Answer:
The answer is "For the stop and wait the value of S and R is equal to 1".
Explanation:
As we know that, the SR protocol is also known as the automatic repeat request (ARQ), this process allows the sender to sends a series of frames with window size, without waiting for the particular ACK of the recipient including with Go-Back-N ARQ. This process is mainly used in the data link layer, which uses the sliding window method for the reliable provisioning of data frames, that's why for the SR protocol the value of S =R and S> 1.Below is some info for some internet transactions. We want to sort it by time and by location. Which sorting algorithm is appropriate for this particular problem?
a. radix sort.
b. heap sort.
c. selection sort.
d. shell sort.
Answer:
c. selection sort
Explanation:
The best way to sort the internet transactions data based on time and location is selection sort. The algorithms sorting technique is used to sort the complex data in computer programs. Shell sort is the technique which sorts the data apart from each other and reduces interval between them. Heap sort is sorting technique based on binary heap data structure. Radix sort is an integer sorting technique in algorithms.
Write a telephone lookup program. Read a data set of 1,000 names and telephone numbers from a file (directory.txt) that contains the numbers in random order. Handle lookups by name and also reverse lookups by phone number. Use a binary search for both lookups. A driver program and templates have been created for you.
Answer:
Here is the JAVA program:
Items.java
public class Item { // Item class
private String name, ph_num; // class data members name to hold the name and ph_num stores the telephone numbers
public Item(String fullName, String PhoneNo){ //constructor of Item class , so fields full name and ph_num can be initialized when the object is created
name = fullName; // holds the name field
ph_num = PhoneNo;} //holds the telephone number
public String getFullName(){ // accessor method to get access to the name field
return name;} //returns the name from directory
public String getPhoneNo(){ //accessor method to get access to the ph_nujm field
return ph_num; } } //returns the telephone number
Explanation:
LookupTable.java
public class LookupTable{ //class name
private ArrayList<Item> data; // dynamic array list named data of Item class. This array list stores the names and telephone numbers from file
public LookupTable(){ //default constructor
data = new ArrayList<Item>();} // creates an array list of Item type which holds the names and phone numbers
public void read(Scanner in){ // Scanner class object is created and this class is used to read input and the method reads the names and phone numbers
while(in.hasNext()){ // the loop moves through each line of the file. scanner class method hasNext checks for the tokens in the input
String name = in.nextLine(); // scans for the name in the input
String ph_num = in.nextLine(); //scans for the phone numbers in the input
data.add(new Item(name, ph_num));}} // adds the names and phone number in to the Array list
public String lookup(String k){ //method looks up for an item in the table. param k is the key to find . returns the value with the given key, or null if no such item was found
String result = null; //result initialized to to null
for(Item item: data){ //creates Item object and traverses the array list for each item i.e. name or phone numbers
if(k.equals(item.getFullName())){ //access the getFullName method through object item and checks if that name matches the key to find.
result = item.getPhoneNo();}} //gets the corresponding phone number and assigns it to result variable
return result;} //returns the result containing the phone number
public String reverseLookup(String v){ //Looks up an item in the table. param v is the value to find . returns the key with the given value, or null if no such item was found. This method performs the lookup through phone number
String result = null; //result is set to null to start
for(Item item: data){ //Traversing list through the for each item in data
if(v.equals(item.getPhoneNo())){ //if the value of v is equal to the phone number accessed by using accessor method and object item
result = item.getFullName();}} //accesses the corresponding name of that phone number and assigns it to the result
return result;}} //returns the result
The data from directory file which contains the number and names. The LookupTable class has a method lookup which handles the lookups by names and the method reverseLookup that handles the lookups by phone number.
Velma is graduating from Ashford at the end of next year. After she completes her final class, she will reward herself for her hard work with a week-long vacation in Hawaii. But she wants to begin saving money for her trip now. Which of the following is the most effective way for Velma to save money each month?
This question is incomplete because the options are missing; here are the options for this question:
Which of the following is the most effective way for Velma to save money each month?
A. Automatically reroute a portion of her paycheck to her savings account.
B. Manually deposit 10% of her paycheck in her savings account.
C. Pay all of her bills and then place the remaining money in her savings account.
D. Pay all of her bills and then place the remaining money in her piggy bank.
The correct answer to this question is A. Automatically reroute a portion of her paycheck to her savings account.
Explanation:
In this case, Velma needs to consistently save money for her vacation as this guarantees she will have the money for the trip. This means it is ideal every month she contributes consistently to her savings for the vacation.
This can be better be achieved by automatically rerouting a part of her paycheck for this purpose (Option A) because in this way, every month the money for the vacations will increase and the amount of money will be consistent, which means Velma will know beforehand the money she will have for the vacation. Moreover, options such as using a piggy bank or paying the bills and using the rest for her savings, do not guarantee she will contribute to the savings every month, or she will have the money she needs at the end.
Write a small program that asks the user how many asterisks it should print out. The user responds with a number, then the program prints that number of asterisks.
Answer:
I am writing a C++ program. Let me know if you want the program in some other programming language.
#include <iostream> //to use input output functions
using namespace std; // to identify objects like cin cout
int main(){ //start of main() function body
int n; // number of asterisks
cout<<"how many asterisks do you want to print? "; //asks user how many asterisks it should print
cin>>n; // reads the value of number of asterisks that user want to print
for( int i=0; i< n; i++) { //loop to display the number of asterisks in output
printf("*"); } } // print * asterisks
Explanation:
I will explain how the for loop works.
Suppose the user entered 3 as number of asterisks that user wants to print.
So n=3
Now for loop has a variable i that is initialized to 0. For loop checks if the value of i is less than that of n. It is true because i=0 and n=3 and 0<3. So the body of the loop executes. This prints the first asterisk *
Then the value of i is incremented to 1 and becomes i=1
At next iteration loop again checks if value of i is less than n. It is true because i=1 and n=3 and 1<3. So the body of the loop executes. This prints the second asterisk **
Then the value of i is incremented to 1 and becomes i=2
At next iteration loop again checks if value of i is less than n. It is true because i=2 and n=3 and 2<3. So the body of the loop executes. This prints the third asterisk ***
Then the value of i is incremented to 1 and becomes i=3
At next iteration loop again checks if value of i is less than n. This time it evaluates to false because i=3 and n=3 so 3=3. So the loop ends and the output is
***
The output screenshot is attached.
Define the instance method inc_num_kids() for PersonInfo. inc_num_kids increments the member data num_kids. Sample output for the given program with one call to inc_num_kids():
Answer:
This is the instance method inc_num_kids()
def inc_num_kids(self):
self.num_kids += 1
Explanation:
The first line is the definition of function inc_num_kids() which has a parameter self. self is basically an instance of class PersonInfo
self.num_kids += 1 this statement incremented the data member num_kids by 1. This means that the instance method inc_num_kids, using instance self, increments the value of num_kids data member by 1.
The complete program is as following:
class PersonInfo: #class name PersonInfo
def __init__(self): #constructor of the class
self.num_kids = 0 # data member num_kids
def inc_num_kids(self): # method inc_num_kids
self.num_kids += 1 #increments num_kids by 1
person1 = PersonInfo() #creates object person of class PersonInfo
print('Kids:', person1.num_kids) # prints num_kids value before increment
person1.inc_num_kids() #calls inc_num_kids method to increment num_kids
print('New baby, kids now:', person1.num_kids) #prints the value of num_kids after increment by inc_num_kids method
The person1 object first access the initial value of num_kids initialized by the constructor. So the first value of num_kids is 0. self.num_kids = 0 This statement assigns the value 0 to num_kids data member. Next the method inc_num_kids() using the object person1. Now when this method is called the value of data member num_kids is incremented to 1.
So previously the value was 0 which now increments by 1 and becomes 1. Last print statement displays this new value which is incremented by the inc_num_kids() method.
Hence the output is:
Kids: 0
New baby, kids now: 1
The program along with its output is attached.
In this exercise we have to use the knowledge of computational language in python to describe a code, like this:
The code can be found in the attached image.
To make it easier the code can be found below as:
class PersonInfo:
def __init__(self):
self.num_kids = 0
def inc_num_kids(self):
self.num_kids += 1
person1 = PersonInfo()
print('Kids:', person1.num_kids)
person1.inc_num_kids()
print('New baby, kids now:', person1.num_kids)
See more about python at brainly.com/question/26104476
A use case description is the best place to start for the design of the forms for a user interface. True False
Answer:
false
Explanation:
Kaiden would like to find the list of physical disk drives that are connected to a Linux system. Which directory contains a subdirectory for each drive
Answer:
The answer is "\root"
Explanation:
The root directory is the part of the Linux OS directory, which includes most other system files and folders but is specified by a forward slash (/). These directories are the hierarchy, which is used to organize files and folders on a device in a standardized protocol framework. This root is also known as the top directory because it .supplied by the os and also is designated especially, that's why it is simply called root.Implement function easyCrypto() that takes as input a string and prints its encryption
defined as follows: Every character at an odd position i in the alphabet will be
encrypted with the character at position i+1, and every character at an even position i
will be encrypted with the character at position i 1. In other words, ‘a’ is encrypted with
‘b’, ‘b’ with ‘a’, ‘c’ with ‘d’, ‘d’ with ‘c’, and so on. Lowercase characters should remain
lowercase, and uppercase characters should remain uppercase.
>>> easyCrypto('abc')
bad
>>> easyCrypto('Z00')
YPP
Answer:
The program written in python is as follows;
import string
def easyCrypto(inputstring):
for i in range(len(inputstring)):
try:
ind = string.ascii_lowercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_lowercase[ind-1],end="")
else:
print(string.ascii_lowercase[ind+1],end="")
except:
ind = string.ascii_uppercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_uppercase[ind-1],end="")
else:
print(string.ascii_uppercase[ind+1],end="")
anystring = input("Enter a string: ")
easyCrypto(anystring)
Explanation:
The first line imports the string module into the program
import string
The functipn easyCrypto() starts here
def easyCrypto(inputstring):
This line iterates through each character in the input string
for i in range(len(inputstring)):
The try except handles the error in the program
try:
This line gets the index of the current character (lower case)
ind = string.ascii_lowercase.index(inputstring[i])
This line adds 1 to the index
pos = ind+1
This line checks if the character is at even position
if pos%2 == 0:
If yes, it returns the alphabet before it
print(string.ascii_lowercase[ind-1],end="")
else:
It returns the alphabet after it, if otherwise
print(string.ascii_lowercase[ind+1],end="")
The except block does the same thing as the try block, but it handles uppercase letters
except:
ind = string.ascii_uppercase.index(inputstring[i])
pos = ind+1
if pos%2 == 0:
print(string.ascii_uppercase[ind-1],end="")
else:
print(string.ascii_uppercase[ind+1],end="")
The main starts here
This line prompts user for input
anystring = input("Enter a string: ")
This line calls the easyCrypto() function
easyCrypto(anystring)
why does study state that unless you were sleeping it is almost impossible not to be communicating?
Answer:
Because your movements, expressions, and posture are also a type of communication
Explanation:
a) five benefits of having
an operating system over not having one.
Answer:
Software Updates, Computing Sources, No Coding, Relatively Inexpensive, Safeguards Data.
Explanation:
Consider a system running ten I/O-bound tasks and one CPU-bound task. Assume that the I/O-bound tasks issue an I/O operation once for every millisecond of CPU computing and that each I/O operation takes 10 milliseconds to complete. Also assume that the context switching overhead is 0.1 millisecond and that all processes are long-running tasks. What is the CPU utilization for a round-robin scheduler when:
Answer:
10 minutes
Explanation:
Write a C function check(x, y, n) that returns 1 if both x and y fall between 0 and n-1 inclusive. The function should return 0 otherwise. Assume that x, y and n are all of type int.
Answer:
See comments for line by line explanation (Lines that begins with // are comments)
The function written in C, is as follows:
//The function starts here
int check(x,y,n)
{
//This if condition checks if x and y are within range of 0 to n - 1
if((x>=0 && x<=n-1) && (y>=0 && y<=n-1))
{
//If the if conditional statement is true, the function returns 1
return 1;
}
else
{
//If the if conditional statement is false, the function returns 0
return 0;
}
//The if condition ends here
}
//The function ends here
Explanation:
Modularize the program by adding the following 4 functions. None of them have any parameters. void displayMenu() void findSquareArea() void findCircleArea() void findTriangleArea() To do that you will need to carry out the following steps: Write prototypes for the four functions and place them above main. Write function definitions (consisting of a function header and initially empty body) for the four functions and place them below main. Move the appropriate code out of main and into the body of each function. Move variable definitions in main for variables no longer in main to whatever functions now use those variables. They will be local variables in those functions. For example, findSquareArea will need to define the side variable and findCircleArea will need to define the radius variable. All of the functions that compute areas will now need to define a variable named area. Move the definition for the named constant PI out of main and place it above the main function. In main, replace each block of removed code with a function call to the function now containing that block of code.
Answer:
It is a C++ program :
#include <iostream> // to use input output functions
using namespace std; //to identify objects like cin cout
//following are the prototypes for the four functions placed above main
void displayMenu();
void findSquareArea();
void findCircleArea();
void findTriangleArea();
//definition for constant PI out of main
const float PI = 3.14159;
int main(){ //start of main function
displayMenu(); //calls displayMenu() method
}
void displayMenu(){ // to make user selection and calls relevant function to compute area according to the choice of user
int selection=0; //to choose from 4 options
cout<<"Program to calculate areas of objects:\n" ; //displays this message at start
do { //this loop asks user to enter a choice and this continues to execute and calculate depending on users choice until user enters 4 to exit
cout<<"\n1.Square \n2.Circle \n3.Right Triangle \n4.Quit";
cout<<"\nEnter your choice:"; //prompts user to enter choice
cin>>selection; //reads the input choice
if(selection==1) //if user enters 1
{ //computes area of square by calling findSquareArea
findSquareArea(); //function call to the findSquareArea function
}
else if(selection==2) //if user enters 2
{ //computes area of circle by calling findCircleArea
findCircleArea(); //function call to the findCircleArea function
}
else if(selection==3) //if user enters 3
{ //computes area of triangle by calling findTriangleArea
findTriangleArea(); //function call to the findTriangleArea function
}
else if(selection==4) //if user enters 4
{
cout<<"\nTerminating!!."; //exits after displaying this message
break;
}
else // displays the following message if user enters anything other than the given choices
{
cout<<"\nInvalid selection"; //displays this message
}
}
while(1);
}
void findSquareArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of square
float side=0; //local variable of this method that stores value of side of square
cout<<"\nLength of side: "; //prompts user to enter length of side
cin>>side; //reads value of side from user
area=side*side; //formula to compute area of square and result is assigned to area variable
cout<<"\nArea of Square: "<<area<<endl; //displays are of the square
}
void findCircleArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of square
float radius=0.0; //local variable of this method that stores value of radius of circle
cout<<"\nRadius of circle: "; //prompts user to enter radius of circle
cin>>radius; // reads input value of radius
area=PI*radius*radius; //formula to compute area of circle
cout<<"\nArea of circle: "<<area<<endl;} //displays are of the circle
void findTriangleArea(){ //function definition. this function has no parameters
float area=0.0; //variable to store the area of triangle
float base=0.0; //local variable of this method that stores value of base of triangle
float height=0.0; //holds value of height of triangle
cout<<"\nHeight of Triangle: "; //prompts user to enter height
cin>>height; //reads input value of height
cout<<"\nBase of Triangle: "; //prompts user to enter base
cin>>base; //reads input value of base
area=0.5*height*base; //computes area of triangle and assign the result to area variable
cout<<"\nArea of Triangle: "<<area<<endl; //displays area of triangle
}
Explanation:
The program is modified as above. The prototypes for the four functions that are named as :
void displayMenu(); to display the Menu of choices and call relevant function to compute area
void findSquareArea(); To compute area of square
void findCircleArea(); To compute area of circle
void findTriangleArea(); To compute area of triangle
Note that these methods have no parameters and their return type is void. These 4 methods prototypes are placed above main() function.
Next the function definitions (consisting of a function header and initially empty body) for the four functions are written and placed below main() For example definition of findTriangleArea() is given below:
void findTriangleArea()
{
}
Next the code in the main is moved to the relevant methods. Then variables selection=0; is moved to displayMenu method, radius=0.0 to findCircleArea method , side=0; to findSquareArea float area=0.0; to each method, float height=0.0; and float base=0.0; to findTriangleArea method.
The relevant code moved to each method is shown in the above code.
The definition for the named constant PI is moved out of main and placed above the main function. const keyword before datatype of PI variable shows that PI is declared constant and its value is initialized once only to 3.14159.
Say our confusion matrix is as follows, calculate precision, recall, and accuracy. Interpret the results for the positive class. Show and explain work.
[25 4
3 25]
Type the correct answer in the box.
Who is responsible for creating and testing the incident response plan?
The _______ is responsible for creating and testing the incident response plan.
Answer: CSIRT
Explanation: CSIRT is team that specializes in day to day cyber incidents
The CSIRT is responsible for creating and testing the incident response plan.
What is CSIRT?CSIRT is the Computer emergency response team. One of the key areas for the efficient operation of a corporation is the legal department. Professionals face enormous challenges, particularly when you take into account the need for other bodies within the company itself.
We can list the reviews of the CSIRT procedures that are conducted through this department as one of its key responsibilities. This department also has the responsibility of comprehending the actions that the CSIRT will take to ensure that they comply with all applicable federal, state, and local laws and regulations.
Therefore, the incident response strategy must be written and tested by the CSIRT.
To learn more about CSIRT, refer to the link:
https://brainly.com/question/18493737
#SPJ2
what is the difference between head header and heading in HTML
Answer:
<Head>the appears the "<body>" of a web page.
<Heading> the appears the body of the web page.
Explanation:<Head> it contains that provides the information about web page.
<Heading> it contains such as the title,date, summary.
<Heading> are the<h1>,<h2>,tags
it provides the title and subtitles of the web page.
<Heading>
</Heading>
Head is element is metadata.
Heading is element is actual element.
Answer:
Head>the appears the "<body>" of a web page.
<Heading> the appears the body of the web page.
Explanation:
Volume of Pyramid = A*h/3 where A is the area of the base of the pyramid and h is the height of the pyramid. Write a C++ program that asks the user to enter the necessary information about the pyramid (note that the user would not know the area of the base of the pyramid, you need to ask them for the length of one of the sides of the base and then calculate the area of the base). Using the information the user input, calculate the volume of the pyramid. Next display the results (rounded to two decimal places). Example Output (output will change depending on user input): The area of the base of the pyramid is: 25.00 The height of the pyramid is: 5.00 The volume of the pyramid is: 41.67 *Pseudocode IS required for this program and is worth 1 point. The program IS auto-graded.
Answer:
#include <iostream>
#include <iomanip>
using namespace std;
int main()
{
double side, height;
cout<<"Enter the length of one of the sides of the base: ";
cin>>side;
cout<<"Enter the height: ";
cin>>height;
double area = side * side;
double volume = area * height / 3;
cout<<"The area of the base of the pyramid is: "<<area<<endl;
cout<<"The height of the pyramid is: "<<height<<endl;
cout<<"The volume of the pyramid is: "<<fixed<<setprecision(2)<<volume<<endl;
return 0;
}
Pseudocode:
Declare side, height
Get side
Get height
Set area = side * side
Set volume = area * height / 3
Print area
Print height
Print volume
Explanation:
Include <iomanip> to have two decimal places
Declare the side and height
Ask the user to enter side and height
Calculate the base area, multiply side by side
Calculate the volume using the given formula
Print area, height and volume (use fixed and setprecision(2) to have two decimal places)
state five uses of building
C++ Fibonacci
Complete ComputeFibonacci() to return FN, where F0 is 0, F1 is 1, F2 is 1, F3 is 2, F4 is 3, and continuing: FN is FN-1 + FN-2. Hint: Base cases are N == 0 and N == 1.
#include
using namespace std;
int ComputeFibonacci(int N) {
cout << "FIXME: Complete this function." << endl;
cout << "Currently just returns 0." << endl;
return 0;
}
int main() {
int N = 4; // F_N, starts at 0
cout << "F_" << N << " is "
<< ComputeFibonacci(N) << endl;
return 0;
}
Answer:
int ComputeFibonacci(int N) {
if(N == 0)
return 0;
else if (N == 1)
return 1;
else
return ComputeFibonacci(N-1) + ComputeFibonacci(N-2);
}
Explanation:
Inside the function ComputeFibonacci that takes one parameter, N, check the base cases first. If N is eqaul to 0, return 0. If N is eqaul to 1, return 1. Otherwise, call the ComputeFibonacci function with parameter N-1 and N-2 and sum these and return the result.
For example,
If N = 4 as in the main part:
ComputeFibonacci(4) → ComputeFibonacci(3) + ComputeFibonacci(2) = 2 + 1 = 3
ComputeFibonacci(3) → ComputeFibonacci(2) + ComputeFibonacci(1) = 1 + 1 = 2
ComputeFibonacci(2) → ComputeFibonacci(1) + ComputeFibonacci(0) = 1 + 0 = 1
*Note that you need to insert values from the bottom. Insert the values for ComputeFibonacci(1) and ComputeFibonacci(0) to find ComputeFibonacci(2) and repeat the process.
Why do you think it is necessary to set the sequence in which the system initializes video cards so that the primary display is initialized first
Answer:
Because if you don't do it BIOS doesn't support it. ... In troubleshooting a boot problem what would be the point of disabling the quick boot feature in BIOS setup
Explanation:
Using SQL
Use the blog database
Write a SQL RIGHT OUTER JOIN statement that joins the user_id column from the blog.posts table, the name column of the blog.users table and the body column of the blog.posts table together
Answer:
Following are the code to this question:
/*using the select statement, that selects column name from the table blog.posts */
SELECT blog.posts.user_id, blog.posts.body, users.name/*column name user_id, body, name*/
FROM blog.posts/* use table name blog.posts*/
RIGHT OUTER JOIN users ON blog.posts.user_id = users.id;/*use right join that connect table through user_id*/
Explanation:
In the structured query language, RIGHT JOIN is used to recovers from both the right side of the table both numbers, although the left table has no sets. It also ensures that even if the 0 (null) documents are linked inside this left table, its entry will always return the outcome row, but still, the number of columns from its left table will be NULL.
In the above-given right join code, the select statements used that selects the column names "user_id, body, and the name" from the table "blog. posts" and use the right join syntax to connect the table through the id.
A hotel salesperson enters sales in a text file. Each line contains the following, separated by semicolons: The name of the client, the service sold (such as Dinner, Conference, Lodging, and so on), the amount of the sale, and the date of that event. Write a program that reads such a file and displays the total amount for each service category. Display an error if the file does not exist or the format is incorrect.
Answer:
Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?
Explanation:
Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?Life can get busy and hectic, but relationships matter. What is an effective way of mending relationships that may have had been neglected?
what is the difference between ram and rom
Answer:
RAM is used to store programs and data the CPU needs. ROM has prerecorded data and is used to boot the computer
Explanation:
#The Fibonacci sequence is a number sequence where each #number is the sum of the previous two numbers. The first #two numbers are defined as 0 and 1, so the third number is #1 (0 + 1 = 1), the fourth number is 2 (1 + 1 = 2), the #fifth number is 3 (1 + 2 = 3), the sixth number is 5 #(2 + 3 = 5), and so on.
#
#Below we've started a class called FibSeq. At any time, #FibSeq holds two values from the Fibonacci sequence: #back1 and back2.
#
#Create a new method inside FibSeq called next_number. The #next_number method should:
#
# - Calculate and return the next number in the sequence, # based on the previous 2. # - Update back2 with the former value of back1, and update # back1 with the new next item in the sequence.
#
#This means that consecutive calls to next_number should #yield each consecutive number from the Fibonacci sequence. #Calling next_number 5 times would print 1, 2, 3, 5, and 8.
class FibSeq:
def __init__(self):
self.back1 = 1
self.back2 = 0
def next_number(self):
self.back1=self.back1+self.back2 # updated the back1 value to the next number in the series first
self.back2=self.back1-self.back2 #updated the back2 value with previous back1 value
yield (self.back1) # yielded the next number in the series since it is updated as back1 so yielded back1
f = FibSeq()
for i in range(5): # here i have iterated the series only 5 times u can change it as you like
s=f.next_number()
print(next(s))# here next is an iterator function for the yield generator.
#The code below will test your method. It's not used for
#grading, so feel free to change it. As written, it should
#print 1, 2, 3, 5, and 8.
newFib = FibSeq()
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
print(newFib.next_number())
Answer:
Here is the next_number method:
def next_number(self): #method to return next number in the sequence
temporary = self.back1 + self.back2 # adds previous number to next number and stores the result in a temporary variable
self.back2 = self.back1 #Updates back2 with the former value of back1,
self.back1 = temporary #update back1 with the new next item in the sequence.
return temporary #
Explanation:
I will explain the working of the above method.
back1 = 1
back2 = 0
At first call to next_number() method:
temporary = back1 + back2
= 1 + 0
temporary = 1
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 1
return temporary
This return statement returns the value stored in temporary variable i.e. 1
Output: 1
back1 = 1
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 1 + 1
temporary = 2
self.back2 = self.back1
self.back2 = 1
self.back1 = temporary
self.back1 = 2
return temporary
This return statement returns the value stored in temporary variable i.e. 2
output: 2
back1 = 2
back2 = 1
At second call to next_number() method:
temporary = back1 + back2
= 2 + 1
temporary = 3
self.back2 = self.back1
self.back2 = 2
self.back1 = temporary
self.back1 = 3
return temporary
This return statement returns the value stored in temporary variable i.e. 3
Output: 3
back1 = 3
back2 = 2
At second call to next_number() method:
temporary = back1 + back2
= 3 + 2
temporary = 5
self.back2 = self.back1
self.back2 = 3
self.back1 = temporary
self.back1 = 5
return temporary
This return statement returns the value stored in temporary variable i.e. 5
Output: 5
back1 = 5
back2 = 3
At second call to next_number() method:
temporary = back1 + back2
= 5 + 3
temporary = 8
self.back2 = self.back1
self.back2 = 5
self.back1 = temporary
self.back1 = 8
return temporary
This return statement returns the value stored in temporary variable i.e. 8
Output: 8
Calling next_number 5 times would print 1, 2, 3, 5, and 8.
The complete program along with its output is attached.
Write a program that extracts the last three items in the list sports and assigns it to the variable last. Make sure to write your code so that it works no matter how many items are in the list
Answer:
sports = ["football", "basketball", "volleyball", "baseball", "swimming"]
last = sports[-3:]
print(last)
Explanation:
*The code is in Python.
Create a list called sports
Create a variable called last and set it to the last three elements of the sports list using slicing
Print the last
what is filter in image processing
Answer:
Image processing operations implemented with filtering include smoothing, sharpening, and edge enhancement.
17. Write a query to get the Order ID, the name of the company that placed the order, and the first and last name of the associated employee. g
Answer:
Required code present in image attached
Explanation:
At first, the subquery (i.e., the inner query) will execute one time before executing the main query (i.e., outer query). This sequence is important since the result from the subquery is being utilized for when the main query executes to produced the desired outcome. The final result will be obtained after the last line of code executes.
Early in the history of technology, the development of tools and machines was based on _____ versus scientific knowledge as is done today. * 5 points technology and mathematics principles the engineering design process technical know-how positive and negative effects of using technology
Answer:
Early in the history of technology, the development of tools and machines was based on technical know-how versus scientific knowledge as is done today.
Explanation:
In the era prior to technological development, men had a basic and at times rudimentary manufacturing development, based on artisan processes that developed their tools and machinery by hand, without any type of automation or mass production rules.
Thus, each part or tool was manufactured in a unique way, which required a broad mastery of the production process by the manufacturer. This is how the first professions began to emerge, such as blacksmiths for example, who mastered the technique of manufacturing different implements and carried them out without any scientific knowledge.
A sample containing 4.30 g of O2 gas has an initial volume of 13.0 L. What is the final volume, in liters, when each of the following changes occurs in the quantity of the gas at constant pressure and temperature.
A sample of 200 g of O, is removed from the 4.30 g of O, in the container.
Answer:
Total amount of O₂ occupy volume = 76.50 L
2 .30 gm O₂ occupy volume = 7.48 L
Explanation:
We konw that,
Molar mass of O₂ = 31.9988 gm / mol
1 mole of O₂ = 31.9988 gm
Sample of oxygen = 0.600 mole
Computation:
0.600 mole = 31.9988 × 0.600
0.600 mole = 19.199 gm
Total amount of O₂ = 4.30 + 19.199
Total amount of O₂ = 23.499 gm
Total amount of O₂ occupy volume = 14 × 23.499/4.30
Total amount of O₂ occupy volume = 76.50 L
Total gm of O₂ = 4.30 - 2.00= 4.30 gm
2 .30 gm O₂ occupy volume = 14 × 2.30/4.30
2 .30 gm O₂ occupy volume = 7.48 L
Suppose that a server sends four packets of audio data, in 15 seconds each. The first is sent by the server exactly at noon (12:00:00), while each of the three successive packets is sent immediately after the completion of its predecessor. The client, on the other hand, receives the four packets beginning at 12:00:03, 12:00:20, 12:00:41, 12:00:59 respectively. What is the smallest delayed wait time (buffer) in seconds that would ensure the client had seamless playback (i.e. each packet plays immediately after the previous one ends)?
Answer:
15
Explanation:
for seamless playback each packet should be played before their predecessor so
4th packet will start at 12:01:03
3rd packet will start at 12:00:48
2nd packet will start at 12:00:33
1st packet will start at 12:00:18
as first packet arrives at 12:00:03 so wait time is 15 seconds for seamless playback