Answer:
The answer is
31°Step-by-step explanation:
Let the unknown angle be x
To find x we use cosine
cos∅ = adjacent / hypotenuse
From the question
The hypotenuse is 56
The adjacent is 48
So we have
cos x = 48/56
cos x = 6/7
x = cos-¹ 6/7
x = 31.003
x = 31° to the nearest degree
Hope this helps you
PLEASE HELP THANK YOUUUU Your group has $120 available for the banquet. Any other costs must be covered from selling tickets for the event. You decided to take care of the major cost first–hall rental and caterer. Each caterer you approach is associated with a specific hall. Caterer One charges $45 per person. The cost of using the hall is inclusive. Caterer Two charges $250 for hall rental plus $28 per person. Cater Three charges $500 for hall rental plus $20 per person. 1. Write the equation to represent the cost of each caterer. Use C to represent cost and n to represent number of people. (3 marks)
Answer:
The cost C, of hosting the banquet with the services of Caterer One is;
C = $ 45·n
The cost C, of hosting the banquet with the services of Caterer Two is;
C = $250 + $ 28·n
The cost C, of hosting the banquet with the services of Caterer Three is;
C = $500 + $ 20·n
Step-by-step explanation:
The information includes;
The amount available to the group for the banquet = $120
The number of people attending the banquet = n
The cost incurred in hosting the banquet = C
The major costs in hosting the banquet are hall rental and caterer
The cost per caterer are as follows;
Caterer One
The cost per person including the hall = $45
Therefore, the cost incurred, C, in hosting the banquet using caterer one is equal;
C = n × $45 = $ 45·n
Caterer Two
The hall rental = $250
The cost per person = $28
Therefore, the cost incurred, C, in hosting the banquet using caterer two is equal;
C = $250 + n × $28 = $250 + $ 28·n
Caterer Three
The hall rental = $500
The cost per person = $20
Therefore, the cost incurred, C, in hosting the banquet using caterer three is equal;
C = $500 + n × $20 = $500 + $ 20·n.
Answer:
The cost C, of hosting the banquet with the services of Caterer One is;
C = $ 45·n
The cost C, of hosting the banquet with the services of Caterer Two is;
C = $250 + $ 28·n
The cost C, of hosting the banquet with the services of Caterer Three is;
C = $500 + $ 20·n
Step-by-step explanation:
The information includes;
The amount available to the group for the banquet = $120
The number of people attending the banquet = n
The cost incurred in hosting the banquet = C
The major costs in hosting the banquet are hall rental and caterer
The cost per caterer are as follows;
Caterer One
The cost per person including the hall = $45
Therefore, the cost incurred, C, in hosting the banquet using caterer one is equal;
C = n × $45 = $ 45·n
Caterer Two
The hall rental = $250
The cost per person = $28
Therefore, the cost incurred, C, in hosting the banquet using caterer two is equal;
C = $250 + n × $28 = $250 + $ 28·n
Caterer Three
The hall rental = $500
The cost per person = $20
Therefore, the cost incurred, C, in hosting the banquet using caterer three is equal;
C = $500 + n × $20 = $500 + $ 20·n.
PLEASE help me with this question with solutions
Answer:
D
Step-by-step explanation:
the inscribed angle intersects an arc that twice the measure of the arc interested by the central angle. The inscribed angle's arc measures 144° and the central angle's arc measures 72°
>central angle and the arc the intersected arc are equal i.e they are both 72°
>the inscribed angle is half of the measure of the intersected arc i.e since the inscribed angle is 72° the arc interested is 144°
Select the correct answer.
Which table shows a proportional relationship between x and y?
x y
1
5
2
6
3
7
x y
2
3
4
6
6
9
x y
4
16
8
64
12
144
x y
1
3
2
9
3
27
Answer:
I think
x y
2
3
4
6
6
9
Step-by-step explanation:
but i don't see any table
Samuel is solving the equation 3 (x minus 1) + 4 = 2 minus (x + 3). Which equivalent equations might Samuel use? Check all that apply.
3 x minus 3 + 4 = 2 minus x minus 3
3 x minus 1 + 4 = 2 minus x + 3
3 x minus 3 + 4 = 2 minus x + 3
3 x + 1 = negative x minus 1
3 x + 3 = negative x + 5
3 x + 1 = negative x + 5
Answer: 3 x minus 3 + 4 = 2 minus x minus 3
3 x + 1 = negative x minus 1
Step-by-step explanation:
A and D. Edge 2020
The required equation that Samuel used is 3x -3 + 4 =2- x -3. option A is correct.
Samuel is solving the equation 3 (x minus 1) + 4 = 2 minus (x + 3). Which equivalent equations might Samuel use, is to be determined.
The equation is the relationship between variables and represented as[tex]y = ax +b[/tex] is an example of a polynomial equation.
Given equation is [tex]3(x-1) +4 =2 -(x+3)[/tex]
Simplification of the above equation,
opening the parenthesis on both sides
step 1⇒ 3x - 3 + 4 = 2 - x - 3
step 2⇒ 3x + 1 = -x - 1
Transposition of -x to the left side and +1 to the right side
step 4 ⇒ 3x +x = -1 -1
4x = -2
Transposition of 4 to the denominator of -2.
step 5⇒ x = -2/4
x = -1/2
Thus , Step 1 3x -3 + 4 =2- x -3 is the equivalent equation used by the samuel.
Learn more about the equation here:
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fins the zeroes of the quadratic equation : 4√ 5 x^ 2 - 24x - 9√ 5
10th grade Cbse chapter 2 : Polynomials
pls give the step by step explanation so that i can understand
Answer:
Step-by-step explanation:
Hello,
First of all, we know that the solution of the following equation
[tex]ax^2+bx+c=0[/tex]
are
[tex]\dfrac{-b\pm\sqrt{b^2-4ac}}{2a} \ \text{ when } \Delta=b^2-4ac \geq 0[/tex]
I would suggest that you try to apply this formula first and check the solution only after you try.
Let's apply it in this case, we have:
[tex]a=4\sqrt{5} \\ \\ b=-24 \\ \\ c= -9\sqrt{5}[/tex]
[tex]\Delta=b^2-4ac=24^2+4*9*5=1296 \\ \\ \sqrt{\Delta}=36 \ \text{ and the solutions are } \\ \\ \\ x_1=\dfrac{24-36}{8\sqrt{5}}=\dfrac{-12}{8\sqrt{5}}=\boxed{\dfrac{-3}{2\sqrt{5}}} \\ \\x_2=\dfrac{24+36}{8\sqrt{5}}=\dfrac{60}{8\sqrt{5}}=\boxed{\dfrac{15}{2\sqrt{5}}}[/tex]
Hope this helps.
Do not hesitate if you need further explanation.
Thank you
For one of the quadrilaterals: the corner are not the right angles, the quadrilateral has rotational symmetry of order 2 and the diagonals cross at the right angles. Write down the name of this quadrilateral
Answer:
Rhombus.
Step-by-step explanation:
A rhombus is a quadrilateral, meaning that it has four lateral sides. A Rhombus is a 2-dimensional shape, and has two lines of symmetry. A Rhombus has a rotational symmetry of order two, and the opposite sides are parallel. Also, the opposite angles in Rhombus are equal. Th diagonals of a Rhombus bisect each other at a right angle.
Other quadrilateral shapes includes the Rectangle, Parallelogram, and the Kite.
You measure the sides of a pool and find that it is 20 yards wide and 50 yards long. Approximately, how far would it be diagonally between corners of the pool?
A. 54 yards
B. 58 yards
C. 62 yards
D. 66 yards
Answer:
[tex]\boxed{d = 54 yards}[/tex]
Step-by-step explanation:
Formula for diagonal is as follows:
[tex]d = \sqrt{l^2+w^2}[/tex]
Where d is diagonal, l is length (50 yards) and w is width (20 yards)
[tex]d = \sqrt{(50)^2+(20)^2}[/tex]
[tex]d = \sqrt{2500+400}[/tex]
[tex]d = \sqrt{2900}[/tex]
d = 53.85 yards
d ≈ 54 yards
Answer:
[tex]\boxed{\mathrm{54 \: yards}}[/tex]
Step-by-step explanation:
The shape of the pool is a rectangle.
The diagonal of a rectangle can be found through a formula by using Pythagorean theorem.
[tex]d^2=l^2 +w^2[/tex]
[tex]d=diagonal\\l=length\\w=width[/tex]
The length is given 50 yards, and width is given 20 yards. Find the diagonal.
[tex]d^2 =50^2 +20^2[/tex]
[tex]d^2 =2500+400[/tex]
[tex]d^2 =2900[/tex]
[tex]d=\sqrt{2900}[/tex]
[tex]d \approx 53.851648[/tex]
[tex]d \approx 54[/tex]
A doctor prescribes a 100-mg antibiotic tablet to be taken every eight hours. Just before each tablet is taken, 20% of the drug remains in the body. (a) How much of the drug is in the body just after the sec- ond tablet is taken
Answer:
120 mg
Step-by-step explanation:
20% of 100 is 20 so that would be 20mg plus the 100mg they just took
100+20=120mg
i hope this helps you!
Does this graph show a function? Explain how you know.
5
-5
-5
A. No; there are y-values that have more than one x-value.
B. No; the graph fails the vertical line test.
C. Yes; the graph passes the vertical line test.
D. Yes; there are no y-values that have more than one x-value.
Answer:
Option (C).
Step-by-step explanation:
To check a graph whether it's a function or not we use a vertical line test. In this test first we draw a vertical line on the given graph. If this line intersects the graph at more than one point, the graph is not a function.
In the given parabola, opening upwards passes the vertical line test.
Therefore, this graph shows a function.
Option (C) will be the answer.
Option (c) Yes; the graph passes the vertical line test. And
(d) Yes; there are no y-values that have more than one x-value are correct options. Hence, a given graph is a function.
This is a graph of [tex]y = x^2[/tex]
Which is a graph of parabola.
To determine the given graph is a function or not, we do a vertical line test.
The vertical line test says that if a vertical line intersects a graph more than once, then that graph is not a function. And in this case, y-values have more than one x-values.
Let’s draw a vertical line in the given graph (attached below)
We see that the vertical line touches the graph only at once. That’s why it is a function, and so there are no y-values that have more than one x-value.
Hence, the given graph is a function and option (3) and (4) are correct options.
Learn more about graphs here:
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WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the normal distribution. The mean of the distribution is 15.0 minutes and the standard deviation is 3.5 minutes. What is the probability that a particular listener will tune in:
Complete question :
WNAE, an all-news AM station, finds that the distribution of the lengths of time listeners are tuned to the station follows the normal distribution. The mean of the distribution is 15.0 minutes and the standard deviation is 3.5 minutes. What is the probability that a particular listener will tune in:
a. More than 20 minutes? b. For 20 minutes or less
Answer: 0.0764 ; 0.9236
Step-by-step explanation:
Mean (m) = 15 minutes
Standard deviation (sd) = 3.5
Z - score :
Z = (x - m) / sd
A) more than 20 minutes
P(X > 20) ; x = 20
Z > (20 - 15) / 3.5 = 5/3.5 = 1.429
P(z > 1.429) = 0.5 - P(0<z<1.43)
Using the z-table: 1.43 = 0.4236
0.5 - 0.4236 = 0.0764
2) 20 minutes or less :
P(X <= 20) ; x = 20
Z < (20 - 15) / 3.5 = 5/3.5 = 1.429
P(z < 1.429) = 0.5 + P(0<z<1.43)
Using the z-table: 1.43 = 0.4236
0.5 + 0.4236 = 0.9236
ASAP!! Please help me. I will not accept nonsense answers, but will mark as BRAINLIEST if you answer is correctly with solutions.
Answer:
the numbers of cars pf various colors in a parking lot
Answer: The speed of a car as it changes during a time.
B is the best example of continuous data.
Step-by-step explanation: The contrast between the definitions of continuous data vs. discreet data is that discrete data is counted, continuous data is measured.
A speedometer measures speed continuously, time is measured continuously.
Time can, however, be reported as discreet measurements in situations where that kind of data is needed. (not in this question)
A Number of cars is discreet.
Data from different workers or different days is not continuous.
write down as decimal.
Answer:
iii) 5.7
iv) 27.85
vii) 0.609
viii) 40.0709
Step-by-step explanation:
hope this helps
HELP ASAP MATH PLS!!!!!
Answer:
A
Step-by-step explanation:
We know that because the second plane flies 15 miles less, it has to be either A or B, because they have -15 at the end.
It cannot be B, because in B, the second plane has a -w in the equation. However, in the word problem, the second plane flies with the wind, not against it. Therefore, it must be A.
i need both answers pls !!
5. Over what interval is the following graph DECREASING? *
Answer:
(3, 13)
Step-by-step explanation:
The curve decreases from x = 3 to x = 13.
Answer: (3, 13)
We have 9 balls, numbered 1 through 9, and 27 bins. How many different ways are there to distribute these 9 balls among the 27 bins? Assume the bins are distinguishable (e.g., numbered 1 through 27).
Answer:
7625597484987 ways
Step-by-step explanation:
Given the following :
Number of ball(k) = 9
Number of bins (n) = 27
How many different ways are there to distribute these 9 balls among the 27 bins.
Here, the balls have different labels (1 to 9)
The bins are also distinguishable, therefore each ball can go into any of the 27 distinct bins.
Therefore, the different ways are there to distribute these 9 balls among the 27 bins equals = n^k
27^9 = 7625597484987 ways.
A club elects a president, vice-president, and secretary-treasurer. How many sets of officers are possible if there are 12 members and any member can be elected to each position? No person can hold more than one office.
Answer:
1320 setsStep-by-step explanation:
This problem brothers on selection without repetition, so we will be using permutation to solve this problem.
Given
n= 12 ,which is the number we are choosing from
r= 3, which is the number of committee(president, vice-president, and secretary-treasurer.)
[tex]= \frac{n!}{(n-r)!}[/tex]
Substituting we have
[tex]= \frac{12!}{(12-3)!}\\\\ = \frac{12!}{(9)!}\\\\= \frac{12*11*10*9!}{9!}[/tex]
[tex]= 12*11*10= 1320[/tex]
Simplify. Your answer should contain only positive exponents.
9) 3^-1 • 3^0
Answer:
1 / 3^1
Step-by-step explanation:
3^-1 • 3^0
When multiplying exponents with the same base, we add the exponents
3^ (-1+0)
3 ^-1
We know that a^ - b = 1/a^b
3 ^ -1 = 1/3^1
Using this data, what is the population proportion of semesters for which the number of student applications is less than 200,000?
Complete question :
The table shows the total number of student applications to universities in a particular state over a period of 12 semesters. States base their decisions on data like this. Suppose they decide that if fewer than 200,000 students apply during 6 or more semesters, the state will make a special effort to promote university education. Using this data, what is the population proportion of semesters for which the number of student applications is less than 200,000?
Semester Student Applications (in thousands)
1 106
2 137
3 285
4 120
5 202
6 195
7 327
8 139
9 307
10 318
11 212
12 217
Answer:
42%
Step-by-step explanation:
Given the above data in thousand :
Proportion of students
1 - - - - 106, 000
2 - - - -137, 000
3 - - - - 285, 000
4 - - - 120, 000
5 - - - 202, 000
6 - - - 195, 000
7 - - - 327, 000
8 - - - 139, 000
9 - - - 307, 000
10 - - - 318, 000
11 - - -212, 000
12 - - - 217, 000
Therefore, proportion of semesters with student application below 200,000
= (Number of semesters below 200,000 / total number of semesters)
Semesters below 200,000 :
(106000, 137000, 120000, 195000, 139000) = 5
(5 / 12) = 0.416666
= 0.42
In terms of percentage :
0.42 * 100 = 42%
Tapiwa raked %5, percent more leaves than Adam raked. Tapiwa raked 357 liters of leaves. How many liters of leaves did Adam rake?
HELP!! DUE SOON
Answer:
340 liters
Step-by-step explanation:
357/1.05=340
In a scale drawing of a rectangular deck, the
length is 10 inches and the width is 8 inches. In
the drawing, 4 inches represents 3 yards. What
is the length of the actual deck, in yards?
Answer:
45
Step-by-step explanation:
10/4x3=7.5
8/4x3=6
6x7.5=45yards
Which is the definition of a rhombus?
a. A quadrilateral with four right angles
b. A quadrilateral with four congruent sides
c. A quadrilateral with interior angles that sum to 360°
d. A quadrilateral with two pairs of opposite congruent sides
Answer:
a) A quadrilateral with 4 right angles
Answer:
I think the answer is b
I'm sorry if I'm not correct
Can you help me plz
Answer:
[tex]\boxed{\sf y=6}[/tex]
Step-by-step explanation:
There are 5 identical squares.
The area of one square is [tex]\sf s^2[/tex].
[tex]\sf{y^2 } \times \sf{5}[/tex]
[tex]\sf 5y^2[/tex]
The area of the whole shape is 180 cm².
[tex]\sf 5y^2=180[/tex]
Solve for y.
Divide both sides by 5.
[tex]\sf y^2=36[/tex]
Take the square root on both sides.
[tex]\sf y=6[/tex]
Benjamin decides to treat himself to breakfast at his favorite restaurant. He orders chocolate milk that
costs $3.25. Then, he wants to buy as many pancakes as he can, but he wants his bill to be at most $30
before tax. The restaurant only sells pancakes in stacks of 4 pancakes for $5.50.
Let S represent the number of stacks of pancakes that Benjamin buys.
1) Which inequality describes this scenario?
Answer:
[tex]\bold {3.25+5.50S \le 30}[/tex] is the correct answer.
Step-by-step explanation:
Given that
Chocolate milk already ordered for the cost of $3.25.
Maximum bill that Benjamin wants = $30
Cost of a stack pancake = $5.50
Number of stacks of pancakes bought = S
It is given that all the money available is to be spent on 1 chocolate milk and S number of stacks of pancakes.
Cost of 1 pancake = $5.50
Cost of S number of stacks of pancakes = [tex]\text{Number of stacks of pancakes} \times \text{Cost of each pancake}[/tex]
i.e. [tex]S \times 5.50 = 5.50S[/tex]
So, total money spent = $3.25+5.50S
Now, this money should be lesser than or equal to $30 because maximum bill that Benjamin wants is $30.
So, the inequality can be written as:
[tex]\bold{3.25+5.50S \le 30}[/tex]
48 - 8x equivalent expression
Answer:
8(6-x)
Step-by-step explanation:
Both 48 and 8 can be divisible by 8.
48 ÷ 8 = 6
8 ÷ 8 = 1
Therefore you get the answer 8(6-x)
as the simplest form.
Hope this helps.
I am really confused... Please help me solve this question!
I hope this helps you
divide 0.377 ÷ 2.9 dosto please solve it
a parabola had a vertex of (-5,0) and passes through the point (-3,1)
Answer:
Step-by-step explanation:
let the parabola be y=a(x+5)²+0
or y=a(x+5)²
∵ it passes through (-3,1)
1=a(-3+5)²
4a=1
a=1/4
so parabola is y=1/4(x+5)²
HELPPPPPPPPPPPPPPPPPPPPPP
Answer:
x= 24, y= 33°
Step-by-step explanation:
MJ is part of the diameter of the circle and there is right angle between the diameter and HK
As the diameter and HK are perpendicular, HM=MK and mHJ= mJK
So,
x= 24and
y= 66°/2= 33°Find the value of each trigonometric ratio.
Answer: 40/41
Step-by-step explanation:
The cosine can be represented as adjacent/hypotenuse. Thus, the cosine of C is 40/41
Answer:
[tex] \frac{40}{41} [/tex]Solution,
BC = 40
AC = 41
Now,
[tex]cos \: theta \: = \frac{adjacent}{hypotenuse} [/tex]
[tex]cos \: c \: = \frac{bc}{ac} [/tex]
Plugging the values
[tex]cos \: c \: = \frac{40}{41} [/tex]
Hope this helps..
Good luck on your assignment..