with respect to t:
[tex]\displaystyle \frac{d}{dt}\left[ \tan\theta\right] = \frac{d}{dt}\left[ \frac{h}{300}\right][/tex]
Implicitly Differentiate:
[tex]\displaystyle \sec^2\theta \cdot \frac{d\theta}{dt} = \frac{1}{300} \frac{dh}{dt}[/tex]
Substitute in known values:
[tex]\displaystyle \sec^2 \left(\frac{\pi}{6}\right) \left(\frac{\pi}{24}\right) = \frac{1}{300} \frac{dh}{dt}[/tex]
Solve for dh/dt:
[tex]\displaystyle \begin{aligned} \frac{dh}{dt} &= 300\left(\sec^2\left(\frac{\pi}{6}\right)\left(\frac{\pi}{24}\right)\right) \\ \\ &= 300\left(\frac{4}{3}\right)\left(\frac{\pi}{24}\right) \\ \\ &= \frac{50\pi}{3} \text{ feet per minute}\end{aligned}[/tex]
In conclusion, the balloon is rising at a rate of 50π/3 feet per minute.
I need help on this problem expand 2-x(x+6)
(This is distributive property)
Answer:
2-x^2-6x
Step-by-step explanation:
2-x(x+6)
2-x^2-6c
Can someone please explain
Answer:
r = 5
Step-by-step explanation:
the sine rules formula :
sin Q/q = sin R/r
=> r = q× sin R / sin Q
= 6× ⅓ / (2/5)
= 2 /(2/5)
= 2× 5/2
= 5
Answer:
r = 5
Step-by-step explanation:
Sine trigonometric ratio
[tex]\sf \sin(\theta)=\dfrac{O}{H}[/tex]
where:
[tex]\theta[/tex] is the angleO is the side opposite the angleH is the hypotenuse (the side opposite the right angle)The sides of a triangle are opposite their angles. Therefore, in ΔPQR:
⇒ side r is opposite angle R
⇒ side p is opposite angle P
⇒ side q is opposite angle Q
Using the given ratio of sin Q:
[tex]\sf \implies \sin Q=\dfrac{q}{H}=\dfrac{2}{5}[/tex]
Substitute the given value of q = 6 and solve for H:
[tex]\sf \implies \dfrac{6}{H}=\dfrac{2}{5}[/tex]
[tex]\sf \implies H=6 \cdot\dfrac{5}{2}[/tex]
[tex]\sf \implies H=15[/tex]
Using the given ratio of sin R:
[tex]\implies \sf \sin R=\dfrac{r}{H}=\dfrac{1}{3}[/tex]
Substitute the found value of H and solve for r:
[tex]\implies \sf \dfrac{r}{15}=\dfrac{1}{3}[/tex]
[tex]\implies \sf r=15 \cdot\dfrac{1}{3}[/tex]
[tex]\implies \sf r=5[/tex]
Learn more about trigonometric ratios here:
https://brainly.com/question/26861422
https://brainly.com/question/27938163
linear equation 5+3x=17
Answer:
x=4
Step-by-step explanation:
5+3x=17
-5 -5
3x=12
3 3
x=4
Answer:
x = 4
Step-by-step explanation:
[tex]5+3x=17\\\\3x=12\\\\x=4[/tex]
The graph of a square root function has a domain of (0, ∞) and range of [1,∞). In two or more complete sentences, explain how the given range of the function can help you to the maximum or minimum y-value of the function.
Answer:
As per given domain and range we can conclude that:
The function has positive domain only, since x = (0, ∞).The function has minimum value of 1 and no maximum value, since y = [1, ∞)Here
[tex]\\ \sf\longmapsto Domain=(0,\infty)[/tex]
[tex]\\ \sf\longmapsto Range=(1,\infty)[/tex]
The function has positive integral values as it lies in 1st Quadrant
[tex]\\ \sf\longmapsto (x,y)=(1,\infty)[/tex]
It has minimum value 1It has infinite or no maximum valueshiiiiiiiiiiiiiiiiiiii my frndz give me the answer3x/4-2y/3=5
2x/5+3y/5=17
Answer:
[tex]thank \: you[/tex]
PLEASE HELP
write and solve an equation to find the value of X. please explain in details and show your work!
Answer:66.5 degrees
Step-by-step explanation:
Write an
equation in slope intercept form y = mx +b.
6) slope = 4, y-intercept = -3
Answer:
y = 4x - 3
Step-by-step explanation:
Slope intercept form is made up of these components:
y = outputm = slopex = inputb = y-interceptThe question gives you the slope and the y-intercept. Now all you need to do is substitute the values for the variables. Therefore, the equation is y = 4x - 3.
PLEASEEEE HELPPP WITH THSI LLALST ONEEEE
Answer:
m∠AKD = 46°
Step-by-step explanation:
Answer:
<AKD = 46°Step-by-step explanation:
Given,
Measure of <AKG = 133°
So,
<AKG = <AKD + <DKG (As both together combine to form one <AKG as shown)
=> 133° = <AKD + 87°
=> <AKD = 133° - 87°
=> <AKD = 46° (Ans)
help please someone
Answer:
(fog)(x) =x –14
(gof)(x) =x
Step-by-step explanation:
[tex](fog)(x) = f(g(x)) \\ = 8( \frac{x - 7}{8} ) - 7 \\ = x - 7 - 7 \\ = x - 14[/tex]
[tex](gof)(x) = g(f(x)) \\ = \frac{(8x - 7) + 7}{8} \\ \\ = \frac{8x}{8} \\ \\ = x[/tex]
find the value of 3²×2³
Answer : 72
Step-by-step explanation:
It's above in the pic .
The point that is 7 units to the left of the y-axis and 5 units above the x-axis
Answer:
(-7, 5)
Step-by-step explanation:
Answer:
(-7,5)
Step-by-step explanation:
have a nice day
–
5z2–7z2
Simplified
Answer:
-12z^2
Brainliest, please!
Step-by-step explanation:
-5z^2 - 7z^2 = -12z^2
9. The length of a garden is 2w + 4 and the width is w. What is the area of the garde
294738917263748hehejshdhf
What is the range of (-1,7)(6,2)(0,4)(5,2)(-3,1)
Answer:
range =(7,2,4,2,1)
if my answer helps you than mark me as brainliest.
I need a answer ASAP what is 1/7 equal to?
Answer:
1/7 = 2/14 = 3/21 = 4/28 = 5/35 = 6/42 = 7/49 = 8/56 = 9/63 = 7/10
Step-by-step explanation:
Find the midpoint of the segment with the given endpoints.
(-7, -9) and (-2,7)
Answer:
(-9/2,-1)
Step-by-step explanation:
Use the midpoint formula to find the midpoint of the line segment.
Given that (7x-8)/(2x-1)(x-2)
Use Partial Fraction Decomposition to Find A and B.
We look for constants a and b such that
[tex]\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac a{2x-1} + \frac b{x-2}[/tex]
Rewrite all terms with a common denominator and set the numerators equal:
[tex]\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)}{(2x-1)(x-2)} + \frac{b(2x-1)}{(x-2)(2x-1)} \\\\ \frac{7x-8}{(2x-1)(x-2)} = \frac{a(x-2)+b(2x-1)}{(2x-1)(x-2)} \\\\ \implies 7x-8 = a(x-2) + b(2x-1) = (a+2b)x - 2a - b[/tex]
Then
a + 2b = 7
-2a - b = -8
Solve for a and b. Using elimination: multiply the first equation by 2 and add it to the second equation:
2 (a + 2b) + (-2a - b) = 2(7) + (-8)
2a + 4b - 2a - b = 14 - 8
3b = 6
b = 2
Then
a + 2(2) = 7 ==> a = 3
and so
[tex]\displaystyle \frac{7x-8}{(2x-1)(x-2)} = \frac 3{2x-1} + \frac 2{x-2}[/tex]
Answer:
a=3
b=2
Do whatever you want with that information^^