In a student survey, forty part-time students were asked how many courses they were taking this term. The (incomplete) results are shown below: Please round your answers to 4 decimal places.


# of Courses Frequency Relative Frequency Cumulative Frequency

1 11 ? 11

2 ? 0.425 28

3 12 0.3 ?

What percent of students take exactly two courses?

%

Answers

Answer 1

Answer:

42.5%

Step-by-step explanation:

First we have to complete the table. We know that there are forty part time students so sum(f)=n=40. So, for two courses frequency is 40-11-12=17.

The relative frequency is the proportion of respective frequency and the sum of frequency. So, the missing relative frequency for 1st course is 11/40=0.275.

The missing relative frequency can also be computed as by subtracting given relative frequencies from 1 as sum of relative frequencies is 1. So, 1-0.425-0.3=0.275.

The cumulative frequency of respective class is the sum of frequency of previous classes and frequency of respective class. The missing cumulative frequency is 11+17+12 or 28+12= 40.

So, the complete table is

# of Courses Frequency Relative Frequency Cumulative Frequency

1                        11                   0.275                    11

2                        17                  0.425                    28

3                         12                  0.3                        40

The percent of students takes exactly two courses=0.425*100=42.5%


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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

See Explanation

Step-by-step explanation:

[tex] \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ LHS = \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} \\ \\ = \frac{ \sin5A \:\cos A - \cos5A \: \sin A}{\sin A \:\cos A } \\ \\ = \frac{ \sin(5A -A )}{\sin A \:\cos A} \\ \\ = \frac{ \sin 4A}{\sin A \:\cos A} \\ \\ = \frac{ 2\sin 2A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 2 \times 2\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ = \frac{ 4\sin A \: \cos A \: \cos 2A}{\sin A \:\cos A} \\ \\ =4\cos 2A \\ \\ = RHS \\ \\ thus \\ \\ \frac{ \sin5A}{\sin A} - \frac{ \cos5A}{\cos A} = 4\cos2A \\ \\ hence \: proved[/tex]

Help plz god bless you I’m handing out brianlest

Answers

I’m pretty sure it’s the last one

                                         [tex]\huge\boxed{(-2)^2x^3y^2}[/tex]

___________________________________________________________

                                              [tex]\boxed{Explanation}[/tex]

[tex](-2)\;*(-2)=(-2)^2\\x*x*x=x^3\\y*y=y^2\\\\Add\;them\;all\;together\;and\;you\;get\;(-2)^2x^3y^2.[/tex]

Hope it helps!

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[tex]\huge\boxed{Thanks,\;Plip.}[/tex]

Earth Science Chapter 1
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Answer:

Annyeonghaseyo! Whats the question ?

Step-by-step explanation:

3.45 x 10^-3=

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Answers

Answer:

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Step-by-step explanation:

Answer:   .00345x

Step-by-step explanation:

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Answers

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Answer: neither

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Answers

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Step-by-step explanation:

6x+2y=10

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Answer: y = -3x + 5

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Slope intercept form is y = mx + b so all you need to do is put the equation into that format.

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Answers

Do you have a specific sample question?

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer:

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Answers

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Step-by-step explanation:

The Byzantines developed their own Christian Church, which became well known as the Eastern Orthodox Church

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Answers

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Answers

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Step-by-step explanation:

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Answers

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Answers

Answer:

Step-by-step explanation:

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Answers

Step-by-step explanation:

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Step-by-step explanation:

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Answers

The answer will be 37 years old

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Which expression shows the side length, in feet,
of the bulletin board?

Answers

Answer: Option A
Take not that this is a square bulletin board thus area = Length Times Base. Notice how it says its a square as well? thus telling us that each side is of equal length

Squaring the value N would give us the value of the one side of the board

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https://brainly.com/question/14198272

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Step-by-step explanation:

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a

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