It is nighttime, and you dropped your goggles into a swimming pool that is 3.0m deep. If you hold a laser pointer 1.0m directly above the edge of the pool, you can illuminate the goggles if the laser beam enters the water 2.0m from the edge. How far are the goggles from the edge of the pool

Answers

Answer 1

Answer:

The distance of the goggle from the edge of the pool is 4.726 m

Explanation:

The given information are;

The depth of the swimming pool = 3.0 m deep

The height of the laser pointer above the swimming pool edge = 1.0 m

The distance from the pool edge the laser  pointer enters the water  = 2.0 m

The angle between the pool and the laser = ∅ = tan⁻¹(1/2) = 26.57°

Therefore, the angle of incidence to the vertical [tex]\theta_i[/tex],  = θ - ∅ = 90 - 26.57° = 63.43°

By Snell's law we have;

The ratio of the sin of the angle of incidence to the sin of the angle of refraction is a a constant equal to the ratio of the refractive indices as follows;

[tex]\dfrac{sin (\theta_i)}{sin (\theta_r} =\dfrac{n_r}{n_i}[/tex]

Where:

[tex]n_r[/tex] = Refractive index of the refractive medium which is water = 1.33

[tex]n_i[/tex] = Refractive index of the incidence medium which is air = 1.00

Therefore;

[tex]\theta_r = sin^{-1} \left (\dfrac{n_i \times sin (\theta_i)}{n_r} \right) = sin^{-1} \left (\dfrac{1\times sin (63.43)}{1.33} \right) = 42.26 ^{\circ}[/tex]

We have that tan([tex]\theta_r[/tex]) = (Distance of the goggles from the point directly above the point of incidence of the beam)/(The water depth)

tan(42.26) = (The horizontal distance of the goggles from the point of incidence of the laser on the water surface)/(3.0)

∴ The horizontal distance of the goggles from the point of incidence of the laser on the water surface = 3.0 × tan(42.26) = 2.726 m

The distance of the goggle from the edge of the pool = The horizontal distance of the goggles from the point of incidence of the laser on the water surface + The distance from the edge of the water surface the laser enters the water

The distance of the goggle from the edge of the pool = 2.726 + 2 = 4.726 m

The distance of the goggle from the edge of the pool = 4.726 m.


Related Questions


Y=5sin (3x -4t)
Cdculate the wavelength frequency and period.
Pls answer and explanation with formula ​

Answers

explanation

the general form of wave equation is

       y=Asin(kx-wt)

we have

      y=5sin(3x-4t)

hence the angular frequency

     w= 4s^-1

the frequency

  f=w/2 pi

  f=4/2 pi

  f=4/2*3.14

  f=0.64 hz

the period

T=1/f

T=1/0.64

T=1.5625=1.6

the wavelength

k=2 pi/lambda

lambda=2 pi/k

k=3

so

lambda=2*3.14/3

lambda=2.09

if my answer is right then mark me brainlist


Which force acts on a body if it is fully or partially immersed in a
liquid? ​

Answers

Answer:

Buoyant Force

Explanation:

That's literally the definition of the buoyant force

This is a question on my physics test :)
Can any1 help me? if you can, please give an explanation​

Answers

Answer:

119.6 J/Kg°C

Explanation:

Data obtained from the question include:

Mass of substance (ms) = 170 g

Initial temperature of substance (Ts) = 120 °C

Volume of water = 200 mL

Initial temperature of water (Ts) = 10 °C

Temperature of the mixture (T2) = 12.6 °C

Density of water = 1 g/mL

Specific heat capacity of water (Cw) = 4200J/Kg°C

Specific heat capacity of substance (Cs) =..?

Next, we shall determine the mass of water. This can be obtained as follow:

Volume of water = 200 mL

Density of water = 1 g/mL

Mass of water =..?

Density = mass /volume

1 = mass /200

Cross multiply

Mass of water = 1 x 200

Mass of water = 200 g

Convert 200 g of water to Kg

Mass of water = 200/1000 0.2 Kg

Mass of water = 0.2 Kg

Now, we obtained the specific heat capacity of the substance using the following formula:

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

Mass of water = 0.2 Kg

Initial temperature of water (Ts) = 10 °C

Specific heat capacity of water (Cw) = 4200J/Kg°C

Temperature of the mixture (T2) = 12.6 °C

Mass of substance (ms) = 170 g = 170/1000 = 0.17 Kg

Initial temperature of substance (Ts) = 120 °C

Specific heat capacity of substance (Cs) =..?

MwCw(T2 – Tw) + MsCs(T2 – Ts) = 0

0.2× 4200(12.6 – 10) + 0.17×Cs×(12.6 – 120) = 0

840(2.6) + 0.17Cs(– 107.4) = 0

2184 – 18.258Cs = 0

Rearrange

2184 = 18.258Cs

Divide both side by the coefficient of Cs i.e 18258

Cs = 2184/18.258

Cs = 119.6 J/Kg°C

Therefore, the specific heat capacity of the substance is 119.6 J/Kg°C

A light bulb lights up with a potential difference of 120 V and a current of 1.5 A. What is the energy consumption of the light bulb?

Answers

Power consumption = (voltage) x (current)

Power = (120 V) x (1.5 A)

Power = 180 watts

But 1 watt = 1 Joule/second

180 watts = 180 Joule/second

Energy consumption of the light bulb =  

(180) x (number of seconds it's turned on)  Joules

A diver releases an air bubble of volume 3.0 cm3 from a depth of 18 m below the surface of a lake, where the temperature is 9.0 ∘C. Part A What is the volume of the bubble when it reaches just below the surface of the lake, where the temperature is 22 ∘C?

Answers

Answer:

Explanation:

We shall apply gas law formula to get the solution .

P₁ V₁ / T₁ = P₂ V₂ / T₂

P₁ = 10⁵ + 18 x 10³ x 9.8  where 10⁵ Pa is atmospheric  pressure at surface

= 1.764 x 10⁵ + 10⁵

= 2.764 x 10⁵

2.764 x 10⁵  x 3 / ( 273 + 9 ) = 10⁵ x V₂ / ( 273 + 22 )

V₂ = 8.67 cm³

Which is one piece of evidence of seafloor spreading?
a. fossil material
b. continent material
c. drilled core samples
d. ocean water samples​

Answers

Answer:

A. Continent material

Explanation:

Eruptions of molten material, which results in continent material is a piece of evidence of seafloor spreading.

Continent material is one piece of evidence of seafloor spreading. Option b is correct.

What is seafloor spreading?

Seafloor spread is a phenomenon that happens along mid-ocean ridges, when new oceanic crust is generated by volcanic activity and then progressively travels away from the ridge.

The geological activity of seafloor spreading occurs when tectonic plates split apart.

Continent material is one piece of evidence of seafloor spreading.

Hence, option b is correct.

To learn more about the seafloor spreading, refer to the link;

https://brainly.com/question/15122129

#SPJ2

Hydrogen fuel cells are used on the space shuttle to provide the shuttle with all of its electrical energy. Explain why fuel cells are used instead of batteries.

Answers

Answer:

Hydrogen used in fuel cells has the energy to weight ratio ten times greater than lithium-ion batteries. Consequently, it offers much greater range while being lighter and occupying smaller volumes. It can also be recharged in a few minutes, similarly to gasoline vehicles.

Two children push on opposite sides of a door during play. Both push horizontally and perpendicular to the surface of the door. One child pushes with a force of 17.5 N at a distance of 0.59 m from the hinges, and the second child pushes at a distance of 0.47 m.
What force must the second child exert to keep the door from moving? Assume friction is negligible.

Answers

Answer:

F₂ = 21.97 N

Explanation:

this is a rotational equilibrium exercise, let's write the formula

         ∑ τ = 0

          F₁ d₁ - F₂ d₂ = 0

force F₁ is 17.5 N and its distance d₁ = 0.59m, the distance d₂ = 0.47m

          F₂ = F₁ d₁ / d₂

          F₂ = 17.5 0.59 / 0.47

          F₂ = 21.97 N

Which of the following does each different kind of atom represent?
O A. A nucleus
O B. An element
O C. An electron
OD. A neutron​

Answers

Answer:

B

Explanation:

because atoms make up an element.

Answer:

B

Explanation:

it's b because an element makes up an atom and signifies the number of element in atom e.g (H2) the two signifies the number of atoms

A scientist wants to measure the relationship between humidity in the
summer and the number of home runs in baseball. Which of the following is a
testable question about this topic?
A. Are home runs more exciting during the summer?
O B. Should fans like the players who hit the most home runs?
O C. Are home runs more fun to watch than normal hits?
D. Are there more home runs during the more humid months of the
summer?

Answers

Answer:

D

Explanation:

The most suitable testable question. in this case, would be that 'are there more home runs during the more humid months of the  summer?'

Since the aim of the investigation is to find the relationship between humidity and the number of home runs, measuring the number of home runs during the more humid months in the summer and comparing the data to the number of home runs during the less humid months in the same summer would provide the answer.

Only option D raises a valid question that is relevant to the aim of the investigation.

Light travels 300 000 000 m/s and one year has approximately 32 000 000 second a light year is the distance light travels in one year

Answers

Explanation:

It is given that,

Speed of light, [tex]v=300 000 000\ m/s=3\times 10^8\ m/s[/tex]

Seconds in 1 year, [tex]t=32 000 000=32\times 10^6\ s[/tex]

We need to find the distance traveled by light in one year. Speed of an object is given by :

[tex]v=\dfrac{d}{t}[/tex]

So,

[tex]d=v\times t\\\\d=3\times 10^8\times 32\times 10^6\\\\d=9.6\times 10^{15}\ m[/tex]

Since,

[tex]1\ \text{light year}=9.46\times 10^{15}\ m\\\\1\ m=\dfrac{1}{9.46\times 10^{15}}\ \text{ly}\\\\9.6\times 10^{15}\ m=\dfrac{9.6\times 10^{15}}{9.46\times 10^{15}}\\\\d=1.01\ \text{ly}[/tex]

So, the distance covered by light is 1.01 light years.

A rocket is launched vertically from the ground with an initial velocity of 64. Write a quadratic function that shows the height, in feet, of the rocket t seconds after it was launched.

Answers

Answer:

y = 64t − 16t²

Explanation:

y = y₀ + v₀ t + ½ at²

y = 0 + 64 t + ½ (-32) t²

y = 64t − 16t²

Proved that
V = u+at

Answers

Answer:

[tex]\sf Proof \ below[/tex]

Explanation:

We know that acceleration is change in velocity over time.

[tex]\sf a=\frac{\triangle v}{t}[/tex]

[tex]\sf a=\frac{v-u}{t}[/tex]

v is the final velocity and u is the initial velocity.

Solve for v.

Multiply both sides by t.

[tex]\sf at=v-u[/tex]

Add u to both sides.

[tex]\sf at + u=v[/tex]

Answer:

Acceleration = v-u/t  when we flip -u and t to right hand side

then -u changes to plus and denominator t changes to numerator

then then  this equations becomes  v=u+at

Explanation:

Is the following nuclear reaction balanced?

Answers

Answer:

yes

Explanation:

Salt compounds are commonly used to melt ice that forms on sidewalks in the winter. A common chemical that is used to melt sidewalk ice is calcium chloride, CaCl2(s). When calcium chloride dissolves into solution is releases thermal energy which aides in melting
the ice.

The molar mass of water is 18.02 g/mol

The thermal energy, in kilojoules (kJ) that must be released from the calcium chloride,
CaCl2(s), to melt 10.0 kg of ice, expressed in scientific notation is a.bc x 104 k).
46
55
The values of a, b, c, and d.

Answers

Answer:

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

Explanation:

The quantity of heat needed to melt the ice is given by Q = mL where m = mass of ice and L = latent heat of fusion of ice = 334 kJ/kg. This quanity of heat is also the thermal energy needed to be released by the calcium chloride, CaCl₂

Now, the mass of ice = 10 kg. So,

Q = mL

Q = 10 kg × 334 kJ/kg

Q = 3340 kJ

In scientific notation,

Q = 3.34 × 10³ kJ

So the thermal energy needed to be released by the calcium chloride is 3.34 × 10³ kJ

Comparing Q = 3.34 × 10³ kJ with a.bc × [tex]10^{d}[/tex] kJ

So, a = 3, b = 3, c = 4 and d = 3

The values of a, b, c and d are

a = 3, b = 3, c = 4 and d = 3

a skydiver jumped out of a plane and fell 9 miles to the ground. his average speed while falling was 174 miles/hour. how much time did the dive last?

Answers

Answer:

t = 0.051 seconds

Explanation:

Given that,

A skydiver jumped out of a plane and fell 9 miles to the ground. It means 9 miles is the distance covered.

The average speed of the skydiver is 174 miles/hour

We need to find the time for which he dive last. It means t is the time taken. Total distance covered divided by time taken is called average speed. So,

[tex]v=\dfrac{d}{t}\\\\t=\dfrac{d}{v}\\\\t=\dfrac{9}{174}\\\\t=0.051\ s[/tex]

So, a skydiver dive for 0.051 seconds.

A ball is launched from the ground with a horizontal speed of 30 m/s and a vertical speed of 30 m/s. What far vertically will it travel before hiting the ground A. 40 m B. 30 m C. 60 m D. 50 m

Answers

Answer:

First, let's think in the vertical problem:

The acceleration will be the gravitational acceleration:

g = 9.8 m/s^2

a = -9.8 m/s^2

For the velocity, we integrate over time:

v(t) = (-9.8 m/s^2)*t + v0

Where v0 is the initial velocity, in this case  v0 = 30m/s.

v(t) =  (-9.8 m/s^2)*t + 30m/s

Now, for the position we integrate again over time, and get:

P(t) = (1/2)*(-9.8 m/s^2)*t^2 + 30m/s*t + p0

Where p0 is the initial position, as the ball is launched from the ground, we can use p0 = 0m

p(t) = (-4.9m/s^2)*t^2 + 30m/s*t

Now, the maximum vertical height is reached when:

v(t) = 0m/s = -9.8m/s^2*t + 30m/s

t = 30m/s/9.8m/s^2 = 3.06s

Now we can evaluate the vertical position in t = 3.06s

p(3.06s) = (-4.9m/s^2)*(3.06)^2 + 30m/s*3.06 = 62m

So, rounding down, the correct option is: C. 60 m

Click this link to view O*NET Skills section for Electrical Engineers. Note that common skills are listed toward the top and less common skills are listed toward the bottom. According to O*NET, what are some common skills Electrical Engineers need?

Answers

Explanation:

O*NET stands for Occupational Network and it is an online platform for job seekers around the world who are searching for jobs. This platforms provides the job information along with the required qualities, education background, skill sets, etc.

The most common skill sets that are required for an electrical engineers are

1. Analytical skills

2. Monitoring and active learning

3. Decision making

4. Able to manage the personal resources

5. Time management.

6. Should have knowledge about different software.

the answers are1, 4, 5, 6orA, D, E, F

A hollow circular shaft made of 304 stainless steel uniformly tapers from an outer diameter of 3.0 cm to an outer diameter of 4.0 cm over a length of 2 meters. The inner diameter of 1.0 cm is constant over the length of the shaft. The shaft is subjected to an applied torque of 500 Nm. Determine the maximum shear stress in the shaft.

Answers

Answer:

maximum shear stress = τ(max) = 95.49 × 10⁶N/m²

Explanation:

given

outer diameter at one end(D₁) = 3.0cm

outer diameter at the other end(D₂) = 4.0cm

inner diameter(d₁) = 1.0cm

torque applied(T) = 500Nm

maximum shear stress will occur at lower outer diameter

the formula is τ/r = T/J

τ= T × r/J

where r is radius

T is the torque

J is the polar 2nd M of area

attached is the calculation of the question

Which egg floated higher? Why do you think that happened?

Answers

Answer:

Generally, fresh eggs will lie on the bottom of the bowl of water.  Eggs that tilt so that the large end is up are older, and eggs that float are rotten.

Explanation:

To a stationary observer, a bus moves south with a speed of 12 m/s. A man
inside walks toward the back of the bus with a speed of 0.5 m/s relative to
the bus. What is the velocity of the man according to a stationary observer?
A. 11 m/s south
B. 12.5 m/s south
C. 11.5 m/s south
D. 0.5 m/s south

Answers

ANSWER

C 11.5 m/s

EXPLANATION

Answer:

11.5m/s south

Explanation:

Online classes

How does increasing frequency affect the crests of a wave?
They get higher.
They get closer together.
They get lower.
They get farther apart.

Answers

When frequency increases more wave crests pass a fixed point each second. That means the wavelength shortens. So as frequency increases,wavelength decreases

Answer:

they get closer together

Explanation:

Three children use the same skateboard. i) 20-30kg, ii) 30-40 kg iii) 40-50kg Which child can move the skateboard using the smallest pushing force? Justify your choice.

Answers

Answer:

i) 20-30 kg

Explanation:

The child with the smallest mass range of 20-30 kg will require the smallest force to move his skate board because he/she has a smaller inertia force to overcome. The mass of a body is the measure of the inertia forces of the body. The inertia force makes it difficult for a body at rest to start moving, and a body already in motion to stop moving.

When the children try to move the skateboard, they exert a force that is proportional to the product of their mass and the acceleration with which they start moving. This force must exceed their body's inertia force before they would start moving.

from

F = ma

where F is the force required

m is the mass

a is the acceleration

We can see that for the given mass ranges, the children with the larger mass range will require more force in order to move their skateboard. Consequently, the child with the smallest mass range will require the smallest pushing force to move his skate board.

Calculate the gravitational acceleration of a satellite that is in orbit at a distance of 1.0 x 10^8 meters from the center of the Earth (Mass of Earth is 6.0 × 10^24).

Answers

Answer:

[tex]g=0.035\ m/s^2[/tex]

Explanation:

Given that,

Mass of Earth, [tex]m=6\times 10^{24}\ kg[/tex]

We need to find the gravitational acceleration of a satellite that is in orbit at a distance of [tex]10^8\ m[/tex] from the center of the Earth.

Radius of earth is 6,371 km

The formula used to find the gravitational acceleration at a distance is given by :

[tex]g=\dfrac{Gm}{R^2}[/tex]

R = r+d

[tex]g=\dfrac{6.67\times 10^{-11}\times 6\times 10^{24}}{(10^8+6371\times 10^3)^2}\\\\g=0.035\ m/s^2[/tex]

So, the gravitational acceleration is [tex]0.035\ m/s^2[/tex].

Which of the following scientists proposed the theories of relativity?
A. Galileo Galilei
B. Johannes Kepler
C. Albert Einstein
D. Sir Isaac Newton

Answers

Answer:

c) Albert Einstein,

Explanation:

in his theory of special relativity, determined that the laws of physics are the same for all non-accelerating observers, and he showed that the speed of light within a vacuum is the same no matter the speed at which an observer travels.

hope this helped

-lvr

A mobile starts and travels 225 m with an acceleration of (- 3.5i + 4.5j) 2 along a rectilinear path. Determine:

a) The time spent
b) The final speed
c) The average speed I hope you can help me.

Answers

Answer:

a) 8.89 s

b) 50.6 m/s

c) 25.3 m/s

Explanation:

d = 225 m

v₀ = 0 m/s

a = (-3.5i + 4.5j) m/s²

First, find the magnitude of the acceleration.

a = √((-3.5)² + (4.5)²) m/s²

a = 5.7 m/s²

a) Find t

Δx = v₀ t + ½ at²

225 m = (0 m/s) t + ½ (5.7 m/s²) t²

t = 8.89 s

b) Find v

v² = v₀² + 2aΔx

v² = (0 m/s)² + 2 (5.7 m/s²) (225 m)

v = 50.6 m/s

c) Find v_avg

v_avg = Δx / t

v_avg = 225 m / 8.89 s

v_avg = 25.3 m/s

Or, for constant acceleration:

v_avg = (v₀ + v) / 2

v_avg = (0 m/s + 50.6 m/s) / 2

v_avg = 25.3 m/s

Why does fire has not any shadow?​

Answers

Fire isnt a object or a human or a animal!!!! So ofc it doesn’t have a shadow

why is string a good force measurer? ​

Answers

Answer:

tension is how much force is being exerted on each end of the string, whereas length is how long the string is. So assuming that the string has finite mass, then the tension on the string should increase proportionally to the string according to Newton's law f=ma.

Explanation:

When the current in a toroidal solenoid is changing at a rate of 0.0260 A/s, the magnitude of the induced emf is 12.2 mV. When the current equals 1.40 A, the average flux through each turn of the solenoid is 0.00308 Wb. How many turns does the solenoid have?

Answers

Answer:

The solenoid has 213 turns.

Explanation:

The number of the solenoid's turns (N) can be found as follows:

[tex] N = \frac{L*I}{\phi_{B}} [/tex]    (1)

Where:

L: is the self-inductance of the solenoid

I: is the current = 1.40 A

[tex]\phi_{B}[/tex]: is the magnetic flux = 0.00308 Wb      

The self-inductance of the solenoid (L) is:

[tex] L = \frac{|\epsilon|}{|dI/dt|} [/tex]   (2)

Where:

ε: is the induced emf = 12.2x10⁻³ V

dI/dt: is the rate changing of the current = 0.0260 A/s

By entering equation (2) into (1) we can find the number of turns:

[tex] N = \frac{|\epsilon|*I}{\phi_{B}|dI/dt|} = \frac{12.2 \cdot 10^{-3} V*1.40 A}{0.00308 Wb*0.0260 A/s} = 213 [/tex]        

Therefore, the solenoid has 213 turns.

I hope it helps you!

sliding friction is _ than the static friction.

Answers

Answer:

less

Explanation:

Sliding friction is always less than static friction. This is because in sliding friction, the bodies slide with each other and thus the effect of friction is not more. However, it does not happen in the case of static friction.

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