Answer:
the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.
Explanation:
Given;
mobility of the mobile electrons in the metal, μ = 0.0033 (m/s)/(N/C)
the electric field strength inside the cube of the metal, E = 0.033 N/C
The average drift speed of the mobile electrons in the metal is calculated as;
v = μE
v = 0.0033 (m/s)/(N/C) x 0.033 N/C
v = 1.089 x 10⁻⁴ m/s.
Therefore, the average drift speed of the mobile electrons in the metal is 1.089 x 10⁻⁴ m/s.
A fairgrounds ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has a 9.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose magnitude is 1.80 times that due to gravity
Answer:
13.37 rev/min
Explanation:
acceleration due to gravity (g) = 9.8 m/s², centripetal acceleration ([tex]a_c[/tex]) = 1.8 * g = 1.8 * 9.8 m/s² = 17.64 m/s².
r = 9 m
Centripetal acceleration ([tex]a_c[/tex]) is given by:
[tex]a_c=\frac{v^2}{r} \\\\v=\sqrt{a_c*r} \\\\v=\sqrt{17.64\ m/s^2*9\ m}\\\\v=12.6\ m/s[/tex]
The velocity (v) is given by:
v = ωr; where ω is the angular velocity
Hence:
ω = v/r = 12.6 / 9
ω = 1.4 rad/s
ω = 2πN
N = ω/2π = 1.4 / 2π
N = 0.2228 rev/s
N = 13.37 rev/min
In the Daytona 500 auto race, a Ford Thunderbird and a Mercedes Benz are moving side by side down a straightaway at 73.5 m/s. The driver of the Thunderbird realizes that she must make a pit stop, and she smoothly slows to a stop over a distance of 250 m. She spends 5.00 s in the pit and then accelerates out, reaching her previous speed of 73.5 m/s after a distance of 400 m. At this point how far has the Thunderbird fallen behind the Mercedes Benz, which has continued at a constant speed
Answer:
Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
Explanation:
Given the data in question;
initial speed of the ford u1 = 73.5 m/s
distance d1 = 250 m
t1 = 5.00 s
d2 = 400 m
Now, let the time taken to stop be t2 and deceleration is a1
so,
a1 = u1² / (2 × d1)
a1 = (73.5)² / (2 × 250)
a1 = 10.8045 m/s²
Now , for acceleration is a2
a2 = v² / (2 × d2)
a2 = (73.5)² / (2 × 400)
a2 = 6.7528 m/s²
total time spend = 5 + u/a1 + u/a2
total time spend = 5 + (73.5/10.8045) + (73.5/6.7528)
total time spend = 22.687 sec
Now, distance Mercedes is ahead = 22.687 × 73.5 - 400 - 250
= 1667.4945 - 400 - 250
= 1017.49 m
Therefore, Thunderbird has fallen behind the Mercedes Benz by 1017.49 m
To throw the discus, the thrower holds it with a fully outstretched arm. Starting from rest, he begins to turn with a constant angular acceleration, releasing the discus after making one complete revolution. The diameter of the circle in which the discus moves is about 1.8 m . Part A If the thrower takes 1.2 s to complete one revolution, starting from rest, what will be the speed of the discus at release
Answer:
9.42 m/s
Explanation:
a) Using Newton's law of motion formula:
[tex]\theta=\frac{(\omega+\omega_o)}{2}t\\\\where \ \theta=angular\ displacement=1\ rev =2\pi, w_o=initial\ velocity\ of\ discus\\=0\ rad/s, \omega=angular\ speed\ of\ discus\ at\ release,t=time\ = 1.2\ s.\\\\Hence:\\\\2\pi=\frac{(0+\omega)}{2}(1.2)\\\\\omega=\frac{2*2\pi}{1.2} \\\\\omega=10.47\ rad/s\\[/tex]
The speed of the discus at release (v) is:
v = ωr; where r = radius of discus
diameter = 1.8 m, r = diameter / 2= 1.6 / 2 = 0.9 m
v = ωr = 10.47 * 0.9
v = 9.42 m/s
When external forces acting on an object are balanced, what will happen to the object's
motion?
(7 Points)
The object will speed up.
The object will slow down.
The object will change direction.
The object's motion will remain the same
The object will stop
Answer:
The objects morion will remain the same
Explanation:
How shadows are formed?
Answer:
Shadows are formed when an opaque object or material is placed in the path of rays of light. The opaque material does not let the light pass through it. The light rays that go past the edges of the material make an outline for the shadow.
Explanation:
Hope it is helpful.....
(a) What type of charge distribution is inside the surface? a positively charged plane parallel to the end faces of the cylinder a positive line charge situated on and parallel to the axis of the cylinder a collection of positive point charges arranged in a line at the center of the cylinder and perpendicular to the axis of the cylinder a collection of negative point charges arranged in a line at the center of the cylinder and perpendicular to the axis of the cylinder a negatively charged plane parallel to the end faces of the cylinder (b) If the radius of the cylinder is 0.66 m and the magnitude of the electric field is 300 N/C, what is the net electric flux through the closed surface? N · m2/C (c) What is the net charge inside the cylinder? nC
Answer:
a) The type of charge distribution inside the surface is a negatively charged plane parallel to the end faces of the cylinder.
b) the net electric flux is -821.09 N.m²/c
c) the net charge inside the cylinder is -7.2666 nC
Explanation:
Given the data in the question;
a) (a) What type of charge distribution is inside the surface?
Based on the Image of the question below;
The type of charge distribution inside the surface is a negatively charged plane parallel to the end faces of the cylinder.
b) If the radius of the cylinder is 0.66 m and the magnitude of the electric field is 300 N/C, what is the net electric flux through the closed surface?
we know that; Electric flux is;
∅ = -2 × E × Area
we substitute
∅ = -2 × 300 × π ( 0.66 m )²
= -821.09 N.m²/c
Therefore; the net electric flux is -821.09 N.m²/c
c) What is the net charge inside the cylinder? nC
from Gause's law;
∅ = q/∈₀
q = ∅ ∈₀
we know permittivity ∈₀ = 8.85 × 10⁻¹²)
we substitute
q = -821.09 N.m²/c × (8.85 × 10⁻¹²)
q = -7.2666 × 10⁻⁹ C
q = -7.2666 nC
Therefore, the net charge inside the cylinder is -7.2666 nC
A star's emission line of 400 nm appears shifted to 404 nm in the spectrum. What can you conclude from this shift?
A. The star is approaching you with the speed of 3000 km/s.
B. The star is approaching you with the speed of 30300 km/s.
C. The star is receding from you with the speed of 3000 km/s.
D. The star is receding from you with the speed of 30300 km/s.
Answer:
C. The star is receding from you with the speed of 3000 km/s
Explanation:
To get this answer we use the doppler effect equation . The formula for a receding emissor is given in the attachment.
We solve for V
V = 3x10⁶m/s
V = 3000km/s
We have the wavelength to be shifting towards red. Therefore we conclude that it is receding. We say the star is receding with speed of 3000km/s towards you.
Thank you!
What impulse must be applied to a 25.0-kg cart to cause a velocity change
of 12.0 m/s?
Answer:
Impulse of force = 300Ns
Explanation:
Given the following data;
Mass = 25kg
Change in velocity = 12m/s
To find the impulse;
Impulse is given by the formula;
[tex] Impulse \; of \; force = mass * change \; in \; velocity [/tex]
Substituting into the equation, we have;
[tex] Impulse \; of \; force = 25 * 12 [/tex]
Impulse of force = 300Ns
An electron is accelerated through 2400 V from rest and then enters a region in which there is a uniform 1.70 T magnetic field. What are (a) the maximum and (b) the minimum magnitudes for the magnetic force this charge can experience
Answer:
Explanation:
Let v be the velocity acquired by electron in electric field
V q = 1/2 m v²
V is potential difference applied on charge q , m is mass of charge , v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on moving electron when it moves perpendicular to magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on electron and v is velocity of electron
= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
(a) The maximum force on the electron due to the magnetic field will be F= 79.02 x 10⁻¹³ N .
(b) Minimum force will be zero when electron moves along the direction of magnetic field .
What is magnetic force?Whenever a current is passes through a wire then the magnetic fields are generated around the wire and if any other charged particle comes under the influence of this magnetic field then the magnetic force is applied in the charge.
Let v be the velocity acquired by an electron in electric field
[tex]Vq=\dfrac{1}{2}mv^2[/tex]
V is potential difference applied on charge q ,
m is mass of charge ,
v is velocity acquired
2400 x 1.6 x 10⁻¹⁹ = .5 x 9.1 x 10⁻³¹ x v²
v² = 844 x 10¹²
v = 29.05 x 10⁶ m /s
Maximum force will be exerted on the moving electron when it moves perpendicular to the magnetic field .
Maximum force = Bqv , where B is magnetic field , q is charge on an electron and v is velocity of electron
F=Bqv
F= 1.7 x 1.6 x 10⁻¹⁹ x 29.05 x 10⁶
F= 79.02 x 10⁻¹³ N .
Minimum force will be zero when electron moves along the direction of magnetic field .
Hence the maximum force on the electron due to the magnetic field will be F= 79.02 x 10⁻¹³ N and the Minimum force will be zero when electron moves along the direction of magnetic field .
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In an early attempt to understand atomic structure, Niels Bohr modeled the hydrogen atom as an electron in uniform circular motion about a proton with the centripetal force caused by Coulomb attraction. He predicted the radius of the electron's orbit to be 5.29 ✕ 10−11 m. Calculate the speed of the electron and the frequency of its circular motion.
Answer:
The answer is below
Explanation:
Using Coulomb's law of electric field which is:
[tex]F=k\frac{q_1q_1}{r^2}\\\\ k =constant=9*10^9\ Nm^2/C^2,q_1=q_2=1.6*10^{-19}C,r=5.29*10^{-11}m\\\\Substituting\ gives:\\\\F=9*10^9*\frac{(1.6*10^{-19})*(1.6*10^{-19})}{(5.29*10^{-11})^2} =8.22*10^{-8}N\\\\Both\ centripetal\ force\ is\ given\ by:\\\\F=m\frac{v^2}{r} \\\\m = mass\ of \ electron=9.11*10^{-31}g,v=speed\ of\ electron\\\\F=m\frac{v^2}{r} \\\\v=\sqrt{\frac{F*r}{m} } \\\\subsituting:\\\\v=\sqrt{\frac{8.22*10^{-8}*5.29*10^{-11}}{9.11*10^{-31}} } \\\\v=2.18*10^6\ m/s\\\\[/tex]
[tex]But\ \omega=\frac{v}{r}=\frac{2.18*10^6}{5.29*10^{-11}} =4.13*10^{17}\\\\\omega=2\pi f; f=frequency\\\\f=\frac{\omega}{2\pi} =\frac{4.13*10^{17}}{2\pi} \\\\f=6.57*10^{15}\ Hz[/tex]
A 28.8 kg child sits on a 6.0 m long teeter-totter at a point 1.5 m from the pivot point (at the center of the teeter-totter). On the other side of the pivot point, an adult pushes straight down on the teeter-totter with a force of 180 N. Determine the direction the teeter-totter will rotate if the adult applies the force at a distance of each of the following from the pivot. (Assume the teeter-totter is horizontal when the adult applies the force and that the child's weight applies a clockwise torque.)
a.
1. 1.0 m
2. counterclockwise
b.
1. 2.0 m
2. clockwise
3. counterclockwise
c.
1. 3.0m
2. clockwise
3. counterclockwise
Answer:
case A) tau_net = -243.36 N m, case B) tau_net = 783.36 N / m, tau_net = -63.36 N m, case C) tau _net = - 963.36 N m,
Explanation:
For this exercise we use Newton's relation for rotation
Σ τ = I α
In this exercise the mass of the child is m = 28.8, assuming x = 1.5 m, the force applied by the man is F = 180N
we will assume that the counterclockwise turns are positive.
case a
tau_net = m g x - F x2
tau_nett = -28.8 9.8 1.5 + 180 1
tau_net = -243.36 N m
in this case the man's force is downward and the system rotates clockwise
case b
2 force clockwise, the direction of
the force is up
tau_nett = -28.8 9.8 1.5 - 180 2
tau_net = 783.36 N / m
in case the force is applied upwards
3) counterclockwise
tau_nett = -28.8 9.8 1.5 + 180 2
tau_net = -63.36 N m
system rotates clockwise
case c
2 schedule
tau_nett = -28.8 9.8 1.5 - 180 3
tau _net = - 963.36 N m
3 counterclockwise
tau_nett = -28.8 9.8 1.5 + 180 3
tau_net = 116.64 Nm
the sitam rotated counterclockwise
How much power does it take to lift 30.0 kg 100 m high in 5.00 s?
._.Answer:.
ijji._. ji
Explanation:.
Two students, each riding bicycles, start from the same apartment building and ride to the same building on campus, but each takes a different route. The first student rides 1300 m due east and then turns due north and travels another 1430 m before arriving at the destination. The second student heads due north for 1930 m and then turns and heads directly toward the destination.
(a) At the turning point, how far is the second student from the destination? ....m
(b) During the last leg of the trip, what direction (measured relative to due east) must the second student head? (Give your answer as a positive number from 0 to 180 degrees, either north or south of due east.) .... degrees south of east
Answer:
a) d= 1393 m
b) θ= 21º S of E.
Explanation:
a)
Since the second student goes due north, and the first student goes due east along 1300m till he turns directly northward, we conclude that when the second student turns, he is at 1300m west from the destination.Since he rode 1930 m due north, we can conclude also that the second student is 500 m past the destination in the north direction.So we can find the distance from the destination at the turning point, using the Pythagorean Theorem, taking the right triangle defined by the 1300 m segment due east, the 500 m segment due south, and which hypotenuse is the distance straight to the destination, as follows:[tex]d = \sqrt{(1300m)^{2} + (500m)^{2} } = 1393 m (1)[/tex]
b)
Taking the same right triangle than in (a), we can find the angle that makes the vector along the direction taken by the second student with the due east, applying the definition of tangent of an angle, as follows:[tex]tg \theta = \frac{500m}{1300m} = 0.385 (2)[/tex]
⇒ θ= tg⁻¹ (0.385) = 21º S of E.
CHEGG In the final stages of production, a pharmaceutical is sterilized by heating it from 25 to 75C as it moves at 0.2 m/s through a straight thin-walled stainless steel tube of 12.7-mm diameter. A uniform heat flux is maintained by an electric resistance heater wrapped around the outer surface of the tube. If the tube is 10 m long, what is the required heat flux
Answer:
xsfacacacacfafafacafaffafafkgxgzrzuamhdaydmursulrsykrsyrkzkyrztluxtulxtisurlztulsitldultsurkstulslutslitslutzusutllruzfjiubarris let lststdtsitsitlsitlsitl probably be perfect lstulitdults is a stlisitldudl us last leg e oil leak pal to Al pa pal rsrururuarul Al pa pal rsrururuarul lzulr para osutlsultsl to be pet lsu football game pa lslitsrulaulrslrusrykakryarulalutasulr ggggggggg is not me I will be there at the same time I don't have a car so I can get a ride to the airport fjztzhdilgdutldiydiltdultdutlstulzlurzykrUrlzultstlditldultsumtsultslutdliydilydlitdljdumtztulstzumtskyrUtlaraulszhfltulsfhlsjstultdisttilsdgkxidlutslutsutlzuzjzltisgHow many boron atoms are there in 5 molecules of BF3? Hint: The symbol for boron is B. Submit
Answer:
5 atoms of Boron
Explanation:
Boron makes up approximately 15.944% of the mass and the rest of the 84.056% is Fluorine. There is 5 Atoms because Boron atomic mass is 10.811 in 1 molecule of BF3 and you wanted 5 Molecules.
To see the number of atoms of an element in a given molecule we need to multiply stoichiometry to the number that is written on the foot of the element that is stoichiometry. Therefore, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
What is atom?Atom is the smallest particle of any element, molecule or compound. Atom can not be further divided. Atoms contains nucleus in its center and electron that revolve around the atom in fixed orbit.
In the nucleus, proton and neutron are present. Electron has -1 charge while proton has +1 charge. Neutron is neutral that is it has no charge. So overall the charge of nucleus is due to only proton, not by neutron.
In one molecule of BF[tex]_3[/tex], the number of boron atoms is 1. So, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
Therefore, in 5 molecules of BF[tex]_3[/tex], the number of boron atoms is 5.
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What are the units of the slope of a velocity-time graph?
Answer: m/s
Explanation:
The slope is the change in y over the change in x. If the graph is velocity over time, then the units will be meters per second
Which sequence correctly shows an increase in potential energy
Answer:
The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds. Gravitational potential energy increases as weight and height increases. Potential energy is energy that is stored in an object or substance.
Which two actions would weaken an electromagnet?
O A. Replacing the steel core of the magnet with a plastic core
O B. Decreasing the number of wraps of wire
O c. Increasing the number of wraps of wire
OD. Replacing a 6 V battery with a 9 V battery
O E. Replacing the hollow core of the magnet with a steel core
The correct options are (a &b) .
The strength of the electromagnet will vary depending on the core material utilized if cores of various materials with the same physical dimensions are employed. The number of flux lines traveling through the central core is what causes this difference in magnetic intensity.a. Replacing the steel core of the magnet with a plastic coreNo, Steel is used in permanent magnets because it takes a long time to get magnetized and remains magnetized after the current is turned off.In contrast, soft iron almost instantly acquires magnetism when the current is turned on, and it quickly loses all of its magnetism when the current is turned off.B. Decreasing the number of wraps of wireAs the number of turns increases the number of paper clips held increase. This means that the strength of the magnet increases with increasing number of turns in the coil.Learn more about an electromagnet brainly.com/question/23727978
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Answer: A & B
Explanation: just took it !
In a series circuit of two resistors, the resistors have the same __________; in a parallel circuit of two resistors, the resistors have the same __________. In a series circuit of two resistors, the resistors have the same __________; in a parallel circuit of two resistors, the resistors have the same __________. Voltage across them, current through them Current through them, voltage across them Current through them, current through them Voltage across them, voltage across them
Answer:
Current through them, voltage across them.
Explanation:
Ohm's law states that at constant temperature, the current flowing in an electrical circuit is directly proportional to the voltage applied across the two points and inversely proportional to the resistance in the electrical circuit.
Mathematically, Ohm's law is given by the formula;
[tex] V = IR[/tex]
Where;
V represents voltage measured in voltage.
I represents current measured in amperes.
R represents resistance measured in ohms.
A resistor can be defined as an electronic component that opposes the free flow of current from one point to another in an electrical circuit.
In a series circuit of two resistors, the resistors have the same current through them; in a parallel circuit of two resistors, the resistors have the same voltage across them.
The vertical component of the acceleration of a sailplane is zero when the air pushes up against its wings with a lift force of 5.20 kN. Assume that the only forces on the sailplane are that due to gravity and that due to the air pushing up against its wings. What will be the gravitational force on Earth due to the sailplane
Answer:
Explanation:
The vertical component of the acceleration of a sailplane is zero , that means the sailplane is experiencing net force of zero in vertical direction . Its weight is acting in downward direction . So airplane is also experiencing an upward force equal to its weight which is making net force equal to zero on it . This force is given as 5.20 k N .
So sailplane is experiencing an upward force equal to its weight . This force is generated due to air pushing up against its wings .
We know that every force generated has equal and opposite reaction force . Air is generating force on wings of sailplane , hence wings will also exert equal force on air on downward direction . This force will be transmitted to the earth by air .
Hence the gravitational force on Earth due to the sailplane will be equal to weight of sailplane . This force is 5.2 kN .
A 0.14 kg baseball moving at 23.00 m s is slowed to a stop by a catcher who exerts a constant force of 370 N How long does it take this force to stop the ball Incorrect Your answer is incorrect s How far does the ball travel before stopping
Answer:
(A) The time taken for the ball to stop is 8.7 x 10⁻³ s
(B) The distance traveled by the baseball before stopping is 0.3 m
Explanation:
Given;
mass of the baseball, m = 0.14 kg
velocity of the baseball, v = 23 m/s
force exerted on the baseball by the catcher, F = 370 N
(A) The time taken for the ball to stop;
[tex]F = ma = \frac{mv}{t} \\\\t = \frac{mv}{F} \\\\t = \frac{0.14 \times 23}{370} \\\\t = 8.7\times 10^{-3} \ s\\\\t = 8.7 \ ms[/tex]
(B) The distance traveled by the baseball before stopping is calculated as;
acceleration of the ball, [tex]a = \frac{v}{t} = \frac{23}{8.7\times 10^{-3}} = 2643.678 \ m/s^2[/tex]
Distance traveled, s;
s = ut + ¹/₂at²
s = (23)(8.7 x 10⁻³) + ¹/₂(2643.678)(8.7 x 10⁻³)²
s = 0.2001 + 0.1001
s = 0.3 m
A motorcyclist is traveling north on a road at a speed of 23.0 m/s. A police car, traveling south at a speed of 40.0 m/s, approaches with its siren producing sound at a frequency of 2500 Hz. (Enter your answers in Hz. Assume that the speed of sound in air is 343 m/s.) (a) What frequency does the motorcyclist observe as the police car approaches
Answer:
f ’= 3019.8 Hz
Explanation:
This is an exercise of the Doppler effect, that is, of the relative movement of the source (s) and the observer (o)
[tex]f' = f_o \frac{v +v_o}{v -v_s}[/tex]
in the case of the source and the observer approaching, if they move away the signs are exchanged
let's calculate
f ’= 2500 [tex]\frac{343 + 23}{343 - 40}[/tex]
f ’= 2500 [tex]\frac{366}{303}[/tex]
f ’= 3019.8 Hz
A 7600 kg rocket blasts off vertically from the launch pad with a constant upward acceleration of 2.35 m/s2 and feels no appreciable air resistance. When it has reached a height of 595 m, its engines suddenly fail so that the only force acting on it is now gravity.
A) What is the maximum height this rocket will reach above the launch pad?
B) How much time after engine failure will elapse before the rocket comes crashing down to the launch pad?
Answer:
a) The rocket reaches a maximum height of 737.577 meters.
b) The rocket will come crashing down approximately 17.655 seconds after engine failure.
Explanation:
a) Let suppose that rocket accelerates uniformly in the two stages. First, rocket is accelerates due to engine and second, it is decelerated by gravity.
1st Stage - Engine
Given that initial velocity, acceleration and travelled distance are known, we determine final velocity ([tex]v[/tex]), measured in meters per second, by using this kinematic equation:
[tex]v = \sqrt{v_{o}^{2} +2\cdot a\cdot \Delta s}[/tex] (1)
Where:
[tex]a[/tex] - Acceleration, measured in meters per square second.
[tex]\Delta s[/tex] - Travelled distance, measured in meters.
[tex]v_{o}[/tex] - Initial velocity, measured in meters per second.
If we know that [tex]v_{o} = 0\,\frac{m}{s}[/tex], [tex]a = 2.35\,\frac{m}{s^{2}}[/tex] and [tex]\Delta s = 595\,m[/tex], the final velocity of the rocket is:
[tex]v = \sqrt{\left(0\,\frac{m}{s} \right)^{2}+2\cdot \left(2.35\,\frac{m}{s^{2}} \right)\cdot (595\,m)}[/tex]
[tex]v\approx 52.882\,\frac{m}{s}[/tex]
The time associated with this launch ([tex]t[/tex]), measured in seconds, is:
[tex]t = \frac{v-v_{o}}{a}[/tex]
[tex]t = \frac{52.882\,\frac{m}{s}-0\,\frac{m}{s}}{2.35\,\frac{m}{s} }[/tex]
[tex]t = 22.503\,s[/tex]
2nd Stage - Gravity
The rocket reaches its maximum height when final velocity is zero:
[tex]v^{2} = v_{o}^{2} + 2\cdot a\cdot (s-s_{o})[/tex] (2)
Where:
[tex]v_{o}[/tex] - Initial speed, measured in meters per second.
[tex]v[/tex] - Final speed, measured in meters per second.
[tex]a[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]s_{o}[/tex] - Initial height, measured in meters.
[tex]s[/tex] - Final height, measured in meters.
If we know that [tex]v_{o} = 52.882\,\frac{m}{s}[/tex], [tex]v = 0\,\frac{m}{s}[/tex], [tex]a = -9.807\,\frac{m}{s^{2}}[/tex] and [tex]s_{o} = 595\,m[/tex], then the maximum height reached by the rocket is:
[tex]v^{2} -v_{o}^{2} = 2\cdot a\cdot (s-s_{o})[/tex]
[tex]s-s_{o} = \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex]
[tex]s = s_{o} + \frac{v^{2}-v_{o}^{2}}{2\cdot a}[/tex]
[tex]s = 595\,m + \frac{\left(0\,\frac{m}{s} \right)^{2}-\left(52.882\,\frac{m}{s} \right)^{2}}{2\cdot \left(-9.807\,\frac{m}{s^{2}} \right)}[/tex]
[tex]s = 737.577\,m[/tex]
The rocket reaches a maximum height of 737.577 meters.
b) The time needed for the rocket to crash down to the launch pad is determined by the following kinematic equation:
[tex]s = s_{o} + v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}[/tex] (2)
Where:
[tex]s_{o}[/tex] - Initial height, measured in meters.
[tex]s[/tex] - Final height, measured in meters.
[tex]v_{o}[/tex] - Initial speed, measured in meters per second.
[tex]a[/tex] - Gravitational acceleration, measured in meters per square second.
[tex]t[/tex] - Time, measured in seconds.
If we know that [tex]s_{o} = 595\,m[/tex], [tex]v_{o} = 52.882\,\frac{m}{s}[/tex], [tex]s = 0\,m[/tex] and [tex]a = -9.807\,\frac{m}{s^{2}}[/tex], then the time needed by the rocket is:
[tex]0\,m = 595\,m + \left(52.882\,\frac{m}{s} \right)\cdot t + \frac{1}{2}\cdot \left(-9.807\,\frac{m}{s^{2}} \right)\cdot t^{2}[/tex]
[tex]-4.904\cdot t^{2}+52.882\cdot t +595 = 0[/tex]
Then, we solve this polynomial by Quadratic Formula:
[tex]t_{1}\approx 17.655\,s[/tex], [tex]t_{2} \approx -6.872\,s[/tex]
Only the first root is solution that is physically reasonable. Hence, the rocket will come crashing down approximately 17.655 seconds after engine failure.
Anyone know this question?
Explain what is happening in this picture
Answer:
in this video waves are coming up for the BOTTOM to the top of the sandbar
A flashlight beam makes an angle of 60 degrees with the surface of the water before it enters the water. In the water what angle does the beam make with the surface
Answer:
θ₂ = 40.5º
Explanation:
For this exercise we must use the law of refraction
n₁ sin θ₁ = n₂ sin θ₂
where index 1 is for the incident ray and index 2 is for the refracted ray
in this case the incident ray has an angle of θ₁ = 60º and the refractive index of the water is
n₂ = 1,333
sin θ₂ = [tex]\frac{n_1}{n_2} \ sin \theta_1[/tex]
let's calculate
sin θ₂ = 1 / 1.3333 sin 60
sin θ₂ = 0.64968
θ₂ = sin⁻¹ (0.64968)
θ₂ = 40.5º
What is one example of an individual in an ecosystem?
Answer:
a
Explanation:
AAAA
What is the speed of a sailboat traveling 100m in 140s?
Answer:
Explanation:
d = rt only works for calculating average speeds.
100 = r(140)
r = 0.714 m/s
Answer: 0.71m/s
Explanation:
Formula: Speed = Distance/time
Speed = 100m/140s
Speed = 100/140 / 20/20
Speed = 5/7 or 0.71m/s
A scalar is a mathematical term for:
a. measurement
b. Magnitude and Direction
c. A number and a unit
d. A Scale
Answer:
c. A number and a unit
Explanation:
A scalar is a real number. We often use the term scalar in the context of vectors or matrices, to stress that a variable such as a is just a real number and not a vector or matrix.
Explain the physics of carnival rides in terms of motion, forces, energy, and momentum
Answer:
it spins
Explanation:
like a lot, bro i was on one before and it was pretty nice :)