ind the difference and write the resulting polynom (19x^(4)-17x-18)-(12x^(4)-8x+5)

The factored form of the given quadratic equation is (2x + 7)(x - 2).

To factor a quadratic equation with a leading coefficient, we need to find two numbers that multiply to give us the constant term (-14) and add to give us the middle term (3).

In this case, the two numbers are 7 and -2. We can then use these numbers to rewrite the middle term of the equation and then factor by grouping.

Here are the steps to factor the given quadratic equation:

1. Rewrite the equation with the new middle terms: 2x^(2) + 7x - 2x - 14
2. Group the first two terms and the last two terms: (2x^(2) + 7x) + (-2x - 14)
3. Factor out the greatest common factor from each group: x(2x + 7) - 2(2x + 7)
4. Factor out the common binomial: (2x + 7)(x - 2)

So, the factored form of the given quadratic equation is (2x + 7)(x - 2).

I hope this helps! Let me know if you have any further questions.

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a) The exact distance is 5√2.

b) The midpoint of the line segment is (5.5, 1.5).

Part 1 of 2 (a) The exact distance between the points (9,2) and (2,1) can be found using the distance formula:

Distance = √[(x2 - x1)^2 + (y2 - y1)^2]

Plugging in the given values:

Distance = √[(2 - 9)^2 + (1 - 2)^2]

Simplifying:

Distance = √[(-7)^2 + (-1)^2]

Distance = √[49 + 1]

Distance = √50

Distance = 5√2

Therefore, the exact distance between the points is 5√2.

Part 2 of 2 (b) The midpoint of the line segment whose endpoints are the given points can be found using the midpoint formula:

Midpoint = [(x1 + x2)/2, (y1 + y2)/2]

Plugging in the given values:

Midpoint = [(9 + 2)/2, (2 + 1)/2]

Simplifying:

Midpoint = [11/2, 3/2]

Midpoint = (5.5, 1.5)

Therefore, the midpoint is (5.5, 1.5).

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The total distance traveled by the taxi driver is 7 1/2 miles.

To find out how many miles the taxi driver travels for the two stops, we need to add up the distance to the first stop and the distance to the second stop.

The distance to the first stop is 4 5/8 miles.

To find the distance to the second stop, we need to subtract 1 3/4 miles from the distance to the first stop:

4 5/8 miles - 1 3/4 miles = 2 7/8 miles

Now we can add the distance to the first stop and the distance to the second stop to find the total distance traveled:

4 5/8 miles + 2 7/8 miles

= 7 1/2 miles

Therefore, the taxi driver will travel 7 3/2 miles for the two stops.

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The remainder when -233 is divided by 11 is 9. To find the remainder when a is divided by b, we can use the formula:

r = a % b

Where % is the modulo operator, which gives the remainder when one number is divided by another.

In this case, we have a = -233 and b = 11. Plugging these values into the formula, we get:

r = -233 % 11

Using a calculator or doing the division by hand, we find that the remainder is -2. However, since we are looking for the positive remainder, we can add b to this value to get the correct answer:

r = -2 + 11 = 9

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The graph is symmetric about the y-axis, so its a even function.

EVEN function:

ODD function:

Thus, the graph is symmetric about the y-axis, so its a even function.

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a)P(number greater than 8) = 4/12 = 1/3 ≈ 0.3

b)P(number less than 6) = 5/12 ≈ 0.4

c)If each face has an equal chance of rolling, the solid is fair. The solid is fair since the faces are numbered sequentially from 1 to 12 and each face has an equal chance of being rolled.

One of the number types in algebra that has a whole integer and a fractional portion separated by a decimal point is a decimal. The decimal point is the dot that appears between the parts of a whole number and a fraction. An example of a decimal number is 34.5.

from the question:

a) A solid has 12 equal-sized faces with numbers ranging from 1 to 12. The chance of getting a number larger than 8 is calculated by dividing the total number of faces by the number of faces with numbers greater than 8. Given that there are 4 faces (12 - 8) with numbers greater than 8, the likelihood of drawing one is:

P(number more than 8) = 4/12 = 1/3 =  0.35

b) Similarly, the chance of receiving a number less than 6 is calculated by dividing the total number of faces by the number of faces that have numbers less than 6. Given that there are 6 - 1 = 5 faces with numbers lower than 6, the likelihood of drawing one is as follows:

P(less than six) = 5/12=  0.4

c) If each face has an equal chance of rolling, the solid is fair. The solid is fair since the faces are numbered sequentially from 1 to 12 and each face has an equal chance of being rolled.

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Answer:

for the first, the answers are 1/2, 1, 2, 4, and 8. for the second, 22[tex]\frac{1}{2}[/tex] sq. km.

Step-by-step explanation:

1/4 times 2 is 1/2, times 2 is 1, times 2 is 2, times two is 4, time 2 is 8.

for the second one, area = base times height. 6 3/4 times 3 1/3 is 22 1/2 km squared.

The rate at which the water level is rising when the water is 3m deep is 0.159 m/min.  The rate at which the tip of his shadow is moving when he is 40ft from the pole is 3ft/sec. The volume of a cone is given by V = 1/3πr^2h.

We are given that the base radius is 2m and the height is 4m. We are also given that the rate at which water is being pumped into the tank is 2 m^3/min. We need to find the rate at which the water level is rising when the water is 3m deep.

To find the rate at which the water level is rising, we need to take the derivative of the volume with respect to time. This gives us:

dV/dt = (1/3)π(2r)(dr/dt)(4) + (1/3)π(2^2)(dh/dt)

We know that dV/dt = 2 and r = 2, so we can plug these values into the equation and solve for dh/dt:

2 = (1/3)π(2)(2)(dr/dt)(4) + (1/3)π(2^2)(dh/dt)

Solving for dh/dt gives us:

dh/dt = (6 - 4π(dr/dt))/(4π)

We are given that the water level is 3m deep, so we can plug this value into the equation for the volume of a cone and solve for r:

V = (1/3)πr^2h

3 = (1/3)πr^2(3)

r = √(3/π)

We can now plug this value of r into the equation for dh/dt and solve for dr/dt:

dh/dt = (6 - 4π(√(3/π))(dr/dt))/(4π)

Solving for dr/dt gives us:

dr/dt = (6 - 4π(dh/dt))/(4π√(3/π))

We can now plug this value of dr/dt back into the equation for dh/dt and solve for dh/dt:

dh/dt = (6 - 4π((6 - 4π(dh/dt))/(4π√(3/π))))/(4π)

Solving for dh/dt gives us:

dh/dt = 0.159 m/min

The street light is mounted at the top of a 15ft tall pole and the man is 6ft tall. The man is walking away from the pole with a speed of 5ft/sec along a straight path. We need to find the rate at which the tip of his shadow is moving when he is 40ft from the pole.

We can use the properties of similar triangles to relate the height of the pole, the height of the man, the distance of the man from the pole, and the length of the shadow. Let x be the distance of the man from the pole and y be the length of the shadow. Then we have:

15/x = 6/(x + y)

Cross-multiplying gives us:

15(x + y) = 6x

Simplifying gives us:

9x = 15y

Taking the derivative of both sides with respect to time gives us:

9(dx/dt) = 15(dy/dt)

We are given that dx/dt = 5ft/sec, so we can plug this value into the equation and solve for dy/dt:

9(5) = 15(dy/dt)

Solving for dy/dt gives us:

dy/dt = 3ft/sec

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Answer:

they finished the entire pie

Step-by-step explanation:

The exponential function showing the relationship between y and t is y = 16,000(0.78)^t

From the question, we have the following parameters that can be used in our computation:

Initial value, a = 16000

Rate = 22% decrement

The exponential function for the resale value y of the car, in dollars, after t years since the purchase can be expressed as:

y = a(1 - r)^t

Substitute the known values in the above equation, so, we have the following representation

y = $16,000 x (1 - 0.22)^t

Evaluate

y = 16,000(0.78)^t

Where 0.78 is the factor by which the resale value decreases each year, calculated as (100% - 22%) / 100% = 0.78.

Hence, the function is y = 16,000(0.78)^t

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The probability that the selected chocolate will be either cookies and cream or peanut butter cups are,

let cookies and cream be x

and peanut butter cups be y

As these are the two chocolates in the bag,

there is a 50:50 probability

Hence,

The probability of cookies and cream = 50%

The probability of peanut butter cups=50%

As x+y=total both have equal probability

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2. The given quadratic equation is in the general form:

ax² + bx + c = 0

therefore:

a = 2

b = -4

c = -3

The quadratic formula is thus:

[tex]x=\frac{-b(+-)\sqrt{b^2-4ac} }{2a}[/tex]

Substituting the values found for a, b, and c:

[tex]x=\frac{-(-4)+\sqrt{(-4)^2-4(2)(-3)} }{2(2)}[/tex] and [tex]x=\frac{-(-4)-\sqrt{(-4)^2-4(2)(-3)} }{2(2)}[/tex]

Therefore x = 2.58, x = -0.58

3. Using the same method as above, first, bring all values to one side, leaving the RHS = 0

a = 1

b = 2

c = -1

The quadratic formula is thus:

[tex]x=\frac{-b(+-)\sqrt{b^2-4ac} }{2a}[/tex]

Substituting the values found for a, b, and c:

[tex]x=\frac{-(2)+\sqrt{(2)^2-4(1)(-1)} }{2(1)}[/tex] and [tex]x=\frac{-(2)-\sqrt{(2)^2-4(1)(-1)} }{2(1)}[/tex]

Therefore, x = 0.41, x = -2.41

[tex]2 {x}^{2} - 4x - 3 = 0[/tex]

A Here ,

[tex]\boxed{a = 2 }\\\boxed{b = - 4} \\ \boxed{c = - 3}[/tex]

B Filling in the values of a , b and c in the Quadratic formula below , we get

[tex]x = \frac{- (b)\pm \sqrt{( {b}^{2}) - 4(a)(c) } }{2(a)} \\ [/tex]

C Simplifying each section , we get

[tex]x = \frac{ - ( - 4) + \sqrt{( { - 4}^{2} ) - 4(2)( - 3)} }{2 \times 2} [/tex]

or

[tex]x = \frac{ - ( - 4) - \sqrt{ {( - 4})^{2} - 4(2)( - 3) } }{2 \times 2} [/tex]

D Simplifying answers from Part C , we get

[tex]\boxed{x = \frac{2 + \sqrt{10} }{2}} \: \: \: \: or \: \: \: \: \boxed{ x = \frac{2 - \sqrt{10} }{2} } \\ [/tex]

Therefore ,

[tex]\boxed{x = 2.58} \: \: \: \: and \: \: \: \: \boxed{x = - 0.58}[/tex]

_____________________________________

[tex] {x}^{2} + 2x = 1 \\ \implies \: {x}^{2} + 2x - 1 = 0[/tex]

A Here ,

[tex]\boxed{a = 1} \\ \boxed{b = 2} \\ \boxed{c = - 1}[/tex]

B Filling in the values of a , b and c in the Quadratic formula below , we get

[tex]x = \frac{- (b)\pm \sqrt{( {b}^{2}) - 4(a)(c) } }{2(a)} \\ [/tex]

C Simplifying each section , we get

[tex]x = \frac{ - (2) + \sqrt{ ({2}^{2} ) - 4(1)( - 1)} }{2 \times 1} [/tex]

or

[tex]x = \frac{ - (2) - \sqrt{( {2}^{2}) - 4(1)( - 1) } }{2 \times 1} [/tex]

D Simplifying answers from Part C , we get

[tex]\boxed{x = - 1 + \sqrt{2} } \: \: \: \: or \: \: \: \: \boxed{x = - 1 - \sqrt{2} }[/tex]

Therefore

[tex]\boxed{x = 0.41} \: \: \: \: or \: \: \: \: \boxed{x = -2.41 }[/tex]

hope helpful! :)

Answer:

See graph below

Step-by-step explanation:

You start at the origin (0,0).  The first number in the ordered pair tells you to go right or left.  If the number is positive you go to the right.  If the number is negative, you go to the left.  

Next, you go up or down. If the number is positive, you go up and if the number is negative you go down.  At that spot, you plot your point.

Helping in the name of Jesus.

The plot of the given points on the coordinate grid is shown

To plot the given points on the coordinate grid, follow these steps:

1. Start with point A(0,-3). This point has an x-coordinate of 0 and a y-coordinate of -3. To plot this point, start at the origin (0,0) and move 3 units down on the y-axis. Mark this point with a dot and label it as point A.

2. Next, plot point B(-2,0). This point has an x-coordinate of -2 and a y-coordinate of 0. To plot this point, start at the origin (0,0) and move 2 units to the left on the x-axis. Mark this point with a dot and label it as point B.

3. Now, plot point C(-1,4). This point has an x-coordinate of -1 and a y-coordinate of 4. To plot this point, start at the origin (0,0) and move 1 unit to the left on the x-axis and 4 units up on the y-axis. Mark this point with a dot and label it as point C.

4. Finally, plot point D(3,-4). This point has an x-coordinate of 3 and a y-coordinate of -4. To plot this point, start at the origin (0,0) and move 3 units to the right on the x-axis and 4 units down on the y-axis. Mark this point with a dot and label it as point D.




So, the plot of the given points on the coordinate grid is shown above.

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Answer:

1.5x + 2y = 12

Step-by-step explanation:

The equation representing Serena’s spending on snacks today would be 1.5x + 2y = 12, where x represents the number of drinks purchased and y represents the number of bags of chips purchased.

Therefore, the equation is 1.5x + 2y = 12.

Answer: 5,948 feet

Step-by-step explanation:

All you really need to do in this problem is subtract 22,834 - 16,896 as shown below:

22,834 - 16,836 = 5,948 feet

The correct answer is f^-1(x) = (8-√x)/2; f^-1 is a function.

To find the inverse of the function f(x) = (8-2x)^2, we need to switch the x and y variables and solve for y. This will give us f^-1(x).

So, we start with:

x = (8-2y)^2

Next, we take the square root of both sides:

√x = 8-2y

Then, we isolate the y variable:

2y = 8-√x

y = (8-√x)/2

So, the inverse of the function is:

f^-1(x) = (8-√x)/2

Now, we need to determine whether f^-1(x) is a function. To do this, we can use the horizontal line test. If a horizontal line intersects the graph of f^-1(x) at more than one point, then f^-1(x) is not a function.

In this case, a horizontal line will only intersect the graph of f^-1(x) at one point, so f^-1(x) is a function.

Therefore, the correct answer is f^-1(x) = (8-√x)/2; f^-1 is a function.

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Answer:

Step-by-step explanation:

You want the weights of trains A and B if the sum of their weights is 184 tons and the difference of their weights is 90 tons.

We can write the equations for the weights as ...

  A +B = 184

  A -B = 90

Adding the two equations gives ...

  2A = 274

  A = 137

Subtracting the second equation from the first gives ...

  2B = 94

  B = 47

Train A weighs 137 tons; train B weighs 47 tons.

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Answer: B' is (1, -2)

Step-by-step explanation:

Point B is (5, 1), so subtract 4 from 5 and subtract 3 from 1 so,

5 - 4 = 1

1 - 3 = -2

B' is (1, -2)

Hope this helps!

The answer is no, these data do not indicate that the percentage of wheat crop lost to hail in that county is different (either way) from the national mean of 11%.

The sample mean is x = 12.1% and the population mean is μ = 11%. We want to test if there is a significant difference between the sample mean and the population mean. We can use a t-test to compare the means.

The null hypothesis is H0: μ = 11%, and the alternative hypothesis is Ha: μ ≠ 11%.

The t-statistic is calculated as:

t = (x - μ) / (σ / √n)

where x is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size.

Plugging in the values, we get:

t = (12.1 - 11) / (5.0 / √16)
t = 1.1 / (5.0 / 4)
t = 0.88

Using a t-table with degrees of freedom (df) = 16 - 1 = 15 and α = 0.01, we find the critical value to be 2.947. Since the absolute value of the t-statistic (0.88) is less than the critical value (2.947), we fail to reject the null hypothesis. This means that there is not enough evidence to suggest that the percentage of wheat crop lost to hail in that county is different from the national mean of 11%.

Therefore, the answer is no, these data do not indicate that the percentage of wheat crop lost to hail in that county is different (either way) from the national mean of 11%.

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The equation in slope-intercept form for the line with slope (2)/(3) and y-intercept -6 is:

y = (2) / (3)x - 6.

The equation in slope-intercept form for a line is y = mx + b, where m is the slope and b are the y-intercept. Since the slope is (2)/(3) and the y-intercept is -6, we can substitute these values into the equation to get:

y = (2)/(3)x + (-6)

Simplifying this equation gives us:

y = (2)/(3)x - 6

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The volume of the cylinder is approximately 40,107.6 cubic yards.

What is the volume of the cylinder?

The formula for the volume of a right circular cylinder is:

[tex]V = \pi r^2h[/tex]

The formula for the volume of a right circular cylinder is:

[tex]V = \pi r^2h[/tex]

Substituting the given values:

V = 3.14 x 17.2² x 45.3

V = 3.14 x 296.84 x 45.3

V = 40,107.6152 cubic yards

Rounding to the nearest tenth:

V ≈ 40,107.6 cubic yards

Therefore, the volume of the cylinder is approximately 40,107.6 cubic yards.

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Answer: 42080.87328 or 42,080.9 rounded to the nearest tenth

Step-by-step explanation:

V=πr2

V= 3.14 x 17.2 x 45.3

V= 3.14 x 17.2 squared x 45.3

= 17.2 squared is 295.84

V= 3.14 x 295.84 x 45.3

V= 42,080.87328

round it to nearest tenth and get 42,080.9 yd

end{bmatrix} = \begin{bmatrix} 1 \\ \frac{1}{5} \\ 1 \end{bmatrix}.

(a) Let $a^1 = \begin{bmatrix} 1 \\ 1 \\ 2 \\ 1 \end{bmatrix}, a^2 = \begin{bmatrix} -1 \\ 2 \\ 0 \\ -2 \end{bmatrix},$ and $a^3 = \begin{bmatrix} 1 \\ 4 \\ 4 \\ 0 \end{bmatrix}.$ Write the matrix $A = \begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix}$ in the form $A = QR$ by using the Gram-Schmidt process. (b) Use the QR factorization of $A$ in part (a) to solve the equation $Ax = b,$ where $b = \begin{bmatrix} 3 \\ 1 \\ 2 \\ 1 \end{bmatrix}.$The Gram-Schmidt algorithm is a numerical method to produce orthonormal basis of a subspace in Hilbert space that spans the same space, which makes the basis more convenient to work with. As for the first part of the question, let us begin by applying the Gram-Schmidt algorithm to $a^1, a^2, a^3.$ We begin by defining $q_1 = a^1 / \|a^1\|.$ Hence,$$q_1 = \frac{1}{3}\begin{bmatrix} 1 \\ 1 \\ 2 \\ 1 \end{bmatrix} = \begin{bmatrix} 1/3 \\ 1/3 \\ 2/3 \\ 1/3 \end{bmatrix}.$$Next, we define $v_2 = a^2 - \langle q_1, a^2 \rangle q_1.$ Therefore,$$v_2 = a^2 - \frac{-1}{3}(1/3)q_1 = \begin{bmatrix} -7/9 \\ 8/9 \\ -2/9 \\ -4/9 \end{bmatrix}.$$Now, we can define $q_2 = v_2 / \|v_2\|.$ Thus,$$q_2 = \frac{1}{3}\begin{bmatrix} -7 \\ 8 \\ -2 \\ -4 \end{bmatrix}.$$Finally, we define $v_3 = a^3 - \langle q_1, a^3 \rangle q_1 - \langle q_2, a^3 \rangle q_2.$ Then,$$v_3 = a^3 - \frac{5}{9}q_1 - \frac{7}{27}q_2 = \begin{bmatrix} -1/27 \\ 5/9 \\ 22/27 \\ -5/27 \end{bmatrix}.$$Lastly, we can define $q_3 = v_3 / \|v_3\|,$ so$$q_3 = \frac{1}{3}\begin{bmatrix} -1 \\ 5 \\ 22 \\ -5 \end{bmatrix}.$$Now, we can write $A = QR$ as $$\begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix} = \begin{bmatrix} q_1 & q_2 & q_3 \end{bmatrix} \begin{bmatrix} r_{11} & r_{12} & r_{13} \\ 0 & r_{22} & r_{23} \\ 0 & 0 & r_{33} \end{bmatrix}.$$We can obtain the entries of the $R$ matrix by calculating the inner product of each $q_i$ with $a^j.$ Thus,$$r_{11} = \|a^1\| = \sqrt{7},$$$$r_{12} = \langle q_1, a^2 \rangle = \frac{-1}{3}\sqrt{7},$$$$r_{13} = \langle q_1, a^3 \rangle = \frac{5}{9}\sqrt{7},$$$$r_{22} = \|v_2\| = \frac{5}{3}\sqrt{2},$$$$r_{23} = \langle q_2, a^3 \rangle = \frac{-7}{9}\sqrt{2},$$$$r_{33} = \|v_3\| = \frac{2}{3}\sqrt{6}.$$Therefore,$$\begin{bmatrix} a^1 & a^2 & a^3 \end{bmatrix} = \begin{bmatrix} q_1 & q_2 & q_3 \end{bmatrix} \begin{bmatrix} \sqrt{7} & -\frac{1}{3}\sqrt{7} & \frac{5}{9}\sqrt{7} \\ 0 & \frac{5}{3}\sqrt{2} & -\frac{7}{9}\sqrt{2} \\ 0 & 0 & \frac{2}{3}\sqrt{6} \end{bmatrix}.$$Now, let us solve the equation $Ax = b$ by using the QR factorization of $A.$ We can write $Ax = QRx = b.$ Since $Q$ is orthogonal, we can multiply both sides of the equation by $Q^T$ to obtain $Rx = Q^Tb.$ Note that $Q^Tb$ is easy to compute since $Q^T$ is just the matrix with the $q_i$'s as rows. Thus,$$\begin{bmatrix} \sqrt{7} & -\frac{1}{3}\sqrt{7} & \frac{5}{9}\sqrt{7} \\ 0 & \frac{5}{3}\sqrt{2} & -\frac{7}{9}\sqrt{2} \\ 0 & 0 & \frac{2}{3}\sqrt{6} \end{bmatrix} \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = \begin{bmatrix} \frac{2}{3} \\ \frac{1}{3} \\ \frac{2}{3} \end{bmatrix}.$$This gives the system of equations$$\begin{cases} \sqrt{7}x_1 - \frac{1}{3}\sqrt{7}x_2 + \frac{5}{9}\sqrt{7}x_3 = \frac{2}{3}, \\ \frac{5}{3}\sqrt{2}x_2 - \frac{7}{9}\sqrt{2}x_3 = \frac{1}{3}, \\ \frac{2}{3}\sqrt{6}x_3 = \frac{2}{3}. \end{cases}$$Solving the last equation for $x_3,$ we obtain $x_3 = 1.$ Substituting this into the second equation, we obtain $x_2 = \frac{1}{5}.$ Finally, substituting these values into the first equation gives us $x_1 = 1.$ Therefore,$$x = \begin{bmatrix} x_1 \\ x_2 \\ x_3 \end{bmatrix} = \begin{bmatrix} 1 \\ \frac{1}{5} \\ 1 \end{bmatrix}.$$

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Answer:

Let's call the first of the three consecutive integers "x".

According to the problem, the third integer (which is the one after the first two) is equal to twice the first increased by five. We can express this algebraically as:

third integer = 2x + 5

Since the three integers are consecutive, the second integer must be one more than the first, and the third must be one more than the second. So, the second integer can be expressed as:

second integer = x + 1

And the third integer is:

third integer = (x + 1) + 1 = x + 2

Now we can set these two expressions for the third integer equal to each other, since they both represent the same value:

2x + 5 = x + 2

Simplifying and solving for x, we get:

x = -3

So the first of the three consecutive integers is -3. The second is one more than the first, which is -3 + 1 = -2. And the third is one more than the second, which is -2 + 1 = -1. Therefore, the three consecutive integers are -3, -2, and -1.

Answer:

Step-by-step explanation:

A line that is parallel to the first line will have the same slope, so:

m = -3

X1 and y1 are basically the coordinates where the new line intersects, which is x1 = -1, and y1 = 6

Point-slope form:

y - 6 = -3(x - (-1))

y-6 = -3(x+1)

Slope-intercept form:

y - 6 = -3x - 3

y = -3x + 3

Hope this helps!

Answer:

Step-by-step explanation:

(-1,6) + (-3x + 4) = (-4x,10). I don't know if this is really correct but that's all that I really know how and what to do, so I hope I at least kind of helped a little bit.

Answer:

The number is → 56

Step-by-step explanation:

tens digit [tex]\Rightarrow x[/tex]

unit digit [tex]\Rightarrow y[/tex]

"The difference between the digits of a two-digit number is 1...", " ...the unit digit is greater than the tens digit..."

[tex]y-x=1 \qquad \textbf{ec.1}[/tex]

"The number itself is one more (unit) than five times the sum of its digits..."

[tex]10x+y=5(x+y)+1\\ 10x+y= 5x + 5y+1\\5x= 4y+1 \qquad \textbf{ec.2}[/tex]

we clear "y" in equation 1:

[tex]y=1+x \qquad \textbf{ec.3}[/tex]

then we substitute in equation 2:

[tex]5x=4(1+x)+1\\5x=5+4x\\\boxed{x=5}[/tex]

Finally, we substitute in equation 3:

[tex]y=1+5\\\boxed{y=6}[/tex]

With this we have solved the exercise.

[tex]\text{-B$\mathfrak{randon}$VN}[/tex]

The basis for span((1,−1,2,2),(2,2,1,1),(2,−1,−1,0),(4,2,−5,−3)) is {(1,−1,2,2), (2,2,1,1), (2,−1,−1,0), (4,2,−5,−3)}.

A basis for a vector space is a set of linearly independent vectors that span the vector space. In this case, we need to find a basis for the vector space spanned by the given vectors (1,−1,2,2), (2,2,1,1), (2,−1,−1,0), and (4,2,−5,−3).

To find a basis, we can use the row reduction method. First, we write the given vectors as rows of a matrix:

```
1 -1  2  2
2  2  1  1
2 -1 -1  0
4  2 -5 -3
```

Next, we use row operations to reduce the matrix to row echelon form:

```
1 -1  2  2
0  4 -3 -3
0  0 -5 -4
0  0  0  2
```

Now, we can see that the first, second, third, and fourth rows are all linearly independent (since they all have a leading 1 in a different column). Therefore, the original vectors (1,−1,2,2), (2,2,1,1), (2,−1,−1,0), and (4,2,−5,−3) form a basis for the vector space.

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Based on the probability distribution, the probability of a randomly selected account having 4 devices is 0.08. The probability of a randomly selected account having at least 3 devices is 0.44. The probability of a randomly selected account having 2 or 4 devices is 0.51. The mean number of devices per account is 2.39. The standard deviation of the distribution is 1.108. The probability that the number of devices in a randomly selected account lies within one standard deviation of the mean (inclusive) is 0.80.

For the given probability distribution, the probability of a randomly selected account having 4 devices is 0.08. This is because the total probability of all possible outcomes must equal 1. So, we can find the missing probability by subtracting the probabilities of the other outcomes from 1:

1 - 0.13 - 0.43 - 0.29 - 0.07 = 0.08

The probability of a randomly selected account having at least 3 devices is the sum of the probabilities of having 3, 4, or 5 devices:

0.29 + 0.08 + 0.07 = 0.44

The probability of a randomly selected account having 2 or 4 devices is the sum of the probabilities of having 2 and 4 devices:

0.43 + 0.08 = 0.51

The mean number of devices per account can be found by multiplying each possible outcome by its probability and summing the results:

(1)(0.13) + (2)(0.43) + (3)(0.29) + (4)(0.08) + (5)(0.07) = 2.39

The standard deviation of the distribution can be found by first calculating the variance and then taking the square root:

Variance = (1-2.39)^2(0.13) + (2-2.39)^2(0.43) + (3-2.39)^2(0.29) + (4-2.39)^2(0.08) + (5-2.39)^2(0.07) = 1.2279

Standard deviation = √1.2279 = 1.108

The probability that the number of devices in a randomly selected account lies within one standard deviation of the mean (inclusive) is the sum of the probabilities of the outcomes that fall within this range:

0.43 + 0.29 + 0.08 = 0.80

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The error that occurred is called a transposition error.

A transposition error is when two digits are reversed or transposed in an accounting transaction. In this case, the debit that was supposed to be made to the Purchaser account was instead debited to the Accounts Payable account.

To correct this error, we need to make a journal entry that reverses the incorrect entry and then make the correct entry. The journal entry to reverse the incorrect entry would be:

Debit: Accounts Payable $5,000
Credit: Purchaser $5,000

This entry reverses the incorrect debit to Accounts Payable and the incorrect credit to Purchaser.

Next, we need to make the correct entry, which is:

Debit: Purchaser $5,000
Credit: Accounts Payable $5,000

This entry correctly debits the Purchaser account and credits the Accounts Payable account.

After these two journal entries are made, the accounts will be correctly balanced and the error will be corrected.

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complete question

A P^(5),000 debit to be made to the Purchaser account was debited to Accounts payabhe instead. which type of error is found here?

Answers:

7. x=4.8          8. x=36.6       9. x=36.9  10. x=17.8

Work is shown in the picture below, I'm learning this stuff right now too, so I hope it helps!

24 buckets of gravel are needed for 4 buckets of cement.

In its most basic form, a ratio is a comparison between two comparable quantities.

There are two types of proportions One is the direct proportion, whereby increasing one number by a constant k also increases the other quantity by the same constant k, and vice versa.

If one quantity is increased by a constant k, the other will decrease by the same constant k in the case of inverse proportion, and vice versa.

Given, Concrete tiles are made using buckets of cement, sand, and gravel mixed into the ratio of 1 : 4 : 6.

Now, 4×1 : 4×4 : 4×6, when it is 4 bucket of cement.

4 : 16 : 24.

Therefore, 24 buckets of gravel needed.

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