Jaoan reads that themass of an average elephant's brain is 3 4/10 kilograms greater than an average man's brain. How many kilograms is an average elephant's brain?

The cost of 15 meters of ribbon at the factory is:

15 meters / 3 meters per $7 = 5 times $7 = $35

The cost of 15 meters of ribbon at the store is:

15 meters x $2.50 per meter = $37.50

Therefore, the amount saved by buying 15 meters of ribbon at the factory rather than at the store is:

$37.50 - $35 = $2.50

Answer:

18.84 kilometers

Step-by-step explanation:

Formula for circumference:  C=2πr

1) find radius

r = d / 2

In this case the diameter is 6 so:

r = 6 / 2

r = 3

2. Plug in your values in the formula:

C = 2 (3.14) (3)

3. Solve (multiply)

C = 2 x 3.14 x 3

C = 18.84

So your answer is 18.84 kilometers, and rounded its 19 kilometers.

Hope this helps :D

A system of inequalities to model this situation is 4x + 9y ≥ 720 and x + y ≤ 110.

The two possible solutions are (80, 40) and (100, 20).

In order to write a linear equation to describe this situation, we would assign variables to the number of student tickets sold and the number of adult tickets sold respectively, and then translate the word problem into a linear equation as follows:

Since each student ticket was sold for $4 and each adult ticket sales to cover the show's costs sells for $9 in order to make a minimum of $720 from show's expenses, a linear equation which can be used to model the situation is given by;

4x + 9y ≥ 720

Additionally, the auditorium can hold no more than 110 people;

x + y ≤ 110

Next, we would use an online graphing calculator to plot the above system of linear equations in order to determine its solution as shown in the graph attached below.

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Without a diagram or additional information, it is impossible to determine the value of the x-coordinate of point A.

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To multiply these fractions, we can simplify each fraction first:

64e^2/5e * 3e/8e = (8*8*e*e)/(5*e) * (3*e)/(2*2*2*e)

Next, we can cancel out common factors between the numerators and denominators:

= (8*8*1*1)/(5*1) * (1*1)/(2*2*2*1)

= 64/5 * 1/8

= 8.

Answer:

24e^2/5e my answer needs to be 20+characters sooooooooooo

1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.

2) . The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.

3) The expanded equation is e² = x² -12x + 36 + h²
4) the expanded equation is a² = b²-x²+32

According to the Pythagorean theorem, the square of the hypotenuse (c) of a right triangle equals the sum of the squares of the other two sides  (a² + b²).

So

1) The relationship between the side lengths in ΔABD is c² = x² + h² by the Pythagorean Theorem.

2) The relationship between the side lengths in Δ CBD is a² = (b-x)² + h² by the Pythagorean Theorem.

3) The equation is e² = (6 - x)² + h² when expanded

e² = 36 - 12x + x² + h²
or

e² = x² -12x + 36 + h²

4) Using this equation, we can solve for h² by subtracting (b-x)² from both sides:

a² - (b-x)² = h²

Now we can substitute this expression for h² into the equation given in step 3

2² = 6² - 2bx + (a² - (b-x)²)

Simplifying this equation, we get:

4 = 36 - 2bx + a² - (b-x)²

Expanding the square term, we get:

4 = 36 - 2bx + a² - (b² - 2bx + x²)

Simplifying further, we get:

4 = 36 - b² + x² + a²

Rearranging, we get:

a² = b² - x² + 32

So the equation expanded  is a² = b² - x² + 32.

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Full Question:

For 1 and 2, see attached image.
3)  The equation e²= (6 – x)² + h² is expanded y to become ?
4) Using the equation from step 1, the equation

2² = 6² - 2bx +32+ h becomes a = 62 - 2bx + 2

by substitution

22 = 62 - 2x + x2 +h?

The functions that represents the cost are

(a) y = 8800, (b) y = 1900 + 4/7x and (c) y = 4800, x ≤ 150;  y = 1200 + 24x x > 150

From the question, we have the following parameters that can be used in our computation:

The graph

The function (a) is a horizontal line that passes through y = 8800

So, the function is

y = 8800

The function (b) is a linear function that passes through

(0, 1900) and (175, 2000)

So, the function is

y = 1900 + 4/7x

The function c is a piecewise function with the following properties

So, the function is

y = 4800, x ≤ 150

y = 1200 + 24x x > 150

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At Burger Heaven, to maximize the total revenue from selling double burgers containing 2 meat patties and 6 pickles, you need to consider the following constraints:

1. Ingredient availability: Ensure that there are enough meat patties and pickles in stock to meet the demand for double burgers.
2. Production capacity: The kitchen staff must be able to efficiently prepare and assemble the double burgers without compromising on quality.

3. Pricing strategy: Set a competitive price for the double burger to attract customers and generate optimal revenue.
4. Demand forecasting: Accurately predict customer demand for the double burger to prevent overstocking or understocking of ingredients, which can impact revenue.

To maximize total revenue at Burger Heaven, follow these steps:

a) Analyze the availability of meat patties and pickles to determine how many double burgers can be made with the current inventory.
b) Evaluate the production capacity of the kitchen staff to ensure that they can efficiently prepare and assemble the double burgers.

c) Research the market to set a competitive price for the double burger, considering the costs of ingredients, labor, and other expenses.
d) Forecast customer demand for the double burger to ensure optimal inventory levels and to meet customer expectations.

By addressing these constraints and following the steps above, Burger Heaven can successfully maximize its total revenue from selling double burgers with 2 meat patties and 6 pickles.

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Your best friend is charging you an annual interest rate of 4% for lending you ₹300 for nine months with a quarterly interest rate of 1%.

The amount a lender charges a borrower for the use of assets, such as money, consumer goods, or physical assets, is known as an interest rate. It is a fraction of the loan's principal, which is the amount borrowed to cover the cost of the purchase or the deposit made with a bank or other financial institution.

If your best friend is charging you an extra ₹3 for every three months that pass before you return the money, then after nine months, you will owe her an extra ₹9 in addition to the original ₹300.

So the total amount you must pay her if you return the ₹300 after nine months would be ₹309.

To calculate the annual rate of interest she is charging you, we can use the formula:

Annual Interest Rate = (Total Interest / Principal) x (12 / Number of Months)

Where the Principal is the original amount borrowed (₹300), the Total Interest is the extra amount you owe her (₹9), and the Number of Months is the time period for which you borrowed the money (9 months).

Plugging in the values, we get:

Annual Interest Rate = (9 / 300) x (12 / 9) = 0.04 or 4%

So, your best friend is charging you an annual interest rate of 4% for lending you ₹300 for nine months with a quarterly interest rate of 1%.

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The complete question is:

You ask your best friend to lend you ₹300 to buy your favourite toy. She says she can lend you the money only if you give her an extra ₹3 for every three months that pass before you return it. What is the total amount you must pay her if you return it after nine months? What is the annual rate of interest she is charging you?

The product of the given expression is 2,916,000,000x³√(9,900x²).

The given expression contains several terms with roots and variables. To simplify and find the product, we'll first multiply the terms with similar roots and variables. The expression is:

√(3x)√5 √(15x)√2 √(30) 3x√5 3√(165x) √10 √6 3x√5 √6 √(10x) √5 √(3x) √10 √6 3x√5 √10 √6 √(3x) √5 √(3x) √10 √6

We can group terms with the same roots and variables together:

(√(3x))⁴ (3x)³ (√5)⁴ (√10)³ (√6)³ √15x √2 √30 √165x

Now, we can simplify each group:

81x³ * 625 * 1000 * 216 * √(2 * 15x * 30 * 165x)

Combine the constants and variables under the root:

81x³ * 625 * 1000 * 216 * √(9,900x²)

Calculate the product of the constants:

13,500,000 * 216 = 2,916,000,000

So, the final simplified expression is:

2,916,000,000x³√(9,900x²)

In summary, the product of the given expression is 2,916,000,000x³√(9,900x²).

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The area of the triangle is (a-6, b-12) square units 6 sq unit.

A triangle is described as  a polygon with three sides having three vertices. The angle formed inside the triangle is equal to 180 degrees.

This means that the sum of the interior angles of a triangle is equal to 180°

Now that we have  the points they make a 3-4-5 triangle.

The two legs are 3 and 4, so the hypotenuse has to be 5.

We  could also use the Pythagorean theorem a² + b² = c² 3² + 4² = c² 25 = c² c = 5

We then calculate the area

Area =1/2 b*h

Area = 1/2(3*4)

Area =  6 sq unit

The area of the triangle is (a-6, b-12) square units 6 sq unit.

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The estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.

Let V = (1/3)πr²h be the volume of the cone, where r and h are the base radius and height of the cone, respectively.

Let dr and dh be the possible errors in the measurements of r and h, respectively.

Then, the actual dimensions of the cone are (r+dr) cm and (h+dh) cm, respectively.

The differential of V is given by:

dV = (∂V/∂r)dr + (∂V/∂h)dh

We have:

∂V/∂r = (2/3)πrh and ∂V/∂h = (1/3)πr²

Substituting the given values, we get:

∂V/∂r = (2/3)π(10 cm)(25 cm) = 500π/3

∂V/∂h = (1/3)π(10 cm)² = 100π/3

Substituting into the differential equation, we get:

dV = (500π/3)dr + (100π/3)dh

Using the given maximum error of 0.1 cm for both r and h, we have:

|dr| ≤ 0.1 cm and |dh| ≤ 0.1 cm

Therefore, the maximum possible error in V is given by:

|dV| = |(500π/3)(0.1 cm) + (100π/3)(0.1 cm)|

|dV| = 50π/3 + 10π/3

|dV| = 60π/3

|dV| = 20π cm³

Therefore, the estimated maximum error in the calculated volume of the cone is 20π cubic centimeters.

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Therefore, the surface area of the mailer is approximately 229.3 square inches.

Total surface area refers to the sum of the areas of all the faces or surfaces of a three-dimensional object. It includes the area of all the faces including the bases, top and sides.

Here,

To find the total surface area of the mailer, we need to find the area of all the faces and then add them up.

First, let's find the area of the rectangular faces. The length of the mailer is 18 inches and the height is 4 inches, so the area of each rectangular face is:

Area of rectangle = length x height

= 18 x 4

= 72 square inches

Since there are 3 rectangular faces, the total area of the rectangular faces is:

Total area of rectangular faces = 3 x 72

= 216 square inches

Next, let's find the area of the triangular faces. The triangular side is 4.7 inches and the base is 5 inches. To find the area of a triangle, we use the formula:

Area of triangle = (1/2) x base x height

where base is the length of the triangle's base and height is the perpendicular distance from the base to the opposite vertex.

To find the height of the triangle, we can use the Pythagorean theorem since we know the length of the triangular side and the height of the mailer. The Pythagorean theorem states that:

c² = a² + b²

where c is the hypotenuse (the triangular side), and a and b are the other two sides (the height of the mailer and the height of the triangle).

Solving for b, we get:

b = √(c² - a²)

= √(4.7² - 4²)

= 2.66 inches

Now we can find the area of each triangular face:

Area of triangle = (1/2) x base x height

= (1/2) x 5 x 2.66

= 6.65 square inches

Since there are 2 triangular faces, the total area of the triangular faces is:

Total area of triangular faces = 2 x 6.65

= 13.3 square inches

Finally, we add up the areas of all the faces to get the total surface area:

Total surface area = area of rectangular faces + area of triangular faces

= 216 + 13.3

= 229.3 square inches (rounded to one decimal place)

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In statistical analysis, the mean absolute deviation (MAD) is a measure of the average distance between each data point and the mean of the data set. For Doctor A's data set on corrective lenses, the MAD is calculated as 0.42, while for Doctor B's data set, it is calculated as 0.38.

This shows that Doctor B's data set has a slightly smaller variation compared to Doctor A's data set.

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The theoretical probability of rolling less than 9 on a 12-sided die is 0.6667 or approximately 67%.

To find the theoretical probability of rolling less than 9 on a 12-sided die, we need to count the number of outcomes that satisfy this condition and divide by the total number of possible outcomes.

There are 8 outcomes that satisfy this condition, namely 1, 2, 3, 4, 5, 6, 7, and 8. The total number of possible outcomes is 12, since the die has 12 sides. Therefore, the theoretical probability of rolling less than 9 on a 12-sided die is:

P(less than 9) = Number of outcomes that satisfy the condition / Total number of possible outcomes

= 8 / 12

= 2 / 3

= 0.6667

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Answer:

Callum’s method is incorrect because he is confusing the conversion of linear units with the conversion of square units. There are indeed 100 cm in 1 m, but when converting square units, you need to square the conversion factor. So 1 m² is equal to (100 cm)² or 10,000 cm². Therefore, 300 cm² is equal to 0.03 m², not 3 m².

Step-by-step explanation:

Answer:

The answer is wrong because the 3m is still squared if you divided it by 100 then it should only be 3m not 3m^2.

Step-by-step explanation:

I am not 100% sure this is correct so please dont get mad at me.

The volume of the larger rectangular box is 125 times the volume of the smaller box.

To compare the volume of the larger rectangular box to the smaller box, we need to consider how the dimensions have changed.

Since the larger box has dimensions 5 times those of the smaller box, let's represent the dimensions of the smaller box as length (L), width (W), and height (H). Therefore, the dimensions of the larger box would be 5L, 5W, and 5H.

Now, let's calculate the volume of both boxes:

1. Volume of the smaller box: V_small = L * W * H
2. Volume of the larger box: V_large = (5L) * (5W) * (5H)

To find the ratio of the larger box's volume to the smaller box's volume, we can divide the volumes:

V_large / V_small = ((5L)*(5W)*(5H)) / (L * W * H)

Notice that L, W, and H can be canceled out:

(5 * 5 * 5) = 125

So, the volume of the larger rectangular box is 125 times the volume of the smaller box.

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Answer:

The first one is - 5 and the other is - 40

Answer:

21.8014 degrees (to 4 decimal places)

Step-by-step explanation:

The equation y=2/5x+9 forms a certain angle with the x-axis.  Note that all lines parallel to y=2/5x+9 also form the same angle with the x-axis, due to Corresponding Angles (the fact that the original line has a y-intercept of 9 is irrelevant).  Therefore, we could simplify this problem slightly by considering the angle that y=2/5x (a y-intercept of 0) forms with the x-axis.

To find the angle that this line makes with the x-axis, we'll need the vertex (the origin -- let's call this point "B"), and one point on each of two rays from the vertex (Let Ray #1 be the ray from the origin directly to the right; and let Ray #2 be the ray from the origin extending into Quadrant I -- up and to the right, along the equation y=2/5x).

One point on Ray #1 is (5,0) -- it is on the positive x-axis.  Call this point "A"

One point on Ray #2 is (5,2) -- inputting "5" for x, the result for y is "2"  Call this point "C"

To find the angle (Angle ABC), observe that the three points form a right triangle (the angle CAB is a right angle because the two lines are perpendicular).

To solve for [tex]\angle ABC[/tex], recall the definition of the tangent function:

[tex]tan(\theta)=\dfrac{opposite}{adjacent}[/tex]

The Opposite side, side AC, is just the height (or the y-value) of point C.  So, opposite = 2.

The Adjacent side, side BA, is just the x-coordinate of point A (and also point C).  So adjacent = 5.

Substituting these known values into the tangent function, we get the following:

[tex]tan(m\angle ABC)=\dfrac{2}{5}[/tex]

To solve for the measure of angle ABC, we need to apply the inverse tangent function (also known as arctangent).

[tex]arctan(tan(m\angle ABC)=arctan(\dfrac{2}{5})[/tex]

The left side simplifies because they are inverse functions:[tex]m\angle ABC=arctan(\dfrac{2}{5})[/tex]

Calculating the right side of the equation (rounding to 4 decimal places):

[tex]m\angle ABC \approx 21.8014^{o}[/tex]

The situation in which Shawn's activity will result in a final value of zero is Shawn travels east ten feet and then travels south ten feet. The correct option is D.

This is because when Shawn travels east ten feet, he moves horizontally to the right of his starting point. When he travels south ten feet after that, he moves vertically downwards from his previous position, cancelling out the horizontal movement he made earlier.

The displacement caused by Shawn's movement in the east direction is equal in magnitude but opposite in direction to the displacement caused by his movement in the south direction.

The net displacement of Shawn's movement is zero, and he ends up back at his starting point. Options A, B, and C do not involve any movements that result in a net displacement of zero.

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The old plan is cheaper for a customer who writes 10 checks per month.

To determine how many checks a customer must write per month before the new plan is cheaper than the old plan, we need to set up an equation to compare the two plans. Let x be the number of checks written per month. The cost of the old plan is given by:

C_old = 0.08x + 2

The cost of the new plan is given by:

C_new = 3 + 0.15x

To find out when the new plan becomes cheaper, we need to set the two costs equal to each other and solve for x:

0.08x + 2 = 3 + 0.15x

0.07x = 1

x ≈ 14.29

Therefore, a customer would need to write 15 checks per month for the new plan to be cheaper than the old plan.

For a customer who writes 10 checks per month, the cost of the old plan is:

C_old = 0.08(10) + 2 = 2.80

The cost of the new plan is:

C_new = 3 + 0.15(10) = 4.50

Therefore, the old plan is cheaper for a customer who writes 10 checks per month.

The formula for the cost of any number of checks for the old plan is:

C_old = 0.08x + 2

where x is the number of checks written per month

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For Camden the equation is c = 18 + 11t and for Violet the equation is v = 39 + 8t. After 2 days, Camden will be on page 40 and Violet will be on page 55.

Let's represent the situation with two equations, one for Camden (c) and one for Violet (v), using the given information and the variable t for the number of days.

Camden:
At the beginning of the month, Camden was on page 18 and will read 11 pages per day. So, his equation will be:
c = 18 + 11t

Violet:
At the beginning of the month, Violet was on page 39 and will read 8 pages per day. So, her equation will be:
v = 39 + 8t

Now, we need to determine who is farther along in the book after 2 days. To do this, we will substitute t = 2 into both equations.

Camden's equation (c):
c = 18 + 11(2)
c = 18 + 22
c = 40

Violet's equation (v):
v = 39 + 8(2)
v = 39 + 16
v = 55

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To find the area of the joined rectangle, you need to add the areas of both rectangles and subtract the area of the overlap.

The area of the first rectangle is:

6 cm x 4 cm = 24 cm²

The area of the second rectangle is:

7 cm x 3 cm = 21 cm²

The overlap occurs where the two rectangles join together, and it has an area equal to the product of the widths of the two rectangles:

4 cm x 3 cm = 12 cm²

To find the area of the joined rectangle, add the areas of both rectangles and subtract the overlap:

24 cm² + 21 cm² - 12 cm² = 33 cm²

Therefore, the area of the joined rectangle is 33 cm².

Therefore, the only value of c that works is 6√5.

(A) To find the average slope of the function f(x) = 1/x on the interval (5, 9), we use the formula:

Average Slope = (f(9) - f(5)) / (9 - 5)

Plugging in the values, we get:

Average Slope = (1/5 - 1/9) / 4 = -1/180

Therefore, the average slope of the function on the interval (5, 9) is -1/180.

(B) By the Mean Value Theorem, we know there exists a c in the open interval (5, 9) such that f'(c) is equal to this mean slope.

The derivative of f(x) = 1/x is f'(x) = -1/x^2.

Setting f'(c) = -1/180, we get:

-1/c^2 = -1/180

Solving for c, we get:

c = ±6√5

Since c must be in the open interval (5, 9), the only value that works is:

c = 6√5

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If boat is heading towards a lighthouse, whose beacon-light is 119 feet above the water, the distance from point A to point B is approximately 973 feet.

To find the distance from point A to point B, we can use trigonometry and the fact that the angles of elevation from both points are known.

Let x be the distance from point A to the lighthouse, and y be the distance from point B to the lighthouse. We can set up two equations using tangent function:

tan(5) = 119/x

tan(18) = 119/y

We can solve for x and y by isolating them in each equation:

x = 119/tan(5) ≈ 1343.44 feet

y = 119/tan(18) ≈ 370.79 feet

Therefore, the distance from point A to point B is approximately 1343.44 - 370.79 = 972.65 feet.

We rounded the final answer to the nearest foot, which is 973 feet.

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To evaluate the double integral I = ∬D xy dA, where D is the triangular region with vertices (0,0),(1,0), (0,6), we need to set up the limits of integration for x and y.

Since D is a triangular region, we can integrate over the two sides that meet at the origin and then integrate over the third side. Let's integrate over the sides that form the right angle at (0,0).

For the side along the x-axis, y = 0 to y = 6x.

For the side along the y-axis, x = 0 to x = 1.

Thus, the double integral becomes:

I = ∫0^1 ∫0⁶x xy dy dx

Evaluating the inner integral with respect to y, we get:

I = ∫0^1 [x(y²/2)]0⁶x dx

Simplifying and evaluating the outer integral with respect to x, we get:

I = ∫0^1 18x⁴ dx

I = 18/5

Therefore, the value of the double integral I = ∬D xy dA over the triangular region with vertices (0,0),(1,0), (0,6) is 18/5.
To evaluate the double integral I = ∬_D xy dA for the triangular region D with vertices (0,0), (1,0), and (0,6), we first need to set up the limits of integration.

The base of the triangle lies on the x-axis, from x = 0 to x = 1. The height of the triangle lies on the y-axis, from y = 0 to the line y = 6(1-x), since the slope of the hypotenuse is -6 and passes through (1,0).

Now we can set up the integral:

I = ∬_D xy dA = ∫_(0 to 1) ∫_(0 to 6(1-x)) xy dy dx

Let's first integrate with respect to y:

∫_(0 to 6(1-x)) xy dy = [x(y²)/2]_(0 to 6(1-x)) = 18x(1-x)²

Next, integrate with respect to x:

I = ∫_(0 to 1) 18x(1-x)² dx

Using integration by substitution or expanding and integrating term by term, we get:

I = 2

So, the value of the double integral is 2.

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Answer:

  A)  x < 15

Step-by-step explanation:

You want the solution to x/3 < 5.

The steps to solving an inequality are basically identical to the steps for solving an equation. There are a couple of differences:

If this were and equation, it would be a "one-step" equation. That step is to multiply both sides by the inverse of the coefficient of x.

The coefficient of x is 1/3. Its inverse is 3. Multiplying both sides by 3, we have ...

  3(x/3) < 3(5)

  x < 15 . . . . . . . . . simplify

Note that 3 is a positive number, so we leave the inequality symbol pointing the same direction.

__

Additional comment

We can swap the sides of an equation based on the symmetric property of equality:

  a = b   ⇔   b = a

When we swap the sides of an inequality, we need to preserve the relationship between them. (This is the meaning of "respect the direction of the inequality symbol".)

  a < b   ⇔   b > a

Besides multiplying and dividing by a negative number, there are other operations that affect the order of values.

Note that the 1/x function is another one that has negative slope, which is why it reverses the ordering for values with the same sign. (It has no effect on ordering of values with opposite signs.)

Weight difference between the large box and the small box is [tex](1/2)*(w2 - w1)[/tex] pounds.

Let's assume that Gina has n boxes in total, and let x be the weight of each box in pounds. We can then express the weight of the boxes that weigh less than [tex]1/2[/tex] pound as [tex](1/2)*w1[/tex], where [tex]w1[/tex] is the number of boxes that weigh less than [tex]1/2[/tex] pound. Similarly, we can express the weight of the boxes that weigh more than 1/2 pound as [tex](1/2)*w2[/tex], where [tex]w2[/tex] is the number of boxes that weigh more than [tex]1/2[/tex] pound.

Since Gina puts all the boxes weighing less than [tex]1/2[/tex] pound into a small box, the weight of the small box will be the sum of the weights of all the boxes that weigh less than [tex]1/2[/tex] pound, which is [tex](1/2)*w1[/tex].

Similarly, since Gina puts all the boxes weighing more than [tex]1/2[/tex] pound into a large box, the weight of the large box will be the sum of the weights of all the boxes that weigh more than [tex]1/2[/tex] pound, which is [tex](1/2)*w2[/tex].

The weight difference between the large box and the small box will be:

[tex](1/2)*w2 - (1/2)*w1[/tex]

Simplifying this expression, we get:

[tex](1/2)*(w2 - w1)[/tex]

Therefore, the weight difference between the large box and the small box is [tex](1/2)*(w2 - w1)[/tex] pounds.

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