In a survey conducted by the marketing agency 11mark, 241 of 1000 adults 19 years of age or older confessed to bringing and using their cell phone every trip to the bathroom (confessions included texting and answering phone calls).
(a) What is the sample in this study? What is the population of interest?
(b) What is the variable of interest in this study? ls it qualitative or quantitative?
(c) Based on the results of this survey, obtain a point estimate for the proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom.
(d) Explain why the point estimate found in part (c) is a statistic. Explain why it is a random variable. What is the source of variability in the random variable?
(e) Construct and interpret a 95% confidence interval for the population proportion of adults 19 years of age or older who bring their cell phone every trip to the bathroom.
(f) What ensures that the results of this study are representative of all adults 19 years of age or older?

Answers

Answer 1

Answer: kindly check explanation

Step-by-step explanation:

A) The sample is a fraction of the total population used in the study.

The sample is 1000 19 years of age or older U.S adult.

The population : all U.S adults aged 19 or older.

B.) Confession about bringing cell phone to the bathroom and it is a qualitative variable

C.) point estimate (p) :

Total number of sample = 1000

Number who confessed to bring cellphone = 241

p = 241/ 1000

= 241/1000 = 0.241

D.) The point estimate was deduced from the sample information and not the population. Random selection because selection is unbiased.

E.) 95% confidence interval (CI)

95% CI = (1 - 0.95) = 0.05

For a two-tailed test : 0.05 / 2 = 0.025

Z - score = 1.96

Error : (√[p(1 - p) / n])*z

1.96 * √0.241(1-0.241)/1000

1.96* √0.000182919

1.96 * 0.0135247

= 0.0265085

Boundary :

(0.241 - 0.0265085), (0.241 + 0.0265085)

(0.2144915, 0.2675085)

F) The sample can be said to be representative of the total population since the sampling was performed and participants were chosen at random.


Related Questions

He Perimeter of a
regular decagon is 328cm
stake the length of one of its
sides

Answers

Answer:

32.8 cm

Step-by-step explanation:

decagons have 10 sides, so 328/10=32.8

Answer:

32.8 cm

Step-by-step explanation:

A regular decagon has 10 equal sides.

The perimeter of the decagon is 328 centimeters. The perimeter is the measure of all 10 sides added together. Since this is a regular decagon, all 10 sides are equal. Therefore, we can divide 328 by 10.

328 / 10

32.8

Add units, in this case, centimeters or cm.

32.8 cm

Each side of the decagon is 32.8 centimeters.

Find the probability of choosing an item from the intersection of following sets Set A : {1, 5, 10, 14, 22} Set B : {5, 14, 20, 22, 27}

Answers

Answer:

1/3

Step-by-step explanation:

There are three elements that are intersecting: 5, 14, 22

Probability of choosing an item is 1/3

Plz write this on paper help me and send it❤️

Answers

Answer:

1. [tex]27^{\frac{2}{3} } =9[/tex]

2. [tex]\sqrt{36^{3} } =216[/tex]

3. [tex](-243)^{\frac{3}{5} } =-27[/tex]

4. [tex]40^{\frac{2}{3}}=4\sqrt[3]{25} =4325[/tex]

5. Step 4: [tex](\frac{343}{27}) ^{-1} =\frac{27}{343}[/tex]

6. [tex]D. -72cd^{7}[/tex]

Step-by-step explanation:

Use the following properties:

[tex]a^{\frac{x}{y} } =\sqrt[x]{a^{y} }[/tex]

[tex]\sqrt[n]{ab} =\sqrt[n]{a} \sqrt[n]{b}[/tex]

[tex]a^{-n} =\frac{1}{a^{n} }[/tex]

[tex](xy)^{z} =x^{z} y^{z} \\\\[/tex]

[tex](x^{y}) ^{z} =x^{yz}[/tex]

[tex]x^{y} x^{z} =x^{y+z}[/tex]

So:

1. [tex]27^{\frac{2}{3} } =\sqrt[3]{27^{2}} =\sqrt[3]{729} }=9[/tex]

2. [tex]\sqrt{36^{3} } =\sqrt{36*36*36} =\sqrt{36} \sqrt{36} \sqrt{36} =6*6*6=216[/tex]

3. [tex](-243)^{\frac{3}{5} } =\sqrt[5]{-243^{3} } =\sqrt[5]{-14348907} =-27[/tex]

4. [tex]40^{\frac{2}{3}}=\sqrt[3]{40^{2} } =\sqrt[3]{2^{6} 5^{2} } =\sqrt[3]{2^{6} } \sqrt[3]{5^{2} } =2^{\frac{6}{3} } 5^{\frac{2}{3} } =4 *5^{\frac{2}{3} } =4\sqrt[3]{5^{2} } =4\sqrt[3]{25}=4325[/tex]

5. [tex](\frac{343}{27}) ^{-1} =\frac{1}{\frac{343}{27} } =\frac{27}{343}[/tex]

6.

[tex](-8c^{9} d^{-3} )^{\frac{1}{3} } *(6c^{-1}d^{4})^{2} =\sqrt[3]{-8} c^{3} d^{-1} 36c^{-2} d^{8} \\\\-2c^{3} d^{-1} 36c^{-2} d^{8}=-72cd^{7}[/tex]

Examine the system of equations. –2x + 3y = 6 –4x + 6y = 12 Answer the questions to determine the number of solutions to the system of equations. What is the slope of the first line? What is the slope of the second line? What is the y-intercept of the first line? What is the y-intercept of the second line? How many solutions does the system have?

Answers

Answer:

Examine the system of equations.

–2x + 3y = 6

–4x + 6y = 12

Answer the questions to determine the number of solutions to the system of equations.

What is the slope of the first line?  

✔ 2/3

What is the slope of the second line?  

✔ 2/3

What is the y-intercept of the first line?  

✔ 2

What is the y-intercept of the second line?  

✔ 2

How many solutions does the system have?  

✔ infinitely many

The equations are a multiple of the other, therefore, by the multiplicative

property of equality, the equations are equivalent.

Response:

The slope and y-intercept of the first equation are [tex]\underline{\dfrac{2}{3} \ and \ 2}[/tex] respectivelyThe slope and y-intercept of the second equation are [tex]\underline{\dfrac{2}{3} \, and \, 2}[/tex]

The system of equations have infinitely many solutions.

Methods used to obtain the above response.

The given system of equations are;

-2·x + 3·y = 6

-4·x + 6·y = 12

Required:

The slope of the first line.

Solution:

The slope of the first line is given by the coefficient of x when the equation is expressed in the form; y = m·x + c.

Therefore, from -2·x + 3·y = 6, we have;

3·y = 2·x + 6

[tex]y = \dfrac{2}{3} \cdot x + \dfrac{6}{3} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y =\dfrac{2}{3} \cdot x + 2[/tex]

[tex]\underline{The \ slope \ of \ the \ first \ equation \ is \ \dfrac{2}{3}}[/tex]

Required:

The slope of the second line;

Solution:

The equation of the second line, -4·x + 6·y = 12, can be expressed in the form;

[tex]y =\dfrac{4}{6} \cdot x + \dfrac{12}{6} = \dfrac{2}{3} \cdot x + 2[/tex]

[tex]y = \mathbf{\dfrac{2}{3} \cdot x + 2}[/tex]

[tex]\underline{The \ slope \ of \ the \ second \ equation \ is \ therefore \ \dfrac{2}{3}}[/tex]

The y-intercept of the first line = 2The y-intercept of the second line = 2

Given that the equation have the same slope and the same y-intercept, the equations are equations of the same line, therefore;

The equations have an infinite number of solutions

Learn more about the solutions of a system of equations here:

https://brainly.com/question/15356519

You can buy 5 cans for green beans at the village market for $2.80. You can buy 10 of the same cans of beans at Sam's club for $4.90. Which place is the better to buy

Answers

Answer:

The unit price at the village market is 2.80 / 5 = 0.56 and the unit price at Sam's Club is 4.90 / 10 = 0.49. Since 0.49 < 0.56, the answer is Sam's Club.

Answer: Sam's club

Step-by-step explanation:

Because 10/2 = 5, at Sam's club you get twice the beans.  Thus, simply multiply 2.8*2 = 5.60.  Because $5.60>$4.90, the village market is the worse place to buy.

what's the value? A.-20 B.-4 C.4 D.20

Answers

Answer:

-4

Option B is the correct option.

Step-by-step explanation:

[tex] {(4 - 2)}^{3} - 3 \times 4[/tex]

Subtract the numbers

[tex] = {(2)}^{3 } - 3 \times 4[/tex]

Multiply the numbers

[tex] = {(2)}^{3} - 12[/tex]

Evaluate the power

[tex] = 8 - 12[/tex]

Calculate the difference

[tex] = - 4[/tex]

Hope this helps..

Best regards!!

Answer:

[tex]\boxed{-4}[/tex]

Step-by-step explanation:

[tex](4-2)^3-3 \times 4[/tex]

Brackets or parenthesis are to be evaluated first. Subtract the numbers in the brackets.

[tex](2)^3-3 \times 4[/tex]

Evaluate the power or exponent.

[tex]8-3 \times 4[/tex]

Multiply the numbers.

[tex]8-12[/tex]

Finally, subtract the numbers.

[tex]=-4[/tex]

Greg goes fishing every day for a week. On the first day he catches seven fish and each
day he catches three more than the previous day. How many fish did he catch in total?

Answers

so first day and so on

7, 10, 13,....

as you can see it's an arithmetic progression

so sum for nth term= n/2 { 2a + (n-1) d}

it's the sum of the 7th term

so

7/2 { 7 ×2 + ( 7-1) 3}

7/2 × 32

7× 16

112 fishes

Answer:

I think the answer is 25

Step-by-step explanation:

7+3+3+3+3+3+3 becuase a week is seven days and the numbers there is seven ,and you plus the 7 with the remaining six days which are 3 each day,my answer was now 25 .please if you know this answer is wrong please tell everyone the correct one

The summer has ended and it's time to drain the swimming pool. 20 minutes after pulling the plug, there is still 45 000L of water in the pool. The pool is empty after 70 minutes. Calculate the rate that the water is draining out of the pool. b) Calculate how much water was in the pool initially. c) Write an equation for this relationship. d) Use your equation to calculate how much water is in the pool at 62 minutes.

Answers

Answer:

a) -900 L/min

b) 63000 L

c)  -900t +63000

 d) 7200 L

Step-by-step explanation:

a) You are given two points on the curve of volume vs. time:

(t, V) = (20, 45000) and (70, 0)

The rate of change of volume

= ΔV/Δt = (0 -45000)/(70 -20) = -45000/50 = -900 liters per minute

b) In the first 20 minutes, the change in volume was

(20 min)(-900 L/min) = -18000 L

So, the initial volume was

initial volume - 18000 = 45000

initial volume = 63,000 liters

c) Since we have the slope and the intercept, we can write the equation in slope-intercept form as

 V= -900t +63000.

d) now putting the number in the equation and do the arithmetic.

When t=62, the amount remaining is

= -900(62) +63000 = -55800 +63000 = 7200

Thus, 7200 L remain after 62 minutes.

The sand used for sanding icy roads in the winter is stored in a conical-shaped structure with a radius of 10 m
and a height of 16 m. Calculate the maximum amount of sand which can be stored in this structure.

Answers

Answer:

[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]

The maximum amount of sand that can be stored in this structure is 1675.52 m³.

Step-by-step explanation:

The volume of a conical-shaped structure is given by

[tex]V = \frac{1}{3} (\pi \cdot r^2 \cdot h)[/tex]

Where r is the radius and h is the height of the structure.

We are given that

radius = 10m

height = 16m

Substituting the above values into the formula, we get

[tex]V = \frac{1}{3} (\pi \cdot 10^2 \cdot 16) \\\\V = \frac{1}{3} (1600 \pi ) \\\\V = 1675.52 \: m^3[/tex]

Therefore, the maximum amount of sand th can be stored in this structure is 1675.52 m³.

HELP!! this is due today

Answers

Answer:

1

Step-by-step explanation:

If y=x, than the only way

y=rx can be possible is if r=1

Hope this helps!

Have a good day! :)

Answer:

1

Step-by-step explanation:

y = rx

Use any set of x and y-coordinates in the equation and solve for r.

For example, use (5.8, 5.8).

5.8 = r(5.8)

Divide both sides by 5.8:

r = 1

Answer: r = 1

.
What is y + 3 = 7(2 – 2) written in standard form?

Answers

Answer:

y = -3

Step-by-step explanation:

y + 3 = 7(2 - 2)

y + 3 = 0

Subtract 3 from both sides

y + 3 - 3 = 0 - 3

y = -3

Answer:

  7x - y = 17

Step-by-step explanation:

Maybe you want the standard form of the point-slope equation ...

  y +3 = 7(x -2)

__

  y + 3 = 7x -14 . . . . . eliminate parentheses

  17 = 7x -y . . . . . . . . add 14-y

  7x - y = 17

graph the circle x2 + y2 - 12x + 6y +36 =0​

Answers

x^2+y^2-12x+6y+36=0

Top Point: (6,0)

Left Point: (3,-3)

Right Point: (9,-3)

Bottom Point: (6,-6)

Answer:

[tex] x^2 +y^2 -12x +6y +36 =0[/tex]

And we can complete the squares like this:

[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]

And we got:

[tex] (x-6)^2 + (y+3)^2 = 9[/tex]

And we have a circle with radius r =3 and the vertex would be;

[tex] V= (6,-3) [/tex]

The graph is on the figure attached.

Step-by-step explanation:

For this case we have the following expression:

[tex] x^2 +y^2 -12x +6y +36 =0[/tex]

And we can complete the squares like this:

[tex] (x^2 -12x +6^2) + (y^2 +6y +3^2) = -36 +6^2 +3^2[/tex]

And we got:

[tex] (x-6)^2 + (y+3)^2 = 9[/tex]

And we have a circle with radius r =3 and the vertex would be;

[tex] V= (6,-3) [/tex]

The graph is on the figure attached.

Which of the following formulas would find the lateral area of a right cylinder
with height equal to hand ras the radius?
O A. LA = 2πr2
O B. LA = 2πr
O C. LA = 2πrh
O D. LA = 2πr2​

Answers

Answer:

C - LA = 2πrh

Step-by-step explanation:

Lateral surface area of right cylinder = 2 * π * radius * height

Solve the equation. \dfrac5{13}=t-\dfrac{6}{13} 13 5 ​ =t− 13 6 ​ start fraction, 5, divided by, 13, end fraction, equals, t, minus, start fraction, 6, divided by, 13, end fraction t=t=t, equals

Answers

Answer:

11 /13 = t

Step-by-step explanation:

5/13  = t -6/13

Add 6/13 to each side

5/13 + 6/13  = t -6/13+ 6/13

11 /13 = t

Answer:

[tex]t=\frac{11}{13}[/tex]

Step-by-step explanation:

[tex]\frac{5}{13} = t -\frac{6}{13}[/tex]

Add [tex]\frac{6}{13}[/tex] to both sides.

[tex]\frac{5}{13} + \frac{6}{13} = t -\frac{6}{13} + \frac{6}{13}[/tex]

[tex]\frac{11}{13} =t[/tex]

HELPPPP The equation 2x = 3y – 5 when written in slope-intercept form is: y = 2x – 5. y = -2x + 5. y = 2x + 5. None of these choices are correct.

Answers

Answer:

Y= 2/3x +(5/3)

Step-by-step explanation:

First, have to get Y alone on one side 3y=2x+5

Second, have to get read of the 3 with the Y so divide each side by three.

MATH HELP ME ASAP!!!!

Answers

Answer: Zak - Resp after 24 months = $4,344.00

              Zak - Technology Fund after 24 months = $1,102.98

              Zak's Technology Fund has enough money to buy a laptop.

              Zak's Savings (Resp) will last less than 6 months

Step-by-step explanation for Zak:

January - June 2019

$15/hr x 20 hr x 4 wks x 6 months = $7200 Gross Income

Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144

Taxable Income is $7200 - $1080 = $6120    (Annual Income $12,240)

Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60

→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income

Tech Fund (5%): $5486.40(0.05) = $274.32

Food Expense (30%): $5486.40(0.3) = $1,645.92

Clothing Expense (30%): $5486.40(0.3) = $1,645.92

Entertainment Expense (25%): $5486.40(0.25) = $1,371.60

Miscellaneous Expense (10%): $5486.40(0.1) = $548.64      

                                               Other Expenses: $5,212.08

July - December 2019 (excluding August)

$16/hr x 20 hr x 4 wks x 5 months = $6400 Gross Income

Resp (15%): $6400(0.15) = $960CPP(5%): $6400(0.05) = $320EI(2%): $6400(0.02) = $128

Taxable Income is $6400 - $960 = $5440    (Annual Income $11,560)

Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($5,440-$4,500)(0.08) = $75.20

→ $6,400 - ($960 + $320 + $128 + $0 + $75.20) = $4,916.80 Net Income

Tech Fund (5%): $4916.80(0.05) = $245.84

Food Expense (30%): $4916.80(0.3) = $1,475.04

Clothing Expense (30%): $4916.80(0.3) = $1,475.04

Entertainment Expense (25%): $4916.80(0.25) = $1,229.20

Miscellaneous Expense (10%): $4916.80(0.1) = $491.68      

                                              Other Expenses: $4,670.96

January - June 2020

$17/hr x 20 hr x 4 wks x 6 months = $8160 Gross Income

Resp (15%): $8160(0.15) = $1224CPP(5%): $8160(0.05) = $408EI(2%): $8160(0.02) = $163.20

Taxable Income is $8160 - $1224 = $6936    (Annual Income $13,872)

Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,936-$4,500)(0.08) = $194.88

→ $8,160 - ($1224 + $408 + $163.20 + $0 + $194.88) = $6,169.92 Net Income

Tech Fund (5%): $6169.92(0.05) = $308.50

Food Expense (30%): $6169.92(0.3) = $1,850.98

Clothing Expense (30%): $6169.92(0.3) = $1,850.98

Entertainment Expense (25%): $6169.92(0.25) = $1,542.48

Miscellaneous Expense (10%): $6169.92(0.1) = $616.98      

                                               Other Expenses: $5,861.42

July - December 2020 (excluding August)

$18/hr x 20 hr x 4 wks x 5 months = $7200 Gross Income

Resp (15%): $7200(0.15) = $1080CPP(5%): $7200(0.05) = $360EI(2%): $7200(0.02) = $144

Taxable Income is $7200 - $1080 = $6120    (Annual Income $13,056)

Income Tax (0% for 0-9,000 Annual): $4500(0) = $0Income Tax (8% for 9-25,000 Annual): ($6,120-$4,500)(0.08) = $129.60

→ $7,200 - ($1080 + $360 + $144 + $0 + $129.60) = $5,486.40 Net Income

Tech Fund (5%): $4916.80(0.05) = $274.32

Food Expense (30%): $5486.40(0.3) = $1,645.92

Clothing Expense (30%): $5486.40(0.3) = $1,645.92

Entertainment Expense (25%): $5486.40(0.25) = $1,371.60

Miscellaneous Expense (10%): $5486.40(0.1) = $548.64      

                                              Other Expenses: $5,212.08

[tex]\boxed{\begin{array}{l|r|r|r|r||r}\underline{ZAK}&\underline{Jan-Jun'19}&\underline{Jul-Dec'19}&\underline{Jan-Jun'20}&\underline{Jul-Dec'20}&\underline{Totals\quad }\\Gross&\$7200.00&\$6400.00&\$8160.00&\$7200.00&\$28960.00\\Resp&\$1080.00&\$960.00&\$1224.00&\$1080.00&\$4344.00\\Net&\$5486.40&\$4916.80&\$6169.92&\$5486.40&\$22059.52\\Other&\$5212.08&\$4670.96&\$5861.42&\$5212.08&\$20956.54\\Tech&\$274.32&\$245.84&\$308.50&\$274.32&\$1102.98\end{array}}[/tex]

can someone please help me

Answers

Answer:

3x^2 + 3/2 x -9

Step-by-step explanation:

f(x) = x/2 -3

g(x) =3x^2 +x -6

(f+g) (x) =  x/2 -3 + 3x^2 +x -6

   Combine like terms

            = 3x^2 + x/2 +x -3-6

              = 3x^2 + 3/2 x -9

Please answer it now in two minutes

Answers

Answer:

3√6

Step-by-step explanation:

tan60=opp/adj

opp(d)=tan60*3√2=√3*3√2=3√6

Bill needs to edge his yard with the dimensions in the shape below. What distance will he have walked after completing his edging? Round your answer to one decimal place. Do not include units in your answer.

Answers

Answer:

37.8 m

Step-by-step explanation:

The computation of the distance is shown below:

In triangle ADE

[tex]AD^2 = AE^2 + DE^2 \\\\ AD^2 = 5^2 + 3^2 \\\\ AD^2 = 34[/tex]

AD = 5.8

Now the distance walked after completing his edging is

Distance = AD + AB + BC + CD

= 5.8 + 12 + 5 + 15

= 37.8 m

We simply added these four sides so that the correct distance could arrive

Hence, the distance walked after completing his edging is 37.7

[tex]Let $u$ and $v$ be the solutions to $3x^2 + 5x + 7 = 0.$ Find\[\frac{u}{v} + \frac{v}{u}.\][/tex]

Answers

By the factor theorem,

[tex]3x^2+5x+7=3(x-u)(x-v)\implies\begin{cases}uv=\frac73\\u+v=-\frac53\end{cases}[/tex]

Now,

[tex](u+v)^2=u^2+2uv+v^2=\left(-\dfrac53\right)^2=\dfrac{25}9[/tex]

[tex]\implies u^2+v^2=\dfrac{25}9-\dfrac{14}3=-\dfrac{17}9[/tex]

So we have

[tex]\dfrac uv+\dfrac vu=\dfrac{u^2+v^2}{uv}=\dfrac{-\frac{17}9}{\frac73}=\boxed{-\dfrac{17}{21}}[/tex]

The value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].

What is quadratic equation?

A quadratic equation is an algebraic equation of the second degree in x. The quadratic equation in its standard form is[tex]ax^{2} +bx+c=0[/tex], where a and b are the coefficients, x is the variable, and c is the constant term.

What is the sum and product of the roots of the quadratic equation?

If [tex]ax^{2} +bx+c = 0[/tex] be the quadratic equation then

Sum of the roots = [tex]\frac{-b}{a}[/tex]

And,

Product of the roots = [tex]\frac{c}{a}[/tex]

According to the given question.

We have a quadratic equation [tex]3x^{2} +5x+7=0..(i)[/tex]

On comparing the above quadratic equation with standard equation or general equation [tex]ax^{2} +bx+c = 0[/tex].

We get

[tex]a = 3\\b = 5\\and\\c = 7[/tex]

Also, u and v are the solutions of the quadratic equation.

⇒ u and v are the roots of the given quadratic equation.

Since, we know that the sum of the roots of the quadratic equation is [tex]-\frac{b}{a}[/tex].

And product of the roots of the quadratic equation is [tex]\frac{c}{a}[/tex].

Therefore,

[tex]u +v = \frac{-5}{3}[/tex] ...(ii) (sum of the roots)

[tex]uv=\frac{7}{3}[/tex]   ....(iii)       (product of the roots)

Now,

[tex]\frac{u}{v} +\frac{v}{u} = \frac{u^{2} +v^{2} }{uv} = \frac{(u+v)^{2}-2uv }{uv}[/tex]                    ([tex](a+b)^{2} =a^{2} +b^{2} +2ab[/tex])

Therefore,

[tex]\frac{u}{v} +\frac{v}{u} =\frac{(\frac{-5}{3} )^{2}-2(\frac{7}{3} ) }{\frac{7}{3} }[/tex]         (from (i) and (ii))

⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{\frac{25}{9}-\frac{14}{3} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{25-42}{9} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} = \frac{\frac{-17}{9} }{\frac{7}{3} }[/tex]

⇒ [tex]\frac{u}{v} +\frac{v}{u} =\frac{-17}{21}[/tex]

Therefore, the value of [tex]\frac{u}{v} +\frac{v}{u}[/tex] is [tex]\frac{-17}{21}[/tex].

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Explain how to solve the equation |2x-3| = x^2 graphically. Using a graphing calculator to find all real number solutions to the equation.

Answers

Answer:

x = -3 , x = 1

Step-by-step explanation:

Hello,

you need to draw the graph of the two functions and then find the intersection points.

please see below

So the solution is the two points A and B

(-3,9) and (1,1)

Hope this helps

Please answer it now in two minutes

Answers

Answer:  3.2 yd

Step-by-step explanation:

Notice that TWV is a right triangle.  

Segment TU is not needed to answer this question.

∠V = 32°, opposite side (TW) is unknown, hypotenuse (TV) = 6

[tex]\sin \theta=\dfrac{opposite}{hypotenuse}\\\\\\\sin 32=\dfrac{\overline{TW}}{6}\\\\\\6\sin 32=\overline{TW}\\\\\\\large\boxed{3.2=\overline{TW}}[/tex]

1/6.43 +2/3.56 +1/8.51 use reciprocal table.Correct answer only​

Answers

Answer:

0.8348

Step-by-step explanation:

Given the expression 1/6.43 +2/3.56 +1/8.51, If 'a' is a number, the reciprocal of such number is 1/a. According to the question, the reciprocal of 6.43, 3.56 and 8.51 are  1/6.43 and 1/3.56 and 1/8.51 respectively.

1/6.43 = 0.1555

2/3.56 = 2 * 1/3.56

= 2 * 0.2809

= 0.5618

1/8.51 = 0.1175

Taking the sum of the reciprocals;

1/6.43 +2/3.56 +1/8.51 = 0.1555 + 0.5618 + 0.1175

1/6.43 +2/3.56 +1/8.51 = 0.8348

Hence, the sum of 1/6.43, 2/3.56 and 1/8.51 is 0.8348

Solve for x: (-1/2) x = 6

Answers

Answer: x = -12

Step-by-step explanation:

-1/2x=6

Divide by -1/2

x = -12

Hope it helps <3

URGENT

What else would need to be congruent to show that AABC= ADEF by the
AAS theorem?

Answers

Answer:

AC = EF

Step-by-step explanation:

ABC = DEF

You would need to know that AC = EF

In the first place, using deduction we know that we dont need another angle. We also know that BC does not equal DF by looking at the angles on the triangles.

The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.

What is AAS theorem?

The angle-angle-side theorem, or AAS, tells us that if two angles and a non-included side of one triangle are congruent to two angles and a non-included side of another triangle, then the triangles are congruent.

here, we have,

to find congruency in a triangle:

ΔABC ≅ ΔDEF

Therefore,

AAS congruence rule or theorem states that if two angles of a triangle with a non-included side are equal to the corresponding angles and non-included side of the other triangle, they are considered to be congruent.

Therefore,

∠C ≅ ∠F

Hence, The solution is : ∠C ≅ ∠F is congruent to show that ΔABC ≅ ΔDEF, else would need to be congruent to show that AABC= ADEF by the AAS theorem.

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solve for x, if a solution is extraneous identify in the final answer. thx :)

Answers

Answer:

x = 6 and x = 11.

Step-by-step explanation:

sqrt(x - 2) + 8 = x

sqrt(x - 2) = x - 8

(sqrt(x - 2))^2 = (x - 8)^2

x - 2 = x^2 - 16x + 64

x^2 - 16x + 64 = x - 2

x^2 - 17x + 66 = 0

We can use the discriminant to find whether there are solutions to the equation.

b^2 - 4ac; where a = 1, b = -17, and c = 66.

(-17)^2 - 4 * 1 * 66

= 289 - 264

= 25

Since the discriminant is positive, we know there are two valid solutions to the equation.

x^2 - 17x + 66 = 0

(x - 6)(x - 11) = 0

The solutions are when x - 6 = 0 and x - 11 = 0.

x - 6 = 0

x = 6

x - 11 = 0

x = 11

Hope this helps!

Answer:

x=11 solution

x=6 extraneous

Step-by-step explanation:

sqrt( x-2) + 8 = x

Subtract x from each side

sqrt(x-2) = x-8

Square each side

(sqrt(x-2))^2 = (x-8) ^2

x-2 = x^2 -8x-8x+64

x-2  = x^2 -16x+64

Subtract ( x-2) from each side

0 = x^2 -17x +66

Factor

0 = (x-6) ( x-11)

Using the zero product property

x=6  x=11

Checking the solutions

x=6

sqrt( 6-2) + 8 = 6

sqrt(4) +8 = 6

2 +8 = 6

False  not a solution

x=11

sqrt( 11-2) + 8 = 11

sqrt(9) +8 =11

3 +8 = 11

solution

Pls solve ASAP!! Review the attachment and solve. Pls hurry!

Answers

Answer:

A. 3

Step-by-step explanation:

ΔDEC is bigger than ΔABC by 5. For the hypotenuse, 25 is 5 times bigger than 5.

So, side DE on ΔDEC has to be 5 times bigger than side AB on ΔABC.

If side AB equals 3, side DE equals 18 - 3, which is 15.

15 is five times bigger than 3, so the answer is A. 3.

Hope that helps.

What is the simplest form for the expression (-12.7y-3.1x) Plus 5.9y-(4.2y Plus x)

Answers

Answer:

[tex]\boxed{-4.1x-11y}[/tex]

Step-by-step explanation:

[tex](-12.7y-3.1x) + 5.9y-(4.2y + x)[/tex]

Expand brackets.

[tex]-12.7y-3.1x+ 5.9y-4.2y - x[/tex]

Combining like terms.

[tex]- x-3.1x-12.7y+ 5.9y-4.2y[/tex]

[tex]-4.1x-11y[/tex]

Answer:

[tex] \boxed{\red{ - 11y - 4.1x}}[/tex]

Step-by-step explanation:

[tex] (- 12.7y - 3.1x) + 5.9y - (4.2y + x) \\ - 12.7y - 3.1x + 5.9y - 4.2y - x \\ - 12.7y + 5.9y - 4.2y- 3.1x - x \\ = - 11y - 4.1x[/tex]

Dora bought a bottle of nail polish that was marked down by 20 percent from its original price of $4.50. Including a 9 percent sales tax, what is the final cost of the bottle of nail polish?

Answers

Answer:

Hey there!

Marked down by 20 percent is equal to 80 percent of the original value.

4.5(0.8)=3.6

9 percent sales tax

3.6(1.09)=3.92

Hope this helps :)

Answer:

$3.92

Step-by-step explanation:

I took the test

Which is the best estimate of 90/7 divided by 1 3/4? 2 6 12 24

Answers

I would say the best estimate would be either 2 or 6.

Answer:

6 is the best estimate.

Step-by-step explanation:

(90/7) / (1 & 3/4) == (90/7) / (7/4) == (90/7) * (4/7) == 360/49 > 7.

Choose 6 as your best approximation.

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